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  • Saving PHP Table as CSV

    - by user2403705
    I have been looking everywhere for a way to do this. There are a lot of people that have asked the questions but when I try myself i cant seem to get it to work. Often I get the format correct but it inputs the information into a new page instead of saving it. I did manage to get one to work for google chrome but when i ran it in internet explorer it didnt work. I have a table being created from a MYSQL query and i would like the table to be able to be saved as a CSV. Could anyone help me out?

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  • PHP while loop, table row

    - by Elliott
    Hi, I'm trying to loop through a database and output data into a div, if there are 3 divs horizontally accross it will the start a new tr until it reaches another 3 etc. It is currently outputted like : [] [] [] [] [] [] Currently I have it working when it reaches 3 it starts a new row, but I don't know how I can only echo a new tr once? As it creates a new table row each time. echo '<table><tr>'; while ($result) { $i ++; if ($i&3) { echo '<td> <div>Row Data</div> </td>'; } else { echo '<tr> <td> <div>Row Data</div> </td></tr>'; } } echo '</tr></table>'; The $result variable is the recordset from my sql query, everything works fine I just don't know how to only create a new table row once? Thanks

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  • Removing part of a string in PHP

    - by Nik
    I'm trying to take a query: SHOW TABLES; which will display a bunch of tables with the chat_ prefix. I want to remove the chat_ prefix from the string, format the variable (with a link), and display it. How is this accomplished?

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  • PHP: question about passing parameters in URL's

    - by user248959
    Hi, i have this two lines: var_dump($parametros_post_signin); $this->redirect('prueba/aux?email='.$parametros_post_signin['signin']); the first one prints this: array 'signin' => array 'email_address' => string '' (length=0) 'password' => string '' (length=0) the second one takes to another action where i have this code: var_dump($request->getParameter('email')); that prints this: string 'password' (length=8) I expected it to print something like this: string '' (length=0) What should i do to the get value of the 'email_address' field ? Regards Javi

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  • PHP - Search array in array

    - by Anonymous2011
    I have tried googling for the past one hour straight now and tried many ways to search for an array, in an array. My objective is, to find a keyword in the URL, and the keywords are in a txt file. This is what i have so far - but doesn't work. $file = "keywords.txt"; $open = fopen($file,'r'); $data = fread($open,filesize($file)); $data = explode(" ",$data); $url = (!empty($_SERVER['HTTPS'])) ? "https://".$_SERVER['SERVER_NAME'].$_SERVER['REQUEST_URI'] : "http://".$_SERVER['SERVER_NAME'].$_SERVER['REQUEST_URI']; $url = parse_url($url); //parse the URL into an array foreach($data as $d) { if(strstr($d,$url)) { echo "yes"; } } This works WITHOUT the text file, or array - but that's not what i want. I'd appreciate it if anyone can assist me.

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  • filter by atributs php script

    - by cosy
    I have the table : id id_products id_atribut name value 1 13 8 autdio 2.1 2 13 9 hdd 200 Gb 3 13 10 cd-rom 2 4 20 8 audio 2.1 the problem is, how can i select from this table where id_products=13 and name="audio" and value="2.1" and name="hdd" and value="200 gb" .... How can i do this?

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  • PHP 1-liner each() with mysql_fetch_assoc()

    - by MVC You Know Me
    Hey All. Trying to create a 1-liner to loop through a mysql result set. Example: $sql = "SELECT uid, role FROM usr WHERE uid = '$this-uid'"; $r = db::q($sql); if($r-rows()) { $q = mysql_fetch_assoc($r-result); while(list($k, $v) = each($q)) { // would like to omit line above and consolidate here $_SESSION['usr'][$k] = $this->$k = $v; } } problem is that consolidating while loop like so: while(list($k, $v) = each(mysql_fetch_assoc($r-result)) returns an error a la each() not getting object or array, even though of course it is. I think the problem is a casting issue, but it does not seem you can do: each( (array) mysql_fetch_assoc($r-result)) Any ideas? I like to code as tersely as possible, and having "$q = mysql_fetch_assoc($r-result)" everywhere will annoy me, does already. Keep posted... Thanks!

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  • give preference to print array values in php

    - by Bharanikumar
    Hi , I have country table, i fetch all values and moved into array , these value i like to populate into combo/dropdown list , here i want to do some magic things, that is , for my site most of the users coming from uk,us,Australia,Romain and few, So i like to populate by my preference , is there any array will do this magic work, else is it possible mysql query , So final question is , Populate country name into combo based on my prefernce , Thanks

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  • "Distance" between colours in PHP

    - by Phil
    I'm looking for a function that can accurately represent the distance between two colours as a number or something. For example I am looking to have an array of HEX values or RGB arrays and I want to find the most similar colour in the array for a given colour eg. I pass a function a RGB value and the 'closest' colour in the array is returned

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  • Fetch multiple rows from SQL in PHP foreach item in array

    - by TrySpace
    I try to request an array of IDs, to return each row with that ID, and push each into an Array $finalArray But only the first result from the Query will output, and at the second foreach, it skips the while loop. I have this working in another script, so I don't understand where it's going wrong. The $arrayItems is an array containing: "home, info" $finalArray = array(); foreach ($arrayItems as $UID_get) { $Query = "SELECT * FROM items WHERE (uid = '" . cleanQuery($UID_get) . "' ) ORDER BY uid"; if($Result = $mysqli->query($Query)) { print_r($UID_get); echo "<BR><-><BR>"; while ($Row = $Result->fetch_assoc()) { array_push($finalArray , $Row); print_r($finalArray ); echo "<BR><><BR>"; } } else { echo '{ "returned" : "FAIL" }'; //. mysqli_connect_errno() . ' ' . mysqli_connect_error() . "<BR>"; } } (the cleanQuery is to escape and stripslashes) What I'm trying to get is an array of multiple rows (after i json_encoded it, like: {"finalArray" : { "home": {"id":"1","created":"0000-00-00 00:00:00","css":"{ \"background-color\" : \"red\" }"} }, { "info": {"id":"2","created":"0000-00-00 00:00:00","css":"{ \"background-color\" : \"blue\" }"} } } But that's after I get both, or more results from the db. the print_r($UID_get); does print info, but then nothing.. So, why am I not getting the second row from info? I am essentially re-querying foreach $arrayItem right?

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  • SFTP not supported error with PHP & cURL

    - by Bad Programmer
    I followed the advice from this Stack Overflow question thread, but I keep hitting a snag. I am receiving the following error message: Unsupported protocol: sftp Here is my code: $ch = curl_init(); if(!$ch) { $error = curl_error($ch); die("cURL session could not be initiated. ERROR: $error.""); } $fp = fopen($docname, 'r'); if(!$fp) { $error = curl_error($ch); die("$docname could not be read."); } curl_setopt($ch, CURLOPT_URL, "sftp://$user_name:$user_pass@$server:22/$docname"); curl_setopt($ch, CURLOPT_UPLOAD, 1); curl_setopt($ch, CURLOPT_PROTOCOLS, CURLPROTO_SFTP); curl_setopt($ch, CURLOPT_INFILE, $fp); curl_setopt($ch, CURLOPT_INFILESIZE, filesize($docname)); //this is where I get the failure $exec = curl_exec ($ch); if(!$exec) { $error = curl_error($ch); die("File $docname could not be uploaded. ERROR: $error."); } curl_close ($ch); I used the curl_version() function to see my curl information, and found that sftp doesn't seem to be in the array of supported protocols: [version_number] => 462597 [age] => 2 [features] => 1597 [ssl_version_number] => 0 [version] => 7.15.5 [host] => x86_64-redhat-linux-gnu [ssl_version] => OpenSSL/0.9.8b [libz_version] => 1.2.3 [protocols] => Array ( [0] => tftp [1] => ftp [2] => telnet [3] => dict [4] => ldap [5] => http [6] => file [7] => https [8] => ftps ) Is this a matter of my version of cURL being outdated, or is the SFTP protocol simply not supported at all? Any advice is greatly appreciated.

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  • PHP : flatten array - fastest way?

    - by Industrial
    Is there any fast way to flatten an array and select subkeys ('key'&'value' in this case) without running a foreach loop, or is the foreach always the fastest way? Array ( [0] => Array ( [key] => string [value] => a simple string [cas] => 0 ) [1] => Array ( [key] => int [value] => 99 [cas] => 0 ) [2] => Array ( [key] => array [value] => Array ( [0] => 11 [1] => 12 ) [cas] => 0 ) ) To: Array ( [int] => 99 [string] => a simple string [array] => Array ( [0] => 11 [1] => 12 ) )

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  • Get websites title and description, save to utf8 table, php/mysql

    - by Geteburg
    Hi guys, I've been trying today all day to figure this out and I have no idea. What I want: Get the title and meta description of any kind of website. Save this info to utf table in mysql. What the problem is? Different sites have different charsets which results in that some have chinese, some contain umlauts (german), then we have russian and so on.. I've tried preg_match which works for some while not for others, i've tried DOMdocument which is the same as preg_match. Is there any class available that will do this? Hope someone can help, thanks.

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  • [PHP] Check Valid date type

    - by yukou
    may be this question had been asked, I've searched but still not confident about my problem.. my problem is checking valid date from string $a='23-June-11'; //valid $b='Normal String';//invalid I want to convert $a and $b using strtotime() before I do that, of course i want to validate whether $a or $b is a valid date format From $a i can get 23, 11 using explode function, but how about 'June'? using function above, 'June' is not numeric

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  • PHP object cannot find method

    - by Daniel Hertz
    Hello, So I have a very simple class that has a method called getThumbUrl() but when I try calling this method on an instance I get Notice: Undefined property: FlickrImage::$getFullUrl But it is clearly there. Here is the code of the function: public function getThumbUrl() { return "http://farm".$this->_farm.".static.flickr.com/".$this->_server."/".$this->_id."_".$this->_secret."_t.jpg"; } And here is where it fails: foreach($photos as $photo) { echo "<img src='$photo->getFullUrl()' />"; } Any ideas? Thanks!

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  • PHP Array to CSV

    - by JohnnyFaldo
    I'm trying to convert an array of products into a CSV file, but it doesn't seem to be going to plan. The CSV file is one long line, here is my code: for($i=0;$i<count($prods);$i++) { $sql = "SELECT * FROM products WHERE id = '".$prods[$i]."'"; $result = $mysqli->query($sql); $info = $result->fetch_array(); } $header = ''; for($i=0;$i<count($info);$i++) { $row = $info[$i]; $line = ''; for($b=0;$b<count($row);$b++) { $value = $row[$b]; if ( ( !isset( $value ) ) || ( $value == "" ) ) { $value = "\t"; } else { $value = str_replace( '"' , '""' , $value ); $value = '"' . $value . '"' . "\t"; } $line .= $value; } $data .= trim( $line ) . "\n"; } $data = str_replace( "\r" , "" , $data ); if ( $data == "" ) { $data = "\n(0) Records Found!\n"; } header("Content-type: application/octet-stream"); header("Content-Disposition: attachment; filename=your_desired_name.xls"); header("Pragma: no-cache"); header("Expires: 0"); print "$data"; Also, the header doesn't force a download. I've been copy and pasting the output and saving as .csv

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  • PHP preg_match image between html tags

    - by Alvins
    I've got an html template like this: <div class="cont"> <div class="..."> <p>...<p> <img alt="" class="popup" src="DESIRED IMAGE LINK" style="..." /></p><p>...</p> .... And i want to extract "DESIRED IMAGE LINK" inside the "" tag, currently i'm using this: $pattern = '<div class="cont">.*?src=["\']?([^"\']?.*?(png|jpg|jpeg|gif))["\']?/i'; if (preg_match($pattern, $content, $image)) ..... But it doesn't work, the error is: warning: preg_match() [function.preg-match]: Unknown modifier '.' How can i fix it? Thanks

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  • MySql php: check if Row exists

    - by Jeff
    This is probably an easy thing to do but I'm an amateur and things just aren't working for me. I just want to check and see if a row exists where the $lectureName shows. If a row does exist with the $lectureName somewhere in it, I want the function to return "assigned" if not then it should return "available". Here's what I have. I'm fairly sure its a mess. Please help. function checkLectureStatus($lectureName) { $con = connectvar(); mysql_select_db("mydatabase", $con); $result = mysql_query("SELECT * FROM preditors_assigned WHERE lecture_name='$lectureName'"); while($row = mysql_fetch_array($result)); { if (!$row[$lectureName] == $lectureName) { mysql_close($con); return "Available"; } else { mysql_close($con); return "Assigned"; } } When I do this everything return available, even when it should return assigned.

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