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• Can I subscribe to window-docking events in windows 7 from C#

  - by www.mortenbock.dk

  Hi. I am wondering if it is possible to create an application that could receive a notification when any other application/window is docked with the new windows 7 docking feature (f.ex. Winkey + left arrow) The purpose of my application would be to set up custom rules for certain windows. So for example if I am using Chrome and I press the Win+LEFT keys, then my application would receive a notification, and would be able to say that the window should not resize to 50% of the screen, but should use 70%. I am not very familiar with writing windows applications (mostly do web), so any pointers at how this might be achieved are very welcome. Thanks.

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• BST Level Traversal

  - by Dalton Conley

  Ok, so I'm trying to do a level order traversal of a binary search tree and its not working. The code below makes sense to me, but that is probably because I've been looking at it forever and I've convinced myself that it should work. void BST<T>::levelByLevel(ostream &out) { Queue<BinNodePointer> q; BinNodePointer subtreeRoot; if(myRoot == NULL) return; q.enqueue(myRoot); while(!q.empty()) { subtreeRoot = q.front(); out << subtreeRoot->data << " "; q.dequeue(); if(subtreeRoot->left != NULL) q.enqueue(subtreeRoot->left); if(subtreeRoot->right != NULL) q.enqueue(subtreeRoot->right); } } Maybe you guys could point out what I'm doing wrong because, although I understand the concept of a binary search tree, I'm not 100% on all the ins and outs.

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• Make a simple animation in winforms using a loop

  - by Michael Quiles

  I need help making this loop to move a label move smoothly across the screen using count for the animation (its required). The labels location is currently in location 0,0 I'd like to make it go in a square right - down - left - back to its original position how can I accomplish this ? please give me an example using my code below. Thank You in advance. private void xAnimeTimer_Tick(object sender, EventArgs e) { int count; this.xAnimTimer.Stop(); for (count = 0; count <= 100; count++) { this.xAnimLabel.Left = count; } for (count = 0; count <= 150; count++) { this.xAnimLabel.Top = count; }

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• PHP: Auto Updating subscriptions?

  - by Duncan Palmer

  Hey guys I am currently making a website and I am hopefully going to start a premium service for it. What I am currently looking into right now is how to make an "auto updating" shop which removes 1 day from how many days left the user has left on their premium status. so for example if the users purchases 30 days of premium, each day that 30 with negate 1 so.. 30, 29, 28, 27.. etc and then if the days gets to 0 in will remove premium status. The only way I can think of keeping track of this right now is by manually monitoring each persons premium status but that wouldnt be very practical. What would the best way for me to do this? (hopefully "automatically") Thanks.

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• How can I get gradients working in IE9?

  - by gladoscc

  CSS: .silver { color: #636363; border: solid 1px #9C9C9C; background: #D6D6D6; /*important part*/ background: -webkit-gradient(linear, left top, left bottom, from(#E8E8E8), to(#BABABA)); background: -moz-linear-gradient(top, #E8E8E8, #BABABA); -ms-filter: "progid:DXImageTransform.Microsoft.gradient(startColorstr='#e8e8e8', endColorstr='#bababa')"; filter: progid:DXImageTransform.Microsoft.gradient(startColorstr='#e8e8e8', endColorstr='#bababa'); padding: 2px 5px 2px 5px; -webkit-border-radius: 5px; -moz-border-radius: 5px; border-radius: 5px; margin-right: 5px; font-size: 95%; } This works when I apply to class to a input / submit button, but the gradients do not display when I apply the class to a span or div. How can I get gradients working in IE9?

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• ModX navigation menu with "wayfinder" snippet

  - by user1219432

  I have a main navigation at the top of the site. And a subnavigation at left of my site. For example: At the top there are these topics: Cars | Trees | Jobs | ... So when you click on "Jobs" there should be the subnavigation of "Jobs" at left, like... Construction Jobs Engineering Jobs Retail Jobs ... The first (top) navigation is easy to achieve: [[!Wayfinder? &startId=0 &level=1 ]] How can I realize the second navigation, so that only the documents are listed that are under the parent document?

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• Unity JS - simple if statements not behaving as expected?

  - by IHazABone

  I have a simple script (please no remarks on the fact that I'm not using a switch statement or better code, this is the earliest version and written this way by a peer, I am improving it) that takes an object and moves it back and forth. For some reason, the variable time gets stuck at 249. It is probably an obvious bug with this inefficient logic, but I cannot seem to find it. var speed = 1; private var time = 0; function Start() { } function Update() { if(condition == true)moveStuff(); } function moveStuff() { var timeSwitch = false; if(time == 0)timeSwitch = false; if(time == timeSet)timeSwitch = true; if(direction == 1) { if(timeSwitch == false) { transform.Translate(Vector3.up * (Time.deltaTime * speed)); time += 1; Debug.Log(time); }else if(timeSwitch == true) { transform.Translate(Vector3.up * ((Time.deltaTime * speed) * -1)); time -= 1; Debug.Log(time); } } else if(direction == 2) { if(timeSwitch == false) { transform.Translate(Vector3.down * (Time.deltaTime * speed)); time += 1; Debug.Log("Moved down. "); }else if(timeSwitch == true){ transform.Translate(Vector3.down * ((Time.deltaTime * speed) * -1)); time -= 1; } } else if(direction == 3) { if(timeSwitch == false) { transform.Translate(Vector3.forward * (Time.deltaTime * speed)); time += 1; Debug.Log("Moved forward. "); }else if(timeSwitch == true){ transform.Translate(Vector3.forward * ((Time.deltaTime * speed) * -1)); time -= 1; } } else if(direction == 4) { if(timeSwitch == false) { transform.Translate(Vector3.back * (Time.deltaTime * speed)); time += 1; Debug.Log("Moved back. "); }else if(timeSwitch == true){ transform.Translate(Vector3.back * ((Time.deltaTime * speed) * -1)); time -= 1; } } else if(direction == 5) { if(timeSwitch == false) { transform.Translate(Vector3.right * (Time.deltaTime * speed)); time += 1; Debug.Log("Moved right. "); }else if(timeSwitch == true){ transform.Translate(Vector3.right * ((Time.deltaTime * speed) * -1)); time -= 1; } } else if(direction == 6) { if(timeSwitch == false) { transform.Translate(Vector3.left * (Time.deltaTime * speed)); time += 1; Debug.Log("Moved left. "); }else if(timeSwitch == true){ transform.Translate(Vector3.left * ((Time.deltaTime * speed) * -1)); time -= 1; } } }

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• How can I prevent my site from being branded a "content farm?"

  - by Fredashay

  I'm building a small social Q&A site. Another Q&A site that I use was recently branded by Google as a content farm and removed from Google results. I know what Wikipedia says is the definition of a content farm (low quality paid articles and spammy text across the page to catch search engines). That other site I use doesn't do those things, so there must be more to it than that. I want to make sure I don't do anything that causes Google to think my Q&A site is a content farm. What should I do, or avoid doing in designing my site layout?

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• Running a python script for a user-specified amount of time?

  - by Rob

  Sorry, this is probably a terrible question. I've JUST started learning python today. I've been reading a Byte of Python. Right now I have a project for Python that involves time. I can't find anything relating to time in Byte of Python, so I'll ask you: How can I run a block for a user specified amount of time and then break? For example (in some pseudo-code): time = int(raw_input('Enter the amount of seconds you want to run this: ')) while there is still time left: #run this block or even better: import sys time = sys.argv[1] while there is still time left: #run this block Thanks for any help. Also, additional online guides and tutorials would be much appreciated. I really like Byte of Python. Dive into Python can't quite hold my attention, though. I suppose I should suck it up and try harder to read that one.

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• WordPress for Windows Phone 7

  - by Enrique Lima

  Slowly but surely apps have been coming out for Windows Phone 7, I must admit that was my biggest concern on moving from the iPhone to the Windows Phone.  Not the fact apps would come slowly, but when they would come.  The iPhone side of things had very nice apps, and moving into a not so populated app landscape was an interesting thought. Anyway, yes there are apps I miss … but now it is one less! WordPress released the “for Windows Phone 7” app. Great experience and layout for the tool. If you are now on Windows Phone 7, check it out. http://windowsphone.wordpress.org/

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• Problem with joining to an empty table

  - by Imran Omar Bukhsh

  I use the following query: select * from A LEFT JOIN B on ( A.t_id != B.t_id) to get all the records in A that are not in B. The results are fine except when table B is completely empty, but then I do not get any records, even from table A. Later It wont work yet! CREATE TABLE IF NOT EXISTS T1 ( id int(11) unsigned NOT NULL AUTO_INCREMENT, title varchar(50) CHARACTER SET utf8 COLLATE utf8_unicode_ci NOT NULL, t_id int(11) NOT NULL, PRIMARY KEY (id) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=3 ; -- -- Dumping data for table T1 INSERT INTO T1 (id, title, t_id) VALUES (1, 'apple', 1), (2, 'orange', 2); -- -- Table structure for table T2 CREATE TABLE IF NOT EXISTS T2 ( id int(11) NOT NULL AUTO_INCREMENT, title varchar(50) CHARACTER SET utf8 COLLATE utf8_unicode_ci NOT NULL, t_id int(11) NOT NULL, PRIMARY KEY (id) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=2 ; -- -- Dumping data for table T2 INSERT INTO T2 (id, title, t_id) VALUES (1, 'dad', 2); Now I want to get all records in T1 that do not have a corresponding records in T2 I try SELECT * FROM T1 LEFT OUTER JOIN T2 ON T1.t_id != T2.t_id and it won't work

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• how to update off screen pivot item

  - by Yama moto

  I want to have a pivot with many PivotItems. However, doing so will impact memory. So I bind pivot to my ViewModel, which has 3 item, and pivot will generate 3 PivotItems. My ViewModel is of type ObservableCollection and my item does implement INotifyPropertyChanged. This works fine. But when I update my ViewModel, only the current PivotItem, and the right PivotItem is updated. The left PivotItem, which is off screen, is not updated. You can see it when you drag pivot to the left. How to fix this? Or WP7 doesnot update off screen PivotItem ?

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• Is asking for control totals on a file an outdated means of verifying a file?

  - by CTKeane

  I'm in a new position where I need to process a flat files on a regular basis. The last time I did this was 5 or 6 years ago but as part of the file layout I received control totals. It gave me simplistic information on the file like the total number of records as well as sums of the important fields. This helped me during testing then also during production to verify the file arrived and has correct information. I have asked for similar data for this new project and have hit a wall of no. Is this no longer a standard practice? Is there a better way?

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• JQuery code does not work not understanding the markup

  - by Andrae Browne

  I am trying to make a simple animation using JQuery. I have tried adding the script externally(external file) and internally(within script tags). I have testing if the page is recognizing the script using the alert function, but the script is not executing. I am thinking that is has something to do with the syntax. $("#container5").hover(function() { //hover in $(#container5).animate({ height: "250", width: "250", left: "-=50", top: "-=50", }, "fast"); }, function() { //hover out $(#container5).animate({ height: "200", width: "200", left: "+=50", top: "+=50", }, "fast"); } })(jQuery);

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• Basic C++ code for multiplication of 2 matrix or vectors (C++ beginner)

  - by Ice

  I am a new C++ user and I am also doing a major in Maths so thought I would try implement a simple calculator. I got some code off the internet and now I just need help to multiply elements of 2 matrices or vectors. Matrixf multiply(Matrixf const& left, Matrixf const& right) { // error check if (left.ncols() != right.nrows()) { throw std::runtime_error("Unable to multiply: matrix dimensions not agree."); } /* I have all the other part of the code for matrix*/ /** Now I am not sure how to implement multiplication of vector or matrix.**/ Matrixf ret(1, 1); return ret; }

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• Testing complex compositions

  - by phlipsy

  I have a rather large collection of classes which check and mutate a given data structure. They can be composed via the composition pattern into arbitrarily complex tree-like structures. The final product contains a lot of these composed structures. My question is now: How can I test those? Albeit it is easy to test every single unit of these compositions, it is rather expensive to test the whole compositions in the following sense: Testing the correct layout of the composition-tree results in a huge number of test cases Changes in the compositions result in a very laborious review of every single test case What is the general guideline here?

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• Question in Flex (parser)

  - by shkk

  Hello... I want to ask you a question about Flex, the program for parsing code. Supposing I have an instruction like this one, in the rules part: "=" BEGIN(attribution); <attribution>{var_name} { fprintf(yyout, "="); ECHO; } <attribution>";" BEGIN(INITIAL); {var_name} is a regular expression that matches a variable's name, and all I want to do is to copy at the output all the attribution instructions, such as a = 3; or b = a; My rule though cannot write with fprintf the left member of the attribution, but only = 3; or =a; One solution for that might be that, after I make the match "=" and I am in the attribution state, to go 2 positions back as to get the left operand as well. How can I do that in Flex?

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• Optimal search queries

  - by Macros

  Following on from my last question http://stackoverflow.com/questions/2788082/sql-server-query-performance, and discovering that my method of allowing optional parameters in a search query is sub optimal, does anyone have guidelines on how to approach this? For example, say I have an application table, a customer table and a contact details table, and I want to create an SP which allows searching on some, none or all of surname, homephone, mobile and app ID, I may use something like the following: select * from application a inner join customer c on a.customerid = a.id left join contact hp on (c.id = hp.customerid and hp.contacttype = 'homephone') left join contact mob on (c.id = mob.customerid and mob.contacttype = 'mobile') where (a.ID = @ID or @ID is null) and (c.Surname = @Surname or @Surname is null) and (HP.phonenumber = @Homphone or @Homephone is null) and (MOB.phonenumber = @Mobile or @Mobile is null) The schema used above isn't real, and I wouldn't be using select * in a real world scenario, it is the construction of the where clause I am interested in. Is there a better approach, either dynamic sql or an alternative which can achieve the same result, without the need for many nested conditionals. Some SPs may have 10 - 15 criteria used in this way

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• iPhone SDK: Keep an image from scrolling with a UIScrollView

  - by Wudstock

  Hi, I've been searching all over for an easy way to do this. Right now I have a UIScrollView setup as my main view. There's an Image on the left and a column of TextFields on the right. When any TextField is tapped, the keyboard comes up and hides the bottom TextField. So I have the ScrollView move up to unhide the bottom TextField. Question #1: Is there a way to have it respond to a specific TextField instead of all of them? Question #2: Is there a way to keep the Image on the left static so it doesn't move with the TextFields? Thanks in advance for any help.

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• WPF - collapsing grid cells

  - by user553765

  Hi, I'm having some problems with the layout of buttons on a screen. There are a number of buttons with the visibility set to collapsed depending on certain criteria. Anyway, with the buttons sitting in a stackpanel, the contents determine the width of the buttons. Because these should share the same size, I put them in a grid where the columns are using the SharedSizeGroup. Having done this, buttons now all share the same width, the smallest width needed to display the button with the largest content. What it does mean though is that buttons don't display at the required position. That is - assume five buttons in columns 0-4 where the first button is collapsed, buttons should ideally all shift to the left so that they always occupy space left to right. Is there any way I can accomplish this or, if not, how can I get buttons in a stackpanel to share the same width? Any help is much appreciated.

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• Problem with multi-table MySQL query

  - by mahle

  I have 3 tables. Here is the relevant information needed for each. items prod_id order_id item_qty orders order_id order_date order_status acct_id accounts acct_id is_wholesale items is linked to order by the order_id and orders is linked to accounts via acct_id I need to sum item_qty for all items where prod_id=464 and the order stats is not 5 and where the is_wholesale is 0 and the order_date is between two dates. Im struggling with this and would appreciate any help. Here is what I have but it's not working correctly: SELECT SUM(items.item_qty) as qty FROM items LEFT JOIN orders ON orders.order_id = items.order_id LEFT JOIN accounts on orders.acct_id = accounts.acct_id WHERE items.prod_id =451 AND orders.order_date >= '$from_date' AND orders.order_date <= '$to_date' AND orders.order_status <>5 AND accounts.is_wholesale=0; Again, any help would be greatly appreciated!

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• MySQL GROUP BY with three tables

  - by Psaniko

  I have the following tables: posts (post_id, content, etc) comments (comment_id, post_id, content, etc) posts_categories (post_category_id, post_id, category_id) and this query: SELECT `p`.*, COUNT(comments.comment_id) AS cmts, posts_categories.*,comments.* FROM `posts` AS `p` LEFT JOIN `posts_categories` ON `p`.post_id = `posts_categories`.post_id LEFT JOIN `comments` ON `p`.post_id = `comments`.post_id GROUP BY `p`.`post_id` There are three comments on post_id=1 and four in total. In posts_categories there are two rows, both assigned to post_id=1. I have four rows in posts. But if I query the statement above I get a result of 6 for COUNT(comments.comment_id) at post_id=1. How is this possible? I guess the mistake is somewhere in the GROUP BY clause but I can't figure out where. Any suggestions?

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• How do i get my search bar to actually work?

  - by Sam

  Hey guys, I've got a search bar and it looks fine, but i don't really know how to make it search the whole of my site... Here's my html code so far: <form class="search2" method="get" action="default.html" /> <input class="search2" type="text" name="serach_bar" size="31" maxlength="255" value="" style="left: 396px; top: 153px; width: 293px; height: 26px;" /> <input class="search1" type="submit" name="submition" value="Search" style=" padding- bottom:20px; left: 691px; top: 153px; height: 23px" /> <input class="search2" type="hidden" name="sitesearch" value="default.html" /> Thanks in advance guys!

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• What's the most basic jQuery implementation of a multi-category dropdown menu?

  - by Coop

  I'm looking for a HORIZONTAL jQuery dropdown menu that presents multiple sub categories. I'll give a VERTICAL example because it's easier to represent here: -> a -> a1 -> a2 -> b -> b1 -> b1a -> b2 -> c -> c2 -> c2a -> c2a1 -> c2a2 If you drop your left ear towards your left shoulder, you can imagine what this would look like from the top of a page :)

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• ontouch - Switching positions of two views(images) in Android

  - by idish

  I've been looking for that 2 days long and haven't found anything related to it. I'll give an example for my goal. Let's say I have 2 images positioned side by side horizontally. I want the user to be able to switch their positions onlongtouch listener. so let's say that the first image was on the left and the second was on the right side, after switching positions between them, the first image would be in the right and the second would be on the left side. Basically, it is just like in the launcher where you can switch apps positions. Please, if anything is not clear for you, I would like to know, and I'll try to explain it better, thank you.

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