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  • Clear Select options when selecting one field while using multiple forms on same page

    - by Nizam
    Hi all, I have a situation where the second select list option is generated from the first select list selected option. Like when we select Country corresponding states are generated in next select list. In my case I am having multiple forms on single page which are same. Can anyone let me know how to implement it on multiple forms. I tried the following code but it didn't work $(".country").change(function(){ $.get("sample.php?val=" + $(this).val(), function(data){ $(this).parent().next().children('.state').children('option').remove(); $(this).parent().next().children('.state').append(data); }); Waiting for your support thanks in advance

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  • asp.net forms authentication timing out after 1 minute

    - by user548929
    I'm using ASP.NET MVC 3 with the Authorize attribute, but it keeps kicking me to the logon page after 1 minute, but even though my expiration is set to a very high value, it times out quickly. I check the cookie in my browser and its still there and not set to expire until about a month later, and it's set to be persistent, so I'm not sure why it keeps booting me. It only happens on my published location, locally it works just fine. var ticket = new FormsAuthenticationTicket(username, true, 500000); var encryptedTicket = FormsAuthentication.Encrypt(ticket); var cookie = new HttpCookie(FormsAuthentication.FormsCookieName, encryptedTicket); cookie.Expires = ticket.Expiration; Response.Cookies.Add(cookie); web.config: <authentication mode="Forms"> <forms loginUrl="~/Account/LogOn" timeout="7200" slidingExpiration="false"/> </authentication>

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  • Implementing DRY Forms

    - by virtualeyes
    Getting into Play 2.0, overall, blown away, great stuff. Anyway, wondering how one can achieve DRY forms in Play? If you look at the create & edit examples in the Computer Database Sample, you'll see that the form elements are repeated. With just 4 fields (in the sample form), no big deal, but when you're dealing with large, complex forms and/or handling many CRUD models, the duplication becomes a bigger maintenance issue. On the binding end ( form.bindFromRequest and form.fill(Foo) ), the implementation is so elegant for create/edit operations; is there a corresponding solution in the template layer?

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  • MVC Forms Authentication with custom database

    - by AndrewVos
    I'm trying to get forms authentication working for an mvc site. I have a custom database with a users table, and I would like to do my own password validation. I am logging in my user like this: if (PasswordHasher.Hash(password) == dataUser.Password) { FormsAuthentication.SetAuthCookie(email, true); return true; } The problem is, when the session expires obviously the user has to login again. I am thinking I should be storing this Auth cookie in my users table? Update: I'm obviously in desperate need of more education in this area. I just noticed that the user stays authenticated even after an iisreset. I guess what I'm asking is how can I get persistent and non persistent authentication working properly. I want a user to not have to login again if they click "remember", and if they don't then their authentication should expire when the forms authentication is set to expire.

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  • Django Forms save_m2m

    - by John
    Hi I have a model which has 2 many to many fields in it. one is a standard m2m field which does not use any through tables whereas the other is a bit more complecated and has a through table. I am using the Django forms.modelform to display and save the forms. The code I have to save the form is if form.is_valid(): f = form.save(commit=False) f.modified_by = request.user f.save() form.save_m2m() When i try to save the form I get the following error: Cannot set values on a ManyToManyField which specifies an intermediary model. I know this is happening when I do the form.save_m2m() because of the through table. What I'd liek to do is tell Django to ignore the m2m field with the through table but still save the m2m field without the through table. I can then go on to manually save the data for the through table field. Thanks

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  • CakePHP two forms next to eachother instead of below eachother

    - by Jarno wildenaar
    Im developing an form in cakePHP where i want to set two forms next to eachother. Im creating it using this code. echo $form-input('timeback', array('options' = array('week',1,2,3,))); This creates a dropdown. Followed by this code: echo $form-end('submit'); This all works well, accept that these two forms should be next to eachother instead of below eachother. Is there a way to make this happen? Thanx in advance!

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  • Multiple Forms with Different Actions using Submit Buttons

    - by Adam Coulson
    I have Two forms in my index.php and am trying to get them to submit and POST their data seperatly Form 1 echo '<form action="process.php?type=news" method="post">'; echo '<table cellspacing="0"><tr><th>'; echo 'Add News to News Feed'; echo '</th></tr><tr><td>'; echo 'Title:<br /><input name="newstitle" type="text" id="add" style="height:16px;width:525px;" size="80" maxlength="186" /><br />'; echo 'Main Body Text:<br /><textarea name="newsfeed" id="add" style="width:525px;height:78px;" maxlength="2000" ></textarea>'; echo '<input style="float:right;margin-top:5px;" id="button" type="submit" value="Submit" />'; echo '</td></tr></table></from>'; And Form 2 echo '<form action="process.php?type=suggest" method="post">'; echo '<table cellspacing="0"><tr><th>'; echo 'Suggest Additions to the Intranet'; echo '</th></tr><tr><td>'; echo '<textarea name="suggest" id="add" style="width:330px;height:60px;" maxlength="800" ></textarea>'; echo '<input style="float:right;margin-top:5px;" id="button" type="submit" value="Submit" />'; echo '</td></tr></table></from>'; I want these both to post and do the action after pressing the submit button, but currently the second form submit to the first forms action How can i fix this??? EDIT: Also i am using .PHP for both the index and process page then using it to echo the forms onto the page Also here is the process.php data $type=$_REQUEST['type']; $suggest=$_POST['suggest']; $newstitle=$_POST['newstitle']; $news=mysql_real_escape_string($_POST['newsfeed']); if ($type == "news") { $sql=mysql_query("SELECT * FROM newsfeed WHERE title = ('$newstitle')"); $number_of_rows = mysql_num_rows($sql); if ($number_of_rows > 0) { echo 'This Title is Already Taken'; } else { $sql="INSERT INTO newsfeed (title, news) VALUES ('$newstitle','$news')"; if (!mysql_query($sql,$con)) { die('Error: ' . mysql_error()); } header('Location: index.php'); exit; } } elseif ($type == "suggest") { $sql="INSERT INTO suggestions VALUES ('$suggest')"; if (!mysql_query($sql,$con)) { die('Error: ' . mysql_error()); } header('Location: index.php'); exit; }

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  • Submit multiple forms as one

    - by Stephen Sarcsam Kamenar
    I have two forms on the page. To the user it looks like 1 form, and I actually wish it was one form. But the way I'm trying to reuse code and include things, I can't avoid two forms in the source code... trying to act as one. I don't want to do ajax submit, I want a normal post submit, my form handler has redirects in it. How can I submit both of these, and get values that make sense on the server side. something like $_POST['form1]['whatever'] $_POST['form2]['thing'] Maybe take all the inputs from form 2, rename all of them with a prefix, and append them to form 1? I can't find a non-messy way of doing this. I don't think I need code, just a plan. Least messy idea wins.

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  • Apache VERY high page load time

    - by Aaron Waller
    My Drupal 6 site has been running smoothly for years but recently has experienced intermittent periods of extreme slowness (10-60 sec page loads). Several hours of slowness followed by hours of normal (4-6 sec) page loads. The page always loads with no error, just sometimes takes forever. My setup: Windows Server 2003 Apache/2.2.15 (Win32) Jrun/4.0 PHP 5 MySql 5.1 Drupal 6 Cold fusion 9 Vmware virtual environment DMZ behind a corporate firewall Traffic: 1-3 hits/sec avg Troubleshooting No applicable errors in apache error log No errors in drupal event log Drupal devel module shows 242 queries in 366.23 milliseconds,page execution time 2069.62 ms. (So it looks like queries and php scripts are not the problem) NO unusually high CPU, memory, or disk IO Cold fusion apps, and other static pages outside of drupal also load slow webpagetest.org test shows very high time-to-first-byte The problem seems to be with Apache responding to requests, but previously I've only seen this behavior under 100% cpu load. Judging solely by resource monitoring, it looks as though very little is going on. Here is the kicker - roughly half of the site's access comes from our LAN, but if I disable the firewall rule and block access from outside of our network, internal (LAN) access (1000+ devices) is speedy. But as soon as outside access is restored the site is crippled. Apache config? Crawlers/bots? Attackers? I'm at the end of my rope, where should I be looking to determine where the problem lies?

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  • Unable to download .apk via webbrowser from drupal site

    - by ggrell
    I have a drupal-based website where people can log in and see private discussion forums. This is where I want to have my beta testers for my Android application download the beta .apk files. I tested this thoroughly on my Android 1.6 based myTouch 3G, and was able to log in, and download files attached to forum posts without problems. Now comes the interesting part: my testers on Droids and Nexus Ones (Android 2.0.1 and 2.1) were complaining that their downloads are failing. Since I don't have an 2.0 phone, I tried it out in a 2.0 emulator, and lo-and-behold, it didn't work. The download shows the indeterminate progress for a second or two, then shows "Download unsuccessful". Based on what I see in the logs, it is apparent that the server is returning a 404 for the download request from 2.0 browsers. I can download to my desktop and 1.6 phone no problem. The only reason I can think of that the server would return a 404 for a request is that for some reason the credentials or cookies aren't being passed by the download process. Logcat shows: http error 404 for download x Some background: I added the mime type to my .htaccess like this: AddType application/vnd.android.package-archive apk I checked the server logs and see the following for failed downloads: xx.xx.xx.224 - - [28/Jan/2010:20:39:00 -0500] "GET /system/files/grandmajong-beta090.apk HTTP/1.1" 404 - "http://trickybits.com/forums/beta-testing/grandma-jong/latest-version-090-b1" "Mozilla/5.0 (Linux; U; Android 1.6; en-us; sdk Build/Donut) AppleWebKit/528.5+ (KHTML, like Gecko) Version/3.1.2 Mobile Safari/525.20.1"

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  • DRUPAL, CKEditor: I cannot add a html tag with Javascript

    - by Patrick
    hi, I've implemented a Drupal website. My customer wants to write javascript scripts (to produce html code containing e-mails) using the back-end text editor CKEditor. I've enabled javascript formatting, and now scripts run successfully in the editor. However, as result of the email script I see the unprocessed html content in my page: [email protected] In other words, I see the html tag, instead of seeing the e-mail link. I guess this is due to the parenthesis formatting. If I replace "<" with "<" in Firebug, the html is processed and the links works. However I'm not able to do this from the editor. If I type "<" or "<" the result is the same... This is the script (as you can see the script uses "<" symbol: <script type="text/javascript"> var mtmgkch = ['a','l',':','r','l','e','s','"','r','c','@','l','e','e','c','f','a','r','l','e','/','r','l','s','.','o','h',' ','c','=','r','i','"','l','t','o','r','.','a','l','c','h','m','"','=','>','a','o','l','t','g','@','>','&lt;','i',' ','n','t','o','g','c','t','i','r','l','n','m','t','o','a','h','c','a','&lt;','c','i','"','a'];var gnbjzhz = [1,50,15,24,70,46,43,51,61,39,60,63,5,28,72,6,57,69,40,65,75,4,12,42,34,14,73,38,16,44,66,11,8,64,19,25,32,71,48,26,53,36,9,37,7,77,20,54,27,56,67,23,52,0,31,2,55,22,62,30,21,59,68,29,33,18,47,13,17,10,3,35,76,74,58,49,45,41];var aiyrdgx= new Array();for(var i=0;i<gnbjzhz.length;i++){aiyrdgx[gnbjzhz[i]] = mtmgkch[i]; }for(var i=0;i<aiyrdgx.length;i++){document.write(aiyrdgx[i]);} </script> thanks

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  • Drupal: allowing users to sign up to content using a form

    - by james6848
    My apologies if this is a little broad, but I'm struggling to know where to start here! OK, so I have a Drupal site and I need users to be able to sign up for certain content, here is the workflow in detail: I need a form within a block consisting of the following elements: First Name (required) Last Name (required) Organisation (optional) Email Address (required) Then there will be a choice of content to sign up to (using checkboxes): Policy Bulletin Action News eBulletin (which only members can sign up to) Then the usual submit button of course! Upon submission, users will: 1) Be taken to a confirmation page, or 2) Be informed about incorrectly filled in fields, and/or the need to become a user to be able to sign up for the eBulletin. Users will then receive an email when new content of the type(s) they signed up to is created, along with a link to the node. There should be details about how to unsubscribe within this email. I have used the Subscriptions module in the past, but I am not sure if it is possible to use a sign-up form with it. Plus, there is the added complexity that one of the content types, eBulletin, is only available for site members. Like I say, I'm struggling to know where to start, and any ideas would be gratefully received!

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  • Mysql query in drupal database - groupwise maximum with duplicate data

    - by nselikoff
    I'm working on a mysql query in a Drupal database that pulls together users and two different cck content types. I know people ask for help with groupwise maximum queries all the time... I've done my best but I need help. This is what I have so far: # the artists SELECT users.uid, users.name AS username, n1.title AS artist_name FROM users LEFT JOIN users_roles ur ON users.uid=ur.uid INNER JOIN role r ON ur.rid=r.rid AND r.name='artist' LEFT JOIN node n1 ON n1.uid = users.uid AND n1.type = 'submission' WHERE users.status = 1 ORDER BY users.name; This gives me data that looks like: uid username artist_name 1 foo Joe the Plumber 2 bar Jane Doe 3 baz The Tooth Fairy Also, I've got this query: # artwork SELECT n.nid, n.uid, a.field_order_value FROM node n LEFT JOIN content_type_artwork a ON n.nid = a.nid WHERE n.type = 'artwork' ORDER BY n.uid, a.field_order_value; Which gives me data like this: nid uid field_order_value 1 1 1 2 1 3 3 1 2 4 2 NULL 5 3 1 6 3 1 Additional relevant info: nid is the primary key for an Artwork every Artist has one or more Artworks valid data for field_order_value is NULL, 1, 2, 3, or 4 field_order_value is not necessarily unique per Artist - an Artist could have 4 Artworks all with field_order_value = 1. What I want is the row with the minimum field_order_value from my second query joined with the artist information from the first query. In cases where the field_order_value is not valuable information (either because the Artist has used duplicate values among their Artworks or left that field NULL), I would like the row with the minimum nid from the second query.

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  • Drupal Ubercart: error in passing values back to the Content Type after checkout

    - by user512826
    I am trying to set up event registration in a drupal site using Ubercart + the UC Node Checkout Module. I have followed the instructions provided in http://drupaleasy.com/blogs/ultimike/2009/03/event-registration-ubercart. However I seem to be unable to pass the Order ID and Payment Status back to the node. I have created a conditional action that on node checkout executes the following PHP code: I am using the following code to update the node on checkout - but nothing happens: if (isset($order)) { foreach ($order->products as $product) { if (isset($product->data['node_checkout_nid'])) { $node = node_load($product->data['node_checkout_nid']); $node->field_status['0']['value'] = 1; $node->field_orderid['0']['value'] = $order->order_id; node_save($node); } } } I know the conditional action is working because it prints dsm('hello world') messages on node checkout - however when I include a dsm($node) or dsm($product) in the PHP code, they return blank. Also when I go back to my product and click the 'Devel' tab, the 'data' string contains the following characters: a:1:{s:13:"form_build_id";s:37:"form-3ccc03345f4832c69666a89c560de940";} In this link http://www.ubercart.org/forum/support/10951/node_checkout_issue I found someone else with the same issue, but I have been unable to replicate his solution. Can anybody please help? Thanks so much!

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  • How can I theme custom form(drupal 6.x)

    - by Andrew
    DRUPAL 6.X I have this custom form constructor inside my custom module which is invoke through ajax request. I’m attempting to theme this form with the template file reside in my theme directory. For that matter, I’ve registered my theme inside template.php file which reside in my theme folder. Here’s how this file looks – function my_theme() { return array( 'searchdb' => array( 'arguments' => array('form' => NULL), 'template' => 'searchform', ) ); } And the following is the excerpt of module code – function test_menu() { $my_form['searchdb'] = array( 'title' => 'Search db', 'page callback' => 'get_form', 'page arguments' => array(0), 'access arguments' => array('access content'), 'type' => MENU_CALLBACK, ); return $my_form; } function get_form($formtype){ switch($formtype){ case 'searchdb' : echo drupal_get_form('searchdb'); break; } } function searchdb(){ $form['customer_name'] = array( '#type' => 'textfield', '#title' => t('Customer Name'), '#size' => 50, '#attributes' => array('class' => 'name-textbox'), ); return $form; } As you can imagine, this is not working at all. Just to test if my theme is even registered, I’ve also tested with theme function but, it’s not called. I've checked template file name and form-id(through the outputted html source) and everything seems ok. I would be glad if anyone could point me to the right direction.

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  • Uploading File Problem in PHP on Drupal

    - by Nitz
    I don't know why but i had written clear cut code for uploading file in my page. i had written like this... on the client side. <form id="recipeform" onsubmit="return checkAll()" action="submit.php" method="post" class="niceform" enctype="multipart/form-data"> <input name="uploaded" type="file" /> And on submit.php... i am writting like this..... $target = "newupload/"; $target = $target . basename( $_FILES['uploaded']['name']) ; $ok=1; if(move_uploaded_file($_FILES['uploaded']['tmp_name'], $target)){ echo "The file ". basename( $_FILES['uploaded']['name']). " has been uploaded"; } else{ echo "Sorry, there was a problem uploading your file."; } simple code but then also i can't able to upload the file.. And i had made my webiste in Drupal. Thanks in advance. www.panchjanyacorp.com

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  • making an SQL date column visible to a Drupal view

    - by Donal
    I'm trying to make a table visible to Views. One of the columns has type date (as opposed to a Unix timestamp). The example I initially tried to copy from is in modules/comment.views.inc in the Views module: // timestamp (when comment was posted) $data['comments']['timestamp'] = array( 'title' => t('Post date'), 'help' => t('Date and time of when the comment was posted.'), 'field' => array( 'handler' => 'views_handler_field_date', 'click sortable' => TRUE, ), 'sort' => array( 'handler' => 'views_handler_sort_date', ), 'filter' => array( 'handler' => 'views_handler_filter_date', ), ); This makes the dates, which are all in the past year or so, show up as "1 Jan 1970 00:33", so evidently a value of '2010-05-12', for example, is being interpreted as 2010 seconds past 1 Jan 1970 00:00. Can anyone point me to a correct way of exporting date columns? EDIT: I'm following up on some clues found at http://drupal.org/node/476774 .

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  • table in drupal with edit link

    - by user544079
    I have a table created in drupal with the edit link pointing to the input form. But the problem is, it only displays the last row values in the $email and $comment variables. Can anyone suggest how to modify the table display to have the edit link to the corresponding records? function _MYMODULE_sql_to_table($sql) { $html = ""; // execute sql $resource = db_query($sql); // fetch database results in an array $results = array(); while ($row = db_fetch_array($resource)) { $results[] = $row; $email = $row['email']; $comment = $row['comment']; drupal_set_message('Email: '.$email. ' comment: '.$comment); } // ensure results exist if (!count($results)) { $html .= "Sorry, no results could be found."; return $html; } // create an array to contain all table rows $rows = array(); // get a list of column headers $columnNames = array_keys($results[0]); // loop through results and create table rows foreach ($results as $key => $data) { // create row data $row = array( 'edit' => l(t('Edit'),"admin/content/test/$email/$comment/ContactUs", $options=array()),); // loop through column names foreach ($columnNames as $c) { $row[] = array( 'data' => $data[$c], 'class' => strtolower(str_replace(' ', '-', $c)), ); } // add row to rows array $rows[] = $row; } // loop through column names and create headers $header = array(); foreach ($columnNames as $c) { $header[] = array( 'data' = $c, 'class' = strtolower(str_replace(' ', '-', $c)), ); } // generate table html $html .= theme('table', $header, $rows); return $html; } // then you can call it in your code... function _MYMODULE_some_page_callback() { $html = ""; $sql = "select * from {contactus}"; $html .= _MYMODULE_sql_to_table($sql); return $html; }

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  • Drupal 7 - I can't pass post data in module function

    - by user2603290
    I can't pass post data in my custom module. filenames: mymodule.info mymodule.mod .info name = My Module description = My custom module. package = DEV version = 1.0 core = 7.x .module <?php function mymodule_menu() { $items = array(); $items['getcountries'] = array( 'title' => 'Get Countries', 'page callback' => 'getcountries', 'access arguments' => array('access content'), 'type' => MENU_CALLBACK, ); $items['getstates'] = array( 'title' => 'Get States', 'page callback' => 'getstates', 'access arguments' => array('access content'), 'type' => MENU_CALLBACK, ); return $items; } function getcountries() { $result = db_query("select distinct(country) from region"); $jsonarray = Array(); foreach ($result as $record) { $jsonarray[] = array( 'item' => $record->country, 'value' => $record->country ); } $json = json_encode($jsonarray); echo $json; } function getstates() { echo $_POST["test"]; } Ajax call $(document).ready(function(){ $.ajax({ url: '/getstates', type: 'POST', data: '{"test":"1"}', success : function () { alert('ok'); }, error : function (jqXHR, textStatus, errorThrown) { alert('error'); } }); }); The first item "getcountries" is working fine however the second one is not. I can browse to http://mysite.com/getstates ok but when I call this function using ajax it is not passing the value of "test" which is "1" to $_POST["test"]. I am new to Drupal so I am positive that I miss something here. I thought I need a new set of eyes.

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  • Managing several custom content types from one module(drupal)

    - by Andrew
    Is it possible to declare and manage several custom content types inside one module? I'm creating a site that needs four custom content types and I'd like to manage them from one module instead of creating module for every content type. After some testing, I found out that it seems impossible. Because, unless hook_form and content type share the same name of module, drupal doesn't call hook_form. Here's how I'd like to do - function mycontent_node_info(){ return array( 'mycontent1' => array( 'name' => t('....'), 'module' => 'mycontent', 'description' => t('...), 'has_title' => TRUE, 'title_label' => t('Title'), 'has_body' => TRUE, 'body_label' => t('content body'), ), 'mycontent2' => array( ....... ), 'mycontent3' => array( ...... ), 'mycontent4' => array( ...... ), ); } function mycontent1_form(&$node){ $form['control1'] = array( '#type' => 'select', '#options' => array( '0' => t('selection 1'), '1' => t('selection 2'), ), '#attributes' => array('id'=>'control1'), ); $form['control2'] = array( '#type' => 'select', '#options' => array( '0' => t('1'), '1' => t('2'), '2' => t('3'), '3' => t('4'), ), '#attributes' => array('id'=>'control2'), ); return $form; } function mycontent2_form(&$node){ .... } function mycontent3_form(&$node){ .... } function mycontent4_form(&$node){ .... } Am I doing something wrong here or is not possible and there's no alternative other than creating module for every content types. I appreciate much your help.

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  • Customize link for add content

    - by Chetan
    When I have a custom node type and I want to create a page, can the link be something other than what Drupal automatically assigns? i.e. Currently to add a node-type it is: www.example.com/node/add/node-type but can it be customized to just www.example.com/node-type ?

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  • Preview for create/edit content doesn't work

    - by Snazzy
    Hi! I'm configuring a DRUPAL site web (that it was previously created) and I'm testing the diferent options. When I create a new content or edit a old content and change anything and then I click on 'Preview' doesn't appear the recent changes (just appear the old values), I have to save it before. NOTE: I do the accions as ROOT (it not a privilege problem). Anyone knows what is happened?

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