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• EntityFramework: Access dabase-column using user defined Type

  - by Nils

  I "inherited" an old Database where dates are stored as Int32 values (times too, but dates shall suffice for this example) i.e. 20090101 for Jan. 1st 2009. I can not change the schema of this database because it is still accessed by the old programs. However I want to write a new program using EF as the O/R-M. Now I'd love to have DateTime-Values in my Model. Is there a way to write a custom type and use this as a Type in the EF-Model. Something like a Type "OldDate" with properties: DatabaseValue : Int23 Value : DateTime (specifying the date-part whereas the time-part is always 0:00:00) Is something like this possible with the EF-Model ?

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• Reading the Set-Cookie instructions in an HTTP Response header

  - by Eduardo León

  Is there any standard means in PHP to read the Set-Cookie instructions in an HTTP Response header, without manually parsing it? More specifically, I want to read the value of the ASP.NET_SessionId cookie returned by an ASP.NET Web Service I am consuming. EDIT: I am consuming the Web Service using PHP's native SoapClient class. I can use the __getLastResponseHeaders() method to retrieve the whole of the HTTP response header returned by the Web Service: HTTP/1.1 200 OK Cache-Control: private, max-age=0 Content-Type: text/xml; charset=utf-8 Server: Microsoft-IIS/7.5 Set-Cookie: ASP.NET_SessionId=ku501l55o300ik3sa2gu3vzj; path=/; HttpOnly X-AspNet-Version: 2.0.50727 X-Powered-By: ASP.NET Date: Tue, 11 Jan 2011 23:34:02 GMT Content-Length: 368 But I want to extract the value of the ASP.NET_SessionID cookie: ku501l55o300ik3sa2gu3vzj And, of course, I don't want to do it manually.

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• XSLT 1.0: Sorting by concating portions of date string

  - by dscl

  I'm trying to take XML data and sort elements by their data attribute. Unfortunately the dates come over in mm/dd/yyyy format and are not static lengths. (Jan = 1 instead of 01) So I believe the string will have to be parsed into three components and the month padded. The newly concated value (yyyymmdd) then sorted descending. Problem is I have no idea how to do this. Here is an example of the data <content date="1/13/2011 1:21:00 PM"> <collection vo="promotion"> <data vo="promotion" promotionid="64526" code="101P031" startdate="1/7/2011 12:00:00 AM"/> <data vo="promotion" promotionid="64646" code="101P026" startdate="2/19/2011 12:00:00 AM"/> <data vo="promotion" promotionid="64636" code="101P046" startdate="1/9/2011 12:00:00 AM"/> </collection> </content> Also can anyone please recommend a good book on learning XSLT? Thanks!

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• R webscraping: interrogating for date and importance

  - by adam.888

  I am able to webscrape a table from a webpage containing news library(XML) webpage <- "http://www.tradingeconomics.com/calendar" tables <- readHTMLTable(webpage ) n.rows <- unlist(lapply(tables, function(t) dim(t)[1])) dfcal <- as.data.frame(tables$calendar) However I do not know how to interrogate for date or for importance. For example how could I webscrape news from Jan 2014? I am able to do this on the webpage by altering button settings, but how can I do it from within R? I was also not able to collect the importance column data. Also are there better ways for collecting economic news from within R? I have looked on http://www.rseek.org/ but could not find anything. Thank you for your help.

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• How do you convert date taken from a bash script to milliseconds in java program?

  - by Matt Pascoe

  I am writing a piece of code in java that needs to take a time sent from a bash script and parse the time to milliseconds. When I check the millisecond conversion on the date everything is correct except for the month I have sent which is January instead of March. Here is the variable I create in the bash script, which later in the script I pass to the java program: TIME=`date +%m%d%Y_%H:%M:%S` Here is the java code which parses the time to milliseconds: String dt = "${scriptstart}"; java.text.SimpleDateFormat scriptStart = new java.text.SimpleDateFormat("MMDDyyyy_HH:mm:ss"); long start = scriptStart.parse(dt).getTime(); The goal of this statement is to find the elapsed time between the start of the script and the current system time. To troubleshoot this I printed out the two: System Time = 1269898069496 (converted = Mon Mar 29 2010 16:27:49 GMT-0500 (Central Daylight Time)) Script Start = 03292010_16:27:45 Script Start in Milli = 1264804065000 (Converted = Fri Jan 29 2010 16:27:45 GMT-0600 (Central Standard Time))

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• processing a file full of unix time strings to human readble

  - by skymook

  I am processing a file full of unix time strings. I want to convert them all to human readable. The file looks like so: 1153335401 1153448586 1153476729 1153494310 1153603662 1153640211 Here is the script: #! /bin/bash FILE="test.txt" cat $FILE | while read line; do perl -e 'print scalar(gmtime($line)), "\n"' done This is not working. The output I get is Thu Jan 1 00:00:00 1970 for every line. I think the line breaks are being picked up and that is why it is not working. Any ideas? I'm using Mac OSX is that makes any difference.

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• Help with dates in Android

  - by SamRowley

  Hi guys, Looking for a bit of help with taking a dat from a DatePicker Widget and storing it in an sqlite database within the app. I have the following code: java.util.Date utilDate = null; String y = Integer.toString(date.getDayOfMonth()) + "/" + (date.getMonth()+1) + "/" + Integer.toString(date.getYear()); SimpleDateFormat formatter = new SimpleDateFormat("dd/MM/yyy"); utilDate = formatter.parse(y); java.sql.Date z = new java.sql.Date(utilDate.getDate()); x = z.toString(); Log.v("The date: ", x); } Where date is the DatePicker widget. If I output the utilDate variable (i.e. the Java version of date) using logCat it seems to work fine and gives me a format like: Tue Jan 04 00:00:00 GMT 2011 which I am expecting but using the code above to get the sql version of the date, it always gives me the date 1970-01-01. I'm pretty sure the solution is very simple but I just can't see it.

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• rearranging a list of months

  - by MacUsers

  How can I list the numbers 01 to 12 (one for each of the 12 months) in such a way so that the current month always comes last where the oldest one is first. In other words, if the number is grater than the current month, it's from the previous year. e.g. 02 is Feb, 2011 (the current month right now), 03 is March, 2010 and 09 is Sep, 2010 but 01 is Jan, 2011. In this case, I'd like to have [09, 03, 01, 02]. This is what I'm doing to determine the year: for inFile in os.listdir('.'): if inFile.isdigit(): month = months[int(inFile)] if int(inFile) <= int(strftime("%m")): year = strftime("%Y") else: year = int(strftime("%Y"))-1 mnYear = month + ", " + str(year) I don't have a clue what to do next. What should I do here?

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• Darwin kernel architecture and OS X, 64bit on 32bit kernel, how does this work?

  - by overscore

  The OS X Lion (10.7) OS runs on mostly 64-bit binaries as reported by Activity Monitor. Given this, and the fact that my laptop runs a 32-bit version of the EFI and thus also a 32-bit kernel, how does the arch mixing work in general? Darwin Kernel Version 11.3.0: Thu Jan 12 18:48:32 PST 2012; root:xnu-1699.24.23~1/RELEASE_I386 Normally one would run 32b binaries on x86_64, but the other way around would require pushing the cpu into 64b mode, which AFAIK cannot be undone. Hope this question is clear enough..

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• Javascript code for serial img loading

  - by Surfer

  Hi everyone, I am new to javascript. I want a javascript code with which i can load an image which is named for every day/month/year. in a serial i have the following code : var year = new Array(); year = ["08", "09", "10", "11"]; var month = new Array(); month = ["JAN", "FEB", "MAR", "APR", "MAY", "JUN", "JULY", "AUG", "SEP", "OCT", "NOV", "DEC"]; var date = new Array(); date = ["01", "02", "03", "04", "05", "06", "07", "08", "09", "10", "11", "12", "13", "14", "15", "16", "17", "18", "19", "20", "21", "22", "23", "24", "25", "26", "27", "28", "29", "30", "31"]; var ims = ""; for (var x in year) { for (var y in month) { for (var z in date) { ims += "<im src=screencover/img/" + date[z] + "" + month[y] + "20" + year[0] + ".png>"; } } } document.write(ims);

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• Long to timestamp for historic data (pre-1900s)

  - by Mike

  I have a database of start and stop times that have previously all had fairly recent data (1960s through present day) which i've been able to store as long integers. This is very simialr to unix timestamps, only with millisecond precision, so a function like java.util.Date.getTime() would be the value of the current time. This has worked well so far, but we recently got data from the 1860s, and the following code no longer works: to_timestamp('1-JAN-1970 00:00:00', 'dd-mon-yyyy hh24:mi:ss') + numtodsinterval(int_to_convert/(1000),'SECOND' ); This wraps the date and we get timestamps in the year 2038. Is there a way around this issue? All of the documentation i've looked at the documentation and timestamps should be able to handle years all the way back to the -4000 (BC), so i'm suspecting an issue with the numtodsinterval. Any ideas suggestions would be greatly appreciated.

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• C# DataTable to Json?

  - by AliRiza Adiyahsi

  I want to get DataTable as Json Format to show it on a chart. public JsonResult GetDataTable() { DataTable dt = new DataTable(); dt.Columns.Add("Jan"); dt.Columns.Add("Feb"); dt.Columns.Add("Mar"); dt.Columns.Add("Apr"); for (int i = 0; i < 10; i++) { dt.Rows.Add(i * 5, i * 10, i * 15, i * 11); } // JsonDataTable = dt to Json return new JsonResult { Data = new { success = true, chartData = JsonDataTable }, JsonRequestBehavior = JsonRequestBehavior.AllowGet }; } How Can I convert DataTable to Json? Thanks.

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• test php disabled caching

  - by user1691389

  My site had a problem in that certain browsers (especially opera and gecko) were "over-caching" (caching far too much for my taste). I've just added the following PHP snippet to hopefully disable caching in all browsers: <?php header("Expires: Tue, 01 Jan 2000 00:00:00 GMT"); header("Last-Modified: " . gmdate("D, d M Y H:i:s") . " GMT"); header("Cache-Control: no-store, no-cache, must-revalidate, max-age=0"); header("Cache-Control: post-check=0, pre-check=0", false); header("Pragma: no-cache"); ?> Question: How would you test this out, to make sure it actually works?

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• Prevent RegEx Hang on Large Matches...

  - by developerjay

  This is a great regular expression for dates... However it hangs indefinitely on this one page I tried... I wanted to try this page ( http://pleac.sourceforge.net/pleac%5Fpython/datesandtimes.html ) for the fact that it does have lots of dates on it and I want to grab all of them. I don't understand why it is hanging when it doesn't on other pages... Why is my regexp hanging and/or how could I clean it up to make it better/efficient ? Python Code: monthnames = "(?:Jan\w*|Feb\w*|Mar\w*|Apr\w*|May|Jun\w?|Jul\w?|Aug\w*|Sep\w*|Oct\w*|Nov(?:ember)?|Dec\w*)" pattern1 = re.compile(r"(\d{1,4}[\/\\\-]+\d{1,2}[\/\\\-]+\d{2,4})") pattern4 = re.compile(r"(?:[\d]*[\,\.\ \-]+)*%s(?:[\,\.\ \-]+[\d]+[stndrh]*)+[:\d]*[\ ]?(PM)?(AM)?([\ \-\+\d]{4,7}|[UTCESTGMT\ ]{2,4})*"%monthnames, re.I) patterns = [pattern4, pattern1] for pattern in patterns: print re.findall(pattern, s) btw... when i say im trying it against this site.. I'm trying it against the webpage source.

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• MySQL : Calculate business day difference between two dates column

  - by yokoyoko

  My sql query returns back two columns, first column is "date created" and second column is "date updated", first column has a prior timestamp with respect to second column. I need to add a third column which can display business day hrs (9:00am to 5:00pm) response i.e. if date created is 2012-01-01 09:00:20 and "dated updated" is 4:00pm same day then third column should display 7 hrs If date created is 2012-01-01 16:00:20 (4:00pm) and "date updated" is 10:00m on 2012:01:02 (2nd Jan) then third column should display 2 hrs. It should exclude Saturday and Sunday. Can you please suggest appropriate SQL query for this.

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• show count of rows between 2 dates

  - by hello

  I am trying to show the number of rows that have a created_at date between 2 dates. Here is my code: $result=mysql_query("select * from payments where created_at between '2013/10/01 00:00:00' and '2013/10/30 00:00:00'") or die('You need to add an administrator ' ); $counter = mysql_query("select * from payments where created_at between '2013/10/01 00:00:00' and '2013/10/30 00:00:00'"); $row = mysql_fetch_array($result); $id = $row['id']; $num = mysql_fetch_array($counter); $countjan = $num["id"]; However when i echo (<?php echo"$jan";?>)this shows as 0 any idea how i can get this to work P.s there is 1 row within this date range

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• Whats wrong with my makefile

  - by user577220

  ##################################################################### # This is the filesystem makefile "make_BuddyAlloc". # Author:Michael Gomes # Date:2 jan 2011 ###################################################################### #variable defination CC = gcc CFLAGS = -g -O2 SRC_DIR=src INC_DIR=inc OBJ_DIR=obj #List of source files SOURCE= buddyMain.c \ Copy.c \ #List of object files OBJECTS=$(addprefix $(OBJ_DIR)/,$(SOURCE:.c=.o)) #BuddyAlloc is dependent on "obj/*.o". BuddyAlloc : $(OBJECTS) $(CC) $(CFLAGS) -o BuddyAlloc $< #obj/*.o depends on src/*.c and inc/*.h, we are redirecting the object files to obj folder $(OBJECTS):$(SRC_DIR)/$(SOURCE) $(CC) $(CFLAGS) -I$(INC_DIR) -o $(OBJ_DIR)/$(OBJECTS) -c $< #Cleans all the *.exe files clean: rm -f *.exe I have kept the source files under src folder includes under inc folder and the object files are being saved in obj folder .given above is the makefile i am trying to create for my mini project. I keep getting the error no rule to make target 'Copy.c' needed by 'obj/buddyAlloc.o', but it works fine it i dont include Copy.c, what did i do wrong?

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• Deleting a cookie in Javascript not working

  - by DisgruntledGoat

  I have a site where authentication is done externally (which I can't access), so I'm creating a cookie on login in order to display a welcome message to the user. Creating the cookie works fine, I write to document.cookie when the login form submits. But deleting the cookie doesn't work. Here's my code (logout.php does the external authentication stuff): <a href="http://external.com/logout.php" style="float:right" onclick="document.cookie='BRLOG=; expires=Thu, 01-Jan-1970 00:00:01 GMT; path=/; domain=.example.com;'">Logout</a>

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• Find first cell in a row that contains a number?

  - by Dexter

  I'm working in Excel with an exported table such as this: |-------------------------------------------------------------------------------| | | A | B | C | D | E | F | G | H | I | |---|-------------------|-----|-----|-----|-----|-----|-------|-----|-----------| | 1 | Domain | JAN | FEB | MAR | APR | MAY | Start | End | Change | |---|-------------------|-----|-----|-----|-----|-----|-------|-----|-----------| | 2 | www.mydomain1.com | | 1 | 4 | 3 | 1 | 1 | 1 | 0 | |---|-------------------|-----|-----|-----|-----|-----|-------|-----|-----------| | 3 | www.mydomain2.com | 2 | 4 | 12 | 18 | 23 | 2 | 23 | 21 | |---|-------------------|-----|-----|-----|-----|-----|-------|-----|-----------| | 4 | www.mydomain3.com | | | 14 | 12 | | 14 | xxx | NOT FOUND | |-------------------------------------------------------------------------------| I'm trying to compare the current state (last cell) to the original cell (first cell with a value). In column I, I have the formula =IF(G2 = "xxx", "NOT FOUND", IF(H2 = "xxx", "NOT FOUND", H2 - G2)) In column H, I have the formula =IF(F2 = "", "xxx", F2) In column G, I need to find the first cell with a number. If there isn't one in that range, I need G to be "xxx". I suppose I only need to check for the first cell in the range (B2 to F2) that contains a value, not just a number. I tried using an Index and Match combo, but I couldn't quite understand it.

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• "Passing Go" in a (python) date range

  - by anonymous coward

  The Rules: An employee accrues 8 hours of Paid Time Off on the day after each quarter. Quarters, specifically being: Jan 1 - Mar 31 Apr 1 - Jun 30 Jul 1 - Sep 30 Oct 1 - Dec 31 The Problem Employees will use an automated system to request paid time off, possibly occurring in the past, as well as the future. Requests should only be accepted if the employee has (or will have) that time available. For instance, if an employee only has 1 Day of Paid Time Off currently available (currently being January 20th), but is requesting 2 Days of Paid Time Off, beginning September 20th, the system should take into account that the employee would have accrued enough time off by then and allow the request. (Obviously ignoring that the employee may use up existing time before that date). I'm currently using Python, and wondering what the correct approach to something like this would be. I'm assuming that using DateTime objects, and possibly the dateutil module, would help here, but my brain isn't wrapping around this problem for some reason.

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• PHP query for totals of products for last six months

  - by user2260925

  I need to get the figures for the last six months from my orders table. The table has the following fields: qty, product, price, code, The format of the report must be as follows: Month: Jan Feb Mar Apr May June Product1 7 5 4 6 8 9 Product2 8 3 1 4 7 7 Product3 5 4 1 7 7 6 My current code gets the figures for one month only: "SELECT product,building, SUM(qty) AS 'month1' FROM sh_orders WHERE MONTH(order_date) = MONTH(CURDATE()) GROUP BY product"; The code to show it is: echo " <td> ". $row['product']. "</td> <td> ". $row['month1']. "</td>; Any help is greatly appreciated.

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• JQuery Slider, Need to Create a Slider with range as Current Date - 3 Months...

  - by Cozmoz

  I am new to Jquery but my task is to create a Slider in Jquery, which will have a range as Current Date to (Last 3 Months Date). Slider --------------------------------------------------------------------- (Below is Just a Reference, the Slider should have a callout box or an area to show the Current Date which is selected) 1-----------------31 | 1---------28 | 1---------30 | 1------Curr Date Jan Feb Mar Apr Also the Data should change according to the range selected. If anyone who has come across any such problem/solution please let me know, I would be more than grateful to him/her. Thanks!

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• HTTP Headers: Max-Age vs Expires – Which One To Choose?

  - by Gopinath

  Caching of static content like images, scripts, styles on the client browser reduces load on the webservers and also improves end users browsing experience by loading web pages quickly. We can use HTTP headers Expires or Cache-Control:max-age to cache content on client browser and set expiry time for them. Expire header is HTTP/1.0 standard and Cache-Control:max-age is introduced in HTTP/1.1 specification to solve the issues and limitation with Expire  header. Consider the following headers.   Cache-Control: max-age=24560 Expires: Tue, 15 May 2012 06:17:00 GMT The first header instructs web browsers to cache the content for 24560 seconds relative to the time the content is downloaded and expire it after the time period elapses. The second header instructs web browser to expiry the content after 15th May 2011 06:17. Out of these two options which one to use – max-age or expires? I prefer max-age header for the following reasons As max-age  is a relative value and in most of the cases it makes sense to set relative expiry date rather than an absolute expiry date. Expire  header values are complex to set – time format should be proper, time zones should be appropriate. Even a small mistake in settings these values results in unexpected behaviour. As Expire header values are absolute, we need to  keep changing them at regular intervals. Lets say if we set 2011 June 1 as expiry date to all the image files of this blog, on 2011 June 2 we should modify the expiry date to something like 2012 Jan 1. This add burden of managing the Expire headers. Related: Amazon S3 Tips: Quickly Add/Modify HTTP Headers To All Files Recursively cc image flickr:rogue3w This article titled,HTTP Headers: Max-Age vs Expires – Which One To Choose?, was originally published at Tech Dreams. Grab our rss feed or fan us on Facebook to get updates from us.

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• An increase to 3 Gig of RAM slows down Ubuntu 10.04 LTS

  - by williepabon

  I have Ubuntu 10.04 running from an external hard drive (installed on an enclosure) connected via USB port. Like a month or so ago, I increased RAM on my pc from 2 Gigs to 3 Gigs. This resulted on extremely long boot times and slow application loads. While I was understanding the nature of my problem, I posted various threads on this forum ( Questions # 188417, 188801), where I was advised to gather speed tests, and other info on my machine. I was also suggested that I might have problems with the RAM installed. Initially, I did not consider that possibility because: 1) I did a memory test with a diagnostic program from DELL (My pc is from Dell) 2) My pc works fine with Windows XP (the default OS), no problems with memory 3) My pc works fine when booting with Ubuntu 10.10 memory stick, no speed problems 4) My pc works fine when booting with Ubuntu 11.10 memory stick, no speed problems Anyway, I performed the memory tests suggested. But before doing it, and to check out any possibility of hardware issues on the hard drive, I did the following: (1) purchased a new hard drive enclosure and moved my hard drive to it, (2) purchased a new USB cable and used it to connect my hard drive/enclosure setup to a different USB port on my pc. Then, I performed speed tests with 1 Gig, 2 Gigs and 3 Gigs of RAM with my Ubuntu 10.04 OS. Ubuntu 10.04 worked well when booted with 1 Gig or 2 Gigs of RAM. When I increased to 3 Gigs, it slowed down to a crawl. I can't understand the relationship between an increase of 1 Gig and the effect it has in Ubuntu 10.04. This doesn't happen with Ubuntu 10.10 and 11.10. Unfortunately for me, Ubuntu 10.04 is my principal work operating system. So, I need a solution for this. Hardware and system information: DELL Precision 670 2 internal SATA Hard drives Audigy 2 ZS audio system Factory OS: Windows XP Professional SP3 NVidia 8400 GTS video card More info: williepabon@WP-WrkStation:~$ uname -a Linux WP-WrkStation 2.6.32-38-generic #83-Ubuntu SMP Wed Jan 4 11:13:04 UTC 2012 i686 GNU/Linux williepabon@WP-WrkStation:~$ lsb_release -a No LSB modules are available. Distributor ID: Ubuntu Description: Ubuntu 10.04.4 LTS Release: 10.04 Codename: lucid Speed test with the 3 Gigs of RAM installed: williepabon@WP-WrkStation:~$ sudo hdparm -tT /dev/sdc [sudo] password for williepabon: /dev/sdc: Timing cached reads: 84 MB in 2.00 seconds = 41.96 MB/sec Timing buffered disk reads: 4 MB in 3.81 seconds = 1.05 MB/sec This is a very slow transfer rate from a hard drive. I will really appreciate a solution or a work around for this problem. I know that that there are users that have Ubuntu 10.04 with 3 Gigs or more of RAM and they don't have this problem. Same question asked on Launchpad for reference.

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• Oracle's Australian Graduate Recruitment Program

  - by david.talamelli

  I have been with Oracle for 5 years now and one thing that I have found that there is never a shortage of here is - Variety. Over the last 5 years I have had the opportunity to work on projects across various countries, across various technologies and skill-sets and also across various level of seniority. No two days are the same. One of the projects I was fortunate to be involved in occurred last year and it is one of the ones that is closest to me. Last year I was able to take responsibility for our 2011 Graduate Recruitment drive in Australia. Two weeks ago I went to Sydney to meet our Graduates who started in February 2011 with us and it was great to see them come to the end (or beginning actually) of our journey together. I am excited at the potential of what our Graduates careers will develop into here with us. I remember at our interviewing last year trying to explain life in Oracle, it is great to see those same Graduates with us now learning and developing life and business skills that I hope they will take with them in their professional careers. I was talking to one of my colleagues this week who mentioned the excitement and energy that our new Graduates bring is infectious, and I agree it really is. Our Graduates have a big learning curve ahead of them and they are about to start going on rotations into some of our Business Groups - but I think it is a great experience to see how a global company operates and pulls together to achieve results together. Here is a picture we took the other week of this year's Oracle Graduates (if any of our Graduates are reading this blog - it was great seeing you in NSW and I do wish you all the success here at Oracle) Once again Oracle's Graduate Program will be running in 2011 in Australia (Graduates will start in Jan/Feb 2012). The Oracle Australia Graduate Development Program is a one-year program consisting of orientation, formal training, project rotations in one core line of business and finally job placement. The formal training is a combination of structured development programs on soft skills and functional competencies via various delivery formats. Graduates are also expected to work in a team environment and complete multiple projects addressing real business challenges and at the time gaining a broad business understanding. For our Australia program we are hiring in our North Ryde and Melbourne offices. Resume submissions are being accepted now. First Round interviews will take place in June 2011 with Final Round interviews in July 2011. The Australia Graduate Program is open to Australian Residents and Citizens who are either in the final year of their studies or have graduated the previous year. For more details on Oracle and our Graduate Program visit our Campus website To express your interest, mail your resume to [email protected]

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