Search Results

Search found 1300 results on 52 pages for 'mr putty'.

Page 33/52 | < Previous Page | 29 30 31 32 33 34 35 36 37 38 39 40  | Next Page >

• Server not accepting uploads

  - by Tatu Ulmanen

  I'm having a strange problem with my VPS: I can download files from it, I can use PuTTy to connect to it and all behaves normally. But sometimes, when I try to upload a file to the server or save a file via SFTP, the connection inexplicably fails. I am using jEdit to edit files remotely via SFTP. When it works, it works fine. When it doesn't, I get an error message: Cannot save: java.io.IOException: inputstream is closed Cannot save: java.io.IOException: 4: I can see that a temporary save file (#file.php#save#) is created on the server with a filesize of 0. So the connection works, but when it comes to sending the actual data, something fails. The same thing with WinSCP, but the error is different: Copying file fatally failed. Copying files to remote side failed. And I can always browse the server with PuTTy without a problem. I see nothing abnormal in any log files. Auth.log shows this when I try to save: sshd[32638]: Accepted password for - from - port 62272 ssh2 sshd[32638]: pam_unix(sshd:session): session opened for user - by (uid=0) sshd[32640]: subsystem request for sftp sshd[32638]: pam_unix(sshd:session): session closed for user - When I wait for a while (say, an hour), everything works fine again. It can't be a temporary ban, as I am still allowed to connect to the server, right? I know this may not be enough info to solve the problem, but I am grateful for any clues or bits of information that might help me. What are the possible causes for this kind of behaviour, what log files can I check for clues etc.. I'm running out of ideas!

  Read the article

• Can't see more than the first few lines in an SSH connection

  - by hello

  I need some help for SSH buffer size. I have a vista machine at home and i have installed "Free SSHD" on it. I also have Dynamic DNS setup to access some of my home lab equipment which are connected to this vista machine. From my work machine which is an XP machine I connect to my home machine using Putty. Everything up to this point is working fine without any problem. The issue is I can't see more lines than the first few lines of the output. I press the space bar to get more output off the screen and the output scrolls up and it gets lost as the more output gets displayed on the screen. The Putty client i am using on my work machine has been setup with enough buffer size but the output still only displays few lines and as it moves up, the buffer gets empty automatically. I have searched the entire web and haven’t found any proper solution any where. Can someone please help here? Thanks.

  Read the article

• Don&rsquo;t Kill the Password

  - by Anthony Trudeau

  A week ago Mr. Honan from Wired.com penned an article on security he titled “Kill the Password: Why a String of Characters Can’t Protect Us Anymore.” He asserts that the password is not effective and a new solution is needed. Unfortunately, Mr. Honan was a victim of hacking. As a result he has a victim’s vendetta. His conclusion is ill conceived even though there are smatterings of truth and good advice. The password is a security barrier much like a lock on your door. In of itself it’s not guaranteeing protection. You can have a good password akin to a steel reinforced door with the best lock money can buy, or you can have a poor password like “password” which is like a sliding lock like on a bathroom stall. But, just like in the real world a lock isn’t always enough. You can have a lock, security system, video cameras, guard dogs, and even armed security guards; but none of that guarantees your protection. Even top secret government agencies can be breached by someone who is just that good (as dramatized in movies like Mission Impossible). And that’s the crux of it. There are real hackers out there that are that good. Killer coding ninja monkeys do exist! We still have locks on our doors, because they still serve their role. Passwords are no different. Security doesn’t end with the password. Most people would agree that stuffing your mattress with your life savings isn’t a good idea even if you have the best locks and security system. Most people agree its safest to have the money in a bank. Essentially this is compartmentalization. Compartmentalization extends to the online world as well. You’re at risk if your online banking accounts are linked to the same account as your social networks. This is especially true if you’re lackadaisical about linking those social networks to outside sources including apps. The object here is to minimize the damage that can be done. An attacker should not be able to get into your bank account, because they breached your Twitter account. It’s time to prioritize once you’ve compartmentalized. This simply means deciding how much security you want for the different compartments which I’ll call security zones. Social networking applications like Facebook provide a lot of security features. However, security features are almost always a compromise with privacy and convenience. It’s similar to an engineering adage, but in this case it’s security, convenience, and privacy – pick two. For example, you might use a safe instead of bank to store your money, because the convenience of having your money closer or the privacy of not having the bank records is more important than the added security. The following are lists of security do’s and don’ts (these aren’t meant to be exhaustive and each could be an article in of themselves): Security Do’s: Use strong passwords based on a phrase Use encryption whenever you can (e.g. HTTPS in Facebook) Use a firewall (and learn to use it properly) Configure security on your router (including port blocking) Keep your operating system patched Make routine backups of important files Realize that if you’re not paying for it, you’re the product Security Don’ts Link accounts if at all possible Reuse passwords across your security zones Use real answers for security questions (e.g. mother’s maiden name) Trust anything you download Ignore message boxes shown by your system or browser Forget to test your backups Share your primary email indiscriminately Only you can decide your comfort level between convenience, privacy, and security. Attackers are going to find exploits in software. Software is complex and depends on other software. The exploits are the responsibility of the software company. But your security is always your responsibility. Complete security is an illusion. But, there is plenty you can do to minimize the risk online just like you do in the physical world. Be safe and enjoy what the Internet has to offer. I expect passwords to be necessary just as long as locks.

  Read the article

• Java Dragging an object from one area to another [on hold]

  - by user50369

  Hello I have a game where you drag bits of food around the screen. I want to be able to click on an ingredient and drag it to another part of the screen where I release the mouse. I am new to java so I do not really know how to do this please help me Here is me code. This is the class with the mouse listeners in it: public void mousePressed(MouseEvent e) { if (e.getButton() == MouseEvent.BUTTON1) { Comp.ml = true; // placing if (manager.title == true) { if (title.r.contains(Comp.mx, Comp.my)) { title.overview = true; } else if (title.r1.contains(Comp.mx, Comp.my)) { title.options = true; } else if (title.r2.contains(Comp.mx, Comp.my)) { System.exit(0); } } if (manager.option == true) { optionsMouse(e); } mouseinventory(e); } else if (e.getButton() == MouseEvent.BUTTON3) { Comp.mr = true; } } private void mouseinventory(MouseEvent e) { if (e.getButton() == MouseEvent.BUTTON1) { } else if (e.getButton() == MouseEvent.BUTTON1) { } } @Override public void mouseReleased(MouseEvent e) { if (e.getButton() == MouseEvent.BUTTON1) { Comp.ml = false; } else if (e.getButton() == MouseEvent.BUTTON3) { Comp.mr = false; } } @Override public void mouseDragged(MouseEvent e) { for(int i = 0; i < overview.im.ing.toArray().length; i ++){ if(overview.im.ing.get(i).r.contains(Comp.mx,Comp.my)){ overview.im.ing.get(i).newx = Comp.mx; overview.im.ing.get(i).newy = Comp.my; overview.im.ing.get(i).dragged = true; }else{ overview.im.ing.get(i).dragged = false; } } } @Override public void mouseMoved(MouseEvent e) { Comp.mx = e.getX(); Comp.my = e.getY(); // System.out.println("" + Comp.my); } This is the class called ingredient public abstract class Ingrediant { public int x,y,id,lastx,lasty,newx,newy; public boolean removed = false,dragged = false; public int width; public int height; public Rectangle r = new Rectangle(x,y,width,height); public Ingrediant(){ r = new Rectangle(x,y,width,height); } public abstract void tick(); public abstract void render(Graphics g); } and this is a class which extends ingredient called hagleave public class HagLeave extends Ingrediant { private Image img; public HagLeave(int x, int y, int id) { this.x = x; this.y = y; this.newx = x; this.newy = y; this.id = id; width = 75; height = 75; r = new Rectangle(x,y,width,height); } public void tick() { r = new Rectangle(x,y,width,height); if(!dragged){ x = newx; y = newy; } } public void render(Graphics g) { ImageIcon i2 = new ImageIcon("res/ingrediants/hagleave.png"); img = i2.getImage(); g.drawImage(img, x, y, null); g.setColor(Color.red); g.drawRect(r.x, r.y, r.width, r.height); } } The arraylist is in a class called ingrediantManager: public class IngrediantsManager { public ArrayList<Ingrediant> ing = new ArrayList<Ingrediant>(); public IngrediantsManager(){ ing.add(new HagLeave(100,200,1)); ing.add(new PigHair(70,300,2)); ing.add(new GiantsToe(100,400,3)); } public void tick(){ for(int i = 0; i < ing.toArray().length; i ++){ ing.get(i).tick(); if(ing.get(i).removed){ ing.remove(i); i--; } } } public void render(Graphics g){ for(int i = 0; i < ing.toArray().length; i ++){ ing.get(i).render(g); } } }

  Read the article

• Linq IQueryable variables

  - by kevinw

  Hi i have a function that should return me a string but what is is doing is bringing me back the sql expression that i am using on the database what have i done wrong public static IQueryable XMLtoProcess(string strConnection) { Datalayer.HameserveDataContext db = new HameserveDataContext(strConnection); var xml = from x in db.JobImports where x.Processed == false select new { x.Content }; return xml; } this is the code sample this is what i should be getting back <PMZEDITRI TRI_TXNNO="11127" TRI_TXNSEQ="1" TRI_CODE="600" TRI_SUBTYPE="1" TRI_STATUS="Busy" TRI_CRDATE="2008-02-25T00:00:00.0000000-00:00" TRI_CRTIME="54540" TRI_PRTIME="0" TRI_BATCH="" TRI_REF="" TRI_CPY="main" C1="DEPL" C2="007311856/001" C3="14:55" C4="CUB2201" C5="MR WILLIAM HOGG" C6="CS12085393" C7="CS" C8="Blocked drain" C9="Scheme: CIS Home Rescue edi tests" C10="MR WILLIAM HOGG" C11="74 CROMARTY" C12="OUSTON" C13="CHESTER LE STREET" C14="COUNTY DURHAM" C15="" C16="DH2 1JY" C17="" C18="" C19="" C20="" C21="CIS" C22="0018586965 ||" C23="BD" C24="W/DE/BD" C25="EX-DIRECTORY" C26="" C27="/" C28="CIS Home Rescue" C29="CIS Home Rescue Plus Insd" C30="Homeserve Claims Management Ltd|Upon successful completion of this repair the contractor must submit an itemised and costed Homeserve Claims Management Ltd Job Sheet." N1="79.9000" N2="68.0000" N3="11.9000" N4="0" N5="0" N6="0" D1="2008-02-25T00:00:00.0000000-00:00" T2="EX-DIRECTORY" T4="Blocked drain" TRI_SYSID="9" TRI_RETRY="3" TRI_RETRYTIME="0" /> can anyone help me please

  Read the article

• Trouble pre-populating drop down and textarea from MySQL Database

  - by Tony

  I am able to successfully pre-populate my questions using the following code: First Name: <input type="text" name="first_name" size="30" maxlength="20" value="' . $row[2] . '" /><br /> However, when I try to do the same for a drop down box and a textarea box, nothing is pre-populated from the database, even though there is actual content in the database. This is the code I'm using for the drop down and textarea, respectively: <?php echo ' <form action ="edit_contact.php" method="post"> <div class="contactfirstcolumn"> Prefix: <select name = "prefix" value="' . $row[0] . '" /> <option value="blank">--</option> <option value="Dr">Dr.</option> <option value="Mr">Mr.</option> <option value="Mrs">Mrs.</option> <option value="Ms">Ms.</option> </select><br />'; ?> AND Contact Description:<textarea id = "contactdesc" name="contactdesc" rows="3" cols="50" value="' . $row[20] . '" /></textarea><br /><br /> It's important to note that I am not receiving any errors. The form loads fine, however without the data for the drop down and textarea fields. Thanks! Tony

  Read the article

• LEFT OUTER JOIN in Linq - How to Force

  - by dodegaard

  I have a LEFT OUTER OUTER join in LINQ that is combining with the outer join condition and not providing the desired results. It is basically limiting my LEFT side result with this combination. Here is the LINQ and resulting SQL. What I'd like is for "AND ([t2].[EligEnd] = @p0" in the LINQ query to not bew part of the join condition but rather a subquery to filter results BEFORE the join. Thanks in advance (samples pulled from LINQPad) - Doug (from l in Users join mr in (from mri in vwMETRemotes where met.EligEnd == Convert.ToDateTime("2009-10-31") select mri) on l.Mahcpid equals mr.Mahcpid into lo from g in lo.DefaultIfEmpty() orderby l.LastName, l.FirstName where l.LastName.StartsWith("smith") && l.DeletedDate == null select g) Here is the resulting SQL -- Region Parameters DECLARE @p0 DateTime = '2009-10-31 00:00:00.000' DECLARE @p1 NVarChar(6) = 'smith%' -- EndRegion SELECT [t2].[test], [t2].[MAHCPID] AS [Mahcpid], [t2].[FirstName], [t2].[LastName], [t2].[Gender], [t2].[Address1], [t2].[Address2], [t2].[City], [t2].[State] AS [State], [t2].[ZipCode], [t2].[Email], [t2].[EligStart], [t2].[EligEnd], [t2].[Dependent], [t2].[DateOfBirth], [t2].[ID], [t2].[MiddleInit], [t2].[Age], [t2].[SSN] AS [Ssn], [t2].[County], [t2].[HomePhone], [t2].[EmpGroupID], [t2].[PopulationIdentifier] FROM [dbo].[User] AS [t0] LEFT OUTER JOIN ( SELECT 1 AS [test], [t1].[MAHCPID], [t1].[FirstName], [t1].[LastName], [t1].[Gender], [t1].[Address1], [t1].[Address2], [t1].[City], [t1].[State], [t1].[ZipCode], [t1].[Email], [t1].[EligStart], [t1].[EligEnd], [t1].[Dependent], [t1].[DateOfBirth], [t1].[ID], [t1].[MiddleInit], [t1].[Age], [t1].[SSN], [t1].[County], [t1].[HomePhone], [t1].[EmpGroupID], [t1].[PopulationIdentifier] FROM [dbo].[vwMETRemote] AS [t1] ) AS [t2] ON ([t0].[MAHCPID] = [t2].[MAHCPID]) AND ([t2].[EligEnd] = @p0) WHERE ([t0].[LastName] LIKE @p1) AND ([t0].[DeletedDate] IS NULL) ORDER BY [t0].[LastName], [t0].[FirstName]

  Read the article

• Cakephp Function in mode not executing

  - by Rixius

  I have a function in my Comic Model as such: <?php class Comic extends AppModel { var $name = "Comic"; // Methods for retriving information. function testFunc(){ $mr = $this->find('all'); return $mr; } } ?> And I am calling it in my controller as such: <?php class ComicController extends AppController { var $name = "Comic"; var $uses = array('Comic'); function index() { } function view($q) { $this->set('array',$this->Comic->testFunc()); } } ?> When I try to load up the page; I get the following error: Warning (512): SQL Error: 1064: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'testFunc' at line 1 [CORE/cake/libs/model/datasources/dbo_source.php, line 525] Query: testFunc And the SQL dump looks like this: (default) 2 queries took 1 ms Nr Query Error Affected Num. rows Took (ms) 1 DESCRIBE comics 10 10 1 2 testFunc 1064: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'testFunc' at line 1 0 So it looks like, instead of running the testFunc() function, it is trying to run a query of "testFunc" and failing...

  Read the article

• create this array

  - by calccrypto

  i know this sounds silly, but can someone please post the arrays described by rfc2612: Cm = 0x5A827999 Mm = 0x6ED9EBA1 Cr = 19 Mr = 17 for (i=0; i<24; i++) { for (j=0; j<8; j++) { Tmj_(i) = Cm Cm = (Cm + Mm) mod 2**32 Trj_(i) = Cr Cr = (Cr + Mr) mod 32 } } i think im doing is wrong for some reason i get this for Tr [[10, 18, 26, 2, 10, 18, 26, 2, 10, 18, 26, 2, 10, 18, 26, 2, 10, 18, 26, 2, 10, 18, 26, 2], [10, 18, 26, 2, 10, 18, 26, 2, 10, 18, 26, 2, 10, 18, 26, 2, 10, 18, 26, 2, 10, 18, 26, 2], [10, 18, 26, 2, 10, 18, 26, 2, 10, 18, 26, 2, 10, 18, 26, 2, 10, 18, 26, 2, 10, 18, 26, 2], [10, 18, 26, 2, 10, 18, 26, 2, 10, 18, 26, 2, 10, 18, 26, 2, 10, 18, 26, 2, 10, 18, 26, 2], [10, 18, 26, 2, 10, 18, 26, 2, 10, 18, 26, 2, 10, 18, 26, 2, 10, 18, 26, 2, 10, 18, 26, 2], [10, 18, 26, 2, 10, 18, 26, 2, 10, 18, 26, 2, 10, 18, 26, 2, 10, 18, 26, 2, 10, 18, 26, 2], [10, 18, 26, 2, 10, 18, 26, 2, 10, 18, 26, 2, 10, 18, 26, 2, 10, 18, 26, 2, 10, 18, 26, 2], [10, 18, 26, 2, 10, 18, 26, 2, 10, 18, 26, 2, 10, 18, 26, 2, 10, 18, 26, 2, 10, 18, 26, 2]]

  Read the article

• Can I use a *.tag from another *.tag file in the same /WEB-INF/tags folder?

  - by Ytsejammer

  Hello, I am trying to refactor my JSP code so that a small conditional test condition gets reused through a *.tag file. There are some big parts of my UI that depend on the value of a two-state property of an object present in the request. Let's say the property is 'gender' and the object is of type Person. Like I said, I would like to simplify & centralize the test on the gender property using a tag. For this purpose, I created two tag files: /WEB-INF/tags/if-male.tag /WEB-INF/tags/if-female.tag Now, I have another tiny spot that gets repeated in all over my application; let's say is the salutation to my site user. With this idea, I created a tag like this: /WEB-INF/tags/salutation.tag As you can imagine, I am trying to use the if-male/if-female test within the salutation.tag file to output 'Mrs.' or 'Mr.' like this: <%@ tag body-content="empty" %> <%@ taglib prefix="g" uri="/WEB-INF/tags" %> <g:if-male> Mr. </g:if-male> <g:if-female> Mrs. </g:if-female> Is the use of the if-male/if-female tags legal within the salutation.tag file? I have tried with such arrangement, but it looks like the JDeveloper 10.1.3.4 compiler gets confused and cannot deal with the salutation.tag tag invoking the other two tags in the same 'library' (folder under /WEB-INF/tags). The reference works perfectly in Jetty 6 and it looks like it works as well if I deploy the application to OC4J directly without relying on JDeveloper to pre-compile all my JSPs. I hope someone can shed some light on this. Thanks, YJ

  Read the article

• String Manipulation: Spliting Delimitted Data

  - by Milli Szabo

  I need to split some info from a asterisk delimitted data. Data Format: NAME*ADRESS LINE1*ADDRESS LINE2 Rules: 1. Name should be always present 2. Address Line 1 and 2 might not be 3. There should be always three asterisks. Samples: MR JONES A ORTEGA*ADDRESS 1*ADDRESS2* Name: MR JONES A ORTEGA Address Line1: ADDRESS 1 Address Line2: ADDRESS 2 A PAUL*ADDR1** Name: A PAUL Address Line1: ADDR1 Address Line2: Not Given My algo is: 1. Iterate through the characters in the line 2. Store all chars in a temp variables until first * is found. Reject the data if no char is found before first occurence of asterisk. If some chars found, use it as the name. 3. Same as step 2 for finding address line 1 and 2 except that this won't reject the data if no char is found My algo looks ugly. The code looks uglier. Spliting using //* doesn't work either since name can be replaced with address line 1 If the data is *Address 1*Address2, split will create two indexes in the array where index 0 will have the value of Address 1 and index 2 will have the value of Address2. Where's the name. Was there a name? Any suggestion?

  Read the article

• Using map/reduce for mapping the properties in a collection

  - by And

  Update: follow-up to MongoDB Get names of all keys in collection. As pointed out by Kristina, one can use Mongodb 's map/reduce to list the keys in a collection: db.things.insert( { type : ['dog', 'cat'] } ); db.things.insert( { egg : ['cat'] } ); db.things.insert( { type : [] }); db.things.insert( { hello : [] } ); mr = db.runCommand({"mapreduce" : "things", "map" : function() { for (var key in this) { emit(key, null); } }, "reduce" : function(key, stuff) { return null; }}) db[mr.result].distinct("_id") //output: [ "_id", "egg", "hello", "type" ] As long as we want to get only the keys located at the first level of depth, this works fine. However, it will fail retrieving those keys that are located at deeper levels. If we add a new record: db.things.insert({foo: {bar: {baaar: true}}}) And we run again the map-reduce +distinct snippet above, we will get: [ "_id", "egg", "foo", "hello", "type" ] But we will not get the bar and the baaar keys, which are nested down in the data structure. The question is: how do I retrieve all keys, no matter their level of depth? Ideally, I would actually like the script to walk down to all level of depth, producing an output such as: ["_id","egg","foo","foo.bar","foo.bar.baaar","hello","type"] Thank you in advance!

  Read the article

• Perl Regex - Condensing groups of find/replace

  - by brydgesk

  I'm using Perl to perform some file cleansing, and am running into some performance issues. One of the major parts of my code involves standardizing name fields. I have several sections that look like this: sub substitute_titles { my ($inStr) = @_; ${$inStr} =~ s/ PHD./ PHD /; ${$inStr} =~ s/ P H D / PHD /; ${$inStr} =~ s/ PROF./ PROF /; ${$inStr} =~ s/ P R O F / PROF /; ${$inStr} =~ s/ DR./ DR /; ${$inStr} =~ s/ D.R./ DR /; ${$inStr} =~ s/ HON./ HON /; ${$inStr} =~ s/ H O N / HON /; ${$inStr} =~ s/ MR./ MR /; ${$inStr} =~ s/ MRS./ MRS /; ${$inStr} =~ s/ M R S / MRS /; ${$inStr} =~ s/ MS./ MS /; ${$inStr} =~ s/ MISS./ MISS /; } I'm passing by reference to try and get at least a little speed, but I fear that running so many (literally hundreds) of specific string replaces on tens of thousands (likely hundreds of thousands eventually) of records is going to hurt the performance. Is there a better way to implement this kind of logic than what I'm doing currently? Thanks Edit: Quick note, not all the replace functions are just removing periods and spaces. There are string deletions, soundex groups, etc.

  Read the article

• String Manipulation: Splitting Delimitted Data

  - by Milli Szabo

  I need to split some info from a asterisk delimitted data. Data Format: NAME*ADRESS LINE1*ADDRESS LINE2 Rules: 1. Name should be always present 2. Address Line 1 and 2 might not be 3. There should be always three asterisks. Samples: MR JONES A ORTEGA*ADDRESS 1*ADDRESS2* Name: MR JONES A ORTEGA Address Line1: ADDRESS 1 Address Line2: ADDRESS 2 A PAUL*ADDR1** Name: A PAUL Address Line1: ADDR1 Address Line2: Not Given My algo is: 1. Iterate through the characters in the line 2. Store all chars in a temp variables until first * is found. Reject the data if no char is found before first occurence of asterisk. If some chars found, use it as the name. 3. Same as step 2 for finding address line 1 and 2 except that this won't reject the data if no char is found My algo looks ugly. The code looks uglier. Spliting using //* doesn't work either since name can be replaced with address line 1 if the data was *Address 1*Address2. Any suggestion?

  Read the article

• Creating one row of information in excel using a unique value

  - by user1426513

  This is my first post. I am currently working on a project at work which requires that I work with several different worksheets in order to create one mail master worksheet, as it were, in order to do a mail merge. The worksheet contains information regarding different purchases, and each purchaser is identified with their own ID number. Below is an example of what my spreadsheet looks like now (however I do have more columns): ID Salutation Address ID Name Donation ID Name Tickets 9 Mr. John Doe 123 12 Ms. Jane Smith 100.00 12 Ms.Jane Smith 300.00 12 Ms. Jane Smith 456 22 Mr. Mike Man 500.00 84 Ms. Jo Smith 300.00 What I would like to do is somehow sort my data so that everythign with the same unique identifier (ID) lines up on the same row. For example ID 12 Jane Smith - all the information for her will show up under her name matched by her ID number, and ID 22 will match up with 22 etc... When I merged all of my spreadsheets together, I sorted them all by ID number, however my problem is, not everyone who made a donation bought a ticket or some people just bought tickets and nothing us, so sorting doesn't work. Hopefully this makes sense. Thanks in advance.

  Read the article

• How to save to Django Model that Have Mulitple Foreign Keys Fields

  - by Spikie

  I have Models for business Apps class staff_name(models.Model): TITLE_CHOICES = ( ('Mr', 'Mr'), ('Miss', 'Miss'), ( 'Mrs', 'Mrs'), ( 'chief', 'chief'), ) titlename = models.CharField(max_length=10,choices=TITLE_CHOICES) firstname = models.CharField(max_length=150) surname = models.CharField(max_length=150) date = models.DateTimeField(auto_now=True) class meta: ordering = ["date"] get_latest_by = "date" class inventory_transaction(models.Model): stock_in = models.DecimalField(blank=True, null=True,max_digits=8, decimal_places=2) stock_out = models.DecimalField(blank=True,null=True,max_digits=8, decimal_places=2) Number_container = models.ForeignKey(container_identity) staffs = models.ForeignKey(staff_name) goods_details = models.ForeignKey(departments) balance = models.DecimalField(max_digits=8, decimal_places=2) date = models.DateTimeField(auto_now=True) What i want to accomplish is check if the staff have made entry to the table before if yes add the value for the stock in plus (last) balance field and assign to balance if no just assign stock in value to balance field and save these are my codes These are my codes: try: s = staffname.staffs_set.all().order_by("-date").latest() # staffname is the instant of the class model staff_name e = s.staffs_set.create(stockin=vdataz,balance=s.balance + vdataz ) # e is the instant of the class model inventory_transaction e.save e.staffs.add(s) e.from_container.add(containersno) e.goods_details.add(department) except ObjectDoesNotExist: e = staff_name.objects.create(stockin=vdataz,balance=vdataz ) e.save e.staffs.add(staffname) e.from_container.add(containersno) e.goods_details.add(department) I will really appreciate a solution Thanks I hope it make more sense now. iam on online if you need more explanation just ask in the comment.Thank you for your help

  Read the article

• Steps for MySQL DB Replication

  - by Manish Agrawal

  Following are the steps for MySQL Replication implementation on Linux machine: Pre-implementation steps for DB Replication:   1.    Identify the databases to be replicated 2.    Identify the tables to be ignored during replication per database for example log tables 3.  Carefully identify and replace the variables and paths(locations) mentioned (in bold) in the commands given below with appropriate values 4.  Schedule the maintenance activity in odd hours as these activities will affect all the databases on Master database server       Implementation steps for DB Replication:     1.    Configure the /etc/my.cnf file on Master database server to enable Binary logging, setting of server id and configuring of dbnames for which logging should be done. [mysqld] log-bin=mysql-bin server-id=1 binlog-do-db = dbname   Note: You can specify multiple DB in binlog-do-db by using comma separated dbname values like: dbname1, dbname2, …, dbnameN   2.    On Master database, Grant Replication Slave Privileges, by executing following command on mysql prompt mysql> GRANT REPLICATION SLAVE ON *.* TO slaveuser@<hostname> identified by ‘slavepassword’;   3.    Stop the Master & Slave database by giving the command      mysqladmin shutdown   4.    Start the Master database by giving the command      /usr/local/mysql-5.0.22/bin/mysqld_safe --user=user&     5.    mysql> FLUSH TABLES WITH READ LOCK; Note: Leave the client (putty session) from which you issued the FLUSH TABLES statement running, so that the read lock remains in effect. If you exit the client, the lock is released. 6.    mysql > SHOW MASTER STATUS;          +---------------+----------+--------------+------------------+          | File          | Position | Binlog_Do_DB | Binlog_Ignore_DB |          +---------------+----------+--------------+------------------+          | mysql-bin.003 | 117       | dbname       |                  |          +---------------+----------+--------------+------------------+ Note: Note this information as this will be required while starting of Slave and replication in later steps   7.    Take MySQL dump by giving the following command, In another session window (putty window) run the following command: mysqldump –u user --ignore-table=dbname.tbl_name -–ignore-table=dbname.tbl_name2 --master-data dbname > dbname_dump.db Note: When choosing databases to include in the dump, remember that you will need to filter out databases on each slave that you do not want to include in the replication process.     8.    Unlock the tables on Master by giving following command: mysql> UNLOCK TABLES;   9.    Copy the dump file to Slave DB server   10.  Startup the Slave by using option --skip-slave      /usr/local/mysql-5.0.22/bin/mysqld_safe --user=user --skip-slave&   11.  Restore the dump file on Slave DB server      mysql –u user dbname < dbname_dump.db   12.  Stop the Slave database by giving the command      mysqladmin shutdown   13.  Configure the /etc/my.cnf file on the Slave database server [mysqld] server-id=2 replicate-ignore-table = dbname.tablename   14.  Start the Slave Mysql Server with 'replicate-do-db=DB name' option.      /usr/local/mysql-5.0.22/bin/mysqld_safe --user=user --replicate-do-db=dbname --skip-slave   15.  Configure the settings at Slave server for Master host name, log filename and position within the log file as shown in Step 6 above Use Change Master statement in the MySQL session mysql> CHANGE MASTER TO MASTER_HOST='<master_host_name>', MASTER_USER='<replication_user_name>', MASTER_PASSWORD='<replication_password>', MASTER_LOG_FILE='<recorded_log_file_name>', MASTER_LOG_POS=<recorded_log_position>;   16.  On Slave Servers mysql prompt give the following command: a.     mysql > START SLAVE; b.    mysql > SHOW SLAVE STATUS;         Note: To stop slave for backup or any other activity you can use the following command on the Slave Servers mysql prompt: mysql> STOP SLAVE     Refer following links for more information on MySQL DB Replication: http://dev.mysql.com/doc/refman/5.0/en/replication-options.html http://crazytoon.com/2008/04/21/mysql-replication-replicate-by-choice/ http://dev.mysql.com/doc/refman/5.0/en/mysqldump.html

  Read the article

• Find Port Number and Domain Name to connect to Hive Table

  - by user1419563

  I am new to Hive, MapReduce and Hadoop. I am using Putty to connect to hive table and access records in the tables. So what I did is- I opened Putty and in the host name I typed- ares-ingest.vip.host.com and then I click Open. And then I entered my username and password and then few commands to get to Hive sql. Below is the list what I did $ bash bash-3.00$ hive Hive history file=/tmp/rjamal/hive_job_log_rjamal_201207010451_1212680168.txt hive> set mapred.job.queue.name=hdmi-technology; hive> select * from table LIMIT 1; So my question is- I was trying to connect to Hive Tables using Squirrel SQL Client, so in that my Connection URL is- jdbc:hive://ares-ingest.vip.host.com:10000/default. So whenever I try to connect with these attributes, I always get Hive: Could not establish connection to ares-ingest.vip.host.com:10000/default: java.net.ConnectException: Connection timed out: connect. It might be possible I am using wrong port number or domain name here. Is there any way from the command prompt I can find out these two things, like what Domain Name and Port Number(where Hive server is running) should I use to connect to Hive table from Squirrel SQL Client. As I know host and port are determined by where the hive server is running

  Read the article

• Socket stops communicating

  - by user1392992

  I'm running python 2.7 code on a Raspberry Pi that receives serial data from an Arduino, processes it, and sends it to a Windows box over a wifi link. The Pi is wired to a Linksys router running in client bridge mode and that router connects over wifi to another Linksys router to which the Windows box is wired. The code in the Pi runs fine for some (apparently) random interval, and then the Pi becomes unreachable from the Windows box. I'm running PUTTY on the the Windows machine to connect to the Pi and when the fail occurs I get a message saying there's been a network error and the Pi is not reachable. Pinging the Pi from the Windows machine works fine until the error, at which time it produces "Reply from 192.168.0.129: Destination host unreachable." The client bridge router to which the Pi is connected remains reachable. I've got the networking code on the Pi wrapped in an exception handler, and when it fails it shows the following: Ethernet problem: Traceback (most recent call last): File "garage.py", line 108, in module s.connect((host, port)) File "/usr/lib/python2.7/socket.py", line 224, in meth return getattr(self._sock,name)(*args) error: [Errno 113] No route to host None The relevant python code looks like: import socket import traceback host = '192.168.0.129' port = 31415 in the setup, and after serial data has been processed: try: bline = strline.encode('utf-8') s = socket.socket(socket.AF_INET, socket.SOCK_STREAM) s.connect((host, port)) s.send(bline) s.close() except: print "Ethernet problem: " print traceback.print_exc() Where strline contains the processed data. As I said, this runs fine for a few hours more or less before failing. Any ideas? EDIT: When PUTTY fails its error message is :Network Error: Software caused connection abort."

  Read the article

• C# 4.0: Named And Optional Arguments

  - by Paulo Morgado

  As part of the co-evolution effort of C# and Visual Basic, C# 4.0 introduces Named and Optional Arguments. First of all, let’s clarify what are arguments and parameters: Method definition parameters are the input variables of the method. Method call arguments are the values provided to the method parameters. In fact, the C# Language Specification states the following on §7.5: The argument list (§7.5.1) of a function member invocation provides actual values or variable references for the parameters of the function member. Given the above definitions, we can state that: Parameters have always been named and still are. Parameters have never been optional and still aren’t. Named Arguments Until now, the way the C# compiler matched method call definition arguments with method parameters was by position. The first argument provides the value for the first parameter, the second argument provides the value for the second parameter, and so on and so on, regardless of the name of the parameters. If a parameter was missing a corresponding argument to provide its value, the compiler would emit a compilation error. For this call: Greeting("Mr.", "Morgado", 42); this method: public void Greeting(string title, string name, int age) will receive as parameters: title: “Mr.” name: “Morgado” age: 42 What this new feature allows is to use the names of the parameters to identify the corresponding arguments in the form: name:value Not all arguments in the argument list must be named. However, all named arguments must be at the end of the argument list. The matching between arguments (and the evaluation of its value) and parameters will be done first by name for the named arguments and than by position for the unnamed arguments. This means that, for this method definition: public static void Method(int first, int second, int third) this call declaration: int i = 0; Method(i, third: i++, second: ++i); will have this code generated by the compiler: int i = 0; int CS$0$0000 = i++; int CS$0$0001 = ++i; Method(i, CS$0$0001, CS$0$0000); which will give the method the following parameter values: first: 2 second: 2 third: 0 Notice the variable names. Although invalid being invalid C# identifiers, they are valid .NET identifiers and thus avoiding collision between user written and compiler generated code. Besides allowing to re-order of the argument list, this feature is very useful for auto-documenting the code, for example, when the argument list is very long or not clear, from the call site, what the arguments are. Optional Arguments Parameters can now have default values: public static void Method(int first, int second = 2, int third = 3) Parameters with default values must be the last in the parameter list and its value is used as the value of the parameter if the corresponding argument is missing from the method call declaration. For this call declaration: int i = 0; Method(i, third: ++i); will have this code generated by the compiler: int i = 0; int CS$0$0000 = ++i; Method(i, 2, CS$0$0000); which will give the method the following parameter values: first: 1 second: 2 third: 1 Because, when method parameters have default values, arguments can be omitted from the call declaration, this might seem like method overloading or a good replacement for it, but it isn’t. Although methods like this: public static StreamReader OpenTextFile( string path, Encoding encoding = null, bool detectEncoding = true, int bufferSize = 1024) allow to have its calls written like this: OpenTextFile("foo.txt", Encoding.UTF8); OpenTextFile("foo.txt", Encoding.UTF8, bufferSize: 4096); OpenTextFile( bufferSize: 4096, path: "foo.txt", detectEncoding: false); The complier handles default values like constant fields taking the value and useing it instead of a reference to the value. So, like with constant fields, methods with parameters with default values are exposed publicly (and remember that internal members might be publicly accessible – InternalsVisibleToAttribute). If such methods are publicly accessible and used by another assembly, those values will be hard coded in the calling code and, if the called assembly has its default values changed, they won’t be assumed by already compiled code. At the first glance, I though that using optional arguments for “bad” written code was great, but the ability to write code like that was just pure evil. But than I realized that, since I use private constant fields, it’s OK to use default parameter values on privately accessed methods.

  Read the article

• Simple VIN API for decoding Vehicle Identification Numbers

  - by kerry

  Ever see a nifty tool that solves a problem for a particular domain that you may never encounter but wish you had a reason to use it? I did that recently with this VIN API by the people at the PullMonkey blog.  It will easily decode a VIN, returning the make, model, year, and other useful information about the vehicle.  It was developed for Mr Quotey, a new free online insurance service. Check out the post if you would like to try it out, it even provides a simple example written in Ruby.

  Read the article

• Learn how Oracle storage efficiencies can help your budget

  - by jenny.gelhausen

  Mark Your Calendar! Live Webcast: Next Generation Storage Management Solutions Wednesday, March 24th, 2010 at 9:00am PT or your local time Please plan to join us for this webcast where Forrester senior analyst Andrew Reichman will discuss the pillars of storage efficiency, how to measure and improve it, and how this can help your business immediately alleviate budget pressures. Joining Mr. Reichman are Phil Stephenson, Senior Principal Product Manager at Oracle, and Matthew Baier, Oracle Product Director, who will explain to you the next generation storage capabilities available in Oracle Database 11g and Oracle Exadata. Register for this March 24th live wecast today! var gaJsHost = (("https:" == document.location.protocol) ? "https://ssl." : "http://www."); document.write(unescape("%3Cscript src='" + gaJsHost + "google-analytics.com/ga.js' type='text/javascript'%3E%3C/script%3E")); try { var pageTracker = _gat._getTracker("UA-13185312-1"); pageTracker._trackPageview(); } catch(err) {}

  Read the article

• SQL Social

  - by SteveP

  Wanted to thanks Simon for putting together a great event last night.  It was a real pleasure to be in the company of some of the greats(Itzik, Greg, Davide, Bill and not forgetting Mr Sabin) in the SQL server space.  The venue was superb and the knowledge of the panel covered pretty much every corner of the SQL Server platform.  I'm very much looking forward to seeing how the social evenings progress.  It's going to be hard to follow this one. 

  Read the article

• Ensure we're found in Facebook search for both full & abbreviated company names?

  - by hawbsl

  We have a client with a facebook page, let's say his company is called Bob Roberts Super Widgets. And if you search in Facebook for Bob Roberts Super Widgets then up he pops. But the shorthand he's commonly known by is BR Super Widgets and indeed the website we've created for him is br-super-widgets.com. In Facebook, searching for BR Super Widgets doesn't show up our Mr Bob. We don't have a lot of Facebook expertise, so asking for help here. Does anyone know how to ensure you're found in Facebook search for both short and long company names? Have found this this similar question in the Facebook forum but the poor old questioner never got a response.

  Read the article

• Ensure we're found in Facebook search for both full & abbreviated company names?

  - by hawbsl

  We have a client with a facebook page, let's say his company is called Bob Roberts Super Widgets. And if you search in Facebook for Bob Roberts Super Widgets then up he pops. But the shorthand he's commonly known by is BR Super Widgets and indeed the website we've created for him is br-super-widgets.com. In Facebook, searching for BR Super Widgets doesn't show up our Mr Bob. We don't have a lot of Facebook expertise, so asking for help here. Does anyone know how to ensure you're found in Facebook search for both short and long company names? Have found this this similar question in the Facebook forum but the poor old questioner never got a response.

  Read the article

< Previous Page | 29 30 31 32 33 34 35 36 37 38 39 40  | Next Page >