Search Results

Search found 5233 results on 210 pages for 'records'.

Page 33/210 | < Previous Page | 29 30 31 32 33 34 35 36 37 38 39 40  | Next Page >

  • Criteria API - How to get records based on collection count?

    - by Cosmo
    Hello Guys! I have a Question class in ActiveRecord with following fields: [ActiveRecord("`Question`")] public class Question : ObcykaniDb<Question> { private long id; private IList<Question> relatedQuestions; [PrimaryKey("`Id`")] private long Id { get { return this.id; } set { this.id = value; } } [HasAndBelongsToMany(typeof(Question), ColumnRef = "ChildId", ColumnKey = "ParentId", Table = "RelatedQuestion")] private IList<Question> RelatedQuestions { get { return this.relatedQuestions; } set { this.relatedQuestions = value; } } } How do I write a DetachedCriteria query to get all Questions that have at least 5 related questions (count) in the RelatedQuestions collection? For now this gives me strange results: DetachedCriteria dCriteria = DetachedCriteria.For<Question>() .CreateCriteria("RelatedQuestions") .SetProjection(Projections.Count("Id")) .Add(Restrictions.EqProperty(Projections.Id(), "alias.Id")); DetachedCriteria dc = DetachedCriteria.For<Question>("alias").Add(Subqueries.Le(5, dCriteria)); IList<Question> results = Question.FindAll(dc); Any ideas what I'm doing wrong?

    Read the article

  • Find all records in database that are within a certain distance of a set of lat and long points

    - by Mike L
    I've seen all the examples and here's what I got so far. my table is simple: schools (table name) - School_ID - lat - long - county - extrainfo here's my code: <?php $con = mysql_connect("xxx","xxx","xxx"); if (!$con) { die('Could not connect: ' . mysql_error()); } else {} mysql_select_db("xxx", $con); $latitude = "36.265541"; $longitude = "-119.207153"; $distance = "1"; //miles $qry = "SELECT *, (3958.75 * ACOS(SIN(" . $latitude . " / 57.2958)*SIN(lat / 57.2958)+COS(" . $latitude . " / 57.2958)*COS(lat / 57.2958)*COS(long / 57.2958 - " . $longitude . " / 57.2958))) as distance FROM schools WHERE (3958.75 * ACOS(SIN(" . $latitude . " / 57.2958)*SIN(lat / 57.2958)+COS(" . $latitude . " / 57.2958)*COS(lat / 57.2958)*COS(long / 57.2958 - " . $longitude . " / 57.2958))) <= " . $distance; $results = mysql_query($qry); if (mysql_num_rows($results) > 0) { while($row = mysql_fetch_assoc($results)) { print_r($row); } } else {} mysql_close($con); ?> but I get this error when I try to run it: Warning: mysql_num_rows(): supplied argument is not a valid MySQL result resource

    Read the article

  • how to count all distinct records in many-to-many relations in django ORM?

    - by marduk-pl
    hi, i have two models: class Project(models.Model): categories = models.ManyToManyField(Category) class Category(models.Model): name = models.CharField() now, i make some queryset: query = Project.objects.filter(id__in=[1,2,3,4]) and i like to get list of all distinct categories in this queryset with count of projects with refering to these categories - exactly i would like to get that results: category1 - 10 projects category2 - 5 projects that is opposite to this query: query2 = query.annotate(Count('categories')) what return me: project1 - 2categories project2 - 7categories how can i make it in django ORM?

    Read the article

  • What's the proper format for an SPF record?

    - by deltanovember
    Querying my domain I get: The TXT records found for your domain are: v=spf1 ip4:50.22.72.198 a mx:wordswithfriends.net ~all So superficially it appears OK. However I also get the following message SPF records should also be published in DNS as type SPF records. No type SPF records found. I want to make sure things are absolutely airtight. So in addition to TXT records I also want a pure SPF record. However I cannot figure out the format. Placing the same text in an SPF record does not seem to work. Edit: At the moment I have a TXT record but not SPF record. When I cut and paste from TXT straight to SPF I get some type of crazy recursive DNS error so quickly deleted the SPF. I just want to know the correct format. Copying v=spf1 ip4:50.22.72.198 a mx:wordswithfriends.net ~all Straight into an SPF record doesn't work.

    Read the article

  • How can I make an SQL statement that finds unassociated records?

    - by William Calleja
    I have two tables as follows: tblCountry (countryID, countryCode) tblProjectCountry(ProjectID, countryID) The tblCountry table is a list of all countries with their codes and the tblProjectCountry table associates certain countries with certain projects. I need an SQL statement that gives me a list of the countries with their country code that do NOT have an associated record in the tblProjectCountry table. so far I got to here: SELECT tblCountry.countryID, tblCountry.countryCode FROM tblProjectCountry INNER JOIN tblCountry ON tblProjectCountry.countryID = tblCountry.countryID WHERE (SELECT COUNT(ProjectID) FROM tblProjectCountry WHERE (ProjectID = 1) AND (countryID = tblCountry.countryID)) = 0 The above statement parses as correct but doesn't give the exact result I'm looking for. Can anyone help?

    Read the article

  • How to convert records including 'include' associations to JSON.

    - by 99miles
    If I do something like: result = Appointment.find( :all, :include => :staff ) logger.debug { result.inspect } then it only prints out the Appointment data, and not the associated staff data. If I do result[0].staff.inpsect then I get the staff data of course. The problem is I want to return this to AJAX as JSON, including the staff rows. How do I force it to include the staff rows, or do I have to loop through and create something manually?

    Read the article

  • checking if records exists in DB, in single step or 2 steps?

    - by Sinan
    Suppose you want to get a record from database which returns a large data and requires multiple joins. So my question would be is it better to use a single query to check if data exists and get the result if it exists. Or do a more simple query to check if data exists then id record exists, query once again to get the result knowing that it exists. Example: 3 tables a, b and ab(junction table) select * from from a, b, ab where condition and condition and condition and condition etc... or select id from a, b ab where condition then if exists do the query above. So I don't know if there is any reason to do the second. Any ideas how this affects DB performance or does it matter at all?

    Read the article

  • How to return all records and whether a related record exists?

    - by David Glenn
    Using Entity Framework 4 CTP5 I have a basic model and a basic DbContext that works public class Customer { public int CustomerId { get; set; } public int Name { get; set; } //... public ICollection<Address> Addresses { get; set; } public bool HasAddress { get { return Addresses.Count > 0; } } } public class Address { public int AddressId { get; set; } public string StreetLine1 { get; set; } //.... public Customer Customer { get; set; } } How can I query my DbContext to return all customers and whether they have an address? A customer can have multiple addresses and I don't want to return all the addresses for each customer when I am only interested in whether they have an address or not. I use context.Customers.Include(c => c.Addresses) but that returns all addresses for each customer

    Read the article

  • Delphi -> Delphi prism, how to use array of records?

    - by Pierre
    Hi there. I'm learning Delphi Prism, and i don't find how to write the following code with it : type TRapportItem = record Label : String; Value : Int16; AnomalieComment : String; end; type TRapportCategorie = record Label : String; CategoriesItems : Array of TRapportItem; end; type TRapportContent = record Categories : array of TRapportCategorie; end; Then, somewhere, i try to put items in the array : rapport.Categories[i].Label:=l.Item(i).InnerText; But it doesn't work.. Can someone enlight me? Thanks!

    Read the article

  • (outofmemoryerror: java heap space) when iterating through oracle records...

    - by rockit
    hello fellow java developers. I'm having a bit of an issue here. I have code that gets a resultset from an oracle database, prints each row to a file, then gets the next row - and continues till the end of the resultset. Only this isn't what happens. What happens is that it gets the resultset, starts iterating through the rows, printing to file as it goes, until it runs out of memory - claiming it needs more space on the java heap. The app is currently running with 2g of memory on the heap and the code breaks at about the 150000th row. I'm using jodbc6.jar and java 6 Here is an idea of what my code is doing: Connection conn = DriverManager.getConnection(url,"name","pwd"); conn.setAutoCommit(false); Statement stmt = conn.createStatement(); ResultSet rset = stmt.executeQuery(strSql); String strVar_1 = null; long lCount = 0; while(rset.next()){ lCount++; if (lCount % 100000 == 0){ System.out.println(lCount + " rows completed"); } strVar_1 = rset.getString("StringID"); /// breaks here!!!!!!!!! if (strVar_1 == null){ strVar_1 = ""; } if (!strQuery_1.equals("")){ out.write(strVar_1 + "\n"); } } out.close();

    Read the article

  • CakePHP: How can I change this find call to include all records that do not exist in the associated

    - by Stephen
    I have a few tables with the following relationships: Company hasMany Jobs, Employees, and Trucks, Users I've got all my foreign keys set up properly, along with the tables' Models, Controllers, and Views. Originally, the Jobs table had a boolean field called "assigned". The following find operation (from the JobsController) successfully returns all employees, all trucks, and any jobs that are not assigned and fall on a certain day for a single company (without returning users by utilizing the containable behavior): $this->set('resources', $this->Job->Company->find('first', array( 'conditions' => array( 'Company.id' => $company_id ), 'contain' => array( 'Employee', 'Truck', 'Job' => array( 'conditions' => array( 'Job.assigned' => false, 'Job.pickup_date' => date('Y-m-d', strtotime('Today')); ) ) ) ))); Now, since writing this code, I decided to do a lot more with the job assignments. So I've created a new model "Assignment" that belongsTo Truck and belongsTo Job. I've added the hasMany Assignments to both the Truck model and the Jobs Model. I have both foreign keys in the assignments table, along with some other assignment fields. Now, I'm trying to get the same information above, only instead of checking the assigned field from the job table, I want to check the assignments table to ensure that the job does not exist there. I can no longer use the containable behavior if I'm going to use the "joins" feature of the find method due to mysql errors (according to the cookbook). But, the following query returns all jobs, even if they fall on different days. $this->set('resources', $this->Job->Company->find('first', array( 'joins' => array( array( 'table' => 'employees', 'alias' => 'Employee', 'type' => 'LEFT', 'conditions' => array( 'Company.id = Employee.company_id' ) ), array( 'table' => 'trucks', 'alias' => 'Truck', 'type' => 'LEFT', 'conditions' => array( 'Company.id = Truck.company_id' ) ), array( 'table' => 'jobs', 'alias' => 'Job', 'type' => 'LEFT', 'conditions' => array( 'Company.id = Job.company_id' ) ), array( 'table' => 'assignments', 'alias' => 'Assignment', 'type' => 'LEFT', 'conditions' => array( 'Job.id = Assignment.job_id' ) ) ), 'conditions' => array( 'Job.pickup_date' => $day, 'Company.id' => $company_id, 'Assignment.job_id IS NULL' ) )));

    Read the article

  • How to always return a set number of records when using find_related_tags with acts-as-taggable-on

    - by hadees
    I'm using the acts-as-taggable-on gem and I need to use find_related_tags on my survey model to get back 3 surveys every time. In the event there aren't always 3 related I need to pick how ever many are related plus some random ones to get to 3. Additionally I have a method I wrote called completed_survey_ids which return an array of survey_ids that shouldn't be used because the user has already completed them. Also there is a rare case that there won't be enough surveys because the user has completed them all so in that event it is okay to return less surveys then requested. I did write a named_scope to handle getting rid of the completed_survey_ids that I think works named_scope :not, lambda { |survey_ids| {:conditions => "id NOT IN (#{survey_ids.join(',')})" } }

    Read the article

  • Oracle/c#: How do i use bind variables with select statements to return multiple records?

    - by twiga
    I have a question regarding Oracle bind variables and select statements. What I would like to achieve is do a select on a number different values for the primary key. I would like to pass these values via an array using bind values. select * from tb_customers where cust_id = :1 int[] cust_id = { 11, 23, 31, 44 , 51 }; I then bind a DataReader to get the values into a table. The problem is that the resulting table only contains a single record (for cust_id=51). Thus it seems that each statement is executed independently (as it should), but I would like the results to be available as a collective (single table). A workaround is to create a temporary table, insert all the values of cust_id and then do a join against tb_customers. The problem with this approach is that I would require temporary tables for every different type of primary key, as I would like to use this against a number of tables (some even have combined primary keys). Is there anything I am missing?

    Read the article

  • Working with legacy data

    - by John Paul Cook
    We encounter legacy data as a part of life. Colleges and universities have transcript records dating back decades or even centuries. Real estate property records in the United States go as far back as Spanish and British land grants in the 1500s. Very old records are completely paper based and may be completely manually prepared, perhaps typed on a typewriter or written in longhand with a quill pen. How long should transcripts be retained? Nola Ochs graduated from college at age 95 (can you imagine...(read more)

    Read the article

  • setting up freedns with an existing domain

    - by romeovs
    I've been running a webserver off of a pc at a static IP succesfully for the past 5 months. recently however, I've moved into another appartment and my ISP only provides a dynamic IP (my IP changes from time to time). I'm not an internet genius but I was thinking to fix this by using a Dynamic DNS provider. So I got on the web and found freedns. I'm a bit confused about how to set up everything though. I've managed to succesfully install the IP updater daemon on my web server. Then, in my registrars control panel, I set the NS records to point at ns1 through ns4.afraid.org (removing the old NS records). I'm not certain what I should do with the A records though (for now they are still pointing to the old static IP address). I have A records for www, blog, irc, etc. but I cannot point them at my new IP address, because it isn't Could someone explain this in the clearest possible sense (perhaps elaborating on what happens at each step of the DNS process). I never really knew what the A records are for anyway. (note that I haven't really found any documentation at the freedns website, or on google)

    Read the article

  • How do I do a join in ActiveRecord after records have been returned?

    - by Russ Bradberry
    I am using ActiveRecord in Rails 3 to pull data from two different tables in two different databases. These databases can not join on each other, but I have the need to do a simple join after-the-fact. I would like to preserve the relation so that I can chain it down the line. here is a simplified version of what I am doing browsers = Browser.all # <-- this is fairly small and can reside in memory events = Event.where(:row_date=>Date.today).select(:name, :browser_id) So as you can see, I want to join browsers in on the events relation, where browser_id should equal browsers.name. events is a relation and I can still add clauses to it down the line, so I dont want to run the query on the db just yet. How would I accomplish this?

    Read the article

  • WebCenter Customer Spotlight: Alberta Agriculture and Rural Developmen

    - by me
    Author: Peter Reiser - Social Business Evangelist, Oracle WebCenter  Solution SummaryAlberta Agriculture and Rural Development is a government ministry that works with producers and consumers to create a strong, competitive, and sustainable agriculture and food industry in the province of Alberta, Canada The primary business challenge faced by the Alberta Ministry of Agriculture was that of managing the rapid growth of their information.  They needed to incorporate a system that would work across 22 different divisions within the ministry and deliver an improved and more efficient experience for Desktop, Web and Mobile users, while addressing their regulatory compliance needs as part of the Canadian government. The customer implemented a centralized Enterprise Content Management solution based on Oracle WebCenter Content and developed a strong and repeatable information life cycle management methodology across all their 22 divisions and agencies. With the implemented solution, Alberta Agriculture and Rural Development  centrally manages over 20 million documents for 22 divisions and agencies and they have improved time required to find records,  reliability of information, improved speed and accuracy of reporting and data security. Company OverviewAlberta Agriculture and Rural Development is a government ministry that works with producers and consumers to create a strong, competitive, and sustainable agriculture and food industry in the province of Alberta, Canada.  Business ChallengesThe business users were overwhelmed by growth in documents (over 20 million files across 22 divisions and agencies) and it was difficult to find and manage documents and versions. There was a strong need for a personalized easy-to-use, secure and dependable method of managing and consuming content via desktop, Web, and mobile, while improving efficiency and maintaining regulatory compliance by removing the risk of non-uniform approaches to retention and disposition. Solution DeployedAs a first step Alberta Agriculture and Rural Development developed a business case with clear defined business drivers: Reduce time required to find records Locate “lost” records Capture knowledge lost through attrition Increase the ease of retrieval Reduce personal copies Increase reliability of information Improve speed and accuracy of reporting Improve data security The customer implemented a centralized Enterprise Content Management solution based on Oracle WebCenter Content. They used an incremental implementation approach aligned with their divisional and agency structure which allowed continuous process improvement. This led to a very strong and repeatable information life cycle management methodology across all their 22 divisions and agencies. Business ResultsAlberta Agriculture and Rural Development achieved impressive business results: Centrally managing over 20 million files for 22 divisions and agencies Federated model to manage documents in SharePoint and other applications Doing records management for both paper and electronic records Reduced time required to find records Increased the ease of retrieval Increased reliability of information Improved speed and accuracy of reporting Improved data security Additional Information Oracle Open World 2012 Presentation Oracle WebCenter Content

    Read the article

  • SQL: without a cursor, how to select records making a unique integer id (identity like) for dups?

    - by Dr. Zim
    If you have the select statement below where the PK is the primary key: select distinct dbo.DateAsInt( dateEntered) * 100 as PK, recordDescription as Data from MyTable and the output is something like this (the first numbers are spaced for clarity): PK Data 2010 01 01 00 New Years Day 2010 01 01 00 Make Resolutions 2010 01 01 00 Return Gifts 2010 02 14 00 Valentines day 2010 02 14 00 Buy flowers and you want to output something like this: PK Data 2010 01 01 01 New Years Day 2010 01 01 02 Make Resolutions 2010 01 01 03 Return Gifts 2010 02 14 01 Valentines day 2010 02 14 02 Buy flowers Is it possible to make the "00" in the PK have an "identity" number effect within a single select? Otherwise, how could you increment the number by 1 for each found activity for that date? I am already thinking as I type to try something like Sum(case when ?? then 1 end) with a group by.

    Read the article

< Previous Page | 29 30 31 32 33 34 35 36 37 38 39 40  | Next Page >