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• APress Deal of the Day 17/Oct2013 - Pro SharePoint 2013 Branding and Responsive Web Development

  - by TATWORTH

  Originally posted on: http://geekswithblogs.net/TATWORTH/archive/2013/10/17/apress-deal-of-the-day-17oct2013---pro-sharepoint-2013.aspxToday's $10 deal of the day from APress at http://www.apress.com/9781430250289 is Pro SharePoint 2013 Branding and Responsive Web Development "Pro SharePoint 2013 Branding and Responsive Web Development is a complete guide to planning, designing, and developing modern, responsive websites and applications using SharePoint 2013 and open standards like HTML5, CSS3 and JavaScript"

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• APress Deal of the Day 9/August/2014 - Pro SharePoint 2013 Administration

  - by TATWORTH

  Originally posted on: http://geekswithblogs.net/TATWORTH/archive/2014/08/09/apress-deal-of-the-day-9august2014---pro-sharepoint-2013.aspxToday’s $10 Deal of the Day from APress at http://www.apress.com/9781430249412 is Pro SharePoint 2013 Administration. “Pro SharePoint 2013 Administration is a practical guide to installing, deploying, and implementing SharePoint 2013 for intermediate to advanced administrators. ”

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• SharePoint Planning/Design Worksheet Links

  - by Mike Huguet

  I ran across a blog entry with a consolidated list of links to the SharePoint 2007 planning worksheets.  These are good starting points for your discovery, analysis, and design and are provided by Microsoft.  I would suggest tweaking them to meet your organizational needs.  http://itfootprint.wordpress.com/2007/10/05/sharepoint-planning-worksheets-in-one-place/ TechNet provides a consolidated list of planning worksheets for SharePoint 2010.  http://technet.microsoft.com/en-us/library/cc262451.aspx  Technorati Tags: SharePoint,planning,design

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• European SharePoint Conference - SP2013 workshop for developers with me

  - by Sahil Malik

  SharePoint 2010 Training: more information I’m delighted to be a part of the European SharePoint Conference, Feb 4-7 2013, in Copenhagen, Denmark.I will be conducting a full day workshop on SharePoint 2013 for Developers. You can register for the conference here. Here is the outline (willing to adjust it based on popular demand of course) SharePoint 2013 IntroductionClient Side Technologies, and Security Read full article ....

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• Database Management for SharePoint 2010

  With each revision, SharePoint becomes more a SQL Server Database application, with everything that implies for planning and deployment. There are advantages to this: SharePoint can make use of mirroring, data-compression and remote BLOB storage. It can employ advanced tools such as data file compression, and object-level restore. DBAs can employ familiar techniques to speed SharePoint applications. Bert explains the way that SharePoint and SQL Server interact.

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• Sharepoint web services -- The HTTP request is unauthorized with client authentication scheme 'Ntlm'

  - by Pandincus

  I know there's a lot of questions on SO similar to this, but I couldn't find one for this particular issue. A couple of points, first: I have no control over our Sharepoint server. I cannot tweak any IIS settings. I believe our IIS server version is IIS 7.0. Our Sharepoint Server is anticipating requests via NTLM. Our Sharepoint Server is on the same domain as my client computer. I am using .NET Framework 3.5, Visual Studio 2008 I am trying to write a simple console app to manipulate Sharepoint data using Sharepoint Web Services. I have added the Service Reference, and the following is my app.config: <system.serviceModel> <bindings> <basicHttpBinding> <binding name="ListsSoap" closeTimeout="00:01:00" openTimeout="00:01:00" receiveTimeout="00:10:00" sendTimeout="00:01:00" allowCookies="false" bypassProxyOnLocal="false" hostNameComparisonMode="StrongWildcard" maxBufferSize="65536" maxBufferPoolSize="524288" maxReceivedMessageSize="65536" messageEncoding="Text" textEncoding="utf-8" transferMode="Buffered" useDefaultWebProxy="true"> <readerQuotas maxDepth="32" maxStringContentLength="8192" maxArrayLength="16384" maxBytesPerRead="4096" maxNameTableCharCount="16384" /> <security mode="Transport"> <transport clientCredentialType="Ntlm" proxyCredentialType="Ntlm" /> </security> </binding> </basicHttpBinding> </bindings> <client> <endpoint address="https://subdomain.companysite.com/subsite/_vti_bin/Lists.asmx" binding="basicHttpBinding" bindingConfiguration="ListsSoap" contract="ServiceReference1.ListsSoap" name="ListsSoap" /> </client> </system.serviceModel> This is my code: static void Main(string[] args) { using (var client = new ListsSoapClient()) { client.ClientCredentials.Windows.ClientCredential = new NetworkCredential("username", "password", "domain"); client.GetListCollection(); } } When I call GetListCollection(), the following MessageSecurityException gets thrown: The HTTP request is unauthorized with client authentication scheme 'Ntlm'. The authentication header received from the server was 'NTLM'. With an inner WebException: "The remote server returned an error: (401) Unauthorized." I've tried various bindings and various code tweaks to try to authenticate properly, but to no avail. I'll list those below. I've tried the following steps: Using a native Win32 Impersonator before creating the client using (new Impersonator.Impersonator("username", "password", "domain")) using (var client = new ListsSoapClient()) { client.ClientCredentials.Windows.ClientCredential = new NetworkCredential("dpincas", "password", "domain"); client.GetListCollection(); } This produced the same error message. Setting TokenImpersonationLevel for my client credentials using (var client = new ListsSoapClient()) { client.ClientCredentials.Windows.AllowedImpersonationLevel = TokenImpersonationLevel.Impersonation; client.GetListCollection(); } This produced the same error message. Using security mode=TransportCredentialOnly <security mode="TransportCredentialOnly"> <transport clientCredentialType="Ntlm" /> </security> This resulted in a different error message: The provided URI scheme 'https' is invalid; expected 'http'. Parameter name: via However, I need to use https, so I cannot change my URI scheme. I've tried some other combinations that I can't remember, but I'll post them when I do. I'm really at wits end here. I see a lot of links on Google that say "switch to Kerberos", but my server seems to only be accepting NTLM, not "Negotiate" (as it would say if it was looking for Kerberos), so that is unfortunately not an option. Any help out there, folks?

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• SQL Max Group By Query Help

  - by Hcabnettek

  Hi All, I have a quick question. How do I select the two values I need in one query? Currently I'm doing this, which works fine, but it's obviously running two queries when one should do the trick. I tried MAX(columnA) and GROUP BY ColumnB, but that returns multiple row. I only want one row returned. DECLARE @biID bigint , @dtThreshold DateTime SELECT @biID = MAX(biID) FROM tbPricingCalculationCount WITH (NOLOCK) SELECT @dtThreshold = dtDateTime FROM tbPricingCalculationCount WITH (NOLOCK) WHERE biID = @biID I would like both those variables to be set correctly in one query. How can I do that? Thanks, ~ck

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• Reading Local Group Policy / Active Directory Settings

  - by Shinobi

  I'm writing a C# program that will enforce password complexity in accordance with the Windows Group Policy setting "Password must meet complexity requirements". Specifically, if that policy is set to Enabled either on the local machine (if it's not part of a domain) or by the Domain Security Policy (for domain members), then my software needs to enforce a complex password for its own internal security. The issue is that I can't figure out how to read that GPO setting. Google searches have indicated that I can read GPO settings with one of these two APIs: the System.DirectoryServices library in .NET Framework, and Windows Management Instrumentation (WMI), but I haven't had any success so far. Any insights would be helpful.

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• MySQL select using datetime, group by date only

  - by Matt

  Is is possible to select a datetime field from a MySQL table and group by the date only? I'm trying to output a list of events that happen at multiple times, grouped by the date it happened on. My table/data looks like this: (the timestamp is a datetime field) 1. 2010-03-21 18:00:00 Event1 2. 2010-03-21 18:30:00 Event2 3. 2010-03-30 13:00:00 Event3 4. 2010-03-30 14:00:00 Event4 I want to output something like this: March 21st 1800 - Event 1 1830 - Event 2 March 30th 1300 - Event 3 1400 - Event 4 Thanks!

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• Specify which row to return on SQLite Group By

  - by lozzar

  I'm faced with a bit of a difficult problem. I store all the versions of all documents in a single table. Each document has a unique id, and the version is stored as an integer which is incremented everytime there is a new version. I need a query that will only select the latest version of each document from the database. While using GROUP BY works, it appears that it will break if the versions are not inserted in the database in the order of version (ie. it takes the maximum ROWID which will not always be the latest version). Note, that the latest version of each document will most likely be a different number (ie. document A is at version 3, and document B is at version 6). I'm at my wits end, does anybody know how to do this (select all the documents, but only return a single record for each document_id, and that the record returned should have the highest version number)?

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• mysql query: SELECT DISTINCT column1, GROUP BY column2

  - by Adam

  Right now I have the following query: SELECT name, COUNT(name), time, price, ip, SUM(price) FROM tablename WHERE time >= $yesterday AND time <$today GROUP BY name And what I'd like to do is add a DISTINCT by column 'ip', i.e. SELECT DISTINCT ip FROM tablename So my final output would be all the columns, from all the rows that where time is today, grouped by name (with name count for each repeating name) and no duplicate ip addresses. What should my query look like? (or alternatively, how can I add the missing filter to the output with php)? Thanks in advance.

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• Grouping with operands question

  - by Filip

  I have a table: mysql> desc kursy_bid; +-----------+-------------+------+-----+---------+-------+ | Field | Type | Null | Key | Default | Extra | +-----------+-------------+------+-----+---------+-------+ | datetime | datetime | NO | PRI | NULL | | | currency | varchar(6) | NO | PRI | NULL | | | value | varchar(10) | YES | | NULL | | +-----------+-------------+------+-----+---------+-------+ 3 rows in set (0.01 sec) I would like to select some rows from a table, grouped by some time interval (can be one day) where I will have the first row and the last row of the group, the max(value) and min(value). I tried: select datetime, (select value order by datetime asc limit 1) open, (select value order by datetime desc limit 1) close, max(value), min(value) from kursy_bid_test where datetime > '2009-09-14 00:00:00' and currency = 'eurpln' group by month(datetime), day(datetime), hour(datetime); but the output is: | open | close | datetime | max(value) | min(value) | +--------+--------+---------------------+------------+------------+ | 1.4581 | 1.4581 | 2009-09-14 00:00:05 | 4.1712 | 1.4581 | | 1.4581 | 1.4581 | 2009-09-14 01:00:01 | 1.4581 | 1.4581 | As you see open and close is the same (but they shouldn't be). What should be the query to do what I want?

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• sql select statement with a group by

  - by user85116

  I have data in 2 tables, and I want to create a report. Table A: tableAID (primary key) name Table B: tableBID (primary key) grade tableAID (foreign key, references Table A) There is much more to both tables, but those are the relevant columns. The query I want to run, conceptually, is this: select TableA.name, avg(TableB.grade) where TableB.tableAID = TableA.tableAID The problem of course is that I'm using an aggregate function (avg), and I can rewrite it like this: select avg(grade), tableAID from TableB group by tableAID but then I only get the ID of TableA, whereas I really need that name column which appears in TableA, not just the ID. Is it possible to write a query to do this in one statement, or would I first need to execute the second query I listed, get the list of id's, then query each record in TableA for the name column... seems to me I'm missing something obvious here, but I'm (quite obviously) not an sql guru...

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• Top x rows and group by (again)

  - by Tibor Szasz

  Hello, I know it's a frequent question but I just can't figure it out and the examples I found didn't helped. What I learned, the best strategy is to try to find the top and bottom values of the top range and then select the rest, but implementing is a bit tricky. Example table: id | title | group_id | votes I'd like to get the top 3 voted rows from the table, for each group. I'm expecting this result: 91 | hello1 | 1 | 10 28 | hello2 | 1 | 9 73 | hello3 | 1 | 8 84 | hello4 | 2 | 456 58 | hello5 | 2 | 11 56 | hello6 | 2 | 0 17 | hello7 | 3 | 50 78 | hello8 | 3 | 9 99 | hello9 | 3 | 1 I've fond complex queries and examples, but they didn't really helped.

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• MySQL: filling empty fields with zeroes when using GROUP BY

  - by SaltLake

  I've got MySQL table CREATE TABLE cms_webstat ( ID int NOT NULL auto_increment PRIMARY KEY, TIMESTAMP_X timestamp DEFAULT CURRENT_TIMESTAMP, # ... some other fields ... ) which contains statistics about site visitors. For getting visits per hour I use SELECT hour(TIMESTAMP_X) as HOUR , count(*) AS HOUR_STAT FROM cms_webstat GROUP BY HOUR ORDER BY HOUR DESC which gives me | HOUR | HOUR_STAT | | 24 | 15 | | 23 | 12 | | 22 | 9 | | 20 | 3 | | 18 | 2 | | 15 | 1 | | 12 | 3 | | 9 | 1 | | 3 | 5 | | 2 | 7 | | 1 | 9 | | 0 | 12 | And I'd like to get following: | HOUR | HOUR_STAT | | 24 | 15 | | 23 | 12 | | 22 | 9 | | 21 | 0 | | 20 | 3 | | 19 | 0 | | 18 | 2 | | 17 | 0 | | 16 | 0 | | 15 | 1 | | 14 | 0 | | 13 | 0 | | 12 | 3 | | 11 | 0 | | 10 | 0 | | 9 | 1 | | 8 | 0 | | 7 | 0 | | 6 | 0 | | 5 | 0 | | 4 | 0 | | 3 | 5 | | 2 | 7 | | 1 | 9 | | 0 | 12 | How should I modify the query to get such result? Thanks.

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• SQL vs MySQL: Rules about aggregate operations and GROUP BY

  - by Phazyck

  In this book I'm currently reading while following a course on databases, the following example of an illegal query using an aggregate operator is given: Find the name and age of the oldest sailor. Consider the following attempt to answer this query: SELECT S.name, S.age FROM Sailors.S The intent is for this query to return not only the maximum age but also the name of the sailors having that age. However, this query is illegal in SQL--if the SELECT clause uses an aggregate operation, then it must use only aggregate operations unless the query contains a GROUP BY clause! Some time later while doing an exercise using MySQL, I faced a similar problem, and made a mistake similar to the one mentioned. However, MySQL didn't complain and just spit out some tables which later turned out not be what I needed. Is the query above really illegal in SQL, but legal in MySQL, and if so, why is that? In what situation would one need to make such a query?

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• Getting counts of 0 from a query with a double group by

  - by Maltiriel

  I'm trying to write a query that gets the counts for a table (call it item) categorized by two different things, call them type and code. What I'm hoping for as output is the following: Type Code Count 1 A 3 1 B 0 1 C 10 2 A 0 2 B 13 2 C 2 And so forth. Both type and code are found in lookup tables, and each item can have just one type but more than one code, so there's also a pivot (aka junction or join) table for the codes. I have a query that can get this result: Type Code Count 1 A 3 1 C 10 2 B 13 2 C 2 and it looks like (with join conditions omitted): SELECT typelookup.name, codelookup.name, COUNT(item.id) FROM typelookup LEFT OUTER JOIN item JOIN itemcodepivot RIGHT OUTER JOIN codelookup GROUP BY typelookup.name, codelookup.name Is there any way to alter this query to get the results I'm looking for? This is in MySQL, if that matters. I'm not actually sure this is possible all in one query, but if it is I'd really like to know how. Thanks for any ideas.

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• How do I use SPMemember.ID property to get User or Group

  - by Jason

  I have to write a utility to enumerate and manage the owners of groups within a SharePoint site. I know I can use the Groups property of the SPWeb object to retrieve a collection of groups. And I know I can use the Owner property of the group to get back the owner. My problem is that I do not know what to do next. The SPGroup.Owner property returns a SPMember object. The member object has one property called ID that returns the unique ID (an integer) of the member. What I cannot seem to find information on is how to use that integer value to determine if the member is a User or a Group and how to get back additional details (say the name). Any ideas? Thanks.

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• Working by group by for grouping data into string format

  - by Shantanu Gupta

  I have a table that contains some data given below. It uses a tree like structure i.e. Department SubD1, SubD2 ..... PreSubD1, PreSubD1... PreSubD2, PreSubD2... pk_map_id preferences ImmediateParent Department_Id -------------------- -------------------- -------------------- -------------------- 20 14 5 1 21 15 5 1 22 16 6 1 23 9 4 2 24 4 3 2 25 24 20 2 26 25 20 2 27 23 13 2 I want to group my records on behalf of department then immediate parent then preferences each seperated by ',' i.e. department Immediate Parent preferences 1 5,6 14,15,16 2 4,3,20,13 9,4,24,25,23 and this table also Immediate parent preferences 5 14,15 6 16 4 9 3 4 20 24,25 13 13 In actual scenario all these are my ids which are to be replaced by their string fields. I am using sql server 2k5

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• how to select and group mysql data based on the follwoing table

  - by user1151680

  how can I achieve the desired result in mysql if my table looks like this. result|year 1 |2011 2 |2011 1 |2011 0 |2011 1 |2012 2 |2012 1 = Won, 2 = lost, 0 = draw Every year can have multiple values like this. Not sure how I can get the desired result like below. year won lost draw totalPlayed 2011 2 1 1 3 2012 1 1 0 2 I have tried the following query but does not get the desired result select year, league_types.league_name, sum(if(result = 1,1,0)) as won, sum(if(result = 0,1,0)) as draw, sum(if(result = 4,1,0)) as noResult, sum(if(result = 2,1,0)) as lost, sum(if(result = 3,1,0)) as tied, sum(if(result > 0 and result < 4,1,0)) as played from match_score_card inner join fixtures on match_score_card.match_id = fixtures.match_id inner join league_types on fixtures.league_id = league_types.league_id where team_id = 1 group by year order by year desc

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• MySQL query with JOINS and GROUP BY

  - by user1854049

  I'm building a MySQL query but I can't seem to get it right. I have four tables: - customers - orders - sales_rates - purchase_rates There is a 1:n relation 'customernr' between customers and orders. There is a 1:n relation 'ordernr' between orders and sales_rates. There is a 1:n relation 'ordernr' between orders and purchase_rates. What I would like to do is produce an output of all customers with their total purchase and sales amounts. So far I have the following query. SELECT c.customernr, c.customer_name, SUM(sr.sales_price) AS sales_price, SUM(pr.purchase_price) AS purchase_price FROM orders o, customers c, sales_rates sr, purchase_rates pr WHERE o.customernr = c.customernr AND o.ordernr = sr.ordernr AND o.ordernr = pr.ordernr GROUP BY k.bedrijfsnaam The result of the sales_price and purchase_price is far too high. I seem to be getting double counts. What am I doing wrong? Is it possible to perform this in a single query? Thank for your response!

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• Oracle Group By Issue

  - by m_oLogin

  Hello community, I am strugling with what seems an easy problem to tackle (at least for me in MySQL / SqlServer!) I'll simplify the problem. Let's say I have the following table: Table VOTE ID ID_IDEA DATE_VOTE with ID_IDEA FK(IDEA.ID) 1 3 10/10/10 2 0 09/09/10 3 3 08/08/10 4 3 11/11/10 5 0 06/06/10 6 1 05/05/10 I'm trying to find the latest votes given for each individual idea, meaning I want to return only rows with ID 4, 2 and 6. It seems with Oracle that you can't use GROUP BY without using a function like SUM(), AVG, etc. I'm a bit confused about how it's supposed to work. Please advise, Thanks.

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• Oracle Utilities Application Framework V4.1 Group Fix 4 available

  - by ACShorten

  Oracle Utilities Application Framework V4.1 Group Fix 4 is available from My Oracle Support as Patch 13523301. This Group Fix contains a number of enhancements and keeps fixes up to date to the latest patch level. The enhancements included in this Group Fix include: UI Hints - In previous group fixes of the Oracle Utilities Application Framework the infrastructure to support UI Hints was introduced. This group fix completes the release of this functionality. Prior to this enhancement, products and implementers typically would build at least one UI Map per Business Object to display and/or maintain the object. Whilst, this can be generated using the UI Map maintenance function and stored, this enhancement allows additional tags and elements to be added to the Business Object directly to allow dynamic generation of the UI Map for maintenance and viewing the object. This reduces the need to generate and build a UI Map at all for that object. This will reduce maintenance effort of maintaining the product and implementation by eliminating the need to maintain the HTML for the UI Map. This also allows lower skilled personnel to maintain the system. Help and working examples are available from the View schema attributes and node names option from the Schema Tips dashboard zone. For example: Note: For examples of the hints, refer to an of the following Business Objects F1_OutcomeStyleLookup, F1-TodoSumEmailType, F1-BOStatusReason or F1-BIGeneralMasterConfig. Setting batch log file names -  By default the batch infrastructure supplied with the Oracle Utilities Application Framework sets the name and location of the log files to set values. In Group Fix 4 a set of user exits have been added to allow implementers and partners to set their own filename and location.  Refer to the Release Notes in the download for more details.

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• Setting up group disk quotas

  - by Ray

  I am hoping to get some advice in setting up disk quotas. So, I know about: Adding usrquota and grpquota on to /etc/fstab for the file systems that need to be managed. Using edquota to assign disk quotas to users. However, I need to do the last step for multiple users and edquota seems to be a bit troublesome. One solution that I have found is that I can do: sudo edquota -u foo -p bar. This will copy the disk quota of bar to user foo. I was wondering if this is the best solution? I tried setting up group disk quotas but they don't seem to be working. Are group quotas meant to help in the assignment of the same quota to multiple users? Or are they suppose to give a total limit to a set of users? For example, if users A, B, C are in group X then assigning a quota of 20 GB gives each user 20 GB or does it give 20 GB to the entire group X to divide up? I'm interested in doing the former, but not the latter. Right now, I've assigned group disk quotas and they aren't working. So, I guess it is due to my misunderstanding of group disk quotas... My problem is I want to easily give the same quota to multiple users; any suggestions on the best way to do this out of what I've tried above or anything else I may not have thought of? Thank you!

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• SharePoint Saturday DC

  - by Mark Rackley

  Wow… did you see this thing? 927 attendees? An exhibition hall full of vendors? 94 speakers? 100 sessions?? Insane is a word that comes to mind… SharePoint Saturday DC was definitely epic as far as SharePoint Saturdays go. I got to catch up with a lot of friends and make some new ones.  Met a couple of fans of the blog (hello ladies…;))  Did you know that people actually read this thing? I guess that means I need to stop putting so much garbage on here and more content. I’ll get right on that as soon as I find out how to add 6 hours to each day. Anyway, once again I did my “Wrapping Your Head Around the SharePoint Beast” session.  I tweaked it even more from Huntsville and presented to a packed room with some people sitting on the floor and standing in the aisles. It was a great crowd, very interactive and they seemed interested at least. Thank you guys so much for attending and please feel free to tell me of any suggestions you have to make the presentation better.  This is one of the presentations that will probably never die. Everyone beginning SharePoint development needs a good introduction and starting point. My goal is to make this THE session to see on the subject. So, a little interesting data about my class. Half of the room was brand new to SharePoint and only one person was using 2010. That tells me that this session still has legs and that 2007 isn’t going anywhere anytime soon.  I know my organization will be using 2007 for at least a couple more years. Oh yeah… the slide deck?  Here it is: SharePoint Saturday DC Slide Deck So, SharePoint Saturday was truly tremendous and if you weren’t there you missed out. @meetdux, @usher, and the rest of their crew did a spectacular job. You guys rock and are a huge asset to the community. Thanks for allowing me to speak. What’s up next for me?  I’m so glad you asked…. SHAREPOINT SATURDAY OZARKS IS JUNE 12TH! Although SharePoint Saturday Ozarks on June 12 in Harrison Arkansas will be a much more intimate event than DC, it promises to be a most memorable event. We’ve got over 30 speakers and sessions, some cool stuff to give away, and we’re going floating down the Buffalo River on the 13th. Let’s see you do THAT in DC.  :) Anyway, I hope to see you there and I would truly appreciate any help you can do to help publicize the event. We just got internet here in the hills and most people here are still looking for the “any” key….

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