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  • Saving a huge dataset into SQL table in a XML column - MS SQL, C#.Net

    - by NLV
    Hello all I'm having a requirement where i've to save a dataset which has multiple tables in it in a sql table XML column by converting into an XML. The problem is that in some cases the dataset grows extremely huge and i get OutOfMemoryException. What i basically do is that i convert the dataset into an xml file and save it in the local disk and then load the XML again and send it as a stored procedure parameter. But when i write the dataset xml into the disk the file sizes over 700 Mb and when i load it in the XMLDocument object in memory i get OutOfMemoryException. How can get the dataset xml without saving it in a file and re-reading it again? Thank You NLV

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  • PostgreSQL 8.3 data types: xml vs varchar

    - by Sejanus
    There's xml data type in Postgres, I never used it before so I'd like to hear opinions. Downsides and upsides vs using regular varchar (or Text) column to store xml. The text I'm going to store is xml, well-formed, UTF-8. No need to search by it (I've read searching by xml is slow). This XML actually is data prepared for PDF generation with Apache FOP. XML can be generated dynamically from data found elsewhere (other Postgres tables), it's stored as is only so that I won't need to generate it twice. Kinda backup#2 for already generated PDF documents. Anything else to know? Good practices, performance, maintenance, etc?

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  • Problem of reading OWL/XML

    - by Mikae Combarado
    Hello, I have a problem reading OWL/XML files from Java using Jena. I have no problem reading RDF/XML files, but whenever I create a OWL/XML file from Protege and try to read it, Java gives this error below : WARN [main] (RDFDefaultErrorHandler.java:36) Exception in thread "main" java.lang.NullPointerException at com.hp.hpl.jena.rdf.arp.impl.XMLHandler.endElement(XMLHandler.java:143) The code that I use to retrieve RDF/XML is below : OntModel ontModel = ModelFactory.createOntologyModel(); InputStream in = FileManager.get().open(inputFileName); if (in == null) { throw new IllegalArgumentException( "File: " + inputFileName + " not found"); } ontModel.read(in, ""); This code works with RDF/XML perfectly. However, I cannot read an OWL/XML. I looked at Internet and I couldn't find anything. I would really appreciate, if someone shows me a way. Many thanks

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  • Actionscript 3 : XML cached in local testing

    - by Boun
    Hi, My question is about XML loading. I need to avoid xml caching. On a web server, the technique is adding a random param to reload each time the XML file. But on local testing (in Flash CS4 IDE, CTRL + Enter), the following lines are not possible : var my_date : Date; path = "toto.xml?time="+my_date.getSeconds()+my_date.getMilliseconds(); Is there any trick to bypass this issue ? I've read on different forum about the "delete" method, we delete the xml object and then recreate one new. In my case, I put : myXML = null; myXML = new XML ( loadedData ); But it doesn't work at all. I spent many hours on that problem, if anyone has a good solution... Thank you.

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  • Why can XSLT not parse this XML?

    - by Matt W
    Taking the XSLT and XML from this page as an example: http://www.w3schools.com/xsl/xsl_transformation.asp I have an xml file which contains (above example modified): <?xml version="1.0" encoding="ISO-8859-1"?> <?xml-stylesheet type="text/xsl" href="cdcatalog.xsl"?> <catalog xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns="http://tempuri.org/"> <cd> In my case, the output contains nothing when the XSLT/XML is processed by the browser. The moment I remove the attributes from the element, it works. Problem is, I don't really have the option of pre-processing those attributes out of the file. Can anyone explain how to force the XSLT to work with the XML as is, please? After all, those attributes seem fairly standard. Many thanks, Matt.

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  • Link XSL Style Sheet to XForms generated XML document

    - by iHeartGreek
    Hi! Through XForms, I generate an XML document. I need this XML document to be transformed by a specific XSL. How do I link the XSL to the XML through XForms? Example of link: <?xml-stylesheet type="text/xsl" href="test.xsl"?> (The XML doc gets regenerated every time the XForms submits to it.. so I cannot hardcode the link in the XML doc, in needs to be done through the XForms) Thanks!

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  • Parsing WordPress XML, slash:comments syntax?

    - by user313653
    This is really just a syntax question. I have a PHP script that parses my WordPress feed and returns the latest posts. I also want my script to parse the # of comments, but the WordPress feed XML object for number of comments has a colon in it (slash:comments). It causes the following error: Parse error: syntax error, unexpected ':' in ... on line ... I have tried each of the following without luck: $xml->slash:comments $comments = 'slash:comments' $xml->$comments $xml->slash.':'.comments $xml->{slash:comments} $xml->{'slash:comments'} How do I parse an object with a colon?

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  • 'Out of Memory exception' in sql server 2005 xml column

    - by Raghuraman
    Hi All, I am devloping a windows forms application and am using sql server 2005 database as my backend. I am having an xml column in my database. I am using ultrawingrid control in my application.I obtain the xml of the dataset which is bound to my ultrawingrid control and pass that as a parameter value to the stored procedure where am inserting this value into the xml column which I specified. The columns in my grid are dynamic and hence there can be any no of columns in my grid. I got 'out of memory' exception in the dataset.GetXml() statement since there were more no of columns I believe.So, what I did is that I used dataset.WriteXml() method and stored all the xml contents into an xml file, loaded the xml file into the XmlDocument object and then passed the xmlnodereader as the value to the stored procedure parameter.Now, while executing the stored procedure am getting the same 'out of memory' exception. How could I resolve this issue?

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  • remove non-UTF-8 characters from xml with declared encoding=utf-8 - Java

    - by St Nietzke
    I have to handle this scenario in Java: I'm getting a request in XML form from a client with declared encoding=utf-8. Unfortunately it may contain not utf-8 characters and there is a requirement to remove these characters from the xml on my side (legacy). Let's consider an example where this invalid XML contains £ (pound). 1) I get xml as java String with £ in it (I don't have access to interface right now, but I probably get xml as a java String). Can I use replaceAll(£, "") to get rid of this character? Any potential issues? 2) I get xml as an array of bytes - how to handle this operation safely in that case?

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  • More XML Problems - Undeclared Entity 'nbsp'

    - by Gogster
    I'm getting the error: Line 49: xml = r.ReadToEnd(); Line 50: Line 51: System.Xml.Linq.XDocument xmlDoc = System.Xml.Linq.XDocument.Parse(xml); Line 52: Line 53: var query = from p in xmlDoc.Descendants("member") On my XML. When I run the code to generate the XML in an empty page, it runs without error, if I call the code within my webpage it throws this error. The only 'nbsp' on the page is a doctype declaration at the top of the XSLT: <!DOCTYPE xsl:stylesheet [ <!ENTITY nbsp "&#x00A0;"> ]> I'm at a loss as to where this error is coming from and I am looking for suggestions please! Thanks.

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  • Parsing XML data with Namespaces in PHP

    - by osbmedia
    I'm trying to work with this XML feed that uses namespaces and i'm not able to get past the colon in the tags. Here's how the XML feed looks like: <r25:events pubdate="2010-05-19T13:58:08-04:00"> <r25:event xl:href="event.xml?event_id=328" id="BRJDMzI4" crc="00000022" status="est"> <r25:event_id>328</r25:event_id> <r25:event_name>Testing 09/2005-08/2006</r25:event_name> <r25:alien_uid/> <r25:event_priority>0</r25:event_priority> <r25:event_type_id xl:href="evtype.xml?type_id=105">105</r25:event_type_id> <r25:event_type_name>CABINET</r25:event_type_name> <r25:node_type>C</r25:node_type> <r25:node_type_name>cabinet</r25:node_type_name> <r25:state>1</r25:state> <r25:state_name>Tentative</r25:state_name> <r25:event_locator>2005-AAAAMQ</r25:event_locator> <r25:event_title/> <r25:favorite>F</r25:favorite> <r25:organization_id/> <r25:organization_name/> <r25:parent_id/> <r25:cabinet_id xl:href="event.xml?event_id=328">328</r25:cabinet_id> <r25:cabinet_name>cabinet 09/2005-08/2006</r25:cabinet_name> <r25:start_date>2005-09-01</r25:start_date> <r25:end_date>2006-08-31</r25:end_date> <r25:registration_url/> <r25:last_mod_dt>2008-02-27T14:22:43-05:00</r25:last_mod_dt> <r25:last_mod_user>abc00296004</r25:last_mod_user> </r25:event> </r25:events> And here is what I'm using for code - I'll trying to throw these into a bunch of arrays where I can format the output however I want: <?php $ch = curl_init(); curl_setopt($ch, CURLOPT_URL, "http://somedomain.com/blah.xml"); curl_setopt ($ch, CURLOPT_HTTPHEADER, Array("Content-Type: text/xml")); curl_setopt($ch, CURLOPT_USERPWD, "username:password"); curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1); $output = curl_exec($ch); curl_close($ch); $xml = new SimpleXmlElement($output); foreach ($xml->events->event as $entry){ $dc = $entry->children('http://www.collegenet.com/r25'); echo $entry->event_name . "<br />"; echo $entry->event_id . "<br /><br />"; }

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  • Word 2010 for writing invoices, starting with XML

    - by TomTom
    Hello, we are doing quite some invoice generation, and so far it is based on some pretty awful word automation that is now in for a review with Word 2010. I would love to move to a XML based format for storing / presenting invoices, only going to a word document in the last stage. This means I can use easily othermeans to present an invoice internally from the XML. We use Word as "last stage" because Word is a lot better than anything else ever discovered for formatting - our invoices have quite some text sometimes, in the invoice item table, and word is smartest with handling page breaks in the "correct" way. Now, here my question: is there any proper way by now to do this with XML easily? I remember Word having (had) in 2007 some XML field mapping mechanism, but it did not handle tables in the XML. Was anything changed? What would be the proposed approach for generating an .docx document (starting with a .dotx templace) for an invoice, if the relevant data is available in XML form?

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  • Flex 4: Defining a XML data model in an Actionscript Class

    - by Steve
    I'm really having a hard time accessing a data model I've defined in an Actionscript class in my Flex app. The following is my AS Class (Model.as): package { import mx.rpc.http.HTTPService; public class Model { private static var _instance:Model; public static function getInstance():Model { if (!_instance) _instance = new Model(); return _instance; } [Bindable] public var xml:mx.rpc.http.HTTPService = new mx.rpc.http.HTTPService(); Model.getInstance().xml.url = "http://127.0.01/RAF/DATAPOINTS.xml"; Model.getInstance().xml.resultFormat = "e4x"; } } I'm then trying to access this in my main application with the following code: Model.getInstance().xml.send(); var sectorList:XMLList = Model.getInstance().xml.lastResult; And it just keeps throwing errors. The errors are generic so I can't determine the source in debugging. Hope this is enough info...

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  • how do I find the number of xml children in AS3

    - by vasion
    so live docs says this for calling .lenght() on an XML object For XML objects, this method always returns the integer 1. The length() method of the XMLList class returns a value of 1 for an XMLList object that contains only one value. i called it on an xml that looked like this: <xml> <picture>1</picture> <picture>2</picture> </xml> and it reallt returned 1. how do i get the number of children in my xml?

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  • Remote XML retrieval

    - by rrrfusco
    I'm retrieving a remote XML file with wget -O remotefile localfile with a cron tab. Every so often the local file becomes malformed probably because of double whitespace (according to firefox) between the CDATA tags. Sometimes the parser gives an error for ' > ' missing, but upon checking the xml file the ' > ' exists... The remote xml file never gives malformed errors when called in the url. EDIT It seems CDATA is not parsed by the xml parser. (w3schools) Is there a way to set wget to retain wellformed XML? If not wget, What is a good way to continously retrieve a remote XML file and keep it well formed?

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  • parsing a xml to get some values

    - by Joan Silverstone
    Hello, i have this xml: http://www.managerleague.com/export_data.pl?data=transfers&output=xml&hide_header=0 These are player sales from a browser game. I want to save some fields from these sales. I am fetching that xml with curl and storing on my server. Then do the following: $xml_str = file_get_contents('salespage.xml'); $xml = new SimpleXMLElement($xml_str); $items = $xml->xpath('*/transfer'); print_r($items); foreach($items as $item) { echo $item['buyerTeamname'], ': ', $item['sellerTeamname'], "\n"; } The array is empty and i cant seem to get anything from it. What am i doing wrong?

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  • Write an xml file from the specified node?

    - by Googler
    Hi all, This is my xml file Input: <world> <patent> <xml>a</xml> <java>333</java> <jaxb>111</jaxb> </patent> </world> I need the read the above xml file and reproduce the following the output Output: <patent> <xml>a</xml> <java>333</java> <jaxb>111</jaxb> </patent> I dont need the world element. How to achieve this using Xpath. Can anyone help me on this?

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  • Maven Grails web.xml

    - by dunn less
    Might be a stupid question, but in my current maven project i do not have a web.xml in my /web-app/WEB-INF folder. There is no web-xml in my project and never has been, im trying to add it but my application is non-responsive to anything written in the web.xml. What am i missing?, iv tried specifying the path to it through the config.groovy like: grails.project.web.xml="web-app/WEB-INF/web.xml" Am i missing something? Do i need to specify the web.xml in some other config file in order to make my project utilize it ?

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  • php, extract data from a non-standard xml document

    - by Michael
    I have some kind xml content I need to extract the information and store it into database <xml file="136000000-136100000"> <Id>136000000</Id> <Name>Sem Serxy</Na me> <Email>[email protected]</Email> <DateRegistration>10/13/2010 1:49:30 AM</DateRegistration> </xml> <xml file="136000000-136100000"> <Id>136000001</Id> <Name>God Deckor</Name> <Email>[email protected]</Email> If I try simple xml load is not working as the document doesn't seem to be valid xml. I can use regex to extract the info with preg_match_all but I feel this is not the right way as the data is already well structured. Any other method ?

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  • Is the XML processing instructions node mandatory ?

    - by ereOn
    I had a discussion with a colleague of mine about the XML processing instructions node (I'm talking about this = <?xml version="1.0" encoding="UTF-8"?>). I believe that for something to be called "valid XML", it requires a processing instructions node. My colleague states that the processing instruction node is optionnal, since the default encoding is UTF-8 and the version is always 1.0. This make sense, but what does the standard says ? In short, given the following file: <books> <book id="1"><title>Title</title></book> </book> Can we say that: It is valid XML ? It is a valid XML node ? It is a valid XML document ? Thank you very much.

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  • XML/XSL nub: Is it possible to create an COMPOSITE XML/XSLT document?

    - by jmweekes
    I have just recently (like 2 days) started using XSLT documents with XML. I understand the basics and am able to generate a formatted document using an .XML document that references a separate .XSLT document. My question, as in the subject, is "Is it possible to create a SINGLE, composite document that contains both the XML data and XSLT processing/formatting/styling and displays as formatted HTML?" I am writing a desktop application in which I need to generate a formatted document on the fly from XML stored in the database. I want to do this without creating or referencing any actual physical files. I will generate a text string containing the XML/XSLT document and feed this to a WebBrowser component for formatted display. Hopefully what I want to do doesn't totally go against the whole XML/XSLT methodology. Any information, direction or suggestions will be greatly appreciated.

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  • Calling to_xml on an Array of ROXML objects results in an empty collection

    - by findchris
    Hi there. I have a ROXML object that looks like: class Activity include ROXML xml_accessor :id end If I have an array of these objects and call .to_xml on the array, I receive an empty xml collection: "<?xml version=\"1.0\" encoding=\"UTF-8\"?>\n<activities type=\"array\">\n</activities>\n" Any idea why or how to fix this? I'm running Rails 2.3.5 with the newest version of ROXML. Thanks

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  • Xml schema, how to make sure one element exists with a specific attribute value

    - by pexxxy
    How do I enforce the existing of an element with a specific attribute value in the XML? For example: <events> <event type="system" desc="this is a system event"/> <event type="bla1" desc="this is bla1 event"/> <event type="bla2" desc="this is bla2 event"/> </events> I need a rule to make sure the event element with type attribute = 'system' exists (once). All other event elements are optional;

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  • Should I use a collection here?

    - by Eva
    So I have code set up like this: public interface IInterface { public void setField(Object field); } public abstract class AbstractClass extends JPanel implements IInterface { private Object field_; public void setField(Object field) { field_ = field; } } public class ClassA extends AbstractClass { public ClassA() { // unique ClassA constructor stuff } public Dimension getPreferredSize() { return new Dimension(1, 1); } } public class ClassB extends AbstractClass { public ClassB() { // unique ClassB constructor stuff } public Dimension getPreferredSize() { return new Dimension(42, 42); } } public class ConsumerA { public ConsumerA(Collection<AbstractClass> collection) { for (AbstractClass abstractClass : collection) { abstractClass.setField(this); abstractClass.repaint(); } } } All hunky-dory so far, until public class ConsumerB { // Option 1 public ConsumerB(ClassA a, ClassB b) { methodThatOnlyTakesA(a); methodThatOnlyTakesB(b); } // Option 2 public ConsumerB(Collection<AbstractClass> collection) { for (IInterface i : collection) { if (i instanceof ClassA) { methodThatOnlyTakesA((ClassA) i); else if (i instanceof ClassB) { methodThatOnlyTakesB((ClassB) i); } } } } public class UsingOption1 { public static void main(String[] args) { ClassA a = new ClassA(); ClassB b = new ClassB(); Collection<AbstractClass> collection = Arrays.asList(a, b); ConsumerA consumerA = new ConsumerA(collection); ConsumerB consumerB = new ConsumerB(a, b); } } public class UsingOption2 { public static void main(String[] args) { Collection<AbstractClass> collection = Arrays.asList(new ClassA(), new ClassB()); ConsumerA = new ConsumerA(collection); ConsumerB = new ConsumerB(collection); } } With a lot more classes extending AbstractClass, both options get unwieldly. Option1 would make the constructor of ConsumerB really long. Also UsingOption1 would get long too. Option2 would have way more if statements than I feel comfortable with. Is there a viable Option3? If it helps, ClassA and ClassB have all the same methods, they're just implemented differently. Thanks for slogging through my code!

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  • Breadcrumb using and schema.org rich snippets

    - by Adam Jenkin
    I am having problems implementing the breadcrumb rich snippets from schema.org. When I construct my breadcrumb using the documentation and run via Google Rich Snippet testing tool, the breadcrumb is identified but not shown in the preview. <!DOCTYPE html> <html> <head> <title>My Test Page</title> </head> <body itemscope itemtype="http://schema.org/WebPage"> <strong>You are here: </strong> <div itemprop="breadcrumb"> <a title="Home" href="/">Home</a> > <a title="Test Pages" href="/Test-Pages/">Test Pages</a> > </div> </body> </html> If I change to use the snippets from data-vocabulary.org, the rich snippets show correctly in the preview. <!DOCTYPE html> <html> <head> <title>My Test Page</title> </head> <body> <strong>You are here: </strong> <ol itemprop="breadcrumb"> <li itemscope itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/" itemprop="url"> <span itemprop="title">Home</span> </a> </li> <li itemscope itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/Test-Pages/" itemprop="url"> <span itemprop="title">Test Pages</span> </a> </li> </ol> </body> </html> I want the breadcrumb to be shown in the search result rather than the url to the page. Given that schema.org is the recommended way to be using rich snippets, I would rather use this, however as the breadcrumb is not showing in the preview of the search result using this method, i'm not convinced this is working correctly. Am I doing something wrong in the markup for schema.org example?

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