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  • Searching for duplicate records within a text file where the duplicate is determined by only two fie

    - by plg
    First, Python Newbie; be patient/kind. Next, once a month I receive a large text file (think 7 Million records) to test for duplicate values. This is catalog information. I get 7 fields, but the two I'm interested in are a supplier code and a full orderable part number. To determine if the record is dupliacted, I compress all special characters from the part number (except . and #) and create a compressed part number. The test for duplicates becomes the supplier code and compressed part number combination. This part is fairly straight forward. Currently, I am just copying the original file with 2 new columns (compressed part and duplicate indicator). If the part is a duplicate, I put a "YES" in the last field. Now that this is done, I want to be able to go back (or better yet, at the same time) to get the previous record where there was a supplier code/compressed part number match. So far, my code looks like this: Compress Full Part to a Compressed Part and Check for Duplicates on Supplier Code and Compressed Part combination import sys import re import time ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ start=time.time() try: file1 = open("C:\Accounting\May Accounting\May.txt", "r") except IOError: print sys.stderr, "Cannot Open Read File" sys.exit(1) try: file2 = open(file1.name[0:len(file1.name)-4] + "_" + "COMPRESSPN.txt", "a") except IOError: print sys.stderr, "Cannot Open Write File" sys.exit(1) hdrList="CIGSUPPLIER|FULL_PART|PART_STATUS|ALIAS_FLAG|ACQUISITION_FLAG|COMPRESSED_PART|DUPLICATE_INDICATOR" file2.write(hdrList+chr(10)) lines_seen=set() affirm="YES" records = file1.readlines() for record in records: fields = record.split(chr(124)) if fields[0]=="CIGSupplier": continue #If incoming file has a header line, skip it file2.write(fields[0]+"|"), #Supplier Code file2.write(fields[1]+"|"), #Full_Part file2.write(fields[2]+"|"), #Part Status file2.write(fields[3]+"|"), #Alias Flag file2.write(re.sub("[$\r\n]", "", fields[4])+"|"), #Acquisition Flag file2.write(re.sub("[^0-9a-zA-Z.#]", "", fields[1])+"|"), #Compressed_Part dupechk=fields[0]+"|"+re.sub("[^0-9a-zA-Z.#]", "", fields[1]) if dupechk not in lines_seen: file2.write(chr(10)) lines_seen.add(dupechk) else: file2.write(affirm+chr(10)) print "it took", time.time() - start, "seconds." ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ file2.close() file1.close() It runs in less than 6 minutes, so I am happy with this part, even if it is not elegant. Right now, when I get my results, I import the results into Access and do a self join to locate the duplicates. Loading/querying/exporting results in Access a file this size takes around an hour, so I would like to be able to export the matched duplicates to another text file or an Excel file. Confusing enough? Thanks.

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  • Enable Disable JQuery Drag-able

    - by jafar201
    Hi all I am working on a print form that will enable Admin user Change the lay out of the print form so i select JQuery Dragable for the job and its working fine but their is one problem when Enable or Disable the first Element in HTML that is dragable take the Disable Style when Dragable is Disabled the other element keep there original look I am using IE 8 . I run the code on Fierfox and Chrome and the result was that all the Element change their style to disable style. I need the Elemnet to Keep there original Stayl <%@ Control Language="C#" AutoEventWireup="true" CodeBehind="PrintablePassportDesigner.ascx.cs" Inherits="CSPDPassportPrintingPOC.UserControls.PrintablePassportDesigner" % function EnableDragAndDrop(cBox) { $("#divDoB").draggable({ disabled: cBox.checked }); $("#divNationalNo").draggable({ disabled: cBox.checked }); $("#divSex").draggable({ disabled: cBox.checked }); $("#divPlaceOfBirth").draggable({ disabled: cBox.checked }); $("#divIssueDate").draggable({ disabled: cBox.checked }); $("#divMotherName").draggable({ disabled: cBox.checked }); $("#divExpDate").draggable({ disabled: cBox.checked }); $("#divAuthority").draggable({ disabled: cBox.checked }); $("#divPassportHolderName").draggable({ disabled: cBox.checked }); }

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  • Strange pattern matching with functions instancing Show

    - by Sean D
    So I'm writing a program which returns a procedure for some given arithmetic problem, so I wanted to instance a couple of functions to Show so that I can print the same expression I evaluate when I test. The trouble is that the given code matches (-) to the first line when it should fall to the second. {-# OPTIONS_GHC -XFlexibleInstances #-} instance Show (t -> t-> t) where show (+) = "plus" show (-) = "minus" main = print [(+),(-)] returns [plus,plus] Am I just committing a motal sin printing functions in the first place or is there some way I can get it to match properly? edit:I realise I am getting the following warning: Warning: Pattern match(es) are overlapped In the definition of `show': show - = ... I still don't know why it overlaps, or how to stop it.

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  • C# Reflection - How can I tell if object o is of type KeyValuePair and then cast it?

    - by Logan
    Hi All I'm currently trying to write a Dump() method from LinqPad equivalent iin C# for my own amusment. I'm moving from Java to C# and this is an exercise rather than a business requirement. I've got almost everything working except for Dumping a Dictionary. The problem is that KeyValuePair is a Value type. For most other Value types I simply call the ToString method but this is insufficient as the KeyValuePair may contain Enumerables and other objects with undesirable ToString methods. So I need to work out if it's a KeyValuePair and then cast it. In Java I could use wildcard generics for this but I don't know the equivalent in C#. Your quest, given an object o, determine if it's a KeyValuePair and call Print on its key and value. Print(object o) { ... } Thanks!

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  • Calculating the null space of a matrix

    - by Ainsworth
    I'm attempting to solve a set of equations of the form Ax = 0. A is known 6x6 matrix and I've written the below code using SVD to get the vector x which works to a certain extent. The answer is approximately correct but not good enough to be useful to me, how can I improve the precision of the calculation? Lowering eps below 1.e-4 causes the function to fail. from numpy.linalg import * from numpy import * A = matrix([[0.624010149127497 ,0.020915658603923 ,0.838082638087629 ,62.0778180312547 ,-0.336 ,0], [0.669649399820597 ,0.344105317421833 ,0.0543868015800246 ,49.0194290212841 ,-0.267 ,0], [0.473153758252885 ,0.366893577716959 ,0.924972565581684 ,186.071352614705 ,-1 ,0], [0.0759305208803158 ,0.356365401030535 ,0.126682113674883 ,175.292109352674 ,0 ,-5.201], [0.91160934274653 ,0.32447818779582 ,0.741382053883291 ,0.11536775372698 ,0 ,-0.034], [0.480860406786873 ,0.903499596111067 ,0.542581424762866 ,32.782593418975 ,0 ,-1]]) def null(A, eps=1e-3): u,s,vh = svd(A,full_matrices=1,compute_uv=1) null_space = compress(s <= eps, vh, axis=0) return null_space.T NS = null(A) print "Null space equals ",NS,"\n" print dot(A,NS)

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  • python win32api registery key change

    - by user340495
    Hi, I am trying to trigger an event every time a registry value is being modified. import win32api import win32event import win32con import _winreg key = _winreg.OpenKey(_winreg.HKEY_CURRENT_USER,'Control Panel\Desktop',0,_winreg.KEY_READ) sub_key = _winreg.CreateKey(key,'Wallpaper') evt = win32event.CreateEvent(None,0,0,None) win32api.RegNotifyChangeKeyValue(sub_key,1,win32api.REG_NOTIFY_CHANGE_ATTRIBUTES,evt,True) ret_code=win32event.WaitForSingleObject(evt,3000) if ret_code == win32con.WAIT_OBJECT_0: print "CHANGED" if ret_code == win32con.WAIT_TIMEOUT: print "TIMED" my problem is that this is never triggered , the event always time-out. (the reg key I am trying to follow is the wallpaper) [ please note I trigger the event by 1) manually changing the registry value in regedit 2) an automated script which run this : from ctypes import windll from win32con import * windll.user32.SystemParametersInfoA(SPI_SETDESKWALLPAPER, 0,"C:\wall.jpg",SPIF_UPDATEINIFILE | SPIF_SENDWININICHANGE) ] Thanks for any help in advance :) EDIT:: sorry about formatting

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  • What do I need to distribute (keys, certs) for Python w/ SSL-socket connection?

    - by fandingo
    I'm trying to write a generic server-client application that will be able to exchange data amongst servers. I've read over quite a few OpenSSL documents, and I have successfully setup my own CA and created a cert (and private key) for testing purposes. I'm stuck with Python 2.3, so I can't use the standard "ssl" library. Instead, I'm stuck with PyOpenSSL, which doesn't seem bad, but there aren't many documents out there about it. My question isn't really about getting it working. I'm more confused about the certificates and where they need to go. Here are my two programs that do work: Server: #!/bin/env python from OpenSSL import SSL import socket import pickle def verify_cb(conn, cert, errnum, depth, ok): print('Got cert: %s' % cert.get_subject()) return ok ctx = SSL.Context(SSL.TLSv1_METHOD) ctx.set_verify(SSL.VERIFY_PEER|SSL.VERIFY_FAIL_IF_NO_PEER_CERT, verify_cb) # ?????? ctx.use_privatekey_file('./Dmgr-key.pem') ctx.use_certificate_file('Dmgr-cert.pem') # ?????? ctx.load_verify_locations('./CAcert.pem') server = SSL.Connection(ctx, socket.socket(socket.AF_INET, socket.SOCK_STREAM)) server.bind(('', 50000)) server.listen(3) a, b = server.accept() c = a.recv(1024) print(c) Client: from OpenSSL import SSL import socket import pickle def verify_cb(conn, cert, errnum, depth, ok): print('Got cert: %s' % cert.get_subject()) return ok ctx = SSL.Context(SSL.TLSv1_METHOD) ctx.set_verify(SSL.VERIFY_PEER, verify_cb) # ?????????? ctx.use_privatekey_file('/home/justin/code/work/CA/private/Dmgr-key.pem') ctx.use_certificate_file('/home/justin/code/work/CA/Dmgr-cert.pem') # ????????? ctx.load_verify_locations('/home/justin/code/work/CA/CAcert.pem') sock = SSL.Connection(ctx, socket.socket(socket.AF_INET, socket.SOCK_STREAM)) sock.connect(('10.0.0.3', 50000)) a = Tester(2, 2) b = pickle.dumps(a) sock.send("Hello, world") sock.flush() sock.send(b) sock.shutdown() sock.close() I found this information from ftp://ftp.pbone.net/mirror/ftp.pld-linux.org/dists/2.0/PLD/i586/PLD/RPMS/python-pyOpenSSL-examples-0.6-2.i586.rpm which contains some example scripts. As you might gather, I don't fully understand the sections between the " # ????????." I don't get why the certificate and private key are needed on both the client and server. I'm not sure where each should go, but shouldn't I only need to distribute one part of the key (probably the public part)? It undermines the purpose of having asymmetric keys if you still need both on each server, right? I tried alternating removing either the pkey or cert on either box, and I get the following error no matter which I remove: OpenSSL.SSL.Error: [('SSL routines', 'SSL3_READ_BYTES', 'sslv3 alert handshake failure'), ('SSL routines', 'SSL3_WRITE_BYTES', 'ssl handshake failure')] Could someone explain if this is the expected behavior for SSL. Do I really need to distribute the private key and public cert to all my clients? I'm trying to avoid any huge security problems, and leaking private keys would tend to be a big one... Thanks for the help!

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  • listing objects from ManyToManyField

    - by Noam Smadja
    i am trying to print a list of all the Conferences and for each conference, print its 3 Speakers. in my template i have: {% if conferences %} <ul> {% for conference in conferences %} <li>{{ conference.date }}</li> {% for speakers in conference.speakers %} <li>{{ conference.speakers }}</li> {% endfor %} {% endfor %} </ul> {% else %} <p>No Conferences</p> {% endif %} in my views.py file i have: from django.shortcuts import render_to_response from youthconf.conference.models import Conference def manageconf(request): conferences = Conference.objects.all().order_by('-date')[:5] return render_to_response('conference/manageconf.html', {'conferences': conferences}) there is a model named conference. which has a class named Conferences with a ManyToManyField named speakers i get the error: Caught an exception while rendering: 'ManyRelatedManager' object is not iterable with this line: {% for speakers in conference.speakers %}

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  • Basic Python While loop compound conditional evaluation

    - by dbjohn
    In Python IDLE Shell it seems I cannot use a compound conditional expression and a while loop. I tried it within brackets too. k=0 m=0 while k<10 & m<10: print k k +=1 m+=1 If I write while k<10: print k k+=1 This does work. Is there a way I could achieve the first block of code with the "and" operator. I have done it in Java. Do I just need to put together "if" statements to achieve the same functionality in Python?

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  • Infinite recursion trying to check all elements of a TreeCtrl

    - by mavnn
    I have a TreeCtrl in which more than one Item can be assigned the same object as PyData. When the object is updated, I want to update all of the items in the tree which have that object as their PyData. I thought the following code would solve the problem quite neatly, but for some reason the logical test (current != self.GetFirstVisibleItem()) always returns true leading to infinite recursion. Can anyone explain why? def RefreshNodes(self, obj, current=None): print "Entered refresh" current = current or self.GetFirstVisibleItem() if current.IsOk(): print self.GetPyData(current).name if self.GetPyData(current) == obj: self.RefreshNode(current) current = self.GetNextVisible(current) if current != self.GetFirstVisibleItem(): self.RefreshNodes(obj, current) Edit: the above is obviously part of a class based on wx.TreeCtrl

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  • Python 3: Recursivley find if number is even

    - by pythonhack
    I am writing a program that must find if a number is even or not. It needs to follow this template. I can get it to find if a number is even or not recursively (call function and subtract 2, base case zero), but I am having a hard time following this template, based on how the isEven function is called in the main function. Any help would be greatly appreciated. Write a recursive function called isEven that finds whether a number is even or not: def isEven() #recursivley determine whether number is even or not def main(): number=int(input(“Enter a number : “)) if (isEven(number)): print(“Number is even”) else: print(“Number is not even”) main() Thank you! Appreciate it.

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  • Replacing backslashes in Python strings

    - by user323659
    I have some code to encrypt some strings in Python. Encrypted text is used as a parameter in some urls, but after encrypting, there comes backslashes in string and I cannot use single backslash in urllib2.urlopen. I cannot replace single backslash with double. For example: print cipherText '\t3-@\xab7+\xc7\x93H\xdc\xd1\x13G\xe1\xfb' print cipherText.replace('\\','\\\\') '\t3-@\xab7+\xc7\x93H\xdc\xd1\x13G\xe1\xfb' Also putting r in front of \ in replace statement did not worked. All I want to do is calling that kind of url: http://awebsite.me/main?param="\t3-@\xab7+\xc7\x93H\xdc\xd1\x13G\xe1\xfb" And also this url can be successfully called: http://awebsite.me/main?param="\\t3-@\\xab7+\\xc7\\x93H\\xdc\\xd1\\x13G\\xe1\\xfb" Any idea will be appreciated.

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  • How to improve performance of opening Microsoft Word when automated from c#?

    - by Abdullah BaMusa
    I have Microsoft Word template that I automated filling it’s fields from my application, and when the user request print I open this template. but creating word application every time user request print after filling fields is very expensive and lead to some delay while opening the template, so I choose to cache the reference to Word then just open the new filled template. that solve the performance issue as opening file is less expensive than recreating Word each time, but this work while the user just close the document not the entire Word application which when happened my reference to Word become invalid and return with exception says: “The RPC server is unavailable” next time request opening template . I tried to subscribe to BeforClosing event but his trigger for Quitting Word as well as Closing documents. My question is how to know if the word is closing document or quit the entire application so I take the proper action, or any hint for another direction of thinking about improve performance of opening word template.

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  • Solving linear system over integers with numpy

    - by A. R. S.
    I'm trying to solve an overdetermined linear system of equations with numpy. Currently, I'm doing something like this (as a simple example): a = np.array([[1,0], [0,1], [-1,1]]) b = np.array([1,1,0]) print np.linalg.lstsq(a,b)[0] [ 1. 1.] This works, but uses floats. Is there any way to solve the system over integers only? I've tried something along the lines of print map(int, np.linalg.lstsq(a,b)[0]) [0, 1] in order to convert the solution to an array of ints, expecting [1, 1], but clearly I'm missing something. Could anyone point me in the right direction?

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  • How can I mix command line arguments and filenames for <> in Perl?

    - by Jimmeh
    Consider the following silly Perl program: $firstarg = $ARGV[0]; print $firstarg; $input = <>; print $input; I run it from a terminal like: perl myprog.pl sample_argument And get this error: Can't open sample_argument: No such file or directory at myprog.pl line 5. Any ideas why this is? When it gets to the < is it trying to read from the (non-existent) file, "sample_argument" or something? And why?

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  • Java program runtime error

    - by Sam
    public class BooksTestDrive { public static void main(String[] args) { Books [] myBooks = new Books[3]; int x=0; myBooks[0].title = "The Grapes of Jave"; myBooks[1].title = "The Java Gatsby"; myBooks[2].title = "The Java Cookbook"; myBooks[0].author = "bob"; myBooks[1].author = "sue"; myBooks[2].author = "ian"; while (x < 3) { System.out.print(myBooks[x].title); System.out.print("by"); System.out.println(myBooks[x].author); x = x+1; } } } This code compiles but while runtime, its giving nullpointer exception.

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  • What technology should I use for a complex report?

    - by SeaDrive
    I have a task to generate reports from a Visual Studio C# application. This is a replacement (caused by new requirements) for a program written using the built-in implementation of Crystal Reports. Although workable, it was far from ideal. The reports have conditional content (If type=1, print this, if type=2 print that.) Crystal does not adjust spacing dynamically and the various pieces were not the same length making for some unprofessional-looking spacing. I had thought of generating the reports in HTML, which would be feasible, but I'm concerned that you lose a degree of control, and I may be asked, e.g. to "move this up a bit" or similar which may be tricky. I'm not either a Crystal guru or an HTML guru. What other reporting technologies are available that would make it easy to drop in parts of different sizes, do table layouts, etc.?

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  • Resizing JPanel to prepare for printing without removing it from its original position

    - by Lesman
    In my program I frequently need to print various JComponents (generally JPanels) and I like them to be full-page. The way I do it now is by using the following code: g2d.scale(pf.getImageableWidth()/componentToPrint.getWidth(), pf.getImageableHeight()/componentToPrint.getHeight()); but this often stretches or otherwise deforms whatever I am trying to print, and I would much prefer to do something that re-sized intelligently, perhaps a functional version of: componentToPrint.setSize(pf.ImageableWidth(), pf.ImageableHeight); or say adding the component into a new JFrame and then setting the frame size (problem is components can't exist in two place at once). I wouldn't care if the resizing would make the rest of the GUI look terrible, as long as it is something that can easily be reset. Is there any way to do this?

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  • can i changed for loop index variable inside the loop in Matlab???

    - by shawana
    hi every one. i need to change my loop variable inside the iterationa as ihave to acces array elements in the loop which is changing w.r.t size inside the loop. ashort piece of code is that: que=[]; que=[2,3,4]; global len; len=size(que,2) x=4; for i=1:len if x<=10 que(x)= 5; len=size(que,2) x=x+1; end end que array should print like: 2 3 4 5 5 5 5 5 5 5 but it is printed in such a way: 2 3 4 5 5 5. how shuould it be accomplished in matlab? in visual c++ it happen correctly and print whole array of 10 elements which increases at run time plz reply me if have any ideaabout this as i m new into matlab

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  • Windows Service Printing Behaviour

    - by Andre
    Alright, I was tasked to develop a Windows Service that listens to a directory for files that are dropped in it, read them, delete them and print out a report. I installed the service on my work laptop (Win 7 x86) and a test machine (XP x86) under a User account at first. It would do everything as it should except the print the report. No errors, nothing. Then I made it run under Local System and it produced a "No printers found" exception. Converting the app to a Console Application and running on these machines gave the desired result. OK, so now I was assuming that there are security "stuff" involved. Then I installed the service on a Server 2008 x64 machine (under Local System) and it just worked. Can anybody explain to me why this is happening? Why does the service allow printing from Server OS but not from a Desktop OS or am I missing something very obvious?

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  • im writing this code so the user would enter his/her name and followed by his/her marks to get the a

    - by WM
    What if the user wanted to enter his/her grades in the following way: Will 23, 34, 45, 45 how would i get rid of the commas public class StudentAverage { public static void main(String[] args) { int markSum = 0; double average = 0; Scanner input1 = new Scanner(System.in); System.out.print("Enter student record : "); String name = input1.next(); Scanner input2 = new Scanner(input1.nextLine()); int countTotal = 0; while (input2.hasNextInt()) { countTotal++; markSum += input2.nextInt(); } average = markSum / countTotal; // to calculate the total average System.out.print( name + " " + average ); } }

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  • AWK: how to reuse a result NR-times without removing END?

    - by HH
    How can I get all differences, not just one? I want to use the calculated result for each item in the third column. The dilemma is that if I remove END I can print $3 but cannot have ave. If I leave END I have ave but not all differences. awk '{sum+=$3} END {ave=sum/NR} END {print $3-ave}' coriolis_data -0.00964 // I want to see the rest differences, how? coriolis_data .105 0.005 0.9766 0.0001 0.595 0.005 .095 0.005 0.9963 0.0001 0.595 0.005 .115 0.005 0.9687 0.0001 0.595 0.005 .105 0.005 0.9693 0.0001 0.595 0.005 .095 0.005 0.9798 0.0001 0.595 0.005 .105 0.005 0.9798 0.0001 0.595 0.005 .095 0.005 0.9711 0.0001 0.595 0.005 .110 0.005 0.9640 0.0001 0.595 0.005 .105 0.005 0.9704 0.0001 0.595 0.005 .090 0.005 0.9644 0.0001 0.595 0.005

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  • perl: added hash entry in a subroutine is lost

    - by hansi
    Why is the hash empty on the second call of printHash? my %hash = (); addToHash(\%hash); printHash(\%hash); sub addToHash { my %hash = %{$_[0]}; $hash{"test"} = "test"; printHash(\%hash); } sub printHash { print "printHash: \n"; my %hash = %{$_[0]}; foreach my $key (keys %hash) { print "key: $key, value: $hash{$key}\n"; } } Output: printHash: key: test, value: test printHash:

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  • Selenium selected option in dropdown not displayed correctly

    - by luckyfool
    I have the following issue with Selenium Webdriver. There are two dropdown menus on a page i am testing "brand" and "items". The options of "items" depend on which brand you choose. I am trying to iterate through all possible choices and print brand-item pairs. I use two possible ways to pick an option from each dropdown menu Using Select(): def retryingSelectOption(name,n): result=False attempts=0 while attempts<5: try: element=Select(driver.find_element_by_name(name)) element.select_by_index(n) print element.all_selected_options[0].text result=True break except StaleElementReferenceException: pass attempts+=1 return result And using .click(): def retryingClickOption(name,n): result=False attempts=0 while attempts<5: try: driver.find_element_by_name(name).find_elements_by_tag_name("option")[n].click() result=True break except StaleElementReferenceException: pass attempts+=1 return result My problem is that at ,what seem to me as random moments (sometimes it works sometimes it does not), even though the above functions return True and printing out the selected option shows me the correct answer, the browser still displays the previous option. So basically Selenium tells me i have picked the right option but the browser displays the previous one.No idea what is wrong.

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