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  • Why is Mac OS X 10.6 using /usr/lib to start Apache when I compiled PHP using /opt/local/lib?

    - by Anthony
    PHP 5.3.3 compiled on Mac OS X 10.6 - using /usr/lib when trying to start Apache... rather than /opt/local/lib specified when PHP was configured. Why is it trying to load from /usr/lib when I specified in my configure not to? httpd: Syntax error on line 115 of /private/etc/apache2/httpd.conf: Cannot load /usr/libexec/apache2/libphp5.so into server: dlopen(/usr/libexec/apache2/libphp5.so, 10): Library not loaded: /opt/local/lib/libiconv.2.dylib\n Referenced from: /usr/libexec/apache2/libphp5.so\n Reason: Incompatible library version: libphp5.so requires version 8.0.0 or later, but libiconv.2.dylib provides version 7.0.0 The error message above refers to /opt/local/lib which when I run: otool -LD /opt/local/lib/libiconv.2.dylib Message: /opt/local/lib/libiconv.2.dylib: /opt/local/lib/libiconv.2.dylib (compatibility version 8.0.0, current version 8.0.0) /usr/lib/libSystem.B.dylib (compatibility version 1.0.0, current version 125.0.0) It shows that the version is different than what httpd is erring out as. I have a feeling I need to recompile Apache using newer libraries, but the error message still doesn't make too much sense to me.

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  • Apache 2.4.2 with PHP 5.4.4 crashes as soon as phpinfo() script is opened

    - by Gremo
    As soon as i open a phpinfo() script called version.php apache stops working. Here is the error.log file. My configuration (my local development machine): Windows 7 Home Premium x64 SP1 with latest updates Apache 2.4.2 win32 from Apache Lounge PHP 5.4.4 VC9 x86 TS from PHP For Windows php5apache2_4.dll (PHP 5.4.4) taken from Apache Lounge php5apache2_4.dll-php-5.4-win32.zip PATH environment variable is PATH=C:\WAMP\Apache\bin;C:\WAMP\PHP and installation folders (unzipping) are: C:/WAMP/Apache C:/WAMP/PHP Microsoft Visual C++ 2010 SP1 x86/x64 installed and updated. So everything looks fine to me. PHP integration in httpd.conf is: # Integrazione PHP LoadModule php5_module "C:/WAMP/PHP/php5apache2_4.dll" PhpIniDir "C:/WAMP/PHP" AddType application/x-httpd-php .php <IfModule dir_module> DirectoryIndex index.html index.php </IfModule>

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  • suPHP permission requirements for all files or only PHP scripts?

    - by puk
    Generally with PHP, files/folders have a permission of 0777 when we want to write to them. suPHP forbids a permission of 0777. Instead, files are supposed to have a permission of 0644 and folders have a permission 0755. However, this is always worded differently SuPHP won't allow chmod of 777 so we need to set all files to 644 and directories to 755 Your scripts and directories can now, only have a maximum of 755 permissions Set file permission(s) to allow read access only by you (e.g., chmod 600 filename.suphp). What is the exact rule and to what files does it apply to? If I have README file somewhere in a nested directory does its permission need to be updated, or does it only apply to .php files?

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  • "PHP Error" when running PHPUnit tests from within Komodo IDE.

    - by Pheter
    I am using the latest version of the Komodo IDE, PEAR and PHPUnit with PHP version 5.3.0. When I run the unit tests for my Komodo project the tests run correctly, but regardless of whether there are any tests to run or not I get shown the error: --------------------------- PHP Error --------------------------- parse error in Unknown on line 7 --------------------------- OK --------------------------- Everything works fine despite this error but it is irritating to see every time I run my tests. Furthermore, running the unit tests from the command line does not trigger any kind of error, suggesting that this is a problem with Komodo. How can I fix the error or, at the very least, stop it from showing up.

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  • How do I share a PHP 5.4 server between OS X and VMWare?

    - by Ben
    I'm running PHP 5.4 on OS X which allows me to set up a virtual server for any directory, using this Terminal command: php -S localhost:8000 This will then set up http://localhost:8000 which works great, but what I would like to do is share this server with the instance of Windows that I have running through VMWare in order to test in Internet Explorer. I was wondering if this is possible and if it is, how do I go about setting it up? Currently trying to visit http://localhost:8000 gives me 'This page cannot be displayed'. I'd really appreciate any help that you can give me on this as I don't have much experience with virtual machines/networking. Thanks in advance.

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  • How to fix this error 'cvs [checkout aborted]: no such tag r20120711' on php eclipse helios?

    - by Manu-dra-kru
    I am using php eclipse helios for debugging php code and using CVS as repositiry. Under CVS repository there are 3 - head branch version and head conatins the repository of server. Under head again I have 3 bms cvsroot news4u To create a new branch I used to click on news4u and select a option 'add to branch list'. But accidently I selected 'Tag as version' with name r20120711 and after that I have created a branch by same name. Now if check out is taken, it gets check out partially and gets failed and if tried to commit the resource, it says, 'no tag is found by that name'. How to fix this.

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  • How to fix this error 'cvs [checkout aborted]: no such tag r20120711' on php eclipse helios?

    - by Manu-dra-kru
    I am using php eclipse helios for debugging php code and using CVS as repositiry. Under CVS repository there are 3 - head branch version and head conatins the repository of server. Under head again I have 3 bms cvsroot news4u To create a new branch I used to click on news4u and select a option 'add to branch list'. But accidently I selected 'Tag as version' with name r20120711 and after that I have created a branch by same name. Now if check out is taken, it gets check out partially and gets failed and if tried to commit the resource, it says, 'no tag is found by that name'. How to fix this.

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  • Why can I not access any file or directory created by PHP from FTP-client?

    - by user43053
    Hello there, If I create a directory with mkdir(), or create a file with fopen(), file_put_contents() or SimpleXMLElement::asXML(), I am unable to access the file with my FTP-client or c-Panel File Manager. If I try to delete or edit them, I get errors. Dreamweaver suggests it is a permission problem or a network or filesystem fault (but I've set the permissions with chmod() to 0777, and when I check the cPanel, it confirms chmod 777. I also tried to use fileowner() and the function returns int(99), the same owner as those files that I could access with my FTP-client. It seems files and directories created with PHP can only be modified or be deleted with PHP. I thought this must be a server setup related issue, so I write it here. I am on a shared server, and I have no idea about setting up servers. Thank you for your time. Kind regards Marius

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  • What is the best Linux distro for a php web server? [on hold]

    - by benjisail
    We are planning to upgrade our hardware and at the same time we plan to reinstall all our web server from a fresh OS. Currently our web server is running on CentOS 4.7 on a dedicated server. We are using Apache, Mysql, PHP, SVN, FTP and all the needed tools for a web server managed through SSH. We plan to use a cloud server for the new web server. I don't know which Linux distro to take for this new server. Should I stay with Centos and just take the latest release 5.4 or should I switch to something else like a Debian base distro (Ubuntu Server)? The thing that I didn't like with CentOS was the none availability of the latest version of PHP and Apache on Yum. This make it harder to keep our webserver updated with the latest technologies... Thanks for your help!

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  • Can you have multiple PHP 5.x versions with cPanel 11.3x?

    - by atomicguava
    I've been Googling around for a while on this one but I haven't found a good answer yet! Is it possible to set up cPanel 11.3x so that it can run different versions of PHP 5.x (e.g. 5.2, 5.3 and later on 5.4) for each of the configured apache vhosts / domains? It would be great to do this either using .htaccess, php.ini or a setting within cPanel itself. I've seen EasyApache 3 mentioned in the documentation but even after reading through several times I haven't seen a definitive yes or no for whether this is possible - please let me know if you need any more info. This was the documentation I found for EA3: http://goo.gl/IH1sP

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  • Varnish cache and PHP session; setting header?

    - by StCee
    Varnish by default would not cache page with cookies. I read on some posts that one workaround for PHP pages is to set header('Cache-Control: public, s-maxage=60'); in php pages. But would it makes Varnish cache the page with the session cookie? Session is started on that page, and although there is nothing personal on that page, I would still want the session to persist in case the user would do something private later. So is there a way to cache the page without the session cookie? And still be able to pass session between pages? I can imagine some sort of weird solution with hidden form, but I would prefer if it can be done with VCL configuration or header setting. Thanks a lot!

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  • How to insert a list of data files(described in CSV file) from client location into database using PHP programming?

    - by Golam Mustafa
    We have some DVD. Each of them contain ---A CSV file containing some information about the documents. ---The list of pdf file(Scanned document). Example of CSV file Title,Author,FileName Design Document 0455, Eric Clipton,ds0455.pdf Tesign Document 0511,Johanson E,td0511.pdf I want to write PHP code that would read the CSV file , insert each information to database table as record. Can anybody help me to provide any idea about ---- How to select individual file from the client location on the basis of file name in the CSV file using PHP script. Thanks Golam

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  • Upgrade PHP 5.1.6 to 5.2.x on Fedora 6 - Solutions?

    - by nicorellius
    I have a CRM on an old Fedora server, running Apache 2.2.6, MySQL 5.0.27, and PHP 5.1.6. I see a couple of options to fix my problem, but I thought I would consult the pros on this one here at Server Fault to see if I'm missing anything. This is after spending a good while searching the net for solutions. Option 1 Upgrade Fedora, step-wise, to Fedora 7 and then to 8, and then the PHP packages I need would be available. I know this is hazardous, because of repository location, dependencies, etc. Option 2 Upgrade using this method. This may or may not work, and so would be considered a crap shoot. I consulted some IT people and they say the best best is to back up data and build a new server with updated hard and software. I happen to agree, but wanted to exhaust all my resources first.

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  • Apache/Varnish/PHP: Just to confirm, is it possible to automatically update $_SERVER['REMOTE_ADDR'] to have the real client's IP?

    - by user1284857
    I just cannot seem to get the real client IP to show in PHP's $_SERVER['REMOTE_ADDR']. It shows in $_SERVER['X_FORWARDED_FOR'], but the $_SERVER['REMOTE_ADDR'] always points to the Varnish service IP. I've played around with just about every Varnish vcl suggestion I could find. I've installed Apache module mod_rpaf. But I still cannot get $_SERVER['REMOTE_ADDR'] to reflect the client's real IP... So my question is, is this even possible? Does everyone who uses Varnish have to do something like this for all PHP applications?: $_SERVER['REMOTE_ADDR'] = $_SERVER['X_FORWARDED_FOR']; Or am I simply not configuring it correctly?

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  • PHP script works fine until I send a parameter from HTTPService in Flash Builder 4?

    - by ben
    I'm using a PHP script to read an RSS feed in my Flex 4 app. The script works when I put the url of the feed in the actual script, but I can't get it to work when I try to send the URL as a parameter from a HTTPService in Flex. Can anyone tell me what I'm doing wrong? Here is the HTTPService from Flex 4 that I'm using: <mx:HTTPService url="http://talk.6te.net/proxy.php" id="proxyService" method="POST" result="rssResult()" fault="rssFault()"> <mx:request> <url> http://feeds.feedburner.com/nah_right </url> </mx:request> </mx:HTTPService> This is the script that works: <?php $ch = curl_init(); $timeout = 30; $userAgent = $_SERVER['HTTP_USER_AGENT']; curl_setopt($ch, CURLOPT_URL, "http://feeds.feedburner.com/nah_right"); curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1); curl_setopt($ch, CURLOPT_CONNECTTIMEOUT, $timeout); curl_setopt($ch, CURLOPT_USERAGENT, $userAgent); $response = curl_exec($ch); if (curl_errno($ch)) { echo curl_error($ch); } else { curl_close($ch); echo $response; } ?> But this is what I actually want to use, but it doesn't work: <?php $ch = curl_init(); $timeout = 30; $userAgent = $_SERVER['HTTP_USER_AGENT']; curl_setopt($ch, CURLOPT_URL, $_REQUEST['url']); curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1); curl_setopt($ch, CURLOPT_CONNECTTIMEOUT, $timeout); curl_setopt($ch, CURLOPT_USERAGENT, $userAgent); $response = curl_exec($ch); if (curl_errno($ch)) { echo curl_error($ch); } else { curl_close($ch); echo $response; } ?> Here is the request and response output of the HTTPService from the network monitor in Flash Builder 4 (using the PHP script that doesn't work): Request: POST /proxy.php HTTP/1.1 Host: talk.6te.net User-Agent: Mozilla/5.0 (Macintosh; U; Intel Mac OS X 10.6; en-US; rv:1.9.2.3) Gecko/20100401 Firefox/3.6.3 Accept: text/html,application/xhtml+xml,application/xml;q=0.9,*/*;q=0.8 Accept-Language: en-us,en;q=0.5 Accept-Encoding: gzip,deflate Accept-Charset: ISO-8859-1,utf-8;q=0.7,*;q=0.7 Keep-Alive: 115 Content-type: application/x-www-form-urlencoded Content-length: 97 url=%0A%09%09%09%09%09http%3A%2F%2Ffeeds%2Efeedburner%2Ecom%2Fnah%5Fright%0A%20%20%20%20%09%09%09 Response: HTTP/1.1 200 OK Date: Mon, 10 May 2010 03:23:27 GMT Server: Apache X-Powered-By: PHP/5.2.13 Content-Length: 15 Content-Type: text/html <url> malformed I've tried putting the URL in " " in the HTTPService, but that didn't do anything. Any help would be greatly appreciated!

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  • PHP script works fine until I send it a parameter from HTTPService in Flash Builder 4?

    - by ben
    I'm using a PHP script to read an RSS feed in my Flex 4 app. The script works when I put the url of the feed in the actual script, but I can't get it to work when I try to send the URL as a parameter from a HTTPService in Flex. Can anyone tell me what I'm doing wrong? Here is the HTTPService from Flex 4 that I'm using: <mx:HTTPService url="http://talk.6te.net/proxy.php" id="proxyService" method="POST" result="rssResult()" fault="rssFault()"> <mx:request> <url> http://feeds.feedburner.com/nah_right </url> </mx:request> </mx:HTTPService> This is the script that works: <?php $ch = curl_init(); $timeout = 30; $userAgent = $_SERVER['HTTP_USER_AGENT']; curl_setopt($ch, CURLOPT_URL, "http://feeds.feedburner.com/nah_right"); curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1); curl_setopt($ch, CURLOPT_CONNECTTIMEOUT, $timeout); curl_setopt($ch, CURLOPT_USERAGENT, $userAgent); $response = curl_exec($ch); if (curl_errno($ch)) { echo curl_error($ch); } else { curl_close($ch); echo $response; } ?> But this is what I actually want to use, but it doesn't work: <?php $ch = curl_init(); $timeout = 30; $userAgent = $_SERVER['HTTP_USER_AGENT']; curl_setopt($ch, CURLOPT_URL, $_REQUEST['url']); curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1); curl_setopt($ch, CURLOPT_CONNECTTIMEOUT, $timeout); curl_setopt($ch, CURLOPT_USERAGENT, $userAgent); $response = curl_exec($ch); if (curl_errno($ch)) { echo curl_error($ch); } else { curl_close($ch); echo $response; } ?> Here is the request and response output of the HTTPService from the network monitor in Flash Builder 4 (using the PHP script that doesn't work): Request: POST /proxy.php HTTP/1.1 Host: talk.6te.net User-Agent: Mozilla/5.0 (Macintosh; U; Intel Mac OS X 10.6; en-US; rv:1.9.2.3) Gecko/20100401 Firefox/3.6.3 Accept: text/html,application/xhtml+xml,application/xml;q=0.9,*/*;q=0.8 Accept-Language: en-us,en;q=0.5 Accept-Encoding: gzip,deflate Accept-Charset: ISO-8859-1,utf-8;q=0.7,*;q=0.7 Keep-Alive: 115 Content-type: application/x-www-form-urlencoded Content-length: 97 url=%0A%09%09%09%09%09http%3A%2F%2Ffeeds%2Efeedburner%2Ecom%2Fnah%5Fright%0A%20%20%20%20%09%09%09 Response: HTTP/1.1 200 OK Date: Mon, 10 May 2010 03:23:27 GMT Server: Apache X-Powered-By: PHP/5.2.13 Content-Length: 15 Content-Type: text/html <url> malformed I've tried putting the URL in " " in the HTTPService, but that didn't do anything. Any help would be greatly appreciated!

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  • IDs necessary in update script not being stored (or even seen!?) (PHP MySQL)

    - by Derek
    Hi guys, I really need help with this one...have spent 3 hours trying to figure it out... Basically, I have 3 tables necessary for this function to work (the query and PHP)... Authors, Books and Users. An author can have many books, and a user can have many books - that's it. When the admin user selects to update a book, they are presented with a form, displaying the current data within the fields, very straight forward... However there is one tricky part, the admin user can change the author for a book (incase they make a mistake) and also change the user for which the book is associated with. When I select to update the single book information I am not getting any values what so ever for author_id or user_id. Meaning that when the user updates the book info, the associations with the user and author is being scrapped altogether (when before there was an association)... I cannot see why this is happening because I can clearly see the IDs for the users and authors for my option values (this is because they are in select dropdowns). Here is what my sql to retrieve the user ID is: SELECT user_id, name FROM users and then i have my select options which brings up all the users in the system: <label>This book belongs to:</label> <select name="name" id="name"> <option value="<?php echo $row['user_id']?>" SELECTED><?php echo $row['name']?> - Current</option> <?php while($row = mysql_fetch_array($result)) { ?> <option value="<?php echo $row['user_id']; if (isset($_POST['user_id']));?>"><?php echo $row['name']?></option> <?php } ?> In the presented HTML form, I can select the users (by name) and within the source code I can see the IDs (for the value) matching against the names of the users. Finally, in my script that performs the update, I have this: $book_id = $_POST['book_id']; $bookname = $_POST['bookname']; $booklevel = $_POST['booklevel']; $author_id = $_POST['author_id']; $user_id = $_POST['user_id']; $sql = "UPDATE books SET bookname= '".$bookname."', booklevel= '".$booklevel."', author_id='".$author_id."', user_id= '".$user_id."' WHERE book_id = ".$book_id; The result of this query returns no value for either author_id or user_id... Obviously in this question I have given the information for the user stuff (with the HTML being displayed) but im guessing that I have the same problem with authors aswell... How can I get these ID's passed to the script so that the change can be acknowledge!! :(

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  • Can't find Localhost files

    - by GMF
    Hope you can help. This is my first time trying Ubuntu/Linux. I am logged in as root I have downloaded and installed LAMP and PHPMYADMIN. I get the test page under localhost say that It works and is installed Correctly. I have also put my files in the /var/www. they are PHP files When I put the address localhost/(page name.php) I get an error saying Not Found The requested URL /index.php was not found on this server. Apache/2.2.22 (Ubuntu) Server at localhost Port 80 I Have put the files in the wrong folder?? If I look in the "/etc/ap[ache2/sites-available/default", It tells my my DocumentRoot is /var/www Would love somehelp on this please Many thanks GF

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  • Can a loosely typed language be considered true object oriented?

    - by user61852
    Can a loosely typed programming language like PHP be really considered object oriented? I mean, the methods don't have returning types and method parameters has no declared type either. Doesn't class design require methods to have a return type? Don't methods signatures have specifically-typed parameters? How can OOP techniques help you code in PHP if you always have to check the types of parameters received because the language doesn't enforce types? Please, if I'm wrong, explain it to me. When you design things using UML, then code classes in PHP with no return-typed methods and no-type parameters... Is the code really compliant with the UML design? You spend time designing the architecture of your software, then the compiler doesn't force the programmer to follow your design while coding, letting he/she assign any object variable to any other variable with no "type-mismatch" warning.

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  • Which programming language for text editing?

    - by Ali
    I need a programming language for text editing and processing (replace, formatting, regex, string comparison, word processing, text analysis, etc). Which programming language is more powerful and has more functions for this purpose? Since I work PHP for my web projects, I currently use PHP; but the fact is that PHP is a scripting language for web applications, my current project is offline. I am curious if other programming languages such as Perl, Python, C, C++, Java, etc have more functionality for this purpose, and worth of shifting the project?

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  • Online & Offline in Web Chat Application

    - by Mohammed Safeer
    I stuck amidst developing a chat web application using php for client side app. I used comet for chat application. And use technique of updating database when someone logout. Thus display offline on other side user. My problem is if someone close browser without logout, how the other side user know the person goes offline. How can i set online and offline icon in a php webchat application, when someone close chat window without logout? Is web sockets in php solve this problem? welcome all suggestions.

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  • Confused about career options in Web Developement.

    - by Radheshyam Nayak
    I am currently in the final year of my graduation in computer science course. I love programming in PHP but not under pressure. As my graduation life is going to be over I have to shape up my career. My personal desire is to become a web developer and start my own web-based company after completion of courses. I do not have any desire to work for a company as a developer. Currently I have programming knowledge of PHP, Mysql and Javascript. Though I have not completed any type of project in PHP. So to become a complete web developer what else do I need to know to be able to get developement project? Any project I apply for are simply declined due to lack of portfolio. So how should I proceed?

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