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  • How to read the whole istream correctly?

    - by L.Lawliet
    Here is a simple code to print all characters of a txt file on screen: #include <iostream> #include <fstream> #include <string> using namespace std; int main() { int **i; int j,k; char a; ifstream test("test.txt", ios::binary); while((a=test.get())!=-1)//if I use "while(!test.eof())" here, how to avoid the output of the last character(-1) to std::cout, or any ostream objects? { putchar(a);//also change this to putchar(test.get()); } getchar(); } As I noted in the code, if I use "test.eof()" to judge the end of test.txt, I'll always get an extra blank at the end of the output. How to avoid it?

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  • Using current database name in T-SQL has Using statement

    - by AmRoSH
    Hello everybody. I have application runs T-SQL statements to update more than one database the problem is i'm using the following t-sql USE [msdb] GO DECLARE @jobId BINARY(16) EXEC msdb.dbo.sp_add_job @job_name=N'test2', @enabled=1, @start_step_id=1, @notify_level_eventlog=0, @notify_level_email=2, @notify_level_netsend=2, @notify_level_page=2, @delete_level=0, @description=N'', @category_name=N'[Uncategorized (Local)]', @owner_login_name=N'sa', @notify_email_operator_name=N'', @notify_netsend_operator_name=N'', @notify_page_operator_name=N'', @job_id = @jobId OUTPUT select @jobId GO EXEC msdb.dbo.sp_add_jobserver @job_name=N'test2', @server_name = N'AMR-PC\SQL2008' GO USE [msdb] GO EXEC msdb.dbo.sp_add_jobstep @job_name=N'test2', @step_name=N'test', @step_id=1, @cmdexec_success_code=0, @on_success_action=1, @on_fail_action=2, @retry_attempts=0, @retry_interval=0, @os_run_priority=0, @subsystem=N'TSQL', @command=N'EXEC sp_MSforeachdb '' EXEC sp_MSforeachtable @command1=''''DBCC DBREINDEX (''''''''*'''''''')'''', @replacechar=''''*''''''', @database_name=N'Client5281', @output_file_name=N'C:\Documents and Settings\Amr\Desktop\Scheduel Reports\report', @flags=2 GO USE [msdb] GO DECLARE @schedule_id int EXEC msdb.dbo.sp_add_jobschedule @job_name=N'test2', @name=N'test', @enabled=1, @freq_type=8, @freq_interval=1, @freq_subday_type=1, @freq_subday_interval=0, @freq_relative_interval=0, @freq_recurrence_factor=1, @active_start_date=20100517, @active_end_date=99991231, @active_start_time=0, @active_end_time=235959, @schedule_id = @schedule_id OUTPUT select @schedule_id GO and i'm using (USE [msdb]) before any block and i want to get database name to replace this @database_name=N'**Client5281**', with the current database name instead of ([msdb]) that i'm using. i hope that i explained what i want well.

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  • Calling software modules (Java, Perl, etc.) from R

    - by harshsinghal
    I've recently started using R for Natural Language Processing tasks and find that a lot of applications are available in Java and Perl (for my purposes). For example: A few perl modules are available to find distance measures between words by querying Wordnet. I am aware of the R Wordnet package, but it does not perform the tasks that these CPAN modules do. Many Java packages for NLP are out there, which I'd like to use from within R. I know of rJava, RSPerl, the simple system command amongst others, but I'd like more examples of how I could make calls to Java and Perl applications from R. Recently I tried capturing console output from a perl script. cat( 'print "Hello World\n";',file="hello.pl" ) system(command="c:\Perl64\bin\perl hello.pl") system(command=paste(Sys.getenv("COMSPEC"),"/c","C:\Perl64\bin\perl hello.pl")) None of the above system commands showed 'Hello World' on the R console. I've used "system" before to run perl scripts to perform tasks without wanting to capture console output. Any hints and redirection to other more extensive sources of information would be highly appreciated. Thank you

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  • Using scanf() in C++ programs is faster than using cin ?

    - by zeroDivisible
    Hello, I don't know if this is true, but when I was reading FAQ on one of the problem providing sites, I found something, that poke my attention: Check your input/output methods. In C++, using cin and cout is too slow. Use these, and you will guarantee not being able to solve any problem with a decent amount of input or output. Use printf and scanf instead. Can someone please clarify this? Is really using scanf() in C++ programs faster than using cin something ? If yes, that is it a good practice to use it in C++ programs? I thought that it was C specific, though I am just learning C++...

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  • How do I bypass GUI in MFC app if command line options exist?

    - by Brandon
    I've got an existing simple MFC app that the user specifies the input file, output file, and then a "Process" button. I'd like to just add the capability so that the input/output files are command line parameters. But, if they exist, I don't want the GUI to show up. I just want the "Process" to execute. I see where I can get the command line parameters (m_lpCmdLine) but how can I bypass the displaying of the GUI? If I step into the app, it goes directly to winmain.cpp and displays the GUI without stepping into any of my code.

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  • Python subprocess.Popen hangs in 'for l in p.stdout' until p terminates, why?

    - by Albert
    I have that code: #!/usr/bin/python -u localport = 9876 import sys, re, os from subprocess import * tun = Popen(["./newtunnel", "22", str(localport)], stdout=PIPE, stderr=STDOUT) print "** Started tunnel, waiting to be ready ..." for l in tun.stdout: sys.stdout.write(l) if re.search("Waiting for connection", l): print "** Ready for SSH !" break The "./newtunnel" will not exit, it will constantly output more and more data to stdout. However, that code will not give any output and just keeps waiting in the tun.stdout. When I kill the newtunnel process externally, it flushes all the data to tun.stdout. So it seems that I can't get any data from the tun.stdout while it is still running. Why is that? How can I get the information? Note that the default bufsize for Popen is 0 (unbuffered). I can also specify bufsize=0 but that doesn't change anything.

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  • Storing and retrieving CGPoints inside NSMutableArray

    - by Matt Dice
    I've looked through countless questions on here and elsewhere and cannot for the life of me figure out what I'm doing wrong. I'm trying to store an array of CGPoints as NSValues inside of an NSMutableArray named points like so on the iPhone: NSValue *point = [NSValue valueWithCGPoint:firstTouch]; NSLog(@"NSValue *point = %@", point); [points addObject:point]; NSLOG OUTPUT NSValue *point = NSPoint: {120, 221} Everything is going smooth converting from the CGPoint to NSValue. But when I try to retrieve the point I get nothing. NSValue *getPoint = [points objectAtIndex:0]; CGPoint thePoint = [getPoint CGPointValue]; NSLog(@"Point = %@", NSStringFromCGPoint(thePoint)); NSLOG OUTPUT Point = {0, 0} The points should be the same but I'm getting a null result. For testing purposes this is happening in the touchesBegan method. Does anyone have any idea where I'm going wrong? Thanks in advance.

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  • Linux server is only using 60% of memory, then swapping

    - by Kamil Kisiel
    I've got a Linux server that's running our bacula backup system. The machine is grinding like mad because it's going heavy in to swap. The problem is, it's only using 60% of its physical memory! Here's the output from free -m: free -m total used free shared buffers cached Mem: 3949 2356 1593 0 0 1 -/+ buffers/cache: 2354 1595 Swap: 7629 1804 5824 and some sample output from vmstat 1: procs -----------memory---------- ---swap-- -----io---- -system-- -----cpu------ r b swpd free buff cache si so bi bo in cs us sy id wa st 0 2 1843536 1634512 0 4188 54 13 2524 666 2 1 1 1 89 9 0 1 11 1845916 1640724 0 388 2700 4816 221880 4879 14409 170721 4 3 63 30 0 0 9 1846096 1643952 0 0 4956 756 174832 804 12357 159306 3 4 63 30 0 0 11 1846104 1643532 0 0 4916 540 174320 580 10609 139960 3 4 64 29 0 0 4 1846084 1640272 0 2336 4080 524 140408 548 9331 118287 3 4 63 30 0 0 8 1846104 1642096 0 1488 2940 432 102516 457 7023 82230 2 4 65 29 0 0 5 1846104 1642268 0 1276 3704 452 126520 452 9494 119612 3 5 65 27 0 3 12 1846104 1641528 0 328 6092 608 187776 636 8269 113059 4 3 64 29 0 2 2 1846084 1640960 0 724 5948 0 111480 0 7751 116370 4 4 63 29 0 0 4 1846100 1641484 0 404 4144 1476 125760 1500 10668 105358 2 3 71 25 0 0 13 1846104 1641932 0 0 5872 828 153808 840 10518 128447 3 4 70 22 0 0 8 1846096 1639172 0 3164 3556 556 74884 580 5082 65362 2 2 73 23 0 1 4 1846080 1638676 0 396 4512 28 50928 44 2672 38277 2 2 80 16 0 0 3 1846080 1628808 0 7132 2636 0 28004 8 1358 14090 0 1 78 20 0 0 2 1844728 1618552 0 11140 7680 0 12740 8 763 2245 0 0 82 18 0 0 2 1837764 1532056 0 101504 2952 0 95644 24 802 3817 0 1 87 12 0 0 11 1842092 1633324 0 4416 1748 10900 143144 11024 6279 134442 3 3 70 24 0 2 6 1846104 1642756 0 0 4768 468 78752 468 4672 60141 2 2 76 20 0 1 12 1846104 1640792 0 236 4752 440 140712 464 7614 99593 3 5 58 34 0 0 3 1846084 1630368 0 6316 5104 0 20336 0 1703 22424 1 1 72 26 0 2 17 1846104 1638332 0 3168 4080 1720 211960 1744 11977 155886 3 4 65 28 0 1 10 1846104 1640800 0 132 4488 556 126016 584 8016 106368 3 4 63 29 0 0 14 1846104 1639740 0 2248 3436 428 114188 452 7030 92418 3 3 59 35 0 1 6 1846096 1639504 0 1932 5500 436 141412 460 8261 112210 4 4 63 29 0 0 10 1846104 1640164 0 3052 4028 448 147684 472 7366 109554 4 4 61 30 0 0 10 1846100 1641040 0 2332 4952 632 147452 664 8767 118384 3 4 63 30 0 4 8 1846084 1641092 0 664 4948 276 152264 292 6448 98813 5 5 62 28 0 Furthermore, the output of top sorted by CPU time seems to support the theory that swap is what's bogging down the system: top - 09:05:32 up 37 days, 23:24, 1 user, load average: 9.75, 8.24, 7.12 Tasks: 173 total, 1 running, 172 sleeping, 0 stopped, 0 zombie Cpu(s): 1.6%us, 1.4%sy, 0.0%ni, 76.1%id, 20.6%wa, 0.1%hi, 0.2%si, 0.0%st Mem: 4044632k total, 2405628k used, 1639004k free, 0k buffers Swap: 7812492k total, 1851852k used, 5960640k free, 436k cached PID USER PR NI VIRT RES SHR S %CPU %MEM TIME+ TIME COMMAND 4174 root 17 0 63156 176 56 S 8 0.0 2138:52 35,38 bacula-fd 4185 root 17 0 63352 284 104 S 6 0.0 1709:25 28,29 bacula-sd 240 root 15 0 0 0 0 D 3 0.0 831:55.19 831:55 kswapd0 2852 root 10 -5 0 0 0 S 1 0.0 126:35.59 126:35 xfsbufd 2849 root 10 -5 0 0 0 S 0 0.0 119:50.94 119:50 xfsbufd 1364 root 10 -5 0 0 0 S 0 0.0 117:05.39 117:05 xfsbufd 21 root 10 -5 0 0 0 S 1 0.0 48:03.44 48:03 events/3 6940 postgres 16 0 43596 8 8 S 0 0.0 46:50.35 46:50 postmaster 1342 root 10 -5 0 0 0 S 0 0.0 23:14.34 23:14 xfsdatad/4 5415 root 17 0 1770m 108 48 S 0 0.0 15:03.74 15:03 bacula-dir 23 root 10 -5 0 0 0 S 0 0.0 13:09.71 13:09 events/5 5604 root 17 0 1216m 500 200 S 0 0.0 12:38.20 12:38 java 5552 root 16 0 1194m 580 248 S 0 0.0 11:58.00 11:58 java Here's the same sorted by virtual memory image size: top - 09:08:32 up 37 days, 23:27, 1 user, load average: 8.43, 8.26, 7.32 Tasks: 173 total, 1 running, 172 sleeping, 0 stopped, 0 zombie Cpu(s): 3.6%us, 3.4%sy, 0.0%ni, 62.2%id, 30.2%wa, 0.2%hi, 0.3%si, 0.0%st Mem: 4044632k total, 2404212k used, 1640420k free, 0k buffers Swap: 7812492k total, 1852548k used, 5959944k free, 100k cached PID USER PR NI VIRT RES SHR S %CPU %MEM TIME+ TIME COMMAND 5415 root 17 0 1770m 56 44 S 0 0.0 15:03.78 15:03 bacula-dir 5604 root 17 0 1216m 492 200 S 0 0.0 12:38.30 12:38 java 5552 root 16 0 1194m 476 200 S 0 0.0 11:58.20 11:58 java 4598 root 16 0 117m 44 44 S 0 0.0 0:13.37 0:13 eventmond 9614 gdm 16 0 93188 0 0 S 0 0.0 0:00.30 0:00 gdmgreeter 5527 root 17 0 78716 0 0 S 0 0.0 0:00.30 0:00 gdm 4185 root 17 0 63352 284 104 S 20 0.0 1709:52 28,29 bacula-sd 4174 root 17 0 63156 208 88 S 24 0.0 2139:25 35,39 bacula-fd 10849 postgres 18 0 54740 216 108 D 0 0.0 0:31.40 0:31 postmaster 6661 postgres 17 0 49432 0 0 S 0 0.0 0:03.50 0:03 postmaster 5507 root 15 0 47980 0 0 S 0 0.0 0:00.00 0:00 gdm 6940 postgres 16 0 43596 16 16 S 0 0.0 46:51.39 46:51 postmaster 5304 postgres 16 0 40580 132 88 S 0 0.0 6:21.79 6:21 postmaster 5301 postgres 17 0 40448 24 24 S 0 0.0 0:32.17 0:32 postmaster 11280 root 16 0 40288 28 28 S 0 0.0 0:00.11 0:00 sshd 5534 root 17 0 37580 0 0 S 0 0.0 0:56.18 0:56 X 30870 root 30 15 31668 28 28 S 0 0.0 1:13.38 1:13 snmpd 5305 postgres 17 0 30628 16 16 S 0 0.0 0:11.60 0:11 postmaster 27403 postfix 17 0 30248 0 0 S 0 0.0 0:02.76 0:02 qmgr 10815 postfix 15 0 30208 16 16 S 0 0.0 0:00.02 0:00 pickup 5306 postgres 16 0 29760 20 20 S 0 0.0 0:52.89 0:52 postmaster 5302 postgres 17 0 29628 64 32 S 0 0.0 1:00.64 1:00 postmaster I've tried tuning the swappiness kernel parameter to both high and low values, but nothing appears to change the behavior here. I'm at a loss to figure out what's going on. How can I find out what's causing this? Update: The system is a fully 64-bit system, so there should be no question of memory limitations due to 32-bit issues. Update2: As I mentioned in the original question, I've already tried tuning swappiness to all sorts of values, including 0. The result is always the same, with approximately 1.6 GB of memory remaining unused. Update3: Added top output to the above info.

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  • Problem with acceding in DOM with jQuery

    - by Tristan
    Hello, I changed the tree of my JSON-P output, and i cannot access to my object DOM anymore : Here's my output : jsonp1271634374310( {"Inter-Medias": {"name":"Inter-Medias","idGSP":"14","average":"80","services":"8.86"} }); And here's my jQuery script : success: function(data, textStatus, XMLHttpRequest){ widget = data.name; widget += data.average ; .... I know one level is missing, but if I try to do : data.Inter-Medias.name or data.name.name it's still not working. Any idea please ? I will have case where i'll have multiple Ojbect, so i want to display all of them, how to do that ? for (i=0;i < data.length;i++) Does it look right ? Bonus question : i understand function(data, textStatus, XMLHttpRequest) that in case of success this function is triggered, the data is what the script recieved from his request, but i have no idea what textStatus or XMLHttpRequest are here too and why ?! Thank you.

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  • MapReduce results seem limited to 100?

    - by user1813867
    I'm playing around with Map Reduce in MongoDB and python and I've run into a strange limitation. I'm just trying to count the number of "book" records. It works when there are less than 100 records but when it goes over 100 records the count resets for some reason. Here is my MR code and some sample outputs: var M = function () { book = this.book; emit(book, {count : 1}); } var R = function (key, values) { var sum = 0; values.forEach(function(x) { sum += 1; }); var result = { count : sum }; return result; } MR output when record count is 99: {u'_id': u'superiors', u'value': {u'count': 99}} MR output when record count is 101: {u'_id': u'superiors', u'value': {u'count': 2.0}} Any ideas?

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  • How to run shell script with live feedback from PHP?

    - by Highway of Life
    How would I execute a shell script from PHP while giving constant/live feedback to the browser? I understand from the system function documentation: The system() call also tries to automatically flush the web server's output buffer after each line of output if PHP is running as a server module. I'm not clear on what they mean by running it as a 'server module'. I attempted to run the script in the cgi-bin, but either I'm doing it wrong, or that's not what they mean. Example PHP code: <?php system('/var/lib/script_test.sh'); Example shell code: #!/bin/bash echo "Start..." for i in {1..10} do echo "$i..." sleep 1 done echo "Done."

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  • how to split string with some seperator but without removing that seperator in Java?

    - by sag
    Hi, I m facing problem in splitting string. Actually i want to split a string with some seperator but without loosing that seperator. when we use somestring.split(String seperator) method in java it splits the string but removes the seperator part from string.It should not happen. I want result like below: Example::string1="Ram-sita-laxman"; seperator="-"; string1.split(seperator); output : [Ram, sita, laxman] but i want the result like :[Ram, -sita, -laxman] is there a way to get output like this?

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  • Does MultiThreading in Java takes much time for task completion?

    - by Geeta
    I have to search for a string in 10 large size files (in zip format 70 MB) and have to print the lines with the search string to corresponding 10 output files.(i.e. file 1 output should be in output_file1...file2--- output_file2). The same program takes 15 mins for a single file. But if use 10 threads to read 10 files and to write in 10 different files it should complete in 15 mins but its taking 40 mins. How can I solve this. Or multithreading will take this much time only?

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  • Problem overridding virtual function

    - by William
    Okay, I'm writing a game that has a vector of a pairent class (enemy) that s going to be filled with children classes (goomba, koopa, boss1) and I need to make it so when I call update it calls the childclasses respective update. I have managed to create a example of my problem. #include <stdio.h> class A{ public: virtual void print(){printf("Hello from A");} }; class B : public A{ public: void print(){printf("Hello from B");} }; int main(){ A ab = B(); ab.print(); while(true){} } Output wanted: "Hello from B" Output got: "Hello from A" How do I get it to call B's print function?

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  • Find the gender from a name

    - by Ramesh
    Hi guys, I recently confronted with a weird yet interesting question. The questions is as follows: Need to write a program which can give the gender as output based on the name. Example: INPUT -- John Michael Britney OUTPUT-- male male female So this is the output I expect. I tried a lot to solve, but I really was not able to crack it. I will be really thankful to this site for giving me an opportunity to share this question. Actually this is asked in a programming contest as a flyer problem, so I thought this can be programmed.

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  • RS-232 confusion under C++

    - by rock
    What's the problem in given code? Why it is not showing the output for rs232 when we connect it by the d-9 connector with the short of pin number 2 & 3 in that? #include <bios.h> #include <conio.h> #define COM1 0 #define DATA_READY 0x100 #define SETTINGS ( 0x80 | 0x02 | 0x00 | 0x00) int main(void) { int in, out, status; bioscom(0, SETTINGS, COM1); /*initialize the port*/ cprintf("Data sent to you: "); while (1) { status = bioscom(3, 0, COM1); /*wait until get a data*/ if (status & DATA_READY) if ((out = bioscom(2, 0, COM1) & 0x7F) != 0) /*input a data*/ putch(out); if (kbhit()) { if ((in = getch()) == 27) /* ASCII of Esc*/ break; bioscom(1, in, COM1); /*output a data*/ } } return 0; }

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  • Confused about "override" vs. "new" in C#

    - by iTayb
    I'm having the following classes: class Base { public virtual void Print() { Console.WriteLine("Base"); } } class Der1 : Base { public new virtual void Print() { Console.WriteLine("Der1"); } } class Der2 : Der1 { public override void Print() { Console.WriteLine("Der2"); } } This is my main method: Base b = new Der2(); Der1 d1 = new Der2(); Der2 d2 = new Der2(); b.Print(); d1.Print(); d2.Print(); The output is Base, Der2, Der2. As far as I know, Override won't let previous method to run, even if the pointer is pointing to them. So the first line should output Der2 as well. However Base came out. How is it possible? How the override didn't work there?

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  • Setting a Global Doctype

    - by Batfan
    Is it possible using PHP (I was thinking may the phpinfo file or a php.ini file) or an .htaccess file to set a doctype for an entire subdirectory? Basically, in a nutshell, I'm using a software that uses XSL templates to output data to a set of HTML files. Modifying the xsl:output tag to include the doctype breaks the template and therefore, does not work. Just adding the doctype in the XSL file, breaks it as well. I need the proper doctypes in place for my CSS to function properly, cross-browser. I realize that I could add the doctype to the HTML files after export but, I'm really striving to automate this process. Any thoughts?

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  • How to call an xslt transform into an xsl stylesheet

    - by Mycol
    I have written an xslt that reads some xml file names and does some operations on them. I use a for-each to work them one-by-one. I have each path inside a parameter $path. But now I would like to output the result of applying an external stylesheet to those files. I would write something like <div> <something like xsl-transform($extern-xslt,$path)> </div> to have the result tree of the transformation inside the main html output. It is possible?

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  • Finding position of each word in a sub-array of a multidimensional array

    - by Shreyas Satish
    I have an array: tokens = [["hello","world"],["hello","ruby"]] all_tokens = tokens.flatten.uniq # all_tokens=["hello","world","ruby"] Now I need to create two arrays corresponding to all_tokens, where the first array will contain the position of each word in sub-array of tokens. I.E Output: [[0,0],[1],[1]] # (w.r.t all_tokens) To make it clear it reads, The index of "hello" is 0 and 0 in the 2 sub-arrays of tokens. And second array contains index of each word w.r.t tokens.I.E Output: [[0,1],[0],[1]] To make it clear it reads,the index of hello 0,1. I.E "hello" is in index 0 and 1 of tokens array. Cheers!

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  • Call static properties within another class in php

    - by ali A
    I have problem about calling a static property of a class inside another class. Class A { public $property; public function __construct( $prop ) { $this->property = $prop; } public function returnValue(){ return static::$this->property; } } Class B extends A { public static $property_one = 'This is first property'; public static $property_two = 'This is second property'; } $B = new B( 'property_one' ); $B->returnValue(); I expect to return This is first property But the Output is just the name a parameter input in __construct; When I print_r( static::$this->property ); the output is just property_one

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  • Ruby: rules for implicit hashes

    - by flyer
    Why second output shows me only one element of Array? Is it still Array or Hash already? def printArray(arr) arr.each { | j | k, v = j.first printf("%s %s %s \n", k, v, j) } end print "Array 1\n" printArray( [ {kk: { 'k1' => 'v1' }}, {kk: { 'k2' => 'v2' }}, {kk: { 'k3' => 'v3' }}, ]) print "Array 2\n" printArray( [ kk: { 'k1' => 'v1' }, kk: { 'k2' => 'v2' }, kk: { 'k3' => 'v3' }, ]) exit # Output: # # Array 1 # kk {"k1"=>"v1"} {:kk=>{"k1"=>"v1"}} # kk {"k2"=>"v2"} {:kk=>{"k2"=>"v2"}} # kk {"k3"=>"v3"} {:kk=>{"k3"=>"v3"}} # Array 2 # kk {"k3"=>"v3"} {:kk=>{"k3"=>"v3"}}

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  • join 3 files by first Column with awk ?

    - by noinflection
    i have three similar files, they are all like this: File A ID1 Value1a ID2 Value2a . . . IDN Value2n and i want an output like this Output ID1 Value1a Value1b Value1c ID2 Value2a Value2b Value2c ..... IDN ValueNa ValueNb ValueNc Looking to the first line, i want value1A to be the value of id1 in fileA, value1B the value of id1 in fileB, and so on which each field and each line. I thougth it like a sql join. I've tried several things but none of them where even close.

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