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  • scala jpa notifying hibernate

    - by coubeatczech
    Hi, i just tried to play a little with Scala Jpa, Downladed and run the basic lift-jpa-basic maven archetype, it works, but when I try to add my own @Entity, there is Unknown entity exception thrown. So what do I need to tell the environment to notify my entities? Thanks for answering.

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  • Hibernate Criteria API equivalent to HQL select clause?

    - by Visus Zhao
    I'd like to have a combined query for two persistent classes. In HQL this could be achieved by the select clause, select new Family(mother, mate, offspr) from DomesticCat as mother join mother.mate as mate left join mother.kittens as offspr In the above example, Family is a conbined class with DemesticCat as its construtor params What is the Criteria equivalent of the HQL select clause ?

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  • HQL(hibernate) timestamp range match

    - by Saky
    I need to write a query to get an object between a range of time, currently the query looks like this: Timestamp from = ... Timestamp to = ... getHibernateTemplate().find("from " + Person.class.getName() + " ml where ml.lastModifiedOn>="+from.toString()+" and m1.lastModifiedOn<=" + to.toString()); However, this doesnot work for obvious reasons. How can I format the timestamp to be acceptable by the query. org.springframework.orm.hibernate3.HibernateQueryException: unexpected token: 16 near line 1, column 123 [from Person ml where ml.lastModifiedOn=2010-02-12 16:00:21.292 and m1.lastModifiedOn

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  • Java Date Hibernate cut off time

    - by Vlad
    Hi folks, I have a Date type column in Oracle DB and it contains date and time for sure. But when I'm trying to get data in java application it will return date with bunch of zeros instead of real time. In code it'll be like: SQLQuery sqlQuery = session.createSQLQuery("SELECT table.id, table.date FROM table"); List<Object[]> resultArray = sqlQuery.list(); Date date = (Date)resultArray[1]; If it was 26-feb-2010 17:59:16 in DB I'll get 26-feb-2010 00:00:00 How to get it with time?

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  • hibernate update JPA foregin key

    - by cometta
    my jpa look like below public class TESTClass implements Serializable { ... private String name; @EmbeddedId protected IssTESTPK issTESTPK; @JoinColumns({@JoinColumn(name = "DIVISION_CODE", referencedColumnName = "DIVISION_CODE", nullable = false , insertable = false, updatable = false), @JoinColumn(name = "SURVEY_NUM", referencedColumnName = "SURVEY_NUM", nullable = false, insertable = false, updatable = false)}) @ManyToOne(optional = false) private IssDivision issDivision; } if i make change to 'name' and call merge, it able to update into database, but when i change issDivision, and call merge, it doesnt update database. how to solve this? does it related to because i'm using embededId (composite primary keys) ?

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  • Enum in Hibernate, persisting as an enum

    - by niklassaers
    In my MySQL database, there's the column "gender enum('male','female')" I've created my enum "com.mydomain.myapp.enums.Gender", and in my Person entity I'm defined "Gender gender". Now I'd want to keep the enum type in my MySQL database, but when I launch my application I get: Wrong column type in MyApp.Person for column Gender. Found: enum, expected: integer Why is this? This would be the equivalent as if I'd annotated my "Gender gender" with "@Enumerated(EnumType.ORDINAL)", which I haven't. EnumType seems only to be able to be either ORDINAL or STRING, so how do I specify that it should treat the field as an enum, not as an int? (not that there's much difference, but enough for it to get upset about it.)

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  • Hibernate proxy serialization and receive on client side.

    - by Bubba88
    I lack understanding of how does the generated proxy class object (CGLib enhanced POJO) is transferred to the remote client and still pertains its ability to generate Lazy Init. Exceptions. Does that mean that there is some kind of contract that all the transferred objects of some kind of class (a proxy) will be reinstantiated as proxies again? Where does the client obtain those generated classes? Sorry, but I totally do not understand.

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  • [java bean]hibernate Session breaks a java bean?

    - by blow
    Hi all, i have a simple JPanel bean in my projects, now i want to drag my panel bean class into my jframe. My panel bean class is like this: public class BeanPanel extends javax.swing.JPanel { /** Creates new form BeanPanel */ public BeanPanel () { initComponents(); Session session=HibernateUtil.getSessionFactory().openSession(); } This code seem to break the bean: Session session=HibernateUtil.getSessionFactory().openSession(); When i try to drag the class into my JFrame bean i had this error message: This component cannot be instantiated. Please make sure it is a JavaBeans Component If i comment it all works fine. What is the reason of this? Thanks.

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  • OneToOne JPA / Hibernate eager loading cause N+1 select

    - by Alexandre Lavoie
    I created a method to have multilingual text on different objects without creating field for each languages or tables for each objects types. Now the only problem I've got is N+1 select queries when doing a simple loading. Tables schema : CREATE TABLE `testentities` ( `keyTestEntity` int(11) NOT NULL, `keyMultilingualText` int(11) NOT NULL, PRIMARY KEY (`keyTestEntity`) ) ENGINE=MyISAM AUTO_INCREMENT=0 DEFAULT CHARSET=utf8; CREATE TABLE `common_multilingualtexts` ( `keyMultilingualText` int(11) NOT NULL auto_increment, PRIMARY KEY (`keyMultilingualText`) ) ENGINE=MyISAM AUTO_INCREMENT=0 DEFAULT CHARSET=utf8; CREATE TABLE `common_multilingualtexts_values` ( `languageCode` varchar(5) NOT NULL, `keyMultilingualText` int(11) NOT NULL, `value` text, PRIMARY KEY (`languageCode`,`keyMultilingualText`) ) ENGINE=MyISAM DEFAULT CHARSET=utf8; MultilingualText.java @Entity @Table(name = "common_multilingualtexts") public class MultilingualText implements Serializable { private Integer m_iKeyMultilingualText; private Map<String, String> m_lValues = new HashMap<String, String>(); public void setKeyMultilingualText(Integer p_iKeyMultilingualText) { m_iKeyMultilingualText = p_iKeyMultilingualText; } @Id @GeneratedValue @Column(name = "keyMultilingualText") public Integer getKeyMultilingualText() { return m_iKeyMultilingualText; } public void setValues(Map<String, String> p_lValues) { m_lValues = p_lValues; } @ElementCollection(fetch = FetchType.EAGER) @CollectionTable(name = "common_multilingualtexts_values", joinColumns = @JoinColumn(name = "keyMultilingualText")) @MapKeyColumn(name = "languageCode") @Column(name = "value") public Map<String, String> getValues() { return m_lValues; } public void put(String p_sLanguageCode, String p_sValue) { m_lValues.put(p_sLanguageCode,p_sValue); } public String get(String p_sLanguageCode) { if(m_lValues.containsKey(p_sLanguageCode)) { return m_lValues.get(p_sLanguageCode); } return null; } } And it is used like this on a object (having a foreign key to the multilingual text) : @Entity @Table(name = "testentities") public class TestEntity implements Serializable { private Integer m_iKeyEntity; private MultilingualText m_oText; public void setKeyEntity(Integer p_iKeyEntity) { m_iKeyEntity = p_iKeyEntity; } @Id @GeneratedValue @Column(name = "keyEntity") public Integer getKeyEntity() { return m_iKeyEntity; } public void setText(MultilingualText p_oText) { m_oText = p_oText; } @OneToOne(cascade = CascadeType.ALL) @JoinColumn(name = "keyText") public MultilingualText getText() { return m_oText; } } Now, when doing a simple HQL query : from TestEntity, I get a query selecting TestEntity's and one query for each MultilingualText that need to be loaded on each TestEntity. I've searched a lot and found absolutely no solutions. I have tested : @Fetch(FetchType.JOIN) optional = false @ManyToOne instead of @OneToOne Now I am out of idea!

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  • Hibernate orm for a view

    - by EugeneP
    How do you ORM a view? Is there any difference with a table in terms of reverse engineering? In my case, I have a whole pile of joined tables that will be read-only in an application. So, if I need sort of a 1 Object with all collections in proper order, instead of long chains of relationships - collection with another etc, it'll be simpler. What do you think and how do you accomplish this?

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  • Deleting objects with FK constraints in Spring/Hibernate

    - by maxdj
    This seems like such a simple scenario to me, yet I cannot for the life of my find a solution online or in print. I have several objects like so (trimmed down): @Entity public class Group extends BaseObject implements Identifiable<Long> { private Long id; private String name; private Set<HiringManager> managers = new HashSet<HiringManager>(); private List<JobOpening> jobs; @ManyToMany(fetch=FetchType.EAGER) @JoinTable( name="group_hiringManager", joinColumns=@JoinColumn(name="group_id"), inverseJoinColumns=@JoinColumn(name="hiringManager_id") ) public Set<HiringManager> getManagers() { return managers; } @OneToMany(mappedBy="group", fetch=FetchType.EAGER) public List<JobOpening> getJobs() { return jobs; } } @Entity public class JobOpening extends BaseObject implements Identifiable<Long> { private Long id; private String name; private Group group; @ManyToOne @JoinColumn(name="group_id", updatable=false, nullable=true) public Group getGroup() { return group; } } @Entity public class HiringManager extends User { @ManyToMany(mappedBy="managers", fetch=FetchType.EAGER) public Set<Group> getGroups() { return groups; } } Say I want to delete a Group object. Now there are dependencies on it in the JobOpening table and in the group_hiringManager table, which cause the delete function to fail. I don't want to cascade the delete, because the managers have other groups, and the jobopenings can be groupless. I have tried overriding the remove() function of my GroupManager to remove the dependencies, but it seems like no matter what I do they persist, and the delete fails! What is the right way to remove this object?

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  • Spring/Hibernate: InvocationTargetException when deleting entity

    - by niklassaers
    I'm sorry if this question is a bit vague, but I'm quite confused. I've got a controller that calls a service to delete an entity and then create an entity in its place. In the service, I've got my DAO, and my entity, and I want to delete my entity, so I call DAO.delete(entity); Then, seemingly out of nowhere, I get an InvocationTargetException. The parameters here are: method: public org.springframework.web.servlet.ModelAndView tld.myproject.view.web.controller.MyController.replaceEntity(org.springframework.web.multipart.MultipartFile,javax.servlet.http.HttpServletRequest) target: tld.myproject.view.web.controller.MyController@185918e args: [org.springframework.web.multipart.commons.CommonsMultipartFile@14812a6, org.springframework.web.multipart.support.DefaultMultipartHttpServletRequest@c08a64] ex: java.lang.reflect.InvocationTargetException private Object doInvokeMethod(Method method, Object target, Object[] args) throws Exception { ReflectionUtils.makeAccessible(method); try { return method.invoke(target, args); } catch (InvocationTargetException ex) { ReflectionUtils.rethrowException(ex.getTargetException()); } throw new IllegalStateException("Should never get here"); } Does anyone have a suggestion to what's going on? Anything I can use in my debugging? Cheers Nik

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  • Hibernate cascade delete on a bag

    - by littlecharva
    Howdy, Having built most of my DAL using NHibernate, I've now discovered that the SQL Server's Cascade On Delete rules also need to be taken into account in my HBM files too. I've been using bags for all my collections, but there doesn't seem to be a way to add a cascade="delete" attribute to a bag. I can change all my bags to sets, but that appears to mean I have changing all my IList<s on my models to PersistentGenericSet<s, which I don't really fancy doing. Any advice? Anthony

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  • Managing Strategy objects with Hibernate & Spring

    - by Francois
    This is a design question better explained with a Stack Overflow analogy: Users can earn Badges. Users, Badges and Earned Badges are stored in the database. A Badge’s logic is run by a Badge Condition Strategy. I would prefer not to have to store Badge Condition Strategies in the database, because they are complex tree structure objects. How do I associate a Badge stored in the database with its Badge Condition Strategy? I can only think of workaround solutions. For example: create 1 class per badge and use a SINGLE_TABLE inheritance strategy. Or get the badge from the database, and then programmatically lookup and inject the correct Badge Condition Strategy. Thanks for suggesting a better design.

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  • Hibernate: same generated value in two properties

    - by Markos Fragkakis
    Hi, I have an entity A with fields: aId (the system id) bId I want the first to be generated: @Id @Column(name = "PRODUCT_ID", unique = true, nullable = false, precision = 12, scale = 0) @GeneratedValue(strategy = GenerationType.SEQUENCE, generator = "PROD_GEN") @BusinessKey public Long getAId() { return this.aId; } I want the bId to be initially exactly as the aId. One approach is to insert the entity, then get the aId generated by the DB (2nd query) and then update the entity, setting the bId to be equal to aId (3rd query). Is there a way to get the bId to get the same generated value as aId? Note that afterwards, I want to be able to update bId from my gui. If the solution is JPA, even better.

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  • Criteria hibernate

    - by apb
    my code session.createCriteria(Input.class); DateFormat format = new SimpleDateFormat("yyyy-MM-dd hh:mm:ss"); Date startDate = (Date)format.parse("2005-01-01 00:00:00"); Date endDate = (Date)format.parse("2005-03-03 00:00:00"); crit.add(Expression.between ("inputDate", new Date(startDate.getTime()), new Date(endDate.getTime()))); This code return a list, but there is no element present in it. i think it doesn't match the condition. Anybody help.

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  • Hibernate SessionFactory: how to configure JNDI in Tomcat?

    - by EugeneP
    that's how the session factory should be gotten: protected SessionFactory getSessionFactory() { try { return (SessionFactory) new InitialContext() .lookup("SessionFactory"); } catch (Exception e) { } } Please provide a simple solution for Tomcat6 to be able to get SessionFactory thru simple jndi lookup in Java code. What should be written in what file on the side of Tomcat ?

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  • hibernate createSQL how to cache it?

    - by cometta
    If i use Criteria statement, i able to use cache easily. but when i using custom CREATESQL, like below, how do i cache it? Query query = getHibernateTemplate().getSessionFactory().getCurrentSession().createSQLQuery( " select company_keysupplier.ddiv as ddiv, company_division.name as DIVISION, company_keysupplier.ddep as ddep,company_department.name as DEPARTMENT"+ " from company_keysupplier "+ " left join company_division on "+ " (company_keysupplier.ddiv= company_division.division_code and company_keysupplier.survey_num=company_division.survey_num) "+ " left join company_department on "+ " (company_keysupplier.ddep= company_department.department_code and company_keysupplier.survey_num=company_department.survey_num) "+ " where company_keysupplier.sdiv = :sdiv and company_keysupplier.sdep = :sdep and company_keysupplier.survey_num= :surveyNum " + " order by company_division.name, company_keysupplier.ddep " ) .addScalar("ddiv") .addScalar("ddep") .addScalar("DIVISION") .addScalar("DEPARTMENT") .setResultTransformer(Transformers.aliasToBean(IssKeysupplier.class)); query.setString("sdiv", sdiv); query.setString("sdep", sdepartment); query.setBigInteger("surveyNum", survey_num); //i tried query.setCachable(true) fail...... List result= (List<IssKeysupplier>)query.list(); return result;

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  • Hibernate Discriminator sort

    - by mrvreddy
    I am trying to sort the records when queried on discriminator column. I am doing a HQL/ Criteria query for retrieving all the records. Here is my class: abstract class A { ... } @DiscriminatorValue("B") class B extends A { } @DiscriminatorValue("C") class C extends A { } When I return the records, I want it sorted on the discriminator value.

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