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• Mapping a property to a field from another table in NHibernate

  - by Khalil Dahab

  consider the following class: class Order { int OrderId {get; set;} int CustomerId {get; set;} string CustomerName {get; set;} //other fields go here } which is mapped to Orders table. Is it possible to map the property CustomerName to the Customers table through the foreign key relation?

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• Calculated property with JPA / Hibernate

  - by Francois

  My Java bean has a childCount property. This property is not mapped to a database column. Instead, it should be calculated by the database with a COUNT() function operating on the join of my Java bean and its children. It would be even better if this property could be calculated on demand / "lazily", but this is not mandatory. In the worst case scenario, I can set this bean's property with HQL or the Criteria API, but I would prefer not to. The Hibernate @Formula annotation may help, but I could barely find any documentation. Any help greatly appreciated. Thanks.

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• Hibernate -using Table per subclass - how to link an existing superclass object to a sibclass object

  - by Chandni

  Hi, I have a User hibernate class, Clerk class and Consumer class. All these maps to their own tables in database. The User PK also acts as Clerk's and Consumer's PK. So now my problem is that if a user is initially a Clerk, he has a record in Users table and Clerks table. If that user wants to become a consumer, I want to link that User's record to the new Consumer's record. So even if I pass the userId to the consumer's record, it treats it as a new User to be persisted and gives a duplicate_key exception. How do I tell Hiernate to link the same user object with this new Consumer object. Thanks in advance, -Chandni

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• question on database query using hibernate in java with annotations

  - by molleman

  Hello, simple question regarding HQL(Hibernate query language) so i have user class , that can hold a list of Projects, how do i take this out of the database depending on a username, this is how i take out my user String username = "stephen"; YFUser user = (YFUser) session.createQuery("select u FROM YFUser u where u.username = :username").setParameter("username", name).uniqueResult(); but i want to take out the list of projects here is the projects list within the class YFUser(my user class); how would i query the database to get this list of projects @Entity @Table(name = "yf_user_table") public class YFUser implements Serializable,ILightEntity { ......... @OneToMany(cascade = CascadeType.ALL,fetch = FetchType.LAZY) @JoinTable(name = "YFUSER_JOIN_PROJECT", joinColumns = { @JoinColumn(name = "user_id") }, inverseJoinColumns = { @JoinColumn(name = "project_id") }) private List<Project> projects = new ArrayList<Project>();

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• Synchronization between hibernate running locally and on a server

  - by linead

  Is there an easy way using a library to facilitate the synchronization of two hibernate instances. One running locally on a client and one running on a central server exposed via a web service. So Client tracks changes it makes, pushes them to the Server. The server ensures that the clients is not updating out of sync objects and stores the clients changes. The Client can also sync with the Server so that it can see the changes made by other clients. The idea is that the client can be run offline, without access to the server and only come online to synchronize when needed.

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• hibernate formula with column

  - by coolguy

  I have a table with a column that will be encrypted by a trigger after the record is inserted. When I read the column, I need to apply a decrypt function in the hibernate domain class. While saving the object, the value of the column will be saved as such. While reading the column, apply a database function on the read data. @Formula and @Column annotation cannot be applied to an attribute in the entity class. How do I achieve this functionality without using one attribute for saving and another one with @Formula for reading it?

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• Mixing table per subclass and per hierarchy in hibernate

  - by Xelluloid

  In my database there are two three tables. The first one, table ABSTRACT, holds three columns id, type, someText This table contains all abstract information for the abstract class abstract. Now the two tables CONCRETEONE and CONCRETETWO contain all information for the concrete classes concreteOne and concreteTwo. Now I know I could use the table per subclass strategy from hibernate to create a mapping with inheritance. But as I have a column that marks the type of the concrete implementation could it be possible to create some mixed behaviour like a table per subclass strategy with an discriminator?

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• Jpa subclass mapping

  - by Roy Chan

  I am making a POS like system. I wonder how to map subclass using JPA (this is for my DAO). Product class has product details and OrderProduct class has information about the Product and details about the order. @Entity @Table(name="products") public class Product implements Serializable{ @Id @Column(name="id") @GeneratedValue(strategy = GenerationType.AUTO public int getId(){ return id;} /** Other get/set methods */ } @Entity @Table(name="order_products") public class OrderProduct extends Product{ @Id @Column(name="id") @GeneratedValue(strategy = GenerationType.AUTO) public int getId(){ return id;} /** Other get/set methods */ } I got complain about duplicate @Id. But OrderProduct class really need another id than the product one. How should I map this? DB is something like this Table products id int name varchar(32) Table order_product id int quantity int productid int fk referencing product table Would @IdClass or @AttributeOverride help?

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• Hibernate/JPA and PostgreSQL - Primary Key?

  - by Shadowman

  I'm trying to implement some basic entities using Hibernate/JPA. Initially the code was deployed on MySQL and was working fine. Now, I'm porting it over to use PostgreSQL. In MySQL, my entity class defines its primary key as an auto-incrementing long value with the following syntax: @Id @GeneratedValue(strategy = GenerationType.AUTO) private Long id; However, I've found that I get errors with PostgreSQL when I try and insert numerous records at a time. What do I need to annotate my primary key with to get the same auto-incrementing behavior in PostgreSQL as I have with MySQL? Thanks for any help you can provide!

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• Hierarchical Hibernate, how many queries are executed?

  - by ghost1

  So I've been dealing with a home brew DB framework that has some seriously flaws, the justification for use being that not using an ORM will save on the number of queries executed. If I'm selecting all possibile records from the top level of a joinable object hierarchy, how many separate calls to the DB will be made when using an ORM (such as Hibernate)? I feel like calling bullshit on this, as joinable entities should be brought down in one query , right? Am I missing something here? note: lazy initialization doesn't matter in this scenario as all records will be used.

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• Transactions in hibernate

  - by kumar1425

  Hi I new to hibernate In my project, i need to handle transactions. How to handle declarative transactions with in two classes Examples: //class 1 class A{ createA() { insert(A); } } //class 2 class B { createB() { insert(B); } } //class 3 @Transaction(Exception.class) class C { test() { create(A); create(B); } } As per the above code is there any possibility to handle transactions, in such a way that if the insert in classA success and the insert in the classB fails then the transaction should rollback and remove the record inserted in the table A corresponding to the Class A please help me with this using declarative transactions.... Thanks in adavace....

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• Hibernate/JPA - annotating bean methods vs fields

  - by Benju

  I have a simple question about usage of Hibernate. I keep seeing people using JPA annotations in one of two ways by annotating the fields of a class and also by annotating the get method on the corresponding beans. My question is as follows: Is there a difference between annotating fields and bean methods with JPA annoations such as @Id. example: @Entity public class User { **@ID** private int id; public int getId(){ return this.id; } public void setId(int id){ this.id=id; } } -----------OR----------- @Entity public class User { private int id; **@ID** public int getId(){ return this.id; } public void setId(int id){ this.id=id; } }

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• hibernate versioning parent entity

  - by Priit

  Consider two entities Parent and Child. Child is part of Parent's transient collection Child has a ManyToOne mapping to parent with FetchType.LAZY Both are displayed on the same form to a user. When user saves the data we first update Parent instance and then Child collection (both using merge). Now comes the tricky part. When user modifies only Child property on the form then hibernate dirty checking does not update Parent instance and thus does not increase optimistic locking version number for that entity. I would like to see situation where only Parent is versioned and every time I call merge for Parent then version is always updated even if actual update is not executed in db.

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• Java Hibernate id auto increment

  - by vinise

  Hy I'v a little problem with hibernate on netbeans. I've a table with an Auto increment id : CREATE TABLE "DVD" ( "DVD_ID" INT not null primary key GENERATED ALWAYS AS IDENTITY (START WITH 1, INCREMENT BY 1), "TITLE" VARCHAR(150), "COM" LONG VARCHAR, "COVER" VARCHAR(150) ); But this auto increment is not properly detected with Reverse Engineering. I get a map file with this : <id name="dvdId" type="int"> <column name="DVD_ID" /> <generator class="assigned" /> </id> i've looked on google and on this site ... foud some stuf but i'm still stuck.. i've tried to add insert="false" update="false" on the map file but i get back : Caused by: org.xml.sax.SAXParseException: Attribute "insert" must be declared for element type "id". Anny help will be pleased Vincent

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• [Hibernate] Problem with saveOrUpdate()

  - by kunkanwan

  Hi, I've problem with Hibernate. I have a class User class User { int id; String name; } where id is native generator in User.hbm.xml , and name is primary-key in DB. In my database , I saved some information about Users. Than, I want to connect with this information about User. For example in my DB i have row INSERT INTO User VALUES ('Bill'); Main.java User bill = new User(); bill.setName("Bill"); session.saveOrUpdate(bill); This code always trying insert bill to database , rather than update when row about Bill exists in DB... Could you help me ? Thank you for advance.

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• avoid duplication with auto increment key in Hibernate

  - by Lily

  I am trying to use Hibernate to auto increment the id, however, I try to avoid duplication. class Service { Long id; // auto increment String name; String owner; // setter and getter } What I want to achieve is, whenever name and owner are the same, it will be a duplicated entry. In this case, I don't want to add another entry into the Database anymore. How to revise the hbm.xml files to avoid this issue?

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• Hibernate deletion issue

  - by muffytyrone

  I'm trying to write a Java app that imports a data file. The process is as follows Create Transaction Delete all rows from datatable Load data file into datatable Commit OR Rollback if any errors were encountered. The data loaded in step 3 is mostly the same as the data deleted in step3. The deletion is performed using the following DetachedCriteria criteria = DetachedCriteria.forClass(myObject.class); List<myObject> myObjects = hibernateTemplate.findByCriteria(criteria); hibernateTemplate.deleteAll(myObjects); When I then load the datafile, i get the following exception nested exception is org.hibernate.NonUniqueObjectException: a different object with the same identifier value was already associated with the session: The whole process needs to take place in transaction. And I don't really want to have to compare the import file / data table and then perform an insert/update/delete to get them into sync. Any help would be appreciated.

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• Constant in Hibernate Mapping Files

  - by bertolami

  I would like to add a value object to a mapped class where one column is fixed depending of the class that contains the component. How can I do something like this? <component name="aComponent"> <property name="abc" column="cde"/> <property name="xyz" value="FIXED"/> </component> Unfortunatly, the value attribute does not exist. Is there another way to apply a constant value to property? Thanks in advance.

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• Hibernate pluralization

  - by matiasf

  I have A MySQL database currently in production use for a CakePHP application A Java SE application accessing the same database via Hibernate, currently in development. I'm using the Netbeans "automigrate" feature to create the POJO classes and XML files (do I really need the XML files when using annotations?). As the schema is quite complex creating the tables manually is way too much work. Cake expects all DB tables to be pluralized (the Address class is automagically mapped to the addresses table). When running the Netbeans automigration it then does pluralization on the already pluralized table names (I'm getting Addresses.java and setAddresseses() methods). I know I'm asking for trouble running two very different data layers against the same database, but I'd like to know if it's possible to have Netbeans generating the POJO classes in singular form or if there is another (better) way to manage this.

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• unable to catch org.hibernate.StaleObjectStateException while deleting record that doesn't exists in database

  - by JAB

  My application has a delete user option. Now in order to check concurrency condition I tried the following use case opened application in chrome and firefox browser. deleted user in firefox now trying to delete the same user in chrome browser I get exception org.hibernate.StaleObjectStateException .. which is right .. since I am trying to delete an object which doesn't exists. But I am not able to catch this exception try{ getHibernateTemplate().delete(userObj); } catch (StaleObjectStateException e) { e.printStackTrace(); } How do i catch this exception ??

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• Size of assosiation in Hibernate criteria.

  - by trnl

  Hello guys. I've faced with a problem when querying with Hibernate Criteria in Grails. Take a look: def visitors = Client.withCriteria{ visits{ use ( TimeCategory ) {between('date',date,date+1.month-1)} } sizeGe("visits",params.from) sizeLe("visits",params.to) fetchMode("visits", FM.JOIN) }; I need only those clients, which has number of visits in month between from and to bounds. But now size* restrictions is being applied to all visits. So if client has one visit in this month, and visit in previous month. And if I set from=2, this client will be in result. But it should not be there. Any help is appreciated. Thanks, Vova.

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• When to use Hibernate?

  - by Ramo

  Hi All, I was asked in an interview this question so I answered with the following: -Better Performance: - Efficient queries. - 1st and 2nd level caching. - Good caching gives better scalability. - Good Database Portability: - Changing the DB is as easy as changing the dialect configuration. - Increased Developer Productivity: - Think only in object terms not in query language terms. But I also feel that systems fall in one of the below categories, and Hibernate may not be suited for all these cases, I'm interested in your thoughts about this, do you agree with me? please let me know when would use HB in the following case and why. Write Only Systems: Read Only Systems: Write Mostly Systems: Read Mostly Systems: Regards Ramo

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• Hibernate Auto-Increment not working

  - by dharga

  I have a column in my DB that is set with Identity(1,1) and I can't get hibernate annotations to work for it. I get errors when I try to create a new record. In my entity I have the following. @GeneratedValue(strategy=GenerationType.IDENTITY, generator="native") @Column(name="SeqNo", unique=true, nullable=false) BigDecimal seqNo; But when I try to add a new record I get the following error. Cannot insert explicit value for identity column in table 'MemberSelectedOptions' when IDENTITY_INSERT is set to OFF. I don't want to set IDENTIY_INSERT to ON because I want the identity column in the db to manage the values. The SQL that is run is the following; where you can clearly see the insert. insert into dbo.MemberSelectedOptions (OptionStatusCd, EffectiveDate, TermDate, SelectionStatusDate, SysLstUpdtUserId, SysLstTrxDtm, SourceApplication, GroupId, MemberId, OptionId, SeqNo) values (?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?) What am I missing?

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• Simplest one-to-many Map case in Hibernate doesn't work in MySQL

  - by Malvolio

  I think this is pretty much the simplest case for mapping a Map (that is, an associative array) of entities. @Entity @AccessType("field") class Member { @Id protected long id; @OneToMany(cascade = CascadeType.ALL, fetch=FetchType.LAZY) @MapKey(name = "name") private Map<String, Preferences> preferences = new HashMap<String, Preferences>(); } @Entity @AccessType("field") class Preferences { @ManyToOne Member member; @Column String name; @Column String value; } This looks like it should work, and it does, in HSQL. In MySQL, there are two problems: First, it insists that there be a table called Members_Preferences, as if this were a many-to-many relationship. Second, it just doesn't work: since it never populates Members_Preferences, it never retrieves the Preferences. [My theory is, since I only use HSQL in memory-mode, it automatically creates Members_Preferences and never really has to retrieve the preferences map. In any case, either Hibernate has a huge bug in it or I'm doing something wrong.]

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• Hibernate is performing unwanted SELECTs on call to saveOrUpdate

  - by digiarnie

  Let's say I have a House entity which maps to many Person entities. I then load an existing House which has 20 occupants. beginTransaction(); House house = houseDao.find(1L); commitTransaction(); Later in the code, I can then add a new Person to the House: ... List<Person> people = house.getPeople(); people.add(new Person("Dilbert")); .... When I make the call: session.saveOrUpdate(house); Hibernate performs 21 queries: 1 to SELECT the House and 20 to SELECT each existing Person in the House. I'm sure it's a small issue on my part, however, what should I do so that I can add a new Person to the house without having such a heavy hit on the database in this situation? This is all done within the same session.

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