Search Results

Search found 1071 results on 43 pages for 'jpeg'.

Page 34/43 | < Previous Page | 30 31 32 33 34 35 36 37 38 39 40 41  | Next Page >

  • Inserting an image into sqlserver gives an "operand type clash"

    - by Termedi
    I'm trying to save an image in a sql server 2000 database. The data type of the column is image. Here is the code: Image Upload: <?php include('config.php'); if(is_uploaded_file($_FILES['userfile']['tmp_name'])) { $fileName = $_FILES['userfile']['name']; $tmpName = $_FILES['userfile']['tmp_name']; $fileSize = $_FILES['userfile']['size']; $fileType = $_FILES['userfile']['type']; $size = filesize($tmpName); set_magic_quotes_runtime(0);//to desactive the default escape spacials caracters made by PHP in the externes files $img_binaire = base64_encode(fread(fopen(str_replace("'","''",$tmpName), "r"), $size)); $query = "INSERT INTO test_image (image_name, image_content, image_size) ". "VALUES ('{$fileName}','{$img_binaire}', '{$size}')"; odbc_exec($conn, $query) or die('Error, query failed'); echo "<br>File $fileName uploaded<br>"; echo "<br>File Size: $fileSize <br>"; } ?> Image Show: <?php include('config.php'); $sql = "select * from test_image where id =2"; $rsl = odbc_exec($conn, $sql); $image_info = odbc_fetch_array($rsl); //$count = sizeof($image_info['image_content']); //header('Accept-Ranges: bytes'); //header('Content-Length: '.$image_info['image_size']); //header("Content-length: 17397"); header('Content-Type: image/jpeg'); echo base64_decode($image_info['image_content']); //echo bindec($image_info['image_content']); ?> It gives the following error: Error: Warning: odbc_exec() [function.odbc-exec]: SQL error: [Microsoft][ODBC SQL Server Driver][SQL Server]Operand type clash: text is incompatible with image, SQL state 22005 in SQLExecDirect in C:\xampp\htdocs\test\upload.php on line 25 Error, query failed What do I need to do differently?

    Read the article

  • C# .NET : Is using the .NET Image Conversion enough?

    - by contactmatt
    I've seen a lot of people try to code their own image conversion techniques. It often seems to be very complicated, and ends up using GDI+ funciton calls, and manipulating bits of the image. This has got me wondering if I am missing something in the simplicity of .NET's image conversion call when saving an image. Here's the code I have Bitmap tempBmp = new Bitmap("c:\temp\img.jpg"); Bitmap bmp = new Bitmap(tempBmp, 800, 600); bmp.Save(c:\temp\img.bmp, //extension depends on format ImageFormat.Bmp) //These are all the ImageFormats I allow conversion to within the program. Ignore the syntax for a second ;) ImageFormat.Gif) //or ImageFormat.Jpeg) //or ImageFormat.Png) //or ImageFormat.Tiff) //or ImageFormat.Wmf) //or ImageFormat.Bmp)//or ); This is all I'm doing in my image conversion. Just setting the location of where the image should be saved, and passing it an ImageFormat type. I've tested it the best I can, but I'm wondering if I am missing anything in this simple format conversion, or if this is suffice?

    Read the article

  • MATLAB only prints a part of my figure

    - by simonty
    I'm trying to print my figure in Matlab, but it keeps screwing up and I have no idea why. opslaan = figure(1); plot(1:handles.aantal,handles.nauw,'-r','LineWidth',1.5); xlabel(gca,sprintf('Framenummer (%g ms per frame)',60/handles.aantal)); ylabel(gca,'dB'); set(gca,'YGrid','on'); yAsMax = ceil( ceil(max(handles.nauw)) / 2) * 2; axis([0 handles.aantal 0 yAsMax]); pause(1); print -dpng image.png The first line is just plotting the data on my figure, then labeling x and y, turning on grid and caculating the y-axis like I want it. This all works great and Matlab shows it like I want it in the Figure window. When saving to .png / .jpeg / .eps it goes wrong and only prints the bottom left corner (473x355 pixels), the rest just disappeared. When exporting manually via File - Save As, it works correctly. Any help? Thanks!

    Read the article

  • jQuery working in everything but IE7. (checked my commas)

    - by deadlyhifi
    The following code works in IE8, FF, Safari, Chrome etc. (not bothering with IE6 for this one), but doesn't work in IE7. I've been through the code with a fine tooth-comb. Checked the commas, messed around with ; but it's not going anywhere. I'm using the jQuery Validate and Uploadify scripts. Can anyone see the problem here? Thanks. <script type="text/javascript"> jQuery(document).ready(function($) { $("#validateform").validate({ errorClass: 'invalid', rules: { bike_url: { required: true, url: true } } }) $("#uploadify").uploadify({ 'uploader' : '<?php echo $url . '/wp-content/plugins/biketest/includes/uploadify/uploadify.swf'; ?>', 'script' : '<?php echo $url . '/wp-content/plugins/biketest/class/class.uploadify.php'; ?>', 'folder' : '<?php echo $url . '/wp-content/plugins/biketest/uploads'; ?>', 'cancelImg' : '<?php echo $url . '/wp-content/plugins/biketest/includes/uploadify/cancel.png'; ?>', 'auto' : true, 'fileDesc' : '.jpg or .png files only please.', 'fileExt' : '*.jpg;*.jpeg;*.png;', 'sizeLimit' : '2097152', 'buttonText': 'Choose Image', 'scriptData': { 'random': '<?php $rand = rand(0, 999999); echo $rand ?>' }, 'onComplete': function(event, queueID, fileObj, response, data) { var image = '<?php echo $rand; ?>-' + ((fileObj.name).toLowerCase()).replace(' ', ''); setTimeout(function(){ $(".uploaded").attr('src', '<?php echo $url; ?>/wp-content/plugins/biketest/uploads/s-' + image); }, 500); $("[name=bike_img]").val(image); } }) }); </script>

    Read the article

  • Trying to attach a file from SD Card to email

    - by Chrispix
    I am trying to launch an Intent to send an email. All of that works, but when I try to actually send the email a couple 'weird' things happen. here is code Intent sendIntent = new Intent(Intent.ACTION_SEND); sendIntent.setType("image/jpeg"); sendIntent.putExtra(Intent.EXTRA_SUBJECT, "Photo"); sendIntent.putExtra(Intent.EXTRA_STREAM, Uri.parse("file://sdcard/dcim/Camera/filename.jpg")); sendIntent.putExtra(Intent.EXTRA_TEXT, "Enjoy the photo"); startActivity(Intent.createChooser(sendIntent, "Email:")); So if I launch using the Gmail menu context It shows the attachment, lets me type who the email is to, and edit the body & subject. No big deal. I hit send, and it sends. The only thing is the attachment does NOT get sent. So. I figured, why not try it w/ the Email menu context (for my backup email account on my phone). It shows the attachment, but no text at all in the body or subject. When I send it, the attachment sends correctly. That would lead me to believe something is quite wrong. Do I need a new permission in the Manifest launch an intent to send email w/ attachment? What am I doing wrong?

    Read the article

  • Self-describing file format for gigapixel images?

    - by Adam Goode
    In medical imaging, there appears to be two ways of storing huge gigapixel images: Use lots of JPEG images (either packed into files or individually) and cook up some bizarre index format to describe what goes where. Tack on some metadata in some other format. Use TIFF's tile and multi-image support to cleanly store the images as a single file, and provide downsampled versions for zooming speed. Then abuse various TIFF tags to store metadata in non-standard ways. Also, store tiles with overlapping boundaries that must be individually translated later. In both cases, the reader must understand the format well enough to understand how to draw things and read the metadata. Is there a better way to store these images? Is TIFF (or BigTIFF) still the right format for this? Does XMP solve the problem of metadata? The main issues are: Storing images in a way that allows for rapid random access (tiling) Storing downsampled images for rapid zooming (pyramid) Handling cases where tiles are overlapping or sparse (scanners often work by moving a camera over a slide in 2D and capturing only where there is something to image) Storing important metadata, including associated images like a slide's label and thumbnail Support for lossy storage What kind of (hopefully non-proprietary) formats do people use to store large aerial photographs or maps? These images have similar properties.

    Read the article

  • Images from SQL Server JPG/PNG Image Column not being Type Converted to Bitmap in HttpHandlers (cons

    - by kanchirk
    Our Silverlight 3.0 Client consumes Images stored/retrieved on the File System thorough ASP.NET HttpHandlers successfully. We are trying to store and read back Images using a SQL Server 2008 Database. Please find the stripped down code pasted below with the Exception. "Bitmap is not Valid" //Store document to the database private void SaveImageToDatabaseKK(HttpContext context, string pImageFileName) { try { //ADO.NET Entity Framework ImageTable documentDB = new ImageTable(); int intLength = Convert.ToInt32(context.Request.InputStream.Length); //Move the file contents into the Byte array Byte[] arrContent = new Byte[intLength]; context.Request.InputStream.Read(arrContent, 0, intLength); //Insert record into the Document table documentDB.InsertDocument(pImageFileName, arrContent, intLength); } catch { } } =The method to Read Back the Row from the Table and Send it back is below.= private void RetrieveImageFromDatabaseTableKK(HttpContext context, string pImageName) { try { ImageTable documentDB = new ImageTable(); var docRow = documentDB.GetDocument(pImageName); //based on Imagename which is unique //DocData column in table is **Image** if (docRow!=null && docRow.DocData != null && docRow.DocData.Length > 0) { Byte[] bytImage = docRow.DocData; if (bytImage != null && bytImage.Length > 0) { Bitmap newBmp = ConvertToBitmap(context, bytImage ); if (newBmp != null) { newBmp.Save(context.Response.OutputStream, ImageFormat.Jpeg); newBmp.Dispose(); } } } } catch (Exception exRI) { } } // Convert byte array to Bitmap (byte[] to Bitmap) protected Bitmap ConvertToBitmap(byte[] bmp) { if (bmp != null) { try { TypeConverter tc = TypeDescriptor.GetConverter(typeof(Bitmap)); Bitmap b = (Bitmap)tc.ConvertFrom(bmp); **//This is where the Exception Occurs.** return b; } catch (Exception) { } } return null; }

    Read the article

  • spring 3 uploadify giving 404 Error

    - by Rajkumar
    I am using Spring 3 and implementing Uploadify. The problem is, the files are updating properly but it is giving HTTP Error 404, on completion of file upload. I tried every possible solution, but none of them works. The files are uploaded. Values are storing in DB properly, only that i am getting HTTP Error 404. Any help is appreciated and Thanks in advance. The JSP Page $(function() { $('#file_upload').uploadify({ 'swf' : 'scripts/uploadify.swf', 'fileObjName' : 'the_file', 'fileTypeExts' : '*.gif; *.jpg; *.jpeg; *.png', 'multi' : true, 'uploader' : '/photo/savePhoto', 'fileSizeLimit' : '10MB', 'uploadLimit' : 50, 'onUploadStart' : function(file) { $('#file_upload').uploadify('settings', 'formData', {'trip_id' :'1', 'trip_name' :'Sample Trip', 'destination_trip' :'Mumbai','user_id' :'1','email' :'[email protected]','city_id' :'12'}); }, 'onQueueComplete' : function(queueData) { console.log('queueData : '+queueData); window.location.href = "trip/details/1"; } }); }); The Controller @RequestMapping(value="photo/{action}", method=RequestMethod.POST) public String postHandler(@PathVariable("action") String action, HttpServletRequest request) { if(action.equals("savePhoto")) { try{ MultipartHttpServletRequest multipartRequest = (MultipartHttpServletRequest)request; MultipartFile file = multipartRequest.getFile("the_file"); String trip_id = request.getParameter("trip_id"); String trip_name = request.getParameter("trip_name"); String destination_trip = request.getParameter("destination_trip"); String user_id = request.getParameter("user_id"); String email = request.getParameter("email"); String city_id = request.getParameter("city_id"); photo.savePhoto(file,trip_id,trip_name,destination_trip,user_id,email,city_id); photo.updatetrip(photo_id,trip_id); }catch(Exception e ){e.printStackTrace();} } return ""; } spring config <bean class="org.springframework.web.multipart.commons.CommonsMultipartResolver" id="multipartResolver"> <property name="maxUploadSize" value="10000000"/> </bean>

    Read the article

  • How to Use Calculated Color Values with ColorMatrix?

    - by Otaku
    I am changing color values of each pixel in an image based on a calculation. The problem is that this takes over 5 seconds on my machine with a 1000x1333 image and I'm looking for a way to optimize it to be much faster. I think ColorMatrix may be an option, but I'm having a difficult time figure out how I would get a set of pixel RGB values, use that to calculate and then set the new pixel value. I can see how this can be done if I was just modifying (multiplying, subtracting, etc.) the original value with ColorMatrix, but now how I can use the pixels returned value to use it to calculate and new value. For example: Sub DarkenPicture() Dim clrTestFolderPath = "C:\Users\Me\Desktop\ColorTest\" Dim originalPicture = "original.jpg" Dim Luminance As Single Dim bitmapOriginal As Bitmap = Image.FromFile(clrTestFolderPath + originalPicture) Dim Clr As Color Dim newR As Byte Dim newG As Byte Dim newB As Byte For x = 0 To bitmapOriginal.Width - 1 For y = 0 To bitmapOriginal.Height - 1 Clr = bitmapOriginal.GetPixel(x, y) Luminance = ((0.21 * (Clr.R) + (0.72 * (Clr.G)) + (0.07 * (Clr.B))/ 255 newR = Clr.R * Luminance newG = Clr.G * Luminance newB = Clr.B * Luminance bitmapOriginal.SetPixel(x, y, Color.FromArgb(newR, newG, newB)) Next Next bitmapOriginal.Save(clrTestFolderPath + "colorized.jpg", ImageFormat.Jpeg) End Sub The Luminance value is the calculated one. I know I can set ColorMatrix's M00, M11, M22 to 0, 0, 0 respectively and then put a new value in M40, M41, M42, but that new value is calculated based of a value multiplication and addition of that pixel's components (((0.21 * (Clr.R) + (0.72 * (Clr.G)) + (0.07 * (Clr.B)) and the result of that - Luminance - is multiplied by the color component). Is this even possible with ColorMatrix?

    Read the article

  • Nginx for static files, Apache isn't working now...

    - by matthewsteiner
    So anything that is a "static file" that exists will just be done with nginx. Otherwise, it should pass it off to Apache. Right now, static files are working correctly. However, if something is passed to apache and it's example.com or subdomain.example.com, apache just spits out the "Apache 2 Test Page" that you get if there's nothing there. Here's my nginx.conf: location ~* ^.+.(jpg|jpeg|gif|png|ico|css|zip|tgz|gz|rar|bz2|doc|xls|exe|pdf|ppt|txt|tar|mid|midi|wav|bmp|rtf|js)$ { root /var/www/vhosts/example.com/public/; access_log off; expires 30d; } location / { proxy_pass http://127.0.0.1:8080/; proxy_redirect off; proxy_set_header Host $host; proxy_set_header X-Real-IP $remote_addr; proxy_set_header X-Forwarded-For $proxy_add_x_forwarded_for; } Apache worked fine before, so I'm guessing it has to do with the way nginx is "asking". I'm not sure though. Any ideas?

    Read the article

  • modx friendly urls nginx FPM php5.3 - friendly url's not working

    - by okdan
    Hi, Im using php5.3 on nginx 0.8.53 with FPM on Modx revolution. Im trying to get "friendly url's" to work, but all I get is 404's. In modx config, friendly url's is set to yes, friendly aliases is set to no (so it drops the suffix) My config file: server { listen 80; server_name .mydomain.net; # index index.php; root /home/mylogin/htdocs; location / { index index.php index.html; if (!-e $request_filename) { rewrite ^/(.*)$ /index.php?q=$1 last; } } # serve static files directly location ~* ^.+\.(jpg|jpeg|gif|css|png|js|ico)$ { root /home/mylogin/htdocs; access_log off; expires 30d; break; } } Fast CGI modx file: fastcgi_connect_timeout 60; fastcgi_send_timeout 300; fastcgi_buffers 4 32k; fastcgi_busy_buffers_size 32k; fastcgi_temp_file_write_size 32k; fastcgi_pass 127.0.0.1:9000; fastcgi_index index.php; fastcgi_param SCRIPT_FILENAME $document_root$fastcgi_script_name; fastcgi_ignore_client_abort on; fastcgi_intercept_errors on; fastcgi_read_timeout 300; fastcgi_param QUERY_STRING $query_string; fastcgi_param REQUEST_METHOD $request_method; fastcgi_param CONTENT_TYPE $content_type; fastcgi_param CONTENT_LENGTH $content_length; fastcgi_param SCRIPT_NAME $fastcgi_script_name; fastcgi_param REQUEST_URI $request_uri; fastcgi_param DOCUMENT_URI $document_uri; fastcgi_param DOCUMENT_ROOT $document_root; fastcgi_param SERVER_PROTOCOL $server_protocol; fastcgi_param GATEWAY_INTERFACE CGI/1.1; fastcgi_param SERVER_SOFTWARE nginx/$nginx_version; fastcgi_param REMOTE_ADDR $remote_addr; fastcgi_param REMOTE_PORT $remote_port; fastcgi_param SERVER_ADDR $server_addr; fastcgi_param SERVER_PORT $server_port; fastcgi_param SERVER_NAME $server_name; fastcgi_param REDIRECT_STATUS 200;

    Read the article

  • How to set DocFlavor for printservice in Java for WIndows.

    - by om
    Hello, I have written code to run the printer programatically in Java.I have to set the value of docflavor to print the .txt file.When I set it for INPUT_STREAM.TEXT_PLAIN_UTF_8 and run my program on Linux , it prints the text file.but when i run the same code for windows.It can't print the text file.It only prints the jpeg format file.I am using HP Deskjet F735 printer for this. Following is my code . DocFlavor docflavor = DocFlavor.INPUT_STREAM.TEXT_PLAIN_UTF_8; PrintRequestAttributeSet attr_set = new HashPrintRequestAttributeSet(); attr_set.add(new Copies(2)); PrintService[] service = PrintServiceLookup.lookupPrintServices(docflavor, attr_set); if (service.length==0) { JOptionPane.showMessageDialog(null, "No Printer Selected"); } else if (service.length > 0) { System.out.println("Selected printer is " + service[0].getName()); DocPrintJob pj = service[0].createPrintJob(); { PrintService ps = pj.getPrintService(); FileInputStream fis = null; try { File file = new File("/home/ignu/Desktop/newfile"); fis = new FileInputStream(file); Doc doc = new SimpleDoc(fis, docflavor, null); pj.print(doc, attr_set);

    Read the article

  • Problems uploading pictures to Facebook wall.

    - by Miguel Ángel Ortuño
    Hi, i'm trying to upload a JPEG picture to Facebook wall using libcurl. Appareantly the connection is established but cURL hangs when waiting for server response. The libcurl output is the following: About to connect() to api.facebook.com port 80 (#0) Trying 66.220.146.15... * connected Connected to api.facebook.com (66.220.146.15) port 80 (#0) POST /restserver.php?api_key=e57addd5a98ac4445e36359043ded182&call_id=3&caption=ddfg&format=JSON&method=facebook.photos.upload&session_key=a3fc731e4c0329201606daeb-723233322&sig=a3f32226cff3e49ec799cf7dcc17a57e&ss=1&v=1.0?method=photos.upload HTTP/1.1 User-Agent: Mozilla/5.0 (Windows; U; Windows NT 5.1; en-US; rv:1.8.1.14) Gecko/20080404 Firefox/2.0.0.14 Host: api.facebook.com Accept: / Content-Type: multipart/form-data; charset=UTF-8; boundary=PPoSt_dElImTTer MIME-version: 1.0 Content-Length: 128033 Expect: 100-continue Done waiting for 100-continue And the C++ code is as follow: String post_header = "Content-Type: multipart/form-data; charset=UTF-8; boundary=PPoSt_dElImTTer\r\nMIME-version: 1.0\r\n"; // POST binary data curl_slist* chunk = NULL; chunk = curl_slist_append(chunk, post_header.c_str()); curl_easy_setopt(m_http, CURLOPT_HTTPHEADER, chunk); curl_easy_setopt(m_http, CURLOPT_POST, true); curl_easy_setopt(m_http, CURLOPT_POSTFIELDS, buf); curl_easy_setopt(m_http, CURLOPT_POSTFIELDSIZE, all_size); curl_easy_setopt(m_http, CURLOPT_URL, m_request.c_str()); curl_easy_setopt(m_http, CURLOPT_WRITEFUNCTION, Facebook::Request::httpCallback); curl_easy_setopt(m_http, CURLOPT_WRITEDATA, this); curl_easy_setopt(m_http, CURLOPT_USERAGENT, "Mozilla/5.0 (Windows; U; Windows NT 5.1; en-US; rv:1.8.1.14) Gecko/20080404 Firefox/2.0.0.14"); curl_easy_setopt(m_http, CURLOPT_VERBOSE, true);

    Read the article

  • Display new image on web page

    - by RuiT
    Hello, I'm uploading images to a folder and I want to display each new image on a web page every time it is saved in the folder. I can display the initial image, which is already in the folder, and I can also detect when a new image is saved into the folder but I don't know how to display the new images. I'm new to web development. Can somebody help me? Here's the code: public partial class _Default : System.Web.UI.Page { string DirectoryPath = "C:\\Users\\Desktop\\PhotoUpload\\Uploads\\"; protected void Page_Load(object sender, EventArgs e) { FileSystemWatcher watcher = new FileSystemWatcher(); try { watcher.Path = DirectoryPath; watcher.Created += new FileSystemEventHandler(watcher_Created); watcher.EnableRaisingEvents = true; Image image = Image.FromFile(DirectoryPath + "inicial.jpg"); MemoryStream ms = new MemoryStream(); image.Save(ms, System.Drawing.Imaging.ImageFormat.Jpeg); byte[] im = ms.ToArray(); Context.Response.ContentType = "Image/JPG"; Context.Response.BinaryWrite(im); } catch (Exception ex) { } } void watcher_Created(object sender, FileSystemEventArgs e) { Console.WriteLine("File Created: Name: " + e.Name); try { //How to display new image? } catch (Exception ex) { } } }

    Read the article

  • Image Grabbing with False Referer

    - by Mr Carl
    Hey guys, I'm struggling with grabbing an image at the moment... sounds silly, but check out this link :P http://manga.justcarl.co.uk/A/Oishii_Kankei/31/1 If you get the image URL, the image loads. Go back, it looks like it's working fine, but that's just the browser loading up the cached image. The application was working fine before, I'm thinking they implemented some kind of Referer check on their images. So I found some code and came up with the following... $ref = 'http://www.thesite.com/'; $file = 'theimage.jpg'; $hdrs = array( 'http' = array( 'method' = "GET", 'header'= "accept-language: en\r\n" . "Accept:application/xml,application/xhtml+xml,text/html;q=0.9,text/plain;q=0.8,image/png,*\/*;q=0.5\r\n" . "Referer: $ref\r\n" . // Setting the http-referer "Content-Type: image/jpeg\r\n" ) ); // get the requested page from the server // with our header as a request-header $context = stream_context_create($hdrs); $fp = fopen($imgChapterPath.$file, 'rb', false, $context); fpassthru($fp); fclose($fp); Essentially it's making up a false referrer. All I'm getting back though is a bunch of gibberish (thanks to fpassthru) so I think it's getting the image, but I'm afraid to say I have no idea how to output/display the collected image. Cheers, Carl

    Read the article

  • Screen capture doesn't work on MFC application in Vista

    - by David Thornley
    We've got some in-house applications built in MFC, with OpenGL drawing routines. They all use the same code to draw on the screen and either print the screen or save it to a JPEG file. Everything's been working fine in Windows XP, and I need to find a way to make them work on Vista. In three of our applications, everything works. In the remaining one, I can get the window border, title bar, menus, and task bar, but the interior never shows up. As I said, these applications use the exact same code to write to the screen and capture the window image, and the only difference I see that looks like it might be relevant is that the problem application uses the MFC multiple document interface, while the ones that work use the single document interface. Either the answer isn't on the net, or I'm worse at Googling than I thought. I asked on the MSDN forums, and the only practical suggestion I got was to use GDI+ rather than GDI, and that did nothing different. I have tried different things with every part of the code that captures and prints or save, given a pointer to the window, so apparently it's a matter of the window itself. I haven't rebuilt the offending application using SDI yet, and I really don't have any other ideas. Has anybody seen anything like this?

    Read the article

  • Access/Download server files, not in site root, with PHP

    - by user271619
    Usually I save documents (images, mpegs, excel, word docs, etc...) for my friends or family on my website's root, inside a directory called /files/ or something similar. Nothing too uncommon. But, I have been playing with user session control, and allowing users to upload files to the dedicated /files/ directory. (the file names are saved in a db, with that user's ID) But, that means other people could try to guess and locate other people's files. I do randomize the file names, upon upload. And I stop the apache from displaying the /files/ directory content. However, I'd like to start saving the files outside of the website's root. This way it can't be accessible via the browser. I don't have any code to show, but I didn't want to even start on this endeavor if it's not able to be accomplished. I did find this snippet that shows how to display an image, from outside your website root: $file = $_GET['file']; $fileDir = '/path/to/files/'; if (file_exists($fileDir . $file)) { // Note: You should probably do some more checks // on the filetype, size, etc. $contents = file_get_contents($fileDir . $file); // Note: You should probably implement some kind // of check on filetype header('Content-type: image/jpeg'); echo $contents; } ? Maybe I can use this for any file type, but has anyone heard of a better way to allow users (logged in) to access their files from online, but not letting other users has similar access?

    Read the article

  • Does Android AsyncTaskQueue or similar exist?

    - by Ben L.
    I read somewhere (and have observed) that starting threads is slow. I always assumed that AsyncTask created and reused a single thread because it required being started inside the UI thread. The following (anonymized) code is called from a ListAdapter's getView method to load images asynchronously. It works well until the user moves the list quickly, and then it becomes "janky". final File imageFile = new File(getCacheDir().getPath() + "/img/" + p.image); image.setVisibility(View.GONE); view.findViewById(R.id.imageLoading).setVisibility(View.VISIBLE); (new AsyncTask<Void, Void, Bitmap>() { @Override protected Bitmap doInBackground(Void... params) { try { Bitmap image; if (!imageFile.exists() || imageFile.length() == 0) { image = BitmapFactory.decodeStream(new URL( "http://example.com/images/" + p.image).openStream()); image.compress(Bitmap.CompressFormat.JPEG, 85, new FileOutputStream(imageFile)); image.recycle(); } image = BitmapFactory.decodeFile(imageFile.getPath(), bitmapOptions); return image; } catch (MalformedURLException ex) { // TODO Auto-generated catch block ex.printStackTrace(); return null; } catch (IOException ex) { // TODO Auto-generated catch block ex.printStackTrace(); return null; } } @Override protected void onPostExecute(Bitmap image) { if (view.getTag() != p) // The view was recycled. return; view.findViewById(R.id.imageLoading).setVisibility( View.GONE); view.findViewById(R.id.image) .setVisibility(View.VISIBLE); ((ImageView) view.findViewById(R.id.image)) .setImageBitmap(image); } }).execute(); I'm thinking that a queue-based method would work better, but I'm wondering if there is one or if I should attempt to create my own implementation.

    Read the article

  • Image insert problem php sqlserver

    - by Termedi
    Hi I can not save image inside a sql server 2000 database. datatype is image here is the code: // Image Upload <?php include('config.php'); if(is_uploaded_file($_FILES['userfile']['tmp_name'])) { $fileName = $_FILES['userfile']['name']; $tmpName = $_FILES['userfile']['tmp_name']; $fileSize = $_FILES['userfile']['size']; $fileType = $_FILES['userfile']['type']; $size = filesize($tmpName); set_magic_quotes_runtime(0);//to desactive the default escape spacials caracters made by PHP in the externes files $img_binaire = base64_encode(fread(fopen(str_replace("'","''",$tmpName), "r"), $size)); $query = "INSERT INTO test_image (image_name, image_content, image_size) ". "VALUES ('{$fileName}','{$img_binaire}', '{$size}')"; odbc_exec($conn, $query) or die('Error, query failed'); echo "<br>File $fileName uploaded<br>"; echo "<br>File Size: $fileSize <br>"; } ?> // Image Show <?php include('config.php'); $sql = "select * from test_image where id =2"; $rsl = odbc_exec($conn, $sql); $image_info = odbc_fetch_array($rsl); //$count = sizeof($image_info['image_content']); //header('Accept-Ranges: bytes'); //header('Content-Length: '.$image_info['image_size']); //header("Content-length: 17397"); header('Content-Type: image/jpeg'); echo base64_decode($image_info['image_content']); //echo bindec($image_info['image_content']); ?> Error: Warning: odbc_exec() [function.odbc-exec]: SQL error: [Microsoft][ODBC SQL Server Driver][SQL Server]Operand type clash: text is incompatible with image, SQL state 22005 in SQLExecDirect in C:\xampp\htdocs\test\upload.php on line 25 Error, query failed

    Read the article

  • Jquery: how to call the function again?

    - by bakazero
    I'm making the script for easy upload many files. I've tried fyneworks plugin, but the file name does not appear in a form that uses tiny_mce. This is the code: $("document").ready(function () { var i = 0; //iteration for Inputted File var max = 5; //max file uploaded createStatus(); //generate status container $('.imageNow').change(function() { if($(this).val()) { var ext = $(this).val().split('.').pop().toLowerCase(); var allow = [ 'gif', 'png', 'jpg', 'jpeg' ]; if (jQuery.inArray(ext, allow) != -1) { //validation true addImgInput($(this).clone()); $(this).addClass('imgOK'); $(this).removeClass('imageNow'); addImgList($(this).val()); removeImgStatus(); i++; } else { addImgStatus(); $(this).remove(); addImgInput(); } } return false; }); }); This is another function that I use: function addImgInput(inputClone) { $(inputClone).prependTo( $('#upload_images') ); //div container for generated InputFileImg }; function addImgList(listingImg) { $('#list_image_file').append('<li>' + listingImg + '</li>' ); //list all images that have been inputted } function createStatus() { $('#upload_images').append('<small class="status"></small>'); //error display container } function addImgStatus() { $('.status').append('* Wrong File Extension'); //error display text } function removeImgStatus() { $('.status').empty(); } Mmm..yeah is't not finished yet, because when I try to generate another Inputfile with imageNow class, the $('.imageNow').change(function() is not going to work anymore. Does anyone can help me? Thanks

    Read the article

  • How can I overlay images over one another in Java?

    - by Sam
    So I have been posting all over and have yet to get a solid answer: I have created an image resizing class, with a crop method. The cropping works great. The issue that I am having is the background color that I specify in the drawImage function of Graphics is not working correctly. It defaults to black as the background regardless of what I supply (in this case Color.WHITE). Also, the overlaying image or top most image (comes from a file) is being inverted (I think it is) or otherwise discolored. Just so you can conceptualize this a little bit better, I am taking a jpeg and overlaying it on top of a new BufferedImage, the new buffered image's background is not being set. Here is the code below that I am working with: public void Crop(int Height, int Width, int SourceX, int SourceY) throws Exception { //output height and width int OutputWidth = this.OutputImage.getWidth(); int OutputHeight = this.OutputImage.getHeight(); //create output streams ByteArrayOutputStream MyByteArrayOutputStream = new ByteArrayOutputStream(); MemoryCacheImageOutputStream MyMemoryCacheImageOutputStream = new MemoryCacheImageOutputStream(MyByteArrayOutputStream); //Create a new BufferedImage BufferedImage NewImage = new BufferedImage(Width, Height, BufferedImage.TYPE_INT_RGB); Graphics MyGraphics = NewImage.createGraphics(); MyGraphics.drawImage(this.OutputImage, -SourceX, -SourceY, OutputWidth, OutputHeight, Color.WHITE, null); // Get Writer and set compression Iterator MyIterator = ImageIO.getImageWritersByFormatName("png"); if (MyIterator.hasNext()) { //get image writer ImageWriter MyImageWriter = (ImageWriter)MyIterator.next(); //get params ImageWriteParam MyImageWriteParam = MyImageWriter.getDefaultWriteParam(); //set outputstream MyImageWriter.setOutput(MyMemoryCacheImageOutputStream); //create new ioimage IIOImage MyIIOImage = new IIOImage(NewImage, null, null); //write new image MyImageWriter.write(null, MyIIOImage, MyImageWriteParam); } //convert output stream back to inputstream ByteArrayInputStream MyByteArrayInputStream = new ByteArrayInputStream(MyByteArrayOutputStream.toByteArray()); MemoryCacheImageInputStream MyMemoryCacheImageInputStream = new MemoryCacheImageInputStream(MyByteArrayInputStream); //resassign as a buffered image this.OutputImage = ImageIO.read(MyMemoryCacheImageInputStream); }

    Read the article

  • Reading in bytes produced by PHP script in Java to create a bitmap

    - by Kareem
    I'm having trouble getting the compressed jpeg image (stored as a blob in my database). here is the snippet of code I use to output the image that I have in my database: if($row = mysql_fetch_array($sql)) { $size = $row['image_size']; $image = $row['image']; if($image == null){ echo "no image!"; } else { header('Content-Type: content/data'); header("Content-length: $size"); echo $image; } } here is the code that I use to read in from the server: URL sizeUrl = new URL(MYURL); URLConnection sizeConn = sizeUrl.openConnection(); // Get The Response BufferedReader sizeRd = new BufferedReader(new InputStreamReader(sizeConn.getInputStream())); String line = ""; while(line.equals("")){ line = sizeRd.readLine(); } int image_size = Integer.parseInt(line); if(image_size == 0){ return null; } URL imageUrl = new URL(MYIMAGEURL); URLConnection imageConn = imageUrl.openConnection(); // Get The Response InputStream imageRd = imageConn.getInputStream(); byte[] bytedata = new byte[image_size]; int read = imageRd.read(bytedata, 0, image_size); Log.e("IMAGEDOWNLOADER", "read "+ read + " amount of bytes"); Log.e("IMAGEDOWNLOADER", "byte data has length " + bytedata.length); Bitmap theImage = BitmapFactory.decodeByteArray(bytedata, 0, image_size); if(theImage == null){ Log.e("IMAGEDOWNLOADER", "the bitmap is null"); } return theImage; My logging shows that everything has the right length, yet theImage is always null. I'm thinking it has to do with my content type. Or maybe the way I'm uploading?

    Read the article

  • Apache HttpClient 4.0. Weird behavior.

    - by Mikhail T
    Hello. I'm using Apache HttpClient 4.0 for my web crawler. The behavior i found strange is: i'm trying to get page via HTTP GET method and getting response about 404 HTTP error. But if i try to get that page using browser it's done successfully. Details: 1. I upload multipart form to server this way: HttpPost httpPost = new HttpPost("http://[host here]/in.php"); MultipartEntity entity = new MultipartEntity(HttpMultipartMode.BROWSER_COMPATIBLE); entity.addPart("method", new StringBody("post")); entity.addPart("key", new StringBody("223fwe0923fjf23")); FileBody fileBody = new FileBody(new File("photo.jpg"), "image/jpeg"); entity.addPart("file", fileBody); httpPost.setEntity(entity); HttpResponse response = httpClient.execute(httpPost); HttpEntity result = response.getEntity(); String responseString = ""; if (result != null) { InputStream inputStream = result.getContent(); byte[] buffer = new byte[1024]; while(inputStream.read(buffer) > 0) responseString += new String(buffer); result.consumeContent(); } Uppload succefully ends. I'm getting some results from web server: HttpGet httpGet = new HttpGet("http://[host here]/res.php?key="+myKey+"&action=get&id="+id); HttpResponse response = httpClient.execute(httpGet); HttpEntity entity = response.getEntity(); I'm getting ClientProtocolException while execute method run. I was debugging this situation with log4j. Server answers "404 Not Found". But my browser loads me that page with no problem. Can anybody help me? Thank you.

    Read the article

  • How do I use IPTC/EXIF metadata to categorise photos?

    - by kbro
    Many photo viewing and editing applications allow you to examine and change EXIF and IPTC data in JPEG and other image files. For example, I can see things like shutter speed, aperture and orientation in the picture files that come off my Canon A430. There are many, many name/value pairs in all this metadata. But... What do I do if I want to store some data that doesn't have a build-in field name. Let's say I'm photographing an athletics competition and I want to tag every photo with the competitor's bib number. Can I create a "bib_number" field and assign it a values of "0001", "5478", "8124" etc, and then search for all photos with bib_number="5478"? I've spent a few hours searching and the best I can come up with is to put this custom information in the "keywords" field but this isn't quite what I'm after. With this socution I'd have to craft a query like "keywords contains bib_number_5478" whereas what I want it "bib_number is 5478". So do the EXIF and/or IPTC standards allow addtional user-defined field names? Thanks Kev

    Read the article

  • Rack, FastCGI, Lighttpd configuration

    - by zacsek
    Hi! I want to run a simple application using Rack, FastCGI and Lighttpd, but I cannot get it working. I get the following error: /usr/lib/ruby/1.8/rack/handler/fastcgi.rb:23:in `initialize': Address already in use - bind(2) (Errno::EADDRINUSE) from /usr/lib/ruby/1.8/rack/handler/fastcgi.rb:23:in `new' from /usr/lib/ruby/1.8/rack/handler/fastcgi.rb:23:in `run' from /www/test.rb:7 Here is the application: #!/usr/bin/ruby app = Proc.new do |env| [200, {'Content-Type' => 'text/plain'}, "Hello World!"] end require 'rack' Rack::Handler::FastCGI.run app, :Port => 4000 ... and the lighttpd.conf: server.modules += ( "mod_access", "mod_accesslog", "mod_fastcgi" ) server.port = 80 server.document-root = "/www" mimetype.assign = ( ".html" => "text/html", ".txt" => "text/plain", ".jpg" => "image/jpeg", ".png" => "image/png" ) index-file.names = ( "test.rb" ) fastcgi.debug = 1 fastcgi.server = ( ".rb" => (( "host" => "127.0.0.1", "port" => 4000, "bin-path" => "/www/test.rb", "check-local" => "disable", "max-procs" => 1 )) ) Can someone help me? What am I doing wrong?

    Read the article

< Previous Page | 30 31 32 33 34 35 36 37 38 39 40 41  | Next Page >