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  • Another Link in the SEO Chain

    External links, reciprocal linking, search engine optimisation... It's enough to spin the heads of those not up to date with web development language. However, if you have a business website and you want to achieve listings on the first few pages (and hopefully the top 10) of Google, you'd better start to pay attention!

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  • How to disable the link MissingFile on Shotwell

    - by user86865
    I have some personal photos which are encrypted by CryptKeeper. I doesn't like to disclose them to anyone. Whenever i lke to view them, I mount them using CryptKeeper. I need to include these photos in Shotwell photo manager at the time of mounting. So, I mounted them using CryptKeeper. Then I imported them to Shotwell. I made a new event and etc to organize and view those photos. After that I unmounted them using CryptKeeper because someone may see it. Now I don't want any single trail on Shotwell beacuse of the same problem. But there is a new button 'MissingFiles' appeared and when i clicked on it, all the photo thumbnail which i unmounted showed there. I dont't want right'click on them and select 'remove from library'; beacuse when i want to view them next time on Shotwell, I need to import, organize, etc at that time. So, the only option here is to disable the unavailability of that MisssingFiles button.

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  • Signs of a Quality SEO Link Building Service

    The most valuable links are those with the nofollow attribute, with keywords in anchor text and which are placed on high authority pages with similar content. Of course, other links also count. You should never focus only on search engines.

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  • 5 Effective Link Building Strategies to Push Your Website to the Top

    You have probably heard a thousand times before that you need to have more backlinks in order to improve your website ranking. This is especially true now with Google than with Yahoo and Bing which rely on different algorithms. But take it from me that you can never have too many backlinks to stamp your authority with the search engines

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  • Importance of Link Building to Your Website

    Whether you are new or old to the search engine optimization strategies also known as SEO for Internet marketing, then you have to know that one of the most vital tools that can help you attain more traffic to your website is inbound links. They are most reliable for increasing popularity and placing your site among the top ranked websites on search engines such as Google.

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  • A Few Link Building SEO Tips

    The more links that you have leading to your website, the more traffic you will get. You cannot have too many links. If you also have outgoing links, then your site ranks higher in the search engines.

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  • SEO - Link Building Explained

    So you've gone through the long process of optimising your website for search engines; completed keyword research, applied your keywords to your HTML page titles ensuring they also appear in your content and submitted a sitemap to the major search engines, that must be it right? Wrong!

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  • NOTEPAD++ Need macro or typeitin for automation of large lists

    - by user2526699
    I'm sure there is a way to do this but I can not seem to figure it out. I will try my best to explain this. I have a list with 20,000 lines in notepad++. I have two tabs open in notepad++. The right side tab is the main list. The left side tab is what needs to be added to the beginning of each line in the right tab. Here is an image of my notepad++ to give you a better understanding. I need to be able to do the following in an automated way as I have over 20,000 lines to do this way. copy line 1 of tab 'new 7' switch to tab 'new 6' paste clipboard(line 1 of tab 'new 7') at beginning of line 1 tab 'new 6' switch back to tab 'new 7' copy line 2 of tab 'new 7' switch to tab 'new 6' paste clipboard(line 2 of tab 'new 7') at beginning of line 2 tab 'new 6' I have both pasteitin and typeitin download but if i need some other program/app or if it's built in to notepad++ that would be great. I need to do this by the program itself or for me to only have to press a button to do each of these.

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  • Link Building and How it Affects Your SEO

    We have all heard that links and backlinks can affect your SEO campaign in a positive manner, but do we know exactly how it works? If you are in the middle of or beginning your SEO campaign soon, you will want to read this article.

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  • How to Use Twitter For Link Building

    Twitter is one of the most popular social bookmarking sites in the world. From the moment you post the tweets on Twitter, it will already have generated viewers to the linked article page. Though Twitter looks like a simple website, it is a powerful marketing tool which is used by internet marketers to market their business to the targeted audience.

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  • Link-building tips? [closed]

    - by RD01
    Possible Duplicate: What is a good way to get many inbound links to your site? I'm probably taking a huge chance here, but I've become a bit desperate. We've paid many a dollar to companies to help push up our page rank, but with no results. I myself have tried everything. Page Rank got up to 5, and now it seems to have gone down to 4. Any advice, even if you point me to an AFFORDABLE and RELIABLE company, I would really appreciate it?

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  • unordered lists as columns

    - by Ben
    I am trying to use unordered lists as columns something setup like the following: <ul> <li>word 1</li> <li>word 1</li> <li>word 1</li> <li>word 1</li> <li>word 1</li> </ul> <ul> <li>word 2</li> <li>word 2</li> <li>word 2</li> <li>word 2</li> <li>word 2</li> </ul> What would I need to do as far as css these to lineup side by side as vertical lists with no bullets. I'm sure I'm missing something simple but I can't seem to figure it out. I specifically need this to work in IE7. Thanks in advance, Ben

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  • ASP.NET: Enumerating header elements from codebehind

    - by JamesBrownIsDead
    On Page_Load() in the codebehind, I'd like to enumerate all the <link> tags. The purpose being I want want to add a <link> to a CSS file if it isn't specified in the Page's markup. How can I do this? I'm thinking I should be able to use LINQ on the collection of elements in the header, no? Here's my pseudocode: var pageAlreadyContainsCssLink = false; foreach(var control in this.Header.Controls) { if (control.TagName == "link" && control.Attributes["href"] == "my_css_file.css") { pageAlreadyContainsCssLink = true; break; } } if (pageAlreadyContainsCssLink) { // Don't add <link> element return; } // Add the <link> to the CSS this.AddCssLink(...);

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  • Database design grouping contacts by lists and companies

    - by Serge
    Hi, I'm wondering what would be the best way to group contacts by their company. Right now a user can group their contacts by custom created lists but I'd like to be able to group contacts by their company as well as store the contact's position (i.e. Project Manager of XYZ company). Database wise this is what I have for grouping contacts into lists contact [id_contact] [int] PK NOT NULL, [lastName] [varchar] (128) NULL, [firstName] [varchar] (128) NULL, ...... contact_list [id_contact] [int] FK, [id_list] [int] FK, list [id_list] [int] PK [id_user] [int] FK [list_name] [varchar] (128) NOT NULL, [description] [TEXT] NULL Should I implement something similar for grouping contacts by company? If so how would I store the contact's position in that company and how can I prevent data corruption if a user modifies a contact's company name. For instance John Doe changed companies but the other co-workers are still in the old company. I doubt that will happen often (might not even happen at all) but better be safe than sorry. I'm also keeping an audit trail so in a way the contact would still need to be linked to the old company as well as the new one but without confusing what company he's actually working at the moment. I hope that made sense... Has anyone encountered such a problem? UPDATE Would something like this make sense contact_company [id_contact_company] [int] PK [id_contact] [int] FK [id_company] [int] FK [contact_title] [varchar] (128) company [id_company] [int] PK NOT NULL, [company_name] [varchar] (128) NULL, [company_description] [varchar] (300) NULL, [created_date] [datetime] NOT NULL This way a contact can work for more than one company and contacts can be grouped by companies

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  • 2 Mutually exclusive RadioButton "Lists"

    - by user72603
    I think this has to be THE most frustrating thing I've ever done in web forms. Yet one would think it would be the easiest of all things in the world to do. That is this: I need 2 separate lists of radiobuttons on my .aspx page. One set allows a customer to select an option. The other set does also but for a different purpose. But only one set can have a selected radiobutton. Ok I've tried this using 2 asp.net Radiobuttonlists controls on the same page. Got around the nasty bug with GroupName (asp.net assigns the control's uniqueID which prevents the groupname from ever working because now, 2 radiobuttonlists can't have the same groupname for all their radiobuttons because each radiobuttonlist has a different uniqueID thus the bug assigns the unique ID as the name attribute when the buttons are rendered. since the name sets are different, they are not mutually exclusive). Anyway, so I created that custom RadioButtonListcontrol and fixed that groupname problem. But when ended up happening is when I went to put 2 instances of my new custom radiobuttonlist control on my .aspx page, all was swell until I noticed that every time I checked for radiobuttonlist1.SelectedValue or radiobuttonlist2.SelectedValue (did not matter which I was checking) the value always spit back string.empty and i was not able to figure out why (see http://forums.asp.net/t/1401117.aspx). Ok onto the third try tonight and into the break of dawn (no sleep). I tried to instead just scrap trying to use 2 custom radiobuttonlists altogether because of that string.empty issue and try to spit out 2 sets of radiobuttonlists via using 2 asp.net repeaters and a standard input HTML tag inside. Got that working. Ok but the 2 lists still are not mutually exclusive. I can select a value in the first set of radiobuttons from repeater1 and same goes for repeater2. I cannot for the life of me get the "sets" to be mutually exclusive sets of radiobuttons.

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  • Permuting a binary tree without the use of lists

    - by Banang
    I need to find an algorithm for generating every possible permutation of a binary tree, and need to do so without using lists (this is because the tree itself carries semantics and restraints that cannot be translated into lists). I've found an algorithm that works for trees with the height of three or less, but whenever I get to greater hights, I loose one set of possible permutations per height added. Each node carries information about its original state, so that one node can determine if all possible permutations have been tried for that node. Also, the node carries information on weather or not it's been 'swapped', i.e. if it has seen all possible permutations of it's subtree. The tree is left-centered, meaning that the right node should always (except in some cases that I don't need to cover for this algorithm) be a leaf node, while the left node is always either a leaf or a branch. The algorithm I'm using at the moment can be described sort of like this: if the left child node has been swapped swap my right node with the left child nodes right node set the left child node as 'unswapped' if the current node is back to its original state swap my right node with the lowest left nodes' right node swap the lowest left nodes two childnodes set my left node as 'unswapped' set my left chilnode to use this as it's original state set this node as swapped return null return this; else if the left child has not been swapped if the result of trying to permute left child is null return the permutation of this node else return the permutation of the left child node if this node has a left node and a right node that are both leaves swap them set this node to be 'swapped' The desired behaviour of the algoritm would be something like this: branch / | branch 3 / | branch 2 / | 0 1 branch / | branch 3 / | branch 2 / | 1 0 <-- first swap branch / | branch 3 / | branch 1 <-- second swap / | 2 0 branch / | branch 3 / | branch 1 / | 0 2 <-- third swap branch / | branch 3 / | branch 0 <-- fourth swap / | 1 2 and so on... Sorry for the ridiculisly long and waddly explanation, would really, really apreciate any sort of help you guys could offer me. Thanks a bunch!

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  • Comparing lists in Standard ML

    - by user1050640
    I am extremely new to SML and we just got out first programming assignment for class and I need a little insight. The question is: write an ML function, called minus: int list * int list -> int list, that takes two non-decreasing integer lists and produces a non-decreasing integer list obtained by removing the elements from the first input list which are also found in the second input list. For example, minus( [1,1,1,2,2], [1,1,2,3] ) = [1,2] minus( [1,1,2,3],[1,1,1,2,2] ) = [3] Here is my attempt at answering the question. Can anyone tell me what I am doing incorrectly? I don't quite understand parsing lists. fun minus(xs,nil) = [] | minus(nil,ys) = [] | minus(x::xs,y::ys) = if x=y then minus(xs,ys) else x :: minus(x,ys); Here is a fix I just did, I think this is right now? fun minus(L1,nil) = L1 | minus(nil,L2) = [] | minus(L1,L2) = if hd(L1) > hd(L2) then minus(L1,tl(L2)) else if hd(L1) = hd(L2) then minus(tl(L1),tl(L2)) else hd(L1) :: minus(tl(L1), L2);

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  • Combine Lists with Same Heads in a 2D List (OCaml)

    - by Atticus
    Hi guys, I'm working with a list of lists in OCaml, and I'm trying to write a function that combines all of the lists that share the same head. This is what I have so far, and I make use of the List.hd built-in function, but not surprisingly, I'm getting the failure "hd" error: let rec combineSameHead list nlist = match list with | [] -> []@nlist | h::t -> if List.hd h = List.hd (List.hd t) then combineSameHead t nlist@uniq(h@(List.hd t)) else combineSameHead t nlist@h;; So for example, if I have this list: [[Sentence; Quiet]; [Sentence; Grunt]; [Sentence; Shout]] I want to combine it into: [[Sentence; Quiet; Grunt; Shout]] The function uniq I wrote just removes all duplicates within a list. Please let me know how I would go about completing this. Thanks in advance!

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