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  • jQuery Validate - require at least one field in a group to be filled

    - by Nathan Long
    I'm using the excellent jQuery Validate Plugin to validate some forms. On one form, I need to ensure that the user fills in at least one of a group of fields. I think I've got a pretty good solution, and wanted to share it. Please suggest any improvements you can think of. Finding no built-in way to do this, I searched and found Rebecca Murphey's custom validation method, which was very helpful. I improved this in three ways: To let you pass in a selector for the group of fields To let you specify how many of that group must be filled for validation to pass To show all inputs in the group as passing validation as soon as one of them passes validation. So you can say "at least X inputs that match selector Y must be filled." The end result is a rule like this: partnumber: { require_from_group: [2,".productinfo"] } //The partnumber input will validate if //at least 2 `.productinfo` inputs are filled For best results, put this rule AFTER any formatting rules for that field (like "must contain only numbers", etc). This way, if the user gets an error from this rule and starts filling out one of the fields, they will get immediate feedback about the formatting required without having to fill another field first. Item #3 assumes that you're adding a class of .checked to your error messages upon successful validation. You can do this as follows, as demonstrated here. success: function(label) { label.html(" ").addClass("checked"); } As in the demo linked above, I use CSS to give each span.error an X image as its background, unless it has the class .checked, in which case it gets a check mark image. Here's my code so far: jQuery.validator.addMethod("require_from_group", function(value, element, options) { // From the options array, find out what selector matches // our group of inputs and how many of them should be filled. numberRequired = options[0]; selector = options[1]; var commonParent = $(element).parents('form'); var numberFilled = 0; commonParent.find(selector).each(function(){ // Look through fields matching our selector and total up // how many of them have been filled if ($(this).val()) { numberFilled++; } }); if (numberFilled >= numberRequired) { // This part is a bit of a hack - we make these // fields look like they've passed validation by // hiding their error messages, etc. Strictly speaking, // they haven't been re-validated, though, so it's possible // that we're hiding another validation problem. But there's // no way (that I know of) to trigger actual re-validation, // and in any case, any other errors will pop back up when // the user tries to submit the form. // If anyone knows a way to re-validate, please comment. // // For imputs matching our selector, remove error class // from their text. commonParent.find(selector).removeClass('error'); // Also look for inserted error messages and mark them // with class 'checked' var remainingErrors = commonParent.find(selector) .next('label.error').not('.checked'); remainingErrors.text("").addClass('checked'); // Tell the Validate plugin that this test passed return true; } // The {0} in the next line is the 0th item in the options array }, jQuery.format("Please fill out at least {0} of these fields.")); Questions? Comments?

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  • Aggregating Excel cell contents that match a label [migrated]

    - by Josh
    I'm sure this isn't a terribly difficult thing, but it's not the type of question that easily lends itself to internet searches. I've been assigned a project for work involving a complex spreadsheet. I've done the usual =SUM and other basic Excel formulas, and I've got enough coding background that I'm able to at least fudge my way through VBA, but I'm not certain how to proceed with one part of the task. Simple version: On Sheet 1 I have a list of people (one on each row, person's name in column A), on sheet 2 I have a list of groups (one on each row, group name in column A). Each name in Sheet 1 has its own row, and I have a "Data Validation" dropdown menu where you choose the group each person belongs to. That dropdown is sourced from Sheet 2, where each group has a row. So essentially the data validation source for Sheet 1's "Group" column is just "=Sheet2!$a1:a100" or whatever. The problem is this: I want each group row in Sheet 2 to have a formula which results in a list of all the users which have been assigned to that group on Sheet 1. What I mean is something the equivalent of "select * from PeopleTab where GROUP = ThisGroup". The resulting cell would just stick the names together like "Bob Smith, Joe Jones, Sally Sanderson" I've been Googling for hours but I can't think of a way to phrase my search query to get the results I want. Here's an example of desired result (Dash-delimited. Can't find a way to make it look nice, table tags don't seem to work here): (Sheet 1) Bob Smith - Group 1 (selected from dropdown) Joe Jones - Group 2 (selected from dropdown) Sally Sanderson - Group 1 (selected from dropdown) (Sheet 2) Group 1 - Bob Smith, Sally Sanderson (result of formula) Group 2 - Joe Jones (result of formula) What formula (or even what function) do I use on that second column of sheet 2 to make a flat list out of the members of that group?

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  • SQL Server: Difference between PARTITION BY and GROUP BY

    - by Mike Mooney
    I've been using GROUP BY for all types of aggregate queries over the years. Recently, I've been reverse-engineering some code that uses PARTITION BY to perform aggregations. In reading through all the documentation I can find about PARTITION BY, it sounds a lot like GROUP BY, maybe with a little extra functionality added in? Are they two versions of the same general functionality, or are they something different entirely?

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  • Custom aggregation in GROUP BY clause

    - by Rire1979
    If I have a table with a schema like this table(Category, SubCategory1, SubCategory2, Status) I would like to group by Category, SubCategory1 and aggregate the Status such that if not all Status values over the group have a certain value Status will be 0 otherwise 1. So my result set will look like (Category, SubCategory1, Status) I don't want to write a function. I would like to do it inside the query.

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  • How to use Linq group a order list by Date

    - by Daoming Yang
    I have a order list and want to group them by the created date. Each order's created datetime will be like "2010-03-13 11:17:16.000" How can I make them only group by date like "2010-03-13"? var items = orderList.GroupBy(t => t.DateCreated) .Select(g => new Order() { DateCreated = g.Key }) .OrderByDescending(x => x.OrderID).ToList();

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  • Group Chat XMPP with Google App Engine

    - by David Shellabarger
    Google App Engine has a great XMPP service built in. One of the few limitations it has is that it doesn't support receiving messages from a group chat. That's the one thing I want to do with it. :( Can I run a 3rd party XMPP/Jabber server on App Engine that supports group chat? If so, which one?

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  • How to use group by and having count in Linq

    - by Luke
    I am having trouble trying to convert the following query from SQL to Linq, in particular with the having count and group by parts of the query: select ProjectID from ProjectAssociation where TeamID in ( select TeamID from [User] where UserID in (4)) group by ProjectID having COUNT(TeamID) = (select distinct COUNT(TeamID) from [User] where UserID in (4)) Any advice on how to do so would be much appreciated.

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  • SQL: Find the max record per group

    - by user319088
    I have one table, which has three fields and data. Name , Top , Total cat , 1 , 10 dog , 2 , 7 cat , 3 , 20 horse , 4 , 4 cat , 5 , 10 dog , 6 , 9 I want to select the record which has highest value of Total for each Name, so my result should be like this: Name , Top , Total cat , 3 , 20 horse , 4 , 4 Dog , 6 , 9 I tried group by name order by total, but it give top most record of group by result. Can anyone guide me, please?

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  • group by query issue

    - by user319088
    gorup by query issue i have one table, which has three fields and data. Name , Top , total cat , 1 ,10 dog , 2, 7 cat , 3 ,20 hourse 4, 4 cat, 5,10 Dog 6 9 i want to select record which has highest value of "total" for each Name so my result should be like this. Name , Top , total cat , 3 , 20 hourse , 4 , 4 Dog , 6 , 9 i tried group by name order by total, but it give top most record of group by result. any one can guide me , please!!!!

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  • Group By Multiple Columns - LINQ

    - by Nev_Rahd
    How can I do GroupBy Multiple Columns in LINQ Something as in SQL : SELECT * FROM <TableName> GROUP BY <Column1>,<Column2> How Can i convert below to LINQ QuantityBreakdown ( MaterialID int, ProductID int, Quantity float ) INSERT INTO @QuantityBreakdown (MaterialID, ProductID, Quantity) SELECT MaterialID, ProductID, SUM(Quantity) FROM @Transactions GROUP BY MaterialID, ProductID Thanks

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  • Calculated group-by fields in MongoDB

    - by Navin Viswanath
    For this example from the MongoDB documentation, how do I write the query using MongoTemplate? db.sales.aggregate( [ { $group : { _id : { month: { $month: "$date" }, day: { $dayOfMonth: "$date" }, year: { $year: "$date" } }, totalPrice: { $sum: { $multiply: [ "$price", "$quantity" ] } }, averageQuantity: { $avg: "$quantity" }, count: { $sum: 1 } } } ] ) Or in general, how do I group by a calculated field?

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  • XS:Group causes Schema to fail validation

    - by paulwhit
    I have an XML document based on a Schema that uses the xs:group element to bunch elements together. The result is an entity where name, address and phone number are defined in a group. This fails Schema validation in MS (Visual Studio) as well as XERCES (oXygen XML editor) Is there a workaround?

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  • Group partial class shortcut

    - by Fred Yang
    I have to cs file for one partial class. I know that I can modify project file to group them together like way that vs.net group *.aspx and *.aspx.cs, but is there a way to do that in vs.net IDE directly?

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  • Drupal 6: Group multiple values in tpl.php

    - by Jozzeh
    When using the date and views module, you can specify in views (using row style fields) 'group multiple values'. Which is default on. If you turn it off, you get multiple nodes each with a date. For example: - 24th March ------- node1 - 25th March ------- node1 What I'm trying to figure out is: what if you are not using fields but node as Row style. How do you implement this not-group-multiple-values in your type-node.tpl.php?

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  • MySQL - generate numbers for a group of results

    - by FreeIX
    I need a query to return this result: +---------+-----+-------+ | ref_nid | nid | delta | +---------+-----+-------+ | AA | 97 | 1 | | BB | 97 | 2 | | CC | 97 | 3 | | DD | 98 | 1 | | EE | 98 | 2 | | FF | 98 | 3 | +---------+-----+-------+ However, I do not have the delta column. I need to generate it for each nid group. In other words, I need an auto incremented number for each group of the result.

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  • SELECT GROUP BY latest entry in INBOX msg sent by user

    - by Mohatir S
    i am building a simple PM for my personal website where a user can join and send message to the registered users on my website, i am stuck in grouping and selecting latest user (by latest msg time) in INBOX page my table : id msg_from msg_to msg date in_del out_del i want to show latest user's id each in a group here is my SQL query : SELECT ttalk.id, ttalk.msg_from, users.first_name, users.last_name FROM ttalk INNER JOIN users ON ttalk.msg_from = users.id WHERE ttalk.msg_to = '$_SESSION[user_id]' AND ttalk.in_del='0' GROUP BY ttalk.msg_from DESC LIMIT 500 Thanks in advance :-)

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  • SQL Command Not Properly Ended (Nested Aggregation with Group-by)

    - by snowind
    I keep getting this error when I tried to execute this query, although I couldn't figure out what went wrong. I'm using Oracle and JDBC. Here's the query: SELECT Temp.flight_number, Temp.avgprice FROM (SELECT P.flight_number, AVG (P.amount) AS avgprice FROM purchase P GROUP BY P.flight_number) AS Temp WHERE Temp.avgprice = (SELECT MAX (Temp.avgprice) FROM Temp) I'm trying to get the maximum of average price of the tickets that customers have booked, group by flight_number.

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