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• matplotlib plot window won't appear

  - by user1518837

  I'm using Python 2.7.3 in 64-bit. I installed pandas as well as matplotlib 1.1.1, both for 64-bit. Right now, none of my plots are showing. After attempting to plot from several different dataframes, I gave up in frustration and tried the following first example from http://pandas.pydata.org/pandas-docs/dev/visualization.html: INPUT: import matplotlib.pyplot as plt ts = Series(randn(1000), index=date_range ('1/1/2000', periods=1000)) ts = ts.cumsum() ts.plot() pylab.show() OUTPUT: Axes(0.125,0.1;0.775x0.8) And no plot window appeared. Other StackOverflow threads I've read suggested I might be missing DLLs. Any suggestions?

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• Create unique file name and fetching it to commandline argument

  - by user343934

  Hi everyone, I am working on python right now and i am little bit stuck in performing some tricks. I have web form with two options- File upload and textarea, i can easily pass file name with file upload options but have problem when it's textarea. Because when i use textarea then first i have to save values passed from textarea to some files and save it on the working directory. After that i can execute commandline argument and pass same saved filename name. For this problem i have to generate unique file first and save the values passed from textarea in it. Can anybody give me some tips to solve my problem. Any algorithms, suggestions and lines of code are appreciated. Thanks for your concern

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• Adding a method to a function object at runtime

  - by Carson Myers

  I read a question earlier asking if there was a times method in Python, that would allow a function to be called n times in a row. Everyone suggested for _ in range(n): foo() but I wanted to try and code a different solution using a function decorator. Here's what I have: def times(self, n, *args, **kwargs): for _ in range(n): self.__call__(*args, **kwargs) import new def repeatable(func): func.times = new.instancemethod(times, func, func.__class__) @repeatable def threeArgs(one, two, three): print one, two, three threeArgs.times(7, "one", two="rawr", three="foo") When I run the program, I get the following exception: Traceback (most recent call last): File "", line 244, in run_nodebug File "C:\py\repeatable.py", line 24, in threeArgs.times(7, "one", two="rawr", three="foo") AttributeError: 'NoneType' object has no attribute 'times' So I suppose the decorator didn't work? How can I fix this?

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• Can't remove first node in linked list

  - by carlmonday

  I'm trying to make a linked list class in python (pointless I know, but it's a learning exercise), and the method I have written to remove a node doesn't work if I try to remove the first element of the linked list. If the node to be removed is anywhere else in the linked list the method works fine. Can someone give me some insight as to where I've gone wrong? Here's my code thus far: class Node: def __init__(self, data=None, next=None): self.data = data self.next = next def __repr__(self): return repr(self.data) def printNodes(self): while self: print self.data self = self.next def removeNode(self, datum): """removes node from linked list""" if self.data == datum: return self.next while self.next: if self.next.data == datum: self.next = self.next.next return self self = self.next

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• symlink files newer than X age, then later remove symlink once file ages?

  - by bleomycin

  Hello everyone, i have a large number of files/folders coming in each day that are being sorted automatically to a wide variety of folders. I'm looking for a way to automatically find these files/folders and create symlinks to them all within an "incoming" folder. Searching for file age should be sufficient for finding the files, however searching for age and owner would be ideal. Then once the files/folders being linked to reach a certain age, say 5 days, remove the symlinks to them automatically from the "incoming" folder. Is this possible to do with a simple shell or python script that can be run with cron? Thanks!

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• Why doesn't functools.partial return a real function (and how to create one that does)?

  - by epsilon

  So I was playing around with currying functions in Python and one of the things that I noticed was that functools.partial returns a partial object rather than an actual function. One of the things that annoyed me about this was that if I did something along the lines of: five = partial(len, 'hello') five('something') then we get TypeError: len() takes exactly 1 argument (2 given) but what I want to happen is TypeError: five() takes no arguments (1 given) Is there a clean way to make it work like this? I wrote a workaround, but it's too hacky for my taste (doesn't work yet for functions with varargs): def mypartial(f, *args): argcount = f.func_code.co_argcount - len(args) params = ''.join('a' + str(i) + ',' for i in xrange(argcount)) code = ''' def func(f, args): def %s(%s): return f(*(args+(%s))) return %s ''' % (f.func_name, params, params, f.func_name) exec code in locals() return func(f, args)

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• sqlite3.OperationalError

  - by fixxxer

  Hi, The "python manage.py syncdb" command is giving me the following error: sqlite3.OperationalError: unable to open database file I'm following the step by step instructions in Practical Django Projects, so I think this has to do something with the Windows Operating system acting quirky! Things I've checkde: 1.The path is updated in settings.py is absolutely correcto! 2. Path is : C:\Documents and Settings\fixavier\Desktop\Django\Database\cms\cms.txt So the entire folder - Database, has sharing and security permissions. I'm pretty much at the bottom of the ocean for not being able to follow and successfully execute simple instructions, so could you please help me out here!

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• Sorting a 2D numpy array by multiple axes

  - by perimosocordiae

  I have a 2D numpy array of shape (N,2) which is holding N points (x and y coordinates). For example: array([[3, 2], [6, 2], [3, 6], [3, 4], [5, 3]]) I'd like to sort it such that my points are ordered by x-coordinate, and then by y in cases where the x coordinate is the same. So the array above should look like this: array([[3, 2], [3, 4], [3, 6], [5, 3], [6, 2]]) If this was a normal Python list, I would simply define a comparator to do what I want, but as far as I can tell, numpy's sort function doesn't accept user-defined comparators. Any ideas?

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• Need help specifying a ending while condition

  - by johnthexiii

  I have written a Python script to download all of the xkcd comic images. The only problem is I can't tell it to stop when it gets to the last one... Here is what I have so far. import re, mechanize from urllib import urlretrieve from BeautifulSoup import BeautifulSoup as bs baseUrl = "http://xkcd.com/1/" #Specify the first comic page br = mechanize.Browser() #Create a browser response = br.open(baseUrl) #Create an initial response x = 1 #Assign an initial file name while (SomeCondition): soup = bs(response.get_data()) #Create an instance of bs that contains the response data img = soup.findAll('img')[1] #Get the online file path of the image localFile = "C:\\Comics\\xkcd\\" + str(x) + ".jpg" #Come up with a local file name urlretrieve(img["src"], localFile) #Download the image file response = br.follow_link(text = "Next >") #Store the response of the next button x += 1 #Increase x by 1 print "All xkcd comics downloaded" #Let the user know the images have been downloaded Initially what I had was something like while br.follow_link(text = "Next >") != br.follow_link(text = ">|"): but by doing this I actually send skip to the last page before the script has a chance to perform the intended purpose.

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• averaging matrix efficiently

  - by user248237

  in Python, given an n x p matrix, e.g. 4 x 4, how can I return a matrix that's 4 x 2 that simply averages the first two columns and the last two columns for all 4 rows of the matrix? e.g. given: a = array([[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16]]) return a matrix that has the average of a[:, 0] and a[:, 1] and the average of a[:, 2] and a[:, 3]. I want this to work for an arbitrary matrix of n x p assuming that the number of columns I am averaging of n is obviously evenly divisible by n. let me clarify: for each row, I want to take the average of the first two columns, then the average of the last two columns. So it would be: 1 + 2 / 2, 3 + 4 / 2 <- row 1 of new matrix 5 + 6 / 2, 7 + 8 / 2 <- row 2 of new matrix, etc. which should yield a 4 by 2 matrix rather than 4 x 4. thanks.

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• Using `.index()` on repeating letters

  - by Yarden

  I'm building a function that builds a dictionary with words, such as: {'b': ['b', 'bi', 'bir', 'birt', 'birth', 'birthd', 'birthda', 'birthday'], 'bi': ['bi', 'bir', 'birt', 'birth', 'birthd', 'birthda', 'birthday'], 'birt': ['birt', 'birth', 'birthd', 'birthda', 'birthday'], 'birthda': ['birthda', 'birthday'], 'birthday': ['birthday'], 'birth': ['birth', 'birthd', 'birthda', 'birthday'], 'birthd': ['birthd', 'birthda', 'birthday'], 'bir': ['bir', 'birt', 'birth', 'birthd', 'birthda', 'birthday']} This is what it looks like: def add_prefixs(word, prefix_dict): lst=[] for letter in word: n=word.index(letter) if n==0: lst.append(word[0]) else: lst.append(word[0:n]) lst.append(word) lst.remove(lst[0]) for elem in lst: b=lst.index(elem) prefix_dict[elem]=lst[b:] return prefix_dict It works great for words like "birthday", but when I have a letter that repeats itself, I have a problem... for example, "hello". {'h': ['h', 'he', 'he', 'hell', 'hello'], 'hell': ['hell', 'hello'], 'hello': ['hello'], 'he': ['he', 'he', 'hell', 'hello']} I know it's because of the index (python chooses the index of the first time the letter appears) but I do not know how to solve it. Yes, this is my homework and I'm really trying to learn from you guys :)

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• Replacing emty csv column values with a zero

  - by homerjay

  Hey, So I'm dealing with a csv file that has missing values. What I want my script to is: #!/usr/bin/python import csv import sys #1. Place each record of a file in a list. #2. Iterate thru each element of the list and get its length. #3. If the length is less than one replace with value x. reader = csv.reader(open(sys.argv[1], "rb")) for row in reader: for x in row[:]: if len(x)< 1: x = 0 print x print row Here is an example of data, I trying it on, ideally it should work on any column lenghth Before: actnum,col2,col4 xxxxx , , xxxxx , 845 , xxxxx , ,545 After actnum,col2,col4 xxxxx , 0 , 0 xxxxx , 845, 0 xxxxx , 0 ,545 Any guidance would be appreciated

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• Routing Skype call to another Voip company

  - by Anarchist

  Hello, As my project to do over this summer I would like to create a program that answers a Skype call using the Skype API and allows a user to connect to another VOIP provider (through SIP) and make calls by dialling through the client callers Skype application. I understand that the Skype API allows me to answer and receive keypad input, but I'm stuck on actually sending the sound of the call to a SIP client. Is there an API/library that would allow me to take the Skype receiving audio as input in the SIP client? Is this even possible? I'm not tied to a language but I had planned on using Python. Thanks.

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• Giving users a "reputation system" - Should I... ?

  - by RadiantHex

  Hi folks, I'm thinking of adding a reputation system to a web application, the site is already being used so I'm trying to be careful about my choices. I'm developing in Django/Python, thought this would be important. Reputation is generated in all actions that contribute to the site, similar to Stackoverflow's system. I know there are literally millions of ways of implementing this, and this is why I feel quite lost. Two alternatives I am not sure about are: Keep track of reasons why reputation was incremented Ignore reasons in order to reduce complexity of the site and overhead Would be happy with a few pointers, and directions. Would be very much appreciated!

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• Django: Why Doesn't the Current URL Match any Patterns in urls.py

  - by austin_sherron

  I've found a few questions here related to my issue, but I haven't found anything that has helped me resolve my issue. I'm using Python 2.7.5 and Django 1.8.dev20140627143448. I have a view that's interacting with my database to delete objects, and it takes two arguments in addition to a request: def delete_data_item(request, dataclass_id, dataitem_id): form = AddDataItemForm(request.POST) data_set = get_object_or_404(DataClass, pk=dataclass_id) context = {'data_set': data_set, 'form': form} data_item = get_object_or_404(DataItem, pk=dataitem_id) data_item.delete() data_set.save() return HttpResponseRedirect(reverse('detail', args=(dataclass_id,))) The URL in myapp.urls.py looks something like this: url(r'^(?P<dataclass_id>[0-9]+)/(?P<dataitem_id>[0-9]+)/delete_data_item/$', views.delete_data_item, name='delete_data_item') and the portion of my template relevant to the view is: <a href="{% url 'delete_data_item' data_set.id data_item.id %}">DELETE</a> Whenever I click on the DELETE link, django tells me that the request URL: http://127.0.0.1:8000/myapp/5/%7B%%20url%20'delete_data_item'%20data_set.id%20data_item.id%20%%7D doesn't match any of my URL patterns. What am I missing? The URL on which the DELETE links exist is myapp/(<dataclass_id>[0-9]+)/

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• How to improve the speed of a loop containing a sqlalchemy query statement as conditional

  - by LtPinback

  This loop checks if a record is in the sqlite database and builds a list of dictionaries for those records that are missing and then executes a multiple insert statement with the list. This works but it is very slow (at least i think it is slow) as it takes 5 minutes to loop over 3500 queries. I am a complete newbie in python, sqlite and sqlalchemy so I wonder if there is a faster way of doing this. list_dict = [] session = Session() for data in data_list: if session.query(Class_object).filter(Class_object.column_name_01 == data[2]).filter(Class_object.column_name_00 == an_id).count() == 0: list_dict.append({'column_name_00':a_id, 'column_name_01':data[2]}) conn = engine.connect() conn.execute(prices.insert(),list_dict) conn.close() session.close() edit: I moved session = Session() outside the loop. Did not make a difference.

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• Writing to CSV issue in Spyder

  - by 0003

  I am doing the Kaggle Titanic beginner contest. I generally work in Spyder IDE, but I came across a weird issue. The expected output is supposed to be 418 rows. When I run the script from terminal the output I get is 418 rows (as expected). When I run it in Spyder IDE the output is 408 rows not 418. When I re-run it in the current python process, it outputs the expected 418 rows. I posted a redacted portion of the code that has all of the relevant bits. Any ideas? import csv import numpy as np csvFile = open("/train.csv","ra") csvFile = csv.reader(csvFile) header = csvFile.next() testFile = open("/test.csv","ra") testFile = csv.reader(testFile) testHeader = testFile.next() writeFile = open("/gendermodelDebug.csv", "wb") writeFile = csv.writer(writeFile) count = 0 for row in testFile: if row[3] == 'male': do something to row writeFile.writerow(row) count += 1 elif row[3] == 'female': do something to row writeFile.writerow(row) count += 1 else: raise ValueError("Did not find a male or female in %s" % row)

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• How to find hidden properties/methods in Javascript objects?

  - by ramanujan

  I would like to automatically determine all of the properties (including the hidden ones) in a given Javascript object, via a generalization of this function: function keys(obj) { var ll = []; for(var pp in obj) { ll.push(pp); } return ll; } This works for user defined objects but fails for many builtins: repl> keys({"a":10,"b":2}); // ["a","b"] repl> keys(Math) // returns nothing! Basically, I'd like to write equivalents of Python's dir() and help(), which are really useful in exploring new objects. My understanding is that only the builtin objects have hidden properties (user code evidently can't set the "enumerable" property till HTML5), so one possibility is to simply hardcode the properties of Math, String, etc. into a dir() equivalent (using the lists such as those here). But is there a better way?

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• Building a financial app with Django

  - by mfalcon

  Hi guys, I'm building an app for a small business so I've to work with currencies, decimal numbers, etc... My goal is to create something like pulseapp.com. I've searched for opensource projects to look and the only thing I had found was django-cashflow. This app uses python-money. I've read some of the code and the ways it's coded seems a bit weird to me and it's not fully complete. Is the app worth to take a deep look? Does anyone know about another similar app? Is the task difficult or a begginer like me could find a way to code it himself?

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• How can I convert this string to list of lists?

  - by Phrixus

  Hi, what I'm trying to do is.. if a user types in [[0,0,0], [0,0,1], [1,1,0]] and press enter, the program should convert this string to several lists; one list holding [0][0][0], other for [0][0][1], and the last list for [1][1][0] I thought tuple thing would work out but no luck... :( I started phython yesterday -- (I'm C / C++ guy.) and cannot use the full advantages of this language... Does python have a good way to handle this? I need help~ :'(

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• Jython: Is there any difference between adding to sys.path vs passing -D?

  - by trinth

  I have a python application that is trying to load some Java libraries (specifically Axis2 web services). When I add the necessary jars in Eclipse via PyDev Project Source Folders, everything seems to work fine. However, I want to be able to do this at run time by adding to sys.path, but then my application doesn't seem to work. In both cases I can load the jars just fine, but something must be different for there to be different results. My question is, is there a difference between adding jars via the sys.path at run time with sys.path.append() versus passing -D to the jython interpreter?

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• Parse text of element with empty element inside

  - by Mando

  I'm trying to convert an XHTML document that uses lots of tables into a semantic XML document in Python using xml.etree. However, I'm having some trouble converting this XHTML <TD> Textline1<BR/> Textline2<BR/> Textline3 </TD> into something like this <lines> <line>Textline1</line> <line>Textline2</line> <line>Textline3</line> </lines> The problem is that I don't know how to get the text after the BR elements.

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• Getting service unavailable message when sending messages to google xmpp using wokkel

  - by Code freak

  Hi, I made a wokkel (twisted python) bot to send and receive messages from the google xmpp service. Everything (auth, presence) etc works fine. One of the rquirements of our prject is that we need to send broadcast messages to everyone in the list. Normal messages and replies work fin, but when i snd a broadcast message, i get this service unavailable error 503 message. There are about 1000 user in my contact list. Is this some bug in the code or is it google policy to prevent rapid messaging. Also, how do other google bots cater to a large contact base ? does google provide a commercial solution for such applications ? Thanks

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• Efficiently Reshaping/Reordering Numpy Array to Properly Ordered Tiles (Image)

  - by Phelix

  I would like to be able to somehow reorder a numpy array for efficient processing of tiles. what I got: >>> A = np.array([[1,2],[3,4]]).repeat(2,0).repeat(2,1) >>> A # image like array array([[[1, 1, 2, 2], [1, 1, 2, 2]], [[3, 3, 4, 4], [3, 3, 4, 4]]]) >>> A.reshape(2,2,4) array([[[1, 1, 2, 2], [1, 1, 2, 2]], [[3, 3, 4, 4], [3, 3, 4, 4]]]) what I want: X >>> X array([[[1, 1, 1, 1], [2, 2, 2, 2]], [[3, 3, 3, 3], [4, 4, 4, 4]]]) to be able to do something like: >>> X[X.sum(2)>12] -= 1 >>> X array([[[1, 1, 1, 1], [2, 2, 2, 2]], [[3, 3, 3, 3], [3, 3, 3, 3]]]) Is this possible without a slow python loop? Bonus: Conversion back from X to A Edit: How can I get X from A?

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• What host do I have to bind a listening socket to?

  - by herrturtur

  I used python's socket module and tried to open a listening socket using import socket import sys def getServerSocket(host, port): for r in socket.getaddrinfo(host, port, socket.AF_UNSPEC, socket.SOCK_STREAM, 0, socket.AI_PASSIVE): af, socktype, proto, canonname, sa = r try: s = socket.socket(af, socktype, proto) except socket.error, msg: s = None continue try: s.bind(sa) s.listen(1) except socket.error, msg: s.close() s = None continue break if s is None: print 'could not open socket' sys.exit(1) return s Where host was None and port was 15000. The program would then accept connections, but only from connections on the same machine. What do I have to do to accept connections from the internet?

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