Search Results

Search found 20157 results on 807 pages for 'friendly url'.

Page 344/807 | < Previous Page | 340 341 342 343 344 345 346 347 348 349 350 351  | Next Page >

  • How to export javascript generated report to pdf?

    - by Parhs
    Hello... I made a reporting engine with javascript for my project... The problem is with printing.. Although with page-break and css i can produce a good looking report, i want to export that report to a pdf in order to be printed better without ,the url,page title and other stuff that browsers add. Note in Chrome there isnt page setup!!! I am using java for server side. i think sending via ajax the Html of the report somehow and return a url for the pdf report maybe... i am looking for a good tool for this thank you

    Read the article

  • .htaccess cross browser

    - by lordsharp
    Hi, Im trying to load a custom error document for a 404 error using a .htaccess file on a linux server, the page gets the current page URL then redirects to another site (which is retrieved from a db) based on an id it retrieved from the URL. The current error documents are stored here: /error_docs/ - i dont have permission to upload anything other than the HTML files that are already in there /HTTPDocs/301redir.php is the site root where the .htaccess file is. i have used the following to load the 301redir.php page as the error doc, which works in FF but no other browsers. ErrorDocument 404 /310redir.php using .htaccess is my only real option for changing this, is there a way to get around this issue and make it work across all browsers?

    Read the article

  • CakePHP delete() function is not working

    - by Logic Artist
    Hello, Im just cracking open cakePHP (v1.3.2). I set it up on my local wamp server, seems to work fine except the delete() function doesn't work. I'm following their blog tutorial exactly, its as simple as it can be so I don't understand why its not working. Heres the function in my PostsController class: function delete($id = NULL) { $this->Post->delete($id); $this->Session->setFlash('The post with id: '.$id.' has been deleted.'); $this->redirect(array('action'=>'index')); } The "Delete" link's url looks like http://localhost/posts/delete/id:1 (where the id number matches the particular post, obviously). It redirects and sets the flash message, however there is no number where $id should be in the message, and the post isn't deleted. It seems the proper id is passed through the url, but I don't think it is getting into the function. I dont get it. Any ideas???

    Read the article

  • How to pass some data to JQuery AJAX in CAKEPHP

    - by kwokwai
    Hi all, I am learning how to use JQuery to help check data availability. To start with it, I wrote a few lines of codes using cakePHP. I have written a function in a Controller for checking data input, and the URL is like this: http://www.mywebsite.com/controllers/action/avariable I was trying to pass the value in a Input TextBox field using the JQuery Ajax to the URL above,but I don't know why it is not working in passing a variable to the Controller's action. Could you help me out please? <Script language="javascript"> //<!-- $(document).ready(function(){ $(document).change(function() { var usr = $("#data\\[User\\]\\[name\\]").val(); if(usr.length >= 3){ $("#username").append('<span><img align="absmiddle" src="loader.gif" />Checking</span>'); $.ajax({ type: "POST", url: "http://www.mywebsite.com/controllers/action/", data: usr, success: function(msg){ if(msg == 'OK') { $("#username").append('<span><img align="absmiddle" src="accepted.png"/></span>'); } else { $("#username").append('<span>'+msg+'</span>'); } } }); } else { $("#username").append('<span>The username should have at least 3 characters.</span>'); } }); }); //--> </Script> <form name="adduser" id="adduser" method="post" action="/controllers/action2"> <table border=0 width="100%"> <tr> <td>Username</td> <td> <div id="username"> <input type=text name="data[User][name]" id="data[User][name]"> </div> </td> </tr> <tr> <td> <input type="submit" value="Send"> </td> </tr> </table> </form>

    Read the article

  • Lighttpd + fastcgi + python (for django) slow on first request

    - by EagleOne
    I'm having a problem with a django website I host with lighttpd + fastcgi. It works great but it seems that the first request always takes up to 3seconds. Subsequent requests are much faster (<1s). I activated access logs in lighttpd in order to track the issue. But I'm kind of stuck. Here are logs where I 'lose' 4s (from 10:04:17 to 10:04:21): 2012-12-01 10:04:17: (mod_fastcgi.c.3636) handling it in mod_fastcgi 2012-12-01 10:04:17: (response.c.470) -- before doc_root 2012-12-01 10:04:17: (response.c.471) Doc-Root : /var/www 2012-12-01 10:04:17: (response.c.472) Rel-Path : /finderauto.fcgi 2012-12-01 10:04:17: (response.c.473) Path : 2012-12-01 10:04:17: (response.c.521) -- after doc_root 2012-12-01 10:04:17: (response.c.522) Doc-Root : /var/www 2012-12-01 10:04:17: (response.c.523) Rel-Path : /finderauto.fcgi 2012-12-01 10:04:17: (response.c.524) Path : /var/www/finderauto.fcgi 2012-12-01 10:04:17: (response.c.541) -- logical -> physical 2012-12-01 10:04:17: (response.c.542) Doc-Root : /var/www 2012-12-01 10:04:17: (response.c.543) Rel-Path : /finderauto.fcgi 2012-12-01 10:04:17: (response.c.544) Path : /var/www/finderauto.fcgi 2012-12-01 10:04:21: (response.c.128) Response-Header: HTTP/1.1 200 OK Last-Modified: Sat, 01 Dec 2012 09:04:21 GMT Expires: Sat, 01 Dec 2012 09:14:21 GMT Content-Type: text/html; charset=utf-8 Cache-Control: max-age=600 Transfer-Encoding: chunked Date: Sat, 01 Dec 2012 09:04:21 GMT Server: lighttpd/1.4.28 I guess that if there is a problem, it's whith my configuration. So here is the way I launch my django app: python manage.py runfcgi method=threaded host=127.0.0.1 port=3033 And here is my lighttpd conf: server.modules = ( "mod_access", "mod_alias", "mod_compress", "mod_redirect", "mod_rewrite", "mod_fastcgi", "mod_accesslog", ) server.document-root = "/var/www" server.upload-dirs = ( "/var/cache/lighttpd/uploads" ) server.errorlog = "/var/log/lighttpd/error.log" server.pid-file = "/var/run/lighttpd.pid" server.username = "www-data" server.groupname = "www-data" accesslog.filename = "/var/log/lighttpd/access.log" debug.log-request-header = "enable" debug.log-response-header = "enable" debug.log-file-not-found = "enable" debug.log-request-handling = "enable" debug.log-timeouts = "enable" debug.log-ssl-noise = "enable" debug.log-condition-cache-handling = "enable" debug.log-condition-handling = "enable" fastcgi.server = ( "/finderauto.fcgi" => ( "main" => ( # Use host / port instead of socket for TCP fastcgi "host" => "127.0.0.1", "port" => 3033, #"socket" => "/home/finderadmin/finderauto.sock", "check-local" => "disable", "fix-root-scriptname" => "enable", ) ), ) alias.url = ( "/media" => "/home/user/django/contrib/admin/media/", ) url.rewrite-once = ( "^(/media.*)$" => "$1", "^/favicon\.ico$" => "/media/favicon.ico", "^(/.*)$" => "/finderauto.fcgi$1", ) index-file.names = ( "index.php", "index.html", "index.htm", "default.htm", " index.lighttpd.html" ) url.access-deny = ( "~", ".inc" ) static-file.exclude-extensions = ( ".php", ".pl", ".fcgi" ) ## Use ipv6 if available #include_shell "/usr/share/lighttpd/use-ipv6.pl" dir-listing.encoding = "utf-8" server.dir-listing = "enable" compress.cache-dir = "/var/cache/lighttpd/compress/" compress.filetype = ( "application/x-javascript", "text/css", "text/html", "text/plain" ) include_shell "/usr/share/lighttpd/create-mime.assign.pl" include_shell "/usr/share/lighttpd/include-conf-enabled.pl" If any of you could help me finding out where I lose these 3 or 4 s. I would much appreciate. Thanks in advance!

    Read the article

  • Apache htaccess Zend redirecting excepting some fodlers

    - by Frederick Marcoux
    Last week, I remade all of my website using the famous Zend Framework and now, I'm starting worrying about it... I'm trying to make an administration zone within a subfolder (also ZF) and a API Zend Application for my mobile Android application. The problem is: I rewrited all routes im my principal website, so now it always search for a route when I go to a subfolder. There's my root folder .htaccess: RewriteEngine On RewriteRule ^.htaccess$ - [F] RewriteCond %{REQUEST_URI}!^/api/ RewriteCond %{REQUEST_URI}!^/admin/ RewriteRule ^public/.*$ /public/index.php [NC,L] RewriteRule ^(.*)$ /public/$1 [NC,L] The way I want it is that: URL: {domain}/ => ./public/index.php (where's my current ZF app) URL: {domain}/[admin|api] => ./[admin/|api]/public/index.php (the others app) {domain} = my TLD; [admin|api] the requested folder So, in simple: Request = /api => /api Request = /admin => /admin Request = {anything else} => /public/index.php I searched a lot on SO and also on Google but I didn't find anything working -_-

    Read the article

  • how to send only selected chebox values to the next page using jquery

    - by kumar
    Hello friends, I am using this code to check wheather my checkbox is checked or not.. $('#btnMassEdit').click(function() { $('#ExceptionDetails input[type=checkbox]').each(function() { if ($(this).attr('checked')) { $('#specialist-tab').tabs('url', 3, '<%=Url.Action("getmasseditexceptions", "Expense", new { @GUI_SPEC_STAT_DSPL = GUI_SPEC_STAT_DSPL, @C_EXCPT_CATG = C_EXCPT_CATG, @C_EXCPT_TYPE = C_EXCPT_TYPE })%>').tabs('enable', 3).tabs('select', 3); return false; } else { alert("please select atleast one exception"); return false; } }); }); I am getting the exceptions but i need only which ever is checkecd i need to send it next page.. but here its only checking for first exception and sending all the other exceptin even that is not checked.. thanks

    Read the article

  • GWT problem wiht htmlunit

    - by ihtram
    i have a gwt url and i am trying to get next page by clicking a button. that button is an image. but when we click that button i got blank page. that url is: http://www.ichotelsgroup.com/redirect?brandCode=hi&regionCode=1&localeCode=en&path=asearch&errorURL=/h/d/6c/1/en/rates&successURL=/h/d/6c/1/en/rates/BOSGC&availabilitySearchSuccessURL=/h/d/6c/1/en/rates/BOSGC?ias=y&actionName=availabilitySearch&hotelCode=BOSGC&checkInDate=2&checkInMonthYear=62010&checkOutDate=6&checkOutMonthYear=62010&numberOfAdults=1&numberOfChildren=0&numberOfRooms=1&smokingPreference=3&secure=false&rateTypeCodes=6CBARC&rateChangePeriod=&_IATAno=99609020&cm_mmc=mdpr-_-kayak-_-USCSR-_-BOSGC i am trying to click "view rates button"..

    Read the article

  • Can we change <input type="file"> style?

    - by learner.php
    I tried to change the HTML form, input type file. Here is my code: HTML, form id = form <input class="upload_file" type="file" id="file" name="file" /> .CSS I tried both: .upload_button{ background: url('../images/upload_btn_bg.png') no-repeat; width: 200px; height: 40px; } #form input[type=file]{ background: url('../images/upload_btn_bg.png') no-repeat; width: 200px; height: 40px; } None of both of those methods works. I did see from some website, like facebook, youtube, google or twitter, they have different style. Wonder how they do it.

    Read the article

  • Visual Studio Snippets: How to reference an assembly that is not in the GAC

    - by user334220
    Hi, I have a 3rd party non-signed assembly that I want to reference in several projects. So I created a snippet to add the reference and the relative imports I tried the following, and several variations with full paths, without file:// etc, to no avail. Any ideas? ... <Snippet> <References> <Reference> <Assembly>MyAssemly.dll</Assembly> <Url>file://C:\Program Files\MyProduct</Url> </Reference> </References> <Imports> <Import> ...

    Read the article

  • How to Send and Receive XML request to another ASP classic page?

    - by SH
    I want to send an XML to another Asp Classic page on the same domain. i am using following code for sending XMl url = "http://localhost/api/xmlget.asp" information = "ColtTaylor100" Set xmlhttp = server.Createobject("MSXML2.ServerXMLHTTP") xmlhttp.Open "POST", url, false xmlhttp.setRequestHeader "Content-Type", "text/xml" xmlhttp.send information And i have setup xmlget.asp with following code to receive XML: Dim xmlDoc Dim userName set xmlDoc=Server.CreateObject("Microsoft.XMLDOM") xmlDoc.async="false" xmlDoc.load(Request) I run the code but do not see any reflection, how would i know? And if it is successful I want to know the xml and i dont know exact property to load from xmlDoc!

    Read the article

  • how to get key value of array with curl (php)

    - by Vierri
    Hello I want to make use of an API but it print alot of info and i don't know how i can get a few key values of the array. <?php $query = "SELECT * FROM kvk WHERE adres='Wit-geellaan 158'"; $host = "http://api.openkvk.nl/php/"; $url = $host ."/". rawurlencode($query); $curl = curl_init(); curl_setopt($curl, CURLOPT_FOLLOWLOCATION, 1); curl_setopt($curl, CURLOPT_URL, $url); curl_setopt($curl, CURLOPT_HEADER, 0); curl_exec($curl); curl_close($curl); ?> Is my php script and it shows array(array("RESULT"=>array("TYPES"=>array("int","bigint","varchar","varchar","varchar","varchar","varchar","int","int","smallint","smallint","int"),"HEADER"=>array("id","kvk","bedrijfsnaam","adres","postcode","plaats","type","kvks","sub","bedrijfsnaam_size","adres_size","verhuisd"),"ROWS"=>array(array("1303095","271242250000","Schoonmaakbedrijf Regio","Wit-geellaan 158","2718CK","Zoetermeer","Hoofdvestiging","27124225","0","23","16","0"))))) Thanks in advance Greetings, Vierri

    Read the article

  • Removing the last character of a string IF it is $variable

    - by KeenLearner
    Hi there, I've made a little script to convert titles into url friendly things. ie: 'I am a title' becomes 'I_am_a_title' My script basically goes through and turns spaces, apostrophes, commas etc etc into an underscore. The problem is, sometimes my url's end up like this: 'i_am_a_title_' with a trailing underscore... So i figure, add a little bit to go through and search to see if the last character is an underscore on the final result, and if it is, then swap it. I looked into the strrchr() function but I seem to be hitting a wall of my own understanding. How is this sort of thing accomplished?

    Read the article

  • Combining Content Data in Google Analytics

    - by David Csonka
    When I first start one of my Wordpress blogs, I had the permanent URL for each post include the date of posting. The slug format looked like this: /blog/2010/01/25/this-is-my-article/ Later on, I changed it so that the date was not included in the permanent URL, like this: /blog/this-is-my-article/ and setup a redirect plugin to make sure that users would get to the page they wanted until the site was re-indexed. In Google Analytics, when I review the stats for content I now have multiple records for what is essentially the same page. ie: Top Content List: 45 Pageviews- /blog/this-is-my-article/ 24 Pageviews- /blog/2010/01/25/this-is-my-article/ 33 Pageviews- /blog/some-other-article/ Is there any way to combine those records somehow?

    Read the article

  • problem in playing mp4 video in safari

    - by Codiator
    I have a particular link to a video file in server. when i load the safari through [[UIApplication sharedApplication] openURL:[NSURL URLWithString:@"http://mydomain/category/2.mp4"]]; simulator pops out an alert message saying that "Cannot Play MOVIE.. Server is not correctly configured"....... Even I tried using the mediaPlayer framework - MPMoviePlayerController and loading it with th e url-"http://mydomain/category/2.mp4" but it didnt play out. when i paste the same url in the 10.5 leopards safari it plays out smoothly.. What may be the reason behind it.?

    Read the article

  • grailsApplication not getting injected in a service , Grails 2.1.0

    - by vijay tyagi
    I have service in which i am accessing few configuration properties from grailsApplication I am injecting it like this class MyWebService{ def grailsApplication WebService webService = new WebService() def getProxy(url, flag){ return webService.getClient(url) } def getResponse(){ def proxy = getProxy(grailsApplication.config.grails.wsdlURL, true) def response = proxy.getItem(ItemType) return response } } When i call getProxy() method, i see this in tomcat logs No signature of method: org.example.MyWebService.getProxy() is applicable for argument types: (groovy.util.ConfigObject, java.lang.Boolean) values: [[:], true] Possible solutions: getProxy(), getProxy(java.lang.String, boolean), setProxy(java.lang.Object) which means grailsApplication is not getting injected into the service, is there any alternate way to access configuration object ? according to burtbeckwith's post configurationholder has been deprecated, can't think of anything else. Interestingly the very same service works fine in my local IDE(GGTS 3.1.0), that means locally grailsApplication is getting injected, but when i create a war to deploy to a standalone tomcat, it stops getting injected.

    Read the article

  • INSERT SQL in Java

    - by Pierre
    Hello. I have a Java application and I want to use SQL database. I have a class for my connection : public class SQLConnection{ private static String url = "jdbc:postgresql://localhost:5432/table"; private static String user = "postgres"; private static String passwd = "toto"; private static Connection connect; public static Connection getInstance(){ if(connect == null){ try { connect = DriverManager.getConnection(url, user, passwd); } catch (SQLException e) { JOptionPane.showMessageDialog(null, e.getMessage(), "Connection Error", JOptionPane.ERROR_MESSAGE); } } return connect; } } And now, in another class I succeeded to print my values but when I attempt to insert a value nothing is happening ... Here's my code : try { Statement state = SQLConnection.getInstance().createStatement(ResultSet.TYPE_SCROLL_INSENSITIVE,ResultSet.CONCUR_READ_ONLY); Statement state2 = SQLConnection.getInstance().createStatement(ResultSet.TYPE_SCROLL_INSENSITIVE,ResultSet.CONCUR_UPDATABLE); state2.executeUpdate("INSERT INTO table(field1) VALUES (\"Value\")"); // Here's my problem ResultSet res = state.executeQuery("SELECT * FROM plateau");

    Read the article

  • F# function calling syntax confusion

    - by Daniel
    I have a piece of code: links |> Seq.map (fun x -> x.GetAttributeValue ("href", "no url")) Which I wanted to rewrite to: links |> Seq.map (fun x -> (x.GetAttributeValue "href" "no url")) But the F# compiler doesn't seem to like that. I was under the impression that these two function calls were interchangeable: f (a, b) (f a b) The error that I get is: The member or object constructor 'GetAttributeValue' taking 2 arguments are not accessible from this code location. All accessible versions of method 'GetAttributeValue' take 2 arguments. Which seems amusing, as it seems to indicate that it needs what I'm giving it. What am I missing here?

    Read the article

  • Which Java Web Framework allows Cross-Domain Javascripting (http proxy) ?

    - by snsd
    So just a quick intro, I am starting to explore Vaadin, and it's absolutely perfect. Previously, I was juggling PHP, Perl, Ruby, and Jquery for designing rich client web application. It didn't work out too well, as I've burnt out from trying to fix cross browser issues (aka get-it-to-work-on-IE-damn-it), handling server-side, client-side, and building a robust communication between the two tier had lot of code not related to application logic....by the time I was burnt out, only tiny bit of application logic was implemented. Vaadin seems like the answer to my problem as it only requires Java and built on top of GWT. However, I am curious how I can incorporate Cross-Domain Javascripting ? Back in LAMP environment, I had a CGI proxy script that loaded external URL, and injected JS into the proxy-loaded page. I used the CGI proxy script, as it rendered Javascript of the external URL well. Is there a class or package for Java or a specific Java web framework similiar to Vaadin that makes this possible ? Thank you.

    Read the article

  • Why doesn't Google OpenID provider work with PHP-OpenId on my server?

    - by Steven Devijver
    Hey, I'm using PHP-OpenId 2.1.3 which I've unzipped on my server here (this is the consumer example that comes with PHP-OpenId). When I enter the Google OpenId url (https://www.google.com/accounts/o8/id) and submit I get a blank screen. When I try the exact same example code on the PHP-OpenId website here with the same URL it works fine. I don't understand what I'm doing wrong. The only thing I can think of is that somehow Google does not want to work with my server. Any ideas how to make this work? Thanks

    Read the article

  • how to link static cells to Outlet/Actions - E.G tap the call cell to call the number

    - by holtii
    The code I have. By the way, I can't get Call to work and Website does not open either! - (void)tableView:(UITableView *)tableView didSelectRowAtIndexPath:(NSIndexPath *)indexPath { NSString *urlToOpen = @""; if( indexPath.section == 0 ){ // call number urlToOpen = @"tel:442074036933"; } else if( indexPath.section == 1 ){ // open website urlToOpen = @"http://www.designmuseum.org"; } else { // open address urlToOpen = @"http://maps.apple.com/maps?daddr=Design+Museum+London"; } [[UIApplication sharedApplication] openURL:[NSURL URLWithString:urlToOpen]]; NSString *destinationAddress = [NSString stringWithFormat:@"%@+%@+%@", [address street], [address city], [address country]]; NSString *sourceAddress = [LocalizedCurrentLocation currentLocationStringForCurrentLanguage]; NSString *url = [NSString stringWithFormat:@"http://maps.apple.com/maps?saddr=%@&daddr=%@", [sourceAddress stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding], [destinationAddress stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding]]; [[UIApplication sharedApplication] openURL:[NSURL URLWithString:url]]; I need to add destination address which for my App is = 28 Shad Thames, London, United Kingdom. Which format to write it in? because I cant get it to work and really need to sort this problem of my app real quick

    Read the article

  • Using Wordpress as a CMS to a site AND blog (two completely different layouts for each). Duplicate i

    - by Somebody still uses you MS-DOS
    I'm going to create a website using Wordpress static pages feature. It's going to have a menu for all the created pages. A blog is going to be created as well. This blog has a completely different layout/menu from the main site, but within the same domain: "http://www.domain.com" is the website url, and "http://www.domain.com/blog/" is the blog url. I was thinking of installing two different Wordpress instances: /var/www/public_html/ and /var/www/public_html/blog/. Although it's a simple solution, users are going to be duplicated: if you change password in one system, you need to change in the other. So, I would like to know from you which other approaches are possible: create a "dynamic" theme (call a theme when in root domain, another whern /blog - dont even know if this is possible), or for example a plugin to syncronize users from both instances? Does Wordpress MU solve this problem for me? Thanks!

    Read the article

  • How to get a site screenshot quickly using PHP?

    - by yuli chika
    I want to create a web directory site, and I need to get these site screenshots. How to get a site screenshot quickly using PHP? I tried IECAPT,webscreencapture, khtml2png, but they are all slowly. And they all get screenshot one url by one url. Is IECAPT depends on a ie browser? if it is, why it can not open many ie tags so that work at the same time? Is there anyone can recommend me a PHP screenshots software using online? according to my above requirements? Thank you.

    Read the article

< Previous Page | 340 341 342 343 344 345 346 347 348 349 350 351  | Next Page >