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  • How do I start working as a programmer - what do I need?

    - by giorgo
    Hello, i am currently learning Java and PHP as I have some projects from university, which require me to apply both languages. Specifically, a Java GUI application, connecting to a MySQL database and a web application that will be implemented in PHP/MySQL. I have started learning the MVC pattern, Struts, Spring and I am also learning PHP with zend. My first question is: How can I find employment as a programmer/software engineer? The reason I ask is because I have sent my CV into many companys, but all of them stated that I required work experience. I really need some guidance on how to improve my career opportunites. At present, I work on my own and haven't worked in collaboration with anyone on a particular project. I'm assuming most people create projects and submit them along with their CVs. My second question is: Everyone has to make a start from somewhere, but what if this somewhere doesn't come? What do I need to do to create the circumstances where I can easily progress forward? Thanks

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  • One good reason for a rewrite

    - by Supermighty
    I have a personal web project I cut my teeth on learning how to program. I wrote it in PHP and learned as I went. I eventually I re-factored it to use MVC and removed all mixing of php/html. Right now it has no users, save myself, and it makes no money. I have a strong desire to rewrite the entire app. Which really isn't that large of an app. I have a lot of reasons why I should not rewrite it. I know that I should move forward. It's a working app now and it will only set me back to rewrite it. But I can't shake this feeling that I would be better off using a different programming language in the long run. That I'd enjoy it more. That I'd feel comfortable with it. I feel like my one good reason to rewrite my app is that I have a gut feeling that I should. PHP seems like a hack thrown together. I want to use a language that feels more elegant to me. Any feedback you have would be welcome.

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  • how to install OpenSSL in windows 7 and also how to check, its enabled or not?

    - by Andy
    how to install OpenSSL in windows 7 and also how to check, its enabled or not? I currently run php through the command line locally not on a server. Thanks I recently installed php 5.2.17 I ran a program which connect with a https server and I got the following error Notice: file_get_contents(): Unable to find the wrapper "https" - did you forget to enable it when you configured PHP? in C:\java\newsweaver-api-v2\simple\list- tags.php on line 30 I added extension=php_openssl.dll to php.ini but I'm wondering is openssl native to php 5.2.17 or do I need to download an extntion. Thanks

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  • CMS and Databases vs. DIY

    - by hozza
    I have been programming for many years now, primarily in PHP and the like and would consider myself an intermediate programmer. Some of my online projects have now gone global and very widely used, i am now in deep thought about scalability etc. All of my systems so far are written in PHP, no known database structure such as MySQL etc. Instead our databases use an 'operating system style' method of storing information, files and folders if you will. We also do not use any outside/third-party software or CMS, so far this has work out extremely well. Most people, when they hear about the way we do things, criticize and say that is an idiotic idea but normally after seeing our systems in more dept are converted to our way of doing things. Is it really that bad to not use a standard databasing systems and only using the one (slightly heavier than others) language of PHP? How well on the face of it will this kind of setup scale? N.B. Our systems include things such as account and user management, documentation development and task/project managing.

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  • Remember me or not?

    - by taeja87
    I was told to post this on webmasters instead of stackoverflow. Is it safe to have the remember me feature? Would it be somewhat safe (knowing it won't be 100% safe) to allow users to close their browser and come back still logged in? I am not exacting sure which way I should go after reading different things about safety. I learned about session fixation and implemented security to add more protection. From experience, if remember me is checked then only your username/email appears and requires you to re-enter your password. Other sites allow you to come in and out as much as you way without logging out after the browser has closed. If it is safe, what is the current best way of implementing remember/stay logged in? http://stackoverflow.com/questions/3531377/best-practise-for-remember-me-feature http://stackoverflow.com/questions/5087969/what-is-the-code-for-stay-logged-in-or-remember-me-while-user-login-in-php http://bytes.com/topic/php/answers/881197-stay-logged-remember-me-php-sessions-cookies http://security.stackexchange.com/questions/41/good-session-practices Also: The site I am working on is email & password login type.

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  • Drupal7 doesn't detect MySQL on CentOS, but Wordpress3 does?

    - by jyaworski
    Hey guys. I'm running CentOS 5.5 here with Apache2, PHP5, and MySQL 5. My wordpress install on the same system runs perfectly, but the drupal7 install script only detects SQLite. The mysql module is enabled in php.ini, so that isn't the problem. Do you think it could be something with Drupal 7, or my PHP install? I tested it on localhost (I'm essentially running ArchLinux with Apache) and it installs just fine. I don't see a difference between my local php.ini and my server php.ini. I get this when accessing install.php on the server. SQLite The type of database your Drupal data will be stored in. Your PHP configuration only supports a single database type, so it has been automatically selected. Edit: The mysql PDO module is installed already.

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  • Is it possible to keep only one Database for both web and desktop applications?

    - by B4NZ41
    I'm experiencing a trouble with my business model, let me explain better. I'm developing a software for 1 year and few months, it's for the food industry, more exactly a software to: Delivery, Take Way, Table Reservation, POS, Accounts Payable and Receivable, Prints(receipt), Kitchen Monitors Orders, Customers Orders Control and Fiscal Area. Well, I had separated the software mainly in two areas, one is web area and the other is desktop area (Used by Admins only) and local installed. 1 - Web Area (Basically do the follow:) Show Catalog with the products Customers Make Orders Customers Pay for the Orders etc ... as mentioned above 2 - Desktop Area Manage Orders Manage Customers Manage Suppliers Manage Accounts Payable and Receivable etc ... as mentioned above The web area is hosted in an online web server (scripts and database are online). The Desktop area is hosted locally in a Linux machine with a local database and local scripts files. My question is: Is it possible to keep only one Database for both applications? If YES, please what is the best approach? Follow my technical specification environment Database: Actually I have two databases working and I would love to keep only one. Operating System: Linux (Kernel 2.6.X and above) or Windows (XP and above) For the Web Area Apache, PHP, Python, Java Script, Shell Script and MySQL. For the Desktop Area: PHP-GTK2, Apache, PHP, MySQL and Shell Script.

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  • Sending two arrays using ajax post request

    - by sachin taware
    I am working on a filter functionality using ajax/jquery and php/mysql.I have two sets of check boxes 1)=for Regions 2)=for Localities.The filter is similar to the one here http://www.proptiger.com/property-in-pune-real-estate.php I want to send the values of both the check boxes to filter the records.The filter for localities will be locally filtered on the selection of a region check box.I have got it to work upto some extent This is called on the first set of check boxes. Html <div class="locality"> <input type="checkbox" id="checkbox1" class="checkbox1" value="<?php echo $suburb['suburb_name']?>" name="Suburb_check[]" onClick="changeResults();" onChange="" ><?php echo $suburb['suburb_name']?> <span class="grey">(<?php echo $suburb['total']?>)</span> </div> <?php }?> Javascript/Jquery function changeResults(){ var data = { 'venue[]' : []}; $("input:checked").each(function() { var chck1 = $(this).val(); //alert(chck1); data['venue[]'].push($(this).val()); }); $.ajax({ type : 'POST', url : 'process.php', data : data, success : function(data){ $('#project_section').html(data); // replace the contents coming from php file } }); $.ajax({ type : 'POST', url : 'loadLocality.php', data : data, success : function(data){ document.getElementById("searchLoader").style.display = 'block'; $('#localityList').html(data); // replace the contents coming from php file // alert(data); document.getElementById("searchLoader").style.display = 'none'; } }); } This is the second set of chck boxes with Localities <div class="locality" id="localities"> <input type="checkbox" onClick="changeLocality();" id="1" value="<?php echo $locality['locality_name'];?>" name="Locality_check[]"><?php echo $locality['locality_name'];?> <span class="grey">(<?php echo $locality['total'];?>)</span> </div> I have called a function similar to the above one and posted it to a different page. Here is the second chck box function: function changeLocality(){ var dataLocality = {'locality[]' : []}; $("input:checked").each(function() { var chcklocal = $(this).val(); //alert(chcklocal); dataLocality['locality[]'].push($(this).val()); }); $.ajax({ type : 'POST', url : 'processLocality.php', data : dataLocality, success : function(dataLocality){ // document.getElementById("newloader").style.display ="block"; $('#project_section').html(dataLocality); // replace the contents coming from php file //alert('data'); // document.getElementById("newloader").style.display ="none"; } }); } But,when I select a region box and then a locality box and then deselect the region,I also get the previous locality value in the region array(name of the array is venue)I want only regions to go in the venue array and regions+localities in the locality array.Actually,if I deselect the region subsequent locality value should also be removed from the array.Also,eventhough I am posting them to different pages the region page holds the locality values.I am stuck as not much of JQUERY knowledge. Went through posts,but was not able to fix it.Any help would be appreciated. EDIT I get an array when I check the first set of chck boxes,and also filter the records using above functions. Array ( [venue] => Array ( [0] => Pune East [1] => Pune West [2] => Pune North [3] => Pune South ) )

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  • jQuery .live fireing multiple times!

    - by cstrzelc
    Greetings Guru's, This is a little hard to explain, but I'll give it a shot. I have a quick question regarding to the .live() function in JQuery. I'm going to simplify the example here. I have a page "index.php" that has a container "#display_files_container" which is populated with anchor links that are generated dynamically by a different page "process.php". The links are loaded into that same <div> when those links are selected based on the attributes of that link. See Examples: INDEX.PHP <html> <head><title>index.php</title> <!-- this function below loads process.php and passes it the dirid variable via post. I then use this post variable inside of process.php to pull other links from the database --> <script language="text/javascript"> $('.directory').live("click", function() { $('#display_files_container').load('plugins/project_files/process.php', {dirid: $(this).attr('dirid')}); }); </script> </head> <?php /*This code initial populates the link array so we have the first links populated before the users clicks for the first time*/ some code to fetch the $current_directory_list array from the database initially.... >? <body> <div id='display_files_container'> <?php /*Cycle through the array and echo out all the links which have been pulled from DB*/ for($i=0;$i<$current_directory_count;$i++) { echo "<a href='#' class='directory' dirid='".$current_directory_list[$i]['id']." '>".$current_directory_list[$i]['directory_name']. "</a> "; } ?> </div> </body> </html> PROCESS.PHP this file includes code to populate the $current_directory_list[] array from the database based on the post variable "$_POST['dirid']" that was sent from the .click() method in index.php. It then echo's the results out and we display them in the #display_files_container container. When you click on those links the process repeats. This works..... you can click though the directory tree and it loads the new links every time. However, it seems to want to .load() the process.php file many times over for one click. The number of times process.php is loaded seems to increase the more the links are clicked. So for example you can click on a link and firebug reports that process.php was loaded 23 times..... Eventually I would imagine I would record a stackoverflow. Please let me know if you have any ideas. Are there any ways that I can assure that .live() loads the process.php file only once? Thanks, -cs

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  • Wordpress how to retrieve the post id once its been reset in the page

    - by Scott B
    I'm working with a script in which the postid of the page has been reset via a script include. How can I retrieve the actual true post id and reset its value once it has been changed via script? Here is the script that I'm referring to. Somewhere in there, the postid is being reset so that the page's the_content() call is no longer pulling the current page being viewed. <?php //$featpages = get_option('woo_slider_pages_landing'); $featpages = '579,584,537'; $featarr=split(",",$featpages); $featarr = array_diff($featarr, array("")); $i = 1; foreach ( $featarr as $featured_tab ) { query_posts('page_id=' . $featured_tab); while (have_posts()) : the_post(); ?> <div class="featured-slide" id="slide-<?php echo $i; $i++; ?>" <?php if($i >=3 ){echo 'style="display:none"';} ?>> <div class="text"> <h2><?php if ( get_post_meta($post->ID, "page_desc", $single = true) <> "" ) { echo get_post_meta($post->ID, "page_desc", $single = true); } else { the_title(); } ?></h2> <p><?php if ( get_post_meta($post->ID, "page_excerpt", $single = true) <> "" ) { echo get_post_meta($post->ID, "page_excerpt", $single = true); } else { the_excerpt(); } ?></p> <?php if ( get_post_meta($post->ID, "link_text", $single = true) <> "" and get_post_meta($post->ID, "link_link", $single = true) <> "" ) { ?> <p><a href="<?php echo get_post_meta($post->ID, "link_link", $single = true); ?>" title="<?php echo get_post_meta($post->ID, "link_text", $single = true); ?>"><?php echo get_post_meta($post->ID, "link_text", $single = true); ?></a></p> <?php } ?> </div><!-- /.text --> <?php if ( get_post_meta($post->ID, "image", $single = true) <> "" ) { ?> <div class="image"> <img src="<?php echo get_post_meta($post->ID, "image", $single = true); ?>" alt="<?php the_title(); ?>" class="featured" /> </div><!-- /.image --> <?php } ?> </div><!-- /.featured-slide --> <?php endwhile; } //endforeach ?>

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  • Hiding tables that have no data to display.

    - by Kinyanjui Kamau
    Hi Guys, I have this css styling and was wondering what I need to change in order to collapse/hide html tables that are empty. The style: <style> #search_settings { position:relative; height:25px; width:500px; } #users_table_results { border-collapse:separate; empty-cells:hide; } #events_table_results { border-collapse:separate; empty-cells:hide; } #establishments_table_results { border-collapse:separate; empty-cells:hide; } </style> My HTML: <div id="search_settings"> <table width="500" border="0"> <tr> <td height="20" class="heading_text_18">Search results</td> </tr> </table> <table id="users_table_results" max-width="500" name="users" border="0"> <tr> <td width="50" height="50"><a href="#profile.php"><img src="Images/<?php echo $row_result_users['picture_thumb_url']; ?>" border="0" height="50" width="50"/></a></td> <td width="150" class="ordinary_text_12"><?php echo $row_result_users['user_first_name']; ?></td> <td width="150" class="ordinary_text_12"><?php echo $row_result_users['user_last_name']; ?></td> <td width="150" class="ordinary_text_12"><?php echo $row_result_users['username']; ?></td> </tr> </table> <table id="events_table_results" width="500" name="events" border="0"> <tr> <td width="50" height="50"><a href="#profile.php"><img src="Images/<?php echo $row_event['event_thumb_url']; ?>" border="0" height="50" width="50"/></a></td> <td width="150" class="ordinary_text_12"><?php echo $row_event['event_name']; ?></td> <td width="150" class="ordinary_text_12"><?php echo $row_event['event_venue']; ?></td> <td width="150" class="ordinary_text_12"><?php echo $row_event['event_date']; ?></td> </tr> </table> <table id="establishments_table_results" width="500" name="establishments" border="0"> <tr> <td width="50" height="50"><a href="#profile.php"><img src="Establishment_Images/<?php echo $row_establishment['establishment_thumb_url']; ?>" border="0" height="50" width="50"/></a></td> <td width="150" class="ordinary_text_12"><?php echo $row_establishment['establishment_name']; ?></td> <td width="150" class="ordinary_text_12"><?php echo $row_establishment['location_name']; ?></td> <td width="150" class="ordinary_text_12"><?php echo $row_establishment['establishment_pricing']; ?></td> </tr> </table> </div> I would want it such that if there are no results for my events table, the table does not show(there is no blank space between search results where event results should be because border=0). Can you hide entire tables?

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  • php functions new php developers should be aware of

    - by John
    Can people suggest a list of common or popular php functions that new/junior programmers should be aware of so that they don't "re-invent-the-wheel" so to speak? For example, I've seen a lot of new coders try to write their own date parsing functions when a combination of date(), strtotime() and time() can do everything their looking for. Any other ones you guys want to add to this list? Thanks

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  • What can I send back to the browser while I wait for PHP execution?

    - by Matt Malesky
    So....I have a PHP page that involves a lot of backend execution, namely 'exec' calls to run shell commands on the host server. This can take upwards of a few minutes depending on the calls involved. (If you look below, each recursion through the exec calls is mounting a LUN; I'd like to sometimes do upwards of 100 per execution.) I'm curious on what I can do to send content back to the browser (and prevent it from timing out). <!DOCTYPE html> <html> <head> <title>sfvmtk</title> </head> <body> <?php // TEMPORARY VARIABLES FOR TESTING $hba = 'vmhba38'; $svip = '10.10.20.100'; $targets = array ( 0 => array ( 'iqn' => 'iqn.2010-01.com.sf:t5np.esxtest.41', 'account' => 'esx', 'isecret' => 'isecret00000', 'tsecret' => 'tsecret00000' ), 1 => array ( 'iqn' => 'iqn.2010-01.com.sf:t5np.esxtest2.42', 'account' => 'esx2', 'isecret' => 'isecret00001', 'tsecret' => 'tsecret00001' ) ); $hostname = $_REQUEST['hostname']; $username = $_REQUEST['username']; $password = $_REQUEST['password']; foreach ($targets as $ctarget) { exec('esxcli -s '.$hostname.' -u '.$username.' -p '.$password.' iscsi adapter discovery statictarget add -A '.$hba.' -a '.$svip.' -n '.$ctarget['iqn'], $out); exec('esxcli -s '.$hostname.' -u '.$username.' -p '.$password.' iscsi adapter target portal auth chap set -A '.$hba.' -a '.$svip.' -N '.$ctarget['account'].' -d uni -l required -n '.$ctarget['iqn'].' -S '.$ctarget['isecret'], $out); exec('esxcli -s '.$hostname.' -u '.$username.' -p '.$password.' iscsi adapter target portal auth chap set -A '.$hba.' -a '.$svip.' -N '.$ctarget['account'].' -d mutual -l required -n '.$ctarget['iqn'].' -S '.$ctarget['tsecret'], $out); } exec('vicfg-rescan --server '.$hostname.' --username '.$username.' --password '.$password.' '.$hba, $out); ?> </body> </html>

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  • Something is making my page perform an Ajax call multiple times... [read: I've never been more frust

    - by Jack Webb-Heller
    NOTE: This is a long question. I've explained all the 'basics' at the top and then there's some further (optional) information for if you need it. Hi folks Basically last night this started happening at about 9PM whilst I was trying to restructure my code to make it a bit nicer for the designer to add a few bits to. I tried to fix it until 2AM at which point I gave up. Came back to it this morning, still baffled. I'll be honest with you, I'm a pretty bad Javascript developer. Since starting this project Javascript has been completely new to me and I've just learn as I went along. So please forgive me if my code structure is really bad (perhaps give a couple of pointers on how to improve it?). So, to the problem: to reproduce it, visit http://furnace.howcode.com (it's far from complete). This problem is a little confusing but I'd really appreciate the help. So in the second column you'll see three tabs The 'Newest' tab is selected by default. Scroll to the bottom, and 3 further results should be dynamically fetched via Ajax. Now click on the 'Top Rated' tab. You'll see all the results, but ordered by rating Scroll to the bottom of 'Top Rated'. You'll see SIX results returned. This is where it goes wrong. Only a further three should be returned (there are 18 entries in total). If you're observant you'll notice two 'blocks' of 3 returned. The first 'block' is the second page of results from the 'Newest' tab. The second block is what I just want returned. Did that make any sense? Never mind! So basically I checked this out in Firebug. What happens is, from a 'Clean' page (first load, nothing done) it calls ONE POST request to http://furnace.howcode.com/code/loadmore . But every time you load a new one of the tabs, it makes an ADDITIONAL POST request each time where there should normally only be ONE. So, can you help me? I'd really appreciate it! At this point you could start independent investigation or read on for a little further (optional) information. Thanks! Jack Further Info (may be irrelevant but here for reference): It's almost like there's some Javascript code or something being left behind that duplicates it each time. I thought it might be this code that I use to detect when the browser is scrolled to the bottom: var col = $('#col2'); col.scroll(function(){ if (col.outerHeight() == (col.get(0).scrollHeight - col.scrollTop())) loadMore(1); }); So what I thought was that code was left behind, and so every time you scroll #col2 (which contains different data for each tab) it detected that and added it for #newest as well. So, I made each tab click give #col2 a dynamic class - either .newestcol, .featuredcol, or .topratedcol. And then I changed the var col=$('.newestcol');dynamically so it would only detect it individually for each tab (makin' any sense?!). But hey, that didn't do anything. Another useful tidbit: here's the PHP for http://furnace.howcode.com/code/loadmore: $kind = $this->input->post('kind'); if ($kind == 1){ // kind is 1 - newest $start = $this->input->post('currentpage'); $data['query'] = "SELECT code.id AS codeid, code.title AS codetitle, code.summary AS codesummary, code.author AS codeauthor, code.rating AS rating, code.date, code_tags.*, tags.*, users.firstname AS authorname, users.id AS authorid, GROUP_CONCAT(tags.tag SEPARATOR ', ') AS taggroup FROM code, code_tags, tags, users WHERE users.id = code.author AND code_tags.code_id = code.id AND tags.id = code_tags.tag_id GROUP BY code_id ORDER BY date DESC LIMIT $start, 15 "; $this->load->view('code/ajaxlist',$data); } elseif ($kind == 2) { // kind is 2 - featured So my jQuery code sends a variable 'kind'. If it's 1, it runs the query for Newest, etc. etc. The PHP code for furnace.howcode.com/code/ajaxlist is: <?php // Our query base // SELECT * FROM code ORDER BY date DESC $query = $this->db->query($query); foreach($query->result() as $row) { ?> <script type="text/javascript"> $('#title-<?php echo $row->codeid;?>').click(function() { var form_data = { id: <?php echo $row->codeid; ?> }; $('#col3').fadeOut('slow', function() { $.ajax({ url: "<?php echo site_url('code/viewajax');?>", type: 'POST', data: form_data, success: function(msg) { $('#col3').html(msg); $('#col3').fadeIn('fast'); } }); }); }); </script> <div class="result"> <div class="resulttext"> <div id="title-<?php echo $row->codeid; ?>" class="title"> <?php echo anchor('#',$row->codetitle); ?> </div> <div class="summary"> <?php echo $row->codesummary; ?> </div> <!-- Now insert the 5-star rating system --> <?php include($_SERVER['DOCUMENT_ROOT']."/fivestars/5star.php");?> <div class="bottom"> <div class="author"> Submitted by <?php echo anchor('auth/profile/'.$row->authorid,''.$row->authorname);?> </div> <?php // Now we need to take the GROUP_CONCATted tags and split them using the magic of PHP into seperate tags $tagarray = explode(", ", $row->taggroup); foreach ($tagarray as $tag) { ?> <div class="tagbutton" href="#"> <span><?php echo $tag; ?></span> </div> <?php } ?> </div> </div> </div> <?php } echo "&nbsp;";?> <script type="text/javascript"> var newpage = <?php echo $this->input->post('currentpage') + 15;?>; </script> So that's everything in PHP. The rest you should be able to view with Firebug or by viewing the Source code. I've put all the Tab/clicking/Ajaxloading bits in the tags at the very bottom. There's a comment before it all kicks off. Thanks so much for your help!

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  • How can I make this script output each categories item per category [closed]

    - by Duice352
    Ok so here is the deal currently this script outputs all the products in a parent category as well as the products in the child categories. What i would like to do is seperate the output based on child categories. All the child categories are in the array $children and the string $childs. The parent category is the first array element of $children with the following ones being the actual children. The category names are stored in the database $result as " $cat_name ". I want to first Display the cat_name then the products that fall in that category and then display the next child cat_name and items, ect. Any suggestions of how to manipulate the while loop that cylcles through the rows? <?php $productsPerRow = 3; $productsPerPage = 15; //$productList = getProductList($catId); $children = array_merge(array($catId), getChildCategories(NULL, $catId)); $childs = ' (' . implode(', ', $children) . ')'; $sql = "SELECT pd_id, pd_name, pd_price, pd_thumbnail, pd_qty, c.cat_id, c.cat_name FROM tbl_product pd, tbl_category c WHERE pd.cat_id = c.cat_id AND pd.cat_id IN $childs ORDER BY pd_name"; $result = dbQuery(getPagingQuery($sql, $productsPerPage)); $pagingLink = getPagingLink($sql, $productsPerPage, "c=$catId"); $numProduct = dbNumRows($result); // the product images are arranged in a table. to make sure // each image gets equal space set the cell width here $columnWidth = (int)(100 / $productsPerRow); ?> <p><?php if(isset($_GET['m'])){echo "You must select a model first! After you select your model you can customize your dragster parts.";} ?> </p> <p align="center"><?php echo $pagingLink; ?></p> <table width="100%" border="0" cellspacing="0" cellpadding="20"> <?php if ($numProduct > 0 ) { $i = 0; while ($row = dbFetchAssoc($result)) { extract($row); if ($pd_thumbnail) { $pd_thumbnail = WEB_ROOT . 'images/product/' .$pd_thumbnail; } else { $pd_thumbnail = 'images/no-image-small.png'; } if ($i % $productsPerRow == 0) { echo '<tr>'; } // format how we display the price $pd_price = displayAmount($pd_price); echo "<td width=\"$columnWidth%\" align=\"center\"><a href=\"" . $_SERVER['PHP_SELF'] . "?c=$catId&p=$pd_id" . "\"><img src=\"$pd_thumbnail\" border=\"0\"><br>$pd_name</a><br>Price : $pd_price <br> $cat_id - $cat_name"; // if the product is no longer in stock, tell the customer if ($pd_qty <= 0) { echo "<br>Out Of Stock"; } echo "</td>\r\n"; if ($i % $productsPerRow == $productsPerRow - 1) { echo '</tr>'; } $i += 1; } if ($i % $productsPerRow > 0) { echo '<td colspan="' . ($productsPerRow - ($i % $productsPerRow)) . '">&nbsp;</td>'; }

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  • PHP Form: After getting results adding a new table row when entering new information.

    - by Chris
    Hello, Although probarly quite simple, i cannot seem to find the following. The form takes certain data, and then represents the data in a table. Next step i click the hyperlink that takes me back to the form. Now my question is how exactly do i make it possible when filling in the same form again so both results are displayed in the same table? Then filling in a other form with data adds another row and so on. Regards. The code below (pardon me that it is not english). <?php session_start(); ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-Strict.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en"> <head> <title>ExpoFormulier</title> <body> <?php if (!empty($_POST)) { $standnaam = $_POST["standnaam"]; $oppervlakte = $_POST["oppervlakte"]; //value in the form van checkboxes op 1 zetten! $verdieping = isset($_POST["verdieping"]) ? $_POST["verdieping"] : 0; //if checkbox checked value 1 anders 0 $telefoon = isset($_POST["telefoon"]) ? $_POST["telefoon"] : 0; $netwerk = isset($_POST["netwerk"]) ? $_POST["netwerk"] : 0; if (is_numeric($oppervlakte)) { $_SESSION["standnaam"]=$standnaam; $_SESSION["oppervlakte"]=$oppervlakte; $_SESSION["verdieping"]=$verdieping; $_SESSION["telefoon"]=$telefoon; $_SESSION["netwerk"]=$netwerk; header("Location:ExpoOverzicht.php"); //verzenden naar ExpoOverzicht.php dmv header } else { echo "<h1>Foute gegevens, Opnieuw invullen a.u.b</h1>"; } } ?> <form action="<?php echo $_SERVER["PHP_SELF"]; ?>" method="post" id="form1"> <h1>Vul de gegevens in</h1> <table> <tr> <td>Standnaam:</td> <td><input type="text" name="standnaam" size="18"/></td> </tr> <tr> <td>Oppervlakte (in m^2):</td> <td><input type="text" name="oppervlakte" size="6"/></td> </tr> <tr> <td>Verdieping:</td> <td><input type="checkbox" name="verdieping" value="1"/></td> <!--value op 1 zetten voor checkbox! indien checked is value 1 --> </tr> <tr> <td>Telefoon:</td> <td><input type="checkbox" name="telefoon" value="1"/></td> </tr> <tr> <td>Netwerk:</td> <td><input type="checkbox" name="netwerk" value="1"/></td> </tr> <tr> <td><input type="submit" name="verzenden" value="Verzenden"/></td> </tr> </table> </form> Second File: <?php session_start(); ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-Strict.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en"> <head> <title>ExpoOverzicht</title> <meta http-equiv="content-type" content="text/html; charset=utf-8" /> <link href="StyleSheetExpo.css" rel="stylesheet" type="text/css" /> </head> <body> <h1>Overzicht van de ingegeven standen in deze sessie</h1> <?php $standnaam = $_SESSION["standnaam"]; $oppervlakte = $_SESSION["oppervlakte"]; $verdieping = $_SESSION["verdieping"]; $telefoon = $_SESSION["telefoon"]; $netwerk = $_SESSION["netwerk"]; $result1 = 0; //telkens declaren anders fout "undefined variable" $result2 = 0; $result3 = 0; $prijsCom = 0; $prijsVerdieping = 0; for ($i=1; $i <= $oppervlakte; $i++) { if($i <= 10) { $tarief1 = 1 * 100; $result1 += $tarief1; } if($i > 10 && $i <= 30) { $tarief2 = 1 * 90; $result2 += $tarief2; } if($i > 30) { $tarief3 = 1 * 80; $result3 += $tarief3; } } $prijsOpp = $result1 + $result2 + $result3; if($verdieping == 1) { $prijsVerdieping = $oppervlakte * 120; } if(($telefoon == 1) || ($netwerk == 1)) // eerst deze OR conditie of anders gebruikt de code alleen nog maar 20 { $prijsCom = 20; } if(($telefoon == 1) && ($netwerk == 1)) { $prijsCom = 30; } $totalePrijs = $prijsOpp + $prijsVerdieping + $prijsCom; echo "<table class=\"tableExpo\">"; echo "<th>Standnaam</th>"; echo "<th>Oppervlakte</th>"; echo "<th>Verdieping</th>"; echo "<th>Telefoon</th>"; echo "<th>Netwerk</th>"; echo "<th>Totale prijs</th>"; echo "<tr>"; echo "<td>".$standnaam."</td>"; echo "<td>".$oppervlakte."</td>"; echo "<td>".$verdieping."</td>"; echo "<td>".$telefoon."</td>"; echo "<td>".$netwerk."</td>"; echo "<td>".$totalePrijs."</td>"; echo "</tr>"; echo "</table>"; ?> <a href="ExpoFormulier.php">Terug naar het formulier</a> </body> </html> </body> </html>

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  • Export mysql database tables to php code to create same tables in other database?

    - by chefnelone
    How do I Export mysql database tables to php code so that it allows me to create and populate same tables in other database? I have a local database, I exported to sql syntax, then I get something like: CREATE TABLE `boletinSuscritos` ( `id` int(11) NOT NULL AUTO_INCREMENT, `name` varchar(120) NOT NULL, `email` varchar(120) NOT NULL, `date` timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP, PRIMARY KEY (`id`) ) ENGINE=MyISAM DEFAULT CHARSET=utf8 AUTO_INCREMENT=3 ; INSERT INTO `boletinSuscritos` VALUES(1, 'walter', '[email protected]', '2010-03-24 12:53:12'); INSERT INTO `boletinSuscritos` VALUES(2, 'Paco', '[email protected]', '2010-03-24 12:56:56'); but I need it to be: (Is there any way to export the tables in this way) $sql = "CREATE TABLE boletinSuscritos ( id int(11) NOT NULL AUTO_INCREMENT, name varchar(120) NOT NULL, email varchar(120) NOT NULL, date timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP, PRIMARY KEY ( id ) ) ENGINE=MyISAM DEFAULT CHARSET=utf8 AUTO_INCREMENT=3 )"; mysql_query($sql,$conexion); mysql_query("INSERT INTO boletinSuscritos VALUES(1, 'walter', '[email protected]', '2010-03-24 12:53:12')"); mysql_query("INSERT INTO boletinSuscritos VALUES(2, 'Paco', '[email protected]', '2010-03-24 12:56:56')");

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  • How to configure Apache2 to host Django and PHP on multiple domains simultaneously?

    - by Bert B.
    I have a VPS (Ubuntu 10.04) that hosts multiple domains, one of them being a CodeIgniter (PHP) web app. The others are just static websites, no fancy backend languages required. Well I am starting a new project and want to use Django. I have Django installed, mod_wsgi enabled in Apache2, but when I did the first steps on the documentation (https://docs.djangoproject.com/en/dev/howto/deployment/wsgi/modwsgi/) it seemingly overwrote my existing Apache2 configuration and served up the Django welcome page to all my domains. What should my httpd.conf file should look like so that it doesn't overtake all my domains.

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  • apache2 and php slow first load on Ubuntu VPS - something like mysqltuner but for apache?

    - by talkingnews
    Ubuntu 10.10 64 bit VPS, 512Mb dedicated RAM. Mysql tuned so that sqltuner is completely happy. Used RAM never above 350Mb out of the 493 available. Load never exceeds 1.04 or so. httpd.conf tuned as per all the guides for vps of that memory - amount of preforks, spares etc. But for the FIRST load a site after having not visited for a while, it's taking ages. First load: Parse Time: 3.576 - Number of Queries: 50 - Query Time: 0.019723195953369 Reload Parse Time: 0.096 - Number of Queries: 39 - Query Time: 0.0066126374511719 Subsequent reloads will be at this speed. htop shows two items as soon as I load that page for the first time: php-cgi /usr/sbin/apache2 -k start I'm using suPHP but I've tried fast-cgi and cgi. Stuck now, a weekend of tweaking has brought me nothing. Advice appreciated.

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  • Ideas for SVN/SQL/PHP/Linux Dev Enviroment Supporting Multiple Isolated Environments?

    - by jpganz18
    I am trying to create a "dev" for my users. In that environment they would access to their own account of PHPMyAdmin, SQL, Subversion and FTP which is not a big problem, but I would like to emulate like if each one would be in their own server. I mean so that they could change the PHP configuration (for example) and would be done only in its own environment. Any idea how to do this? Do I have to make something "special" at the installations of my server or something like that?

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  • What are some good, free tools to run automated security audits for PHP code?

    - by James Simpson
    I've been looking for some time now and have come up short. The most promising I found was Spike PHP, which seems to no longer work. I'm looking to scan my code for potential risks of SQL Injection, XSS, etc. I've gone through most of my code manually, but with a few hundred thousand lines of code, I'm sure I missed things. If possible, are there any tools that can be downloaded and analyze code on my local machine rather than installing to the live server (this isn't a requirement if not)?

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  • When did Red Hat start shipping PHP 5.3 with 5.x?!?

    - by Jason
    Okay this is a PSA more than a question because I know the answer: January 13, 2011. See: https://rhn.redhat.com/errata/RHEA-2011-0069.html Colour me surprised though, didn't hear anything about in the blogosphere until I got a Security Errata notice today. I have been using the REMI repo for this in the past but will switch over to the Red Hat blessed PHP 5.3. Don't down-vote me bro! I'll select as the best answer the source that broke the news first (other than Red Hat of course). People have wanted this for so long I'm just amazed that it's finally happened!

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  • Is it possible to upgrade PHP to 5.3 on a Centos Kloxo installation?

    - by Malachi
    I have a VPS running Centos with Kloxo on and I was wondering how I would upgrade the PHP to 5.3 - It's currently running 5.2.6. When I try and do a yum update I get the following errors: Resolving Dependencies --> Running transaction check --> Processing Dependency: libpq.so.4 for package: lxphp ---> Package postgresql-libs.i386 0:8.3.7-umask.7 set to be updated --> Finished Dependency Resolution lxphp-5.2.1-400.i386 from installed has depsolving problems --> Missing Dependency: libpq.so.4 is needed by package lxphp-5.2.1-400.i386 (installed) Error: Missing Dependency: libpq.so.4 is needed by package lxphp-5.2.1-400.i386 (installed) You could try using --skip-broken to work around the problem You could try running: package-cleanup --problems package-cleanup --dupes rpm -Va --nofiles --nodigest The program package-cleanup is found in the yum-utils package. Any help would be greatly appreciated.

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  • How do I install hiphop-php in CentOS 6?

    - by Dai
    I've been trying to install hiphop-php on CentOS 6 with no luck. I found an .rpm for it but it fails dependency checks on boost which fails to install because it depends on curl which fails to install because it can't overwrite /etc/lib64/libcurl.so.4 I can't remove the current curl version because half the system seems to depend on it. Has anybody had any luck doing this? It's driving me mad. I tried compiling from source but that's even more hellish and I really have no idea what I'm doing anyway.

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