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  • How do i convert a string to a JSON object in JQuery?

    - by Rob
    I have a string in my db I want to pull into my page and convert to a json object. [ {id: 1,title: "Long Event", start: new Date(2009, 5, 6, 14, 0),end: new Date(2009, 5, 11)}, {id: 2,title: "Repeating Event", start: new Date(2009, 5, 2)}, {id: 3,title: "Meeting", start: new Date(2009, 5, 20, 9, 0)}, {id: 4,title: "Click for Facebook", start: new Date(2009, 5, 27, 16),end: new Date(2009, 5, 29), url: "http://facebook.com/"} ] How can I do this using JQuery?

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  • How to copy and paste text from one page to another page using jquery?

    - by ischnura
    I have to copy repeatedly data (contact info such as name, surname, telephone...) from form A (page 1 in domain x.com) to form B (page 2 in domain y.com) I have been thinking about creating a chrome extension with the help of jquery to copy the data from form A, and inject it form B... I have a feeling that this is not the best way to solve this problem... What do you think is the best way to copy and paste data from pages in different domains?

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  • How can you use jQuery to make sIFR-replaced elements fade in?

    - by Sam Goldman
    This is what I currently have: // #content is visibility=hidden sIFR.replace(mix_bold, { selector: '#content p', onReplacement: function(fi) { $('#content').fadeIn("slow"); } }); The fade in happens, but for a split second the replaced flash movie appears before being hidden. Has anyone gotten this to work? I am using jQuery 1.2.6 and sIFR 3 r436. Tested in Safari 4 and FF 3. Thanks!

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  • How do I simulate a scrollbar click with jQuery?

    - by Ian Davis
    How do I simulate a scrollbar click with jQuery? So, if a user clicks on a div that says "scroll down," it'll be the exact same behavior as if he/she clicked on the down arrow of the browser's scrollbar. Using the current browser's behavior would be optimal, vs. doing something like $.browser.scrolldown(200,'fast'). Something like $.browser.triggerDownArrowOnScrollBar() would be sweet!

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  • How can call a JQuery function when it in side the from view (asp.net control)?

    - by ricky roy
    Hi, All I have a Span in side the Form view. I wanted to Call a Jquery Fucntion when the from load how can i do this? Thanks Waiting for your reply here is my code <asp:FormView ID="FormView1" runat="server" OnItemCommand="FormView1_ItemCommand"> <ItemTemplate> <asp:HiddenField ID="hidProductID" Value='<%#Eval("ProductID") %>' runat="server" /> <asp:HiddenField ID="hidCustomerID" Value='<%#Eval("CustomerID") %>' runat="server" /> <a href='<%=WinToSave.SettingsConstants.SiteURL%>WintoSave/AuctionProduct.aspx?id=<%#Eval("ProductID") %>'> <%#Eval("ProductName")%> </a> <br /> <img src='<%#Eval("ImagePath")%>' alt="Image No available" /> <br /> <asp:Label ID="lblTime" runat="server" Text='<%#Convert.ToDateTime(Eval("ModifiedOn")).ToString("hh:mm:ss") %>'></asp:Label> <span id='Countdown_<%#Eval("ProductID") %>' onload="GetTimeOnLoad('<%#Eval("ModifiedOn")%>','Countdown_<%#Eval("ProductID") %>');"></span> <br /> <asp:Label ID="lblFinalPrice" runat="server" Text='<%#Convert.ToDouble(Eval("FinalPrice")).ToString("#.00")%>'></asp:Label> <br /> <asp:Label ID="lblFullName" runat="server" Text='<%#Eval("FullName") %>'></asp:Label> <br /> <asp:Button ID="btnAddbid" Text="Bid" CommandName="AddBid" CommandArgument='<%#Eval("ID")%>' runat="server" /> </ItemTemplate> </asp:FormView> and following is my jquery code function GetTimeOnLoad(shortly,DivID) { var dt = new Date(shortly); alert(dt); alert(shortly); alert(DivID); var ProductDivID = "#" +DivID; alert(ProductDivID); $(ProductDivID).countdown({ until: dt, onExpiry: liftOff, onTick: watchCountdown, format: 'HMS', layout: '{hnn}{sep}{mnn}{sep}{snn}' }); } function liftOff(){}; function watchCountdown(){}; In above code I Used ' onload="GetTimeOnLoad('<%#Eval("ModifiedOn")%','Countdown_<%#Eval("ProductID") %');" but is not working

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  • How can i check if key is pressed during click event with jquery?

    - by daniel smith
    Hi, I would like to catch a click event with jquery and be able to tell if a key was pressed at the same time so i can fork within the callback function based on the keypress. for example: $("button").click(function() { if([KEYPRESSED WHILE CLICKED]) { do something... } else { do something different... } }); Does anyone know if this is possible at all or how it can be done if it is possible?

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  • Is it possible to return the "highlighted" (like Firebug) css selector or dom id with jquery?

    - by Jonathan
    Hi Folks, When you click the "Click an element on the page to inspect" arrow with FireBug, it puts a Blue Border around the target element, and also returns the DOM Id. I am building an application and that feature would be awesome to add. Be able to hover over elements and highlight the target, upon clicking return the DOM Id or CSS selector to the application. Is there a jquery plugin that does this magic? Some other smart way? Thanks!, Jonathan

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  • Jquery - Loading a page with .load and selector doesn't execute script?

    - by PirateKitten
    I'm trying to load one page into another using the .load() method. This loaded page contains a script that I want to execute when it has finished loading. I've put together a barebones example to demonstrate: Index.html: <html> <head> <title>Jquery Test</title> <script type="text/javascript" src="script/jquery-1.3.2.min.js"></script> <script type="text/javascript"> $(document).ready(function() { $('#nav a').click(function() { $('#contentHolder').load('content.html #toLoad', '', function() {}); return false; }); }); </script> </head> <body> <div id="nav"> <a href="content.html">Click me!</a> </div> <hr /> <div id="contentHolder"> Content loaded will go here </div> </body> </html> Content.html: <div id="toLoad"> This content is from content.html <div id="contentDiv"> This should fade away. </div> <script type="text/javascript"> $('#contentDiv').fadeOut('slow', function() {} ); </script> </div> When the link is clicked, the content should load and the second paragraph should fade away. However it doesn't execute. If I stick a simple alert("") in the script of content.html it doesn't execute either. However, if I do away with the #toLoad selector in the .load() call, it works fine. I am not sure why this is, as the block is clearly in the scope of the #toLoad div. I don't want to avoid using the selector, as in reality the content.html will be a full HTML page, and I'll only want a select part out of it. Any ideas? If the script from content.html was in the .load() callback, it works fine, however I obviously don't want that logic contained within index.html. I could possibly have the callback use .getScript() to load "content.html.js" afterwards and have the logic in there, that seems to work? I'd prefer to keep the script in content.html, if possible, so that it executes fine when loaded normally too. In fact, I might do this anyway, but I would like to know why the above doesn't work.

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  • jQuery - How can I temporarily disable the onclick event listener after the event has been fired?

    - by aldux
    How can I temporarily disable the onclick event listener, (jQuery preferred), after the event has been fired? Example: After the user clicks on the button and fires this function below, I want to disabled the onclick listener, therefore not firing the same command to my django view. $(".btnRemove").click(function(){ $(this).attr("src", "/url/to/ajax-loader.gif"); $.ajax({ type: "GET", url: "/url/to/django/view/to/remove/item/" + this.id, dataType: "json", success: function(returned_data){ $.each(returned_data, function(i, item){ // do stuff }); } }); Thanks a lot, Aldo

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  • Is there a jQuery widget equal to DOJO's TitlePane?

    - by Bill Caswell
    I like the visual behavior of the DOJO TitlePane widget, but it has too much other bunk for my purpose. http://dojotoolkit.org/reference-guide/dijit/TitlePane.html#dijit-titlepane Is anyone aware of a jQuery widget that provides the same ability to expose and hide content in a stacked manner with the little flippy-arrow, pane highlighting on mouse over, etc? An accordion does not accomplish my goal being able to have multiple panes open at the same time. Thanks in advance.

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  • Submiting a Form without Refreshing the page with jQuery and Ajax Not updating MySQL database.

    - by HEEEEEEELP
    I'm a newbie to JQuery and have a problem, when I click submit button on the form everything says registration was successful but my MYSQL database was not updated everything worked fine until I tried to add the JQuery to the picture. Can someone help me fix this problem so my database is updated? Thanks Here is the JQuery code. $(function() { $(".save-button").click(function() { var address = $("#address").val(); var address_two = $("#address_two").val(); var city_town = $("#city_town").val(); var state_province = $("#state_province").val(); var zipcode = $("#zipcode").val(); var country = $("#country").val(); var email = $("#email").val(); var dataString = 'address='+ address + '&address_two=' + address_two + '&city_town=' + city_town + '&state_province=' + state_province + '&zipcode=' + zipcode + '&country=' + country + '$email=' + email; if(address=='' || address_two=='' || city_town=='' || state_province=='' || zipcode=='' || country=='' || email=='') { $('.success').fadeOut(200).hide(); $('.error').fadeOut(200).show(); } else { $.ajax({ type: "POST", url: "http://localhost/New%20Project/home/index.php", data: dataString, success: function(){ $('.success').fadeIn(200).show(); $('.error').fadeOut(200).hide(); } }); } return false; }); }); Here is the PHP code. if (isset($_POST['contact_info_submitted'])) { // Handle the form. // Query member data from the database and ready it for display $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"SELECT users.*, contact_info.* FROM users INNER JOIN contact_info ON contact_info.user_id = users.user_id WHERE users.user_id=3"); $user_id = mysqli_real_escape_string($mysqli, htmlentities('3')); $address = mysqli_real_escape_string($mysqli, htmlentities($_POST['address'])); $address_two = mysqli_real_escape_string($mysqli, htmlentities($_POST['address_two'])); $city_town = mysqli_real_escape_string($mysqli, htmlentities($_POST['city_town'])); $state_province = mysqli_real_escape_string($mysqli, htmlentities($_POST['state_province'])); $zipcode = mysqli_real_escape_string($mysqli, htmlentities($_POST['zipcode'])); $country = mysqli_real_escape_string($mysqli, htmlentities($_POST['country'])); $email = mysqli_real_escape_string($mysqli, strip_tags($_POST['email'])); //If the table is not found add it to the database if (mysqli_num_rows($dbc) == 0) { $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"INSERT INTO contact_info (user_id, address, address_two, city_town, state_province, zipcode, country, email) VALUES ('$user_id', '$address', '$address_two', '$city_town', '$state_province', '$zipcode', '$country', '$email')"); } //If the table is in the database update each field when needed if ($dbc == TRUE) { $dbc = mysqli_query($mysqli,"UPDATE contact_info SET address = '$address', address_two = '$address_two', city_town = '$city_town', state_province = '$state_province', zipcode = '$zipcode', country = '$country', email = '$email' WHERE user_id = '$user_id'"); } if (!$dbc) { // There was an error...do something about it here... print mysqli_error($mysqli); return; } } Here is the XHTML code. <form method="post" action="index.php"> <fieldset> <ul> <li><label for="address">Address 1: </label><input type="text" name="address" id="address" size="25" class="input-size" value="<?php if (isset($_POST['address'])) { echo $_POST['address']; } else if(!empty($address)) { echo $address; } ?>" /></li> <li><label for="address_two">Address 2: </label><input type="text" name="address_two" id="address_two" size="25" class="input-size" value="<?php if (isset($_POST['address_two'])) { echo $_POST['address_two']; } else if(!empty($address_two)) { echo $address_two; } ?>" /></li> <li><label for="city_town">City/Town: </label><input type="text" name="city_town" id="city_town" size="25" class="input-size" value="<?php if (isset($_POST['city_town'])) { echo $_POST['city_town']; } else if(!empty($city_town)) { echo $city_town; } ?>" /></li> <li><label for="state_province">State/Province: </label> <?php echo '<select name="state_province" id="state_province">' . "\n"; foreach($state_options as $option) { if ($option == $state_province) { echo '<option value="' . $option . '" selected="selected">' . $option . '</option>' . "\n"; } else { echo '<option value="'. $option . '">' . $option . '</option>'."\n"; } } echo '</select>'; ?> </li> <li><label for="zipcode">Zip/Post Code: </label><input type="text" name="zipcode" id="zipcode" size="5" class="input-size" value="<?php if (isset($_POST['zipcode'])) { echo $_POST['zipcode']; } else if(!empty($zipcode)) { echo $zipcode; } ?>" /></li> <li><label for="country">Country: </label> <?php echo '<select name="country" id="country">' . "\n"; foreach($countries as $option) { if ($option == $country) { echo '<option value="' . $option . '" selected="selected">' . $option . '</option>' . "\n"; } else if($option == "-------------") { echo '<option value="' . $option . '" disabled="disabled">' . $option . '</option>'; } else { echo '<option value="'. $option . '">' . $option . '</option>'."\n"; } } echo '</select>'; ?> </li> <li><label for="email">Email Address: </label><input type="text" name="email" id="email" size="25" class="input-size" value="<?php if (isset($_POST['email'])) { echo $_POST['email']; } else if(!empty($email)) { echo $email; } ?>" /><br /><span>We don't spam or share your email with third parties. We respect your privacy.</span></li> <li><input type="submit" name="submit" value="Save Changes" class="save-button" /> <input type="hidden" name="contact_info_submitted" value="true" /> <input type="submit" name="submit" value="Preview Changes" class="preview-changes-button" /></li> </ul> </fieldset> </form>

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