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  • how to insert Link in to jquery grid column

    - by kumar
    Hello Friends, Can any one tell me how to insert link in to Jquery grid column,, that is I have a column with Edittype { name: 'Comments', index: 'Comments', editable: true, editype: 'textarea', editoptions: { rows: "2", cols: "10"} } I need to insert comments in to this.. so if I have link to click on the column so that some popup bubble will come there in the window to enter comments more like user friendly.. can anybody sujjests me on this.. Thanks

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  • Find git branch that got pushed to a bare repository.

    - by Senthil A Kumar
    Lets have 2 repositories, one containing the actual data repo and a bare repository which is loaded with deltas from the actual data repository by doing a git push from data repo to bare repo. Hope you have understood the model that am using here. Am creating clones by cloning the bare repo, and i will be pushing from the branches in my local clone to the branches in bare repository. When am pushing data from my branch to bare repo, the data is automatically synced to the data repo by a hook. The question i have - is there a way to find from which branch a code has come to the bare repo. I can see the source and target branch during a git push, but after pushing can i see from logs or other way to identify from which branch and repository the data has been pushed from? If there are 5 developers pushing to bare repo, can i find in the bare repo from which branch and clone a code is pushed?

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  • Xampp error on windows

    - by Deepak Kumar
    My problem is when i use xampp i see many error and when i use my web it has no error Notice: Undefined index: action in C:\xampp\htdocs\xyz\index.php on line 3 Notice: Undefined index: usNick in C:\xampp\htdocs\xyz\config.php on line 11 Notice: Use of undefined constant setname - assumed 'setname' in C:\xampp\htdocs\xyz\config.php on line 31 Notice: Use of undefined constant setname - assumed 'setname' in C:\xampp\htdocs\xyz\config.php on line 31 Notice: Undefined index: usNick in C:\xampp\htdocs\xyz\config.php on line 34 Notice: A session had already been started - ignoring session_start() in C:\xampp\htdocs\xyz\data.php on line 2 Notice: Undefined index: r in C:\xampp\htdocs\xyz\data.php on line 4 Notice: Undefined index: ucNick in C:\xampp\htdocs\xyz\data.php on line 8 I have tried many time changing things in Setting, Security, Privileges etc but nothing changed, I want to know if im missing something out Thanks

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  • how to remove IEnemurable in asp.net mvc

    - by kumar
    I have a view with <%@ Control Language="C#" Inherits="System.Web.Mvc.ViewUserControl<IEnumerable<StudentInfo>>" %> in my view if i have IEnumerable I can do foreach.. but before that i need to access the properties for StudnetInfo.. StudentInfo clas having Public class StudentInfo { public Studentdetails sd {get;set;} public classDetails cd {get;set;} } <% foreach(var e in Model){%> <div> <%=Html.DisplayFor(x=>e.StdentEdit) %> <div> <span> <% Html.RenderAction("Details", "Home", new { @t = e }); %> </span> </div> </div> <% } %> please can anybody help me out.. how to get the properties of StudentInfo above the foreach loop... if i remove IEnemurable I can do that.. but i need to have Ienemurable for RenderAction.. is there any other way we can achieve this? thanks

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  • Where should we manage session objects in an ASP.NET application?

    - by Kumar
    I am developing a 3-tired ASP.NET C# web application and was wondering where should the sessions be managed. I have a SessionManager class as follows: public sealed class SessionManager { private const string USER = "User"; private SessionManager() { } public static SessionManager Instance { get { return _instance; } } public User User { get { return HttpContext.Current.Session[USER] as User; } set { HttpContext.Current.Session[USER] = value; } } } Now should the session information be managed in the Business Logic Layer or should it be managed in the Presentation Layer?

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  • How to remove the link if value is 0 using asp.net mvc

    - by kumar
    i have this code.. <table class="dashboard-table"> <thead> <tr> <th>&nbsp;</th> <th>Worked</th> </tr> </thead> <% foreach (var e in Model.ExceptionsByType) { %> <tr> <td> <%=Html.ActionLink(e.ExceptionTypeName, "VirtualScrollingDataRequested", Model.exceptionCategory.GetControllerName(), new { C_EXCPT_TYPE = e.ExceptionTypeID, GUI_SPEC_STAT_DSPL = 2, C_EXCPT_CATG = Model.exceptionCategory.Id, @ASSET_CLASS = string.Empty, @INST_MNEM = string.Empty, @_lock = "ALL" }, new { @title = e.BuildGridTitle(2, e.ExceptionTypeName) })%> </td> <td class="number"> <%=e.WorkedExceptions %> </td> </tr> <% } %> </table> e.WorkedExceptions is the count of exceptions.. I need to to the condition here if the e.workedexceptions == 0 I need to remove the link? please can any body hlep me out? thanks

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  • can i change the image place using jquery

    - by kumar
    I have jquery datepicker code where i am dispalying one calander control to dispaly dateand time $("input[id^='exc-flwup-<%=Model.ExceptionID%>']").datepicker({ duration: 0, buttonImage: '/Content/images/calender.gif', buttonImageOnly: true, showOn:'button', constrainInput: true, showTime: true, stepMinutes: 30, stepHours: 1, altTimeField: '', time24h: true, minDate: 0 }); Image button is allways coming left side of my textbox I need to keep it right side of my textbox is there any way I can adjust my image on this? thanks

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  • Jquery Block on my document .ready function not working

    - by kumar
    Hello Friens, I have this code, I added JS Script file to my Master page. <script src="/Scripts/Jquery.blockUI.js" type="text/javascript"></script> This Below code I have in my master page.on document.ready <script type="text/javascript"> $(document).ready(function () { $.blockUI({ message: $('#question'), css: { width: '275px'} }); }); </script> <div id="question" style="display:none; cursor: default"> <h2 class="padding"><br />An unexpected system error has occurred while processing your request.<br /></h2> <h3>We apologize for this inconvenience.<br /> Please report this error to your system administrator with the following information:<br /><br /> Session id is:</h3> <input type="button" id="OK" value="OK" /> </asp:Content> On my Document.ready Function my BlockUi is not working? can any body tell me why its not working? thanks

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  • waht is the differnce between these two types using jquery

    - by kumar
    hi, $('tr td:first-child').click(function() { var foobar = $(this).text(); $("#showgrid").load('/Product/List/Item?id=' + foobar); }); when I am seding foobar value like this in the Actionresult method I am getting string id value perfectly but I am not able to display the grid? but intresting thing is when I am seding like this $("#showgrid").load('/Product/List/Item?id=' + "12345"); then I am able to display the grid.. foobar result is same 12345.. what is the differnt between these two types? can any body help me out.. thanks

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  • What is the differnce between these two types using jquery

    - by kumar
    hi, $('tr td:first-child').click(function() { var foobar = $(this).text(); $("#showgrid").load('/Product/List/Item?id=' + foobar); }); when I am seding foobar value like this in the Actionresult method I am getting string id value perfectly but I am not able to display the grid? but intresting thing is when I am seding like this $("#showgrid").load('/Product/List/Item?id=' + "12345"); then I am able to display the grid.. foobar result is same 12345.. what is the differnt between these two types? can any body help me out.. thanks

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  • jQuery does not work anymore after re-rendring any RichFaces component

    - by Manish Kumar
    I have a page which contains following components: 1 Button 1 drop down list using jQuery 1 button whose on click event changes a text box value using jQuery 2 another buttons shown on hover If I change the dropdown value, or press a button, then the page is re-rendered by ajax. After that, jQuery does not work anymore. If I refresh the page, then jQuery works fine. How is this caused and how can I solve it?

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  • how to append dropdown list box

    - by kumar
    $("#Grid").click( $("#showgrid").load('SomeURL')); $.each($('#Grid td:nth-child(4n)'), function() { var forthColumn = $(this); forthColumn.append("<select><option value='1'>Division 1</option><option value='2'>Division 2</option><option value='3'>Division 3</option></select>"); }); }; I am trying to append the dropdown list box? this way but I am not seeing the dropdownbox at 4th colum? is this right? thanks for all..

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  • how to do the each funtion for all to check checkboxes

    - by kumar
    I am using this code to check the checkbox is chekced or not.. $('#nextpage').click(function() { var result = $('#Details input[type=checkbox]').attr('checked'); if (result == true) { $("#tabs").tabs('enable', 3).tabs('select', 3); } else { $().ShowDialog('please select atleast one'); } }); using this I can check only for one checkbox if I need to check for multipe checkboxes in teh Details page how do I need to loop throw? thanks

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  • How improve skills in Java?

    - by kumar kasimala
    I would like to get updates Java and related technogies news on every day so that I will new features of java, even I want to improve java skills by learning existing or new things which is related to logic, therory, programs, How do I get all above details & give me links , so that I will subscribe to it

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