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  • No WiFi after upgrading 12.04 kernel to 3.2.0-24-generic-pae

    - by lunar
    I'm on Ubuntu 12.04 LTS. With the previous kernel everything was okay — until today's upgrade to 3.2.0-24-generic-pae. The device network tools show that my WiFi card is in an inactive state. How can I enable it? These commands don't work: sudo ifconfig wlan0 up sudo /etc/init.d/networking restart The last one returns some weird errors, brackets, tildes, ampersands like in some kind of a loop.

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  • SQL Server 2008 R2 Reporting Services: A generic error occurred in GDI+

    - by Greg Low
    While building some maps today in SQL Server 2008 R2 Reporting Services, I kept coming up with an error that said: A generic error occurred in GDI+ I was struggling to think what I'd done wrong. After much nashing of teeth and removal of hair, I finally worked out what the error was. When I got to the "Choose Color Scheme and Visualization" page of the map wizard for building a color analytical map, I hadn't picked the correct value for the "Field to Visualize" drop-down. I'm guessing that because...(read more)

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  • SQL Server 2008 R2 Reporting Services: A generic error occurred in GDI+

    - by Greg Low
    While building some maps today in SQL Server 2008 R2 Reporting Services, I kept coming up with an error that said: A generic error occurred in GDI+ I was struggling to think what I'd done wrong. After much nashing of teeth and removal of hair, I finally worked out what the error was. When I got to the "Choose Color Scheme and Visualization" page of the map wizard for building a color analytical map, I hadn't picked the correct value for the "Field to Visualize" drop-down. I'm guessing that because...(read more)

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  • parsing a list and producing a structure of that

    - by qzar
    ;; structure representing homework points ;; nr: number - the number of the homework ;; points: number - the number of points reached (define-struct homework (nr points)) ;; parse-homework: (list of number pairs) -> (list of homework) ;; The procedure takes a list of number pairs and produces a list of homework structures ;; Example: (parse-homework (list (list 1 6) (list 2 7) (list 3 0))) should produce (list (make-homework 1 6) (make-homework 2 7) (make-homework 3 0)) (define (parse-homework homework-entries) (if (and (= (length (first homework-entries) 2))(= (length (parse-homework (rest homework-entries)) 2))) (make-homework (first homework-entries) (parse-homework (rest homework-entries))) (error 'Non-valid-input "entered list is not of length two")) ) (parse-homework (list (list 1 6) (list 2 7) (list 3 0))) This code produces the error length: expects 1 argument, given 2: (list 1 6) 2 I really appreciate every explanation that you can give me to get in in this scheme-stuff... Thank you very much

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  • Big problem with Dijkstra algorithm in a linked list graph implementation

    - by Nazgulled
    Hi, I have my graph implemented with linked lists, for both vertices and edges and that is becoming an issue for the Dijkstra algorithm. As I said on a previous question, I'm converting this code that uses an adjacency matrix to work with my graph implementation. The problem is that when I find the minimum value I get an array index. This index would have match the vertex index if the graph vertexes were stored in an array instead. And the access to the vertex would be constant. I don't have time to change my graph implementation, but I do have an hash table, indexed by a unique number (but one that does not start at 0, it's like 100090000) which is the problem I'm having. Whenever I need, I use the modulo operator to get a number between 0 and the total number of vertices. This works fine for when I need an array index from the number, but when I need the number from the array index (to access the calculated minimum distance vertex in constant time), not so much. I tried to search for how to inverse the modulo operation, like, 100090000 mod 18000 = 10000 and, 10000 invmod 18000 = 100090000 but couldn't find a way to do it. My next alternative is to build some sort of reference array where, in the example above, arr[10000] = 100090000. That would fix the problem, but would require to loop the whole graph one more time. Do I have any better/easier solution with my current graph implementation?

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  • How do I implement a remove by index method for a singly linked list in Java?

    - by Lars Flyger
    Hi, I'm a student in a programming class, and I need some help with this code I've written. So far I've written an entire linked list class (seen below), yet for some reason the "removeByIndex" method won't work. I can't seem to figure out why, the logic seems sound to me. Is there some problem I don't know about? public class List<T> { //private sub-class Link private class Link { private T value; private Link next; //constructors of Link: public Link (T val) { this.value = val; this.next = null; } public Link (T val, Link next) { this.value = val; this.next = next; } @SuppressWarnings("unused") public T getValue() { return value; } } private static final Exception NoSuchElementException = null; private static final Exception IndexOutOfBoundsException = null; private Link chain = null; //constructors of List: public List() { this.chain = null; } //methods of List: /** * Preconditions: none * Postconditions: returns true if list is empty */ public boolean isEmpty() { return this.chain == null; } /** * Preconditions: none * Postconditions: A new Link is added via add-aux * @param element */ public void add(T element) { this.add_aux(element, this.chain); } /** * Preconditions: none * Postconditions: A new Link is added to the current chain * @param element * @param chain */ private void add_aux(T element, Link chain) { if (chain == null) { //if chain is null set chain to a new Link with a value of //element this.chain = new Link(element); } else if (chain.next != null) { //if chain.next is not null, go to next item in chain and //try //to add element add_aux(element, chain.next); } else { //if chain.next is null, set chain.next equal to a new Link //with value of element. chain.next = new Link(element); } } /** * Preconditions: none * Postconditions: returns the link at the defined index via nthlink_aux * @param index * @return */ private Link nthLink (int index) { return nthLink_aux(index, this.chain); } /** * Preconditions: none * Postconditions: returns the link at the defined index in the specified *chain * @param i * @param c * @return */ private Link nthLink_aux (int i, Link c) { if (i == 0) { return c; } else return nthLink_aux(i-1, c.next); } /** * Preconditions: the specified element is present in the list * Postconditions: the specified element is removed from the list * @param element * @throws Exception */ public void removeElement(T element) throws Exception { if (chain == null) { throw NoSuchElementException; } //while chain's next is not null and the value of chain.next is not //equal to element, //set chain equal to chain.next //use this iteration to go through the linked list. else while ((chain.next != null) && !(chain.next.value.equals(element))){ Link testlink = chain.next; if (testlink.next.value.equals(element)) { //if chain.next is equal to element, bypass the //element. chain.next.next = chain.next.next.next; } else if (testlink.next == null) { throw NoSuchElementException; } } } /** * Preconditions: none * Postsconditions: the Link at the specified index is removed * @param index * @throws Exception */ public void removeByIndex(int index) throws Exception { if (index == 0) { //if index is 0, set chain equal to chain.next chain = chain.next; } else if (index > 0) { Link target = nthLink(index); while (target != null) { if (target.next != null) { target = target.next; } //if target.next is null, set target to null else { target = null; } } return; } else throw IndexOutOfBoundsException; } /** * Preconditions: none * Postconditions: the specified link's value is printed * @param link */ public void printLink (Link link) { if(link != null) { System.out.println(link.value.toString()); } } /** * Preconditions: none * Postconditions: all of the links' values in the list are printed. */ public void print() { //copy chain to a new variable Link head = this.chain; //while head is not null while (!(head == null)) { //print the current link this.printLink(head); //set head equal to the next link head = head.next; } } /** * Preconditions: none * Postconditions: The chain is set to null */ public void clear() { this.chain = null; } /** * Preconditions: none * Postconditions: Places the defined link at the defined index of the list * @param index * @param val */ public void splice(int index, T val) { //create a new link with value equal to val Link spliced = new Link(val); if (index <= 0) { //copy chain Link copy = chain; //set chain equal to spliced chain = spliced; //set chain.next equal to copy chain.next = copy; } else if (index > 0) { //create a target link equal to the link before the index Link target = nthLink(index - 1); //set the target's next equal to a new link with a next //equal to the target's old next target.next = new Link(val, target.next); } } /** * Preconditions: none * Postconditions: Check to see if element is in the list, returns true * if it is and false if it isn't * @param element * @return */ public boolean Search(T element) { if (chain == null) { //return false if chain is null return false; } //while chain's next is not null and the value of chain.next is not //equal to element, //set chain equal to chain.next //use this iteration to go through the linked list. else while ((chain.next != null) && !(chain.next.value.equals(element))) { Link testlink = chain.next; if (testlink.next.value.equals(element)) { //if chain.next is equal to element, return true return true; } else if (testlink.next == null) { return false; } } return false; } /** * Preconditions: none * Postconditions: order of the links in the list is reversed. */ public void reverse() { //copy chain Link current = chain; //set chain equal to null chain = null; while (current != null) { Link save = current; current = current.next; save.next = chain; chain = save; } } }'

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  • create graph using adjacency list

    - by sum1needhelp
    #include<iostream> using namespace std; class TCSGraph{ public: void addVertex(int vertex); void display(); TCSGraph(){ head = NULL; } ~TCSGraph(); private: struct ListNode { string name; struct ListNode *next; }; ListNode *head; } void TCSGraph::addVertex(int vertex){ ListNode *newNode; ListNode *nodePtr; string vName; for(int i = 0; i < vertex ; i++ ){ cout << "what is the name of the vertex"<< endl; cin >> vName; newNode = new ListNode; newNode->name = vName; if (!head) head = newNode; else nodePtr = head; while(nodePtr->next) nodePtr = nodePtr->next; nodePtr->next = newNode; } } void TCSGraph::display(){ ListNode *nodePtr; nodePtr = head; while(nodePtr){ cout << nodePtr->name<< endl; nodePtr = nodePtr->next; } } int main(){ int vertex; cout << " how many vertex u wan to add" << endl; cin >> vertex; TCSGraph g; g.addVertex(vertex); g.display(); return 0; }

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  • Is this good code? Linked List Stack Implementation

    - by Quik Tester
    I have used the following code for a stack implementation. The top keeps track of the topmost node of the stack. Now since top is a data member of the node function, each node created will have a top member, which ideally we wouldn't want. Firstly, is this good approach to coding? Secondly, will making top as static make it a better coding practice? Or should I have a global declaration of top? #include<iostream> using namespace std; class node { int data; node *top; node *link; public: node() { top=NULL; link=NULL; } void push(int x) { node *n=new node; n->data=x; n->link=top; top=n; cout<<"Pushed "<<n->data<<endl; } void pop() { node *n=new node; n=top; top=top->link; n->link=NULL; cout<<"Popped "<<n->data<<endl; delete n; } void print() { node *n=new node; n=top; while(n!=NULL) { cout<<n->data<<endl; n=n->link; } delete n; } }; int main() { node stack; stack.push(5); stack.push(7); stack.push(9); stack.pop(); stack.print(); } Any other suggestions welcome. I have also seen codes where there are two classes, where the second one has the top member. What about this? Thanks. :)

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  • Printing elements out of list

    - by chavanak
    Hi, I have a certain check to be done and if the check satisfies, I want the result to be printed. Below is the code: import string import codecs import sys y=sys.argv[1] list_1=[] f=1.0 x=0.05 write_in = open ("new_file.txt", "w") write_in_1 = open ("new_file_1.txt", "w") ligand_file=open( y, "r" ) #Open the receptor.txt file ligand_lines=ligand_file.readlines() # Read all the lines into the array ligand_lines=map( string.strip, ligand_lines ) #Remove the newline character from all the pdb file names ligand_file.close() ligand_file=open( "unique_count_c_from_ac.txt", "r" ) #Open the receptor.txt file ligand_lines_1=ligand_file.readlines() # Read all the lines into the array ligand_lines_1=map( string.strip, ligand_lines_1 ) #Remove the newline character from all the pdb file names ligand_file.close() s=[] for i in ligand_lines: for j in ligand_lines_1: j = j.split() if i == j[1]: print j The above code works great but when I print j, it prints like ['351', '342'] but I am expecting to get 351 342 (with one space in between). Since it is more of a python question, I have not included the input files (basically they are just numbers). Can anyone help me? Cheers, Chavanak

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  • Declaring an array of linked list in C#

    - by xarzu
    I got the compile error message "Array size cannot be specified in a variable declaration (try initializing with a 'new' expression)" when I tried to declare an array of linked lists. public LinkedList[2] ExistingXMLList; Also, if I wanted to create a small array of strings, isn't this the way: string [2] inputdata;

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  • Python directory list returned to Django template

    - by Shu
    Total Python newb here. I have a images directory and I need to return the names and urls of those files to a django template that I can loop through for links. I know it will be the server path, but I can modify it via JS. I've tried os.walk, but I keep getting empty results.

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  • printing reverse in singly link list using pointers

    - by theoneabhinav
    i have been trying this code. i think the logic is ok but the program terminates abruptly when the display_rev function is called here is code of display_rev void display_rev(emp_node *head) { emp_node *p=head, *q; while(p->next != NULL) p=p->next; while(p!=head || p==head){ q=head; display_rec(p); while(q->next != p) q=q->next; p=q; } } here is my whole code #include<stdio.h> #include<stdlib.h> #include<ctype.h> #include<string.h> //Declarations=============================================================== typedef struct //employee record { int emp_id; char name[150]; char mob_no[11]; float salary; int proj[5]; struct emp_node *next; } emp_node; emp_node* add_rec(emp_node*); emp_node* create_db(emp_node*); emp_node* search_db(emp_node*, int); emp_node* delete_rec(emp_node*, int); void read_name(emp_node*); void read_mob(emp_node*); void display_db(emp_node*); void display_rec(emp_node*); void display_rev(emp_node*); void modify_rec(emp_node*); void swtch(emp_node*); //=========================================================================== int main() { char ans; emp_node *head = NULL; head = create_db(head); display_db(head); do { swtch(head); printf("\n\n\tDo you want to continue (y/n) : "); getchar(); scanf("%c", &ans); } while (ans == 'y' || ans == 'Y'); return 0; } //Definitions================================================================ emp_node* create_db(emp_node *head) //database creation { int i = 1, no; emp_node *p; printf("Enter number of employees:"); scanf("%d", &no); printf("\n\n"); head = (emp_node *) malloc(sizeof(emp_node)); head = add_rec(head); head->next = NULL; p = head; while (i < no) { p->next = (emp_node *) malloc(sizeof(emp_node)); p = p->next; p = add_rec(p); p->next = NULL; i++; } return head; } emp_node* add_rec(emp_node *p) //new record { int j; printf("\n\tEmployee ID : "); scanf("%d", &(p->emp_id)); printf("\n\tFirst Name:"); read_name(p); printf("\n\tMobile No.:"); read_mob(p); printf("\n\tSalary :"); scanf("%f", &(p->salary)); printf( "\n\tEnter \"1\" for the projects employee is working on, otherwise enter \"0\": \n"); for (j = 0; j < 5; j++) { printf("\n\t\tProject No. %d : ", j + 1); scanf("%d", &(p->proj[j])); while (p->proj[j] != 1 && p->proj[j] != 0) { printf("\n\nInvalid entry!! Please re-enter."); printf("\n\t\tProject No. %d : ", j + 1); scanf("%d", &(p->proj[j])); } } printf("\n\n\n"); return p; } void read_name(emp_node *p) //validation for name { int j, len; scanf("%s", p->name); len = strlen(p->name); for (j = 0; j < len; j++) { if (!isalpha(p->name[j])) { printf( "\n\n\tInvalid name!!Can contain only characters. Please Re-enter.\n"); printf("\n\tName : "); read_name(p); } } } void read_mob(emp_node *p) //validation for mobile no. { int j; scanf("%s", p->mob_no); while (strlen(p->mob_no) != 10) { printf("\n\nInvalid Mobile No!!Please Re-enter"); printf("\n\n\tMobile No.:"); read_mob(p); } for (j = 0; j < 10; j++) { if (!(48 <= p->mob_no[j] && p->mob_no[j] <= 57)) { printf( "\n\nInvalid Mobile No!!Can contain only digits. Please Re-enter."); printf("\n\n\tMobile No.:"); read_mob(p); } } } void display_db(emp_node *head) //displaying whole database { emp_node *p; p = head; printf("\n\n\t\t****** EMPLOYEE DATABASE ******\n"); printf( "\n=============================================================================="); printf("\n Id.\t Name\t\t Mobile No\t Salary\t Projects\n"); while (p != NULL) { display_rec(p); p = p->next; printf("\n\n\n"); } printf( "\n=============================================================================="); } void swtch(emp_node *head) //function for menu and switch case { int cho, x; emp_node *p; printf("\n\n\t\t****** MENU ******"); printf( "\n\n\t1. insert Record\n\t2. Search Record\n\t3. Modify Record\n\t4. Delete Record\n\t5. Display Reverse\n\t6. Exit"); printf("\n\tWhich operation do you want to perform? "); scanf("%d", &cho); switch (cho) { case 1: p=head; while(p->next != NULL) p=p->next; p->next = (emp_node *) malloc(sizeof(emp_node)); p=p->next; p = add_rec(p); p->next = NULL; display_db(head); break; case 2: printf("\n\n\tEnter employee ID whose record is to be Searched :"); scanf("%d", &x); p = search_db(head, x); if (p == NULL) printf("\n\nRecord not found."); else display_rec(p); break; case 3: printf("\n\n\tEnter employee ID whose record is to be modified :"); scanf("%d", &x); p = search_db(head, x); if (p == NULL) printf("\n\nRecord not found."); else modify_rec(p); display_db(head); break; case 4: printf("\n\n\tEnter employee ID whose record is to be deleted :"); scanf("%d", &x); head = delete_rec(head, x); display_db(head); break; case 5: display_rev(head); case 6: exit(0); default: printf("Invalid Choice!! Please try again."); } } emp_node* search_db(emp_node *head, int id) //search database { emp_node *p = head; while (p != NULL) { if (p->emp_id == id) return p; p = p->next; } return NULL; } void display_rec(emp_node *p) //display a single record { int j; printf("\n %d", p->emp_id); printf("\t %10s", p->name); printf("\t %10s", p->mob_no); printf("\t %05.2f", p->salary); printf("\t "); for (j = 0; j < 5; j++) { if (p->proj[j] == 1) printf(" %d,", j + 1); } } void modify_rec(emp_node *p) //modifying a record { int j, cho; char ch1, edt; do { printf( "\n\t1. Name\n\t2. Email Address\n\t3. Mobile No.\n\t4. Salary\n\t5. Date of birth\n\t6. Projects\n"); printf("Enter your choice : "); scanf("%d", &cho); switch (cho) { case 1: printf("\n\tPrevious name:%s", p->name); printf("\n\tDo you want to edit ? (y/n)"); getchar(); scanf("%c", &ch1); if (ch1 == 'y' || ch1 == 'Y') { printf("\n\tEnter New Name:"); read_name(p); } break; case 2: printf("\n\tPrevious Mobile No. : %s", p->mob_no); printf("\n\tDo you want to edit ? (y/n)"); getchar(); scanf("%c", &ch1); if (ch1 == 'y' || ch1 == 'Y') { printf("\n\tEnter New Mobile No. :"); read_mob(p); } break; case 3: printf("\n\tPrevious salary is : %f", p->salary); printf("\n\tDo you want to edit ? (y/n)"); getchar(); scanf("%c", &ch1); if (ch1 == 'y' || ch1 == 'Y') { printf("\n\tEnter New salary:"); scanf("%f", &(p->salary)); } break; case 4: printf("the employee is currently working on project no. "); for (j = 0; j < 5; j++) { if (p->proj[j] == 1) printf(" %d,", j + 1); } printf("\n\tDo you want to edit ? (y/n)"); getchar(); scanf("%c", &ch1); if (ch1 == 'y' || ch1 == 'Y') { printf( "\n\tEnter \"1\" for the projects employee is working on : \n"); for (j = 0; j < 5; j++) { printf("\n\t\tProject No. %d : ", j + 1); scanf("%d", &(p->proj[j])); while (p->proj[j] != 1) { printf("\n\nInvalid entry!! Please re-enter."); printf("\n\t\tProject No. %d : ", j + 1); scanf("%d", &(p->proj[j])); } } } break; default: printf("\n\nInvalid Choice!! Please Try again."); } printf("\n\nDo you want to edit any other fields ?(y/n)"); getchar(); scanf("%c", &edt); } while (edt == 'y' || edt == 'Y'); } emp_node* delete_rec(emp_node *head, int id) //physical deletion of record { emp_node *p = head, *q; if (head->emp_id == id) { head = head->next; free(p); return head; } else { q = p->next; while (q->emp_id != id) { p = p->next; q = q->next; } if (q->next == NULL) p->next = NULL; else p->next = q->next; free(q); return head; } } void display_rev(emp_node *head) { emp_node *p=head, *q; while(p->next != NULL) p=p->next; while(p!=head || p==head){ q=head; display_rec(p); while(q->next != p) q=q->next; p=q; } }

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  • How to get a list of all domains?

    - by AngryHacker
    I'm trying to get all domains that are available in the Windows Login dialog (in the Domain dropdown). I've tried the following code but it only returns the domain I am logged into. Am I missing something? StringCollection domainList = new StringCollection(); try { DirectoryEntry en = new DirectoryEntry("LDAP://"); // Search for objectCategory type "Domain" DirectorySearcher srch = new DirectorySearcher("objectCategory=Domain"); SearchResultCollection coll = srch.FindAll(); // Enumerate over each returned domain. foreach (SearchResult rs in coll) { ResultPropertyCollection resultPropColl = rs.Properties; foreach( object domainName in resultPropColl["name"]) { domainList.Add(domainName.ToString()); } } } catch (Exception ex) { Trace.Write(ex.Message); } return domainList;

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  • efficient list mapping in python

    - by Joey
    Hi everyone, I have the following input: input = [(dog, dog, cat, mouse), (cat, ruby, python, mouse)] and trying to have the following output: outputlist = [[0, 0, 1, 2], [1, 3, 4, 2]] outputmapping = {0:dog, 1:cat, 2:mouse, 3:ruby, 4:python, 5:mouse} Any tips on how to handle given with scalability in mind (var input can get really large).

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  • Simple Constructor With Initializer List? - C++

    - by Alex
    Hi all, below I've included my h file, and my problem is that the compiler is not liking my simple exception class's constructor's with initializer lists. It also is saying that string is undeclared identifier, even though I have #include <string> at the top of the h file. Do you see something I am doing wrong? For further explanation, this is one of my domain classes that I'm integrating into a wxWidgets GUI application on Windows. Thanks! Time.h #pragma once #include <string> #include <iostream> // global constants for use in calculation const int HOURS_TO_MINUTES = 60; const int MINUTES_TO_HOURS = 100; class Time { public: // default Time class constructor // initializes all vars to default values Time(void); // ComputeEndTime computes the new delivery end time // params - none // preconditions - vars will be error-free // postconditions - the correct end time will be returned as an int // returns an int int ComputeEndTime(); // GetStartTime is the getter for var startTime // params - none // returns an int int GetStartTime() { return startTime; } // GetEndTime is the getter for var endTime // params - none // returns an int int GetEndTime() { return endTime; } // GetTimeDiff is the getter for var timeDifference // params - none // returns a double double GetTimeDiff() { return timeDifference; } // SetStartTime is the setter for var startTime // params - an int // returns void void SetStartTime(int s) { startTime = s; } // SetEndTime is the setter for var endTime // params - an int // returns void void SetEndTime(int e) { endTime = e; } // SetTimeDiff is the setter for var timeDifference // params - a double // returns void void SetTimeDiff(double t) { timeDifference = t; } // destructor for Time class ~Time(void); private: int startTime; int endTime; double timeDifference; }; class HourOutOfRangeException { public: // param constructor // initializes message to passed paramater // preconditions - param will be a string // postconditions - message will be initialized // params a string // no return type HourOutOfRangeException(string pMessage) : message(pMessage) {} // GetMessage is getter for var message // params none // preconditions - none // postconditions - none // returns string string GetMessage() { return message; } // destructor ~HourOutOfRangeException() {} private: string message; }; class MinuteOutOfRangeException { public: // param constructor // initializes message to passed paramater // preconditions - param will be a string // postconditions - message will be initialized // params a string // no return type MinuteOutOfRangeException(string pMessage) : message(pMessage) {} // GetMessage is getter for var message // params none // preconditions - none // postconditions - none // returns string string GetMessage() { return message; } // destructor ~MinuteOutOfRangeException() {} private: string message; }; class PercentageOutOfRangeException { public: // param constructor // initializes message to passed paramater // preconditions - param will be a string // postconditions - message will be initialized // params a string // no return type PercentageOutOfRangeException(string pMessage) : message(pMessage) {} // GetMessage is getter for var message // params none // preconditions - none // postconditions - none // returns string string GetMessage() { return message; } // destructor ~PercentageOutOfRangeException() {} private: string message; }; class StartEndException { public: // param constructor // initializes message to passed paramater // preconditions - param will be a string // postconditions - message will be initialized // params a string // no return type StartEndException(string pMessage) : message(pMessage) {} // GetMessage is getter for var message // params none // preconditions - none // postconditions - none // returns string string GetMessage() { return message; } // destructor ~StartEndException() {} private: string message; };

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  • Best MAILING LIST solution for a CONFERENCE and its 400 participants

    - by Ole Morten Amundsen
    Dear community, what would you recommend for mailling lists? The conference is non-profit, named Smidig2010 (=Agile2010 in norwegian), will have about 400-500 participants 16.-17.november. At the time of writing this, we have not opened for registration, but would like people to be able to participate, ask questions, get informed and get inspired. We've used a forum before, but forums don't seem to be a good fit for this. I would like to set up a mailinglist, It'll have to be KISS, for the users: enter your email (a input box at our site smidig2010.no) get a confirmation mail, click a link. start posting, reading through archives, answering others etc. I like the look and feel of googlegroups, but I don't like the signup/account creation overhead imposed on the user. I've heard you may combine googlegroups with mailman and stuff, but, yeah, I can't believe our own incompetence on this subject! Btw, we are mostly developers and the conference app is being written in ruby on rails. Being non-profit, we prefer free, but we take everything into consideration. Any suggestions?

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  • How can I also add class to the last list for the second list block in IE?

    - by user244394
    Hi All I have 2 list and i want to add a class ="last" to the list item 5 for both. they seem to work fine on firefox. it add green to both list item 5. But in IE7 it adds only the first list item 5, not the second How can I also add class last it to the second list block as well for IE? .last{background-color: green} jQuery( document ).ready( function () { // Add first and last menu item classes $('ul.menu li:first-child').addClass( 'first_item' ); $('#menu li:last-child').addClass( 'last' ); }); list item 1 list item 2 list item 3 list item 4 list item 5 list item 1 list item 2 list item 3 list item 4 list item 5

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  • R: how can I concatenate a list?

    - by John
    I'm trying to produce a single variable which is a concatenation of two chars e.g to go from "p30s4" "p28s4" to "p30s4 p28s4". I've tried cat and paste as shown below. Both return empty variables. What am I doing wrong? > blah = c("p30s4","p28s4") > blah [1] "p30s4" "p28s4" > foo = cat(blah) p30s4 p28s4 > foo NULL > foo = paste(cat(blah)) p30s4 p28s4 > foo character(0)

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