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• Will my shared variables loose value? (asp.net vb)

  - by Phil

  I have a class includes.vb that holds some variables (sharing them with other pages) like: Public Shared pageid As Integer = 0 I then have a function that does some work with these variables returning them with values; Return pageid When I step through the code, the variables have values (while stepping through the function), but when they are returned to the page, they come back null. Do they loose value everytime a page is loaded? Can you suggest an alternative method? Thanks a lot.

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• Does Ruby have a special stack for return value?

  - by prosseek

  The following Ruby code def a(b,c) b+c end is the same as follows with Python def a(b,c): return b+c It looks like that ruby has the special stack that stores the final evaluation result and returns the value when a function is called. If so, what's the name of the stack, and how can I get that stack? If not, how does the Ruby code work without returning something?

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• Is there a way to get the end value of an animation in jQuery?

  - by George Edison

  I have a script that animates an element as follows: var item_height = $('#item').height(); $('#item').height(0); $('#item').animate({ height: item_height }); Now suppose the animation needs to be stopped before it is complete: $('#item').stop(); How can I get the end value of the animation? (The total height of the element when the animation would have been complete)

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• Query for model by key

  - by Jason Hall

  What I'm trying to do is query the datastore for a model where the key is not the key of an object I already have. Here's some code: class User(db.Model): partner = db.SelfReferenceProperty() def text_message(self, msg): user = User.get_or_insert(msg.sender) if not user.partner: # user doesn't have a partner, find them one # BUG: this line returns 'user' himself... :( other = db.Query(User).filter('partner =', None).get() if other: # connect users else: # no one to connect to! The idea is to find another User who doesn't have a partner, that isn't the User we already know. I've tried filter('key !=, user.key()), filter('__key__ !=, user.key()) and a couple others, and nothing returns another User who doesn't have a partner. filter('foo !=, user.key()) also returns nothing, for the record.

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• foreign key and index issue

  - by George2

  Hello everyone, I am using SQL Server 2008 Enterprise. I have a table and one of its column is referring to another column in another table (in the same database) as foreign key, here is the related SQL statement, in more details, column [AnotherID] in table [Foo] refers to another table [Goo]'s column [GID] as foreign key. [GID] is primary key and clustered index on table [Goo]. My question is, in this way, if I do not create index on [AnotherID] column on [Foo] explicitly, will there be an index created automatically for [AnotherID] column on [Foo] -- because its foreign key reference column [GID] on table [Goo] already has primary clustered key index? CREATE TABLE [dbo].[Foo]( [ID] [bigint] IDENTITY(1,1) NOT NULL, [AnotherID] [int] NULL, [InsertTime] [datetime] NULL CONSTRAINT DEFAULT (getdate()), CONSTRAINT [PK_Foo] PRIMARY KEY CLUSTERED ( [ID] ASC )WITH (PAD_INDEX = OFF, STATISTICS_NORECOMPUTE = OFF, IGNORE_DUP_KEY = OFF, ALLOW_ROW_LOCKS = ON, ALLOW_PAGE_LOCKS = ON) ON [PRIMARY] ) ON [PRIMARY] ALTER TABLE [dbo].[Foo] WITH CHECK ADD CONSTRAINT [FK_Foo] FOREIGN KEY([Goo]) REFERENCES [dbo].[Goo] ([GID]) ALTER TABLE [dbo].[Foo] CHECK CONSTRAINT [FK_Foo] thanks in advance, George

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• Referencing surrogate key

  - by Arman

  I have a table that has an autoincrement surrogate key. I want to use it as a foreign key of my other table. The thing is, I cant figure out how I can reference it to that table, because it is nearly impossible to determine what I have to reference(the actual value of the surrogate key). Please be noted that what I am trying to do is adding a tuple/record through my program(outside the dbms). The process is: Add a new record in Table1 and generate an autoincrement key. Update Add a new record in Table2 and reference its foreign key to the primary key of Table1. Update My question is : HOW do I store the foreign key if I didnt know what is it?

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• OS X Terminal: Meta key + alt functionality at the same time

  - by abababa22

  Is there a way to use "alt/option" key as a meta key but still be able to use the key to make some characters which need it? For example in my local keyboard layout: @ is alt-2 \ is alt-shift-7 | is alt-7 etc. So if I set alt as meta key, I can't make those characters. On the other hand using "press esc, release esc, press a key" to make meta key sequences makes my hands hurt. Any emacs users with international keyboards who have solved this, please give any tips you might have! :) edit: It appears that I can set alt as meta key and then add these kind of settings in inputrc: "\e2": "@" This works in bash shell but it still won't work with emacs though, so no good.

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• Problems in Binary Search Tree

  - by user2782324

  This is my first ever trial at implementing the BST, and I am unable to get it done. Please help The problem is that When I delete the node if the node is in the right subtree from the root or if its a right child in the left subtree, then it works fine. But if the node is in the left subtree from root and its any left child, then it does not get deleted. Can someone show me what mistake am I doing?? the markedNode here gets allocated to the parent node of the node to be deleted. the minValueNode here gets allocated to a node whose left value child is the smallest value and it will be used to replace the value to be deleted. package DataStructures; class Node { int value; Node rightNode; Node leftNode; } class BST { Node rootOfTree = null; public void insertintoBST(int value) { Node markedNode = rootOfTree; if (rootOfTree == null) { Node newNode = new Node(); newNode.value = value; rootOfTree = newNode; newNode.rightNode = null; newNode.leftNode = null; } else { while (true) { if (value >= markedNode.value) { if (markedNode.rightNode != null) { markedNode = markedNode.rightNode; } else { Node newNode = new Node(); newNode.value = value; markedNode.rightNode = newNode; newNode.rightNode = null; newNode.leftNode = null; break; } } if (value < markedNode.value) { if (markedNode.leftNode != null) { markedNode = markedNode.leftNode; } else { Node newNode = new Node(); newNode.value = value; markedNode.leftNode = newNode; newNode.rightNode = null; newNode.leftNode = null; break; } } } } } public void searchBST(int value) { Node markedNode = rootOfTree; if (rootOfTree == null) { System.out.println("Element Not Found"); } else { while (true) { if (value > markedNode.value) { if (markedNode.rightNode != null) { markedNode = markedNode.rightNode; } else { System.out.println("Element Not Found"); break; } } if (value < markedNode.value) { if (markedNode.leftNode != null) { markedNode = markedNode.leftNode; } else { System.out.println("Element Not Found"); break; } } if (value == markedNode.value) { System.out.println("Element Found"); break; } } } } public void deleteFromBST(int value) { Node markedNode = rootOfTree; Node minValueNode = null; if (rootOfTree == null) { System.out.println("Element Not Found"); return; } if (rootOfTree.value == value) { if (rootOfTree.leftNode == null && rootOfTree.rightNode == null) { rootOfTree = null; return; } else if (rootOfTree.leftNode == null ^ rootOfTree.rightNode == null) { if (rootOfTree.rightNode != null) { rootOfTree = rootOfTree.rightNode; return; } else { rootOfTree = rootOfTree.leftNode; return; } } else { minValueNode = rootOfTree.rightNode; if (minValueNode.leftNode == null) { rootOfTree.rightNode.leftNode = rootOfTree.leftNode; rootOfTree = rootOfTree.rightNode; } else { while (true) { if (minValueNode.leftNode.leftNode != null) { minValueNode = minValueNode.leftNode; } else { break; } } // Minvalue to the left of minvalue node rootOfTree.value = minValueNode.leftNode.value; // The value has been swapped if (minValueNode.leftNode.leftNode == null && minValueNode.leftNode.rightNode == null) { minValueNode.leftNode = null; } else { if (minValueNode.leftNode.leftNode != null) { minValueNode.leftNode = minValueNode.leftNode.leftNode; } else { minValueNode.leftNode = minValueNode.leftNode.rightNode; } // Minvalue deleted } } } } else { while (true) { if (value > markedNode.value) { if (markedNode.rightNode != null) { if (markedNode.rightNode.value == value) { break; } else { markedNode = markedNode.rightNode; } } else { System.out.println("Element Not Found"); return; } } if (value < markedNode.value) { if (markedNode.leftNode != null) { if (markedNode.leftNode.value == value) { break; } else { markedNode = markedNode.leftNode; } } else { System.out.println("Element Not Found"); return; } } } // Parent of the required element found // //////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////// if (markedNode.rightNode != null) { if (markedNode.rightNode.value == value) { if (markedNode.rightNode.rightNode == null && markedNode.rightNode.leftNode == null) { markedNode.rightNode = null; return; } else if (markedNode.rightNode.rightNode == null ^ markedNode.rightNode.leftNode == null) { if (markedNode.rightNode.rightNode != null) { markedNode.rightNode = markedNode.rightNode.rightNode; return; } else { markedNode.rightNode = markedNode.rightNode.leftNode; return; } } else { if (markedNode.rightNode.value == value) { minValueNode = markedNode.rightNode.rightNode; } else { minValueNode = markedNode.leftNode.rightNode; } if (minValueNode.leftNode == null) { // MinNode has no left value markedNode.rightNode = minValueNode; return; } else { while (true) { if (minValueNode.leftNode.leftNode != null) { minValueNode = minValueNode.leftNode; } else { break; } } // Minvalue to the left of minvalue node if (markedNode.leftNode != null) { if (markedNode.leftNode.value == value) { markedNode.leftNode.value = minValueNode.leftNode.value; } } if (markedNode.rightNode != null) { if (markedNode.rightNode.value == value) { markedNode.rightNode.value = minValueNode.leftNode.value; } } // MarkedNode exchanged if (minValueNode.leftNode.leftNode == null && minValueNode.leftNode.rightNode == null) { minValueNode.leftNode = null; } else { if (minValueNode.leftNode.leftNode != null) { minValueNode.leftNode = minValueNode.leftNode.leftNode; } else { minValueNode.leftNode = minValueNode.leftNode.rightNode; } // Minvalue deleted } } } // //////////////////////////////////////////////////////////////////////////////////////////////////////////////// if (markedNode.leftNode != null) { if (markedNode.leftNode.value == value) { if (markedNode.leftNode.rightNode == null && markedNode.leftNode.leftNode == null) { markedNode.leftNode = null; return; } else if (markedNode.leftNode.rightNode == null ^ markedNode.leftNode.leftNode == null) { if (markedNode.leftNode.rightNode != null) { markedNode.leftNode = markedNode.leftNode.rightNode; return; } else { markedNode.leftNode = markedNode.leftNode.leftNode; return; } } else { if (markedNode.rightNode.value == value) { minValueNode = markedNode.rightNode.rightNode; } else { minValueNode = markedNode.leftNode.rightNode; } if (minValueNode.leftNode == null) { // MinNode has no left value markedNode.leftNode = minValueNode; return; } else { while (true) { if (minValueNode.leftNode.leftNode != null) { minValueNode = minValueNode.leftNode; } else { break; } } // Minvalue to the left of minvalue node if (markedNode.leftNode != null) { if (markedNode.leftNode.value == value) { markedNode.leftNode.value = minValueNode.leftNode.value; } } if (markedNode.rightNode != null) { if (markedNode.rightNode.value == value) { markedNode.rightNode.value = minValueNode.leftNode.value; } } // MarkedNode exchanged if (minValueNode.leftNode.leftNode == null && minValueNode.leftNode.rightNode == null) { minValueNode.leftNode = null; } else { if (minValueNode.leftNode.leftNode != null) { minValueNode.leftNode = minValueNode.leftNode.leftNode; } else { minValueNode.leftNode = minValueNode.leftNode.rightNode; } // Minvalue deleted } } } } // //////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////// } } } } } } public class BSTImplementation { public static void main(String[] args) { BST newBst = new BST(); newBst.insertintoBST(19); newBst.insertintoBST(13); newBst.insertintoBST(10); newBst.insertintoBST(20); newBst.insertintoBST(5); newBst.insertintoBST(23); newBst.insertintoBST(28); newBst.insertintoBST(16); newBst.insertintoBST(27); newBst.insertintoBST(9); newBst.insertintoBST(4); newBst.insertintoBST(22); newBst.insertintoBST(17); newBst.insertintoBST(30); newBst.insertintoBST(40); newBst.deleteFromBST(5); newBst.deleteFromBST(4); newBst.deleteFromBST(9); newBst.deleteFromBST(10); newBst.deleteFromBST(13); newBst.deleteFromBST(16); newBst.deleteFromBST(17); newBst.searchBST(5); newBst.searchBST(4); newBst.searchBST(9); newBst.searchBST(10); newBst.searchBST(13); newBst.searchBST(16); newBst.searchBST(17); System.out.println(); newBst.deleteFromBST(20); newBst.deleteFromBST(23); newBst.deleteFromBST(27); newBst.deleteFromBST(28); newBst.deleteFromBST(30); newBst.deleteFromBST(40); newBst.searchBST(20); newBst.searchBST(23); newBst.searchBST(27); newBst.searchBST(28); newBst.searchBST(30); newBst.searchBST(40); } }

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• Parent key of type encoded string?

  - by user246114

  Hi, How do we create a parent key which is an encoded string? Example: class Parent { @PrimaryKey @Persistent(valueStrategy = IdGeneratorStrategy.IDENTITY) @Extension(vendorName="datanucleus", key="gae.encoded-pk", value="true") private String mEncKey; } class Child { @PrimaryKey @Persistent(valueStrategy = IdGeneratorStrategy.IDENTITY) @Extension(vendorName="datanucleus", key="gae.encoded-pk", value="true") private String mEncKey; // In the doc examples, they have Key as the type here. @Persistent @Extension(vendorName="datanucleus", key="gae.parent-pk", value="true") private String mParentEncKey; } yeah I'm not sure how to make mParentEncKey an encoded string type, because the 'key' label is already being used? I would need something like?: key="gae.parent-pk.encoded-pk" not sure - is that possible? Thanks

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• SQL Server PIVOT on key-value table

  - by Zenox

  I have a table that has attributes based on a key-value. Example: CREATE TABLE ObjectAttributes ( int objectId, key nvarchar(64), value nvarchar(512) ) When I select from this I get: objectId key value ---------------------------- 1 Key 1 Value 1 1 Key 2 Value 2 I was wondering if I could use the PIVOT syntax to turn this into: objectId Key 1 Key 2 --------------------------- 1 Value 1 Value 2 I know all of my tables will have the same keys. (Unfortunately I cannot easily change the table structure. This is what is leading me to attempt using PIVOTS). The big issue here though is that pivots require an aggression function to be used. Is there a way to avert this? Am I completely wrong attempting this? Or is there a better solution?

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• Key repeat on Windows

  - by Rolle

  When you hold a key on the keyboard under Windows XP, the keyboard seems to send Key Down, Key Up repeatedly. However I am developing for a device where holding a key generates a "proper" key repeat, that is, lots of Key Down and then one Key Up when you release the button. I want to get the same behaviour under Windows to get our emulator to work as on he device. Is there anyway to acheive this? Do I need to get another keyboard driver? Thanks!

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• Oracle AutoVue Key Highlights from Oracle OpenWorld 2012

  - by Celine Beck

  We closed another successful Oracle Open World for AutoVue. Thanks to everyone who joined us this year. As usual, from customer presentations to evening networking activities, there was enough to keep us busy during the entire event. Here is a summary of some of the key highlights of the conference: Sessions:We had two AutoVue-specific sessions during Oracle Open World this year. The first session was part of the Product Lifecycle Management track and covered how AutoVue can be used to help drive effective decision making and streamline design for manufacturing processes. Attendees had the opportunity to learn from customer speaker GLOBALFOUNDRIES how they have been leveraging Oracle AutoVue within Agile PLM to enable high degree of collaboration during the exceptionally creative phases of their product development processes, securely, without risking valuable intellectual property. If you are interested, you can actually download the presentation by visiting launch.oracle.com/?plmopenworld2012.AutoVue was also featured as part of the Utilities track. This session focused on how visualization solutions play a critical role in effective plant optimization and configuration strategies defined by owners and operators of power generation facilities. Attendees learnt how integrated with document management systems, and enterprise applications like Oracle Primavera and Asset Lifecycle Management, AutoVue improves change management processes; minimizes risks by providing access to accurate engineering drawings which capture and reflect the as-maintained status of assets; and allows customers to drive complex maintenance projects to successful completion.Augmented Business Visualization for Agile PLMDuring Oracle Open World, we also showcased an Augmented Business Visualization-based solution for Oracle Agile PLM. An Augmented Business Visualization (ABV) solution is one where your structured data (from Oracle Agile PLM for instance) and your unstructured data (documents, designs, 3D models, etc) come together to allow you to make better decisions (check out our blog posts on the topic: Augment the Value of Your Data (or Time to replace the “attach” button) and Context is Everything ). As part of the Agile PLM, the idea is to support more effective decision-making by turning 3D assemblies into color-coded reports, and streamlining business processes like Engineering Change Management by enabling the automatic creation of engineering change requests in Agile PLM directly from documents being viewed in AutoVue. More on this coming soon...probably during the Oracle Value Chain Summit to be held in San Francisco, from Feb. 4-6, 2013 in San Francisco! Mark your calendars and stay tuned for more information! And thanks again for joining us at Oracle OpenWorld!

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• SQL SERVER – Storing 64-bit Unsigned Integer Value in Database

  - by Pinal Dave

  Here is a very interesting question I received in an email just another day. Some questions just are so good that it makes me wonder how come I have not faced it first hand. Anyway here is the question - “Pinal, I am migrating my database from MySQL to SQL Server and I have faced unique situation. I have been using Unsigned 64-bit integer in MySQL but when I try to migrate that column to SQL Server, I am facing an issue as there is no datatype which I find appropriate for my column. It is now too late to change the datatype and I need immediate solution. One chain of thought was to change the data type of the column from Unsigned 64-bit (BIGINT) to VARCHAR(n) but that will just change the data type for me such that I will face quite a lot of performance related issues in future. In SQL Server we also have the BIGINT data type but that is Signed 64-bit datatype. BIGINT datatype in SQL Server have range of -2^63 (-9,223,372,036,854,775,808) to 2^63-1 (9,223,372,036,854,775,807). However, my digit is much larger than this number. Is there anyway, I can store my big 64-bit Unsigned Integer without loosing much of the performance of by converting it to VARCHAR.” Very interesting question, for the sake of the argument, we can ask user that there should be no need of such a big number or if you are taking about identity column I really doubt that if your table will grow beyond this table. Here the real question which I found interesting was how to store 64-bit unsigned integer value in SQL Server without converting it to String data type. After thinking a bit, I found a fairly simple answer. I can use NUMERIC data type. I can use NUMERIC(20) datatype for 64-bit unsigned integer value, NUMERIC(10) datatype for 32-bit unsigned integer value and NUMERIC(5) datatype for 16-bit unsigned integer value. Numeric datatype supports 38 maximum of 38 precision. Now here is another thing to keep in mind. Using NUMERIC datatype will indeed accept the 64-bit unsigned integer but in future if you try to enter negative value, it will also allow the same. Hence, you will need to put any additional constraint over column to only accept positive integer there. Here is another big concern, SQL Server will store the number as numeric and will treat that as a positive integer for all the practical purpose. You will have to write in your application logic to interpret that as a 64-bit Unsigned Integer. On another side if you are using unsigned integers in your application, there are good chance that you already have logic taking care of the same. Reference: Pinal Dave (http://blog.sqlauthority.com) Filed under: PostADay, SQL, SQL Authority, SQL Query, SQL Server, SQL Tips and Tricks, T SQL, Technology Tagged: SQL Datatype

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• SQL: empty string vs NULL value

  - by Jacek Prucia

  I know this subject is a bit controversial and there are a lot of various articles/opinions floating around the internet. Unfortunatelly, most of them assume the person doesn't know what the difference between NULL and empty string is. So they tell stories about surprising results with joins/aggregates and generally do a bit more advanced SQL lessons. By doing this, they absolutely miss the whole point and are therefore useless for me. So hopefully this question and all answers will move subject a bit forward. Let's suppose I have a table with personal information (name, birth, etc) where one of the columns is an email address with varchar type. We assume that for some reason some people might not want to provide an email address. When inserting such data (without email) into the table, there are two available choices: set cell to NULL or set it to empty string (''). Let's assume that I'm aware of all the technical implications of choosing one solution over another and I can create correct SQL queries for either scenario. The problem is even when both values differ on the technical level, they are exactly the same on logical level. After looking at NULL and '' I came to a single conclusion: I don't know email address of the guy. Also no matter how hard i tried, I was not able to sent an e-mail using either NULL or empty string, so apparently most SMTP servers out there agree with my logic. So i tend to use NULL where i don't know the value and consider empty string a bad thing. After some intense discussions with colleagues i came with two questions: am I right in assuming that using empty string for an unknown value is causing a database to "lie" about the facts? To be more precise: using SQL's idea of what is value and what is not, I might come to conclusion: we have e-mail address, just by finding out it is not null. But then later on, when trying to send e-mail I'll come to contradictory conclusion: no, we don't have e-mail address, that @!#$ Database must have been lying! Is there any logical scenario in which an empty string '' could be such a good carrier of important information (besides value and no value), which would be troublesome/inefficient to store by any other way (like additional column). I've seen many posts claiming that sometimes it's good to use empty string along with real values and NULLs, but so far haven't seen a scenario that would be logical (in terms of SQL/DB design). P.S. Some people will be tempted to answer, that it is just a matter of personal taste. I don't agree. To me it is a design decision with important consequences. So i'd like to see answers where opion about this is backed by some logical and/or technical reasons.

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• Enum types, FlagAttribute & Zero value

  - by nmgomes

  We all know about Enums types and use them every single day. What is not that often used is to decorate the Enum type with the FlagsAttribute. When an Enum type has the FlagsAttribute we can assign multiple values to it and thus combine multiple information into a single enum. The enum values should be a power of two so that a bit set is achieved. Here is a typical Enum type: public enum OperationMode { /// <summary> /// No operation mode /// </summary> None = 0, /// <summary> /// Standard operation mode /// </summary> Standard = 1, /// <summary> /// Accept bubble requests mode /// </summary> Parent = 2 } In such scenario no values combination are possible. In the following scenario a default operation mode exists and combination is used: [Flags] public enum OperationMode { /// <summary> /// Asynchronous operation mode /// </summary> Async = 0, /// <summary> /// Synchronous operation mode /// </summary> Sync = 1, /// <summary> /// Accept bubble requests mode /// </summary> Parent = 2 } Now, it’s possible to do statements like: [DefaultValue(OperationMode.Async)] [TypeConverter(typeof(EnumConverter))] public OperationMode Mode { get; set; } /// <summary> /// Gets a value indicating whether this instance supports request from childrens. /// </summary> public bool IsParent { get { return (this.Mode & OperationMode.Parent) == OperationMode.Parent; } } or switch (this.Mode) { case OperationMode.Sync | OperationMode.Parent: Console.WriteLine("Sync,Parent"); break;[…]  But there is something that you should never forget: Zero is the absorber element for the bitwise AND operation. So, checking for OperationMode.Async (the Zero value) mode just like the OperationMode.Parent mode makes no sense since it will always be true: (this.Mode & 0x0) == 0x0 Instead, inverse logic should be used: OperationMode.Async = !OperationMode.Sync public bool IsAsync { get { return (this.Mode & ContentManagerOperationMode.Sync) != ContentManagerOperationMode.Sync; } } or public bool IsAsync { get { return (int)this.Mode == 0; } } Final Note: Benefits Allow multiple values combination The above samples snippets were taken from an ASP.NET control and enabled the following markup usage: <my:Control runat="server" Mode="Sync,Parent"> Drawback Zero value is the absorber element for the bitwise AND operation Be very carefully when evaluating the Zero value, either evaluate the enum value as an integer or use inverse logic.

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• sftp and public keys

  - by Lizard

  I am trying to sftp into an a server hosted by someone else. To make sure this worked I did the standard sftp [email protected] i was promted with the password and that worked fine. I am setting up a cron script to send a file once a week so have given them our public key which they claim to have added to their authorized_keys file. I now try sftp [email protected] again and I am still prompted for a password, but now the password doesn't work... Connecting to [email protected]... [email protected]'s password: Permission denied, please try again. [email protected]'s password: Permission denied, please try again. [email protected]'s password: Permission denied (publickey,password). Couldn't read packet: Connection reset by peer I did notice however that if I simply pressed enter (no password) it logged me in fine... So here are my questions: Is there a way to check what privatekey/pulbickey pair my sftp connection is using? Is it possible to specify what key pair to use? If all is setup correctly (using correct key pair and added to authorized files) why am I being asked to enter a blank password? Thanks for your help in advance! UPDATE I have just run sftp -vvv [email protected] .... debug1: Authentications that can continue: publickey,password debug3: start over, passed a different list publickey,password debug3: preferred gssapi-with-mic,publickey,keyboard-interactive,password debug3: authmethod_lookup publickey debug3: remaining preferred: keyboard-interactive,password debug3: authmethod_is_enabled publickey debug1: Next authentication method: publickey debug1: Offering public key: /root/.ssh/id_rsa debug3: send_pubkey_test debug2: we sent a publickey packet, wait for reply debug1: Server accepts key: pkalg ssh-rsa blen 277 debug2: input_userauth_pk_ok: SHA1 fp 45:1b:e7:b6:33:41:1c:bb:0f:e3:c1:0f:1b:b0:d5:e4:28:a3:3f:0e debug3: sign_and_send_pubkey debug1: read PEM private key done: type RSA debug1: Authentications that can continue: publickey,password debug1: Trying private key: /root/.ssh/id_dsa debug3: no such identity: /root/.ssh/id_dsa debug2: we did not send a packet, disable method debug3: authmethod_lookup password debug3: remaining preferred: ,password debug3: authmethod_is_enabled password debug1: Next authentication method: password It seems to suggest that it tries to use the public key... What am I missing?

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• How to Make Your Computer Press a Key Every X Seconds

  - by The Geek

  Have you ever needed to press a key every couple of seconds, or every few minutes? Perhaps you’re playing a video game and you’re waiting for an item, or you’ve got some other reason. Either way, here’s how to make your PC do it automatically. You’ll need to start by downloading and installing AutoHotkey, which is a simple scripting language that allows you to create easy scripts. Once you do that, right-click anywhere and choose New –> AutoHotkey Script. Once you’ve done that, paste the following into the script: #PersistentSetTimer, PressTheKey, 1800000Return HTG Explains: How Hackers Take Over Web Sites with SQL Injection / DDoS Use Your Android Phone to Comparison Shop: 4 Scanner Apps Reviewed How to Run Android Apps on Your Desktop the Easy Way

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• Big Data – Operational Databases Supporting Big Data – Key-Value Pair Databases and Document Databases – Day 13 of 21

  - by Pinal Dave

  In yesterday’s blog post we learned the importance of the Relational Database and NoSQL database in the Big Data Story. In this article we will understand the role of Key-Value Pair Databases and Document Databases Supporting Big Data Story. Now we will see a few of the examples of the operational databases. Relational Databases (Yesterday’s post) NoSQL Databases (Yesterday’s post) Key-Value Pair Databases (This post) Document Databases (This post) Columnar Databases (Tomorrow’s post) Graph Databases (Tomorrow’s post) Spatial Databases (Tomorrow’s post) Key Value Pair Databases Key Value Pair Databases are also known as KVP databases. A key is a field name and attribute, an identifier. The content of that field is its value, the data that is being identified and stored. They have a very simple implementation of NoSQL database concepts. They do not have schema hence they are very flexible as well as scalable. The disadvantages of Key Value Pair (KVP) database are that they do not follow ACID (Atomicity, Consistency, Isolation, Durability) properties. Additionally, it will require data architects to plan for data placement, replication as well as high availability. In KVP databases the data is stored as strings. Here is a simple example of how Key Value Database will look like: Key Value Name Pinal Dave Color Blue Twitter @pinaldave Name Nupur Dave Movie The Hero As the number of users grow in Key Value Pair databases it starts getting difficult to manage the entire database. As there is no specific schema or rules associated with the database, there are chances that database grows exponentially as well. It is very crucial to select the right Key Value Pair Database which offers an additional set of tools to manage the data and provides finer control over various business aspects of the same. Riak Rick is one of the most popular Key Value Database. It is known for its scalability and performance in high volume and velocity database. Additionally, it implements a mechanism for collection key and values which further helps to build manageable system. We will further discuss Riak in future blog posts. Key Value Databases are a good choice for social media, communities, caching layers for connecting other databases. In simpler words, whenever we required flexibility of the data storage keeping scalability in mind – KVP databases are good options to consider. Document Database There are two different kinds of document databases. 1) Full document Content (web pages, word docs etc) and 2) Storing Document Components for storage. The second types of the document database we are talking about over here. They use Javascript Object Notation (JSON) and Binary JSON for the structure of the documents. JSON is very easy to understand language and it is very easy to write for applications. There are two major structures of JSON used for Document Database – 1) Name Value Pairs and 2) Ordered List. MongoDB and CouchDB are two of the most popular Open Source NonRelational Document Database. MongoDB MongoDB databases are called collections. Each collection is build of documents and each document is composed of fields. MongoDB collections can be indexed for optimal performance. MongoDB ecosystem is highly available, supports query services as well as MapReduce. It is often used in high volume content management system. CouchDB CouchDB databases are composed of documents which consists fields and attachments (known as description). It supports ACID properties. The main attraction points of CouchDB are that it will continue to operate even though network connectivity is sketchy. Due to this nature CouchDB prefers local data storage. Document Database is a good choice of the database when users have to generate dynamic reports from elements which are changing very frequently. A good example of document usages is in real time analytics in social networking or content management system. Tomorrow In tomorrow’s blog post we will discuss about various other Operational Databases supporting Big Data. Reference: Pinal Dave (http://blog.sqlauthority.com) Filed under: Big Data, PostADay, SQL, SQL Authority, SQL Query, SQL Server, SQL Tips and Tricks, T SQL

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• A Technical Perspective On Rapid Planning

  - by Robert Story

  Upcoming WebcastTitle: A Technical Perspective On Rapid PlanningDate: April 14, 2010 Time: 11:00 am EDT, 9:00 am MDT, 8:00 am PDT, 16:00 GMT Product Family: Value Chain PlanningSummary Oracle's Strategic Network Optimization (SNO) product is a powerful supply chain design and tactical planning tool.  This one-hour session is recommended for functional users who want to gain a better understanding of how Oracle's SNO solution can help you solve complex supply chain issues, including supply chain design, risk management, logistics planning, sustainability planning, and a whole lot in between! Find out how SNO can be used to solve many different types of real-world business issues. Topics will include: Risk/Disaster Management Carbon Emissions Management Global Sourcing Labor/Workforce Planning Product Mix Optimization A short, live demonstration (only if applicable) and question and answer period will be included. Click here to register for this session....... ....... ....... ....... ....... ....... .......The above webcast is a service of the E-Business Suite Communities in My Oracle Support.For more information on other webcasts, please reference the Oracle Advisor Webcast Schedule.Click here to visit the E-Business Communities in My Oracle Support Note that all links require access to My Oracle Support.

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• Multiple Key Presses in XNA?

  - by Bryan Harrington

  I'm actually trying to do something fairly simple. I cannot get multiple key presses to work in XNA. I've tried the following pieces of code. else if (keyboardState.IsKeyDown(Keys.Down) && (keyboardState.IsKeyDown(Keys.Left))) { //Move Character South-West } and I tried. else if (keyboardState.IsKeyDown(Keys.Down)) { if (keyboardState.IsKeyDown(Keys.Left)) { //Move Character South-West } } Neither worked for me. Single presses work just fine. Any thoughts?

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• How to set x509 Certificate private key access rights for AppPoolIdentity

  - by ChrisD

  If your website uses the AppPoolIdentity and requires access to the private key of an x509Certficate, you’ll need to grant the read permissions to the iis application pool.   To grant permissions to the AppPoolIdentity: Run Certificates.MMC (or Start->run->mmc.exe, Add Certificate Snap-In for LocalMachine) Select the certificate (Personal node on the certificate tree) , right click and Manage Permissions. Add a new user to the permissions list. Enter "IIS AppPool\AppPoolName" on the local machine". Replace "AppPoolName" with the name of your application pool.

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• A Technical Perspective On Rapid Planning

  - by Robert Story

  Upcoming WebcastTitle: Strategic Network Optimization - One Solution for Many Problems!Date: April 14, 2010 Time: 11:00 am EDT, 9:00 am MDT, 8:00 am PDT, 16:00 GMT Product Family: Value Chain PlanningSummary This one-hour session is recommended for System Administrators, Database Administrators, and Technical Users seeking a general overview of Rapid Planning, installation issues, and debug information. This webcast is intended to provide users with insight into known issues, and an overview of the debugging possibilities for Rapid Planning. Topics will include: Benefits of using simulation planning Installing Oracle Rapid planning, points to be aware of Relevant tables Rapid planning log files Information needed by supportA short, live demonstration (only if applicable) and question and answer period will be included. Click here to register for this session....... ....... ....... ....... ....... ....... .......The above webcast is a service of the E-Business Suite Communities in My Oracle Support.For more information on other webcasts, please reference the Oracle Advisor Webcast Schedule.Click here to visit the E-Business Communities in My Oracle Support Note that all links require access to My Oracle Support.

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• Getting fingerprint from Apache certificate (combined with key)

  - by Alois Mahdal

  I have just created a certificate for my Apache SSL host using: make-ssl-cert /usr/share/ssl-cert/ssleay.cnf /etc/ssl/private/myhost.crt Now that is the correct way to get the fingerprint out of it? (So I can keep it in other place for visual comparison---in case I need to connect and really don't trust the network?) openssl sha1 /etc/ssl/private/myhost.crt returns different SHA1 than Opera tells me about the cert. Is this because it's combined with the key? (...or am I spoofed already? :-)).

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• Vim key mappings / plugin XCode?

  - by Daniel Upton

  I'm a developer who mostly does web stuff in ruby and C#.. I'd like to start tinkering with iOS and Mac development, Over the last few month i've been trying to get fluent in one set of key bindings (vi / vim because it just feels right).. I have the awesome ViEmu installed for visual studio on windows which gives me a ton of the vim awesomeness side by side with visual studio power toys.. Is there anything like this for xcode? I know i could set up MacVim as the default editor but i'm not too interested in this as it means losing all of xcode's cocoa awareness.. The other option of course would be to go for the lowest common denominator and switch to emacs (as the mac keybindings are based massively on emacs) but lets not think about that for too long. :P

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• Unity: Assigning a key to perform an action in the inspector

  - by Marc Pilgaard

  I am trying to write a simple piece of code in JavaScript where a button toggles the activation of a shield, by dragging a prefab with Resources.load("ActivateShieldPreFab") and destroying it again (Haven't implemented that yet). I wish to assign this button through the inspector, so I have created a string variable which appears as intended in the inspector. Though it doesn't seem to register the inspector input, even though I changed the value through the inspector. It only provides the error: "Input Key named: is unknown" When the button name is assigned within the code, there is no issues. Code as follows: var ShieldOn = false; var stringbutton : String; function Start(){ } function Update () { if(Input.GetKey(stringbutton) && ShieldOn != true) { Instantiate(Resources.load("ActivateShieldPreFab"), Vector3 (0, 0, 0), Quaternion.identity); ShieldOn = true; } }

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