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  • Qt C++ XML, validating against a DTD?

    - by Airjoe
    Is there a way to validate an XML file against a DTD with Qt's XML handling? I've tried googling around but can't seem to get a straight answer. If Qt doesn't include support for validating an XML file, what might be the process of implementing validation myself? Any good reference to start with in regards to validating XML against a spec? Thanks for the help!

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  • Redirection of xml file for iphone app

    - by gotye
    Hey guys, I have a xml file on my server like the one below : www.myWebSite.com/myXmlFile.xml which is used by my iphone application. In case the address of my xml file changes to www.myOtherWebsite.com/myXmlFile.xml How can I make my app to work anyway ? What kind of PHP server-side code do I need to write ? Is NSURLConnection supporting reirections ? Thanks for any incomings ;) Gotye.

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  • How to send raw XML in Python?

    - by davywahd
    Hi, I am trying to send raw xml to a service in Python. I have a the address of the service and my question is how would I wrap XML in python and send it to the service. The address is in the format below. 192.1100.2.2:54239 And say the XML is: <xml version="1.0" encoding="UTF-8"><header/><body><code><body/> Anyone know what to do?

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  • Is there a way to enforce/preserve order of XML elements in an XML Schema?

    - by MarcoS
    Let's consider the following XML Schema: <?xml version="1.0" encoding="UTF-8"?> <schema targetNamespace="http://www.example.org/library" elementFormDefault="qualified" xmlns="http://www.w3.org/2001/XMLSchema" xmlns:lib="http://www.example.org/library"> <element name="library" type="lib:libraryType"></element> <complexType name="libraryType"> <sequence> <element name="books" type="lib:booksType"></element> </sequence> </complexType> <complexType name="booksType"> <sequence> <element name="book" type="lib:bookType" maxOccurs="unbounded" minOccurs="1"></element> </sequence> </complexType> <complexType name="bookType"> <attribute name="title" type="string"></attribute> </complexType> </schema> and a corresponding XML example: <?xml version="1.0" encoding="UTF-8"?> <lib:library xmlns:lib="http://www.example.org/library" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://www.example.org/library src/library.xsd "> <lib:books> <lib:book title="t1"/> <lib:book title="t2"/> <lib:book title="t3"/> </lib:books> </lib:library> Is there a way to guarantee that the order of <lib:book .../> elements is preserved? I want to be sure that any parser reading the XML will return books in the specified oder, that is first the book with title="t1", then the book with title="t2", and finally the book with title="t3". As far as I know XML parsers are not required to preserve order. I wonder whether one can enforce this through XML Schema? One quick solution for me would be adding an index attribute to the <lib:book .../> element, and delegate order preservation to the application reading the XML. Comments? Suggestions?

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  • Representing xml through a single class

    - by Charles
    I am trying to abstract away the difficulties of configuring an application that we use. This application takes a xml configuration file and it can be a bit bothersome to manually edit this file, especially when we are trying to setup some automatic testing scenarios. I am finding that reading xml is nice, pretty easy, you get a network of element nodes that you can just go through and build your structures quite nicely. However I am slowly finding that the reverse is not quite so nice. I want to be able to build a xml configuration file through a single easy to use interface and because xml is composed of a system of nodes I am having a lot of struggle trying to maintain the 'easy' part. Does anyone know of any examples or samples that easily and intuitively build xml files without declaring a bunch of element type classes and expect the user to build the network themselves? For example if my desired xml output is like so <cook version="1.1"> <recipe name="chocolate chip cookie"> <ingredients> <ingredient name="flour" amount="2" units="cups"/> <ingredient name="eggs" amount="2" units="" /> <ingredient name="cooking chocolate" amount="5" units="cups" /> </ingredients> <directions> <direction name="step 1">Preheat oven</direction> <direction name="step 2">Mix flour, egg, and chocolate</direction> <direction name="step 2">bake</direction> </directions> </recipe> <recipe name="hot dog"> ... How would I go about designing a class to build that network of elements and make one easy to use interface for creating recipes? Right now I have a recipe object, an ingredient object, and a direction object. The user must make each one, set the attributes in the class and attach them to the root object which assembles the xml elements and outputs the formatted xml. Its not very pretty and I just know there has to be a better way. I am using python so bonus points for pythonic solutions

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  • Unable to Export contents of Data table (with French formatted Numbers ) to XML

    - by Ananth
    I have a data Table with numbers formatted according to the current regional settings. ie ( in French decimal separators are ',' instead of '.' in English). I need to export it to XML. Numbers in XML needs to be formatted according to the current regional settings.But now numbers in XML are formatted in English.Is there any way to make the number formatting in XML according to current regional settings ( or based on the locale of the Data Table) during the exporting process ?

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  • Flex - How to edit a xml file on the server

    - by BS_C3
    Hi! I was wondering if it was possible to edit an xml on the server side from a web based flex application. When you use XML files in a Flex application and then compile it to upload it in the server, Flex Buidler generates a swf file with the xml data embedded. How should I do to have access to those XML files?? Thanks for your answers. Regards. BS_C3

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  • utf8 format in xml

    - by hussain
    i want to know how to store this è (this type of symbols) in xml file if i store this symbol in xml file.. the file shows this symbol like ? i was inserted in front of xml file is <?xml version="1.0" encoding="UTF-8"?> but that doest not shows correct thanks and advance

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  • Boost and XML (c++)

    - by Nuno
    Hi, Is there any good way (and a simple way too) using boost to read and write xml files? I can't seem to find any simple sample to read xml files using boost? (can you point me some simple sample that use boost for reading and writing xml files) If not boost, is out there any good and simple library to read and write xml files that you can recommend? (it must be a c++ library) Thanks Nuno

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  • Parsing xml with jQuery in IE6/7 issue

    - by Alexander Corotchi
    Hi, I have some problem with parsing XML in Ie6/7(original 7 no compatible mode). On Another normal browsers it works. Jquery code: $.ajax({ type: "GET", url: "test.xml", dataType: "html", success: function(xml) { $(xml).find('quoteresult').each(function(){ var bid = $(this).find('bid').text(); alert(bid); }); } }); I can't understand what is wrong ! Thanks

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  • passing data to and from server using xml

    - by sapna
    i need to design a web site in which data is passed to and from the server using xml.i got it how to transform data from database to xml and then to html.but i am not able to find how to pass data from client to server using xml.webpages are designed using asp.is it possible to do pass data from client to server using xml.what are the things that are to be studied.help needed immediately.

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  • XSLT 2.0 Header Leaks into Transformed XML

    - by user1303797
    First, a thank you in advance. Second, this is my first post so apologies for any errors or wrongdoings. I am a noob w/ xml and xslt, and can't seem to figure this out. When I transform some xml using xslt 2.0, some of the headers from the xslt leaks into the new xml. It doesn't seem to do it in xslt 1.0 (granted the xslt is a little different). Here is the xml: <?xml version="1.0" encoding="ISO-8859-1" ?> <xml_content> <feed_name>feed</feed_name> <feed_info> <entry_1> <id>1</id> <pub_date>1320814800</pub_date> </entry_1> </feed_info> </xml_content> Here is the xslt: <xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns="http://www.w3.org/TR/xhtml1/strict"> <xsl:output method="xml" indent="yes" /> <xsl:template match="xml_content"> <Records> <xsl:for-each select="feed_info/entry_1"> <Record> <ID><xsl:value-of select="id" /></ID> <PublicationDate><xsl:value-of select='xs:dateTime("1970-01-01T00:00:00") + xs:integer(pub_date) * xs:dayTimeDuration("PT1S")'/></PublicationDate> </Record> </xsl:for-each> </Records> </xsl:template> </xsl:stylesheet> Here is the new xml. Look specifically at the first "Records" element. <?xml version="1.0" encoding="UTF-8"?> <Records xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns="http://www.w3.org/TR/xhtml1/strict"> <Record> <ID>1</ID> <PublicationDate>2011-11-09T05:00:00</PublicationDate> </Record> </Records>

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  • SQL Server 2008 2mb Limit for XML??

    - by Nai
    I am trying to output a long XML result from SMSS. When I right click on the results and 'save results as...', I can only get a 2mb file? I have changed the settings in SMSS via Tools - Options - Query Results - SQL Server - Results to Grid, for XML data to be unlimited. Forever, it still seems to be truncating my XML results? So, how can I bypass this problem and output my XML result to a file? Thanks

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  • Url rewriting : prevent to display xml

    - by Frank
    Edit : I've got an aspx file (default.aspx) that loads a flash file (index.swf), but this swf needs a xml file (foo.xml) to load correctly. However, I would like to block any request aiming directly at the xml file. Is it possible, using a rewritting engine (isapi_rewrite for example) to detect if the xml file is being 'hotlinked' or being loaded by the 'index.swf'(inside default.aspx)? Any ideas? Thank you.

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  • What is the best way to modify a few fields in an XML using Java

    - by Kailas J C
    I have a big XML which contains around 300 elements. I need to modify 2 or 3 elements in this xml using Java. I don't want to go for conventional marshalling and unmarshalling as it involves the parsing of the whole XML. How is XPath/XSLT manipulation? I know that I can easily read the data but i need to modify the same and put in back in the same XML. The primary concern here is performance. Kindly advise

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  • Reading embedded XML file c#

    - by Pila
    How can I read from an embedded XML file - an XML file that is part of a c# project? I've added a XML file to my project and I want to read from it. I want the XML file to compile with the project because I don't want that it will be a resource which the user can see. Any idea?

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  • 'ErrorMessageResourceType' property specified was not found. on XmlSerialise

    - by Redeemed1
    In my ASP.Net MVC app I have a Model layer which uses localised validation annotations on business objects. The code looks like this: [XmlRoot("Item")] public class ItemBo : BusinessObjectBase { [Required(ErrorMessageResourceName = "RequiredField", ErrorMessageResourceType = typeof(StringResource))] [HelpPrompt("ItemNumber")] public long ItemNumber { get; set; } This works well. When I want to serialise the object to xml I get the error: "'ErrorMessageResourceType' property specified was not found" (although it is lost beneath other errors, it is the innerexception I am trying to work on. The problem therefore is the use of the DataAnnotations attributes. The relevant resource files are in another assembly and are marked as 'public' and as I said everything works well until I get to serialisation. I have references to the relevant DataAnnotations class etc in my nunit tests and target class. By the way, the HelpPrompt is another data annotation I have defined elsewhere and is not causing the problem. Furthermore if I change the Required attribute to the standard format as follows, the serialisation works ok. [Required(ErrorMessage="Error")] Can anyone help me?

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  • Deserializing XML to Objects in C#

    - by Justin Bozonier
    So I have xml that looks like this: <todo-list> <id type="integer">#{id}</id> <name>#{name}</name> <description>#{description}</description> <project-id type="integer">#{project_id}</project-id> <milestone-id type="integer">#{milestone_id}</milestone-id> <position type="integer">#{position}</position> <!-- if user can see private lists --> <private type="boolean">#{private}</private> <!-- if the account supports time tracking --> <tracked type="boolean">#{tracked}</tracked> <!-- if todo-items are included in the response --> <todo-items type="array"> <todo-item> ... </todo-item> <todo-item> ... </todo-item> ... </todo-items> </todo-list> How would I go about using .NET's serialization library to deserialize this into C# objects? Currently I'm using reflection and I map between the xml and my objects using the naming conventions.

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  • Xml files stop being served by IIS6 after allowing .net to process the .xml extension

    - by Brian Surowiec
    I added a route into my site to allow for a sitemap and everything worked fine in IIS7 but once I deployed the route stopped working. Since the live server is running IIS6 I needed to put a new mapping in for .xml to be processed by .net and then it started to work. My issue though is on every other xml file on the site now. I keep getting a 404 error when trying to view xml files, but the sitemap.xml route works. Is this a routing issue or an IIS setup issue? Here are my routes if it will help routes.IgnoreRoute("{resource}.axd/{*pathInfo}"); routes.MapRoute( "Gallery-Group-View", "Projects/{groupId}", new { controller = "Gallery", action = "GalleryList", groupId = "" }); routes.MapRoute( "Gallery-List-View", "Projects/{groupId}/{galleryId}", new { controller = "Gallery", action = "GalleryView", groupId = "", galleryId = "" }); routes.MapRoute( "Sitemap", "Sitemap.xml", new { controller = "XML", action = "Sitemap" } ); routes.MapRoute( "Default", "{controller}/{action}/{id}", new { controller = "Home", action = "Index", id = "" } );

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  • Collectable<T> serialization, Root Namespaces on T in .xml files.

    - by Stacey
    I have a Repository Class with the following method... public T Single<T>(Predicate<T> expression) { using (var list = (Models.Collectable<T>)System.Xml.Serializer.Deserialize(typeof(Models.Collectable<T>), FileName)) { return list.Find(expression); } } Where Collectable is defined.. [Serializable] public class Collectable<T> : List<T>, IDisposable { public Collectable() { } public void Dispose() { } } And an Item that uses it is defined.. [Serializable] [System.Xml.Serialization.XmlRoot("Titles")] public partial class Titles : Collectable<Title> { } The problem is when I call the method, it expects "Collectable" to be the XmlRoot, but the XmlRoot is "Titles" (all of object Title). I have several classes that are collected in .xml files like this, but it seems pointless to rewrite the basic methods for loading each up when the generic accessors do it - but how can I enforce the proper root name for each file without hard coding methods for each one? The [System.Xml.Serialization.XmlRoot] seems to be ignored.

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  • Storing a big xml string in a xml document in java

    - by shyam R
    Hi All, I Have a Java object which I am converting into a xml file. I am getting a big xml file here after converting java object. I am capturing that converted xml file in a string like below String ouputXML = xmlfile; Noe If I pring the ouputXML on the console of IBM RSA in the proper format only it is printing but my requirement is I need to redirect outputXML in to an XML instead of printing in IBm RSA console. I am able to do this but the problem is if I open the craetd XML file the xml structure is not proper , it is showing so many special characters . Please help me !!

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  • Why does JAXB not create a member variable in its generated code when an XML schema base type and subtype have the same element declared in them?

    - by belltower
    I have a question regarding with regard to JAXB generated classes. As you can I see, I have a complex type, DG_PaymentIdentification1, declared in my schema. Its a restriction of PaymentIdentification1. DG_PaymentIdentification1 is also identical to PaymentIdentification1. I also have a type called DG_CreditTransferTransactionInformation10 which has a base type of CreditTransferTransactionInformation10 and is identical to it. I have included the relevant XML schema snippets below. <xs:complexType name="DG_PaymentIdentification1"> <xs:complexContent> <xs:restriction base="PaymentIdentification1"> <xs:sequence> <xs:element name="InstrId" type="DG_Max35Text_REF" minOccurs="0"/> <xs:element name="EndToEndId" type="DG_Max35Text_REF" id="DG-41"/> </xs:sequence> </xs:restriction> </xs:complexContent> </xs:complexType> <xs:complexType name="PaymentIdentification1"> <xs:sequence> <xs:element name="InstrId" type="Max35Text" minOccurs="0"/> <xs:element name="EndToEndId" type="Max35Text"/> </xs:sequence> </xs:complexType> <xs:complexType name="DG_CreditTransferTransactionInformation10"> <xs:complexContent> <xs:restriction base="CreditTransferTransactionInformation10"> <xs:sequence> <xs:element name="PmtId" type="DG_PaymentIdentification1"/> <xs:simpleType name="DG_Max35Text_REF"> <xs:restriction base="DG_NotEmpty35"> <xs:pattern value="[\-A-Za-z0-9\+/\?:\(\)\.,'&#x20;]*"/> </xs:restriction> </xs:simpleType> <xs:simpleType name="Max35Text"> <xs:restriction base="xs:string"> <xs:minLength value="1"/> <xs:maxLength value="35"/> </xs:restriction> </xs:simpleType> JAXB generates the following java class for DG_PaymentIdentification1: @XmlAccessorType(XmlAccessType.FIELD) @XmlType(name = "DG_CreditTransferTransactionInformDGion10") public class DGCreditTransferTransactionInformation10 extends CreditTransferTransactionInformation10 { } My question is why doesnt the DGCreditTransferTransactionInformation10 generated class have a variable of type DG_PaymentIdentification1 in the generated code? The base class CreditTransferTransactionInformation10 does have a type PaymentIdentification1 declared in it. Is there any way of ensuring that DGCreditTransferTransactionInformation10 will have a DG_PaymentIdentification1 in it?

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  • Writing xml with powershell

    - by alex
    i have a script that get all the info i need about my SharePoint farm : [System.Reflection.Assembly]::LoadWithPartialName("Microsoft.SharePoint") > $null $farm = [Microsoft.SharePoint.Administration.SPFarm]::Local $websvcs = $farm.Services | where -FilterScript {$_.GetType() -eq [Microsoft.SharePoint.Administration.SPWebService]} $webapps = @() foreach ($websvc in $websvcs) { write-output "Web Applications" write-output "" foreach ($webapp in $websvc.WebApplications) { write-output "Webapp Name -->"$webapp.Name write-output "" write-output "Site Collections" write-output "" foreach ($site in $webapp.Sites) { write-output "Site URL --> -->" $site.URL write-output "" write-output "Websites" write-output "" foreach ($web in $site.AllWebs) { write-output "Web URL --> --> -->" $web.URL write-output "" write-output "Lists" write-output "" foreach ($list in $web.Lists) { write-output "List Title --> --> --> -->" $list.Title write-output "" } foreach ($group in $web.Groups) { write-output "Group Name --> --> --> -->" $group.Name write-output "" foreach ($user in $group.Users) { write-output "User Name --> --> --> -->" $user.Name write-output "" } } } } } } i want to make the output to an XML file and then connect the xml file to HTML and make a site of it for manager use how can i do it ? thanks for the help !

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  • Mac - KeyRemap4MacBook - Custom XML

    - by DjRikyx
    I hope someone of you know this powerfull Pref Panel to remap the keyboard.. Since i'm using a PC Keyboard, i wanted to make Screenshot a bit easy to do.. I managed to get working: -Command+Shift+3 to Stamp (full screen screenshot) -Command+Shift+4 to Control+Stamp (Selection Cursor Screenshot) Now i want to remap Shift+Stamp to Command+Shift+4+Space to get Windows Screenshot.. i tried but nothing was working.. Here is my current XML.. i only need to add the last remap! <?xml version="1.0"?> <root> <item> <name>Custom PC Style Screenshot</name> <appendix>Command+Shift_L+4+Space to Shift+F13</appendix> <appendix>Command+Shift_L+4 to Control+F13</appendix> <appendix>Command+Shift_L+3 to F13</appendix> <identifier>private.custom_pc_style_screenshot</identifier> <autogen></autogen> <autogen>--KeyToKey-- KeyCode::F13, VK_CONTROL, KeyCode::KEY_4, ModifierFlag::COMMAND_L | ModifierFlag::SHIFT_L</autogen> <autogen>--KeyToKey-- KeyCode::F13, KeyCode::KEY_3, ModifierFlag::COMMAND_L | ModifierFlag::SHIFT_L</autogen> Hope someone of you can help me out! Thank you

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