Search Results

Search found 11421 results on 457 pages for 'zend db'.

Page 35/457 | < Previous Page | 31 32 33 34 35 36 37 38 39 40 41 42  | Next Page >

  • Zend_Dojo_Form not rendering in layout

    - by Grant Collins
    Hi, I have a quick question about adding Zend_Dojo_Form into Zend_layouts. I have a Zend_Dojo_Form that I want to display in the layout that is used for a particular controller. I can add the form to the layout without any issue however the dojo elements fail to render, as they would do if I added the form to a standard view. Is there any reason why this would be the case? Do I need to do something to the layout so that it will enable the components for this embedded form in the layout. Any other dojo enabled forms that are added in the view using this layout work fine. My form is created in the usual way: class QuickAddJobForm extends Zend_Dojo_Form{ public function init(){ $this->setName('quickaddjobfrm') ->setMethod('post') ->setAction('/addjob/start/); /*We now create the elements*/ $jobTitle = new Zend_Dojo_Form_Element_TextBox('jobtitle', array( 'trim' => true ) ); $jobTitle->setAttrib('style', 'width:200px;') ->addFilter('StripTags') ->removeDecorator('DtDdWrapper') ->removeDecorator('HtmlTag') ->removeDecorator('Label'); .... $this->addElements(array($jobTitle, ....)); In the controller I declare the layout and the form in the init function: public function init(){ $this->_helper->layout->setLayout('add-layout'); $form = new QuickAddJobForm(); $form->setDecorators(array(array('ViewScript', array('viewScript' => 'quickAddJobFormDecorator.phtml')))); $this->_helper->layout()->quickaddjob = $form; In my layout Where I want the form I have: echo $this->layout()->quickaddjob; Why would adding this form in the layout fail to render/add the Dojo elements? All that is currently being displayed are text boxes, rather than some of the other components such as ComboBoxes/FilteringSelects etc... Thanks in advance.

    Read the article

  • Trying to understand the Zend_Auth OpenId

    - by Will Olbrys
    I'm using a slightly modified version of the Zend_Auth_OpenId classes to get openid logins from google apps. The results are very positive, as I seem to be getting successful results from Google. I cannot get successful results passed to Zend_Auth, though. For example, Zend_Auth_Adapter_OpenId on line 241: if (!$consumer->login($id, $this->_returnTo, $this->_root, $this->_extensions, $this->_response)) { return new Zend_Auth_Result( Zend_Auth_Result::FAILURE, $id, array("Authentication failed", $consumer->getError())); } The consumer calls login() which in turn calls the private method _checkId() in Zend_OpenId_Consumer. _checkId() always ends in redirecting to the openid server. How is this ever supposed to return a valid Zend_Auth_Result object? I'm pretty close to giving up and trying to implement another OpenId library, but I'm so close to just making this work. I must be missing something so obvious! Maybe I don't understand how openid works exactly, but if someone could help me understand I would really appreciate it.

    Read the article

  • Zend_Form setMultiFile()

    - by Cristian
    Hello everyone, i got a question related to the setMultiFile method of zend_form. I already got a form like this: $foto->setLabel('Foto:'); $foto->addValidator('IsImage', true); $foto->addValidator('Count', true, 12); $foto->addValidator('Extension', true, 'gif,png,jpg'); $foto->setDestination(PUBLIC_PATH.'/upload/img/'); $foto->addFilter('Rename', array( 'target' => PUBLIC_PATH.'/upload/img/', 'overwrite' => true )); $foto->addDecorators(array( array('Description',array('tag'=>'','escape'=>false)) )); And it's everything working...but now i need to iterate each element to set a description and decorators...any suggestions ? Thanks to everyone that will reply to this, i'm drivin crazy with that..

    Read the article

  • ??????:???????:Oracle DB?????????????????·???

    - by Yusuke.Yamamoto
    PS???????????????????:Oracle DB?????????????????·????2???????????? ??????????????????????????????????????????????????????????? Togetter - ???????:Oracle DB?????????????????·??? ??????????????????????????·???????????????????????????? ???DBA???????????????????????????????????????? ?????????????????????(@yoshikaw?????????????!)? Oracle?????????????(Part1) - Keep It Simple, Stupid Oracle?????????????(Part2) - Keep It Simple, Stupid ??????????????????????????(????????)? Oracle Database ??????????? Oracle Ace ? ORACLE MASTER Platinum ????????????????????????????????? Oracle?????????????? - ??????????????????????? ????????????????????? oracletech.jp ????????????

    Read the article

  • Where do I put inline script in head with Zend Framework?

    - by Joel
    I'm reading the manual here: http://zendframework.com/manual/en/zend.view.helpers.html but I'm still confused. I have a script in my head that I'm converting to the layout/view for the Zend MVC: <script type="text/javascript"> var embedCode = '<object data="http://example.com" type="application/x-shockwave-flash" height="385" width="475"><param name="src" value="http://example.com" /><param name="allowfullscreen" value="true" /></object>' </script> I first tried to add it is an external file like this (in layout): $this->headScript()->appendFile('js/embeddedVideo.js')->appendScript($onloadScript); <head> <?php echo $this->headScript(); ?> </head> Didn't really work, but anyway, I'm wanting to just add the script and not add it as an external file. How do I do that? Thanks!

    Read the article

  • How to retrieve an url parameter in the Zend Framework ?

    - by ismaelsow
    Hello guys ! I'am trying to retrieve an parameter passed in a url using the zend framework. But of course, it is not working ! My code looks like this : Generating the url : <?php echo $this->url(array('controller' => 'poll', 'action' => 'showresults', 'poll_id' => $poll['_id']), null, true) ?> Retrieving the "poll_id" parameter in showresultsAction() : $request = new Zend_Controller_Request_Http(); $poll_id = $request->getParam('poll_id'); The problem is that $poll_id is NULL. When I do a var_dump of $request-getParams(), it is also NULL. I have glanced trough the Zend Framework doc, but it was not very usefull. Any idea ? Thanks !

    Read the article

  • Highlights from recent Yammer video

    - by Eric Jensen
    Normal 0 false false false EN-US X-NONE X-NONE MicrosoftInternetExplorer4 /* Style Definitions */ table.MsoNormalTable {mso-style-name:"Table Normal"; mso-tstyle-rowband-size:0; mso-tstyle-colband-size:0; mso-style-noshow:yes; mso-style-priority:99; mso-style-qformat:yes; mso-style-parent:""; mso-padding-alt:0in 5.4pt 0in 5.4pt; mso-para-margin-top:0in; mso-para-margin-right:0in; mso-para-margin-bottom:10.0pt; mso-para-margin-left:0in; line-height:115%; mso-pagination:widow-orphan; font-size:11.0pt; font-family:"Calibri","sans-serif"; mso-ascii-font-family:Calibri; mso-ascii-theme-font:minor-latin; mso-hansi-font-family:Calibri; mso-hansi-theme-font:minor-latin;} A few weeks back, Ryan Kennedy of Yammer gave a talk about Berkeley DB Java Edition. You can find it posted here on Alex Popescu's Blog, or go directly to the video post itself. It was full of useful nuggets of information, such as why they chose to use BDB JE, performance, and some tips & tricks at the end. At over 40 minutes, the video is quite long. Ryan is an entertaining speaker, so I suggest you watch all of it. But if you only have time for the highlights, here are some times you can sync to:  06:18 hear the Berkeley DB JE features that caused Yammer select it, including: replication auto leader election, failover configurable durability and consistency guarantees 23:10 System performance characteristics 35:08 Check out the tips and tricks for using Berkeley DB JE I know the Berkeley DB development team is very pleased that BDB JE is working out well for Yammer. We definitely encourage others out there to take note of this success, especially if your requirements are similar to Yammer's (which Ryan outlines at the beginning of his talk)

    Read the article

  • Apache refusing to change DocumentRoot

    - by mingos
    I've installed Zend Server CE 5.1.0 on Windows 7 Ultimate 64 bit in its default location, meaning the path to my htdocs is C:\Program Files (x86)\Zend\Apache2\htdocs. Not something that I would like to type each time I check out a project from SVN in Eclipse or something. I'd like to set the DocumentRoot to a different folder, namely D:\www. What I've done I edited conf/httpd.conf, with the significant lines being: DocumentRoot "D:\www" <Directory "D:\www"> Options Indexes FollowSymLinks AllowOverride All Order allow,deny Allow from all </Directory> Include conf/extra/httpd-vhosts.conf I edited conf/extra/httpd-vhosts.conf to add a virtual host: NameVirtualHost *:80 <VirtualHost *:80> DocumentRoot D:\www ServerName localhost ServerAlias localhost SetEnv APPLICATION_ENV development SetEnv APPLICATION_DOMAIN localhost </VirtualHost> <VirtualHost *:80> DocumentRoot D:\www\UmbraCMS ServerName umbracms.local ServerAlias umbracms.local SetEnv APPLICATION_ENV development SetEnv APPLICATION_DOMAIN umbracms.local </VirtualHost> I edited C:\Windows\System32\drivers\etc\hosts to add this line: 127.0.0.1 umbracms.local And I also added a PHP project to D:\www\UmbraCMS. And restarted Apache. Actually, I restarted the computer, too, just in case. What's supposed to happen After typing http://umbracms.local/ in the browser's address bar, I want to see my PHP project launch, obviously. What's actually happening No matter whether whether I type http://umbracms.local/ or http://localhost/, I'm taken to the test zend page, located in C:\Program Files (x86)\Zend\Apache2\htdocs\index.html, as if neither DocumentRoot was changed nor name-based virtual hosting worked. Interestingly, when I put another project in C:\Program Files (x86)\Zend\Apache2\htdocs\bugraid\ and then, in the browser, typed http://localhost/bugraid, the project actually opened, or at least tried to, as it completely ignored the project's .htaccess file. Extra considerations Zend Server's Apache version is 2.2.16, PHP version is 5.3.0 I've installed MySQL CE 5.5.13 separately, and it works, both from command line and via MySQL Workbench. I have XAMPP installed, but none of its components are started up. It's got its own install of Apache 2.2.17 and MySQL 5.5.1. PHP version is 5.3.5 (I think). Question Have you had a similar situation before? What else might need taking care of in order to have Zend Server's Apache use D:\www as document root for my PHP projects?

    Read the article

  • How to use filegroups for DB split?

    - by Robin Jain
    In my project I have one DB used for everything. I want it to break into two databases. Static tables having look up values are to be stored in one DB and another DB would be having tables with dynamic data. My problem is that how would I use foreign key constraint in between those two DBs. Can someone help me out and suggest a way to proceed, better if I'm provided an example for the same. I thought of using synonyms for tables and then constraints on synonyms. but later I came to know that synonyms couldn't be used for constraints. I need to maintain relationships among the tables from both DB as the issue is with update, with a new release I just want to update look up tables and for the same I want to split my DB. I want to know how FileGroups could be used for this.

    Read the article

  • Database Web Service using Toplink DB Provider

    - by Vishal Jain
    With JDeveloper 11gR2 you can now create database based web services using JAX-WS Provider. The key differences between this and the already existing PL/SQL Web Services support is:Based on JAX-WS ProviderSupports SQL Queries for creating Web ServicesSupports Table CRUD OperationsThis is present as a new option in the New Gallery under 'Web Services'When you invoke the New Gallery option, it present you with three options to choose from:In this entry I will explain the options of creating service based on SQL queries and Table CRUD operations.SQL Query based Service When you select this option, on 'Next' page it asks you for the DB Conn details. You can also choose if you want SOAP 1.1 or 1.2 format. For this example, I will proceed with SOAP 1.1, the default option.On the Next page, you can give the SQL query. The wizard support Bind Variables, so you can parametrize your queries. Give "?" as a input parameter you want to give at runtime, and the "Bind Variables" button will get enabled. Here you can specify the name and type of the variable.Finish the wizard. Now you can test your service in Analyzer:See that the bind variable specified comes as a input parameter in the Analyzer Input Form:CRUD OperationsFor this, At Step 2 of Wizard, select the radio button "Generate Table CRUD Service Provider"At the next step, select the DB Connection and the table for which you want to generate the default set of operations:Finish the Wizard. Now, run the service in Analyzer for a quick check.See that all the basic operations are exposed:

    Read the article

  • Oracle DB, Oracle ADF, GlassFish, JDeveloper, NetBeans IDE

    - by Geertjan
    Today I started some experiments with Oracle guru Steven Davelaar, who lives about 20 minutes away from my place in Amsterdam by underground. Very convenient. He showed me a bunch of things in JDeveloper, while I showed him a bunch of things in NetBeans IDE. He managed to deploy an ADF application to GlassFish in JDeveloper. And, so far, I failed to do the same thing in NetBeans IDE. Quite a few (around 100) JARs are needed, aside from the question of correctly setting up or importing an ADF application, and we're still figuring out which and who and when and where. And how. And if. And why. Nonetheless, I did manage to get Oracle DB set up in NetBeans IDE, after downloading it from here: http://www.oracle.com/technetwork/products/express-edition/downloads/index.html Here's what it looks like when registered in NetBeans IDE, i.e., notice that I have a cool sample database available:   Data from the above database I managed to display very easily via the various NetBeans code generators in a PrimeFaces application, exactly as has been done many times in demonstrations and tutorials everywhere, i.e., generate JPA entities, then create an EJB, then inject the EJB into a PrimeFaces data table: The next step is to somehow do the same with ADF in NetBeans IDE. I had some trouble with passwords for Oracle DB, the command line (with Steven's help) proved helpful: Wish us luck as we continue our ADF-inspired journey. This blog entry by Shay is also relevant: Deploying Oracle ADF Essentials Applications to Glassfish

    Read the article

  • Call DB Stored Procedure using @NamedStoredProcedureQuery Injection

    - by anwilson
    Oracle Database Stored Procedure can be called from EJB business layer to perform complex DB specific operations. This approach will avoid overhead from frequent network hits which could impact end-user result. DB Stored Procedure can be invoked from EJB Session Bean business logic using org.eclipse.persistence.queries.StoredProcedureCall API. Using this approach requires more coding to handle the Session and Arguments of the Stored Procedure, thereby increasing effort on maintenance. EJB 3.0 introduces @NamedStoredProcedureQuery Injection to call Database Stored Procedure as NamedQueries. This blog will take you through the steps to call Oracle Database Stored Procedure using @NamedStoredProcedureQuery.EMP_SAL_INCREMENT procedure available in HR schema will be used in this sample.Create Entity from EMPLOYEES table.Add @NamedStoredProcedureQuery above @NamedQueries to Employees.java with definition as given below - @NamedStoredProcedureQuery(name="Employees.increaseEmpSal", procedureName = "EMP_SAL_INCREMENT", resultClass=void.class, resultSetMapping = "", returnsResultSet = false, parameters = { @StoredProcedureParameter(name = "EMP_ID", queryParameter = "EMPID"), @StoredProcedureParameter(name = "SAL_INCR", queryParameter = "SALINCR")} ) Observe how Stored Procedure's arguments are handled easily in  @NamedStoredProcedureQuery using @StoredProcedureParameter.Expose Entity Bean by creating a Session Facade.Business method need to be added to Session Bean to access the Stored Procedure exposed as NamedQuery. public void salaryRaise(Long empId, Long salIncrease) throws Exception { try{ Query query = em.createNamedQuery("Employees.increaseEmpSal"); query.setParameter("EMPID", empId); query.setParameter("SALINCR", salIncrease); query.executeUpdate(); } catch(Exception ex){ throw ex; } } Expose business method through Session Bean Remote Interface. void salaryRaise(Long empId, Long salIncrease) throws Exception; Session Bean Client is required to invoke the method exposed through remote interface.Call exposed method in Session Bean Client main method. final Context context = getInitialContext(); SessionEJB sessionEJB = (SessionEJB)context.lookup("Your-JNDI-lookup"); sessionEJB.salaryRaise(new Long(200), new Long(1000)); Deploy Session BeanRun Session Bean Client.Salary of Employee with Id 200 will be increased by 1000.

    Read the article

  • Compiling Gearman extension for PHP on OS-X Snow Leopard with Zend Server Community Edition

    - by GrumpyCanuck
    I was wondering if anyone else has figured out how to solve this problem. Whether I install the extension via PECL or compile it by hand, I get the same error: PHP Warning: PHP Startup: Unable to load dynamic library '/usr/local/zend/lib/php_extensions/gearman.so' - dlopen(/usr/local/zend/lib/php_extensions/gearman.so, 9): no suitable image found. Did find: /usr/local/zend/lib/php_extensions/gearman.so: mach-o, but wrong architecture in Unknown on line 0 I have no idea how to fix this problem and I can only bang my head into my desk so many times.

    Read the article

  • rake db:create not working for legacy rails app (2.3.5) using MySQL (5.5.28)

    - by ridicter
    I'm a new Rails Developer, and I'm working on a legacy Rails app. Whenever I run the rake db:create command, I get an error that the database couldn't be created. I have found many StackOverflow questions related to this, but in troubleshooting nearly all permutations of solutions, I couldn't resolve the issue. I created the three Dbs (dev, prod, test), created the user with all access privileges to these dbs, and ran rake db:create. I'm running Mac OS X Lion, MySQL 5.5.28, Rails 2.3.5, Ruby 1.8.7. Here are my settings development: adapter: mysql encoding: utf8 database: adva_development username: adva password: **** host: localhost socket: /tmp/mysql.sock Here's the error: Couldn't create database for {"adapter"=>"mysql", "username"=>"adva", "host"=>"localhost", "encoding"=>"utf8", "database"=>"adva_development", "socket"=>"/tmp/mysql.sock", "password"=>"****"}, charset: utf8, collation: utf8_unicode_ci (if you set the charset manually, make sure you have a matching collation) I have done the following troubleshooting: Verified user and password are correct, and the user has access to the DB. (Double checked user access with SELECT * FROM mysql.db WHERE Db = 'adva_development' \G; User has all privileges.) Verify the socket is correct. I don't really understand sockets, but I can plainly see it at /tmp/mysql.sock. Checked collation and character set. I found out I had created the DB in latin charset and collation, so I recreated them. I ran show variables like "collation_database"; and show variables like "character_set_database"; and came back with utf8 and utf8_unicode_ci respectively. I followed the instructions in this question. After uninstalling mysql gem, I ran the following but came up with the same error: gem install --no-rdoc --no-ri mysql -- --with-mysql-dir=/usr/local/mysql-5.5.28-osx10.6-x86_64/bin --with-mysql-config=/usr/local/mysql-5.5.28-osx10.6-x86_64/bin/mysql_config Following Matt's suggestion, here's what a rake --trace db:create reveals: ** Invoke db:create (first_time) ** Invoke db:load_config (first_time) ** Invoke rails_env (first_time) ** Execute rails_env ** Execute db:load_config ** Execute db:create Couldn't create database for {"database"=>"adva_development", "adapter"=>"mysql", "host"=>"127.0.0.1", "password"=>"woof2adva", "username"=>"adva", "encoding"=>"utf8"}, charset: utf8, collation: utf8_unicode_ci (if you set the charset manually, make sure you have a matching collation) After 3 days and six or seven hours, I have pretty much run out of options. I tried various random things, like replacing localhost with 127.0.0.1 to no avail. Could there be something wrong related to my specific environment? Mac OS X Lion + MySQL 5.5.28? I plan on trying on setting up everything in a Linux environment. Thanks!

    Read the article

  • SQL SERVER – Example of Performance Tuning for Advanced Users with DB Optimizer

    - by Pinal Dave
    Performance tuning is such a subject that everyone wants to master it. In beginning everybody is at a novice level and spend lots of time learning how to master the art of performance tuning. However, as we progress further the tuning of the system keeps on getting very difficult. I have understood in my early career there should be no need of ego in the technology field. There are always better solutions and better ideas out there and we should not resist them. Instead of resisting the change and new wave I personally adopt it. Here is a similar example, as I personally progress to the master level of performance tuning, I face that it is getting harder to come up with optimal solutions. In such scenarios I rely on various tools to teach me how I can do things better. Once I learn about tools, I am often able to come up with better solutions when I face the similar situation next time. A few days ago I had received a query where the user wanted to tune it further to get the maximum out of the performance. I have re-written the similar query with the help of AdventureWorks sample database. SELECT * FROM HumanResources.Employee e INNER JOIN HumanResources.EmployeeDepartmentHistory edh ON e.BusinessEntityID = edh.BusinessEntityID INNER JOIN HumanResources.Shift s ON edh.ShiftID = s.ShiftID; User had similar query to above query was used in very critical report and wanted to get best out of the query. When I looked at the query – here were my initial thoughts Use only column in the select statements as much as you want in the application Let us look at the query pattern and data workload and find out the optimal index for it Before I give further solutions I was told by the user that they need all the columns from all the tables and creating index was not allowed in their system. He can only re-write queries or use hints to further tune this query. Now I was in the constraint box – I believe * was not a great idea but if they wanted all the columns, I believe we can’t do much besides using *. Additionally, if I cannot create a further index, I must come up with some creative way to write this query. I personally do not like to use hints in my application but there are cases when hints work out magically and gives optimal solutions. Finally, I decided to use Embarcadero’s DB Optimizer. It is a fantastic tool and very helpful when it is about performance tuning. I have previously explained how it works over here. First open DBOptimizer and open Tuning Job from File >> New >> Tuning Job. Once you open DBOptimizer Tuning Job follow the various steps indicates in the following diagram. Essentially we will take our original script and will paste that into Step 1: New SQL Text and right after that we will enable Step 2 for Generating Various cases, Step 3 for Detailed Analysis and Step 4 for Executing each generated case. Finally we will click on Analysis in Step 5 which will generate the report detailed analysis in the result pan. The detailed pan looks like. It generates various cases of T-SQL based on the original query. It applies various hints and available hints to the query and generate various execution plans of the query and displays them in the resultant. You can clearly notice that original query had a cost of 0.0841 and logical reads about 607 pages. Whereas various options which are just following it has different execution cost as well logical read. There are few cases where we have higher logical read and there are few cases where as we have very low logical read. If we pay attention the very next row to original query have Merge_Join_Query in description and have lowest execution cost value of 0.044 and have lowest Logical Reads of 29. This row contains the query which is the most optimal re-write of the original query. Let us double click over it. Here is the query: SELECT * FROM HumanResources.Employee e INNER JOIN HumanResources.EmployeeDepartmentHistory edh ON e.BusinessEntityID = edh.BusinessEntityID INNER JOIN HumanResources.Shift s ON edh.ShiftID = s.ShiftID OPTION (MERGE JOIN) If you notice above query have additional hint of Merge Join. With the help of this Merge Join query hint this query is now performing much better than before. The entire process takes less than 60 seconds. Please note that it the join hint Merge Join was optimal for this query but it is not necessary that the same hint will be helpful in all the queries. Additionally, if the workload or data pattern changes the query hint of merge join may be no more optimal join. In that case, we will have to redo the entire exercise once again. This is the reason I do not like to use hints in my queries and I discourage all of my users to use the same. However, if you look at this example, this is a great case where hints are optimizing the performance of the query. It is humanly not possible to test out various query hints and index options with the query to figure out which is the most optimal solution. Sometimes, we need to depend on the efficiency tools like DB Optimizer to guide us the way and select the best option from the suggestion provided. Let me know what you think of this article as well your experience with DB Optimizer. Please leave a comment. Reference: Pinal Dave (http://blog.sqlauthority.com) Filed under: PostADay, SQL, SQL Authority, SQL Joins, SQL Optimization, SQL Performance, SQL Query, SQL Server, SQL Tips and Tricks, T SQL, Technology

    Read the article

  • Building a modular Website with Zend Framework: Am I on the right way?

    - by Oliver
    Hi, i´m a little bit confused by reading all this posts an tutorials about staring with Zend, because there a so many different ways to solve a problem. I only need a feedback about my code to know if iam on the right way: To simply get a (hard coded) Navigation for my side (depending on who is logged in) i build a Controller Plugin with a postDispatch method that holds following code: public function postDispatch(Zend_Controller_Request_Abstract $request) { $menu = new Menu(); //Render menu in menu.phtml $view = new Zend_View(); //NEW view -> add View Helper $prefix = 'My_View_Helper'; $dir = dirname(__FILE__).'/../../View/Helper/'; $view->addHelperPath($dir,$prefix); $view->setScriptPath('../application/default/views/scripts/menu'); $view->menu = $menu->getMenu(); $this->getResponse()->insert('menu', $view->render('menu.phtml')); } Is it right that i need to set the helper path once again? I did this in a Plugin Controller named ViewSetup. There i do some setup for the view like doctype, headlinks, helper paths...(This step is from the book: Zend Framework in Action) The Menu class which is initiated looks like this: class Menu { protected $_menu = array(); /** * Menu for notloggedin and logged in */ public function getMenu() { $auth = Zend_Auth::getInstance(); $view = new Zend_View(); //check if user is logged in if(!$auth->hasIdentity()) { $this->_menu = array( 'page1' => array( 'label' => 'page1', 'title' => 'page1', 'url' => $view->url(array('module' => 'pages','controller' => 'my', 'action' => 'page1')) ), 'page2' => array( 'label' => 'page2', 'title' => 'page2', 'url' => $view->url(array('module' => 'pages','controller' => 'my', 'action' => 'page2')) ), 'page3' => array( 'label' => 'page3', 'title' => 'page3', 'url' => $view->url(array('module' => 'pages','controller' => 'my', 'action' => 'page3')) ), 'page4' => array( 'label' => 'page4', 'title' => 'page4', 'url' => $view->url(array('module' => 'pages','controller' => 'my', 'action' => 'page4')) ), 'page5' => array( 'label' => 'page5', 'title' => 'page5', 'url' => $view->url(array('module' => 'pages','controller' => 'my', 'action' => 'page5')) ) ); } else { //user is vom type 'client' //.. } return $this->_menu; } } Here´s my view script: <ul id="mainmenu"> <?php echo $this->partialLoop('menuItem.phtml',$this->menu) ?> </ul> This is working so far. My question is: is it usual to do it this way, is there anything to improve? I´m new to Zend and in the web are many deprecated tutorials which often is not obvious. Even the book is already deprecated where the autoloader is mentioned. Many thanks in advance

    Read the article

  • Dump Trac DB on Windows/XAMPP

    - by Whiteknight
    I have a Trac instance running on a WindowsXP machine with XAMPP. I am trying to migrate the trac instance to a newer Linux-based machine. However, I'm having a hard time getting the database to cooperate. I try to dump the db with this command: sqlite3 C:\tracroot\db\trac.db ".dump" >> mysqldump.sql But the generated file is mostly empty: BEGIN TRANSACTION; COMMIT; So that's not right. For the record my trac instance is running now and appears to have full access to all the contents of the DB. But sqlite3 (located in C:\xampp\apache\bin) can't seem to get any information from the file. The DB file itself has the header "SQLite format 3", so that seems to be correct. I need to know one of two things: How to get this dump working OR An alternate way to migrate the Trac database to the new machine. Update: When I try to open the .db file in sqlite3, I get the error Error: unsupported file format. What format is it in, and why is it unsupported?

    Read the article

< Previous Page | 31 32 33 34 35 36 37 38 39 40 41 42  | Next Page >