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  • SQL select statement

    - by kwokwai
    Hi all, I got a Table which has two fields: Point, and Level, with some sample data as follows: ----------------------- Point | Level ----------------------- 10 | Level 1 20 | Level 2 30 | Level 3 40 | Level 4 Suppose that there is a user who has 25 points, to find the Level in which this user is in, the Select statement I used was: Select Level from Table where Point < 30 AND Point > 20; But the Select SQL ststament is a hard-copy one where you can see the ponts 30 and 20 are fixed. I want to alter the Select statement so that the new SQL Select statement can be applied to all users with different points, but I don't know how to do it.

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  • SELECT a list of elements and 5 tags for each one

    - by Vittorio Vittori
    Hi, I'm trying to query a set of buldings listed on a table, these buildings are linked with tags. I'm able to do it, but my problem is how limit the number of tags to see: table buildings id building_name style 1 Pompidou bla 2 Alcatraz bla 3 etc. etc. table tags // they can be 50 or more per building id tag_name 1 minimal 2 gothic 3 classical 4 modern 5 etc. table buildings_tags id building_id tag_id I though to do something like this to retrieve the list, but this isn't compplete: SELECT DISTINCT(tag), bulding_name FROM buldings INNER JOIN buildings_tags ON buildings.id = buildings_tags.building_id INNER JOIN tags ON tags.id = buildings_tags.tag_id LIMIT 0, 20 // result building tag Pompidou great Pompidou france Pompidou paris Pompidou industrial Pompidou renzo piano <= How to stop at the 5th result? Pompidou hi-tech Pompidou famous place Pompidou wtf etc.. etc... this query loads the buildings, but this query loads all the tags linked for the building, and not only 5 of them?

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  • Take Current Snapshot of DB and send it to FTP in same PHP Scripts: Advice Needed

    - by Rachel
    Not sure if I can do it this way. I want to get current snapshot of the database and send it via FTP Server, both of this functionality should be implemented in PHP scripts. Here are the steps I am thinking on right now. In my php scripts(basically am extending an PDO into my Dao class and then preparing the query), $qry = SELECT * FROM MyTablename; $stmt = $this->prepare($qry); $stmt = $this->execute(); Now I will store $stmt in csv file using fputcsv or I will execute the sql command from the script itself and than try to store the result in the $file(csv file) note here that I do not have any csv file with me at this point to basically I will have to create one and let's say its $file, so then $file = fputcsv($stmt); or $file = exec("Select * from MyTablename"); Will this put all records in the file ? If yes, then I will use FTP Functionality to transfer file to the FTP Folder. I am not sure if this approach would work and also have concerns regarding the need of preparing the $qry Any suggestions or different approach advised would be highly appreciated. Thanks !!!

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  • PHP replace string help...

    - by MILESMIBALERR
    i am designing a site with a comment system and i would like a twitter like reply system. The if the user puts @a_registered_username i would like it to become a link to the user's profile. i think preg_replace is the function needed for this. $ALL_USERS_ROW *['USERNAME'] is the database query array for all the users and ['USERNAME'] is the username row. $content is the comment containing the @username i think this should not be very hard to solve for someone who is good at php. Does anybody have any idea how to do it?

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  • Selecting a whole database over an individual table to output to file

    - by Daniel Wrigley
    :::::::: EDIT :::::::: New code for people to have a look at, one question I have with this is where do I set were the *.gz file is saved? $backupFile = $dbname . date("Y-m-d-H-i-s") . '.gz'; $command = "mysqldump --opt -h $dbhost -u $dbuser -p $dbpass $dbname | gzip > $backupFile"; system($command); Also why the hell can you not reply yo your own post with answering it? :( :::::::: EDIT :::::::: Ok Im having trouble finding out how to select a full database for backup as an *.sql file rather than only an individual table. On the localhost I have several databases with one named "foo" and it is that which I want to backup and not any of the individual tables inside the database "foo". The code to connect to the database; //Database Information $dbhost = "localhost"; $dbname = "foo"; $dbuser = "bar"; $dbpass = "rulz"; //Connect to database mysql_connect ($dbhost, $dbuser, $dbpass) or die("Could not connect: ".mysql_error()); mysql_select_db($dbname) or die(mysql_error()); The code to backup the database; // Grab the time to know when this post was submitted $time = date('Y-m-d-H-i-s'); $tableName = 'foo'; $backupFile = '/sql/backup/'. $time .'.sql'; $query = "SELECT * INTO OUTFILE '". $backupFile ."' FROM ". $tableName .""; $result = mysql_query($query)or die("Database query died: " . mysql_error()); My brain is hurting near to the end of the day so no doubts i've missed something out very obvious. Thanks in advance to anyone helping me out.

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  • PHP Post Count in Forum

    - by Chris
    I'm currently desiging a forum application, I considered using a premade but decided against it as it's useful for me to learn some of the techniques. So I've written a fairly full featured forum... great. One of the problems I want to solve is to include user data for each post, at the minute the post table includes the poster ID (obviously) and I added the poster's username at a later date so I didn't have to query the User DB for X number of posts in a thread. However, it's become apparent I now want to do this, usernames don't need to update retrospectively, however avatars, sigs, and especially post counts need to update actively, so data in some form needs keeping up to date somewhere... What would be a good way of implementing this? I obviously don't want to include any more user data on the Posts DB table than necessary, but I'm struggling to find an easy way to do this short of querying the DB for each post in a thread, which is potentially going to create a lot of traffic. How have other people solved this, I've been examining the code on some other open source apps but I can't find what I'm looking for. Is it possible to select multiple records in one query? In which case I could build an array dynamically on each page request (eg 'SQL blah blah' then a for each loop to insert the ID's). Could I join the tables each time? Do I submit a query for each post? Hmm.

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  • Problem in Fetching Table contents when adding rows in same table

    - by jasmine
    Im trying to write a function for adding category: function addCategory() { $cname = mysql_fix_string($_POST['cname']); $kabst = mysql_fix_string($_POST['kabst']); $kselect = $_POST['kselect']; $kradio = $_POST['kradio']; $ksubmit = $_POST['ksubmit']; $id = $_POST['id']; if($ksubmit){ $query = "INSERT INTO category VALUES (' ', '{$cname}', '{$kabst}', {$kselect}, {$kradio}, ' ') "; $result = mysql_query($query); if ($result) { echo "ok"; } else{ echo $query ; } } $text .= '<div class="form"> <h2>ADD new category</h2> <form action="?page=addCategory" method="post"> <ul> <li><label>Category</label></li> <li><input name="cname" type="text" class="inp" /></li> <li><label>Description</label></li> <li><textarea name="kabst" cols="40" rows="10" class="inx"></textarea></li> <li>Published:</li> <li> <select name="kselect" class="ins"> <option value="1">Active</option> <option value="0">Passive</option> </select> </li> <li>Show in home page:</li> <li> <input type="radio" name="kradio" value="1" /> yes <input type="radio" name="kradio" value="0" /> no </li> <li>Subcategory of</li> <li> <select>'; while ($row = mysql_fetch_assoc(mysql_query("SELECT * FROM category"))){ $text .= '<option>'.$row['name'].'</option>'; } $text .= '</select> </li> <li><input name="ksubmit" type="submit" value="ekle" class="int"/></li> </ul> </form> '; return $text;} And the error: Fatal error: Maximum execution time of 30 seconds exceeded What is wrong in my function?

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  • Creating search functionality with Laravel 4

    - by Mitch Glenn
    I am trying to create a way for users to search through all the products on a website. When they search for "burton snowboards", I only want the snowboards with the brand burton to appear in the results. But if they searched only "burton", then all products with the brand burton should appear. This is what I have attempted to write but isn't working for multiple reasons. Controller: public function search(){ $input = Input::all(); $v= Validator::make($input, Product::$rules); if($v->passes()) { $searchTerms = explode(' ', $input); $searchTermBits = array(); foreach ($searchTerms as $term) { $term = trim($term); if (!empty($term)){ $searchTermBits[] = "search LIKE '%$term%'"; } } $result = DB::table('products') ->select('*') ->whereRaw(". implode(' AND ', $searchTermBits) . ") ->get(); return View::make('layouts/search', compact('result')); } return Redirect::route('/'); } I am trying to recreate the first solution given for this stackoverflow.com problem The first problem I have identified is that i'm trying to explode the $input, but it's already an array. So i'm not sure how to go about fixing that. And the way I have written the ->whereRaw(". implode(' AND ', $searchTermBits) . "), i'm sure isn't correct. I'm not sure how to fix these problems though, any insights or solutions will be greatly appreciated.

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  • SQLAlchemy: select over multiple tables

    - by ahojnnes
    Hi, I wanted to optimize my database query: link_list = select( columns=[link_table.c.rating, link_table.c.url, link_table.c.donations_in], whereclause=and_( not_(link_table.c.id.in_( select( columns=[request_table.c.recipient], whereclause=request_table.c.donator==donator.id ).as_scalar() )), link_table.c.id!=donator.id, ), limit=20, ).execute().fetchall() and tried to merge those two selects in one query: link_list = select( columns=[link_table.c.rating, link_table.c.url, link_table.c.donations_in], whereclause=and_( link_table.c.active==True, link_table.c.id!=donator.id, request_table.c.donator==donator.id, link_table.c.id!=request_table.c.recipient, ), limit=20, order_by=[link_table.c.rating.desc()] ).execute().fetchall() the database-schema looks like: link_table = Table('links', metadata, Column('id', Integer, primary_key=True, autoincrement=True), Column('url', Unicode(250), index=True, unique=True), Column('registration_date', DateTime), Column('donations_in', Integer), Column('active', Boolean), ) request_table = Table('requests', metadata, Column('id', Integer, primary_key=True, autoincrement=True), Column('recipient', Integer, ForeignKey('links.id')), Column('donator', Integer, ForeignKey('links.id')), Column('date', DateTime), ) There are several links (donator) in request_table pointing to one link in the link_table. I want to have links from link_table, which are not yet "requested". But this does not work. Is it actually possible, what I'm trying to do? If so, how would you do that? Thank you very much in advance!

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  • How to setup testing LAMP environment to work with outsourcing companies?

    - by Kelvin
    Hello Guys, I need to setup testing LAMP environment in my office to work with outsourcing companies. This is what I think should be done on my side: Setup testing web server with the same configuration as on production Setup testing SQL server with "fake data"? Outsourcers should have access only to some part of original code Outsourcers should use CVS to update their code Once testing is finished someone releases the update ............ How would you separate original code and database from testing environment, but keep it as close as possible to production? What is the general practice for setting up testing environment and how other companies deal with outsourcers? I will appreciate for any of your thoughts and ideas from your personal experience. Maybe someone can suggest some article on this topic. Thank you a lot!

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  • How would I UPDATE these table entries with SQL?

    - by CT
    I am working on an Asset Database problem. I enter assets into a database. Every object is an asset and has variables within the asset table. An object is also a type of asset. In this example the type is server. Here is the Query to retrieve all necessary data: SELECT asset.id ,asset.company ,asset.location ,asset.purchaseDate ,asset.purchaseOrder ,asset.value ,asset.type ,asset.notes ,server.manufacturer ,server.model ,server.serialNumber ,server.esc ,server.warranty ,server.user ,server.prevUser ,server.cpu ,server.memory ,server.hardDrive FROM asset LEFT JOIN server ON server.id = asset.id WHERE asset.id = '$id' How would I write a query to update an asset?

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  • HTML checkbox field is being passed to PHP as checked even when it is not

    - by Ryan
    Hello all, First of all thanks in advance, this has been very frustrating and I'm hoping someone can see something I'm not, I am definitely no php expert. Well here' what is going on. I have a form where I have a checkbox for people to opt in to our newletter. The form element looks like this: <label for=newsletter accesskey=N class="checkbox">Signup for Cloverton's Newsletter</label> <input name="newsletter" type="checkbox" id="newsletter" value="Yes" style="width:20px;" /> That is then submitted to a php file with this code: if (isset($_POST['newsletter']) && $_POST['newsletter'] == 'Yes'){ echo "newletter yes"; $newsletter = 1; }else{ echo "newsletter no"; $newsletter = 0; } $newsletter is then inserted into a database field. The issue is that whether the box is checked or not it is being sent to php as true, so every entry is receiving the newsletter. Any help would be greatly appreciated! Thanks!

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  • Complex Join - involving date ranges and sum...

    - by calumbrodie
    I have two tables that I need to join... I want to join table1 and table2 on 'id' - however in table two id is not unique. I only want one value returned for table two, and this value represents the sum of a column called 'total_sold' - within a specified date range (say one month).. SELECT ta.id, tb.total_sold as total_sold_this_week FROM table_a as ta LEFT JOIN table_b as tb ON ta.id=tb.id AND tb.date_sold BETWEEN ADDDATE(NOW(),INTERVAL -3 WEEK) AND NOW() this works but does not SUM the rows - only returning one row for each id... how do I get the sum from table b instead of only one row??? Please criticise if format of question could use more work - I can rewrite and provide sample data if required - this is a trivialised version of a much larger problem. -Thanks

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  • Can you automatically create a mysqldump file that doesn't enforce foreign key constraints?

    - by Tai Squared
    When I run a mysqldump command on my database and then try to import it, it fails as it attempts to create the tables alphabetically, even though they may have a foreign key that references a table later in the file. There doesn't appear to be anything in the documentation and I've found answers like this that say to update the file after it's created to include: set FOREIGN_KEY_CHECKS = 0; ...original mysqldump file contents... set FOREIGN_KEY_CHECKS = 1; Is there no way to automatically set those lines or export the tables in the necessary order (without having to manually specify all table names as that can be tedious and error prone)? I could wrap those lines in a script, but was wondering if there is an easy way to ensure I can dump a file and then import it without manually updating it.

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  • Update multiple rows with one query?

    - by kavoir.com
    I found something that works with updating one field at here: http://www.karlrixon.co.uk/articles/sql/update-multiple-rows-with-different-values-and-a-single-sql-query/ UPDATE person SET name = CASE id WHEN 1 THEN 'Jim' WHEN 2 THEN 'Mike' WHEN 3 THEN 'Precious' END WHERE id IN (1,2,3) My question is how to update more than one field? Such as: UPDATE person SET name = CASE, sex = CASE id WHEN 1 THEN 'Jim', 'female' WHEN 2 THEN 'Mike' 'male' WHEN 3 THEN 'Precious', 'male' END WHERE id IN (1,2,3) Which doesn't work of course. Tried a few other combination and failed. Any idea? Thanks!

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  • Fiscal year, quarters, student table, and faculty table... How do I relate these?!

    - by yuudachi
    I have a student and faculty table. The primary key for student is studendID (SID) and faculty's primary key is facultyID, naturally. Student has an advisor column and a requested advisor column, which are foreign key to faculty. That's simple enough, right? However, now I have to throw in dates. I want to be able to view who their advisor was for a certain quarter (such as 2009 Winter) and who they had requested. The result will be a table like this: Year | Term | SID | Current | Requested ------------------------------------------------ 2009 | Winter | 860123456 | 1 | NULL 2009 | Winter | 860445566 | 3 | NULL 2009 | Winter | 860369147 | 5 | 1 And then if I feel like it, I could also go ahead and view a different year and a different term. I am not sure how these new table(s) will look like. Will there be a year table with three columns that are Fall, Spring and Winter? And what will the Fall, Spring, Winter table have? I am new to the art of tables, so this is baffling me... Also, I feel I should clarify how the site works so far now. Admin can approve student requests, and what happens is that the student's current advisor gets overwritten with their request. However, I think I should not do that anymore, right?

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  • Trouble making login page?

    - by Ken
    Okay, so I want to make a simple login page. I've created a register page successfully, but i can't get the login thing down. login.php: <?php session_start(); include("mainmenu.php"); $usrname = mysql_real_escape_string($_POST['usrname']); $password = md5($_POST['password']); $con = mysql_connect("localhost", "root", "g00dfor@boy"); if(!$con){ die(mysql_error()); } mysql_select_db("users", $con) or die(mysql_error()); $login = "SELECT * FROM `users` WHERE (usrname = '$usrname' AND password = '$password')"; $result = mysql_query($login); if(mysql_num_rows($result) == 1 { $_SESSION = true; header('Location: indexlogin.php'); } else { echo = "Wrong username or password." ; } ?> indexlogin.php just echoes "Login successful." What am I doing wrong? Oh, and just FYI- my database is "users" and my table is "data".

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  • Using a table-alias in Kohana queries?

    - by Aristotle
    I'm trying to run a simple query with $this->db in Kohana, but am running into some syntax issues when I try to use an alias for a table within my query: $result = $this->db ->select("ci.chapter_id, ci.book_id, ci.chapter_heading, ci.chapter_number") ->from("chapter_info ci") ->where(array("ci.chapter_number" => $chapter, "ci.book_id" => $book)) ->get(); It seems to me that this should work just fine. I'm stating that "chapter_info" ought to be known as "ci," yet this isn't taking for some reason. The error is pretty straight-forward: There was an SQL error: Table 'gb_data.chapter_info ci' doesn't exist - SELECT `ci`.`chapter_id`, `ci`.`book_id`, `ci`.`chapter_heading`, `ci`.`chapter_number` FROM (`chapter_info ci`) WHERE `ci`.`chapter_number` = 1 AND `ci`.`book_id` = 1 If I use the full table name, rather than an alias, I get the expected results without error. This requires me to write much more verbose queries, which isn't ideal. Is there some way to use shorter names for tables within Kohana's query-builder?

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  • php - upload script mkdir saying file already exists when same directory even though different filename

    - by neeko
    my upload script says my file already exists when i try upload even though different filename <?php // Start a session for error reporting session_start(); ?> <?php // Check, if username session is NOT set then this page will jump to login page if (!isset($_SESSION['username'])) { header('Location: index.html'); } // Call our connection file include('config.php'); // Check to see if the type of file uploaded is a valid image type function is_valid_type($file) { // This is an array that holds all the valid image MIME types $valid_types = array("image/jpg", "image/JPG", "image/jpeg", "image/bmp", "image/gif", "image/png"); if (in_array($file['type'], $valid_types)) return 1; return 0; } // Just a short function that prints out the contents of an array in a manner that's easy to read // I used this function during debugging but it serves no purpose at run time for this example function showContents($array) { echo "<pre>"; print_r($array); echo "</pre>"; } // Set some constants // Grab the User ID we sent from our form $user_id = $_SESSION['username']; $category = $_POST['category']; // This variable is the path to the image folder where all the images are going to be stored // Note that there is a trailing forward slash $TARGET_PATH = "img/users/$category/$user_id/"; mkdir($TARGET_PATH, 0755, true); // Get our POSTed variables $fname = $_POST['fname']; $lname = $_POST['lname']; $contact = $_POST['contact']; $price = $_POST['price']; $image = $_FILES['image']; // Build our target path full string. This is where the file will be moved do // i.e. images/picture.jpg $TARGET_PATH .= $image['name']; // Make sure all the fields from the form have inputs if ( $fname == "" || $lname == "" || $image['name'] == "" ) { $_SESSION['error'] = "All fields are required"; header("Location: error.php"); exit; } // Check to make sure that our file is actually an image // You check the file type instead of the extension because the extension can easily be faked if (!is_valid_type($image)) { $_SESSION['error'] = "You must upload a jpeg, gif, or bmp"; header("Location: error.php"); exit; } // Here we check to see if a file with that name already exists // You could get past filename problems by appending a timestamp to the filename and then continuing if (file_exists($TARGET_PATH)) { $_SESSION['error'] = "A file with that name already exists"; header("Location: error.php"); exit; } // Lets attempt to move the file from its temporary directory to its new home if (move_uploaded_file($image['tmp_name'], $TARGET_PATH)) { // NOTE: This is where a lot of people make mistakes. // We are *not* putting the image into the database; we are putting a reference to the file's location on the server $imagename = $image['name']; $sql = "insert into people (price, contact, category, username, fname, lname, expire, filename) values (:price, :contact, :category, :user_id, :fname, :lname, now() + INTERVAL 1 MONTH, :imagename)"; $q = $conn->prepare($sql) or die("failed!"); $q->bindParam(':price', $price, PDO::PARAM_STR); $q->bindParam(':contact', $contact, PDO::PARAM_STR); $q->bindParam(':category', $category, PDO::PARAM_STR); $q->bindParam(':user_id', $user_id, PDO::PARAM_STR); $q->bindParam(':fname', $fname, PDO::PARAM_STR); $q->bindParam(':lname', $lname, PDO::PARAM_STR); $q->bindParam(':imagename', $imagename, PDO::PARAM_STR); $q->execute(); $sql1 = "UPDATE people SET firstname = (SELECT firstname FROM user WHERE username=:user_id1) WHERE username=:user_id2"; $q = $conn->prepare($sql1) or die("failed!"); $q->bindParam(':user_id1', $user_id, PDO::PARAM_STR); $q->bindParam(':user_id2', $user_id, PDO::PARAM_STR); $q->execute(); $sql2 = "UPDATE people SET surname = (SELECT surname FROM user WHERE username=:user_id1) WHERE username=:user_id2"; $q = $conn->prepare($sql2) or die("failed!"); $q->bindParam(':user_id1', $user_id, PDO::PARAM_STR); $q->bindParam(':user_id2', $user_id, PDO::PARAM_STR); $q->execute(); header("Location: search.php"); exit; } else { // A common cause of file moving failures is because of bad permissions on the directory attempting to be written to // Make sure you chmod the directory to be writeable $_SESSION['error'] = "Could not upload file. Check read/write persmissions on the directory"; header("Location: error.php"); exit; } ?>

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  • problem parsing JSON Strings

    - by blacktooth
    var records = JSON.parse(JsonString); for(var x=0;x<records.result.length;x++) { var record = records.result[x]; ht_text+="<b><p>"+(x+1)+" " +record.EMPID+" " +record.LOCNAME+" " +record.DEPTNAME+" " +record.CUSTNAME +"<br/><br/><div class='slide'>" +record.REPORT +"</div></p></b><br/>"; } The above code works fine when the JsonString contains an array of entities but fails for single entity. result is not identified as an array! Whats wrong with it? http://pastebin.com/hgyWw5hd

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  • Is there a way to optimize this update query?

    - by SchlaWiener
    I have a master table called "parent" and a related table called "childs" Now I run a query against the master table to update some values with the sum from the child table like this. UPDATE master m SET quantity1 = (SELECT SUM(quantity1) FROM childs c WHERE c.master_id = m.id), quantity2 = (SELECT SUM(quantity2) FROM childs c WHERE c.master_id = m.id), count = (SELECT COUNT(*) FROM childs c WHERE c.master_id = m.id) WHERE master_id = 666; Which works as expected but is not a good style because I basically make multiple SELECT querys on the same result. Is there a way to optimize that? (Making a query first and storing the values is not an option. I tried this: UPDATE master m SET (quantity1, quantity2, count) = ( SELECT SUM(quantity1), SUM(quantity2), COUNT(*) FROM childs c WHERE c.master_id = m.id ) WHERE master_id = 666; but that doesn't work.

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