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  • How to write an error message from an BCP operation to a log file and stop processing the batch file

    - by Newbie
    I have a BCP operation in a batch command file. when there is an error in the BCP Operation I need to stop the processing and write the err msg in the log file I've used to -e option to write the error message during a BCP operation to a err file. The err file is getting created in the location but does not contain any error message written to it. My BCP statement is like this. BCP DbName.dbo.tableName In FileLocation -e Errorfile -S ServerName -T -c Is there a way to get the error level and then stop the processing. Appreciate quick help.

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  • PHP Load variables from external file

    - by Adrian M.
    Hello, How can I import a variable from an external file? What I want to do is to have a configuration file in which I can write all my website settings and then to import these settings to every file, so I can set the website skin and things like that.. How can I do this? Thanks!

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  • C# DriveInfo FileInfo

    - by maxfridbe
    This may seem like a stupid question, so here goes: Other than parsing the string of FileInfo.FullPath for the drive letter to then use DriveInfo("c") etc to see if there is enough space to write this file. Is there a way to get the drive letter from FileInfo?

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  • http file upload in blackberry jde

    - by Karthick
    Hi I need to upload file to http server. I wish to use jsp for server side processing. How to upload file from my blackberry application to http server?. What should I do in the server part and how to send file data to http server from blackberry?. I need some help about this problem.

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  • File.mkdir is not working and I can't understand why

    - by gotch4
    Hello, I've this brief snippet: String target = baseFolder.toString() + entryName; target = target.substring(0, target.length() - 1); File targetdir = new File(target); if (!targetdir.mkdirs()) { throw new Exception("Errore nell'estrazione del file zip"); } doesn't mattere if I leave the last char (that is usually a slash). It's done this way to work on both unix and windows. The path is actually obtained from the URI of the base folder. As you can see from baseFolder.toString() (baseFolder is of type URI and is correct). The base folder actually exists. I can't debug this because all I get is true or false from mkdir, no other explanations.The weird thing is that baseFolder is created as well with mkdir and in that case it works. Now I'm under windows. the value of target just before the creation of targetdir is "file:/C:/Users/dario/jCommesse/jCommesseDB" if I cut and paste it (without the last entry) in windows explore it works...

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  • xsd and wsdl incorrect file

    - by Gandalf StormCrow
    How to fix corrupted xsd and wsdl files, is there any IDE which can suggest what is wrong? such as eclipse for java code when pressing CTRL + 1 , or where can I find books tutorials to understand formatting of these file types better? thank you Here is concrete message error I have [ERROR] 'item' is already defined line 223 of file:/C:/project/src/main/resources/schema.xsd [ERROR] (related to above error) the first definition appears here line 22 of file:/C:/project/src/main/resources/schema.xsd

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  • Loading an external .htm file into a div with javascript

    - by Mads Friis
    So I got this code Javascript: <script type="text/javascript"> $(function(){ $('.ajax') .click(function(e){ e.preventDefault() $('#content').load( 'file.htm' ) }) }) </script> html: <a href="file.htm" class="ajax">Link</a> it works perfectly in firefox, but nothing happens when I click the link in chrome and IE simply opens a new window with the file. any advice?

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  • Python IOError: Not a gzipped file (Gzip and Blowfish Encrypt/Compress)

    - by notbad.jpeg
    I'm having some problems with python's built-in library gzip. Looked through almost every other stack question about it, and none of them seem to work. MY PROBLEM IS THAT WHEN I TRY TO DECOMPRESS I GET THE IOError I'm Getting: Traceback (most recent call last): File "mymodule.py", line 61, in return gz.read() File "/usr/lib/python2.7/gzip.py", line 245, readself._read(readsize) File "/usr/lib/python2.7/gzip.py", line 287, in _readself._read_gzip_header() File "/usr/lib/python2.7/gzip.py", line 181, in _read_gzip_header raise IOError, 'Not a gzipped file'IOError: Not a gzipped file This is my code to send it over SMB, it might not make sense why i do things, but it's normally in a while loop and memory efficient, I just simplified it. buffer = cStringIO.StringIO(output) #output is from a subprocess call small_buffer = cStringIO.StringIO() small_string = buffer.read() #need a string to write to buffer gzip_obj = gzip.GzipFile(fileobj=small_buffer,compresslevel=6, mode='wb') gzip_obj.write(small_string) compressed_str = small_buffer.getvalue() blowfish = Blowfish.new('abcd', Blowfish.MODE_ECB) remainder = '|'*(8 - (len(compressed_str) % 8)) compressed_str += remainder encrypted = blowfish.encrypt(compressed_str) #i send it over smb, then retrieve it later Then this is the code that retrieves it: #buffer is a cStringIO object filled with data from smb retrieval decrypter = Blowfish.new('abcd', Blowfish.MODE_ECB) value = buffer.getvalue() decrypted = decrypter.decrypt(value) buff = cStringIO.StringIO(decrypted) buff.seek(0) gz = gzip.GzipFile(fileobj=buff) return gz.read() Here's the problem return gz.read()

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  • xml file reading

    - by Dilse Naaz
    How to read an xml file in silverlight using webclient. I have one task, in this the xml file that i stored in my machine will read and the content od the xml file will display on a data grid. how it will be done?

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  • Where will log4net create this log file?

    - by Blankman
    When I set the file value to 'logs\log-file.txt' where exactly will it create this folder? in the /bin directory? My web.config looks like: <log4net> <appender name="FileAppender" type="log4net.Appender.FileAppender"> <file value="logs\log-file.txt" /> <appendToFile value="true" /> <lockingModel type="log4net.Appender.FileAppender+MinimalLock" /> <layout type="log4net.Layout.PatternLayout"> <conversionPattern value="%date [%thread] %-5level %logger [%property{NDC}] - %message%newline" /> </layout> </appender> </log4net> is this the correct way to log: ILog logger = LogManager.GetLogger(typeof(CCController)); logger.Error("Some Page", ex); // where ex is the exception instance

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  • Create an upload form, select a folder and get a specific file in folder

    - by aladine
    Hi, To upload a single file, it is very simple to use this HTML script: <p> <input type="file" name="input.txt" /> In this question, my task is to select a folder and then get the input.txt inside that folder. The server will response whether input.txt is available or not and to upload it to web server. Is there any way to select a folder instead selecting a file in the input form. Thanks.

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  • IIS Directory listing doesn't reconize .mkv files

    - by Buckley
    Hello I use the directory listing function in IIS to upload a bunch of files for friends and family to easy access and download. My problem is that .mkv files it lists but when you click it i get a 'The page cannot be found'. Ive tried relocating the file and renaming it but i get the same error each time. Why does it do this? Its only my .mkv files everything else works perfectly. Thanks in advance.

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  • Setting classpath and installing database via batch file

    - by Supereme
    Hi, I want my classpath to be set via a batch file. I'm working on Windows XP. I have two questions: My first question: I made a batch file in which I typed "set classpath = C:\WINDOWS\system32\;.;C:\jdk1.5.0\lib\tools.jar;C:\poi-3.6\poi-3.6-20091214.jar;C:\poi-3.6\poi-contrib-3.6-20091214.jar;C:\poi-3.6\poi-ooxml-3.6-20091214.jar;C:\poi-3.6\poi-ooxml-schemas-3.6-20091214.jar;C:\poi-3.6\poi-scratchpad-3.6-20091214.jar;E:\jdbc\postgresql-8.2-505.jdbc3.jar;C:\xmlbeans-2.5.0\lib\jsr173_1.0_api.jar;C:\xmlbeans-2.5.0\lib\resolver.jar;C:\xmlbeans-2.5.0\lib\xbean.jar;C:\xmlbeans-2.5.0\lib\xbean_xpath.jar;C:\xmlbeans-2.5.0\lib\xmlbeans-qname.jar;C:\xmlbeans-2.5.0\lib\xmlpublic.jar;C:\dom4j-1.6.1\dom4j-1.6.1.jar; exit" When I tried to run this file it ran but when I went into control panel systemadvancedenvironment variables and then selected classpath, it didn't show me the classpath I did set. What is the correct way to set the classpath via batch file? My second question: Is there any way by which we can install database via batch file say for eg: postgresql8.2? Thank you.

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  • Extracting a .app from a zip file in Python, using ZipFile

    - by Yakattak
    I'm trying to extract new revisions of Chromium.app from their snapshots, and I can download the file fine, but when it comes to extracting it, ZipFile either extracts the chrome-mac folder within as a file, says that directories don't exist, etc. I am very new to python, so these errors make little sense to me. Here is what I have so far. import urllib2 response = urllib2.urlopen('http://build.chromium.org/buildbot/snapshots/chromium-rel-mac/LATEST') latestRev = response.read() print latestRev # we have the revision, now we need to download the zip and extract it latestZip = urllib2.urlopen('http://build.chromium.org/buildbot/snapshots/chromium-rel-mac/%i/chrome-mac.zip' % (int(latestRev)), '~/Desktop/ChromiumUpdate/%i-update' % (int(latestRev))) #declare some vars that hold paths n shit workingDir = '/Users/slehan/Desktop/ChromiumUpdate/' chromiumZipPath = '%s%i-update.zip' % (workingDir, (int(latestRev))) chromiumAppPath = 'chrome-mac/' #the path of the chromium executable within the zip file chromiumAppExtracted = '%s/Chromium.app' % (workingDir) # path of the extracted executable output = open(chromiumZipPath, 'w') #delete any current file there output.write(latestZip.read()) output.close() # we have the .zip now we need to extract the Chromium.app file, it's in ziproot/chrome-mac/Chromium.app import zipfile, os zippedFile = open(chromiumZipPath) zippedChromium = zipfile.ZipFile(zippedFile, 'r') zippedChromium.extract(chromiumAppPath, workingDir) #print zippedChromium.namelist() zippedChromium.close() #zippedChromium.close() Any ideas?

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  • problems with unpickling a 80 megabyte file in python

    - by tipu
    I am using the pickle module to read and write large amounts of data to a file. After writing to the file a 80 megabyte pickled file, I load it in a SocketServer using class MyTCPHandler(SocketServer.BaseRequestHandler): def handle(self): print("in handle") words_file_handler = open('/home/tipu/Dropbox/dev/workspace/search/words.db', 'rb') words = pickle.load(words_file_handler) tweets = shelve.open('/home/tipu/Dropbox/dev/workspace/search/tweets.db', 'r'); results_per_page = 25 query_details = self.request.recv(1024).strip() query_details = eval(query_details) query = query_details["query"] page = int(query_details["page"]) - 1 return_ = [] booleanquery = BooleanQuery(MyTCPHandler.words) if query.find("(") > -1: result = booleanquery.processAdvancedQuery(query) else: result = booleanquery.processQuery(query) result = list(result) i = 0 for tweet_id in result and i < 25: #return_.append(MyTCPHandler.tweets[str(tweet_id)]) return_.append(tweet_id) i += 1 self.request.send(str(return_)) However the file never seems to load after the pickle.load line and it eventually halts the connection attempt. Is there anything I can do to speed this up?

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  • Crystal Reports "File Break"

    - by Chris B. Behrens
    I'm generating a Crystal Reports report which will ultimately need to be split into thousands of pdf files. What would be ideal would be if Crystal Reports had something like a "file break", like a page break, that you could insert into the file at the appropriate places. I will need reasonably fine control over the file names, as well....something like "fileName_{CustomerId}_{CustomerIsLocal}.pdf". I'm presuming a third-party piece of software will probably be needed. Thoughts? TIA.

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  • Form File Upload with other TextBox Inputs + Creating Custom Form Action attribute

    - by Jonathan Stowell
    Hi All, I am attempting to create a form where a user is able to enter your typical form values textboxes etc, but also upload a file as part of the form submission. This is my View code it can be seen that the File upload is identified by the MCF id: <% using (Html.BeginForm("Create", "Problem", FormMethod.Post, new { id = "ProblemForm", enctype = "multipart/form-data" })) {%> <p> <label for="StudentEmail">Student Email (*)</label> <br /> <%= Html.TextBox("StudentEmail", Model.Problem.StudentEmail, new { size = "30", maxlength=26 })%> <%= Html.ValidationMessage("StudentEmail", "*") %> </p> <p> <label for="Type">Communication Type (*)</label> <br /> <%= Html.DropDownList("Type") %> <%= Html.ValidationMessage("Type", "*") %> </p> <p> <label for="ProblemDateTime">Problem Date (*)</label> <br /> <%= Html.TextBox("ProblemDateTime", String.Format("{0:d}", Model.Problem.ProblemDateTime), new { maxlength = 10 })%> <%= Html.ValidationMessage("ProblemDateTime", "*") %> </p> <p> <label for="ProblemCategory">Problem Category (* OR Problem Outline)</label> <br /> <%= Html.DropDownList("ProblemCategory", null, "Please Select...")%> <%= Html.ValidationMessage("ProblemCategory", "*")%> </p> <p> <label for="ProblemOutline">Problem Outline (* OR Problem Category)</label> <br /> <%= Html.TextArea("ProblemOutline", Model.Problem.ProblemOutline, 6, 75, new { maxlength = 255 })%> <%= Html.ValidationMessage("ProblemOutline", "*") %> </p> <p> <label for="MCF">Mitigating Circumstance Form</label> <br /> <input id="MCF" type="file" /> <%= Html.ValidationMessage("MCF", "*") %> </p> <p> <label for="MCL">Mitigating Circumstance Level</label> <br /> <%= Html.DropDownList("MCL") %> <%= Html.ValidationMessage("MCL", "*") %> </p> <p> <label for="AbsentFrom">Date Absent From</label> <br /> <%= Html.TextBox("AbsentFrom", String.Format("{0:d}", Model.Problem.AbsentFrom), new { maxlength = 10 })%> <%= Html.ValidationMessage("AbsentFrom", "*") %> </p> <p> <label for="AbsentUntil">Date Absent Until</label> <br /> <%= Html.TextBox("AbsentUntil", String.Format("{0:d}", Model.Problem.AbsentUntil), new { maxlength = 10 })%> <%= Html.ValidationMessage("AbsentUntil", "*") %> </p> <p> <label for="AssessmentID">Assessment Extension</label> <br /> <%= Html.DropDownList("AssessmentID") %> <%= Html.ValidationMessage("AssessmentID", "*") %> <%= Html.TextBox("DateUntil", String.Format("{0:d}", Model.AssessmentExtension.DateUntil), new { maxlength = 16 })%> <%= Html.ValidationMessage("DateUntil", "*") %> </p> <p> <label for="Details">Assessment Extension Details</label> <br /> <%= Html.TextArea("Details", Model.AssessmentExtension.Details, 6, 75, new { maxlength = 255 })%> <%= Html.ValidationMessage("Details", "*") %> </p> <p> <label for="RequestedFollowUp">Requested Follow Up</label> <br /> <%= Html.TextBox("RequestedFollowUp", String.Format("{0:d}", Model.Problem.RequestedFollowUp), new { maxlength = 16 })%> <%= Html.ValidationMessage("RequestedFollowUp", "*") %> </p> <p> <label for="StaffEmail">Staff</label> <br /> <%= Html.ListBox("StaffEmail", Model.StaffEmail, new { @class = "multiselect" })%> <%= Html.ValidationMessage("StaffEmail", "*")%> </p> <p> <input class="button" type="submit" value="Create Problem" /> </p> This is my controller code: [AcceptVerbs(HttpVerbs.Post)] public ActionResult Create(Problem problem, AssessmentExtension assessmentExtension, Staff staffMember, HttpPostedFileBase file, string[] StaffEmail) { if (ModelState.IsValid) { try { Student student = studentRepository.GetStudent(problem.StudentEmail); Staff currentUserStaffMember = staffRepository.GetStaffWindowsLogon(User.Identity.Name); var fileName = Path.Combine(Request.MapPath("~/App_Data"), Path.GetFileName(file.FileName)); file.SaveAs(@"C:\Temp\" + fileName); if (problem.RequestedFollowUp.HasValue) { String meetingName = student.FirstName + " " + student.LastName + " " + "Mitigating Circumstance Meeting"; OutlookAppointment outlookAppointment = new OutlookAppointment(currentUserStaffMember.Email, meetingName, (DateTime)problem.RequestedFollowUp, (DateTime)problem.RequestedFollowUp.Value.AddMinutes(30)); } problemRepository.Add(problem); problemRepository.Save(); if (assessmentExtension.DateUntil != null) { assessmentExtension.ProblemID = problem.ProblemID; assessmentExtensionRepository.Add(assessmentExtension); assessmentExtensionRepository.Save(); } ProblemPrivacy problemPrivacy = new ProblemPrivacy(); problemPrivacy.ProblemID = problem.ProblemID; problemPrivacy.StaffEmail = currentUserStaffMember.Email; problemPrivacyRepository.Add(problemPrivacy); if (StaffEmail != null) { for (int i = 0; i < StaffEmail.Length; i++) { ProblemPrivacy probPrivacy = new ProblemPrivacy(); probPrivacy.ProblemID = problem.ProblemID; probPrivacy.StaffEmail = StaffEmail[i]; problemPrivacyRepository.Add(probPrivacy); } } problemPrivacyRepository.Save(); return RedirectToAction("Details", "Student", new { id = student.Email }); } catch { ModelState.AddRuleViolations(problem.GetRuleViolations()); } } return View(new ProblemFormViewModel(problem, assessmentExtension, staffMember)); } This form was working correctly before I had to switch to using a non-AJAX file upload, this was due to an issue with Flash when enabling Windows Authentication which I need to use. It appears that when I submit the form the file is not sent and I am unsure as to why? I have also been unsuccessful in finding an example online where a file upload is used in conjunction with other input types. Another query I have is that for Create, and Edit operations I have used a PartialView for my forms to make my application have higher code reuse. The form action is normally generated by just using: Html.BeginForm() And this populates the action depending on which Url is being used Edit or Create. However when populating HTML attributes you have to provide a action and controller value to pass HTML attributes. using (Html.BeginForm("Create", "Problem", FormMethod.Post, new { id = "ProblemForm", enctype = "multipart/form-data" })) Is it possible to somehow populate the action and controller value depending on the URL to maintain code reuse? Thinking about it whilst typing this I could set two values in the original controller action request view data and then just populate the value using the viewdata values? Any help on these two issues would be appreciated, I'm new to asp.net mvc :-) Thanks, Jon

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