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  • ASP.Net MVC 2 - How to set up a Cancel button with client side navigation

    - by arame3333
    Thanks to a previous question I found a useful link on multiple buttons. http://weblogs.asp.net/dfindley/archive/2009/05/31/asp-net-mvc-multiple-buttons-in-the-same-form.aspx What I want to do is have a cancel button on my page, similar to this; <button name="button" type="button" onclick="document.location.href=$('#cancelUrl').attr('href')">Cancel</button> <a id="cancelUrl" href="<%: Url.Action("Index", "Home") %>" style="display:none;"></a> However although this code works, I really want to go back to the previous page. For Web Forms I could use the javascript Back() or Go(-1) functions, but they relied on postbacks. I could of course hard code the previous page and controller as I have done above. However I am struggling to find links that explain to me how Url.Action works. Because if I do this, I also need to include an index parameter, and I am not clear how the syntax works for that. It seems odd the amount of coding to do this. Out of curiosity, I am also wondering how you TDD client side code like this.

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  • ASP.NET MVC: Returning a view with querystring intact

    - by ajbeaven
    I'm creating a messaging web app in ASP.NET and are having some problems when displaying an error message to the user if they go to send a message and there is something wrong. A user can look through profiles of people and then click, 'send a message'. The following action is called (url is /message/create?to=username) and shows them a page where they can enter their message and send it: public ActionResult Create(string to) { ViewData["recipientUsername"] = to; return View(); } On the page that is displayed, the username is entered in to a hidden input field. When the user clicks 'send': [AcceptVerbs(HttpVerbs.Post)] public ActionResult Create(FormCollection collection, string message) { try { //do message stuff that errors out } catch { ModelState.AddModelErrors(message.GetRuleViolations()); //adding errors to modelstate } return View(); } So now the error message is displayed to the user fine, however the url is changed in that it no longer has the querystring (/message/create). Again, this would be fine except that when the user clicks the refresh button, the page errors out as the Create action no longer has the 'to' parameter. So I'm guessing that I need to maintain my querystring somehow. Is there any way to do this or do I need to use a different method altogether?

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  • Show progress during a long Ajax call

    - by kousen
    I have a simple web site (http://www.kousenit.com/twitterfollowervalue) that computes a quantity based on a person's Twitter followers. Since the Twitter API only returns followers 100 at a time, a complete process may involve lots of calls. At the moment, I have an Ajax call to a method that runs the Twitter loop. The method looks like (Groovy): def updateFollowers() { def slurper = new XmlSlurper() followers = [] def next = -1 while (next) { def url = "http://api.twitter.com/1/statuses/followers.xml?id=$id&cursor=$next" def response = slurper.parse(url) response.users.user.each { u -> followers << new TwitterUser(... process data ...) } next = response.next_cursor.toBigInteger() } return followers } This is invoked from a controller called renderTTFV.groovy. I call the controller via an Ajax call using the prototype library: On my web page, in the header section (JavaScript): function displayTTFV() { new Ajax.Updater('ttfv','renderTTFV.groovy', {}); } and there's a div in the body of the page that updates when the call is complete. Everything is working, but the updateFollowers method can take a fair amount of time. Is there some way I could return a progress value? For example, I'd like to update the web page on every iteration. I know ahead of time how many iterations there will be. I just can't figure out a way to update the page in the middle of that loop. Any suggestions would be appreciated.

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  • Problem with my Jquery loading in my Codeigniter views

    - by sico87
    Hello, I am working on a one page website that allows the users to add and remove pages from there navigation as and when they would like too, the way it works is that if the click 'Blog' on the main nav a 'Blog' section should appear on the page, if they then click 'News' the 'News' section should also be visible, however the way I have started to implement this it seems I can only have one section at a time, can my code be adpated to allow multiple sections to shown on the main page. Here is my code for the page that has the main menu and the users selections on it. <!DOCTYPE html> <head> <title>Development Site</title> <link rel="stylesheet" href="/media/css/reset.css" media="screen"/> <link rel="stylesheet" href="/media/css/generic.css" media="screen"/> <script type="text/javascript" src="/media/javascript/jquery-ui/js/jquery.js"></script> <script type="text/javascript" src="/media/javascript/jquery-ui/development-bundle/ui/ui.core.js"></script> <script type="text/javascript" src="/media/javascript/jquery-ui/development-bundle/ui/ui.accordion.js"></script> <script type="text/javascript"> $(document).ready(function() { $('a.menuitem').click(function() { var link = $(this), url = link.attr("href"); $("#content_pane").load(url); return false; // prevent default link-behavior }); }); </script> </head> <body> <li><a class="menuitem" href="inspiration">Inspiration</a></li> <li><a class="menuitem" href="blog">Blog</a></li> <div id="content_pane"> </div> </body> </html>

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  • Experts help needed on libcurl programming in sending HTTP HEAD Request.

    - by Mani
    Hi all, I need clarifications on using libcurl for the following: I need to send an http HEAD request shown as below :: HEAD /mshare/3/30002:12:primary/stream_xNKNVH.mpeg HTTP/1.1 Host: 192.168.70.1:8080 Accept: */* User-Agent: Kreatel_IP-STB getcontentFeatures.dlna.org: 1 The code I wrote (shown below) , sends the HEAD Request in slightly different way: curl_global_init(CURL_GLOBAL_ALL); CURL* ctx = NULL; const char *url = "http://192.168.70.1:8080/mshare/3/30002:12:primary/stream_xNKNVH.mpeg" ; char *returnString; struct curl_slist *headers = NULL; ctx = curl_easy_init(); headers = curl_slist_append(headers,"Accept: /"); headers = curl_slist_append(headers,"User-Agent: Kreatel_IP-STB");\ headers = curl_slist_append(headers,"getcontentFeatures.dlna.org: 1"); headers = curl_slist_append(headers,"Pragma:"); headers = curl_slist_append(headers,"Proxy-Connection:"); curl_easy_setopt(ctx,CURLOPT_HTTPHEADER , headers ); curl_easy_setopt(ctx,CURLOPT_NOBODY ,1 ); curl_easy_setopt(ctx,CURLOPT_VERBOSE, 1); curl_easy_setopt(ctx,CURLOPT_URL,url ); curl_easy_setopt(ctx,CURLOPT_NOPROGRESS ,1 ); curl_easy_perform(ctx); curl_easy_cleanup(ctx); curl_global_cleanup(); The code shown above sends the HEAD Request in slightly different form (shown below) HEAD http://192.168.70.1:8080/mshare/3/30002:12:primary/stream_xNKNVH.mpeg HTTP/1.1 Host: 192.168.70.1:8080 Proxy-Connection: Keep-Alive Accept: */* User-Agent: Kreatel_IP-STB getcontentFeatures.dlna.org: 1 Can any one , share the appropriate code ?

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  • Google Reader API - feed/[FEEDURL]/ is coming back as Not found

    - by JustinXXVII
    There is one feed I'm subscribed to which always turns up as NOT FOUND when I try to use the API. I return an array of Dictionaries, containing 3 objects. The first in the list represents the user himself, like so: { FeedID = "user/MY_UNIQUE_NUMBER/state/com.google/reading-list"; Timestamp = 1273448807271463; Unread = 59; } The Unread count is very important. My client depends on downloading 59 items from Google before it refreshes. If a feed doesn't download properly, the count is off and the client won't update. An example of a working Feed is here: { FeedID = "feed/http://arstechnica.com/index.rssx"; Timestamp = 1273447158484528; Unread = 13; } The FeedID value combines with a specially formatted URL string and gives back a list of articles. The above example works fine. However, the following feed always returns NOT FOUND on Google, and if I paste the URL verbatim into a browser, it never turns up. See here: { FeedID = "feed/http://www.peopleofwalmart.com/?feed=rss2"; Timestamp = 1273424138183529; Unread = 6; } http://www.google.com/reader/api/0/stream/contents/feed/http://www.peopleofwalmart.com/?feed=rss2?ot=1&r=n&xt=user/-/state/com.google/read&n=6&ck=1273449028&client=testClient If you are at all proficient with the API, can you please help me? Like I said, since Google always says NOT FOUND when I search for that feed, my download count is off by N articles and won't update. I would rather not hack around it, honestly. Thanks!

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  • NoClassDefFoundError: HttpClient 4 (APACHE)

    - by Pujan Srivastava
    Hello All, I am using HC APACHE. I have added both httpcore-4.0.1.jar and httpclient-4.0.1.jar in the classpath of netbeans. I am getting error: java.lang.NoClassDefFoundError: org/apache/http/impl/client/DefaultHttpClient My Code is as follows. Please help. import org.apache.http.client.HttpClient; import org.apache.http.client.ResponseHandler; import org.apache.http.client.methods.HttpGet; import org.apache.http.impl.client.BasicResponseHandler; import org.apache.http.impl.client.DefaultHttpClient; public class HttpClientManager { public HttpClient httpclient; public HttpClientManager() { this.init(); } public void init() { try { httpclient = new DefaultHttpClient(); } catch (Exception e) { e.printStackTrace(); } } public void getCourseList() { String url = "http://exnet.in.th/api.php?username=demoinst&ha=2b62560&type=instructor"; HttpGet httpget = new HttpGet(url); ResponseHandler<String> responseHandler = new BasicResponseHandler(); try { String responseBody = httpclient.execute(httpget, responseHandler); System.out.println(responseBody); } catch (Exception e) { } } }

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  • Pulling specific entries from RSS feed [PHP]

    - by n0s
    So, I have an RSS feed with variations of each item. What I want to do is just get entries that contain a specific section of text. For example: <item> <title>RADIO SHOW - CF64K - 05-20-10 + WRAPUP </title> <link>http://linktoradioshow.com</link> <comments>Radio show from 05-20-10</comments> <pubDate>Thu, 20 May 2010 19:12:12 +0200</pubDate> <category domain="http://linktoradioshow.com/browse/199">Audio / Other</category> <dc:creator>n0s</dc:creator> <guid>http://otherlinktoradioshow.com/</guid> <enclosure url="http://linktoradioshow.com/" length="13005" /> </item> <item> <title>RADIO SHOW - CF128K - 05-20-10 + WRAPUP </title> <link>http://linktoradioshow.com</link> <comments>Radio show from 05-20-10</comments> <pubDate>Thu, 20 May 2010 19:12:12 +0200</pubDate> <category domain="http://linktoradioshow.com/browse/199">Audio / Other</category> <dc:creator>n0s</dc:creator> <guid>http://otherlinktoradioshow.com/</guid> <enclosure url="http://linktoradioshow.com/" length="13005" /> </item> I only want to display the results that contain the string CF64K. While it's probably really simple regex, I can't seem to wrap my head around getting it right. I always get seem to only be able to display the string 'CF64K', and not the stuff that surrounds it. Thanks in advance.

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  • Apply a Quartz filter while saving PDF under Mac OS X 10.6.3

    - by olpa
    Using Mac OS X API, I'm trying to save a PDF file with a Quartz filter applied, just like it is possible from the "Save As" dialog in the Preview application. So far I've written the following code (using Python and pyObjC, but it isn't important for me): -- filter-pdf.py: begin from Foundation import * from Quartz import * import objc page_rect = CGRectMake (0, 0, 612, 792) fdict = NSDictionary.dictionaryWithContentsOfFile_("/System/Library/Filters/Blue \ Tone.qfilter") in_pdf = CGPDFDocumentCreateWithProvider(CGDataProviderCreateWithFilename ("test .pdf")) url = CFURLCreateWithFileSystemPath(None, "test_out.pdf", kCFURLPOSIXPathStyle, False) c = CGPDFContextCreateWithURL(url, page_rect, fdict) np = CGPDFDocumentGetNumberOfPages(in_pdf) for ip in range (1, np+1): page = CGPDFDocumentGetPage(in_pdf, ip) r = CGPDFPageGetBoxRect(page, kCGPDFMediaBox) CGContextBeginPage(c, r) CGContextDrawPDFPage(c, page) CGContextEndPage(c) -- filter-pdf.py: end Unfortunalte, the filter "Blue Tone" isn't applied, the output PDF looks exactly as the input PDF. Question: what I missed? How to apply a filter? Well, the documentation doesn't promise that such way of creating and using "fdict" should cause that the filter is applied. But I just rewritten (as far as I can) sample code /Developer/Examples/Quartz/Python/filter-pdf.py, which was distributed with older versions of Mac (meanwhile, this code doesn't work too): ----- filter-pdf-old.py: begin from CoreGraphics import * import sys, os, math, getopt, string def usage (): print ''' usage: python filter-pdf.py FILTER INPUT-PDF OUTPUT-PDF Apply a ColorSync Filter to a PDF document. ''' def main (): page_rect = CGRectMake (0, 0, 612, 792) try: opts,args = getopt.getopt (sys.argv[1:], '', []) except getopt.GetoptError: usage () sys.exit (1) if len (args) != 3: usage () sys.exit (1) filter = CGContextFilterCreateDictionary (args[0]) if not filter: print 'Unable to create context filter' sys.exit (1) pdf = CGPDFDocumentCreateWithProvider (CGDataProviderCreateWithFilename (args[1])) if not pdf: print 'Unable to open input file' sys.exit (1) c = CGPDFContextCreateWithFilename (args[2], page_rect, filter) if not c: print 'Unable to create output context' sys.exit (1) for p in range (1, pdf.getNumberOfPages () + 1): #r = pdf.getMediaBox (p) r = pdf.getPage(p).getBoxRect(p) c.beginPage (r) c.drawPDFDocument (r, pdf, p) c.endPage () c.finish () if __name__ == '__main__': main () ----- filter-pdf-old.py: end

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  • how to dispaly image in grid view reading imageUrl from xml using sax parser in android

    - by Pramod kuamr
    thanks for answer but i am able to read xml file from url but i need if in xml imageUrl is there so show in grid view ..this is my xml file and read URL <?xml version="1.0" encoding="UTF-8"?> <channels> <channel> <name>ndtv</name> <logo>http://a3.twimg.com/profile_images/670625317/aam-logo--twitter.png</logo> <description>this is a news Channel</description> <rssfeed>ndtv.com</rssfeed> </channel> <channel> <name>star news</name> <logo>http://a3.twimg.com/profile_images/740897825/AndroidCast-350_normal.png</logo> <description>this is a newsChannel</description> <rssfeed>starnews.com</rssfeed> </channel> </channels>

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  • unable to get data from iphone application

    - by user317192
    Hi, I have made a php web services that takes the username and password from iPhone application and saves the data in the users table. I call that web service from my button touchup event like this: NSLog(userName.text); NSLog(password.text); NSString * dataTOB=[userName.text stringByAppendingString:password.text]; NSLog(dataTOB); NSData * postData=[dataTOB dataUsingEncoding:NSUTF8StringEncoding allowLossyConversion:YES]; NSString *postLength = [NSString stringWithFormat:@"%d", [postData length]]; NSLog(postLength); NSMutableURLRequest *request = [[[NSMutableURLRequest alloc] init] autorelease]; NSURL *url = [NSURL URLWithString:[NSString stringWithFormat:@"http://localhost:8888/write.php"]]; [request setURL:url]; [request setHTTPMethod:@"POST"]; [request setValue:postLength forHTTPHeaderField:@"Content-Length"]; [request setValue:@"application/x-www-form-urlencoded" forHTTPHeaderField:@"Content-Type"]; [request setHTTPBody:postData]; NSURLResponse *response; NSError *error; [NSURLConnection sendSynchronousRequest:request returningResponse:&response error:&error]; if(error==nil) NSLog(@"Error is nil"); else NSLog(@"Error is not nil"); NSLog(@"success!"); I am getting nothing from Iphone side into the web service and I am unable to understand why this is happening. Although i debugged and found that everything is fine at the iphone application level but the call to the web service doesn't works as expected...... Please suggest..... Thanks Ashish

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  • how to handle out of memory error?

    - by UMMA
    dear friends, i am using following code to display bitmap in my imageview. when i try to load image of size for example bigger than 1.5MB it give me error any one suggest me solution? try { URL aURL = new URL(myRemoteImages[val]); URLConnection conn = aURL.openConnection(); conn.connect(); InputStream is = null; try { is= conn.getInputStream(); }catch(IOException e) { return 0; } int a= conn.getConnectTimeout(); BufferedInputStream bis = new BufferedInputStream(is); Bitmap bm; try { bm = BitmapFactory.decodeStream(bis); }catch(Exception ex) { bis.close(); is.close(); return 0; } bis.close(); is.close(); img.setImageBitmap(bm); } catch (IOException e) { return 0; } return 1; Log cat 06-14 12:03:11.701: ERROR/AndroidRuntime(443): Uncaught handler: thread main exiting due to uncaught exception 06-14 12:03:11.861: ERROR/AndroidRuntime(443): java.lang.OutOfMemoryError: bitmap size exceeds VM budget 06-14 12:03:11.861: ERROR/AndroidRuntime(443): at android.graphics.BitmapFactory.nativeDecodeStream(Native Method)

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  • PHP & cUrl - POST problems in while loop.

    - by Max Hoff
    I have a while loop, with cUrl inside. (I can't use curl_multi for various reasons.) The problem is that cUrl seems to save the data it POSTS after each loop traversal. For instance, if parameter X is One the first loop through, and if it's Two the second loop through, cUrl posts: "One,Two". It should just POST "Two".(This is despite closing and unsetting the curl handle.) Here's a simplified version of the code (with unecessary info stripped out): while(true){ // code to form the $url. this code is local to the loop. so the variables should be "erased" and made new for each loop through. $ch = curl_init(); $userAgent = 'Googlebot/2.1 (http://www.googlebot.com/bot.html)'; curl_setopt($ch,CURLOPT_USERAGENT, $userAgent); curl_setopt($ch,CURLOPT_URL,$url); curl_setopt($ch,CURLOPT_POST,count($fields)); curl_setopt($ch,CURLOPT_POSTFIELDS,$fields_string); curl_setopt($ch, CURLOPT_FAILONERROR, true); curl_setopt($ch, CURLOPT_FOLLOWLOCATION, true); curl_setopt($ch, CURLOPT_AUTOREFERER, true); curl_setopt($ch, CURLOPT_RETURNTRANSFER,true); curl_setopt($ch, CURLOPT_TIMEOUT, 10); $html = curl_exec($ch); curl_close($ch); unset($ch); $dom = new DOMDocument(); @$dom->loadHTML($html); $xpath = new DOMXPath($dom); $resultTable = $xpath->evaluate("/html/body//table"); // $resultTable is 20 the first time through the loop, and 0 everytime thereafter becauset he POSTing doesn't work right with the "saved" parameters. What am I doing wrong here?

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  • Using AJAX to get a specific DOM Element (using Javascript, not jQuery)

    - by Matt Frost
    How do you use AJAX (in plain JavaScript, NOT jQuery) to get a page (same domain) and display just a specific DOM Element? (Such as the DOM element marked with the id of "bodyContent"). I'm working with MediaWiki 1.18, so my methods have to be a little less conventional (I know that a version of jQuery can be enabled for MediaWiki, but I don't have access to do that so I need to look at other options). I apologize if the code is messy, but there's a reason I need to build it this way. I'm mostly interested in seeing what can be done with the Javascript. Here's the HTML code: <div class="mediaWiki-AJAX"><a href="http://www.domain.com/whatever"></a></div> Here's the Javascript I have so far: var AJAXs = document.getElementsByClassName('mediaWiki-AJAX'); if (AJAXs.length > 0) { for (var i = AJAXs.length - 1; i >= 0; i--) { var URL = AJAXs[i].getElementsByTagName('a')[0].href; xmlhttp = new XMLHttpRequest(); xmlhttp.onreadystatechange = function() { if (xmlhttp.readyState == 4 && xmlhttp.status == 200) { AJAXs[i].innerHTML = xmlhttp.responseText; } } xmlhttp.open('GET',URL,true); xmlhttp.send(); } }

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  • Yii user rights extension

    - by jailed abroad
    i have installed the yii rights extension and here is my code after installation, database tables are created after installation. 'modules'=>array( // uncomment the following to enable the Gii tool 'rights'=>array( 'superuserName'=>'Admin', // Name of the role with super user privileges. 'authenticatedName'=>'Authenticated', //// Name of the authenticated user role. 'userIdColumn'=>'id',// Name of the user id column in the database. 'userNameColumn'=>'username', // Name of the user name column in the database. 'enableBizRule'=>true, // Whether to enable authorization item business rules. 'enableBizRuleData'=>false, //Whether to enable data for business rules. 'displayDescription'=>true, // Whether to use item description instead of name. ' // Key to use for setting success flash messages. 'flashErrorKey'=>'RightsError', / Key to use for setting error flash messages. // 'install'=>true, // Whether to install rights. 'baseUrl'=>'/rights', // Base URL for Rights. Change if module is nested. 'layout'=>'rights.views.layouts.main', // Layout to use for displaying Rights. 'appLayout'=>'application.views.layouts.main', //Application layout. 'cssFile'=>'rights.css', // Style sheet file to use for Rights. ' 'install'=>false, // Whether to enable installer. 'debug'=>false, ), 'gii'=>array( 'class'=>'system.gii.GiiModule', 'password'=>'1234', // If removed, Gii defaults to localhost only. Edit carefully to taste. 'ipFilters'=>array('127.0.0.1','::1'), ), ), But when i type url http://localhost/rightsTest/index.php/rights then it says There must be at least one superuser! I have tried many things but unable to find answer. Thanks for your help.

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  • UISplitView's DetailView not changing its content

    - by Knodel
    I have an iPad app with a UISplitView. In the Root View I have a two level UITableView (it takes its content from a plist). In the Detail View I have a UIWebView. - (void)tableView:(UITableView *)tableView didSelectRowAtIndexPath:(NSIndexPath *)indexPath { //Get the dictionary of the selected data source. NSDictionary *dictionary = [self.tableDataSource objectAtIndex:indexPath.row]; //Get the children of the present item. NSArray *Children = [dictionary objectForKey:@"Children"]; RootViewController *rvController = [[RootViewController alloc] init]; rvController.CurrentTitle = [dictionary objectForKey:@"Title"]; rvController.CurrentLevel = +1; //Push the new table view on the stack [self.navigationController pushViewController:rvController animated:YES]; rvController.tableDataSource = Children; NSString *name = [NSString stringWithFormat:@"%@.rtfd.zip", rvController.CurrentTitle ]; NSString* resourcePath = [[NSBundle mainBundle] resourcePath]; NSString* sourceFilePath = [resourcePath stringByAppendingPathComponent:name]; NSURL* url = [NSURL fileURLWithPath:sourceFilePath isDirectory:NO]; NSURLRequest* request = [NSURLRequest requestWithURL:url]; [detailViewController.webView loadRequest:request]; } That's how I want the UIWebView's content to be changed. If I name the .rtfd.zip file the same as a first level cell of the UITableView, it works, UIWebView's content changes. But this doesn't work with the second level UITableView. What am I doing wrong? Thanks in advance!

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  • Android App - disappearance of app GUI

    - by Radek Šimko
    I'm trying to create a simple app, whose main task is to open the browser on defined URL. I've created first Activity: public class MyActivity extends Activity { @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); //setContentView(R.layout.main); Intent myIntent = new Intent(Intent.ACTION_VIEW, Uri.parse("http://my.url.tld")); startActivity(myIntent); } Here's my AndroidManifest.xml: <manifest ...> <application ...> <activity android:name=".MyActivity" ...> <intent-filter> <action android:name="android.intent.action.MAIN"/> <category android:name="android.intent.category.LAUNCHER"/> </intent-filter> </activity> This code is fully functional, but before it opens the browser, it displays a black background - blank app GUI. I didn't figured out, how to go directly do the browser (without displaying the GUI). Anyone knows?

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  • Really frustrated: Help writing a sample twitter app

    - by Jack
    I have installed WAMP. I have enable cURL in php.ini. I want to implement a twitter app that posts a new status message for a user. Here's my code <?php function updateTwitter($status) { $username = 'xxxxxx'; $password = 'xxxx'; $url = 'http://twitter.com/statuses/update.xml'; $postargs = 'status='.urlencode($status); $responseInfo=array(); $ch = curl_init($url); curl_setopt($ch, CURLOPT_CONNECTTIMEOUT, 2); curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1); curl_setopt($ch, CURLOPT_PROXY,"localhost:80"); curl_setopt ($ch, CURLOPT_POST, true); // Give CURL the arguments in the POST curl_setopt ($ch, CURLOPT_POSTFIELDS, $postargs); // Set the username and password in the CURL call curl_setopt($ch, CURLOPT_USERPWD, $username.':'.$password); // Set some cur flags (not too important) $response = curl_exec($ch); if($response === false) { echo 'Curl error: ' . curl_error($ch); } else { echo 'Operation completed without any errors<br/>'; } // Get information about the response $responseInfo=curl_getinfo($ch); // Close the CURL connection curl_close($ch); // Make sure we received a response from Twitter if(intval($responseInfo['http_code'])==200){ // Display the response from Twitter echo $response; }else{ // Something went wrong echo "Error: " . $responseInfo['http_code']; } curl_close($ch); } updateTwitter("Just finished a sweet tutorial on http://brandontreb.com"); ?> I am getting the following output Operation completed without any errors Error: 404 Please help.

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  • parser 2.1 and 2.2

    - by yaniv
    hi i using the follwing Code to retrive XML element text using getElementsByTagName this code success in 2.2 and Failed in 2.1 any idea ? URL metafeedUrl = new URL("http://x..../Y.xml") URLConnection connection ; connection= metafeedUrl.openConnection(); HttpURLConnection httpConnection = (HttpURLConnection)connection ; int resposnseCode= httpConnection.getResponseCode() ; if (resposnseCode == HttpURLConnection.HTTP_OK) { InputStream in = httpConnection.getInputStream(); DocumentBuilderFactory dbf ; dbf = DocumentBuilderFactory.newInstance(); DocumentBuilder db = dbf.newDocumentBuilder(); // Parse the Earthquakes entry Document dom = db.parse(in); Element docEle = dom.getDocumentElement(); //ArrayList<Album> Albums = new ArrayList<Album>(); /* Returns a NodeList of all descendant Elements with a given tag name, in document order.*/ NodeList nl = docEle.getElementsByTagName("entry"); if (nl!=null && nl.getLength() > 0) { for (int i = 0; i < nl.getLength(); i++) { Element entry = (Element)nl.item(i); /* Now on every property in Entry **/ Element title =(Element)entry.getElementsByTagName("title").item(0); *Here i Get an Error* String album_Title = title.getTextContent(); Element id =(Element)entry.getElementsByTagName("id").item(0); String album_id = id.getTextContent(); //

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  • How to read properties file in Greek using Java

    - by Subhendu Mahanta
    I am trying to read from a properties file which have keys in English & values in greek.My code is like this: public class I18NSample { static public void main(String[] args) { String language; String country; if (args.length != 2) { language = new String("el"); country = new String("GR"); } else { language = new String(args[0]); country = new String(args[1]); } Locale currentLocale; ResourceBundle messages; currentLocale = new Locale(language, country); messages = ResourceBundle.getBundle("MessagesBundle",currentLocale, new CustomClassLoader("E:\\properties")); System.out.println(messages.getString("greetings")); System.out.println(messages.getString("inquiry")); System.out.println(messages.getString("farewell")); } } import java.io.File; import java.net.MalformedURLException; import java.net.URL; public class CustomClassLoader extends ClassLoader { private String path; public CustomClassLoader(String path) { super(); this.path = path; } @Override protected URL findResource(String name) { File f = new File(path + File.separator + name); try { return f.toURL(); } catch (MalformedURLException e) { e.printStackTrace(); } return super.findResource(name); } } MessagesBundle_el_GR.properties greetings=??µ. ?a??et? farewell=ep?f. a?t?? inquiry=t? ???e?s, t? ???ete I am compiling like this javac -encoding UTF8 CustomClassLoader.java javac -encoding UTF8 I18Sample.java When I run this I get garbled output.If the properies file is in English,French or German it works fine. Please help. Regards, Subhendu

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  • UITableView Inactive Until Scroll iPhone

    - by dubbeat
    HI, I'm trying to find the cause of some annoying behaviour with my UITableView. In each cell of my table (10 of them ) I asynchronously load an image. The problem is, is that if I don't touch the app at all the imageviews will permanently show a loading icon. However as soon as I scroll a cell off the screen and back on again the image shows straight away. What could be causing this "stuck in the mud" behaviour? Is there a way to force whatever gets called when the list is scrolled to make the needed update happen? #define ASYNC_IMAGE_TAG 9999 #define LABEL_TAG 8888 // Customize the appearance of table view cells. - (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath { PromoListItem *promo = [promoList objectAtIndex:indexPath.row]; static NSString *CellIdentifier = @"Cell"; AsyncImageView *asyncImageView = nil; UILabel *label = nil; UITableViewCell *cell = [tableView dequeueReusableCellWithIdentifier:CellIdentifier]; if (cell == nil) { cell = [[[UITableViewCell alloc] initWithStyle:UITableViewCellStyleDefault reuseIdentifier:CellIdentifier] autorelease]; CGRect frame; frame.origin.x = 0; frame.origin.y = 0; frame.size.width = 100; frame.size.height = 100; asyncImageView = [[[AsyncImageView alloc] initWithFrame:frame] autorelease]; asyncImageView.tag = ASYNC_IMAGE_TAG; [cell.contentView addSubview:asyncImageView]; frame.origin.x = 110; frame.size.width =100; label = [[[UILabel alloc] initWithFrame:frame] autorelease]; label.tag = LABEL_TAG; [cell.contentView addSubview:label]; cell.accessoryType = UITableViewCellAccessoryDisclosureIndicator; } else { asyncImageView = (AsyncImageView *) [cell.contentView viewWithTag:ASYNC_IMAGE_TAG]; label = (UILabel *) [cell.contentView viewWithTag:LABEL_TAG]; } NSURL *url = [NSURL URLWithString:promo.imgurl]; [asyncImageView loadImageFromURL:url]; label.text = promo.artistname; return cell; }

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  • Java webapp: how to implement a web bug (1x1 pixel)?

    - by NoozNooz42
    In the accepted answer in the following question, a SO regular with 13K+ rep suggests to use a "web bug" (non-cacheable 1x1 img) to be able to track requests in the logs: http://stackoverflow.com/questions/1784893 How can I do this in Java? Basically, I've got two issues: how to make sure the 1x1 image is not cacheable (how to set the header)? how to make sure the query for these 1x1 image will appear in the logs? I'm looking for exact piece of code because I know how to write a .jsp/servlet and I know how to serve an 1x1 image :) My question is really about the exact .jsp/servlet that I should write and how/what needs to be done so that Tomcat logs the request. For example I plan to use the following mapping: <servlet-mapping> <servlet-name>WebBugServlet</servlet-name> <url-pattern>/webbug*</url-pattern> </servlet-mapping> and then use an img tag referencing a "webbug.png" (or .gif), so how do I write the .jsp/servlet? What/where should I look for in the logs?

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  • JSF works only with the .xhtml ending

    - by ThreeFingerMark
    Hello, i start with the programming of a JSF Website. At the moment all files have the .xhtml ending. When i go to http://localhost:8080/myProject/start.jsf everything is all right. But when i rename the file from start.xhtml to start.jsf i became a NoClassDefFound Error. What is my mistake? <servlet-name>Faces Servlet</servlet-name> <servlet-class>javax.faces.webapp.FacesServlet</servlet-class> </servlet> <servlet-mapping> <servlet-name>Faces Servlet</servlet-name> <url-pattern>*.jsf</url-pattern> </servlet-mapping> <context-param> <param-name>javax.faces.PROJECT_STAGE</param-name> <param-value>Development</param-value> </context-param>

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  • What techniques can be used to detect so called "black holes" (a spider trap) when creating a web crawler?

    - by Tom
    When creating a web crawler, you have to design somekind of system that gathers links and add them to a queue. Some, if not most, of these links will be dynamic, which appear to be different, but do not add any value as they are specifically created to fool crawlers. An example: We tell our crawler to crawl the domain evil.com by entering an initial lookup URL. Lets assume we let it crawl the front page initially, evil.com/index The returned HTML will contain several "unique" links: evil.com/somePageOne evil.com/somePageTwo evil.com/somePageThree The crawler will add these to the buffer of uncrawled URLs. When somePageOne is being crawled, the crawler receives more URLs: evil.com/someSubPageOne evil.com/someSubPageTwo These appear to be unique, and so they are. They are unique in the sense that the returned content is different from previous pages and that the URL is new to the crawler, however it appears that this is only because the developer has made a "loop trap" or "black hole". The crawler will add this new sub page, and the sub page will have another sub page, which will also be added. This process can go on infinitely. The content of each page is unique, but totally useless (it is randomly generated text, or text pulled from a random source). Our crawler will keep finding new pages, which we actually are not interested in. These loop traps are very difficult to find, and if your crawler does not have anything to prevent them in place, it will get stuck on a certain domain for infinity. My question is, what techniques can be used to detect so called black holes? One of the most common answers I have heard is the introduction of a limit on the amount of pages to be crawled. However, I cannot see how this can be a reliable technique when you do not know what kind of site is to be crawled. A legit site, like Wikipedia, can have hundreds of thousands of pages. Such limit could return a false positive for these kind of sites. Any feedback is appreciated. Thanks.

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  • How can I properly handle 404s in ASP.NET MVC?

    - by Brian
    I am just getting started on ASP.NET MVC so bear with me. I've searched around this site and various others and have seen a few implementations of this. EDIT: I forgot to mention I am using RC2 Using URL Routing: routes.MapRoute( "Error", "{*url}", new { controller = "Errors", action = "NotFound" } //404s ); The above seems to take care of requests like this (assuming default route tables setup by initial MVC project): "/blah/blah/blah/blah" Overriding HandleUnknownAction() in the controller itself: //404s - handle here (bad action requested protected override void HandleUnknownAction(string actionName) { ViewData["actionName"] = actionName; View("NotFound").ExecuteResult(this.ControllerContext); } However the previous strategies do not handle a request to a Bad/Unknown controller. For example, I do not have a "/IDoNotExist", if I request this I get the generic 404 page from the web server and not my 404 if I use routing + override. So finally, my question is: Is there any way to catch this type of request using a route or something else in the MVC framework itself? OR should I just default to using Web.Config customErrors as my 404 handler and forget all this? I assume if I go with customErrors I'll have to store the generic 404 page outside of /Views due to the Web.Config restrictions on direct access. Anyway any best practices or guidance is appreciated.

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