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  • [JS] How to manipulate a PHP Array in javascript?

    - by rasouza
    I have an Array in PHP which contains data from database. And it prints out also as a table in the same page which has an AJAX delete function. Trying to explain better The array contains debt sums related to many people, it is the application's main function. In the same page, there is a table containing every debt record related to the array, which can be deleted or edited using AJAX. I have coded the part of deleting the record and removing the TR entry, but it's not enough: I'd like to change also the debt sum using AJAX which is an PHP Array. What I have I have the JS function which removes the TR when the delete button is clicked // TR Fading when deleted $('.delete') .click(function() { $.ajax({ type: 'GET', url: 'history/delete/id/'+$(this).attr('id') }); $(this).parent().parent().fadeOut(); return false; }); and I have the PHP array (image)

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  • Is it possible to configure Apache to host both an ASP.NET Web Service and a PHP Web site?

    - by Eduardo León
    Noob question (because I'm a noob when it comes to Web development). I'm not sure whether I should ask it here or at ServerFault. I am developing an ASP.NET Web Service and a PHP Web site consuming the Web Service. They are meant to be run on different machines. However, only for development purposes, I need to run both on my machine. I cannot use virtual machines. I would like to know if it is possible to configure IIS Apache to host both my Web Service and my Web site? Or, do I need to host the PHP site using Apache? I am using IIS 7.5 Apache HTTP Server 2.2 (NOTE: I have nothing against Apache. In fact, so far I like it more than IIS, however, I would rather not have two Web server applications installed in the same machine.) PHP 5.3.4 .NET Framework 2.0 3.0 or 3.5 (whichever comes with Visual Studio 2008) mod_aspdotnet for Apache 2.2

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  • Accessing php $_SESSION from python (wsgi) - is it possible?

    - by Bill Zimmerman
    Hi, I've got a python/WSGI app which needs to check to see if a user has logged on to a PHP web app. The problem is that the PHP app checks if a user has logged on by comparing a value in the $_SESSION variable to a value in the cookie from the user's browser. I would prefer to avoid changing the behavior of the php app if at all possible. My questions: Is there anyway I can access the session variables from within python? Where should I start to look? Are there any obvious security/performance issues I should be aware of when taking this approach?

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  • How to pass PHP array parameter to Javascript Function???

    - by Son of Man
    index.php <script type="text/javascript" src="javascript.js"> </script> <?php $movies = array("Bloodsport", "Kickboxer", "Cyborg", "Timecop", "Universal Soldier", "In Hell", "The Quest"); ?> <input type="submit" value="Test Javascript" onclick="showMovies(<?php echo $movies; ?>);" /> javascript.js function showMovies(movies) { alert(movies.length); return false; } I am new to programming so Im having hard time fixing this one which is obviously simple for you guys. When I hit the submit button it says the that the array size is 1 which I think should be 7. How could this be??? Pls tell me what to do... Thanks in Advance...

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  • Why would I see PHP NOTICE and ERRORs when running a script as a regular user, but not as root?

    - by Shawn
    As far as I can tell, there's no difference between the error reporting or message redirection between users. They both use the same PHP ini. However, when I run a script as a regular user, I get tons of NOTICES, when run as root, I get none. When starting PHP interactive mode as a regular user, I get two PHP Warnings that 'memcache' and 'xmlwriter' are already loaded; when starting as the root user, I get no warnings. I know that I should be fixing the warnings, not "making the warnings go away;" that's on the ticket. The question is, Why are the users treated differently? Why does a regular user get notices and warnings, but root does not, even if their error reporting are the same?

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  • How do I know if my PHP application is using too much memory?

    - by John
    I'm working on a PHP web application that let's users network with each other, book events, message etc... I launched it a few months ago and at the moment, there's only about 100 users. I set up the application on a VPS with ubuntu 9.10, apache 2, mysql 5 and php 5. I had 360 Mb of RAM, but upgraded to 720 MB a few minutes ago. Lately, my web application has been experiencing outages due to excessive memory usage. From what I can tell in error logs, it seems the server automatically kills apache processes that consume too much memory. As a result, I upgraded memory from 360 MB to 720 MB as a stop-gap measure. So my question is, how do I go about resolving these outage issues? How do I know if my website's need for more memory is due to poor code or if it's part of the website's natural growth? What's the most efficient way to determine which PHP scripts consume the most memory?

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  • How to get the age from a birthdate using PHP & MySQL?

    - by TaG
    I ask my users for their birthdate and store it in my database in the following way $month $day $year output May 6 1901 but I was wondering how can I get the age from the stored birthdate using PHP & MySQL? Here is the PHP code. if (isset($_POST['submitted'])) { $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"SELECT users.* FROM users WHERE user_id=3"); $month_options = array("Month", "January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December"); $day_options = array("Day", "1", "2", "3", "4", "5", "6", "7", "8", "9", "10", "11", "12", "13", "14", "15", "16", "17", "18", "19", "20", "21", "22", "23", "24", "25", "26", "27", "28", "29", "30", "31"); $month = mysqli_real_escape_string($mysqli, htmlentities(strip_tags($_POST['month']))); $day = mysqli_real_escape_string($mysqli, htmlentities(strip_tags($_POST['day']))); $year = mysqli_real_escape_string($mysqli, htmlentities(strip_tags($_POST['year']))); if (mysqli_num_rows($dbc) == 0) { $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"INSERT INTO users (user_id, month, day, year) VALUES ('$user_id', '$month', '$day', '$year')"); } if ($dbc == TRUE) { $dbc = mysqli_query($mysqli,"UPDATE users SET month = '$month', day = '$day', year = '$year' WHERE user_id = '$user_id'"); echo '<p class="changes-saved">Your changes have been saved!</p>'; } if (!$dbc) { print mysqli_error($mysqli); return; } } Here is the html. <form method="post" action="index.php"> <fieldset> <ul> <li><label>Date of Birth: </label> <label for="month" class="hide">Month: </label> <?php // month options echo '<select name="month" id="month">' . "\n"; foreach($month_options as $option) { if ($option == $month) { echo '<option value="' . stripslashes(htmlentities(strip_tags($option))) . '" selected="selected">' . stripslashes(htmlentities(strip_tags($option))) . '</option>' . "\n"; } else { echo '<option value="'. stripslashes(htmlentities(strip_tags($option))) . '">' . stripslashes(htmlentities(strip_tags($option))) . '</option>'."\n"; } } echo '</select>'; ?> <label for="day" class="hide">Day: </label> <?php // day options echo '<select id="day" name="day">' . "\n"; foreach($day_options as $option) { if ($option == $day) { echo '<option value="' . stripslashes(htmlentities(strip_tags($option))) . '" selected="selected">' . stripslashes(htmlentities(strip_tags($option))) . '</option>' . "\n"; } else { echo '<option value="'. stripslashes(htmlentities(strip_tags($option))) . '">' . stripslashes(htmlentities(strip_tags($option))) . '</option>'."\n"; } } echo '</select>'; ?> <label for="year" class="hide">Year: </label><input type="text" name="year" id="year" size="4" maxlength="4" value="<?php if (isset($_POST['year'])) { echo stripslashes(htmlentities(strip_tags($_POST['year']))); } else if(!empty($year)) { echo stripslashes(htmlentities(strip_tags($year))); } ?>" /></li> <li><input type="submit" name="submit" value="Save Changes" class="save-button" /> <input type="hidden" name="submitted" value="true" /> <input type="submit" name="submit" value="Preview Changes" class="preview-changes-button" /></li> </ul> </fieldset> </form>

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  • Why PHP (script) serves more requests than CGI (compiled)?

    - by Lucas Batistussi
    I developed the following CGI script and run on Apache 2 (http://localhost/test.chtml). I did same script in PHP (http://localhost/verifica.php). Later I performed Apache benchmark using Apache Benchmark tool. The results are showed in images. include #include <stdlib.h> int main(void) { printf("%s%c%c\n", "Content-Type:text/html;charset=iso-8859-1",13,10); printf("<TITLE>Multiplication results</TITLE>\n"); printf("<H3>Multiplication results</H3>\n"); return 0; } Someone can explain me why PHP serves more requests than CGI script?

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  • PHP reporting error. DB verify how to?

    - by iamfab
    Error reporting Notice: Undefined variable: random_chars in wamp\www\php_sandbox\idgen.php on line 21 Call Stack: # Time Memory Function Location 1 0.0045 678928 {main}( ) ..\idgen.php:0 GPB7446 How do I fix this error? Using this code like an automatic unique id generator. How do I connect to DB to verify code is truly unique before allowing it to be assigned to a user creating a new account? Thanks <?php $characters = array( "A","B","E","F","G","H","J","K","M","N","P","R","S","T","W","X","Y","Z"); $keys = array(); while(count($keys) < 3) { $x = mt_rand(0, count($characters)-1); if(!in_array($x, $keys)) { $keys[] = $x; } } foreach($keys as $key){ $random_chars .= $characters[$key];} $randNum = rand(2327,9987); $randLet = rand(2327,9987); echo $random_chars . $randNum; ?>

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  • Where do I put constants file for Codeigniter (PHP)?

    - by wag2639
    I have a list of constants (I'm using them as an enum), some are define statements, and some are just global variables. Where am I suppose to put them in the MVC framework so I can use them for both my model and my controller that needs to reference it? I'd rather not stick it into config/constants.php since they shouldn't be called except for by this model and the controllers that use it. Edit 1: Clarification To be more specific, I have my message_model model and it has a bunch of constants that I need that are stored in message_model_constants.php. Where should I put message_model_constants.php and is there a way to have it automatically included by the controller that loads message_model when message_model is not (and I don't want it to be) auto-loaded. Edit 2: I really don't want to have the constants auto-loaded except for when I use the model

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  • A beginner's question...How do I use $_POST instead of $_GET? (PHP)

    - by ggfan
    Okay, for all my coding so far I been using GETs and only $_POST on the same script. Ex: profile.php would show all the posts an user made and under each of their post, they can edit their post. The way I been using it is through $_GETs. So.. //this is the link users click to edit their post echo '<td><a href="editad.php?posting_id='.$row3['posting_id'].' ">Edit</a>'; //on the editad.php $posting_id=$_GET['posting_id']; if (isset($posting_id)){ //show all the forms, sqls to do the editing } else{ //if the $_GET hasn't been set echo "You have not specified which ad to edit. Please go back"; } How do I do this via POST? Thanks :)

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  • Why doesn't Google OpenID provider work with PHP-OpenId on my server?

    - by Steven Devijver
    Hey, I'm using PHP-OpenId 2.1.3 which I've unzipped on my server here (this is the consumer example that comes with PHP-OpenId). When I enter the Google OpenId url (https://www.google.com/accounts/o8/id) and submit I get a blank screen. When I try the exact same example code on the PHP-OpenId website here with the same URL it works fine. I don't understand what I'm doing wrong. The only thing I can think of is that somehow Google does not want to work with my server. Any ideas how to make this work? Thanks

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  • How do I return the numeric value from a database query in PHP?

    - by Luke
    Hello, I am looking to retreive a numerical value from the database function adminLevel() { $q = "SELECT userlevel FROM ".TBL_USERS." WHERE id = '$_SESSION[id]'"; return mysql_query($q, $this->connection); } This is the SQL. I then wrote the following php/html: <?php $q = $database->adminLevel(); if ($q > 7) { ?> <a href="newleague.php">Create a new league</a> <? } ?> The problem I have is that the userlevel returned isn't affecting the if statement. It is always displayed. How do i get it to test the value of userlevel is greater than 7? Thanks

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  • HTML block nested in PHP if statement - is this considered bad practice?

    - by JYelton
    Consider the following example: <table> <tr> <td>Row One</td> </tr> <?php if ($rowtwo) { ?> <tr> <td>Row Two</td> </tr> <?php } ?> </table> If $rowtwo is true, the second row is output, otherwise it is skipped. The code works as desired, however I am evaluating Netbeans (7 beta) as a PHP IDE (instead of just using a text editor). Netbeans flags the code with an error: Misplaced non-space characters insided [sic] a table. Should I consider an alternate way of writing this code, or is Netbeans incapable of understanding this flow control wrapper for HTML output?

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  • Using PHP's exec() function (or the likes), how can you display terminal error output?

    - by Miciah Amberong
    Previous Reference I am just wondering if there's a way (using PHP) to output the compile error information from the terminal to the browser? For example: If you use this code to execute in the terminal... gcc -o try try.c ...and assuming the "try.c" have some errors. The terminal will output something like this: try.c In function 'main': try.c:27 'x' undeclared (first use in this function) try.c:27 (Each undeclared identifier is reported only once try.c:27 for each function it appears in.) Meanwhile, using this PHP code... <?php exec("gcc -o try try.c"); ?> The browser does not return any output like the terminal does. Is there a possible way direct or indirect that the error details that the terminal showed can be passed to the be displayed on a browser? Thank you very much.

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  • How exactly do you use json_decode to pass a javascript array to php?

    - by Adam
    This is how I got my php array to javascript echo 'var daysofweek = '.json_encode($daysofweek).';'; Now I am aware that json_decode can do the opposite, however the problem is I don't know the syntax to do so. I tried: <script> var array_days = new Array(); array_days[] = "psdfo"; array_days[] = "bsdf"; <?php $array_days = json_decode(?>array_days<?php);?> </script> yes im clueless. I forgot to mention that I want to send an array through post, having all my information regarding all the form values dynamically created by javascript. Otherwise, I wouldn't know which name="" to look for as it will be decided by the user. Unless someone else has an alternative solution...

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  • Should I convert data arrays to objects in PHP in a CouchDB/Ajax app?

    - by karlthorwald
    I find myself converting between array and object all the time in PHP application that uses couchDB and Ajax. Of course I am also converting objects to JSON and back (for sometimes couchdb but mostly Ajax), but this is not so much disturbing my workflow. At the present I have php objects that are returned by the CouchDB modules I use and on the other hand I have the old habbit to return arrays like array("error"="not found","data"=$dataObj) from my functions. This leads to a mixed occurence of real php objects and nested arrays and I cast with (object) or (array) if necessary. The worst thing is that I know more or less by heart what a function returns, but not what type (array or object), so I often run into type errors. My plan is now to always cast arrays to objects before returning from a function. Of course this implies a lot of refactoring. Is this the right way to go? What about the conversion overhead? Other ideas or tips?

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  • Using PHP to grab the absolute URL of the script?

    - by Rob
    Basically, I want my script to output its absolute URL, but I don't want to statically program it into the script. For example, if my current URL is http://example.com/script.php I want to be able to store it as a variable, or echo it. i.e. $url = http://example.com/script.php; But if I move the script to a different server/domain, I want it to automatically adjust to that, i.e. $url = http://example2.com/newscript.php; But I have no idea how to go about doing this. Any ideas?

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  • Wordpress php: Way to test if pages are children of a parent page?

    - by Erykan
    Hi - Working on my first Wordpress site so I'm sure this is a really basic question. I'm struggling to write a conditional php statement that performs a certain action when a page is a child of a parent page. For example, rather than just specifying one page, as below, I'd like to specify all pages that have the 'About Us' page as a parent: <?php if (is_page('About Us')) echo 'Hello World!'; ?> I've tried the "child_of" function but it wasn't as straightforward as I'd hoped. When I use the below, I get a syntax error - probably just me not knowing how to use the function: <?php if (child_of('About Us')) echo 'Hello World!'; ?> Any suggestions? Thanks!!

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  • Interpreted vs. Compiled Languages for Web Sites (PHP, ASP, Perl, Python, etc.)

    - by Andrew Swift
    I build database-driven web sites. Previously I have used Perl or PHP with MySQL. Now I am starting a big new project, and I want to do it in the way that will result in the most responsive possible site. I have seen several pages here where questions about how to optimize PHP are criticized with various versions of "it's not worth going to great lengths to optimize PHP since it's an interpreted language and it won't make that much difference". I have also heard various discussions (especiallon on the SO podcast) about the benefits of compiled vs. interpreted languages, and it seems as though it would be in my interests to use a compiled language to serve up the site instead of an interpreted language. Is this even possible in a web context? If so, what would be a reasonable language choice? In addition to speed one benefit I forsee is the possiblity of finding bugs at compile time instead of having to debug the web site. Is this reasonable to expect?

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  • PHP - login to a remote server, trough my own server, with HTTPS, cookies and proxy, and downloading the html

    - by Yunga Mohani
    Hello, so what i am trying to do is this: login to the other server with a PHP on my own server (either with my username and pass/or with my cookies) then have access to the page i want to display/download i want to write a PHP script that is located on my own server, that automatically does a login to another server, that uses HTTPS and a web form for login. after the login i have access to that page that i am trying to download. i dont know if it would be possible to login and download the html only with the cookies that i have in my browser through a previous login, or if i need to do the login in my php script through some https login method. can i do any of this with curl or fsocksopen or what would be the best way to realize this? thanks in advance!

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  • What's the safest way to remove data from mysql? (PHP/Mysql)

    - by ggfan
    I want to allow users as well as me(the admin) to delete data in mysql. I used to have remove.php that would get $_GETs from whatever that needed to be deleted such as... remove.php?action=post&posting_id=2. But I learned that anyone can simply abuse it and delete all my data. So what's the safest way for users and me to delete information without getting all crazy and hard? I am only a beginner :) I'm not sure if I can use POSTs because there is no forms and the data isn't changing. Is sessions good? Or would there be too many with postings, user information, comments, etc. Ex: James wants to delete one of his postings(it is posting_id=5). So he clicks the remove link and that takes him to remove.php?action=post&posting_id=5.

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  • php mysqli help, first line in DB not being returned?

    - by williamsongibson
    Here is my code <?php require_once 'connect.php'; $sql = "SELECT * FROM `db-pages`"; $result = $mysqli->query($sql) or die($mysqli->error.__LINE__); while ($row = $result->fetch_assoc()) { echo($row['pagetitle'].' - To edit this page <a href="editpage.php?id='.$row['id'].'">click here</a><br>'); } } ?> I've added a couple more rows to the Database and it's returning them all, apart from id=1 in the DB. Any idea why?

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  • Not Installing Sqlite 3 on CentOS correctly

    - by Ming
    I need to get sqlite 3 installed for php on a CentOS but its still telling that it's not installed. I did the command and got this message: yum install sqlite Package sqlite-3.6.20-1.el6.x86_64 already installed and latest version I looked into php.ini and notice this, but not sure if it's any use [sqlite] ; http://www.php.net/manual/en/sqlite.configuration.php#ini.sqlite.assoc-case ;sqlite.assoc_case = 0 [sqlite3] ;sqlite3.extension_dir =: Let me know what else you need?

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  • order of operations for environment variables

    - by alyda
    I want to understand how environment variables are set and reset (overridden). I'm running Apache/2.2.24 (Unix) PHP/5.4.14 on a mac . My theory is this: Environment vars can be set in bash, then they can be overwritten with httpd.conf preceding a VirtualHost directive that precedes php.ini, which can then be overwritten by .htaccess (if allowable) and finally by PHP I tried the following: setting environment variable in bash: I added export ENVIRONMENT='local' to my ~/.bashrc file, restarted apache and did not get any output from print_r($_ENV); (in a simple index.php file at the root of my webserver). I also tried putting ENVIRONMENT='local' into /etc/environment, and restarting apache, nothing, as well as /etc/bashrc, restart apache. still nothing. setting environment variable in httpd.conf: I added SetEnv ENVIRONMENT 'local-httpd to the end of my /etc/apache2/httpd.conf file (but before I load other conf files, such as virtual host [Include /private/etc/apache2/other/*.conf]). I now see the variable in the array print_r($_SERVER); but not print_r($_ENV);. setting environment variable in httpd-vhosts.conf: I added SetEnv ENVIRONMENT 'local-vhost to my /etc/apache2/extra/httpd-vhosts.conf file in my generic directive that points to my default document root. I now see the variable has been overwritten (to local-vhost from local-httpd, so I know where the variable is getting set). setting environment variable in php.ini: while searching for a proper place to put my environment variable, I noticed that variables_order = "GPCS" was set to the production value rather than EGPCS. I changed it, restarted my server and found that I was now getting output for print_r($_ENV); but not my expected custom variable. It also appears that I am not able to set a custom variable in this file. Please tell me if I am wrong setting environment variable in .htaccess: I added SetEnv ENVIRONMENT 'local-htaccess'. This worked as expected, overwriting all other values that were set. setting / overwriting environment variable in PHP: if (...) { putenv('ENVIRONMENT=local'); } I'm asking this question because I have a lot of local and remote testing servers, some of which may or may not allow me access to modify httpd, httpd-vhost, php.ini or environment variables. I want to understand what is best for those difference scenarios (shared hosting, heroku, local servers, etc) I obviously don't know how to properly set the environment variable in bash in a way that php can use it, I'd like to know how to do that (as I think Heroku does something similar with heroku config set...)

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