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  • PHP strtotime() setting date to default

    - by Paddyd
    I have a script which is reading values from an excel sheet and inserting them into an sql table. My problem is when the script reads in some of the date fields it is setting them to a default value : 1970-01-01 01:00:00 I have noticed that this is happening when it comes across a date where the 'day' is greater than 12 : 13/05/2012 18:52:33 (dd-mm-yyyy hh-mm-ss) I thought this may be due to the script thinking that this is the month field (i.e american format) and it sees it as an invalid value, so I set the default timezone to my own hoping it may resolve the problem but it made no difference. date_default_timezone_set('Europe/Dublin'); Here is an example of what my code is doing: Excel field value : 01/05/2012 18:32:45 Script: $start_time = $data->val($x,5); echo $start_time = date("Y-m-d H:i:s", strtotime($start_time)); Output: 2012-01-05 18:32:45 This is the exact format I am looking for (except for the fact that the day and month fields are switched around i.e american date format) but it doesnt work for the type of dates I mentioned above.

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  • PHP sort multidimensional array by value

    - by stef
    How can I sort this array by the value of the "order" key? Even though the values are currently sequential, they will not always be. Array ( [0] => Array ( [hashtag] => a7e87329b5eab8578f4f1098a152d6f4 [title] => Flower [order] => 3 ) [1] => Array ( [hashtag] => b24ce0cd392a5b0b8dedc66c25213594 [title] => Free [order] => 2 ) [2] => Array ( [hashtag] => e7d31fc0602fb2ede144d18cdffd816b [title] => Ready [order] => 1 ) )

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  • PHP preg_match image between html tags

    - by Alvins
    I've got an html template like this: <div class="cont"> <div class="..."> <p>...<p> <img alt="" class="popup" src="DESIRED IMAGE LINK" style="..." /></p><p>...</p> .... And i want to extract "DESIRED IMAGE LINK" inside the "" tag, currently i'm using this: $pattern = '<div class="cont">.*?src=["\']?([^"\']?.*?(png|jpg|jpeg|gif))["\']?/i'; if (preg_match($pattern, $content, $image)) ..... But it doesn't work, the error is: warning: preg_match() [function.preg-match]: Unknown modifier '.' How can i fix it? Thanks

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  • Get websites title and description, save to utf8 table, php/mysql

    - by Geteburg
    Hi guys, I've been trying today all day to figure this out and I have no idea. What I want: Get the title and meta description of any kind of website. Save this info to utf table in mysql. What the problem is? Different sites have different charsets which results in that some have chinese, some contain umlauts (german), then we have russian and so on.. I've tried preg_match which works for some while not for others, i've tried DOMdocument which is the same as preg_match. Is there any class available that will do this? Hope someone can help, thanks.

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  • php web based portal authentication through IP.

    - by user434885
    i have a web portal running which involves basic data entry. The issue being that this is highly sensitive data. And the credibility of the data entry personel is very low. Therefore i have implemented recording of IP when an entry is made. The Problem i am facing is if this if this person starts forwarding his IP from a proxy server then i am unable to track authenticity of the data. How do i detect if the IP forwarding is happening/ get the real ip address of the person.

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  • PHP array minor problem

    - by Sennheiser
    I'm really not sure how to explain this. It's so simple I can't fathom why it's not working. I have a loop. It puts a bunch of strings into an array. If I fill a single variable with any given string, it will output it perfectly. But filling an array with the strings will make it give me the dreaded: Array Array Array Array Array Array Array Array Note: my strings are not all 'Array'. The way I loop is: while(...) { $arr[] = $resultFromLoop; } Here is my var_dump. array(1) { ["tagName"]=> string(5) "magic" } array(1) { ["tagName"]=> string(4) "nunu" } array(1) { ["tagName"]=> string(5) "books" } array(1) { ["tagName"]=> string(0) "" } array(1) { ["tagName"]=> string(3) "zzz" } array(1) { ["tagName"]=> string(4) "grey" } array(1) { ["tagName"]=> string(3) "new" } array(1) { ["tagName"]=> string(6) "flight" }

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  • PHP Array to CSV

    - by JohnnyFaldo
    I'm trying to convert an array of products into a CSV file, but it doesn't seem to be going to plan. The CSV file is one long line, here is my code: for($i=0;$i<count($prods);$i++) { $sql = "SELECT * FROM products WHERE id = '".$prods[$i]."'"; $result = $mysqli->query($sql); $info = $result->fetch_array(); } $header = ''; for($i=0;$i<count($info);$i++) { $row = $info[$i]; $line = ''; for($b=0;$b<count($row);$b++) { $value = $row[$b]; if ( ( !isset( $value ) ) || ( $value == "" ) ) { $value = "\t"; } else { $value = str_replace( '"' , '""' , $value ); $value = '"' . $value . '"' . "\t"; } $line .= $value; } $data .= trim( $line ) . "\n"; } $data = str_replace( "\r" , "" , $data ); if ( $data == "" ) { $data = "\n(0) Records Found!\n"; } header("Content-type: application/octet-stream"); header("Content-Disposition: attachment; filename=your_desired_name.xls"); header("Pragma: no-cache"); header("Expires: 0"); print "$data"; Also, the header doesn't force a download. I've been copy and pasting the output and saving as .csv

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  • php:: apply backticks to first word in sentence

    - by Hailwood
    Hi guys, basically what I am trying to do is, I have an array that looks something like this: array( array( 'select' =>'first string', 'escape' => true ), array( 'select' =>'second', 'escape' => true ), array( 'select' =>'the third string', 'escape' => true ), array( 'select' =>'fourth string', 'escape' => false ), ) I am looping over it and I want to end up with this output array( array( 'select' =>'`first` string', 'escape' => true ), array( 'select' =>'`second`', 'escape' => true ), array( 'select' =>'`the` third string', 'escape' => true ), array( 'select' =>'fourth string', 'escape' => false ), ) so basic rules are backticks are only applied if escape is true backticks are only applied to the first word in a sentence if there is only one word backticks are applied to the word My plan was to use if($item['escape']) { $pos = (strpos($item['select'], ' ') === false ? strlen($item['select']) : strpos($item['select'], ' ')); $item['select'] = '`' . substr($item['select'], 0, $pos) . '`' . substr($item['select'], $pos, strlen($item['select'])); } but the $item['select'] = line seems rather long winded, is there a better way to write it?

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  • php values of one array to key of another array

    - by mark
    I have 2 arrays $arr1 = Array ( [0] => 12 [1] => 4 [2] => 8 [3] => xx [4] => 1 [5] => 1year [6] => 7 ) $arr2 = Array ( [0] => 1 [1] => 2 [2] => 3 [3] => 4 [4] => 5 [5] => 6 [6] => 7 ) I want to create a new array with the values of a2 as keys in $arr1. My resultant array should be like this $arr3 = Array ( [1] => 12 [2] => 4 [3] => 8 [4] => xx [5] => 1 [6] => 1year [7] => 7 )

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  • PHP: Remove blank line before text

    - by Bailey
    Occasionally, my email-to-support-ticket system catches an extra line break before the message itself, thus my messages look like this: " Hello. I have been wondering if y..." What can I use to get rid of that line before the text? It is on random occasion due to email providers and the way they format their emails using mime. I have already tried the trim functions but no luck. (Yes, I also tried ltrim) Once processed it should look like: "Hello. I have been wondering if y..."

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  • PHP MYSQL SIMPLE SEARCH ISSUE

    - by Kunal
    Hi I have a table with the following structure: id int(11), name varchar(250) I have lots of records in the table but when I am trying to find a particluar record which has the following value on the name field: Lorem ipsum d\'olor sit amet The query is simply returning a blank recordset. I am not being able to figure out this weird behaviour, when my query is as simple as follows: SELECT * FROM slot_games WHERE name='Lorem ipsum d\'olor sit amet' Would appreciate your help please! Thanks in advance.

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  • PHP - ftp_get only works once

    - by William
    I'm connecting to an ftp server that I have no control over, and I'm pretty sure is using something old and outdated due to other issues I've run into. I'm simply using this code in a loop to get all the files in a directory. ftp_put($this->conn_id, $remote, $local, FTP_ASCII); The first time all goes well, but after that I get this error thrown for each file I try to get: "There is already an active transaction" I've tried both passive & active with no luck. It's the exact same code I use to connect to other FTP servers and get files with no problem. Any ideas? I suppose my last resort could be disconnecting and reconnecting for each file, but that seems like a huge waste.

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  • PHP: Remove all fcn not acting as expected, Code Inside

    - by Josh K
    I made this simple function (remove all $elem from $array): function remall($array, $elem) { for($i=0; $i < count($array); $i++) if($array[$i] == $elem) unset($array[$i]); $newarray = array_values($array); return $newarray; } But it isn't working perfectly, here are some inputs and outputs $u = array(1, 7, 2, 7, 3, 7, 4, 7, 5, 7, 6, 7); $r = remall($u, 7); Output of $r: 12345767 $n = array(7, 7, 1, 7, 3, 4, 6, 7, 2, 3, 1, -3, 10, 11, 7, 7, 7, 2, 7); $r = remall($n, 7); Output of $r: 1346231-30117727 Notice how there are still 7s in my outputs. Also, My function will only be removing numbers from an array. Let me know if you spot something, thanks.

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  • Empty files generated from running `mysqldump` using PHP

    - by alex
    I keep getting empty files generated from running $command = 'mysqldump --opt -h localhost -u username -p \'password\' dbname > \'backup 2009-04-15 09-57-13.sql\''; command($command); Anyone know what might be causing this? My password has strange characters in it, but works fine with connecting to the db. I've ran exec($command, $return) and outputted the $return array and it is finding the command. I've also ran it with mysqldump > file.sql and the file contains Usage: mysqldump [OPTIONS] database [tables] OR mysqldump [OPTIONS] --databases [OPTIONS] DB1 [DB2 DB3...] OR mysqldump [OPTIONS] --all-databases [OPTIONS] For more options, use mysqldump --help So it would seem like the command is working.

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  • PHP variable question

    - by Kyle Parisi
    This works: $customerBox = mysql_query("MY SQL STATEMENT HERE"); $boxRow = mysql_fetch_array($customerBox); $customerBox = mysql_query("MY SQL STATEMENT AGAIN"); while($item = mysql_fetch_assoc($customerBox)) { foreach ($item as $columnName = $value) { if (empty($value)) { print $columnName; } } } This does not: $customerBox = mysql_query("MY SQL STATEMENT HERE"); $boxRow = mysql_fetch_array($customerBox); while($item = mysql_fetch_assoc($customerBox)) { foreach ($item as $columnName = $value) { if (empty($value)) { print $columnName; } } } Why? I guess I don't understand how variables work yet.

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  • Php read directory file

    - by kwek-kwek
    I have a script that goes through a directory that has 3 images $imglist=''; $img_folder = "path to my image"; //use the directory class $imgs = dir($img_folder); //read all files from the directory, checks if are images and ads them to a list while ($file = $imgs->read()) { if (eregi("gif", $file) || eregi("jpg", $file) || eregi("png", $file)) $imglist .= "$file "; } closedir($imgs->handle); //put all images into an array $imglist = explode(" ", $imglist); //display image foreach($imglist as $image) { echo '<img src="'.$img_folder.$image.'">'; } but the problem that I am having is it display a 4th img with no image.. yet I only have 3 image in that folder.

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  • php adding value to session

    - by antikbd
    I am trying to implement a 'shopping cart' where, if the 'Add to Cart' has been clicked, the respective item is either added to the cart or incremented by one if already present. However, the following code isn't working and giving me a "Cannot use a scalar value as an array" error. Any help would be highly appreciated. if (isset($_POST['fan']) && ($_POST['fan']=="Add to Cart")) { if (($_SESSION['cart']['fan']==0) || (!isset($_SESSION['cart']['fan']))) { $_SESSION['cart']['fan']=1; } else { $_SESSION['cart']['fan']++; } }

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  • Can't figure out what's wrong with my php/sql statement

    - by Olegious
    So this is probably a dumb beginner question, but I've been looking at it and can't figure it out. A bit of background: just practicing making a web app, a form on page 1 takes in some values from the user, posts them to the next page which contains the code to connect to the DB and populate the relevant tables. I establish the DB connection successfully, here's the code that contains the query: $conn->query("SET NAMES 'utf9'"); $query_str = "INSERT INTO 'qa'.'users' ('id', 'user_name','password' ,'email' ,'dob' ,'sx') VALUES (NULL, $username, $password, $email, $dob, $sx);"; $result = @$conn->query($query_str); Here's the error that is returned:Insert query failed: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ''qa'.'users' ('id', 'user_name' ,'password' ,'email' ,'dob' ,'s' at line 1 Thanks in advance!

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  • PHP SDK Requires two logins...doesn't recognize first

    - by Jay Konieczny
    I am using the following code to authenticate whether users are logged in or not. While users can log in, they have to click the login button twice. Additionally, sometimes even after they click the log-in button twice, my "user info" part of the page (earlier in the page than the content) shows them as logged out while the actual page shows them as logged in. Here is the code. Could someone suggest a better way of handling log-ins? function isLoggedIn($facebook) { if (isset($facebook) and $facebook->getUser() != 0) { // UserID exists, but user may still not be logged in. Let's check: try { $facebook->api('/me', 'GET'); // If this succeeds, then they are logged in. return true; } catch(FacebookApiException $e) { // Some kind of error, so not logged in. if(session_id() === '') session_destroy(); return false; } } else { if(session_id() === '') session_destroy(); return false; } } Thanks!

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  • help with php MVC problem

    - by aprencai
    hello, I have groups on my site and the urls have the following hierarchy: / groups / {id_group} / / groups / {id_group} / news / groups / {id_group} / gallery / groups / {id_group} / events / groups / {id_group} / events / {id_event} / groups / {id_group} / events / {id_event} / news / groups / {id_group} / events / {id_event} / gallery / groups / {id_group} / events / {id_event} / news As you can see a group can have news, gallery, etc. and in turn an event that is in a group can also have news, gallery, etc. How to implement this approach in a framework without specifying any specific one?, ie I would like some guidance on what would have modules, controllers, etc. Thanks.

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  • PHP --> SQL Server + Excel file upload from a specific row

    - by lucky
    I have a requirement in which, i need to upload an excel file into SQL Server database. It is working well till this point. But sometimes i am getting excel file in such a way, that the first 2 rows and columns are empty rows. That is not even fixed every time. so the format of the table after upload is not as expected. It is assigning F1, F2 as column names for the table in SQL Server. It varies from file to file. I want to program it in such away so that the user can enter the row number and the column number from where the actual data is starting. So that while upload it should from line 3 and column 2. I don't know how to specify that row and column while uploading. Please help me to solve the same.

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