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  • the error in the stringbuilder

    - by Kubi
    string rowString = "<tr id=\"row1\" bgcolor=\"#FFFFFF\" onMouseOver=\"this.bgColor='#EEEEEE';\" onMouseOut=\"this.bgColor='#FFFFFF';\" style=\"cursor:pointer;\">" + "<td bgcolor=\"#FFFFFF\"><img src=\"images/"+"-companylogofilename-"+"\" width=\"108\" height=\"32\" alt=\""+"-companyname-"+"\" /></td>" + //turkish.airlines.jpg airlineiconfilename, airline name "<td class=\"table_content\">{0}</td>" + "<td class=\"table_content\">{1}</td>" + "<td class=\"table_content\">{2}</td>" + "<td class=\"table_content\">{3}</td>" + "<td class=\"table_content\">{4}</td>" + "<td class=\"table_content\"><table width=\"98%\" border=\"0\" cellspacing=\"0\" cellpadding=\"0\">" + "<tr><td class=\"table_content\">{5}</td>" + "<td width=\"20\" align=\"right\">" + "<a href=\"default.aspx\" onClick=\"return hs.htmlExpand(this, { headingText: '{6} - {7}', width: 600, height: 215, targetX: 'row1 400px', targetY: 'row1 40px' })\">" + "<img src=\"images/arrow.png\" width=\"13\" height=\"16\" border=\"0\" class=\"tip\" onMouseOver=\"tooltip('Click for Details.');\" onMouseOut=\"exit();\" />" + "</a>"; accordionHTML.Append(String.Format(rowString, flight.Get_AirlineCode(), flight.Get_Clase(), flight.Get_Departure(), flight.Get_DeprtDate(), flight.Get_DeprtTime(), flight.Get_Destination(), flight.Get_Departure(), flight.Get_Destination())); Hi, Can someone please help me to find the mistake above ? I am getting an error as "Input string was not correct !"; Thanks in advance,

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  • Filter of Data in Gridview logical error please using asp.net

    - by RajuBabli Abbasi
    I wanted to filter the Data in asp.net but my Data is not filtering i have some logical error So please help me for this case i will be very thanks full to those who will help me please consider my code and replay me with code if you can so please i am waiting for your replay thanks again my asp.cs file is protected void Page_Load(object sender, EventArgs e) { if (!IsPostBack) { DisplayStudentInformation(); } } private void DisplayStudentInformation() { string filter = "%" + filterTextBox.Text + "%"; if (filter == String.Empty) filter = "%"; try { using (SqlDataReader reader = DAC.GetCompanyInformation(filter)) {//reader.Read(); StudentGridView.DataSource = reader; StudentGridView.DataBind(); } } catch (SqlException ex) { StatusLabel.Text = ex.Message; } } my .aspx file is asp:Table ID="Tabel" runat ="server" asp:TableRow asp:TableCell asp:Label ID="filterLabel" runat ="server" Text ="Company Name Filter:" AssociatedControlID="filterTextBox" /asp:TableCell asp:TableCell asp:TextBox ID="filterTextBox" runat="server" MaxLength ="50" /asp:TableCell asp:TableCell asp:Button ID="refreshButton" runat ="server" Text ="Filter" CausesValidation="false" / /asp:TableCell /asp:TableRow /asp:Table My DAC file is public static SqlDataReader GetCompanyInformation(string filter) { SqlDataReader reader; string sql = "SELECT * FROM Student WHERE LastName LIKE @prmLastName "; using(SqlCommand command = new SqlCommand (sql,ConnectionManager.GetConnection())) {//In ExecuteReader we pass the CommandBehavior as singleResult because we need the Single result and also passing the close connection when Datais retriev // command.Parameters.Add("@prmLastName", SqlDbType.VarChar, 25).Value = filter; command.Parameters.AddWithValue("@prmLastName", filter); reader = command.ExecuteReader(CommandBehavior.SingleResult | CommandBehavior.CloseConnection); } return reader; } Note:- When i don't use the If(!Ispostback) Condition and simply pass the DisplayStudentInformation(); method in my page load then Data can be filter but with If(!IspostBack ) condition which is also important for updating the data and for other purpose . Data can be filter . Se aim of the expert is that Filter the Data in a gridview using condition of IF(!IspostBack ) means without the removing is post back condition Filter the Data . I have been ask other about this question but no body solve this so please help me i will be very thanks full to you all ok

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  • Why "Not an ARRAY reference" error?

    - by Sandra Schlichting
    I have this script #!/usr/bin/perl use strict; use warnings; use yy; my $data = [ ["aax", "ert", "ddd"], ["asx", "eer", "kkk"], ["xkk", "fff", "lll"], ["xxj", "vtt", "lle"], ]; use Test::More tests => 4; is(yy::type1_to_type2(\$data, 'aax'), 'ert'); is(yy::type1_to_type3(\$data, 'asx'), 'kkk'); is(yy::type2_to_type3(\$data, 'fff'), 'lll'); is(yy::type3_to_type1(\$data, 'lle'), 'xxj'); which uses this module package yy; sub typeX_to_typeY { my ($x, $y, $data, $str) = @_; foreach (@$data) { if ($_->[$x - 1] eq $str) { return $_->[$y - 1]; } } return; } sub type1_to_type2 { typeX_to_typeY(1, 2, @_) } sub type1_to_type3 { typeX_to_typeY(1, 3, @_) } sub type2_to_type1 { typeX_to_typeY(2, 1, @_) } sub type2_to_type3 { typeX_to_typeY(2, 3, @_) } sub type3_to_type1 { typeX_to_typeY(3, 1, @_) } sub type3_to_type2 { typeX_to_typeY(3, 2, @_) } 1; and gives this error Not an ARRAY reference at yy.pm line 6. # Looks like your test died before it could output anything. The line it complains about is foreach (@$data) { Isn't this the way to pass an array reference? What am I doing wrong?

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  • ByteFlow installation Error on Windows

    - by Patrick
    Hi Folks, When I try to install ByteFlow on my Windows development machine, I got the following MySQL error, and I don't know what to do, please give me some suggestion. Thank you so much!!! E:\byteflow-5b6d964917b5>manage.py syncdb !!! Read about DEBUG in settings_local.py and then remove me !!! !!! Read about DEBUG in settings_local.py and then remove me !!! J:\Program Files\Python26\lib\site-packages\MySQLdb\converters.py:37: DeprecationWarning: the sets module is deprecated from sets import BaseSet, Set Creating table auth_permission Creating table auth_group Creating table auth_user Creating table auth_message Creating table django_content_type Creating table django_session Creating table django_site Creating table django_admin_log Creating table django_flatpage Creating table actionrecord Creating table blog_post Traceback (most recent call last): File "E:\byteflow-5b6d964917b5\manage.py", line 11, in <module> execute_manager(settings) File "J:\Program Files\Python26\lib\site-packages\django\core\management\__init__.py", line 362, in execute_manager utility.execute() File "J:\Program Files\Python26\lib\site-packages\django\core\management\__init__.py", line 303, in execute self.fetch_command(subcommand).run_from_argv(self.argv) File "J:\Program Files\Python26\lib\site-packages\django\core\management\base.py", line 195, in run_from_argv self.execute(*args, **options.__dict__) File "J:\Program Files\Python26\lib\site-packages\django\core\management\base.py", line 222, in execute output = self.handle(*args, **options) File "J:\Program Files\Python26\lib\site-packages\django\core\management\base.py", line 351, in handle return self.handle_noargs(**options) File "J:\Program Files\Python26\lib\site-packages\django\core\management\commands\syncdb.py", line 78, in handle_noargs cursor.execute(statement) File "J:\Program Files\Python26\lib\site-packages\django\db\backends\util.py", line 19, in execute return self.cursor.execute(sql, params) File "J:\Program Files\Python26\lib\site-packages\django\db\backends\mysql\base.py", line 84, in execute return self.cursor.execute(query, args) File "J:\Program Files\Python26\lib\site-packages\MySQLdb\cursors.py", line 166, in execute self.errorhandler(self, exc, value) File "J:\Program Files\Python26\lib\site-packages\MySQLdb\connections.py", line 35, in defaulterrorhandler raise errorclass, errorvalue _mysql_exceptions.OperationalError: (1071, 'Specified key was too long; max key length is 767 bytes')

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  • Powerpoint displays a "can't start the application" error when an Excel Chart object is embedded in

    - by A9S6
    This is a very common problem when Excel Worksheet or Chart is embedded into Word or Powerpoint. I am seeing this problem in both Word and Powerpoint and the reason it seems is the COM addin attached to Excel. The COM addin is written in C# (.NET). See the attached images for error dialogs. I debugged the addin and found a very strange behavior. The OnConnection(...), OnDisConnection(...) etc methods in the COM addin works fine until I add an event handler to the code. i.e. handle the Worksheet_SheetChange, SelectionChange or any similar event available in Excel. As soon as I add even a single event handler (though my code has several), Word and Powerpoint start complaining and do not Activate the embedded object. On some of the posts on the internet, people have been asked to remove the anti-virus addins for office (none in my case) so this makes me believe that the problem is somewhat related to COM addins which are loaded when the host app activates the object. Does anyone have any idea of whats happening here?

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  • OracleGlobalization.SetThreadInfo() ORA-12705 Error

    - by michele
    Hi guys! I'm stuck in a problem, i cannot workaround! I have a Oracle client 11, with registry key set to AMERICAN_AMERICA.WE8ISO8859P1. I cannot edit this key, but my application must get data from Oracle in Italian culture format. So I want to edit culture info form my application only. I'm trying to using OracleGlobalization class in ODP.NET library before my Application.Run(), to set culture for my thread: OracleGlobalization og = OracleGlobalization.GetThreadInfo(); //OracleGlobalization.SetThreadInfo(OracleGlobalization.GetThreadInfo()); og.Calendar = "GREGORIAN"; og.Comparison = "BINARY"; og.Currency = "€"; og.DateFormat = "DD-MON-RR"; og.DateLanguage = "ITALIAN"; og.DualCurrency = "€"; og.ISOCurrency = "ITALY"; og.Language = "ITALIAN"; og.LengthSemantics = "BYTE"; og.NCharConversionException = false; og.NumericCharacters = ",."; og.Sort = "WEST_EUROPEAN"; og.Territory = "ITALY"; OracleGlobalization.SetThreadInfo(og); I get always the same error: ORA-12705: Cannot access NLS data files or invalid environment specified. I really don't know ho to solve this problem! Any hint? I'm working on a Win7 pc with VisualStudio 2008. Thank you in advance!

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  • DroDownlist in DataGrid produces Error

    - by S Nash
    I have a DataGrid and everytime I change value of it's embeded dropdwonlist I get: "System.Web.HttpException: The IListSource does not contain any data sources." I have a data grid which loads fine: Name column is editable. I have a dropdownlist these : DataDataGrid gets its value from a table. (Select Name, Address From Persons) Dropdown list also gets list of names from the same table. So DataGrid and dropdownlist are bound to 2 different datasets. Here is my code for dataGrid" <Columns> <ASP:ButtonColumn Text="Delete" CommandName="Delete"></ASP:ButtonColumn> <asp:EditCommandColumn ButtonType="LinkButton" UpdateText="Update" CancelText="Cancel" EditText="Edit"></asp:EditCommandColumn> <ASP:TemplateColumn HeaderText="Name" SortExpression="FY" HeaderStyle-HorizontalAlign="center" HeaderStyle-Wrap="True"> <ItemStyle Wrap="false" HorizontalAlign="left" /> <ItemTemplate> <ASP:Label ID="Name" Text='<%# DataBinder.Eval(Container.DataItem, "Name") %>' runat="server"/> </ItemTemplate> <EditItemTemplate> <ASP:DropDownList id="ddlName" cssClass="DropDownList" runat="server" datasource="<%#allNames%>" DataTextField= "Name" DataValueField="ID" Defaultvalue='<%# DataBinder.Eval(Container.DataItem, "ID") %>' OnPreRender="SetDefaultListItem" accessKey="I" AutoPostBack="true" /> </EditItemTemplate> </ASP:TemplateColumn> <asp:BoundColumn DataField="Address" ReadOnly="True" HeaderText="Address"></asp:BoundColumn> </Columns> Error happens here : dg.DataSource = ds dg.DataBind() Any ideas how to solve this issues? All I want is a DataGrid with a editable column ,which can be edited by choosing one of the value of in a dropdownlist.

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  • Paypal Error - IPN Validation Failed.

    - by user504178
    Hello , I am getting below error. [12/26/2010 5:48 AM] - FAIL: IPN Validation Failed. IPN POST Vars from Paypal: auth=A76zglTH7sCSLAVjZISTEp38SYXWAoNlO1uurxDvnlFy40uy-mlrvqkp_S5q3bFhVBbO2GwpJRvdYDvfQuM0581EYkEITS1SnDzfWV-ju60OZm_VzHsc8o2Q8K7mmZuDs9ANFwW9iIP2Ig8fGPSwZN8APK2PtCMIda28rBnNMJ2FWaeNKgmzTCuG5HnpzLD7ZtTCElp4MC05kyx9Ro-9ggqzVx7OU1zleJ_c1W, form_charset=UTF-8, IPN Response from Paypal Server: HTTP/1.1 200 OK Date: Sun, 26 Dec 2010 10:48:50 GMT Server: Apache Set-Cookie: c9MWDuvPtT9GIMyPc3jwol1VSlO=Ejohjh-kFgFpKAeNiYlgG8LwsLOi5Sir4Ut7tXINWaRmWM2eNXfFkJRQmO09WqBbXWIpXd0ydzrS7JMWO0sHZMg0Wfdd4gt6UcpSswiiUl2EfiP_ykxKJOFOzcjMrn_6xzc8GG%7c5mvwkJOzeFg-vpKR1fovKAVDyvmzI5sFbPatUC6gbf9Wk4Llel4btOJa7uQbYSLhuprHVG%7c537g5xvn4Hns8l-HE1pnyQ2GUAxcSINm-oVJENMuU6yS_bYa4IAw4QlGP-0zq80pjZa5j0%7c1293360531; domain=.paypal.com; path=/ Set-Cookie: cookie_check=yes; expires=Wed, 23-Dec-2020 10:48:51 GMT; domain=.paypal.com; path=/ Set-Cookie: navcmd=_notify-validate; domain=.paypal.com; path=/ Set-Cookie: navlns=0.0; expires=Sat, 21-Dec-2030 10:48:51 GMT; domain=.paypal.com; path=/ Set-Cookie: Apache=10.191.196.11.222161293360530699; path=/; expires=Sat, 12-Nov-04 04:20:34 GMT Connection: close Transfer-Encoding: chunked Content-Type: text/html; charset=UTF-8 7 INVALID 0 Can anyone please let me know whats wrong over here. Regards, Atul

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  • Validation error while putting <h> tag inside <a> tag(document type does not allow element "h2")

    - by makmour
    when using this code: <div class="menu"> <ul id="mainnav"> <li><h2><a href="dir1/" >AAAAA</a></h2> <ul> <li><a href="dir1/xxx.php"><h3>xxx</h3></a></li> <li><a href="dir1/xxx2.php"><h3>xxx2</h3></a></li> <li><a href="dir1/hxxx3.php"><h3>hxxx3</h3></a></li> </ul> </li> I get an error while validating saying that I should put <h2> outside of <a>. document type does not allow element <h2> When I do this validation passes without any problems but my styling breaks. Is there a way to keep both validation and styling? This is styling for menu and <h2> .menu li a{ font: 100% Helvetica, Arial, sans-serif; display:inline-block; color: #fff; } .menu li a:hover{ color: #014661; background: url('../images/menu1.png') center left no-repeat; } .menu li a h2{ font-size: 92%; padding: 8px 18px; font-weight: bold; text-transform: uppercase; } .menu h3{ font-size: 87%; font-weight: bold; text-transform: uppercase; } .menu li a h2:hover{ background: url('../images/menu2.png') center right no-repeat; }

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  • Error setting env thru subprocess.call to run a python script on a remote linux machine

    - by John Smith
    I am running a python script on a windows machine to invoke another python script on a remote linux machine. I am using subprocess.call with ssh to do this, like below: subprocess.call('ssh -i <identify file> username@hostname python <script_on_linux_machine>') and this works fine. However, if I want to set some environment variables, like below: subprocess.call('ssh -i <identify file> username@hostname python <script_on_linux_machine>', env={key1:value1}) it fails. I get the following error: ssh_connect: getnameinfo failed ssh: connect to host <hostname> port 22: Operation not permitted 255 I've tried splitting the ssh commands into list and passing. Didn't help. I've tried to run other 'local'(windows) commands thru subprocess.call() and tried setting the env. It works fine. I've tried to run other commands(such as ls) on the remote linux machine. Again, subprocess.call() works fine, as long as I don't try to set the environment. What am I doing wrong? Would I be able to set the environment for a python script on a remote machine? Any help will be appreciated.

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  • Parameter cannot be null error after success save

    - by tigermain
    I am getting the following nhibernate error when saving an entity (via: NHibernateSession.Save(entity);) despite it being persisted to the database fine "Value cannot be null.\r\nParameter name: id" This is my hbm file <?xml version="1.0" encoding="utf-8" ?> <hibernate-mapping xmlns="urn:nhibernate-mapping-2.2" namespace="JeanieMaster.Domain.Entities" assembly="JeanieMaster.Domain"> <class name="ActionLog" table="ActionLog" schema="[DBSVR1].[mydatabase].[dbo]" select-before-update="false" optimistic-lock="none"> <id name="Id" column="ActionLogId" type="Int32"> <generator class="identity"/> </id> <property name="ActionId" type="Int32"/> <many-to-one name="User" class="JeanieUser" column="UserId" /> <many-to-one name="ApplicationProvider" class="ApplicationProvider" column="ApplicationProviderId" /> <many-to-one name="ContentProvider" class="ContentProvider" column="ContentProviderId" /> <many-to-one name="SearchLog" class="SearchLog" column="SearchLogId" /> <property name="Data" type="string"/> <property name="DateCreated" type="DateTime"/> <property name="ActionDuration" type="Double"/> </class> </hibernate-mapping>

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  • Set ContentTemplate in CodeBehind: XamlParseException 2260 Error

    - by user362215
    Hi, I'd like to change the ContentTemplate of a ContentPresenter in the CodeBehind file. But if I run the Silverlight 4 application a XamlParseException with the error code 2260 occures. foreach (ContentPresenter item in Headers) { item.ContentTemplate = Parent.UnselectedHeaderTemplate; } if ((index >= 0) && (index < Headers.Count)) { ContentPresenter item0 = (ContentPresenter)Headers[index]; item0.ContentTemplate = Parent.SelectedHeaderTemplate; } If I do only the foreach code without the code in the "if", it works. And if I only do the code in the "if" without the foreach it works too. But togheter (the "if"-code and the foreach-code) it doesn't work. I have no idea why it doesn't work. The two templates look like this: <Setter Property="UnselectedHeaderTemplate"> <Setter.Value> <DataTemplate> <ContentControl Content="{Binding RelativeSource={RelativeSource TemplatedParent}, Path=Content}" Margin="10,-10" FontSize="72" Foreground="#FF999999" CacheMode="BitmapCache"/> </DataTemplate> </Setter.Value> </Setter> <!-- SelectedHeader template --> <Setter Property="SelectedHeaderTemplate"> <Setter.Value> <DataTemplate> <ContentControl Content="{Binding RelativeSource={RelativeSource TemplatedParent}, Path=Content}" Margin="10,-10" FontSize="72" Foreground="{TemplateBinding Foreground}" CacheMode="BitmapCache"/> </DataTemplate> </Setter.Value> </Setter> If you have an idea what problem is please tell me.

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  • OpenID Authentication using AuthLogic Error

    - by Steve
    Hi, I am trying to implement openid authentication using authlogic. I have installed the open_id_authentication in the process but when I entered rake open_id_authentication:db:create --trace I get the following error (in /Users/felix/login) rake aborted! Don't know how to build task 'open_id_authentication:db:create' /usr/local/lib/ruby/gems/1.9.1/gems/rake-0.8.7/lib/rake.rb:1728:in `[]' /usr/local/lib/ruby/gems/1.9.1/gems/rake-0.8.7/lib/rake.rb:2050:in `invoke_task' /usr/local/lib/ruby/gems/1.9.1/gems/rake-0.8.7/lib/rake.rb:2029:in `block (2 levels) in top_level' /usr/local/lib/ruby/gems/1.9.1/gems/rake-0.8.7/lib/rake.rb:2029:in `each' /usr/local/lib/ruby/gems/1.9.1/gems/rake-0.8.7/lib/rake.rb:2029:in `block in top_level' /usr/local/lib/ruby/gems/1.9.1/gems/rake-0.8.7/lib/rake.rb:2068:in `standard_exception_handling' /usr/local/lib/ruby/gems/1.9.1/gems/rake-0.8.7/lib/rake.rb:2023:in `top_level' /usr/local/lib/ruby/gems/1.9.1/gems/rake-0.8.7/lib/rake.rb:2001:in `block in run' /usr/local/lib/ruby/gems/1.9.1/gems/rake-0.8.7/lib/rake.rb:2068:in `standard_exception_handling' /usr/local/lib/ruby/gems/1.9.1/gems/rake-0.8.7/lib/rake.rb:1998:in `run' /usr/local/lib/ruby/gems/1.9.1/gems/rake-0.8.7/bin/rake:31:in `<top (required)>' /usr/local/bin/rake:19:in `load' /usr/local/bin/rake:19:in `<main>' Can someone tell what am i doing incorrectly Thanks

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  • Initializing PHP class property declarations with simple expressions yields syntax error

    - by user171929
    According to the PHP docs, one can initialize properties in classes with the following restriction: "This declaration may include an initialization, but this initialization must be a constant value--that is, it must be able to be evaluated at compile time and must not depend on run-time information in order to be evaluated." I'm trying to initialize an array and having some issues. While this works fine: public $var = array( 1 => 4, 2 => 5, ); This creates a syntax error: public $var = array( 1 => 4, 2 => (4+1), ); Even this isn't accepted: public $var = 4+1; which suggests it's not a limitation of the array() language construct. Now, the last time I checked, "4+1" equated to a constant value that not only should be accepted, but should in fact be optimized away. In any case, it's certainly able to be evaluated at compile-time. So what's going on here? Is the limitation really along the lines of "cannot be any calculated expression at all", versus any expression "able to be evaluated at compile time"? The use of "evaluated" in the doc's language suggests that simple calculations are permitted, but alas.... If this is a bug in PHP, does anyone have a bug ID? I tried to find one but didn't have any luck.

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  • Facing error in apple multitasking code

    - by user366584
    Actually I am working for multitasking and facing error please assist me, as I need to work on background application and also in foreground application - (void)applicationDidEnterBackground:(UIApplication *)application { UIApplication* app = [UIApplication sharedApplication]; // Request permission to run in the background. Provide an // expiration handler in case the task runs long. NSAssert(bgTask == UIBackgroundTaskInvalid, nil); bgTask = [app beginBackgroundTaskWithExpirationHandler:^{ // Synchronize the cleanup call on the main thread in case // the task actually finishes at around the same time. dispatch_async(dispatch_get_main_queue(), ^{ if (bgTask != UIBackgroundTaskInvalid) { [app endBackgroundTask:bgTask]; bgTask = UIBackgroundTaskInvalid; } }); }]; // Start the long-running task and return immediately. dispatch_async(dispatch_get_global_queue(DISPATCH_QUEUE_PRIORITY_DEFAULT, 0), ^{ // Do the work associated with the task. // Synchronize the cleanup call on the main thread in case // the expiration handler is fired at the same time. dispatch_async(dispatch_get_main_queue(), ^{ if (bgTask != UIBackgroundTaskInvalid) { [app endBackgroundTask:bgTask]; bgTask = UIBackgroundTaskInvalid; } }); }); }

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  • Check if file is locked or catch error for trying to open

    - by Duncan Matheson
    I'm trying to handle the problem where a user can try to open, with an OpenFileDialog, a file that is open by Excel. Using the simple FileInfo.OpenRead(), it chucks an IOException, "The process cannot access the file 'cakes.xls' because it is being used by another process." This would be fine to display to the user except that the user will actually get "Debugging resource strings are unavailable" nonsense. It seems not possible to open a file that is open by another process, since using FileInfo.Open(FileMode.Open, FileAccess.Read, FileShare.ReadWrite) chucks a SecurityException, "File operation not permitted. Access to path 'C:\whatever\cakes.xls' is denied.", for any file. Rather unhelpful. So it's down to either finding some way of checking if the file is locked, or trying to catch the IOException. I don't want to catch all IOExceptions and assume they're all locked file errors, so I need some sort of way of classifying this type of exception as this error... but the "Debugging resource strings" nonsense along with the fact that that message itself is probably localized makes it tricky. I'm partial trust, so I can't use Marshal.GetHRForException. So: Is there any sensible way of either check if a file is locked, or at least determining if this problem occurred without just catching all IOExceptions?

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  • PHP cURL error: "Empty reply from server"

    - by ABach
    All, I have a class function to interface with the RESTful API for Last.FM - its purpose is to grab the most recent tracks for my user. Here it is: private static $base_url = 'http://ws.audioscrobbler.com/2.0/'; public static function getTopTracks($options = array()) { $options = array_merge(array( 'user' => 'bachya', 'period' => NULL, 'api_key' => 'xxxxx...', // obfuscated, obviously ), $options); $options['method'] = 'user.getTopTracks'; // Initialize cURL request and set parameters $ch = curl_init(); curl_setopt_array($ch, array( CURLOPT_URL => self::$base_url, CURLOPT_POST => TRUE, CURLOPT_POSTFIELDS => $options, CURLOPT_RETURNTRANSFER => TRUE, CURLOPT_TIMEOUT => 30, CURLOPT_USERAGENT => 'Mozilla/4.0 (compatible; MSIE 5.01; Windows NT 5.0)' )); $results = curl_exec($ch); return $results; } This returns "Empty reply from server". I know that some have suggested that this error comes from some fault in network infrastructure; I do not believe this to be true in my case. If I run a cURL request through the command line, I get my data; the Last.FM service is up and accessible. Before I go to those folks and see if anything has changed, I wanted to check with you fine folks and see if there's some issue in my code that would be causing this. Thanks!

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  • 'send' button error 401

    - by jjd
    I'm having a strange error with 'Send' button I have the following code on my page <div id="fb-root"></div> <script type="text/javascript"> (function(d, s, id) { var js, fjs = d.getElementsByTagName(s)[0]; if (d.getElementById(id)) return; js = d.createElement(s); js.id = id; js.src = "//connect.facebook.net/en_US/all.js#xfbml=1&amp;appId=<myAppId>"; fjs.parentNode.insertBefore(js, fjs); }(document, 'script', 'facebook-jssdk')); </script> <br/> <fb:like send="true" width="450" show_faces="true"></fb:like> The 'send' button works fine if I access the application via IP address, but if I use a domain name, Facebook returns The page at http://<...>.com:8080/pages/question.jsf could not be reached because the server returned status code 401. Meantime 'like' button works fine. The application front-end is built with JSF2+Primefaces. Any ideas would be appreciated Thanks

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  • MVC View Model Intellesense / Compile error

    - by Marty Trenouth
    I have one Library with my ORM and am working with a MVC Application. I have a problem where the pages won't compile because the Views can't see the Model's properties (which are inherited from lower level base classes). They system throws a compile error saying that 'object' does not contain a definition for 'ID' and no extension method 'ID' accepting a first argument of type 'object' could be found (are you missing a using directive or an assembly reference?) implying that the View is not seeing the model. In the Controller I have full access to the Model and have check the Inherits from portion of the view to validate the correct type is being passed. Controller: return View(new TeraViral_Blog()); View: <%@ Page Title="" Language="C#" MasterPageFile="~/Views/Shared/Site.Master" Inherits="System.Web.Mvc.ViewPage<com.models.TeraViral_Blog>" %> <asp:Content ID="Content1" ContentPlaceHolderID="TitleContent" runat="server"> Index2 </asp:Content> <asp:Content ID="Content2" ContentPlaceHolderID="MainContent" runat="server"> <h2>Index2</h2> <fieldset> <legend>Fields</legend> <p> ID: <%= Html.Encode(Model.ID) %> </p> </fieldset> </asp:Content>

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  • javascript error handeling

    - by pankaj
    I have a javascript function for checking errors which i am callin on OnClicentClick event of a button. Once it catch a error i want to stop execution of click event . But in my case it always it always executes the onclick event. Following is my function: function DisplayError() { if (document.getElementById('<%=txtPassword.ClientID %>').value.length < 6 || document.getElementById('<%=txtPassword.ClientID %>').value.length > 12) { document.getElementById('<%=lblError.ClientID %>').innerText = "Password length must be between 6 to 12 characters"; return false; } var str = <%=PhoneNumber()%>; if(str.length <10) { alert('<%=phoneNum%>'.length); document.getElementById('<%=lblError.ClientID %>').innerText = "Phone Number not in correct format"; return false; } } button html code: <asp:Button runat="server" Text="Submit" ID="btnSubmit" ValidationGroup="submit" onclick="btnSubmit_Click" OnClientClick="DisplayError()"/> It should not execute the button click event once it satisfies any of the IF condition in javascript function.

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  • get Random in ArrayList has error of java.lang.IllegalArgumentException: n must be positive

    - by gabrielle fregil
    In my ArrayList, i have get a random Item from my ArrayList for the equip method. Whenever i use my tester, the terminal window prints java.lang.IllegalArgumentException: n must be positive when I try to call random for the size. I tried to change the value of totalElements to the integer size of the elements, then the error would be an OutOfBoundsExeption import java.util.*; import java.util.Scanner; import java.util.Random; public class GameMaster { private int turn, totalElements; private boolean winner; private Avatar x1; private Avatar x2; private ArrayList<Item> inventory; public GameMaster(Avatar a1, Avatar a2) { x2 = a1; x1 = a2; turn = 1; winner = false; inventory = new ArrayList<Item>(); totalElements = 0; } private void fillInventory() { inventory.add( new Item( "Zealot Blades", true, 8 ) ); inventory.add( new Item( "BFG", true, 13 ) ); inventory.add( new Item( "Synthetic Cloth", false, 7 ) ); // more items inventory.add( new Item( "Gauss Rifle", true, 9 ) ); inventory.add( new Item( "Flight Unit", false, 6 ) ); totalElements = inventory.size(); } public String equip() { Avatar w; String a; if (turn%2==1) w=x2; else w=x1; if (w.beltIsFull()) { a = w.getName() + "'s belt is full. \n"; } else { turn++; Random generator = new Random(); Item rand = inventory.get(generator.nextInt(totalElements)); //terminal window in blueJ: java.lang.IllegalArgumentException: n must be positive a = w.getName()+" is equiped with "+rand.getName()+"."; } return a; }

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  • svn+apache per directory access control: weird permissions issue (403 Forbidden error)

    - by gveda
    Hi, I had a perfectly working svn+apache install where I was using per directory access control to restrict access to various parts of the repository. In particular, no one had access to the top level in the repository [/]. People had access to folders like [/www] etc. I was specifying these permissions in a file (svn-access-file). I had to move to a new machine. So I installed subversion-1.6.3 and httpd-2.2.11 on it, and modified the conf file to mimic the conf file on the old machine (and I copied the svn-access-file and the svn-auth-file). Then I took an svn dump and did a load to put stuff back in the new repository. Now I can check stuff out, modify stuff, and commit. However, as soon as I try to do an 'svn up' on an already checked out copy of some sub-folder [/www/people], I get the following error: svn: Server sent unexpected return value (403 Forbidden) in response to OPTIONS request for 'https://[servername]/svn' It seems the problem is that it is trying to access the top level directory [/] even though really it should only be trying to access [/www]. If I temporarily give the user access to [/], it works. Can someone please tell me how to fix this? Everything worked on the old machine. Thanks! Gaurav

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  • Heroku app throws "Internal Server Error"

    - by picardo
    This app works just fine on my local computer. After pushing it to Heroku, static pages appear to be working but the blog section throws an Internal Server Error. I pulled the logs by running "heroku logs" and this is what I get: ==> production.log <== /usr/ruby1.8.7/lib/ruby/gems/1.8/gems/eventmachine-0.12.10/lib/eventmachine.rb:256:in `run' /home/slugs/215194_e5b887e_c999/mnt/.bundle/gems/gems/thin-1.2.7/lib/thin/backends/base.rb:57:in `start' /home/slugs/215194_e5b887e_c999/mnt/.bundle/gems/gems/thin-1.2.7/lib/thin/server.rb:156:in `start' /home/slugs/215194_e5b887e_c999/mnt/.bundle/gems/gems/thin-1.2.7/lib/thin/controllers/controller.rb:80:in `start' /home/slugs/215194_e5b887e_c999/mnt/.bundle/gems/gems/thin-1.2.7/lib/thin/runner.rb:177:in `send' /home/slugs/215194_e5b887e_c999/mnt/.bundle/gems/gems/thin-1.2.7/lib/thin/runner.rb:177:in `run_command' /home/slugs/215194_e5b887e_c999/mnt/.bundle/gems/gems/thin-1.2.7/lib/thin/runner.rb:143:in `run!' /home/slugs/215194_e5b887e_c999/mnt/.bundle/gems/gems/thin-1.2.7/bin/thin:6 Something wrong with the eventmachine gem, I suppose....but it works fine on my machine. So I'm not sure what's going on or how to debug it.

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  • HTTP Handler error when downloading files - SSL

    - by Chiefy
    Ok big problem as this is affecting two projects on our new server. We have a file that is downloaded by users, the files are downloaded using a HTTPHandler. Since moving the site to the server and setting SSL the downloads have stopped working and we get an error message "Unable to download DownloadDocument.ashx" from site". DownloadDocument.ashx is the handler page that is set in the web.config and the button that goes there is a hyperlink with the id of the document as a querystring. Ive read the article on http://support.microsoft.com/kb/316431 and read a few other requests on this site but nothing seems to be working. This problem only happens in IE and works fine when I run it on the server in http instead of https. public override void HandleRequest(HttpContext context) { Guid guid = new Guid(context.Request.QueryString["ID"]); DataTable dt = Documents.GetDocument(guid); if (dt != null) { context.Response.Cache.SetCacheability(HttpCacheability.Private); context.Response.AddHeader("content-disposition", string.Format("attachment; filename={0}", dt.Rows[0]["DocumentName"].ToString())); context.Response.AddHeader("Content-Transfer-Encoding", "binary"); context.Response.AddHeader("Content-Length", ((byte[])dt.Rows[0]["Document"]).Length.ToString()); context.Response.ContentType = string.Format("application/{0}", dt.Rows[0]["Extension"].ToString().Remove(0, 1)); context.Response.Buffer = true; context.Response.BinaryWrite((byte[])dt.Rows[0]["Document"]); context.Response.Flush(); context.Response.End(); } } The above is my current code for the request. Ive used the base handler on http://haacked.com/archive/2005/03/17/AnAbstractBoilerplateHttpHandler.aspx. Any ideas on what this might be and how we can fix it. Thanks in advance for all responses.

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  • MySQL PHP SELECT throwing up an error?

    - by user1909695
    I am trying to make a comment section on my hand made site, using PHP and MySQL. I have got the comments stored in my database, but when I try to SELECT them my site throws up this error, mysql_result() [function.mysql-result]: Unable to jump to row 0 on MySQL result index 9 in /home/a9210109/public_html/comments.php on line 16 My code so far is below <?php $comment = $_POST['comment']; $mysql_host = ""; $mysql_database = ""; $mysql_user = ""; $mysql_password = ""; mysql_connect($mysql_host,$mysql_user,$mysql_password); @mysql_select_db($mysql_database) or die( "Unable to select database"); $CreateTable = "CREATE TABLE comments (comment VARCHAR(255), time VARCHAR(255));"; mysql_query($CreateTable); $UseComment = "INSERT INTO comments VALUES ('$comment')"; mysql_query($UseComment); $SelectComments = "SELECT * FROM comments"; $comments = mysql_query($SelectComments); $num=mysql_numrows($comments); $variable=mysql_result($comments,$i,"comment"); mysql_close(); ?> <a href="#" onclick="toggle_visibility('hidden');">Show/Hide Comments</a> <?php $i=0; while ($i < $num) { $comment=mysql_result($comments,$i,"comment"); echo "<div id='hidden' style='display:none'><h3>$comment</h3></div>"; $i++; } ?>

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