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  • tapestry 4 session expired

    - by cometta
    is below caused by user session expired? if yes, how to exend session on tapestry 4 ? or any other way to solve this problem? Unable to process client request: Unable to forward to local resource '/app?service=page&page=Home&id=692': java.lang.NullPointerException: Property 'webRequest' of <OuterProxy for tapestry.globals.RequestGlobals(org.apache.tapestry.services.RequestGlobals)> is null. Apr 22, 2010 5:14:43 PM org.apache.catalina.core.ApplicationContext log SEVERE: app: ServletException javax.servlet.ServletException: java.lang.NullPointerException: Property 'webRequest' of <OuterProxy for tapestry.globals.RequestGlobals(org.apache.tapestry.services.RequestGlobals)> is null. at org.apache.tapestry.services.impl.WebRequestServicerPipelineBridge.service(WebRequestServicerPipelineBridge.java:65) at $ServletRequestServicer_128043b52ea.service($ServletRequestServicer_128043b52ea.java) at org.apache.tapestry.request.DecodedRequestInjector.service(DecodedRequestInjector.java:55) at $ServletRequestServicerFilter_128043b52e6.service($ServletRequestServicerFilter_128043b52e6.java) at $ServletRequestServicer_128043b52ec.service($ServletRequestServicer_128043b52ec.java) at org.apache.tapestry.multipart.MultipartDecoderFilter.service(MultipartDecoderFilter.java:52) at $ServletRequestServicerFilter_128043b52e4.service($ServletRequestServicerFilter_128043b52e4.java) at $ServletRequestServicer_128043b52ec.service($ServletRequestServicer_128043b52ec.java) at org.apache.tapestry.services.impl.SetupRequestEncoding.service(SetupRequestEncoding.java:53) at $ServletRequestServicerFilter_128043b52e8.service($ServletRequestServicerFilter_128043b52e8.java) at $ServletRequestServicer_128043b52ec.service($ServletRequestServicer_128043b52ec.java) at $ServletRequestServicer_128043b52de.service($ServletRequestServicer_128043b52de.java) at org.apache.tapestry.ApplicationServlet.doService(ApplicationServlet.java:126) at org.apache.tapestry.ApplicationServlet.doPost(ApplicationServlet.java:171) at javax.servlet.http.HttpServlet.service(HttpServlet.java:637) at javax.servlet.http.HttpServlet.service(HttpServlet.java:717) at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:290) at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:206) at org.springframework.security.util.FilterChainProxy$VirtualFilterChain.doFilter(FilterChainProxy.java:378) at org.springframework.security.intercept.web.FilterSecurityInterceptor.invoke(FilterSecurityInterceptor.java:109) at org.springframework.security.intercept.web.FilterSecurityInterceptor.doFilter(FilterSecurityInterceptor.java:83) at org.springframework.security.util.FilterChainProxy$VirtualFilterChain.doFilter(FilterChainProxy.java:390) at org.springframework.security.ui.SessionFixationProtectionFilter.doFilterHttp(SessionFixationProtectionFilter.java:67) at org.springframework.security.ui.SpringSecurityFilter.doFilter(SpringSecurityFilter.java:53) at org.springframework.security.util.FilterChainProxy$VirtualFilterChain.doFilter(FilterChainProxy.java:390) at org.springframework.security.ui.ntlm.NtlmProcessingFilter.doFilterHttp(NtlmProcessingFilter.java:358) at org.springframework.security.ui.SpringSecurityFilter.doFilter(SpringSecurityFilter.java:53) at org.springframework.security.util.FilterChainProxy$VirtualFilterChain.doFilter(FilterChainProxy.java:390) at org.springframework.security.ui.ExceptionTranslationFilter.doFilterHttp(ExceptionTranslationFilter.java:101) at org.springframework.security.ui.SpringSecurityFilter.doFilter(SpringSecurityFilter.java:53) at org.springframework.security.util.FilterChainProxy$VirtualFilterChain.doFilter(FilterChainProxy.java:390) at org.springframework.security.context.HttpSessionContextIntegrationFilter.doFilterHttp(HttpSessionContextIntegrationFilter.java:235) at org.springframework.security.ui.SpringSecurityFilter.doFilter(SpringSecurityFilter.java:53) at org.springframework.security.util.FilterChainProxy$VirtualFilterChain.doFilter(FilterChainProxy.java:390) at org.springframework.security.concurrent.ConcurrentSessionFilter.doFilterHttp(ConcurrentSessionFilter.java:99) at org.springframework.security.ui.SpringSecurityFilter.doFilter(SpringSecurityFilter.java:53) at org.springframework.security.util.FilterChainProxy$VirtualFilterChain.doFilter(FilterChainProxy.java:390) at org.springframework.security.util.FilterChainProxy.doFilter(FilterChainProxy.java:175) at org.springframework.web.filter.DelegatingFilterProxy.invokeDelegate(DelegatingFilterProxy.java:236) at org.springframework.web.filter.DelegatingFilterProxy.doFilter(DelegatingFilterProxy.java:167) at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:235) at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:206) at org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:233) at org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:191) at org.apache.catalina.core.StandardHostValve.invoke(StandardHostValve.java:128) at org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:102) at org.apache.catalina.core.StandardEngineValve.invoke(StandardEngineValve.java:109) at org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:286) at org.apache.coyote.http11.Http11Processor.process(Http11Processor.java:845) at org.apache.coyote.http11.Http11Protocol$Http11ConnectionHandler.process(Http11Protocol.java:583) at org.apache.tomcat.util.net.JIoEndpoint$Worker.run(JIoEndpoint.java:447) at java.lang.Thread.run(Thread.java:619)

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  • how to specify query string in url with apache bench

    - by kshama
    hi, My rails application is running on thin server which i want to benchmark using apachebench the command am using is ab -n 1 -c 1 http://localhost:3001/welcome/search?query="doctor"&rad=5 But thin server is not taking this url.Its giving !! Invalid Request Can any one help me how to give the url such that thin accepts the url with query string

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  • recv with MSG_NONBLOCK and MSG_WAITALL

    - by osgx
    Hello I want to use recv syscall with nonblocking flags MSG_NONBLOCK. But with this flag syscall can return before full request is satisfied. So, can I add MSG_WAITALL flag? Will it be nonblocking? or how should I rewrite blocking recv into the loop with nonblocking recv

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  • Webservice returns java.lang.reflect.InvocationTargetException

    - by Damian
    Hi, I am receiving the above message when making a request to a java webservice. We originally created a Java Console application and manually submitted an xml file. When running this as a Java Application the response is successfully created and displayed by using System.out.println. We are creating the web service by selecting the java file that contains the methods and choosing "create webservice" specifying the dynamic project that the webservice is to be created in and the methods to be exposed. What the application is doing is taking an xml file and unmarshalling this to an object using: public static Object unmarshalToObject(Class classToBeBound, String xmlRequest) { Object obj = new Object(); try { JAXBContext jc = JAXBContext.newInstance(classToBeBound); Unmarshaller um = jc.createUnmarshaller(); obj = um.unmarshal(new StringReader(xmlRequest)); } catch (Exception e) { e.printStackTrace() } return obj; } Some processing is carried out on the file and then an object is marshalled to xml as follows: public static String marshalToXML(Object data) { StringWriter sw = new StringWriter(); try { logger.info("Create new Marshall"); JAXBContext jc = JAXBContext.newInstance("ContextPathName"); logger.info("Marshalled to xmlObjects"); Marshaller marshaller = jc.createMarshaller(); marshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true); marshaller.setProperty(Marshaller.JAXB_FRAGMENT, true); marshaller.marshal(data, sw); } catch (Exception e) { logException(logger, e); } return sw.toString(); } The following is the line of code that seems to be causing an issue as the logger displays the message prior to this: JAXBContext jc = JAXBContext.newInstance("ContextPathName"); The webservice never gets to the next line - the following is the body of the SOAP message: <soapenv:Fault> <faultcode>soapenv:Server.userException</faultcode> <faultstring>java.lang.reflect.InvocationTargetException</faultstring> <detail> <ns1:hostname xmlns:ns1="http://xml.apache.org/axis/">servername</ns1:hostname> </detail> </soapenv:Fault> I have added Try/Catch around this section of code even as far as looking for JAXBExceptions but this does not seem to catch anything - nor does the general exception. This issue does not occur when running the console application. The build path for this includes the following contents of sun\jwsdp-2.0\jaxb\lib: jaxb-api.jar jsr173_1.0_api.jar jaxb-impl.jar I have added these to the lib folder in the WEB-INF file of the dynamic project. I am running the webservice in JBuilder 2008 R2 and using SOAPUI to submit the request - this points to the wsdl generated when creating the webservice. If anyone has any help or ideas on how to solve this could they please reply - thanks for taking the time to read this post!

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  • Points (PTS) in flash game

    - by Erik Persson
    Hi, A friend to me made a flash game for my website. The game makes a request to /game/p00ints.php with the points in $_POST['points']. But, a hacker can easy find out how to get more points I guess, so, how can my friend or I fix this security hole? Best regards, Erik Persson

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  • generateUrl problem

    - by Daniel Hertz
    I am trying to generate a url but I keep getting a strange warning even though it works. I am making an api xml page and I use the following call in the controller: public function executeList(sfWebRequest $request) { $this->users = array(); foreach($this->getRoute()->getObjects() as $user) { $this->users[$this->generateUrl('user_show', $user, true)] = $user->asArray($request->getHost()); } } The user_show route is as follows: # api urls user_show: url: /user/:nickname param: { module: user, action: show } And the xml outputs as follows: <br /> <b>Warning</b>: array_diff_key() [<a href='function.array-diff-key'>function.array-diff-key</a>]: Argument #1 is not an array in <b>/opt/local/lib/php/symfony/routing/sfRoute.class.php</b> on line <b>253</b><br /> <br /> <b>Warning</b>: array_diff_key() [<a href='function.array-diff-key'>function.array-diff-key</a>]: Argument #1 is not an array in <b>/opt/local/lib/php/symfony/routing/sfRoute.class.php</b> on line <b>253</b><br /> <br /> <b>Warning</b>: array_diff_key() [<a href='function.array-diff-key'>function.array-diff-key</a>]: Argument #1 is not an array in <b>/opt/local/lib/php/symfony/routing/sfRoute.class.php</b> on line <b>253</b><br /> <?xml version="1.0" encoding="utf-8"?> <users> <user url="http://krowdd.dev/frontend_dev.php/user/danny"> <name>Danny tz</name> <nickname>danny</nickname> <email>[email protected]</email> <image></image> </user> <user url="http://krowdd.dev/frontend_dev.php/user/adrian"> <name>Adrian Sooian</name> <nickname>adrian</nickname> </user> </users> So it outputs the correct xml but I do not know why it throws thows warning when calling the generateurl method. Thanks!

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  • Spring security - Reach users ID without passing it through every controller

    - by nilsi
    I have a design issue that I don't know how to solve. I'm using Spring 3.2.4 and Spring security 3.1.4. I have a Account table in my database that looks like this: create table Account (id identity, username varchar unique, password varchar not null, firstName varchar not null, lastName varchar not null, university varchar not null, primary key (id)); Until recently my username was just only a username but I changed it to be the email address instead since many users want to login with that instead. I have a header that I include on all my pages which got a link to the users profile like this: <a href="/project/users/<%= request.getUserPrincipal().getName()%>" class="navbar-link"><strong><%= request.getUserPrincipal().getName()%></strong></a> The problem is that <%= request.getUserPrincipal().getName()%> returns the email now, I don't want to link the user's with thier emails. Instead I want to use the id every user have to link to the profile. How do I reach the users id's from every page? I have been thinking of two solutions but I'm not sure: Change the principal to contain the id as well, don't know how to do this and having problem finding good information on the topic. Add a model attribute to all my controllers that contain the whole user but this would be really ugly, like this. Account account = entityManager.find(Account.class, email); model.addAttribute("account", account); There are more way's as well and I have no clue which one is to prefer. I hope it's clear enough and thank you for any help on this. ====== Edit according to answer ======= I edited Account to implement UserDetails, it now looks like this (will fix the auto generated stuff later): @Entity @Table(name="Account") public class Account implements UserDetails { @Id private int id; private String username; private String password; private String firstName; private String lastName; @ManyToOne private University university; public Account() { } public Account(String username, String password, String firstName, String lastName, University university) { this.username = username; this.password = password; this.firstName = firstName; this.lastName = lastName; this.university = university; } public String getUsername() { return username; } public String getPassword() { return password; } public String getFirstName() { return firstName; } public String getLastName() { return lastName; } public void setUsername(String username) { this.username = username; } public void setPassword(String password) { this.password = password; } public void setFirstName(String firstName) { this.firstName = firstName; } public void setLastName(String lastName) { this.lastName = lastName; } public University getUniversity() { return university; } public void setUniversity(University university) { this.university = university; } public int getId() { return id; } public void setId(int id) { this.id = id; } @Override public Collection<? extends GrantedAuthority> getAuthorities() { // TODO Auto-generated method stub return null; } @Override public boolean isAccountNonExpired() { // TODO Auto-generated method stub return false; } @Override public boolean isAccountNonLocked() { // TODO Auto-generated method stub return false; } @Override public boolean isCredentialsNonExpired() { // TODO Auto-generated method stub return false; } @Override public boolean isEnabled() { // TODO Auto-generated method stub return true; } } I also added <%@ taglib prefix="sec" uri="http://www.springframework.org/security/tags" %> To my jsp files and trying to reach the id by <sec:authentication property="principal.id" /> This gives me the following org.springframework.beans.NotReadablePropertyException: Invalid property 'principal.id' of bean class [org.springframework.security.authentication.UsernamePasswordAuthenticationToken]: Bean property 'principal.id' is not readable or has an invalid getter method: Does the return type of the getter match the parameter type of the setter? ====== Edit 2 according to answer ======= I based my application on spring social samples and I never had to change anything until now. This are the files I think are relevant, please tell me if theres something you need to see besides this. AccountRepository.java public interface AccountRepository { void createAccount(Account account) throws UsernameAlreadyInUseException; Account findAccountByUsername(String username); } JdbcAccountRepository.java @Repository public class JdbcAccountRepository implements AccountRepository { private final JdbcTemplate jdbcTemplate; private final PasswordEncoder passwordEncoder; @Inject public JdbcAccountRepository(JdbcTemplate jdbcTemplate, PasswordEncoder passwordEncoder) { this.jdbcTemplate = jdbcTemplate; this.passwordEncoder = passwordEncoder; } @Transactional public void createAccount(Account user) throws UsernameAlreadyInUseException { try { jdbcTemplate.update( "insert into Account (firstName, lastName, username, university, password) values (?, ?, ?, ?, ?)", user.getFirstName(), user.getLastName(), user.getUsername(), user.getUniversity(), passwordEncoder.encode(user.getPassword())); } catch (DuplicateKeyException e) { throw new UsernameAlreadyInUseException(user.getUsername()); } } public Account findAccountByUsername(String username) { return jdbcTemplate.queryForObject("select username, firstName, lastName, university from Account where username = ?", new RowMapper<Account>() { public Account mapRow(ResultSet rs, int rowNum) throws SQLException { return new Account(rs.getString("username"), null, rs.getString("firstName"), rs.getString("lastName"), new University("test")); } }, username); } } security.xml <?xml version="1.0" encoding="UTF-8"?> <beans:beans xmlns="http://www.springframework.org/schema/security" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:beans="http://www.springframework.org/schema/beans" xsi:schemaLocation="http://www.springframework.org/schema/security http://www.springframework.org/schema/security/spring-security-3.1.xsd http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.1.xsd"> <http pattern="/resources/**" security="none" /> <http pattern="/project/" security="none" /> <http use-expressions="true"> <!-- Authentication policy --> <form-login login-page="/signin" login-processing-url="/signin/authenticate" authentication-failure-url="/signin?error=bad_credentials" /> <logout logout-url="/signout" delete-cookies="JSESSIONID" /> <intercept-url pattern="/addcourse" access="isAuthenticated()" /> <intercept-url pattern="/courses/**/**/edit" access="isAuthenticated()" /> <intercept-url pattern="/users/**/edit" access="isAuthenticated()" /> </http> <authentication-manager alias="authenticationManager"> <authentication-provider> <password-encoder ref="passwordEncoder" /> <jdbc-user-service data-source-ref="dataSource" users-by-username-query="select username, password, true from Account where username = ?" authorities-by-username-query="select username, 'ROLE_USER' from Account where username = ?"/> </authentication-provider> <authentication-provider> <user-service> <user name="admin" password="admin" authorities="ROLE_USER, ROLE_ADMIN" /> </user-service> </authentication-provider> </authentication-manager> </beans:beans> And this is my try of implementing a UserDetailsService public class RepositoryUserDetailsService implements UserDetailsService { private final AccountRepository accountRepository; @Autowired public RepositoryUserDetailsService(AccountRepository repository) { this.accountRepository = repository; } @Override public UserDetails loadUserByUsername(String username) throws UsernameNotFoundException { Account user = accountRepository.findAccountByUsername(username); if (user == null) { throw new UsernameNotFoundException("No user found with username: " + username); } return user; } } Still gives me the same error, do I need to add the UserDetailsService somewhere? This is starting to be something else compared to my initial question, I should maybe start another question. Sorry for my lack of experience in this. I have to read up.

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  • How to POST data to ASP.NET HttpHandler?

    - by Ali Kazmi
    Hi, I am trying to send a large chunk of data over to a HTTP handler. I can't send it using GET because of the URL length limit so I decided to POST it instead. The problem is that I can't get at the values. context.Request.Form shows that it has 0 items. So is there a way that I can POST data to a HttpHandler?

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  • xmlhttprequest always return with status code 0 for firefox

    - by Neo
    hi, I am trying to make asynchronous calls using xmlhttprequest object so it completely works fine in internet explorer but for firefox it wont work a small code snippet of problem if (req.readyState == 4) { if (req.status == 200) //here firefox gives status code always 0 and for IE works fine { //read response } else { alert("There was a problem with the request."); } }

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  • Django url parameters

    - by Hulk
    How to pass two paramters in urls in django <script> url=/toolbox/display/" + id + "2"; window.location=url; </script> Also how is this handeled in urls.py (r'^display/(?P<rid>\d+)/(?P<param>\d+)/$', 'table_display'), In views, def table_display(request,rid,param): print param //This should print 2

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  • TwitPic Multiple image upload

    - by Tim Karen
    Has anybody experienced Timeout error with TwitPic API using ASIFormDataRequest when uploading multiple images? Status updates without images are fine. I was trying to upload the exact same 2 images. The first request went through fine, but the second one was timeout. It also happens when multiple images are uploaded, some went through, but some didn't. It's happening randomly and I have no idea how to debug it anymore.

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  • jQuery "Access Is Denied" Error

    - by Jimbo
    I have an $.ajax() request that queries currency exchange rate information from another web server, which is the reason (I believe) for which I am getting an "Access Is Denied" error on the $.ajax() call. Is there a way to permit this type of activity?

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  • Using Android SAXParser, one my my XML Elements is mysteriously breaking in half.

    - by Drennen
    And its not '&' Im using the SAXParser object do parse the actual XML. This is normally done by passing a URL to the XMLReader.Parse method. Because my XML is coming from a POST request to a webservice, I am saving that result as a String and then employing StringReader / InputSource to feed this string back to the XMLReader.Parse method. However, something strange is happening at the 2001st character of the XMLstring. The 'characters' method of the document handler is being called TWICE in between the startElement and endElement methods, effectively breaking my string (in this case a project title) into two pieces. Because I am instantiating objects in my characters method, I am getting two objects instead of one. This line, about 2000 chars into the string fires 'characters' two times, breaking between "Lower" and "Level" <title>SUMC-BOOKSTORE, LOWER LEVEL RENOVATIONS</title> When I bypass the StringReader / InputSource workaround and feed a flat XML file to XMLReader.Parse, it works absolutely fine. Something about StringReader and or InputSource is somehow screwing this up. Here is my method that takes and XML string and parses is through the SAXParser. public void parseXML(String XMLstring) { try { SAXParserFactory spf = SAXParserFactory.newInstance(); SAXParser sp = spf.newSAXParser(); XMLReader xr = sp.getXMLReader(); xr.setContentHandler(this); // Something is happening in the StringReader or InputSource // That cuts the XML element in half at the 2001 character mark. StringReader sr = new StringReader(XMLstring); InputSource is = new InputSource(sr); xr.parse(is); } catch (IOException e) { Log.e("CMS1", e.toString()); } catch (SAXException e) { Log.e("CMS2", e.toString()); } catch (ParserConfigurationException e) { Log.e("CMS3", e.toString()); } } I would greatly appreciate any ideas on how to not have 'characters' firing off twice when I get to this point in the XML String. Or, show me how to use a POST request and still pass off the URL to the Parse function. THANK YOU.

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  • UIWebView leak? Can someone confirm?

    - by Shaggy Frog
    I was leak-testing my current project and I'm stumped. I've been browsing like crazy and tried everything except chicken sacrifice. I just created a tiny toy project app from scratch and I can duplicate the leak in there. So either UIWebView has a leak or I'm doing something really silly. Essentially, it boils down to a loadRequest: call to a UIWebView object, given an URLRequest built from an NSURL which references a file URL, for a file in the app bundle, which lives inside a folder that Xcode is including by reference. Phew. The leak is intermittent but still happens ~75% of the time (in about 20 tests it happened about 15 times). It only happens on the device -- this does not leak in the simulator. I am testing targeting both iPhone OS 3.1.2 and 3.1.3, on an original (1st Gen) iPod Touch that is using iPhone OS 3.1.3. To reproduce, just create a project from scratch. Add a UIWebView to the RootViewController's .xib, hook it up via IBOutlet. In the Finder, create a folder named "html" inside your project's folder. Inside that folder, create a file named "dummy.html" that has the word "Test" in it. (Does not need to be valid HTML.) Then add the html folder to your project in Xcode by choosing "Create Folder References for any added folders" Add the following to viewDidLoad NSString* resourcePath = [[NSBundle mainBundle] resourcePath]; NSString* filePath = [[resourcePath stringByAppendingPathComponent:@"html"] stringByAppendingPathComponent:@"dummy.html"]; NSURL* url = [[NSURL alloc] initFileURLWithPath:filePath]; NSURLRequest* request = [NSURLRequest requestWithURL:url]; // <-- this creates the leak! [browserView loadRequest:request]; [url release]; I've tried everything from setting delegate for the UIWebView and implementing UIWebViewDelegate, to not setting a delegate in IB, to not setting a delegate in IB and explicitly setting the web view's delegate property to nil, to using alloc/init instead of getting autoreleased NSURLRequests (and/or NSURLs)... I tried the answer to a similar question (setting the shared URL cache to empty) and that did not help. Can anyone help?

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  • Having a POST'able API and Django's CSRF Middleware

    - by T. Stone
    I have a Django webapp that has both a front-end, web-accessible component and an API that is accessed by a desktop client. However, now with the new CSRF middleware component, API requests from the desktop client that are POST'ed get a 403. I understand why this is happening, but what is the proper way to fix this without compromising security? Is there someway I can signal in the HTTP header that it's an API request and that Django shouldn't be checking for CSRF or is that a bad strategy?

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  • BasicHTTPServer, SimpleHTTPServer and concurrency

    - by braindump
    I'm writing a small web server for testing purposes using python, BasicHTTPServer and SimpleHTTPServer. It looks like it's processing one request at a time. Is there any way to make it a little faster without messing around too deeply? Basicly my code looks as the following and I'd like to keep it this simple ;) os.chdir(webroot) httpd = BaseHTTPServer.HTTPServer(("", port), SimpleHTTPServer.SimpleHTTPRequestHandler) print("Serving directory %s on port %i" %(webroot, port) ) try: httpd.serve_forever() except KeyboardInterrupt: print("Server stopped.")

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  • ASP.NET MVC 1.0: OutputCache, RenderPartial and WriteSubstitution

    - by David
    Hi folks, after digging into this topic and having the requirement, that a single page should be totally cached, except for a Html.RenderPartial("LogOnUserControl"); i couldn't find any working solution on this... the only "it getting warmer" thing i foudn was this solution , which unfortunately is not working with a "partial view", which requires the Request.IsAuthenticated attribute ( the fakeContext is losing this info ) Have you heard of any other solution to do this?!

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  • Plupload works with Ruby on Rails?

    - by sebtm
    I tried following the example at: http://www.plupload.com/example_custom.php But in the request, file is not sent to the method of the controller, only the name. Maybe I need to set in the configuration of Plupload, something like 'multipart = true' Any idea?

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  • jQueryUI autocomplete - when no results are returned

    - by Brian M. Hunt
    I'm wondering how one can catch and add a custom handler when empty results are returned from the server when using jQueryUI autocomplete. There seem to be a few questions on this point related to the various jQuery plugins (e.g. jQuery autocomplete display “No data” error message when results empty), but I am wondering if there's a better/simpler way to achieve the same with the jQueryUI autocomplete. It seems to me this is a common use case, and I thought perhaps that jQueryUI had improved on the jQuery autocomplete by adding the ability to cleanly handle this situation. However I've not been able to find documentation of such functionality, and before I hack away at it I'd like to throw out some feelers in case others have seen this before. While probably not particularly influential, I can have the server return anything - e.g. HTTP 204: No Content to a 200/JSON empty list - whatever makes it easiest to catch the result in jQueryUI's autocomplete. My first thought is to pass a callback with two arguments, namely a request object and a response callback to handle the code, per the documentation: The third variation, the callback, provides the most flexibility, and can be used to connect any data source to Autocomplete. The callback gets two arguments: A request object, with a single property called "term", which refers to the value currently in the text input. For example, when the user entered "new yo" in a city field, the Autocomplete term will equal "new yo". A response callback, which expects a single argument to contain the data to suggest to the user. This data should be filtered based on the provided term, and can be in any of the formats described above for simple local data (String-Array or Object-Array with label/value/both properties). When the response callback receives no data, it inserts returns a special one-line object-array that has a label and an indicator that there's no data (so the select/focus recognize it as the indicator that no-data was returned). This seems overcomplicated. I'd prefer to be able to use a source: "http://...", and just have a callback somewhere indicating that no data was returned. Thank you for reading. Brian

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  • Is there a way to simulate a remote AMF call with WCAT?

    - by Lieven Cardoen
    I managed to use WCAT to test an url for an aspx page getting an asset. Now I would like to use it to test a remote call to WebORB from Flex. Problem is I don't know what to put in RequestData, RequestHeader, ... If I look with Charles (HTTP Monitor), then it's impossible to copy paste the request data (it has squares and all kind of weird characters that can't be copy paste to my txt file).

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  • django: CheckboxMultiSelect problem with db queries

    - by xiackok
    firstly sorry for my bad english there is a simple model Person. That contains just languages: LANGUAGE_LIS = ( (1, 'English'), (2, 'Turkish'), (3, 'Spanish') ) class Person(models.Model): languages = models.CharField(max_length=100, choices=LANGUAGE_LIST) #languages is multi value (CheckBoxSelectMultiple) and here person_save_form: class person_save_form(forms.ModelForm): languages = forms.CharField(widget=forms.CheckBoxSelectMultiple(choices=LANGUAGE_LIST)) class Meta: model = Person it is ok. but how can i search persons for languages like "get persons who knows turkish and english" in the database (MySQL) record "languages" column seen like "[u'1', u'2']". but i want search persons like this: persons = Person.objects.filter(languages__in=request.POST.getlist('languages'))

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