Search Results

Search found 18609 results on 745 pages for 'url shortening'.

Page 357/745 | < Previous Page | 353 354 355 356 357 358 359 360 361 362 363 364  | Next Page >

  • C Programing - Return libcurl http response to string to the calling function

    - by empty set
    I have a homework and i need somehow to compare two http responses. I am writing it on C (dumb decision) and i use libcurl to make things easier. I am calling the function that uses libcurl to http request and response from another function and i want to return the http response to it. Anyway, the code below doesn't work, any ideas? #include <stdio.h> #include <curl/curl.h> #include <string.h> size_t write_data(void *ptr, size_t size, size_t nmemb, void *stream) { size_t written; written = fwrite(ptr, size, nmemb, stream); return written; } char *handle_url(void) { CURL *curl; char *fp; CURLcode res; char *url = "http://www.yahoo.com"; curl = curl_easy_init(); if (curl) { curl_easy_setopt(curl, CURLOPT_URL, url); curl_easy_setopt(curl, CURLOPT_WRITEFUNCTION, write_data); curl_easy_setopt(curl, CURLOPT_WRITEDATA, fp); res = curl_easy_perform(curl); if(res != CURLE_OK) fprintf(stderr, "curl_easy_perform() failed: %s\n", curl_easy_strerror(res)); curl_easy_cleanup(curl); //printf("\n%s", fp); } return fp; } This solution C libcurl get output into a string works, but not in my case because i want to return this string to the calling function.

    Read the article

  • loading a href's content into a shadowbox using .load() HELP!!!

    - by kielie
    <script type="text/javascript"> $(function() { $('#wp-calendar a').click(function(event) { event.preventDefault(); var url = $(this).attr('href') + ' #content'; var loaded = Shadowbox.load(url); Shadowbox.open({ content: loaded, player: "html", title: "<?php the_title(); ?>", height: 300, width: 470, }); }); }); </script> That is the code I am using to try and display content in a shadowbox, I am using the default wordpress calendar and with jQuery/AJAX (if I am not mistaken) adding this click event to every link in the calendar, so that when a link is clicked, the content is loaded and displayed in a shadowbox instead of opening on a new page. When I click on one of the links all I get inside of the shadowbox is "undefined". As I am sure you can see in my code, I am still very new to this, so any help or pointers would be appreciated. Thanx in advance!

    Read the article

  • Using POST or SESSION to capture data

    - by Karinne
    Hi all! I'm currently working on web application using VB in ASP.NET. Right now I have 1 page with panels that we are using to show/hide depending on the flow. When the user first comes in, he/she is presented with a gridview containing a list of clients. Then the user, clicks a link from a row and is presented a form where he/she can update the clients' info. Originally, I had a HYPERLINKFIELD that put the clientId in the url, then I'd grab the url and do the code appropriately <asp:HyperLinkField Text='<%$ Resources:Resource, ManageClient %>' DataNavigateUrlFields="CLIENT_ID" DataNavigateUrlFormatString="~/clients/manage.aspx?clientId={0}" /> Now, I'm rethinking that and wondering if it's better to use SESSIONs to grab the clientID via this instead <asp:TemplateField Visible="false"><ItemTemplate><asp:Label runat="server" ID="hidClientId" Text='<%# Bind("CLIENT_ID")%>' Visible="false" /></ItemTemplate></asp:TemplateField> <asp:ButtonField Text='<%$ Resources:Resource, ManageClient %>' CommandName="Manage" /> Or use the POST method, which I'm not sure how it works in .NET (but I've used it in PHP) Any help would be greatly appreciated.

    Read the article

  • Ruby and RSS2 Feed not displaying image

    - by pcasa
    Trying to create a simple RSS2 Feed that I could later pass on to FeedBurner but can't get RSS feed to display images at all. Also, from what I have read having xml.instruct! on top might cause IE to complain it's not a valid feed. Is this true? My Code looks like xml.instruct! xml.rss "version" => "2.0", "xmlns:dc" => "http://purl.org/dc/elements/1.1/" do xml.channel do xml.title "Store" xml.link url_for :only_path => false, :controller => 'products' xml.description "Store" xml.pubDate @products.first.updated_at.rfc822 if @products.any? @products.each do |product| xml.item do xml.title product.name xml.pubDate (product.updated_at.rfc822) xml.image do xml.url domain_host + product.product_image.url(:small) xml.title "Store" xml.link url_for :only_path => false, :controller => 'products' end xml.link url_for :only_path => false, :controller => 'products', :action => 'show', :id => product.permalink xml.description product.fine_print xml.guid url_for :only_path => false, :controller => 'products', :action => 'show', :id => product.permalink end end end end

    Read the article

  • RetinaJS and LESS : Background image doesn't show on iOS

    - by jidma
    I am trying to make a background image into a retina image using LESS CSS and RetinaJs: in my index.html file : <html> <head> <meta http-equiv="content-type" content="text/html; charset=UTF-8"> <meta name="viewport" content="width=device-width, initial-scale=1.0, user-scalable=0, minimum-scale=1.0, maximum-scale=1.0"> <meta name="apple-mobile-web-app-capable" content="yes"> <meta name="apple-mobile-web-app-status-bar-style" content="black"> [...] <link type="text/css" rel="stylesheet/less" href="resources/css/retina.less"> <script type="text/javascript" src="resources/js/less-1.3.0.minjs" ></script> [...] </head> <body> [...] <script type="text/javascript" src="resources/js/retina.js"></script> </body> </html> in my retina.less file: .at2x(@path, @w: auto, @h: auto) { background-image: url("@{path}"); @at2x_path: ~`"@{path}".split('.').slice(0, "@{path}".split('.').length - 1).join(".") + "@2x" + "." + "@{path}".split('.')["@{path}".split('.').length - 1]`; @media all and (-webkit-min-device-pixel-ratio : 1.5) { background-image: url("@{at2x_path}"); background-size: @w @h; } } .topMenu { .at2x('../../resources/img/topMenuTitle.png'); } I have both topMenuTitle.png (320px x 40px) and [email protected] (640px x 80px) in the same folder. When test this code: In Firefox i have the normal Background In the XCode iPhone simulator I also have the normal Background In the iPhone device, I don't have any background at all. I'm using GWT if that matters. Any suggestions ? Thanks.

    Read the article

  • ASP.NET - Webservice not being called from javascript

    - by Robert
    Ok I'm stumped on this one. I've got a ASMX web service up and running. I can browse to it (~/Webservice.asmx) and see the .NET generated page and test it out.. and it works fine. I've got a page with a Script Manager with the webservice registered... and i can call it in javascript (Webservice.Method(...)) just fine. However, I want to use this Webservice as part of a jQuery Autocomplete box. So I have use the url...? and the Webservice is never being called. Here's the code. [WebService(Namespace = "http://tempuri.org/")] [WebServiceBinding(ConformsTo = WsiProfiles.BasicProfile1_1)] // To allow this Web Service to be called from script, using ASP.NET AJAX, uncomment the following line. [System.Web.Script.Services.ScriptService] public class User : System.Web.Services.WebService { public User () { //Uncomment the following line if using designed components //InitializeComponent(); } [WebMethod] public string Autocomplete(string q) { StringBuilder sb = new StringBuilder(); //doStuff return sb.ToString(); } web.config <system.web> <webServices> <protocols> <add name="HttpGet"/> <add name="HttpPost"/> </protocols> </webServices> And the HTML $(document).ready(function() { User.Autocomplete("rr", function(data) { alert(data); });//this works ("#<%=txtUserNbr.ClientID %>").autocomplete("/User.asmx/Autocomplete"); //doesn't work $.ajax({ url: "/User.asmx/Autocomplete", success: function() { alert(data); }, error: function(e) { alert(e); } }); //just to test... calls "error" function });

    Read the article

  • e4x filter on more than one children?

    - by Chris
    My XML Looks like this: <?xml version="1.0" encoding="utf-8" ?> <projects> <project id="1" thumb="media/images/thumb.jpg" > <categories> <id>1</id> <id>2</id> </categories> <director>Director name</director> <name><![CDATA[IPhone commercial]]></name> <url><![CDATA[http://www.iphone.com]]></url> <description><![CDATA[Description about the project]]></description> <thumb><![CDATA[/upload/images/thumb.jpg]]></thumb> </project> </projects> But I cannot figure out how to filter projects based on a category id? Does anybody know how to do ? :) Something like: projects.project.(categories.(id == 3)) Just returns all items :(

    Read the article

  • How to map (large) integer on (small in size( alphanumeric string with PHP? (Cantor?)

    - by Glooh
    Dear all, I can't figure out how to optimally do the following in PHP: In a database, I have messages with a unique ID, like 19041985. Now, I want to refer to these messages in a short-url service but not using generated hashes but by simply 'calculate' the original ID. In other words, for example: http://short.url/sYsn7 should let me calculate the message ID the visitor would like to request. To make it more obvious, I wrote the following in PHP to generate these 'alphanumeric ID versions' and of course, the other way around will let me calculate the original message ID. The question is: Is this the optimal way of doing this? I hardly think so, but can't think of anything else. $alphanumString = '0123456789abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ-_'; for($i=0;$i < strlen($alphanumString);$i++) { $alphanumArray[$i] = substr($alphanumString,$i,1); } $id = 19041985; $out = ''; for($i=0;$i < strlen($id);$i++) { if(isset($alphanumString["".substr($id,$i,2).""]) && strlen($alphanumString["".substr($id,$i,2).""]) 0) { $out.=$alphanumString["".substr($id,$i,2).""]; } else { $out.=$alphanumString["".substr($id,$i,1).""]; $out.=$alphanumString["".substr($id,($i+1),1).""]; } $i++; } print $out;

    Read the article

  • Generate and download a text file in javascript

    - by Mark B
    All my research so far suggests this can't be done, but I'm hoping someone here has some cunning ideas. I have a form on a website which allows users to bulk upload lots of URLs to add to a list on the server. There's quite a lot of server-side processing to do on each URL, so to avoid timeouts and to display progress, I've implemented the upload using jQuery to submit the URLs one at a time using ajax. This is all working nicely. However, part of the processing on each URL is deduplicating it against the complete list. The ajax call returns a status indicating either a successful upload or a rejection due to duplication. As the upload progresses, I tell the user how many URLs have been rejected as duplicates (along with overall progress and ETA). The problem now is how to give the user a complete list of the failed duplicate URLs. I've kept them in an array in my jQuery, and would like the user to be able to click on a link on the form to download a text file containing those URLs. Is this possible just using client-side processing? The server-side processing basically handles a single keyword at a time. I'd rather not have to store the duplicates in a database table with some kind of session key which gets sent with every ajax call, and is then used at the end to generate the text file server-side (and then gets cleaned up some time later). I can see how to do this, but it seems very clunky and a bit 20th century.

    Read the article

  • php curl login not work

    - by Massimo Zampieri
    Hi i have a problem with the curl. I watched an old post Remote Login not Working With Curl, but it not work. I followed baba's advice but the code enter in the if statement. Sorry for my bad english. Can anyone help me? This is the code: $url="http://hipfile.com/"; $urllog="http://hipfile.com/login.html"; $postdata = "login=bnnoor&password=########&op=login"; $ch = curl_init(); curl_setopt ($ch, CURLOPT_URL, $url); curl_setopt ($ch, CURLOPT_SSL_VERIFYPEER, FALSE); curl_setopt ($ch, CURLOPT_USERAGENT, "Mozilla/5.0 (Windows; U; Windows NT 5.1; en-US; rv:1.8.1.6) Gecko/20070725 Firefox/2.0.0.6"); curl_setopt ($ch, CURLOPT_TIMEOUT, 60); curl_setopt ($ch, CURLOPT_FOLLOWLOCATION, 1); curl_setopt ($ch, CURLOPT_RETURNTRANSFER, 1); curl_setopt ($ch, CURLOPT_REFERER, $urllog); curl_setopt ($ch, CURLOPT_POSTFIELDS, $postdata); curl_setopt ($ch, CURLOPT_POST, 1); $result = curl_exec ($ch); if (!$result) { $http_code = curl_getinfo($ch, CURLINFO_HTTP_CODE); curl_close($ch); // make sure we closeany current curl sessions die($http_code.' Unable to connect to server. Please come back later.'); } echo $result; curl_close($ch);

    Read the article

  • HTML href with css ie Problem

    - by Jordan Pagaduan
    <style type="text/css"> .web_westloh { background-image: url(images/web_westloh.png); background-repeat: no-repeat; height: 100px; width: 350px; } .web_westloh:hover { border-bottom-width: 2px; border-bottom-style: dashed; border-bottom-color: #999999; padding-bottom: 5px; } .web_money { background-image: url(images/web_money.png); background-repeat: no-repeat; height: 100px; width: 350px; } .web_money:hover { border-bottom-width: 2px; border-bottom-style: dashed; border-bottom-color: #999999; padding-bottom: 5px; } </style> <a href="http://www.westloh.com" title="Click to Visit http://www.westloh.com" target="_blank" class="web_westloh"> <div class="web_westloh"></div> </a> <a href="http://www.money-mind-set.com" title="Click to Visit http://www.money-mind-set.com" target="_blank"> <div class="web_money"></div> </a> The Problem is: In mozilla linking is ok. No problem. But in IE the link is a problem, it will not link in the target. See this page to see Problem: http://replytowest.com -- at the bottom. Thank You

    Read the article

  • Converting Python Script to Vb.NET - Involves Post and Input XML String

    - by Jason Shoulders
    I'm trying to convert a Python Script to Vb.Net. The Python Script appears to accept some XML input data and then takes it to a web URL and does a "POST". I tried some VB.NET code to do it, but I think my approach is off because I got an error back "BadXmlDataErr" plus I can't really format my input XML very well - I'm only doing string and value. The input XML is richer than that. Here is an example of what the XML input data looks like in the Python script: <obj is="MyOrg:realCommand_v1/" > <int name="priority" val="1" /> <real name="value" val="9.5" /> <str name="user" val="MyUserName" /> <reltime name="overrideTime" val="PT60S"/> </obj> Here's the Vb.net code I attempted to convert that: Dim reqparm As New Specialized.NameValueCollection reqparm.Add("priority", "1") reqparm.Add("value", "9.5") reqparm.Add("user", "MyUserName") reqparm.Add("overrideTime", "PT60S") Using client As New Net.WebClient Dim sTheUrl As String = "[My URL]" Dim responsebytes = client.UploadValues(sTheUrl, "POST", MyReqparm) Dim responsebody = (New System.Text.UTF8Encoding).GetString(responsebytes) End Using I feel like I should be doing something else. Can anyone point me to the right direction?

    Read the article

  • help needed on libcurl programming in sending HTTP HEAD Request.

    - by Mani
    Hi all, I need clarifications on using libcurl for the following: I need to send an http HEAD request shown as below :: HEAD /mshare/3/30002:12:primary/stream_xNKNVH.mpeg HTTP/1.1 Host: 192.168.70.1:8080 Accept: */* User-Agent: Kreatel_IP-STB getcontentFeatures.dlna.org: 1 The code I wrote (shown below) , sends the HEAD Request in slightly different way: curl_global_init(CURL_GLOBAL_ALL); CURL* ctx = NULL; const char *url = "http://192.168.70.1:8080/mshare/3/30002:12:primary/stream_xNKNVH.mpeg" ; char *returnString; struct curl_slist *headers = NULL; ctx = curl_easy_init(); headers = curl_slist_append(headers,"Accept: */*"); headers = curl_slist_append(headers,"User-Agent: Kreatel_IP-STB");\ headers = curl_slist_append(headers,"getcontentFeatures.dlna.org: 1"); headers = curl_slist_append(headers,"Pragma:"); headers = curl_slist_append(headers,"Proxy-Connection:"); curl_easy_setopt(ctx,CURLOPT_HTTPHEADER , headers ); curl_easy_setopt(ctx,CURLOPT_NOBODY ,1 ); curl_easy_setopt(ctx,CURLOPT_VERBOSE, 1); curl_easy_setopt(ctx,CURLOPT_URL,url ); curl_easy_setopt(ctx,CURLOPT_NOPROGRESS ,1 ); curl_easy_perform(ctx); curl_easy_cleanup(ctx); curl_global_cleanup(); The code shown above sends the HEAD Request in slightly different form (shown below) HEAD http://192.168.70.1:8080/mshare/3/30002:12:primary/stream_xNKNVH.mpeg HTTP/1.1 Host: 192.168.70.1:8080 Proxy-Connection: Keep-Alive Accept: */* User-Agent: Kreatel_IP-STB getcontentFeatures.dlna.org: 1 Can any one , share the appropriate code ?

    Read the article

  • ASP.NET MVC 2.0 + Implementation of a IRouteHandler goes not fire

    - by Peter
    Can anybody please help me with this as I have no idea why public IHttpHandler GetHttpHandler(RequestContext requestContext) is not executing. In my Global.asax.cs I have public class MvcApplication : System.Web.HttpApplication { public static void RegisterRoutes(RouteCollection routes) { routes.IgnoreRoute("{resource}.axd/{*pathInfo}"); routes.MapRoute( "Default", // Route name "{controller}/{action}/{id}", // URL with parameters new { controller = "Home", action = "Index", id = "" } // Parameter defaults ); routes.Add("ImageRoutes", new Route("Images/{filename}", new CustomRouteHandler())); } protected void Application_Start() { RegisterRoutes(RouteTable.Routes); } } //CustomRouteHandler implementation is below public class CustomRouteHandler : IRouteHandler { public IHttpHandler GetHttpHandler(RequestContext requestContext) { // IF I SET A BREAK POINT HERE IT DOES NOT HIT FOR SOME REASON. string filename = requestContext.RouteData.Values["filename"] as string; if (string.IsNullOrEmpty(filename)) { // return a 404 HttpHandler here } else { requestContext.HttpContext.Response.Clear(); requestContext.HttpContext.Response.ContentType = GetContentType(requestContext.HttpContext.Request.Url.ToString()); // find physical path to image here. string filepath = requestContext.HttpContext.Server.MapPath("~/logo.jpg"); requestContext.HttpContext.Response.WriteFile(filepath); requestContext.HttpContext.Response.End(); } return null; } } Can any body tell me what I'm missing here. Simply public IHttpHandler GetHttpHandler(RequestContext requestContext) does not fire. I havn't change anything in the web.config either. What I'm missing here? Please help.

    Read the article

  • Is there any other way of using signed applets

    - by 640KB
    Hi There, If I want to deploy high privileged applets they need to be signed. For that a certificate is created and then a jar file is signed with a jarsigner. After that in the HTML code one has to specify code,codebase AND archive (jar) which we signed before. However I wrote a servlet which acts as two things: it sits at the URL pointed by the codebase and serves class bytecode to the applet. The same servlet also uses serialization to communicate with the applet whereby whenever the applet gets a class it does not know it goes to the codebase which ends up back at the servlet. Almost like a mini RMI setup but simpler. I hope you can see the power in this. Unfortunately for signed applets one needs the archive. Now the servlet is also able to load a Certificate object and can send it to the applet too. So here is the setup: At one point the applet receives class bytecode and it also has the Certificate. It would be nice if the applet could instantiate all received classes using that certificate (otherwise code from jar is signed and outside is not which prompts nasty messages to the user). So my question to you fine Java aficionados: Would there by any way for me to use the bytecode data and the Certificate to instantiate the class as a signed object so that the plugin pops the Security dialog, accepts teh certificate and elevates the object's privileges. What I could find is that the there is a class CodeSource that accepts codebase URL and certificate and is essential to the signing process. What I am not sure is how one could intercept the class loading inside applets to install additional certificates not obtained through a JAR file via archive. What do you say? Thanks a bunch.

    Read the article

  • POSTmethod and PHP- login verification

    - by Neethusha
    I wrote a code for login verification..I got output with GET. But i need output with POST since it is more secure.pls let me know if there is any error in my code. javascript code: var xml; function verifyusernamepasswd(pass) { //pass is password that will be passed as parameter xml=new XMLHttpRequest(); var url="http://localhost/loginvalidate.php"; var para="q="+username+"&p="+pass;//username is global xml.setRequestHeader("Content-type", "application/x-www-form-urlencoded"); xml.setRequestHeader("Content-length", para.length); xml.setRequestHeader("Connection", "close"); xml.open("POST",url,true); xml.onreadystatechange=statechanged1; xml.send(para); } function statechanged1() { if(xml.readyState==4) alert(xml.responseText); } php code: <?php $username=$_POST["q"]; $password=$_POST["p"]; $con=mysql_connect("localhost","root","blaze"); if(!$con) { die('Could not connect: '.mysql.error()); } mysql_select_db("BLAZE",$con) or die("No such Db"); $result=mysql_query("SELECT Passwword FROM USERTABLE WHERE Userhandle='$username'"); if($result==null) echo "false"; else if($result!=null) { $row=mysql_fetch_array($result); if((strcmp($row['Passwword'],$password)==0)) echo "true"; else echo "false"; } ?> the verification does not return anything, cos my alert is not displayed at all...pls tell me whats wrong....

    Read the article

  • Paging not working in my wordpress installation

    - by Bootcamp
    I recently started a blog site and wanted to give it a magazine look. I used Wordpress for my blog and used the Arthemia theme with it. I also changed the permalink structure to point to /%year%/%monthnum%/%day%/%postname%/ structure. Now the problem that i have is that the paging has stopped working on my home page. When i click on the next page link i get a 404 error. My /page/2 url does not show the next page. I check on google and found out that it was due to the redirection that is being performed due to the permalink change. The solution given was that i need to skip the url rewriting for the /page/* urls. This is the link to an article which said this http://www.yoursearchadvisor.com/blog/wordpress-next_posts_link-broken/ . I was not able to follow this article and solve my problem, as i could not find the permanent redirect manager under the settings section as said in this article. Can somebody please guide me how to solve this problem. I am using the latest Wordpress version and Arthemia theme with it. Thanks.

    Read the article

  • Dynamic loading a class in java with a different package name

    - by C. Ross
    Is it possible to load a class in Java and 'fake' the package name/canonical name of a class? I tried doing this, the obvious way, but I get a "class name doesn't match" message in a ClassDefNotFoundException. The reason I'm doing this is I'm trying to load an API that was written in the default package so that I can use it directly without using reflection. The code will compile against the class in a folder structure representing the package and a package name import. ie: ./com/DefaultPackageClass.class // ... import com.DefaultPackageClass; import java.util.Vector; // ... My current code is as follows: public Class loadClass(String name) throws ClassNotFoundException { if(!CLASS_NAME.equals(name)) return super.loadClass(name); try { URL myUrl = new URL(fileUrl); URLConnection connection = myUrl.openConnection(); InputStream input = connection.getInputStream(); ByteArrayOutputStream buffer = new ByteArrayOutputStream(); int data = input.read(); while(data != -1){ buffer.write(data); data = input.read(); } input.close(); byte[] classData = buffer.toByteArray(); return defineClass(CLASS_NAME, classData, 0, classData.length); } catch (MalformedURLException e) { throw new UndeclaredThrowableException(e); } catch (IOException e) { throw new UndeclaredThrowableException(e); } }

    Read the article

  • Django: Serving a Download in a Generic View

    - by TheLizardKing
    So I want to serve a couple of mp3s from a folder in /home/username/music. I didn't think this would be such a big deal but I am a bit confused on how to do it using generic views and my own url. urls.py url(r'^song/(?P<song_id>\d+)/download/$', song_download, name='song_download'), The example I am following is found in the generic view section of the Django documentations: http://docs.djangoproject.com/en/dev/topics/generic-views/ (It's all the way at the bottom) I am not 100% sure on how to tailor this to my needs. Here is my views.py def song_download(request, song_id): song = Song.objects.get(id=song_id) response = object_detail( request, object_id = song_id, mimetype = "audio/mpeg", ) response['Content-Disposition'= "attachment; filename=%s - %s.mp3" % (song.artist, song.title) return response I am actually at a loss of how to convey that I want it to spit out my mp3 instead of what it does now which is to output a .mp3 with all of the current pages html contained. Should my template be my mp3? Do I need to setup apache to serve the files or is Django able to retrieve the mp3 from the filesystem(proper permissions of course) and serve that? If it do need to configure Apache how do I tell Django that? Thanks in advanced. These files are all on the HD so I don't need to "generate" anything on the spot and I'd like to prevent revealing the location of these files if at all possible. A simple /song/1234/download would be fantastic.

    Read the article

  • Add class active when clicking the menu link with Jquery

    - by Adrian
    I have HTML <div id="top" class="shadow"> <ul class="gprc"> <li><a href="http://www.domain.com/">Home</a></li> <li><a href="http://www.domain.com/link1/">Text1</a></li> <li><a href="http://www.domain.com/link2/">Text2</a></li> <li><a href="http://www.domain.com/link3/">Text3</a></li> <li><a href="http://www.domain.com/link4">Text4</a></li> </ul> </div> and JQUERY $(function () { var url = window.location.pathname, urlRegExp = new RegExp(url.replace(/\/$/, '') + "$"); $('#top a').each(function () { if (urlRegExp.test(this.href.replace(/\/$/, ''))) { $(this).addClass('active'); } }); }); The problem is that when i click on the Home link all tabs are getting active class and don't understand why. I need it for the first link to not get any active class.

    Read the article

  • How can I bind a simple Javascript array to an MVC3 controller action method?

    - by Sergio Tapia
    Here is the javascript code I use to create the array and send it on it's way: <script type="text/javascript" language="javascript"> $(document).ready(function () { $("#update-cart-btn").click(function() { var items = []; $(".item").each(function () { var productKey = $(this).find("input[name='item.ProductId']").val(); var productQuantity = $(this).find("input[type='text']").val(); items[productKey] = productQuantity; }); $.ajax({ type: "POST", url: "@Url.Action("UpdateCart", "Cart")", data: items, success: function () { alert("Successfully updated your cart!"); } }); }); }); </script> The items object is properly constructed with the values I need. What data type must my object be on the backend of my controller? I tried this but the variable remains null and is not bound. [Authorize] [HttpPost] public ActionResult UpdateCart(object[] items) // items remains null. { // Some magic here. return RedirectToAction("Index"); }

    Read the article

  • Django: Determining if a user has voted or not

    - by TheLizardKing
    I have a long list of links that I spit out using the below code, total votes, submitted by, the usual stuff but I am not 100% on how to determine if the currently logged in user has voted on a link or not. I know how to do this from within my view but do I need to alter my below view code or can I make use of the way templates work to determine it? I have read http://stackoverflow.com/questions/1528583/django-vote-up-down-method but I don't quite understand what's going on ( and don't need any ofjavascriptery). Models (snippet): class Link(models.Model): category = models.ForeignKey(Category, blank=False, default=1) user = models.ForeignKey(User) created = models.DateTimeField(auto_now_add=True) modified = models.DateTimeField(auto_now=True) url = models.URLField(max_length=1024, unique=True, verify_exists=True) name = models.CharField(max_length=512) def __unicode__(self): return u'%s (%s)' % (self.name, self.url) class Vote(models.Model): link = models.ForeignKey(Link) user = models.ForeignKey(User) created = models.DateTimeField(auto_now_add=True) def __unicode__(self): return u'%s vote for %s' % (self.user, self.link) Views (snippet): def hot(request): links = Link.objects.select_related().annotate(votes=Count('vote')).order_by('-created') for link in links: delta_in_hours = (int(datetime.now().strftime("%s")) - int(link.created.strftime("%s"))) / 3600 link.popularity = ((link.votes - 1) / (delta_in_hours + 2)**1.5) if request.user.is_authenticated(): try: link.voted = Vote.objects.get(link=link, user=request.user) except Vote.DoesNotExist: link.voted = None links = sorted(links, key=lambda x: x.popularity, reverse=True) links = paginate(request, links, 15) return direct_to_template( request, template = 'links/link_list.html', extra_context = { 'links': links, }) The above view actually accomplishes what I need but in what I believe to be a horribly inefficient way. This causes the dreaded n+1 queries, as it stands that's 33 queries for a page containing just 29 links while originally I got away with just 4 queries. I would really prefer to do this using Django's ORM or at least .extra(). Any advice?

    Read the article

  • tomcat resource missing, servlet not running

    - by user2837260
    import javax.servlet.*; import java.io.*; public class MyServlet implements Servlet { public void init(ServletConfig con) {} public void service(ServletRequest req, ServletResponse res) throws IOException,ServletException { res.setContentType("text/html"); PrintWriter out=res.getWriter(); String s="blah"; String s1="blah"; out.println("<html><body>"); if((s.equals(req.getParameter("firstname")))&&(s1.equals(req.getParameter("pwd")))) out.println("passwords match"); else out.println("password and name combo does not match"); out.println("</body></html>"); } public void destroy() {} public ServletConfig getServletConfig() { return null;} public String getServletInfo() { return null;} } this is my java file with the servlet class.its saved with the name MyServlet.java and so is the class file. and here is the xml file: <web-app> <servlet> <servlet-name>demoo</servlet-name> <servlet-class>MyServlet</servlet-class> </servlet> <servlet-mapping> <servlet-name>demoo</servlet-name> <url-pattern>/demo</url-pattern> </servlet-mapping> </web-app> i have made the folder as WEB-INF and then classes... WEB-INF also contains the .xml file but when i try to run the servlet , it says resource not found ps- i am already looking for the servlet with the name :demo localhost:8081/s1/demo* s1 is the war file * a html file in the war file seems to run fine on the server though. *

    Read the article

  • Load images into separate movie clips from a XML, Flash, Actionscript 3.0

    - by James Dunay
    I have an xml image bank, pretty standard, and I have a loader, along with movie clips that I want the images loaded into, the problem that I am running into is I want the images to load into separate movie clips, so I’m using a case statement to specify where they go. However, I can only get them to load into a single movie clip, I assume they are loading ontop of each other and I don’t know how to get them to separate out. I’ll post my code. It doesn’t make any sense to me but if you have any suggestions that would be real great. I can make separate loaders and then just do 1 image per loader, but that just doesn’t sound right to me. var counterNumber:Number = 0; function callThumbs():void{ for (var i:Number = 0; i <3; i++){ thumbLoaded(); counterNumber++; } } function thumbLoaded(){ var photoLoader = new Loader(); switch (counterNumber){ case 1: photoLoader.load(new URLRequest(MovieClip(this.parent).xml.photos.imageOne.image.@url[0])); whole.boxOne.pictureLoader.addChild(photoLoader); trace("1Done"); break; case 2: photoLoader.load(new URLRequest(MovieClip(this.parent).xml.photos.imageTwo.image.@url[0])); whole.boxTwo.pictureLoader.addChild(photoLoader); trace("2Done"); break; } }

    Read the article

  • Render only a portion of a PDF on iPhone/iPad

    - by Infinity
    Hello guys! I am rendering my pdf in an UIView's drawRect method. Here's my code: - (void)drawRect:(CGRect)rect2 { NSString *filename = @"lol.pdf"; CFStringRef path = CFStringCreateWithCString (NULL, [filename UTF8String], kCFStringEncodingUTF8); CFURLRef url = CFURLCreateWithFileSystemPath (NULL, path, kCFURLPOSIXPathStyle, 0); CGPDFDocumentRef pdf = CGPDFDocumentCreateWithURL(url); CGPDFPageRef page = CGPDFDocumentGetPage (pdf, 1); CGAffineTransform m; CGContextRef context = UIGraphicsGetCurrentContext(); CGRect aRect = CGRectMake(0, 0, 768, 1024); CGContextTranslateCTM(context, 0.0, aRect.size.height); CGContextScaleCTM(context, 1.0, -1.0); m = CGPDFPageGetDrawingTransform (page, kCGPDFMediaBox, aRect, 0, YES); CGContextSaveGState (context); CGContextConcatCTM (context, m); CGContextClipToRect (context,CGPDFPageGetBoxRect (page, kCGPDFCropBox)); CGContextDrawPDFPage (context, page); CGContextRestoreGState (context); } It renders the whole pdf. How can I render only a part from it? Can you help me with it?

    Read the article

< Previous Page | 353 354 355 356 357 358 359 360 361 362 363 364  | Next Page >