Search Results

Search found 27396 results on 1096 pages for 'mysql query'.

Page 359/1096 | < Previous Page | 355 356 357 358 359 360 361 362 363 364 365 366  | Next Page >

  • Is it necessary to write ROLLBACK if queries fail?

    - by Donator
    I write mysql_query("SET AUTOCOMMIT=0"); mysql_query("START TRANSACTION"); before I write all queries. Then check if all of them are true and then write: mysql_query("COMMIT"); But if one of query fails, I just pass COMMIT query. So do I really need ROLLBACK function if one of the queries fail? Because without ROLLBACK it also works. Thanks.

    Read the article

  • How do I workaround this error ? You can't specify target table my table for update in FROM clause

    - by Jules
    I'm struggling to convert my select query into a update query, it has aliases.. Update pads set RemoveMeDate = '1999-01-01 00:00:00' where padid in ( SELECT old_table.padid FROM `jules-fix-reasons`.`pads` AS old_table JOIN `jules`.`pads` AS new_table ON old_table.padid = new_table.`PadID` WHERE new_table.RemoveMeDate <> '2001-01-01 00:00:00' AND old_table.RemoveMeDate = '2001-01-01 00:00:00') I've tried removing the aliases, but that doesn't help :(

    Read the article

  • php functions within functions.

    - by Adamski
    Hi all, ihave created a simple project to help me get to grips with php and mysql, but have run into a minor issue, i have a working solution but would like to understand why i cannot run this code successfully this way, ill explain: i have a function, function fetch_all_movies(){ global $connection; $query = 'select distinct * FROM `'.TABLE_MOVIE.'` ORDER BY movieName ASC'; $stmt = mysqli_prepare($connection,$query); mysqli_execute($stmt); mysqli_stmt_bind_result($stmt,$id,$name,$genre,$date,$year); while(mysqli_stmt_fetch($stmt)){ $editUrl = "index.php?a=editMovie&movieId=".$id.""; $delUrl = "index.php?a=delMovie&movieId=".$id.""; echo "<tr><td>".$id."</td><td>".$name."</td><td>".$date."</td><td>".get_actors($id)."</td><td><a href=\"".$editUrl."\">Edit</a> | <a href=\"".$delUrl."\">Delete</a></td></tr>"; } } this fetches all the movies in my db, then i wish to get the count of actors for each film, so i pass in the get_actors($id) function which gets the movie id and then gives me the count of how many actors are realted to a film. here is the function for that: function get_actors($movieId){ global $connection; $query = 'SELECT DISTINCT COUNT(*) FROM `'.TABLE_ACTORS.'` WHERE movieId = "'.$movieId.'"'; $result = mysqli_query($connection,$query); $row = mysqli_fetch_array($result); return $row[0]; } the functions both work perfect when called separately, i just would like to understand when i pass the function inside a function i get this warning: Warning: mysqli_fetch_array() expects parameter 1 to be mysqli_result, boolean given in /Applications/MAMP/htdocs/movie_db/includes/functions.inc.php on line 287 could anyone help me understand why? many thanks.

    Read the article

  • get-wmiobject sql join in powershell - trying to find physical memory vs. virtual memory of remote s

    - by Willy
    get-wmiobject -query "Select TotalPhysicalMemory from Win32_LogicalMemoryConfiguration" -computer COMPUTERNAME output.csv get-wmiobject -query "Select TotalPageFileSpace from Win32_LogicalMemoryConfiguration" -computer COMPUTERNAME output.csv I am trying to complete this script with an output as such: Computer Physical Memory Virtual Memory server1 4096mb 8000mb server2 2048mb 4000mb

    Read the article

  • Update is not updating the whole string

    - by Malik
    Following is my SQL fiddle: http://sqlfiddle.com/#!2/f9bae/1 In which i am trying to check if the whole name is being verified by lookup table or not and if there is any error then it should get replaced by the correct value but the problem i am facing is that if any name contains more than one wrong values then query only update one part of that name and leave the rest unchanged , kindly let me know how can i modify my query for update so it'll update the whole name as per lookup table correct values. Thanks,

    Read the article

  • Getting all database entries into organized array

    - by Industrial
    Hi everyone, I have just made the update/add/delete part for the "Closure table" way of organizing query hierarchical data that are shown on page 70 in this slideshare: http://www.slideshare.net/billkarwin/sql-antipatterns-strike-back However, I have a bit of an issue getting the full tree back as an multidimensional array from a single query. Here's what I would like to get back: array ( 'topvalue' = array ( 'Subvalue', 'Subvalue2', 'Subvalue3' = array ('Subvalue 1', 'Subvalue 2', 'Subvalue 3' ) ); );

    Read the article

  • When running UPDATE ... datetime = NOW(); will all rows updated have the same date/time?

    - by Darryl Hein
    When you run something similar to: UPDATE table SET datetime = NOW(); on a table with 1 000 000 000 records and the query takes 10 seconds to run, will all the rows have the exact same time (minutes and seconds) or will they have different times? In other words, will the time be when the query started or when each row is updated? I'm running MySQL, but I'm thinking this applies to all dbs.

    Read the article

  • Session is working in Localhost Properly but not Online (Cpanel)

    - by nando pandi
    Hello guys Sorry for my stupid question regarding to my yesterday question its not solved yet even the advice you have given but still not working. i have removed all of spaces but still showing the problem for me. it's working perfect in localhost but not in CPANEL. Here is the errors which give: Warning: session_start() [function.session-start]: Cannot send session cookie - headers already sent by (output started at /home/scalepro/public_html/Admin Panel/Remote Employee/main.php:1) in /home/scalepro/public_html/Admin Panel/Remote Employee/main.php on line 1 Warning: session_start() [function.session-start]: Cannot send session cache limiter - headers already sent (output started at /home/scalepro/public_html/Admin Panel/Remote Employee/main.php:1) in /home/scalepro/public_html/Admin Panel/Remote Employee/main.php on line 1 Warning: Cannot modify header information - headers already sent by (output started at /home/scalepro/public_html/Admin Panel/Remote Employee/main.php:1) in /home/scalepro/public_html/Admin Panel/Remote Employee/main.php on line 13 Warning: Unknown: Your script possibly relies on a session side-effect which existed until PHP 4.2.3. Please be advised that the session extension does not consider global variables as a source of data, unless register_globals is enabled. You can disable this functionality and this warning by setting session.bug_compat_42 or session.bug_compat_warn to off, respectively in Unknown on line 0 ANY ONE PLEASE ??? Here is my code: <?php session_start(); require_once('../../Admin Panel/db.php'); if(isset($_POST['email']) && !empty($_POST['email']) && isset($_POST['password']) && !empty($_POST['password'])) { $email = $_POST['email']; $password = $_POST['password']; $query="SELECT RemoteEmployeeFullName, RemoteEmployeeEmail, RemoteEmployeePassword FROM remoteemployees WHERE RemoteEmployeeEmail='".$email."' AND RemoteEmployeePassword='".$password."'"; $queryrun=$connection->query($query); if($queryrun->num_rows > 0) { $_SESSION['email']=$RemoteEmployeeFullName; header("Location: /home/scalepro/public_html/Admin Panel/Remote Employee/REPLists.php"); } else { echo 'Email: <b>'.$email. '</b> or Password <b>'. $password.'</b> Is Not Typed Correctly Try Again Please!.'; header( "refresh:5;url= /home/scalepro/public_html/spd/myaccount.php" ); } } else { header( "refresh:5;url= /home/scalepro/public_html/spd/myaccount.php" ); } ?> if the condition gets true this will be redirected to a page by the name of REPLists.php here is the page. <?php session_start(); require_once('../../Admin Panel/db.php'); ?> <html> <head> <style> .wrapper { width:1250px; height:auto; border:solid 1px #000; margin:0 auto; padding:5px; border-radius:5px; -webkit-border-radius:5px; -moz-border-radius:5px; -ms-border-radius:5px; } .wrapper .header { width:1250px; height:20px; border-bottom:solid 1px #f0eeee; margin:auto 0; margin-bottom:12px; } .wrapper .header div { text-decoration:none; color:#F60; } .wrapper .header div a { text-decoration:none; color:#F60; } .wrapper .Labelcon { width:1250px; height:29px; border-bottom:solid 1px #ccc; } .wrapper .Labelcon .Label { width:125px; height:20px; float:left; text-align:center; border-left:1px solid #f0eeee; font:Verdana, Geneva, sans-serif; font-size:14.3px; font-weight:bold; } .wrapper .Valuecon { width:1250px; height:29px; border-bottom:solid 1px #ccc; color:#F60; text-decoration:none; } .wrapper .Valuecon .Value { width:125px; height:20px; float:left; text-align:center; border-left:1px solid #f0eeee; font-size:14px; } </style> </head> <body> <div class="wrapper"> <div class="header"> <div style="float:left;"><font color="#000000">Email: </font> <?php if(isset($_SESSION['email'])) { echo $_SESSION['email']; } ?> </div> <div style="float:right;"> <a href="#">My Profile</a> | <a href="logout.php">Logout</a></div> </div> <div class="Labelcon"> <div class="Label">Property ID</div> <div class="Label">Property Type</div> <div class="Label">Property Deal Type</div> <div class="Label">Property Owner</div> <div class="Label">Proposted Price</div> </div> <?php if(!isset($_SESSION['email'])) { header('Location:../../spd/myaccount.php'); } else { $query = "SELECT properties.PropertyID, properties.PropertyType, properties.PropertyDealType, properties.Status, properties.PropostedPrice, remoteemployees.RemoteEmployeeFullName, propertyowners.PropertyOwnerName, propertydealers.PropertyDealerName FROM remoteemployees, propertyowners, propertydealers, properties WHERE properties.PropertyOwnerID=propertyowners.PropertyOwnerID AND properties.PropertyDealerID=propertydealers.PropertyDealerID AND remoteemployees.RemoteEmployeeID=properties.RemoteEmployeeID ORDER BY properties.PropertyID "; $query_run = $connection->query($query); if( $connection->error ) exit( $connection->error ); while($row=$query_run->fetch_assoc()) { ?> <div class="Valuecon"> <div class="Value"><?php echo $row['PropertyID'] ?></div> <div class="Value"><?php echo $row['PropertyType'] ?></div> <div class="Value"><?php echo $row['PropertyDealType']?></div> <div class="Value"><?php echo $row['PropertyOwnerName'] ?></div> <div class="Value"><?php echo $row['PropostedPrice'];?></div> </div> <?php } }?> </div> </body> </html>

    Read the article

  • Php random row help...

    - by Skillman
    I've created some code that will return a random row, (well, all the rows in a random order) But i'm assuming its VERY uneffiecent and is gonna be a problem in a big database... Anyone know of a better way? Here is my current code: $count3 = 1; $count4 = 1; //Civilian stuff... $query = ("SELECT * FROM `*Table Name*` ORDER BY `Id` ASC"); $result = mysql_query($query); while($row = mysql_fetch_array($result)) { $count = $count + 1; $civilianid = $row['Id']; $arrayofids[$count] = $civilianid; //echo $arrayofids[$count]; } while($alldone != true) { $randomnum = (rand()%$count) + 1; //echo $randomnum . "<br>"; //echo $arrayofids[$randomnum] . "<br>"; $currentuserid = $arrayofids[$randomnum]; $count3 += 1; while($count4 < $count3) { $count4 += 1; $currentarrayid = $listdone[$count4]; //echo "<b>" . $currentarrayid . ":" . $currentuserid . "</b> "; if ($currentarrayid == $currentuserid){ $found = true; //echo " '" .$found. "' "; } } if ($found == true) { //Reset array/variables... $count4 = 1; $found = false; } else { $listdone[$count3] = $currentuserid; //echo "<u>" . $count3 .";". $listdone[$count3] . "</u> "; $query = ("SELECT * FROM `*Tablesname*` WHERE Id = '$currentuserid'"); $result = mysql_query($query); $row = mysql_fetch_array($result); $username = $row['Username']; echo $username . "<br>"; $count4 = 1; $amountdone += 1; if ($amountdone == $count) { //$count $alldone = true; } } } Basically it will loop until its gets an id (randomly) that hasnt been chosen yet. -So the last username could take hours :P Is this 'bad' code? :P :(

    Read the article

  • SQL Select -> product -> comments -> user

    - by user1492716
    thanks for yout time helping on this ;) I'm new to SQL and wish to solve somethign in just one query and i dont know how to do it.- Basically I've a table of products, a table of users and a table of comments, linked by products.id - comments.pid and user.id - comments.uid , i wish to know what is the best practice to create just 1 query and get all products with child comments, including username.

    Read the article

  • Delete duplicate rows, do not preserve one row

    - by Radley
    I need a query that goes through each entry in a database, checks if a single value is duplicated elsewhere in the database, and if it is - deletes both entries (or all, if more than two). Problem is the entries are URLs, up to 255 characters, with no way of identifying the row. Some existing answers on Stackoverflow do not work for me due to performance limitations, or they use uniqueid which obviously won't work when dealing with a string. Long Version: I have two databases containing URLs (and only URLs). One database has around 3,000 urls and the other around 1,000. However, a large majority of the 1,000 urls were taken from the 3,000 url database. I need to merge the 1,000 into the 3,000 as new entries only. For this, I made a third database with combined URLs from both tables, about 4,000 entries. I need to find all duplicate entries in this database and delete them (Both of them, without leaving either). I have followed the query of a few examples on this site, but whenever I try to delete both entries it ends up deleting all the entries, or giving sql errors. Alternatively: I have two databases, each containing the separate database. I need to check each row from one database against the other to find any that aren't duplicates, and then add those to a third database. Edit: I've got my own PHP solution which is pretty hacky, but works. I cannot answer my own question for 8 hours because I'm new, so here it is for now: I went with a PHP script to accomplish this, as I'm more familiar with PHP than MySQL. This generates a simple list of urls that only exist in the target database, but not both. If you have more than 7,000 entries to parse this may take awhile, and you will need to copy/paste the results into a text file or expand the script to store them back into a database. I'm just doing it manually to save time. Note: Uses MeekroDB <pre> <?php require('meekrodb.2.1.class.php'); DB::$user = 'root'; DB::$password = ''; DB::$dbName = 'testdb'; $all = DB::query('SELECT * FROM old_urls LIMIT 7000'); foreach($all as $row) { $test = DB::query('SELECT url FROM new_urls WHERE url=%s', $row['url']); if (!is_array($test)) { echo $row['url'] . "\n"; }else{ if (count($test) == 0) { echo $row['url'] . "\n"; } } } ?> </pre>

    Read the article

  • least value in count

    - by Nyfer
    i have a table employee(id,dept_id,salary,hire_date,job_id) . the following query i have to execute. Show all the employee who were hired on the day of the week on which least no of employee were hired. i have done the query, but am not able to get the least. please check if am correct. select id, WEEKDAY(hire_date)+1 as days,count(WEEKDAY(hire_date)+1) as count from test.employee group by days

    Read the article

  • NUL symbol gets inserted anywhere in the XML

    - by Racs
    I am using Oracle 11g and when I query data from database manually, it looks ok. But when I view it using Notepad++, there is a special character that gets inserted anywhere in the xml produced. Please see image below: I tried everything and deleted some parts of the xml, updated the db and query again but the invalid character just differ in location. Any idea is much appreciated, thanks! Best regards, Racs

    Read the article

  • Does it make sense to replace sub-queries by join?

    - by Roman
    For example I have a query like that. select col1 from t1 where col2>0 and col1 in (select col1 from t2 where col2>0) As far as I understand, I can replace it by the following query: select t1.col1 from t1 join (select col1 from t2 where col2>0) as t2 on t1.col1=t2.col1 where t1.col2>0 ADDED In some answers I see join in other inner join. Are both right? Or they are even identical?

    Read the article

  • datesub question

    - by Ahmet vardar
    Hi, is it possible to use date_sub like this ? $dt = date("Y-m-d h:i:s"); $query = "INSERT INTO `table` (`date`) VALUES ('DATE_SUB('$dt', INTERVAL 15 DAY)')"; $result = MYSQL_QUERY($query); Thanks

    Read the article

  • Doing sum's if certain conditions are true

    - by Gugu
    I am trying to build a query that does a sum if a certain parameter is set. For example: SELECT SUM(IF(<condition>,field,field)) AS total_value ...which is working correctly. But i have more than one condition in IF(), like: SELECT SUM(IF(<condition> <condition>,field,field)) AS total_value ..which is not working, could you have any idea what should be the right query for this.

    Read the article

  • Sorting by value with ORDER BY?

    - by Kevin
    For clarification, are you able to use MySQL this way to sort? ORDER BY CompanyID = XXX DESC What I am trying to do is use one sql query to sort everything where X = Y, in this case, where CompanyID = XXX. All values where CompanyID is not XXX should come after all the results where CompanyID = XXX. I don't want to limit my query but I do want to sort a particular company above other listings.

    Read the article

  • phpMyAdmin: The additional features for working with linked tables have been deactivated.

    - by The Disintegrator
    I'm getting this error in the main page of phpMyAdmin verson: 3.2.1deb1 The additional features for working with linked tables have been deactivated. To find out why click here. When I click the link I get this report. $cfg['Servers'][$i]['pmadb'] ... OK $cfg['Servers'][$i]['relation'] ... not OK [ Documentation ] General relation features: Disabled $cfg['Servers'][$i]['table_info'] ... not OK [ Documentation ] Display Features: Disabled $cfg['Servers'][$i]['table_coords'] ... not OK [ Documentation ] $cfg['Servers'][$i]['pdf_pages'] ... not OK [ Documentation ] Creation of PDFs: Disabled $cfg['Servers'][$i]['column_info'] ... not OK [ Documentation ] Displaying Column Comments: Disabled Bookmarked SQL query: Disabled Browser transformation: Disabled $cfg['Servers'][$i]['history'] ... not OK [ Documentation ] SQL history: Disabled $cfg['Servers'][$i]['designer_coords'] ... not OK [ Documentation ] Designer: Disabled I already used the script to create the tables. I assigned the permissions to the pma user. And everything is set in /etc/phpmyadmin/conf.inc.php But it's still not working... The tables are empty. I assume that they should have something. I'm interested in the relations an history features. Obviously I have read the documentation. Maybe something else is unsetting those values? Any toughs?

    Read the article

  • Better way to design a database

    - by cMinor
    I have a conceptual problem and I would like to get your ideas on how I'll be able to do what I am aiming. My goal is to create a database with information of persons who work at a place depending on their profession and skills,and keep control of salary and projects (how much would cost summing all the hours of work) I have 3 categories which can have subcategories: Outsourcing Technician welder turner assistant Administrative supervisor manager So each person has its information and the projects they are working on, also one person may do several jobs... I was thinking about having 5 tables (EMPLOYEE, SKILLS, PROYECTS, SALARY, PROFESSION) but I guess there is a better way of doing this. create table Employee ( PRIMARY KEY [Person_ID] int(10), [Name] varchar(30), [sex] varchar(10), [address] varchar(10), [profession] varchar(10), [Skills_ID] int(10), [Proyect_ID] int(10), [Salary_ID] int(10), [Salary] float ) create table Skills ( PRIMARY KEY [Skills_ID] int(10), FOREIGN KEY [Skills_name] varchar(10) REFERENCES Employee(Person_ID), [Skills_pay] float(10), [Comments] varchar(50) ) create table Proyects ( PRIMARY KEY [Proyect_ID] int(10), FOREIGN KEY [Skills_name] varchar(10) REFERENCES Employee(Person_ID) [Proyect_name] varchar(10), [working_Hours] float(10), [Comments] varchar(50) ) create table Salary ( PRIMARY KEY [Salary_ID] int(10), FOREIGN KEY [Skills_name] varchar(10) REFERENCES Employee(Person_ID) [Proyect_name] varchar(10), [working_Hours] float(10), [Comments] varchar(50) ) So to get the total amount of the cost of a project I would just sum the working hours of each employee envolved and sum some extra costs in an aggregate query. Is there a way to do this in a more efficient way? What to add or delete of this small model? I guess I am missing something in the salary - maybe I need another table for that?

    Read the article

< Previous Page | 355 356 357 358 359 360 361 362 363 364 365 366  | Next Page >