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  • How do I animate a UIButton in a UITableView?

    - by Ryan Lopez
    I currently have a UITableView with each cell containing four UIButtons. I am placing an image for each button with a downloaded picture from online. I'd like to have the button fade in when the image is finished downloading. I know I can animate in the viewDidLoad, but I assign the image in the cellForRowAtIndex function. How do I go about animating just the UIButton at a later point in time when I update the UIButton with the image?

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  • How to stop Native video player in Blackberry?

    - by Rajapandian
    Hi, I created one blackberry application which will play a video on a button click.This is my code, invocation=new Invocation("file:///SDCard/Blackberry/videos/PlayingVideo/funny.mp4"); registry=Registry.getRegistry("net.rim.device.api.content.BlackBerryContentHandler"); try { registry.invoke(invocation); } catch(Exception e) { } Now i can play the Video file.After clicking the Back button the native player is going to the background.It always running in the background.But i want to close that player.I have no idea about how to do it.Anybody knows please help me.

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  • Problem in understanding connectSlotsByName() in pyqt???

    - by Jebagnanadas
    Hi all, I couldn't understand the connectSlotsByName() method which is predominently used by pyuic4.. As far the class is single in a PyQt file it's ok since we can use self which will be associated with a single object throughout.. But when we try to use various classes from different files the problem and the need to use connectSlotsByName() arises.. Here's what i encountered which is weird.. I created a stacked widget.. I placed my first widget on it.. It has a button called "Next ". On clicking next it hides the current widget and adds another widget which has the "click me" button.. The problem here is the click event for "click me" button in second is not captured.. It's a minimal example that i can give for my original problem.. Please help me.. This is file No.1..(which has the parent stacked widget and it's first page). On clicking next it adds the second page which has "clickme" button in file2.. from PyQt4 import QtCore, QtGui import file2 class Ui_StackedWidget(QtGui.QStackedWidget): def __init__(self,parent=None): QtGui.QStackedWidget.__init__(self,parent) self.setObjectName("self") self.resize(484, 370) self.setWindowTitle(QtGui.QApplication.translate("self", "stacked widget", None, QtGui.QApplication.UnicodeUTF8)) self.createWidget1() def createWidget1(self): self.page=QtGui.QWidget() self.page.setObjectName("widget1") self.pushButton=QtGui.QPushButton(self.page) self.pushButton.setGeometry(QtCore.QRect(150, 230, 91, 31)) self.pushButton.setText(QtGui.QApplication.translate("self", "Next >", None, QtGui.QApplication.UnicodeUTF8)) self.addWidget(self.page) QtCore.QMetaObject.connectSlotsByName(self.page) QtCore.QObject.connect(self.pushButton,QtCore.SIGNAL('clicked()'),self.showWidget2) def showWidget2(self): self.page.hide() obj=file2.widget2() obj.createWidget2(self) if __name__ == "__main__": import sys app = QtGui.QApplication(sys.argv) ui = Ui_StackedWidget() ui.show() sys.exit(app.exec_()) Here's file2 from PyQt4 import QtGui,QtCore class widget2(): def createWidget2(self,parent): self.page = QtGui.QWidget() self.page.setObjectName("page") self.parent=parent self.groupBox = QtGui.QGroupBox(self.page) self.groupBox.setGeometry(QtCore.QRect(30, 20, 421, 311)) self.groupBox.setObjectName("groupBox") self.groupBox.setTitle(QtGui.QApplication.translate("self", "TestGroupBox", None, QtGui.QApplication.UnicodeUTF8)) self.pushButton = QtGui.QPushButton(self.groupBox) self.pushButton.setGeometry(QtCore.QRect(150, 120, 92, 28)) self.pushButton.setObjectName("pushButton") self.pushButton.setText(QtGui.QApplication.translate("self", "Click Me", None, QtGui.QApplication.UnicodeUTF8)) self.parent.addWidget(self.page) self.parent.setCurrentWidget(self.page) QtCore.QMetaObject.connectSlotsByName(self.page) QtCore.QObject.connect(self.pushButton,QtCore.SIGNAL('clicked()'),self.printMessage) def printMessage(self): print("Hai") Though in both the widgets(i mean pages) QtCore.QMetaObject.connectSlotsByName(self.page) the clicked signal in second dialog isn't getting processed. Thanks in advance.. Might be a beginner question..

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  • Keep Jquery dialog State after poseback

    - by shaahin
    Hi i have a dialog that made by jquery in this dialog i have asp button that save information in database but when i pust the button the page will be poseback and dialog will be close but i want to keep dialog state how can i do that cheers shaahin please give me an example

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  • How to pass an object from a Frame to another Frame in a Windows 8 Style App

    - by Mythul
    I have problem that i just cant figure out right now. I am trying to develop a Windows-8 style app and im stuck implementing this functionality. I have a MainWindow which contains a ListBox and a Button (lets say addButton). When i click the button i navigate to a new page, lets say AddCustomerPage with this.Frame.Navigate(typeof (AddCustomerPage)); AddCustomerPage has 1 textBox and 1 button (lets say doneButton. When i click the button i want the string in the textBox to be added to the ListBox on the previous page. This is my current functionality: 1. MainWindow is created. Click addButton AddCustomer page is created. MainWindow is destroyed(problem). Click doneButton A MainWindow object is created with a ListBox with 1 item. Repeat the add process, i always get a MainWindow with a ListBox with 1 item. Thanks for the help. Here is the code: public sealed partial class MainPage : Page { public MainPage() { this.InitializeComponent(); this.brainPageController = new PageController(); // add items from the List<String> to the listBox listGoals.ItemsSource = brainPageController.GetListGoals(); } protected override void OnNavigatedTo(NavigationEventArgs e) { var parameter = e.Parameter as String; // a simple controller that adds a string to a List<string> brainPageController.AddGoal(parameter); } private void addButton_Click(object sender, RoutedEventArgs e) { this.Frame.Navigate(typeof (GoalsInfo)); } // VARIABLES DECLARATION private PageController brainPageController; } public sealed partial class GoalsInfo : WinGoalsWIP.Common.LayoutAwarePage { public GoalsInfo() { this.InitializeComponent(); this.brainPageController = new PageController(); } protected override void LoadState(Object navigationParameter, Dictionary<String, Object> pageState) { } protected override void SaveState(Dictionary<String, Object> pageState) { } private void Button_Click_1(object sender, RoutedEventArgs e) { brainPageController.AddGoal(nameTextBox.Text); this.Frame.Navigate(typeof(MainPage), nameTextBox.Text); } // VARIABLES DECLARATION PageController brainPageController; }

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  • URL in iPhone SMS content.

    - by user265201
    Hello, I'm developing an iPhone application where SMS native application should open when the user clicks the button. This is working fine and I am also able to copy the content to clipboard when the user clicks on the button. But I want to provide a URL in the SMS content which I am copying so that the user click on the URL to open it in the browser. Can anyone suggest me how to provide clickable URL in SMS content?

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  • problem in presentmodelviewcontroller?

    - by Bala
    i am using tabbarcontroller. In tabbar having one view.In that tab i call one function using Nstimer it open another viewcontroller. First * sVC = [[First alloc] initWithNibName:@"First" bundle:[NSBundle mainBundle]]; [self presentModalViewController:sVC animated:YES]; Opened viewcontrller having one button.when user click that button i want to close the view and call Nstimer. [self dismissModalViewControllerAnimated:NO] The problem is first the view opened and closed but second time view could not open.

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  • write jquery plugin

    - by tazphoenix
    hi.i wrote a jquery function and now i want to use it as a plugin so i could use that more than 1 place.the code lookes like this: function loadTable(){ $.post("includes/action.php", {action: "gettable"}, function(html){ $("#tblstudents tbody").html(html); $("#tblstudents") .tablesorter({widthFixed: false, widgets: ['zebra'], sortList: [[0,0]]}) .tablesorterPager({container: $("#pager")}) .tablesorterFilter({filterContainer: $("#filter-box"), filterClearContainer: $("#filter-clear-button")}); }); } And I want it have functions for setting "includes/action.php" and "gettable" in $.post function and $("#pager") ,$("#filter-box") and $("#filter-clear-button") from $("#tblstudents").Can anyone help me?

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  • Why is the application not starting from top...

    - by user536213
    i have created iphone game.When i pause the game using pause button i quit cliking quit button... Now when i start the game again ..the previous counter i created using this code... [NSTimer scheduledTimerWithTimeInterval:1.0 target:self selector:@selector(updateTimerFunc) userInfo:nil repeats:YES]; the timer is 100 sec and moves to zero...now it start giving the difference of twwo ,,98,96,94 if i quit the game again ans start this time the difference will become of 4 96,92 ...its keep on increasing ....what is this issue? kindly help

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  • Onclick not added until after Postback

    - by Morph
    I have the following: <asp:Button id="SubmitButton" Text="Submit" runat="server" OnClientClick="Do();" OnClick="SubmitButton_Click"/> When the page is first rendered, I go to the view source in my browser and see that the onclick="Do();" is not added to my submit button tag. But when I do a post back, and do the view source again, the onclick is added to the submit. Why would the onclick not be there on the first request?

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  • Animate css attributes: set "bottom" and remove "top"

    - by Slevin
    I'm working on a few animations with jQuery. I have 3-4 elements which should slide in from the top. I defined their positions with css: #element-1 { top:124px; left:0px; right:auto; bottom:auto; } #element-2 { top:230px; left:670px; right:auto; bottom:auto; } #element-3 { top:auto; left:0px; right:auto; bottom:100px; } Then I save their positions initial on pageload, cause i have to manipulate the css value to top: -1000px to hide them and make the "slide in from top" animation possible. var image_margins = []; $('img').each(function() { var obj = $(this), id = obj.attr('id'), mtop = obj.css('top'), mleft = obj.css('left'), mright = obj.css('right'), mbottom = obj.css('bottom'); // save alle margins in array image_margins[id] = {mtop:mtop,mleft:mleft,mright:mright,mbottom:mbottom}; // hide all content elements obj.css({'top':'-1000px'}); }); When the user clicks the animate button, the elements should slide to their saved positions. The problem: i can't remove the top attribute. Some elements only have bottom margins. I tried to set top to auto or '', but it's always 0px in DOM inspector. And bottom don't work if top is set. How can i get rid of the top attribute? $('.button').click(function(){ $('img').each(function() { var image = $(this), id = image.attr('id'), timeout = 0; setTimeout(function() { var mtop, mleft, mright, mbottom; if (image_margins[id].mtop != 'auto') { mtop = image_margins[id].mtop; } else { mtop = ''; } if (image_margins[id].mleft != 'auto') { mleft = image_margins[id].mleft; } else { mleft = ''; } if (image_margins[id].mright != 'auto') { mright = image_margins[id].mright; } else { mright = ''; } if (image_margins[id].mbottom != 'auto') { mbottom = image_margins[id].mbottom; } else { mbottom = ''; } image.animate({'top':mtop,'left':mleft,'right':mright,'bottom':mbottom},500); },timeout); timeout = timeout + 200; }); });

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  • change text color using jquery

    - by pradeep
    <input type='radio' name='specific_consultant' id='specific_consultant_no' value='no'>No</input> hii. i have a radio button like this . on click of this radio button , i need to change text color of text like No .. how do i do it..

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  • data grid in flex 3

    - by Madhu
    I have initially two data grids,a button and a list.. If i select one item in grid one and second in grid 2 and after clicking the button the details should be displayed on the list depending upon the selection.presently iam not dealing with the data base. iam doing it stand alone.

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  • Need help with text animation within UITableViewCell

    - by gdiphone
    I'm trying to implement a simple text animation in a custom UITableViewCell without having to go into editing mode which automatically brings up the delete button on the right. What I'm trying to accomplish is that when the label is updated by a button within the UITableviewcell, the text in the label is updated but with some smooth animation like sliding to the right since the updated text is prepended to the string. Any sample code would be great. thanks

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  • How to set message when I get Exception

    - by user1748932
    public class XMLParser { // constructor public XMLParser() { } public String getXmlFromUrl(String url) { String responseBody = null; getset d1 = new getset(); String d = d1.getData(); // text String y = d1.getYear(); // year String c = d1.getCircular(); String p = d1.getPage(); List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(); nameValuePairs.add(new BasicNameValuePair("YearID", y)); nameValuePairs.add(new BasicNameValuePair("CircularNo", c)); nameValuePairs.add(new BasicNameValuePair("SearchText", d)); nameValuePairs.add(new BasicNameValuePair("pagenumber", p)); try { HttpClient httpclient = new DefaultHttpClient(); HttpPost httppost = new HttpPost(url); httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs)); HttpResponse response = httpclient.execute(httppost); HttpEntity entity = response.getEntity(); responseBody = EntityUtils.toString(entity); } catch (UnsupportedEncodingException e) { e.printStackTrace(); } catch (ClientProtocolException e) { e.printStackTrace(); } catch (IOException e) { e.printStackTrace(); } // return XML return responseBody; } public Document getDomElement(String xml) { Document doc = null; DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance(); try { DocumentBuilder db = dbf.newDocumentBuilder(); InputSource is = new InputSource(); is.setCharacterStream(new StringReader(xml)); doc = db.parse(is); } catch (ParserConfigurationException e) { Log.e("Error: ", e.getMessage()); return null; } catch (SAXException e) { Log.e("Error: ", e.getMessage()); // i m getting Exception here return null; } catch (IOException e) { Log.e("Error: ", e.getMessage()); return null; } return doc; } /** * Getting node value * * @param elem * element */ public final String getElementValue(Node elem) { Node child; if (elem != null) { if (elem.hasChildNodes()) { for (child = elem.getFirstChild(); child != null; child = child .getNextSibling()) { if (child.getNodeType() == Node.TEXT_NODE) { return child.getNodeValue(); } } } } return ""; } /** * Getting node value * * @param Element * node * @param key * string * */ public String getValue(Element item, String str) { NodeList n = item.getElementsByTagName(str); return this.getElementValue(n.item(0)); } } I am getting Exception in this class for parsing data. I want print this message in another class which extends from Activity. Can you please tell me how? I tried much but not able to do.. public class AndroidXMLParsingActivity extends Activity { public int currentPage = 1; public ListView lisView1; static final String KEY_ITEM = "docdetails"; static final String KEY_NAME = "heading"; public Button btnNext; public Button btnPre; public static String url = "http://dev.taxmann.com/TaxmannService/TaxmannService.asmx/GetNotificationList"; @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.main); // listView1 lisView1 = (ListView) findViewById(R.id.listView1); // Next btnNext = (Button) findViewById(R.id.btnNext); // Perform action on click btnNext.setOnClickListener(new View.OnClickListener() { public void onClick(View v) { currentPage = currentPage + 1; ShowData(); } }); // Previous btnPre = (Button) findViewById(R.id.btnPre); // Perform action on click btnPre.setOnClickListener(new View.OnClickListener() { public void onClick(View v) { currentPage = currentPage - 1; ShowData(); } }); ShowData(); } public void ShowData() { XMLParser parser = new XMLParser(); String xml = parser.getXmlFromUrl(url); // getting XML Document doc = parser.getDomElement(xml); // getting DOM element NodeList nl = doc.getElementsByTagName(KEY_ITEM); int displayPerPage = 5; // Per Page int TotalRows = nl.getLength(); int indexRowStart = ((displayPerPage * currentPage) - displayPerPage); int TotalPage = 0; if (TotalRows <= displayPerPage) { TotalPage = 1; } else if ((TotalRows % displayPerPage) == 0) { TotalPage = (TotalRows / displayPerPage); } else { TotalPage = (TotalRows / displayPerPage) + 1; // 7 TotalPage = (int) TotalPage; // 7 } int indexRowEnd = displayPerPage * currentPage; // 5 if (indexRowEnd > TotalRows) { indexRowEnd = TotalRows; } // Disabled Button Next if (currentPage >= TotalPage) { btnNext.setEnabled(false); } else { btnNext.setEnabled(true); } // Disabled Button Previos if (currentPage <= 1) { btnPre.setEnabled(false); } else { btnPre.setEnabled(true); } // Load Data from Index int RowID = 1; ArrayList<HashMap<String, String>> menuItems = new ArrayList<HashMap<String, String>>(); HashMap<String, String> map; // RowID if (currentPage > 1) { RowID = (displayPerPage * (currentPage - 1)) + 1; } for (int i = indexRowStart; i < indexRowEnd; i++) { Element e = (Element) nl.item(i); // adding each child node to HashMap key => value map = new HashMap<String, String>(); map.put("RowID", String.valueOf(RowID)); map.put(KEY_NAME, parser.getValue(e, KEY_NAME)); // adding HashList to ArrayList menuItems.add(map); RowID = RowID + 1; } SimpleAdapter sAdap; sAdap = new SimpleAdapter(AndroidXMLParsingActivity.this, menuItems, R.layout.list_item, new String[] { "RowID", KEY_NAME }, new int[] { R.id.ColRowID, R.id.ColName }); lisView1.setAdapter(sAdap); } } This my class where I want to Print that message

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  • Adding a control in Datagridview

    - by sameer
    How to add a control in DataGridView? Using Button event. For example i want to create a new a row and column in DataGridView, this i want to happen through button control. How can i do it? I am using C#.net and MS-Access.

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  • can i change the image place using jquery

    - by kumar
    I have jquery datepicker code where i am dispalying one calander control to dispaly dateand time $("input[id^='exc-flwup-<%=Model.ExceptionID%>']").datepicker({ duration: 0, buttonImage: '/Content/images/calender.gif', buttonImageOnly: true, showOn:'button', constrainInput: true, showTime: true, stepMinutes: 30, stepHours: 1, altTimeField: '', time24h: true, minDate: 0 }); Image button is allways coming left side of my textbox I need to keep it right side of my textbox is there any way I can adjust my image on this? thanks

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  • alpha property problem in swf file.

    - by sabuj
    i made a button & i used a on click event on this. So it can show some images. but after that when i click on another button for showing some text the images still upon there. Images hide the text. what will be the solution ?

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  • jquery dynamic jcarsoul make it as autorun

    - by Bharanikumar
    Hi , Am using this jquery plugin]1 How to change the click mode to automatically run mode , Present scenario , When u click NEXt it show the next three image, When u click BACK It shows the previous three images , I want to change this scenario to Whe loads , the plugin should start running(image) , Also i need the NEXT and BCK button , When user click the back button , then it show show previous three image and run image toward back, Is it possible in this ? Thanks

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  • UITableViewCell: Allowing Selective Deletion

    - by Aran Mulholland
    I have a table view and want to allow rearranging of all cells, however there are certain cells that i do not want to be allowed to be deleted. when the UiTableView is put into deletion mode i do not want the red '-' button to appear on the left hand side, and do not want the swipe gesture to bring up the Delete button of these cells but want it to happen for the others. Any ideas?

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  • Keeping the keyboard from obscuring widgets in a form

    - by synic
    In an iPhone app, how do I keep the software keyboard from obscuring buttons, or UITextView fields in a View? I've got the following layout: View -\ UITextView UIButton ... but, the keyboard obscures the button at the bottom when I'm typing in the UITextView. I tried using the following: View -\ UIScrollView -\ UITextView UIButton ... but, the window does not scroll as expected, so the user has no way of clicking the button. How is this normally handled?

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