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  • $.ajax is not working

    - by Geetha
    Hi All, In my web page there is a textbox to get the scanned barcode value. Once we scan the barcode it has to get details from the database. I am creating the change event for the textbox. Problem: $.ajax is not working. Code: var target = $('#txtBarcode'), val = target.val(); target.change(monitor()); function monitor() { var xx = $('#txtBarcode').val(); $.ajax({ type: "POST", contentType: "application/json; charset=utf-8", data: "{}", url: "HomePage.aspx/SearchProduct", dataType: "json", success: function(data) { alert("Success!!!"); } }); }

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  • jquery $.ajax call succeeds but returns nothing. (jsonp)

    - by Shawn
    $(document).ready(function() { $('#button').click(function() { try { var json = $.ajax({url : 'http://www.example.com/experimental/service.php', type : 'jsonp', success : function() {alert('success')}}); alert(json); } catch(err) { alert(err.description) } var sjson = JSON.stringify(json); $('#display').html(sjson); }) }) After a button is pressed I get an alert message that says "success" and also one that says undefined, referring to the fact that nothing was returned from the ajax call. I checked the firebug 'net' tab and indeed i get a succesful response from the server of "jsonp1272724228884( {} );" Any ideas?

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  • jQuery AJAX & an ASP.NET web service works locally but not remotely

    - by Alex
    Interesting one here. I have an ASP.NET 1.1 project that contains a web service in it. I'm using jQuery's AJAX functionality to call some services from the client. This is what my code looks like: $.ajax({ type: "POST", url: 'foo.asmx/functionName', data: 'foo1=' + foo1 + '&foo2=' + foo2, dataType: "xml", success: function(xml) { //do something with my xml data }, error: function(request, error){ //handle my error } }); This works great when I run the site from my IDE on localhost. However, when I deploy this site to any other server I get a parsererror error from jQuery. It does not appear to even call my service as I dropped in some code to write a log file to disk and it's not making it there. The same exact XML should be returned from both my localhost and the server I deployed to. Any ideas?

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  • Jquery ajax and php die()

    - by BizMark
    Hi, I have an IE problem. I am using the jquery ajax method to call a php script. The php script just calls die(). In firefox, the error message is displayed, but in IE the success message is displayed without any data. I would prefer the error function to be called. Is there any way to fix this? I'm guessing my javascript code needs change somehow. Thanks! <?php die() ?> $.ajax({ url: "phps/php.php?id="+the_id, dataType: "json", error: function(){ alert('error'); }, success: function(data){ alert("SUCCESS"); } });

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  • ajax echo returns javascript code!

    - by StevanSteve
    Hi, i have an ajax call. Php page (A) called by ajax requires some other php page (B). Page "B" is php file looking something like this <html> <head> javascript code </head> <body> PHP Code </body> Inside of "head" tags is javascript code. Now, Page "A" includes page "B", but instead of expected result, it echoes pure javascript code from included page "B"! How to prevent that?

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  • Download content of the page using ajax jquery

    - by niao
    Greetings, how can I download some page content using ajax and jquery: I am doing something like that (2 versions inside one script): $("p").click(function() { $('#result').load('http://google.com'); $.ajax({ url='www.google.com', success: function(data) { $("result").html(data); alert('Load was performed.'); var url = 'www.wp.pl'; $('div#result').load(url); //var content = $.load(url); //alert(content); //$("#result").html("test"); } }); }); but it does not return any content

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  • Show AJAX content after images have loaded

    - by Ben4Himv
    I am developing my own lightbox kind of jquery plugin. Everything works but I want to hide the loaded content until the images have loaded in the browser from the AJAX call. I found a similar post and I am using the following script but the setTimeout function is what reveals the content and not the .load function. Am I trying to achieve the impossible? $.ajax({ url: 'meet/'+ pLoad + '.html', success: function(data) { var imageCount = $(data).filter('img').length; var imagesLoaded = 0; $(data).hide() .appendTo('#zoom_inner') .filter('img') .load( function() { ++imagesLoaded; if (imagesLoaded >= imageCount) { $('#zoom_inner').children().show(); } }); setTimeout( function() { $('#zoom_inner').children().show() }, 5000 ); } });

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  • using ajax url to call function

    - by Steven Vanerp
    Hopefully I can ask this correctly cuz I know what I want it to do but can't seem to find any answers from searching. I have a func.php page where I have all my functions and I want ajax to use one function from that page. func.php function toptable() { echo"something happens in here"; } index.php <?php include 'func.php'; ?> <script type="text/javascript"> function check_username() { uname=document.getElementById("username").value; var params = "user_id="+uname; var url = "topoftable()"; $.ajax({ type: 'POST', url: url, dataType: 'html', data: params, beforeSend: function() { document.getElementById("right").innerHTML= 'checking' ; }, complete: function() { }, success: function(html) { document.getElementById("right").innerHTML= html ; } }); } </script> Make sense?

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  • How do you send an array as part of an (jquery) ajax request

    - by Ankur
    I tried to send an array as part of an ajax request like this: var query = []; // in between I add some values to 'query' $.ajax({ url: "MyServlet", data: query, dataType: "json", success: function(noOfResults) { alert(noOfResults); } }); } I wanted to see what I get back in the servlet, so I used this line: System.out.println(request.getParameterMap().toString()); Which returned {} suggesting an empty map. Firebug tells me I am getting a 400 bad request error If I send a queryString like attribute=value as the 'data' then everything works fine, so it has to do with not being able to send an array as is. What do I have to do to get that data into the servlet for further processing. I don't want to pull it out and turn it into a queryString in the JS if I can avoid it. EDIT: I used the .serializeArray() (jQuery) function before sending the data. I don't get the 400 but nothing useful is being sent through.

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  • jQuery ajax get

    - by Happy
    There are many class="item" blocks on the page. For each one there is different var item_link and ajax request. Ajax searches for src attribute of .message img and throws it to var src. $(".item").each(function(){ var item_link = "http://..."; $(this).prepend('<div class="src"></div>'); $.get(item_link, function(data) { var src = $('.message img', data).attr('src'); }); }); How to print var src to <div class="src"></div>? Thanks.

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  • How come $(this) is undefined after ajax call

    - by JohnnyQ
    I am doing an ajax request when an anchor tag is clicked with an ID set to href. Btw, this anchor tag is dynamically created. <a href="983" class="commentDeleteLink">delete</a> When the anchor tag is clicked the following code is executed: $('.commentDeleteLink').live('click', function(event) { event.preventDefault(); var result = confirm('Proceed?'); if ( result ) { $.ajax({ url: window.config.AJAX_REQUEST, type: "POST", data: { action : 'DELCOMMENT', comment : $('#commentText').val(), comment_id : $(this).attr('href') }, success: function(result) { alert($(this).attr('href')); //$(this).fadeOut(slow); } }); } }); When I tried to display $(this).attr('href') it says it's "undefined". What I really want to do is fadeOut the anchor tag but when I investigated the value of $(this) it is "undefined". What could be wrong with the snippet above?

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  • Use AJAX to check for a new message

    - by Luke
    Quite simply, I need to alert the end user when they have a new private message. From a combination of research and other opinion, I realise I need to use AJAX for this. The mysql query would be SELECT id FROM tbl_messages WHERE to_viewed = 1 So when someone sends a message, I want an alert to popup on the screen to inform the user without a page reload. I have absolutely no idea what I am doing, but know what I want. Really need help with this, AJAX is definitely something I want to improve as it opens up greater possibilities! Thanks

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  • Ajax posting to PHP

    - by JQonfused
    Hi guys, I'm testing a jQuery ajax post method on a local Apache 2.2 server with PHP 5.3 (totally new at this). Here are the files, all in the same folder. html body (jQuery library included in head): <form id="postForm" method="post"> <label for="name">Input Name</label> <input type="text" name="name" id="name" /><br /> <label for="age">Input Age</label> <input type="text" name="age" id="age" /><br /> <input type="submit" value="Submit" id="submitBtn" /> </form> <div id="resultDisplay"></div> <script src="queryRequest.js"></script> queryRequest.js $(document).ready(function(){ $('#s').focus(); $('#postForm').submit(function(){ var name = $('#name').val(); var age = $('#age').val(); var URL = "post.php"; $.ajax({ type:'POST', url: URL, datatype:'json', data:{'name': name ,'age': age}, success: function(data){ $('#resultDisplay').append("Value returned.<br />name: "+data.name+" age: "+data.age); }, error: function() { $('resultDisplay').append("ERROR!") } }); }); }); post.php <?php $name = $_POST['name']; $age = $_POST['age']; $return = array('name' => $name, 'age' => $age); echo json_encode($return); ?> After inputting the two fields and pressing 'Submit', the success method is called, text appended, but the values returned from ajax post are undefined. And then after less than a second, the text fields are emptied, and the text appended to the div is gone. Doesn't seem like it's a page refresh, though, since there's no empty page flash. What's going on here? I'm sure it's a silly mistake but Firebug isn't telling me anything.

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  • call .js file after ajax load

    - by asovgir
    I am trying to apply a .js file to a page I loaded via ajax (since ajax automatically strips the content of all the javascript). var url; var textUrl = 'local/file.js'; $('a').click(function() { url = $(this).attr('href'); $('.secondaryDiv').load(url, function() { $.getScript(textUrl, function(data, textStatus, jqxhr) { console.log(data); //data returned from getScript console.log(textStatus); //return "success" console.log(jqxhr.status); //200 }); }); return false; }); Am I approaching this the right way? I tried everything I could think of and I can't get it to work

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  • ajaxStart only called once

    - by cmroanirgo
    I'm having trouble with ajaxStart/ajaxStop. In the following code, the ajaxStart/ajaxStop code is only ever called once (the very first time). Any ideas why? var A_func = function() { $.get($(this).attr("href"), function(response) { $("#content_inner").replaceWith($("#content_inner", response)); }); return false; }; $(function() { $("A").live("click", A_func); $(document).ajaxStart(function(){$("#loading").show();alert("loading");}); $(document).ajaxStop(function(){$("#loading").hide();alert("finished");}); }); Note that the ajax requests themselves work correctly, it's just that the 'loading' icon only shows the once and then never again. My html is something like: <body> <img id="loading" width="12" height="12" src="/images/ajax-loader.gif" style="display:none" alt="loading"/> ... <div id="content"><div id="content_inner"...</div></div>... </body> I have also tried using ajaxSend/ajaxComplete and it has the same problem

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  • Form submitted via dialog opens dialog again

    - by VikingGoat
    I have a form in a jquerymobile dialog box that I am submitting via jQuery Ajax. Currently my problem is that once the form is submitted the same dialog box is opened again on top of the original dialogbox. So that my url reads before submission: url/index.php#&ui-state=dialog and then after submission: url/index.php#&ui-state=dialog#&ui-state=dialog&ui-state=dialog Has anyone ever encountered something like this before? [edit added code example] $(function(){ $("#form").submit(function(e){ e.preventDefault(); var dataString = $("#form").serialize(); errorInput = $("input[name=valOne]#valOne").val(); $.ajax({ type: "GET", url: "formHandler.php", data: dataString, dataType: "text", success: function(data){ if(data.toLowerCase().indexOf("error") >= 0){ alert(data); $(".ui-dialog").dialog("close"); $("#valOne").val(errorInput); //the reentering info so user doesn't have to }else{ $(".ui-dialog").dialog("close"); location.href="index.php"; } }, error:function (xhr, ajaxOptions, thrownError){ alert(thrownError); } }); }); });

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  • jquery checkbox and array help

    - by sea_1987
    Hi There I need to get the names and values of checkboxes that have been checked into an array name selected, I cannot for life of me get it working, below is my attempt, if someone could clrify what I am doing wrong that would be brilliant. //Location AJAX //var dataObject = new Object(); var selected = new Array(); $('#areas input.radio').change(function(){ // will trigger when the checked status changes var checked = $(this).attr("checked"); // will return "checked" or false I think. // Do whatever request you like with the checked status if(checked == true) { /*$("input:checked").each(function() { selected.push($(this).attr('name')+"="+$(this).val(); }); alert(selected)*/ getQuery = $(this).attr('name')+"="+$(this).val()+"&location_submit=Next"; $.ajax({ type:"POST", url:"/search/location", data: getQuery, success:function(data){ alert(getQuery); console.log(data); // $('body.secEmp').html(data); } }); } else { //do something to remove the content here alert("Remove"); } });

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  • passing input text value to ajax call

    - by amby
    Hi, I have to pass string entered in the input text to server method calling through jquery ajax. But its not going through. can please somebody tell me what i m doing wrong here. Below is the code: $.ajaxSetup({ cache: false timeout: 1000000}); function concatObject(obj) { strArray = []; //new Array for (prop in obj) { strArray.push(prop + " value :" + obj[prop]); } return strArray.join();} //var Eid = "stephen.gilroy1"; function testCAll() { //var ntid = $('#Eid').val(); $.ajax({ type: "POST", url: "Testing.aspx/SendMessage", //data: "{'ntid':'stephen.gilroy1'}", //working data: "{'ntid': $('#Eid').val()}", contentType: "application/json; charset=utf-8", dataType: "json", success: function(result) { alert(result.d); resultData = eval("(" + result.d + ")"); $("#rawResponse").html(result.d); //$("#response").html(resultData.sn); }, error: function(result) { alert("jQuery Error:" + result.statusText); } });}$.ajaxSetup({ cache: false //timeout: 1000000 }); function concatObject(obj) { strArray = []; //new Array for (prop in obj) { strArray.push(prop + " value :" + obj[prop]); } return strArray.join(); } //var Eid = "stephen.gilroy1"; function testCAll() { //var ntid = $('#Eid').val(); $.ajax({ type: "POST", url: "Testing.aspx/SendMessage", //data: "{'ntid':'stephen.gilroy1'}", //working data: "{'ntid': $('#Eid').val()}", contentType: "application/json; charset=utf-8", dataType: "json", success: function(result) { alert(result.d); resultData = eval("(" + result.d + ")"); $("#rawResponse").html(result.d); //$("#response").html(resultData.sn); }, error: function(result) { alert("jQuery Error:" + result.statusText); } }); } above is js file and below is its aspx file: <%@ Page Language="C#" AutoEventWireup="true" CodeFile="Testing.aspx.cs" Inherits="Testing" %> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head runat="server"> <title></title> <script src="jquery.js" type="text/javascript"></script> <script src="Testing.js" type="text/javascript"></script> <script src="json2.js" type="text/javascript"></script> </head> <body> <form id="form1" runat="server"> <div> Employee's NTID: <input type="text" id = "Eid" name="Employee_NTID" /> <asp:GridView ID="GridView1" runat="server"> </asp:GridView> <br /> <br /> <input type="button" onclick="testCAll()" value = "Search"/> <div id="rawResponse"></div> <hr /> <div id="response"></div> </div> </form> </body> </html>

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  • jQuery AJAX (google PageRank)

    - by RobertPitt
    Hey guys, I need a little help.. iv'e been developing a Jqery plug-in to get the page ranks of urls on a website using XHR, The problem is when requesting the rank from google servers the page is returned no content, but if i use an inspector and get the url that was requests and go to it via my browser the pageranks are shown. so it must be something with headers but its just got me puzzled. Heres some source code but i have removed several aspects that are not needed to review. pagerank.plugin.js ( $.fn.PageRank = function(callback) { var _library = new Object(); //Creat the system library _library.parseUrl = function(a) { var b = {}; var a = a || ''; /* * parse the url to extract its parts */ if (a = a.match(/((s?ftp|https?):\/\/){1}([^\/:]+)?(:([0-9]+))?([^\?#]+)?(\?([^#]+))?(#(.+))?/)) { b.scheme = a[2] ? a[2] : "http"; b.host = a[3] ? a[3] : null; b.port = a[5] ? a[5] : null; b.path = a[6] ? a[6] : null; b.args = a[8] ? a[8] : null; b.anchor = a[10] ? a[10] : null } return b } _library.ValidUrl = function(url) { var b = true; return b = url.host === undefined ? false : url.scheme != "http" && url.scheme != "https" ? false : url.host == "localhost" ? false : true } _library.toHex = function(a){ return (a < 16 ? "0" : "") + a.toString(16) } _library.hexEncodeU32 = function(a) { } _library.generateHash = function(a) { for (var b = 16909125, c = 0; c < a.length; c++) { } return _library.hexEncodeU32(b) } var CheckPageRank = function(domain,_call) { var hash = _library.generateHash(domain); $.ajax( { url: 'http://www.google.com/search?client=navclient-auto&ch=8'+hash+'&features=Rank&q=info:' + escape(domain), async: true, dataType: 'html', ifModified:true, contentType:'', type:'GET', beforeSend:function(xhr) { xhr.setRequestHeader('Referer','http://google.com/'); //Set Referer }, success: function(content,textS,xhr){ var d = xhr.responseText.substr(9, 2).replace(/\s$/, ""); if (d == "" || isNaN(d * 1)) d = "0"; _call(d); } }); } //Return the callback $(this).each(function(){ urlsegments = _library.parseUrl($(this).attr('href')) if(_library.ValidUrl(urlsegments)) { CheckPageRank(urlsegments.host,function(rank){ alert(rank) callback(rank); }); } }); return this; //Dont break any chain. } )(jQuery); Index.html (example) <html> <head> <script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.4.1/jquery.min.js"></script> <script type="text/javascript" src="pagerank.plugin.js"></script> <script type="text/javascript"> $(document).ready(function() { $('a').PageRank(function(pr){ alert(pr); }) }); </script> </head> <body> <a href="http://facebook.com">a</a> <a href="http://twitter.com">a</a> <div></div> </body> </html> i just cant understand why its doing this.

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  • update datagridview using ajax in my asp.net without refreshing the page.(Display real time data)

    - by kurt_jackson19
    I need to display a real time data from MS SQL 2005. I saw some blogs that recommend Ajax to solve my problem. Basically, right now I have my default.aspx page only just for a workaround I could able to display the data from my DB. But once I add data manually to my DB there's no updating made. Any suggestions guys to fix this problem? I need to update datagridview with out refreshing the page. Here's my code on Default.aspx.cs using System; using System.Data; using System.Configuration; using System.Web; using System.Web.Security; using System.Web.UI; using System.Web.UI.WebControls; using System.Web.UI.WebControls.WebParts; using System.Web.UI.HtmlControls; using System.Data.SqlClient; public partial class _Default : System.Web.UI.Page { protected void Page_Load(object sender, EventArgs e) { FillDataGridView(); } protected void up1_Load(object sender, EventArgs e) { FillDataGridView(); } protected void FillDataGridView() { DataSet objDs = new DataSet(); SqlConnection myConnection = new SqlConnection (ConfigurationManager.ConnectionStrings["MainConnStr"].ConnectionString); SqlDataAdapter myCommand; string select = "SELECT * FROM Categories"; myCommand = new SqlDataAdapter(select, myConnection); myCommand.SelectCommand.CommandType = CommandType.Text; myConnection.Open(); myCommand.Fill(objDs); GridView1.DataSource = objDs; GridView1.DataBind(); } } Code on my Default.aspx <html xmlns="http://www.w3.org/1999/xhtml" > <head runat="server"> <title>Ajax Sample</title> </head> <body> <form id="form1" runat="server"> <asp:ScriptManager ID="ScriptManager1" runat="server" EnablePageMethods="true"> <Scripts> <asp:ScriptReference Path="JScript.js" /> </Scripts> </asp:ScriptManager> <asp:UpdatePanel ID="UpdatePanel1" runat="server" OnLoad="up1_Load"> <ContentTemplate> <asp:GridView ID="GridView1" runat="server" Height="136px" Width="325px"/> </ContentTemplate> <Triggers> <asp:AsyncPostBackTrigger ControlID="GridView1" /> </Triggers> </asp:UpdatePanel> </form> </body> </html> My problem now is how to call or use the ajax.js and how to write a code to call the FillDataGridView() in my Default.aspx.cs page. Thank you guys, hope anyone can help me on this problem.

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  • Ajax loaded content , jquery plugins not working

    - by Sylph
    Hello, I have a link that calls the ajax to load content, and after the content is loaded, my jquery function doesn't work anymore Here is my HTML <a href="#" onclick="javascript:makeRequest('content.html','');">Load Content</a> <span id="result"> <table id="myTable" valign="top" class="tablesorter"> <thead> <tr> <th>Title 1</th> <th>Level 1</th> <th>Topics</th> <th>Resources</th> </tr> </thead> <tbody> <tr> <td>Example title 1</td> <td>Example level 1</td> </tr> <tr> <td>Example title 2</td> <td>Example level 2</td> </tr> </tbody> </table> </span> The table is sorted using jquery table sorter plugin from http://tablesorter.com/docs/ After the ajax content is loaded, another set of table with different data will be displayed. However, the sorting doesn't work anymore. Here is my ajax script which is use to load the content : var http_request = false; function makeRequest(url, parameters) { http_request = false; if (window.XMLHttpRequest) { // Mozilla, Safari,... http_request = new XMLHttpRequest(); if (http_request.overrideMimeType) { // set type accordingly to anticipated content type //http_request.overrideMimeType('text/xml'); http_request.overrideMimeType('text/html'); } } else if (window.ActiveXObject) { // IE try { http_request = new ActiveXObject("Msxml2.XMLHTTP"); } catch (e) { try { http_request = new ActiveXObject("Microsoft.XMLHTTP"); } catch (e) {} } } if (!http_request) { alert('Cannot create XMLHTTP instance'); return false; } http_request.onreadystatechange = alertContents; http_request.open('GET', url + parameters, true); http_request.send(null); } function alertContents() { if (http_request.readyState == 4) { // alert(http_request.status); if (http_request.status == 200) { //alert(http_request.responseText); result = http_request.responseText; document.getElementById('result').innerHTML = result; } else { alert('There was a problem with the request.'); } } } Any idea how I can get the jquery plugins to work after the content is loaded? I have searched and changed the jquery.tablesorter.js click function into live() like this $headers.live("click",function(e) but it doesn't work as well. How can I make the jquery functions to work after the content is loaded? Thank you

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  • php, mySQL & AJAX: Unable to use sessions across the scripts in the same domain

    - by Devner
    Hi all, I have the following pages: page1.php, page2.php and page3.php. Code in each of them is as below CODE: page1.php <script type="text/javascript"> $(function(){ $('#imgID').upload({ submit_to_url: "page2.php", file_name: 'myfile1', description : "Image", limit : 1, file_types : "*.jpg", }) }); </script> <body> <form action="page3.php" method="post" enctype="multipart/form-data" name="frm1" id="frm1"> //Some other text fields <input type="submit" name="submit" id="submit" value="Submit" /> </form> </body> page2.php <?php session_start(); $a = $_SESSION['a']; $b = $_SESSION['b']; $c = $_SESSION['c']; $res = mysql_query("SELECT col FROM table WHERE col1 = $a AND col2 = $b AND col3 = $c LIMIT 1"); $num_rows = mysql_num_rows($res); echo $num_rows; //echos 0 when in fact it should have been 1 because the data in the Session exists. //Ok let's proceed further //... Do some stuff... //Store some more values and create new session variables (and assume that page1.php is going to be able to use it) $_SESSION['d'] = 'd'; $_SESSION['e'] = 'e'; $_SESSION['f'] = 'f'; if (move_uploaded_file($_FILES['file']['tmp_name'], $file)) { echo "success"; } else { echo "error ".$_FILES['file']['error']; } ?> page3.php <?php session_start(); if( isset($_POST['submit']) ) { //These sessions are non-existent although the AJAX request //to page2.php may have created them when called via AJAX from within page1.php echo $_SESSION['d'].$_SESSION['e'].$_SESSION['f']; ?> } ?> As the code says it I am posting some info via AJAX call from page1.php to page2.php. page2.php is supposed to be able to use the session values from page1.php i.e. $_SESSION['a'], $_SESSION['b'] and $_SESSION['c'] but it does not. Why? How can I fix this? page2.php is creating some more sessions after some processing is done and a response is sent back to page1.php. The submit button of the form on page1.php is hit and the page gets POST'ed to page3.php. But when the SESSION info that gets created in page2.php is echoed, it's blank signifying that SESSIONS from page2.php are not used. How can I fix this? I looked over a lot of information and have spent about 50 hours trying to do different things with my scripts before arriving at the above conclusions. My app. is custom made using function (not OOPS) and does not use any PHP frameworks & I am not even about to use any as my knowledge of OOP concepts is limited any many frameworks are object oriented. I came across race conditions, but the solutions provided don't help too much. One more solution of using DB to hold sessions and seek and retrieve from DB is the last thing on my mind and I really want to avoid creating table, coding and maintaining code for a task as simple as just keeping sessions across pages in the same domain. So my request is: Is there a way that I can solve the above problem(s) via simple coding in present conditions? Any help is appreciated. Thank you.

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  • Jquery ajax function working in IE but not in FF

    - by booota
    Okay I have this ajax call $('.updatecom .registercomplaint').click(function(){ updatecomplaints(); }); This calls the function updatecomplaints() function updatecomplaints() { var tno = $(".updatecom #tno").val(); var status = $(".updatecom #status").val(); if(status=='DONE') { $(".updatecom #con").val(''); } var tname = $(".updatecom #tname").val(); var rg11 = $(".updatecom #crg11").val(); var rg06 = $(".updatecom #crg06").val(); var tvpins = $(".updatecom #tvpins").val(); var jointer = $(".updatecom #jointer").val(); var cquantity = $(".updatecom #conqty").val(); var nooftv = $(".updatecom #tvno").val(); var misc = $(".updatecom #misc").val(); var tcomments = $(".updatecom #tcomments").val(); var con = $(".updatecom #con").val(); //alert(tno+status+tname+rg11+rg06+tvpins+jointer+cquantity+nooftv+misc+tcomments+con); $.ajax( { type: "POST", url: "up_functions.php", data: "ticket="+ tno +"& opt=upcom" +"& status="+ status +"& tname="+ tname +"& rg11="+ rg11 +"& rg06="+ rg06 +"& tvpins="+ tvpins +"& jointer="+ jointer +"& cquantity="+ cquantity +"& nooftv="+ nooftv +"& misc="+ misc +"& tcomments="+ tcomments +"& con="+ con, success: function(response) { alert(response); } }); } here is my up_functions.php $tno = htmlspecialchars(trim($_REQUEST['ticket'])); $status = htmlspecialchars(trim($_REQUEST['status'])); $tname = htmlspecialchars(trim($_REQUEST['tname'])); $rg11 = htmlspecialchars(trim($_REQUEST['rg11'])); $rg06 = htmlspecialchars(trim($_REQUEST['rg06'])); $tvpins = htmlspecialchars(trim($_REQUEST['tvpins'])); $jointer = htmlspecialchars(trim($_REQUEST['jointer'])); $cquantity = htmlspecialchars(trim($_REQUEST['cquantity'])); $nooftv = htmlspecialchars(trim($_REQUEST['nooftv'])); $misc = htmlspecialchars(trim($_REQUEST['misc'])); $tcomments = htmlspecialchars(trim($_REQUEST['tcomments'])); $con = htmlspecialchars(trim($_REQUEST['con'])); $result=$ptr->upcomticketinfo($tno,$status,$tname,$rg11,$rg06,$tvpins,$jointer,$cquantity,$nooftv,$misc,$tcomments,$con); echo $result; and here is my upconticketinfo() php function function upcomticketinfo($tno,$status,$tname,$rg11,$rg06,$tvpins,$jointer,$cquantity,$nooftv,$misc,$tcomments,$con) { if($con!='' || $con!=NULL) { $this->query = "update `booking discription` set `STATUS`='$status',`CLOSED ON`='$con' where `TICKET NO`='$tno'"; $this->q_result = mysql_query($this->query,$this->conn) or die(mysql_error()); if($this->q_result) { $query = "update `tech detail` set `TECH NAME`='$tname',`CABLE RG11`='$rg11',`CABLE RG06`='$rg06',`TV PINS USED`='$tvpins',`JOINTER USED`='$jointer',`CONNECTOR QTY`='$cquantity',`NO OF TV`='$nooftv',`MISC`='$misc',`TECH COMMENTS`='$tcomments' where `BOOKING`='$tno'"; $q_result = mysql_query($query,$this->conn) or die(mysql_error()); if($q_result) { $response = "updated"; } else { $response = "error"; } } else { $response = "error"; } } else { $this->query = "update `booking discription` set `STATUS`='$status' where `TICKET NO`='$tno'"; $this->q_result = mysql_query($this->query,$this->conn) or die(mysql_error()); if($this->q_result) { $query = "update `tech detail` set `TECH NAME`='$tname',`CABLE RG11`='$rg11',`CABLE RG06`='$rg06',`TV PINS USED`='$tvpins',`JOINTER USED`='$jointer',`CONNECTOR QTY`='$cquantity',`NO OF TV`='$nooftv',`MISC`='$misc',`TECH COMMENTS`='$tcomments' where `BOOKING`='$tno'"; $q_result = mysql_query($query,$this->conn) or die(mysql_error()); if($q_result) { $response = "updated"; } else { $response = "error"; } } else { $response = "error"; } } return $response; } Question is that, this code is working just fine in IE8 i.e i am using... but it is not working in FF 3.6.3... I have checked each n everything... One thing is that the code works fine on FF too only when i activate the firebug debugger. Otherwise the alert in ajax success shows itself with nothing in it... Help me...

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