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  • Django Initial for a ManyToMany Field

    - by gramware
    I have a form that edits an instance of my model. I would like to use the form to pass all the values as hidden with an inital values of username defaulting to the logged in user so that it becomes a subscribe form. The problem is that the normal initial={'field':value} doesn't seem to work for manytomany fields. how do i go about it? my views.py @login_required def event_view(request,eventID): user = UserProfile.objects.get(pk=request.session['_auth_user_id']) event = events.objects.get(eventID = eventID) if request.method == 'POST': form = eventsSusbcribeForm( request.POST,instance=event) if form.is_valid(): form.save() return HttpResponseRedirect('/events/') else: form = eventsSusbcribeForm(instance=event) return render_to_response('event_view.html', {'user':user,'event':event, 'form':form},context_instance = RequestContext( request )) my forms.py class eventsSusbcribeForm(forms.ModelForm): eventposter = forms.ModelChoiceField(queryset=UserProfile.objects.all(), widget=forms.HiddenInput()) details = forms.CharField(widget=forms.Textarea(attrs={'cols':'50', 'rows':'5'}),label='Enter Event Description here') date = forms.DateField(widget=SelectDateWidget()) class Meta: model = events exclude = ('deleted') def __init__(self, *args, **kwargs): super(eventsSusbcribeForm, self).__init__(*args, **kwargs) self.fields['username'].initial = (user.id for user in UserProfile.objects.filter())

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  • In Django, why is user.is_authenticated a method and not a member variable like is_staff

    - by luc
    Hello all, I've lost some time with a bug in my app due to user authentication. I think that it's a bit confusing but maybe someone can explain the reason and it will appear to me very logical. The user.is_staff is a member variable while user.is_authenticated is a method. However is_authenticated only returns True or False depending if the class is User or AnonymousUser (see http://docs.djangoproject.com/en/dev/topics/auth/) Is there a reason for that? Why user.is_authenticated is a method? Thanks in advance

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  • In plain English, what are Django generic views?

    - by allyourcode
    The first two paragraphs of this page explain that generic views are supposed to make my life easier, less monotonous, and make me more attractive to women (I made up that last one): http://docs.djangoproject.com/en/dev/topics/generic-views/#topics-generic-views I'm all for improving my life, but what do generic views actually do? It seems like lots of buzzwords are being thrown around, which confuse more than they explain. Are generic views similar to scaffolding in Ruby on Rails? The last bullet point in the intro seems to indicate this. Is that an accurate statement?

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  • Django QuerySet ordering by expression

    - by Andrew
    How can i use order_by like order_by('field1'*'field2') For example i have items with price listed in different currencies, so to order items - i have to make currency conversion. class Currency(models.Model): code = models.CharField(max_length=3, primary_key=True) rateToUSD = models.DecimalField(max_digits=20,decimal_places=10) class Item(models.Model): priceRT = models.DecimalField(max_digits=15, decimal_places=2, default=0) cur = models.ForeignKey(Currency) I would like to have something like: Item.objects.all().order_by(F('priceRT')*F('cur__rateToUSD')) But unfortunately it doesnt work, i also faild with annotate. How can i permorm QuerySet ordering by result of value multiplication of 2 model's fields.

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  • how to save django object using dictionary?

    - by shahjapan
    is there a way that I can save the model by using dictionary for e.g. this is working fine, p1 = Poll.objects.get(pk=1) p1.name = 'poll2' p1.descirption = 'poll2 description' p1.save() but what if I have dictionary like { 'name': 'poll2', 'description: 'poll2 description' } is there a simple way to save the such dictionary direct to Poll

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  • Django: FloatField or DecimalFied for Currency ?

    - by Hellnar
    I am curious which one would be better fitting as a currency field ? I will do simple operations such as taking difference, the percentage between old and new prices. I plan to keep two digits after the zero (ie 10.50) and majority of the time if these digits are zero, I will be hiding these numbers and display it as "10"

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  • Django show manytomanyfield on form when definition is on other model

    - by John
    Hi I have the definition for my manytomany relationship on one model but want to display the field on a form for the other model. How do I do this? for example: # classes class modelA(models.Model): name = models.CharField(max_length=300) manytomany = models.ManyToManyField(modelA) class modelB(models.Model): name = models.CharField(max_length=300) # forms class modelBForm(forms.ModelForm): class Meta: model = modelB I want to use the form modelBForm but show a select box with a list from modelA (just how it would work if the model was set to modelA in the form class). How can I do this? Thanks

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  • How do I make nested regroups in Django?

    - by Marcio Cruz
    I've got the following situation in this system: Each category of products has many subcategories, and each subcategory has many products under it. I'm trying to make a product searh, which returns a list, and in my template, I show an overview of the results, like this: Cellphones Dumbphones (2 results) Smartphones (3 results) Monitors CRT (1 result) LCD (3 results) I'm my template I have only the list of products. I've tryed many combinations of nested regroups, without success. Any ideas?

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  • Django multiple many to many fields?

    - by Tom
    Hello everybody I am building a news app for my website. I want to use a sort of tag system. Each news article can have different and multiple tags. All tags are saved in a tag model, and i want to connect the tags to the newsarticle. Now is this possible with: tags = models.ForeignKey( TagsModel ) for one tag, but how i can do this with multiple of them? Thank you!

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  • Django sys.path.append for project *and* app needed under WSGI

    - by GerardJP
    Hi all, Could somebody give me a pointer on why I need to add my project root path to the python path as well as the application itself in my WSGI file? Project base is called 'djapp', the application is called 'myapp'. sys.path.append(os.path.dirname(os.path.abspath(__file__)) + '/..') sys.path.append(os.path.dirname(os.path.abspath(__file__)) + '/../djapp') os.environ['DJANGO_SETTINGS_MODULE'] = 'djapp.settings' If I omit the line with "/../djapp/" the log tells my that 'myapp' can not be imported, even though 'djapp.settings' is. (validating 'djapp' was imported) It al runs properly with the ./manage.py command. there's a __init__ in the project folder. For testings sake, I see the same issue using addsitedir: site.addsitedir('/home/user/web/project/') site.addsitedir('/home/user/web/project/djapp') Thanx a lot. Gerard.

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  • Django url tag multiple parameters

    - by Overdose
    I have two similar codes. The first one works as expected. urlpatterns = patterns('', (r'^(?P<n1>\d)/test/', test), (r'', test2), {% url testapp.views.test n1=5 %} But adding the second parameter makes the result return empty string. urlpatterns = patterns('', (r'^(?P<n1>\d)/test(?P<n2>\d)/', test), (r'', test2),) {% url testapp.views.test n1=5, n2=2 %} Views signature: def test(request, n1, n2=1):

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  • Django: Serializing models in a nested data structure?

    - by Rosarch
    It's easy to serialize models in an iterable: def _toJSON(models): return serializers.serialize("json", models, ensure_ascii=False) What about when I have something more complicated: [ (Model_A_1, [Model_B_1, Model_B_2, Model_B_3]), (Model_A_2, [Model_B_3, Model_B_4, Model_B_5, Model_B_59]), (Model_A_3, [Model_B_6, Model_B_7]), ] I tried serializing each model as it was added to the structure, then serializing the whole thing with simplejson.dumps, but that causes the JSON defining each model to be escaped. Is there a better way to do this?

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  • Django: How can I protect against concurrent modification of data base entries

    - by Ber
    If there a way to protect against concurrent modifications of the same data base entry by two or more users? It would be acceptable to show an error message to the user performing the second commit/save operation, but data should not be silently overwritten. I think locking the entry is not an option, as a user might use the "Back" button or simply close his browser, leaving the lock for ever.

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  • Django get_FOO_display and distinct()

    - by datakid
    I've seen answers to both halves of my question, but I can't work out how to marry the two. I have a book model, and a translatedBook model. The translatedBook has a langage set up as model choices in the usual way: LANGUAGES = ( (u'it', u'Italian'), (u'ja', u'Japanese'), (u'es', u'Spanish'), (u'zh-cn', u'Simplified Chinese'), (u'zh-tw', u'Traditional Chinese'), (u'fr', u'French'), (u'el', u'Greek'), (u'ar', u'Arabic'), (u'bg', u'Bulgarian'), (u'bn', u'Bengali'), etc I know that to get "Italian" I have to do translatedBook.get_language_display on a Book object. But how do I get a list of distinct languages in their long format? I've tried: lang_avail = TargetText.objects.values('language').distinct().order_by('language') lang_avail = TargetText.objects.distinct().order_by('language').values('language'). lang_avail = TargetText.objects.all().distinct('language').order_by('language') but I can't seem to get what I want - which is a list like: "English, Italian, Simplified Chinese, Spanish" The final lang_avail listed above didn't return the list of 5, it returned the list of 355 (ie, # of books) with multiple repeats....

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  • Django Generating RSS feed with description

    - by Issy
    Hey Guys, I am trying to generate a full rss feed, however when loading the feed in Mail, it just shows the title, with a read more link at the bottom. I have tried several different options. But none seem to work. I would like to generate the feed with a combination of several feeds in my modl. Here is the code i have tried: class LatestEvents(Feed): description_template = "events_description.html" def title(self): return "%s Events" % SITE.name def link(self): return '/events/' def items(self): events = list(Event.objects.all().order_by('-published_date')[:5]) return events author_name = 'Latest Events' def item_pubdate(self, item): return item.published_date And in my template which is stored in TEMPLATE_ROOT/feeds/ {{ obj.description|safe }} <h1>Event Location Details</h1> {{ obj.location|safe }} Even if i hard code the description it does not work.

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  • Django comments form validation, check if the comment is from authenticated user

    - by Headcrab
    I wanted to add reCaptcha to the comment form, but only for non-authenticated users. I've created my own comments app, using reCaptcha more or less according to this post, except that I don't have any (explicit) view function to post the comment, but instead I check captcha as a part of form validation process. Everything works fine so far. Now, how do I disable reCaptcha for a logged in user? Removing all reCaptcha-related fields in the template is no problem, but how do I validate the form, not checking captcha if the comment if from an authenticated user? Alternatively, is there a way to use two different comment form classes, depending on whether the user is authenticated or not?

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  • django related_name for field clashes.

    - by Absolute0
    I am getting a field clash in my models: class Visit(models.Model): user = models.ForeignKey(User) visitor = models.ForeignKey(User) Error: One or more models did not validate: profiles.visit: Accessor for field 'user' clashes with related field 'User.visit_set'. Add a related_name argument to the definition for 'user'. profiles.visit: Accessor for field 'visitor' clashes with related field 'User.visit_set'. Add a related_name argument to the definition for 'visitor'. what would be a sensible 'related_field' to use on visitor field? This model basically represents the visits that take place to a particular user's profile. Also should I replace any of the ForeignKey's with a ManyToManyField? The logic is a bit confusing. Edit: This seems to fix it, but I am unsure if its what I want. :) class Visit(models.Model): user = models.ForeignKey(User) visitor = models.ForeignKey(User, related_name='visitors')

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  • Django left join m2m field.

    - by duder
    Here's my Model: class User(models.Model): pass class Item(models.Model): pass class ItemVote(models.Model): user = models.ForeignKey(User) item = models.ForeignKey(Item) vote = models.BooleanField() I want to retrieve a list of Items, and I want to know if the current user has voted for each Item. How do I alter my query object so that it will generate sql similar to: SELECT ... FROM items LEFT OUTER JOIN item_votes ON (item_votes.user_id = ? AND item_votes.item_id = items.id)

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  • Django nested formsets

    - by dragoon
    Hi, I have an edit object view that contains a formset(one or many if this matters), now I want to create a page that can display multiple edit object forms and submit it in a single form. What is the correct way to achieve this task?

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  • How to cutomize a modelform widget in django 1.1?

    - by muudscope
    I'm trying to modify a django form to use a textarea instead of a normal input for the "address" field in my house form. The docs seem to imply this changed from django 1.1 (which I'm using) to 1.2. But neither approach is working for me. Here's what I've tried: class HouseForm(forms.ModelForm): address = forms.Textarea() # Should work with django 1.1, but doesn't class Meta: model = House #widgets = { 'address': forms.Textarea() } # 1.2 style - doesn't work either.

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  • Django Piston - how can I create custom methods?

    - by orokusaki
    I put my questions in the code comments for clarity: from piston.handler import AnonymousBaseHandler class AnonymousAPITest(AnonymousBaseHandler): fields = ('update_subscription',) def update_subscription(self, request, months): # Do some stuff here to update a subscription based on the # number of months provided. # How the heck can I call this method? return {'msg': 'Your subscription has been updated!'} def read(self, request): return { 'msg': 'Why would I need a read() method on a fully custom API?' }

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  • Specifying different initial values for fields in inherited models (django)

    - by Shawn Chin
    Question : What is the recommended way to specify an initial value for fields if one uses model inheritance and each child model needs to have different default values when rendering a ModelForm? Take for example the following models where CompileCommand and TestCommand both need different initial values when rendered as ModelForm. # ------ models.py class ShellCommand(models.Model): command = models.Charfield(_("command"), max_length=100) arguments = models.Charfield(_("arguments"), max_length=100) class CompileCommand(ShellCommand): # ... default command should be "make" class TestCommand(ShellCommand): # ... default: command = "make", arguments = "test" I am aware that one can used the initial={...} argument when instantiating the form, however I would rather store the initial values within the context of the model (or at least within the associated ModelForm). My current approach What I'm doing at the moment is storing an initial value dict within Meta, and checking for it in my views. # ----- forms.py class CompileCommandForm(forms.ModelForm): class Meta: model = CompileCommand initial_values = {"command":"make"} class TestCommandForm(forms.ModelForm): class Meta: model = TestCommand initial_values = {"command":"make", "arguments":"test"} # ------ in views FORM_LOOKUP = { "compile": CompileCommandFomr, "test": TestCommandForm } CmdForm = FORM_LOOKUP.get(command_type, None) # ... initial = getattr(CmdForm, "initial_values", {}) form = CmdForm(initial=initial) This feels too much like a hack. I am eager for a more generic / better way to achieve this. Suggestions appreciated. Other attempts I have toyed around with overriding the constructor for the submodels: class CompileCommand(ShellCommand): def __init__(self, *args, **kwargs): kwargs.setdefault('command', "make") super(CompileCommand, self).__init__(*args, **kwargs) and this works when I try to create an object from the shell: >>> c = CompileCommand(name="xyz") >>> c.save() <CompileCommand: 123> >>> c.command 'make' However, this does not set the default value when the associated ModelForm is rendered, which unfortunately is what I'm trying to achieve. Update 2 (looks promising) I now have the following in forms.py which allow me to set Meta.default_initial_values without needing extra code in views. class ModelFormWithDefaults(forms.ModelForm): def __init__(self, *args, **kwargs): if hasattr(self.Meta, "default_initial_values"): kwargs.setdefault("initial", self.Meta.default_initial_values) super(ModelFormWithDefaults, self).__init__(*args, **kwargs) class TestCommandForm(ModelFormWithDefaults): class Meta: model = TestCommand default_initial_values = {"command":"make", "arguments":"test"}

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  • Django display manytomany field in form when definition is on other model

    - by John
    Hi I have the definition for my manytomany relationship on one model but want to display the field on the form of my other model. How do I do this? for example: # classes class modelA(models.Model): name = models.CharField(max_length=300) manytomany = models.ManyToManyField(modelA) class modelB(models.Model): name = models.CharField(max_length=300) # forms class modelBForm(forms.ModelForm): class Meta: model = modelB If I then used modelBForm it would show a select box with the models from modelA rather than just name. Thanks

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