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  • Some doubts about the use of usermod and groupmod command

    - by AndreaNobili
    I am not yet a true "Linux guy" and I have the following doubts about how exactly do the following shell procedure (a list of commands steps) founded in a tutorial that I am following (I want deeply understand what I am doing before do it): sudo passwd root then login again as root usermod -l miner pi usermod -m -d /home/miner miner groupmod -n miner pi exit So at the beginning it enable the root account and I have to login again in the system as root...this is perfectly clear for me. And now I have the followings doubts: 1) The usermod command: usermod -l miner pi usermod -m -d /home/miner miner Reading the official documentation of the usermod command I understand that this command modify the informations related to an existing account Reading the documentation it seems to me that the -l parmether modify the name of the user pi in miner and then the -m -d paramether move the contents of the old home directory to the new one (named miner) and use this new directory as home directory My doubt is: what exactly do the executions of these operation? I think that: Rename the existing pi user in miner Then move the content of the old home directory (the pi home directory? or what?) into a new directory (/home/miner) that now is the home directory for the miner user. Is it right? The the second doubt is related to this command groupmod -n miner pi It seems to me that change the group name from pi in miner But what exactly is a group in Linux and why is it used? Tnx

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  • How to script GPO in Windows computers without Active Directory?

    - by Peteris Krumins
    Does anyone know how to script GPO for users in a Windows computer that is not on any Active Directory network? I can't use GPMC because it doesn't work without a domain. I have been searching the net for the last couple of hours and all the solutions that I find are related to GPMC. I'd imagine there are some objects in the GPO that are accessible via WMI? Does anyone know anything about that? I was unable to find any information about that. Here is the situation I am trying to script: I have 10 users on the machine, and I want to restrict what they are able to do on the machine. So I created 10 GPOs for each one of them. Now I want to apply a common policy to all of them. The only way to do it is to go through each of the GPO and do it manually. This is too time consuming, therefore I am seeking for a simpler solution. I was unable to find a way to copy GPO from a user to a user. That would make it much easier, I would create a GPO for 1st user, then copy it over to all the other users, but no luck, couldn't find a way to copy GPOs. The other method I tried was creating a GPO for the whole user group but it turns out you can't apply GPO to a group unless you use GPMC, which I can't cause the computer is not on any domain. So I am thinking about scripting this whole process, but again I can't find any examples of how to access particular GPO objects for particular users and modify properties through WMI. Any suggestions on the issue I am having? Thanks!

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  • How to scrape a _private_ google group?

    - by John
    Hi there, I'd like to scrape the discussion list of a private google group. It's a multi-page list and I might have to this later again so scripting sounds like the way to go. Since this is a private group, I need to login in my google account first. Unfortunately I can't manage to login using wget or ruby Net::HTTP. Surprisingly google groups is not accessible with the Client Login interface, so all the code samples are useless. My ruby script is embedded at the end of the post. The response to the authentication query is a 200-OK but no cookies in the response headers and the body contains the message "Your browser's cookie functionality is turned off. Please turn it on." I got the same output with wget. See the bash script at the end of this message. I don't know how to workaround this. am I missing something? Any idea? Thanks in advance. John Here is the ruby script: # a ruby script require 'net/https' http = Net::HTTP.new('www.google.com', 443) http.use_ssl = true path = '/accounts/ServiceLoginAuth' email='[email protected]' password='topsecret' # form inputs from the login page data = "Email=#{email}&Passwd=#{password}&dsh=7379491738180116079&GALX=irvvmW0Z-zI" headers = { 'Content-Type' => 'application/x-www-form-urlencoded', 'user-agent' => "Mozilla/5.0 (Windows; U; Windows NT 6.1; en-US) AppleWebKit/533.2 (KHTML, like Gecko) Chrome/6.0"} # Post the request and print out the response to retrieve our authentication token resp, data = http.post(path, data, headers) puts resp resp.each {|h, v| puts h+'='+v} #warning: peer certificate won't be verified in this SSL session Here is the bash script: # A bash script for wget CMD="" CMD="$CMD --keep-session-cookies --save-cookies cookies.tmp" CMD="$CMD --no-check-certificate" CMD="$CMD --post-data='[email protected]&Passwd=topsecret&dsh=-8408553335275857936&GALX=irvvmW0Z-zI'" CMD="$CMD --user-agent='Mozilla'" CMD="$CMD https://www.google.com/accounts/ServiceLoginAuth" echo $CMD wget $CMD wget --load-cookies="cookies.tmp" http://groups.google.com/group/mygroup/topics?tsc=2

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  • How can I access the group of a linq group-by query from a nested repeater control?

    - by Duke
    I'm using a linq group by query (with two grouping parameters) and would like to use the resulting data in a nested repeater. var dateGroups = from row in data.AsEnumerable() group row by new { StartDate = row["StartDate"], EndDate = row["EndDate"] }; "data" is a DataTable from an SqlDataAdapter-filled DataSet. "dateGroups" is used in the parent repeater, and I can access the group keys using Eval("key.StartDate") and Eval("key.EndDate"). Since dateGroups actually contains all the data rows grouped neatly by Start/End date, I'd like to access those rows to display the data in a child repeater. To what would I set the child repeater's DataSource? I have tried every expression in markup I could think of; I think the problem is that I'm trying to access an anonymous member (and I don't know how.) In case it doesn't turn out to be obvious, what would be the expression to access the elements in each iteration of the child repeater? Is there an expression that would let me set the DataSource in the markup, or will it have to be in the codebehind on some event in the parent repeater?

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  • How to parse the "<media:group>" using feedparser?

    - by Wayle.C
    The rss file is shown as below, i want to get the content in section media:group . I check the document of feedparser, but it seems not mention this. How to do it? Any help is appreciated. XYZ InfoX: Special hello http://www1.XYZInfoX.com/learninghello/home hello en Wed, 17 Mar 2010 08:50:06 GMT 2010-03-17T08:50:06Z en Voice of America http://www1.XYZInfoX.com/learninghello http://media.XYZInfoX.com/designimages/XYZRSSIcon.gif <item> <title>Who Were the Deadliest Gunmen of the Wild West?</title> <link>http://www1.XYZInfoX.com/learninghello/home/Deadliest-Gunmen-of-the-Wild-West-87826807.html</link> <description> The story of two of them: "Killin'" Jim Miller was an outlaw, "Texas" John Slaughter was a lawman | EXPLORATIONS </description> <pubDate>Wed, 17 Mar 2010 00:38:48 GMT</pubDate> <guid isPermaLink="false">87826807</guid> <dc:creator></dc:creator> <dc:date>2010-03-17T00:38:48Z</dc:date> *<media:group> <media:content url="http://media.XYZInfoX.com/images/archives_peace_comm_480_16mar_se.jpg" medium="image" isDefault="true" height="300" width="480" /> <media:content url="http://media.XYZInfoX.com/images/archives_peace_comm_230_16mar_se_edited-1.jpg" medium="image" isDefault="false" height="230" width="230" /> <media:content url="http://media.XYZInfoX.com/images/tex_trans_lawmans_230_16mar10_se.jpg" medium="image" isDefault="false" height="230" width="230" /> <media:content url="http://www.XYZInfoX.com/MediaAssets2/learninghello/dalet/se-exp-outlaws-part2-17mar2010.Mp3" type="audio/mpeg" medium="audio" isDefault="false" /> </media:group>* </item>

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  • Fast way to get a list of group members in Active Directory with C#

    - by Jeremy
    In a web app, we're looking to display a list of sam accounts for users that are a member of a certain group. Groups could have 500 or more members in many cases and we need the page to be responsive. With a group of about 500 members it takes 7-8 seconds to get a list of sam accounts for all members of the group. Are there faster ways? I know the Active Directory Management Console does it in under a second. I've tried a few methods: 1) PrincipalContext pcRoot = new PrincipalContext(ContextType.Domain) GroupPrincipal grp = GroupPrincipal.FindByIdentity(pcRoot, "MyGroup"); List<string> lst = grp.Members.Select(g => g.SamAccountName).ToList(); 2) PrincipalContext pcRoot = new PrincipalContext(ContextType.Domain) GroupPrincipal grp = GroupPrincipal.FindByIdentity(pcRoot, "MyGroup"); PrincipalSearchResult<Principal> lstMembers = grp.GetMembers(true); List<string> lst = new List<string>(); foreach (Principal member in lstMembers ) { if (member.StructuralObjectClass.Equals("user")) { lst.Add(member .SamAccountName); } } 3) PrincipalContext pcRoot = new PrincipalContext(ContextType.Domain) GroupPrincipal grp = GroupPrincipal.FindByIdentity(pcRoot, "MyGroup"); System.DirectoryServices.DirectoryEntry de = (System.DirectoryServices.DirectoryEntry)grp.GetUnderlyingObject(); List<string> lst = new List<string>(); foreach (string sDN in de.Properties["member"]) { System.DirectoryServices.DirectoryEntry deMember = new System.DirectoryServices.DirectoryEntry("LDAP://" + sDN); lst.Add(deMember.Properties["samAccountName"].Value.ToString()); }

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  • (rsErrorOpeningConnection) Could not obtain information about Windows NT group/user

    - by ChelleATL
    I am trying to deploy a report to the Reporting Services Server but keep running up against this error: An error occurred during client rendering. An error has occurred during report processing. (rsProcessingAborted) Cannot create a connection to data source 'dataSource1'. (rsErrorOpeningConnection) Could not obtain information about Windows NT group/user 'DOMAIN\useradmin', error code 0x5. Here’s my situation: Everything is being ran using DOMAIN\useradmin and the report is using a remote database. Reporting Services and SQL Server are both ran under DOMAIN\useradmin. DOMAIN\useradmin is a windows AD login and is part of the server machine Administrators group. My test report is using a data source model that in turn is using a data source that is connection to a database on a different SQL Server. The data source is using “Credentials stored securely in the report server” with the options “Use as Windows credentials when connecting to the data source” and “Impersonate the authenticated user after a connection has been made to the data source.” I am using the credentials of DOMAIN\useradmin that is the db owner of the remote database. DOMAIN\useradmin is assigned the roles, System Administrator, System User and Browser, Content Manager, My Reports, Publisher, Report Builder. So if everything is being run under an über AD account, why I am getting this Could not obtain information about Windows NT group/user 'DOMAIN\useradmin' error? Under normal circumstances , an AD login with Publisher permissions will developing reports using a datasource model created by DOMAIN\useradmin but using one of the remote database’s users which is mapped from yet another AD login. I ran the following statements and non errors were returned: use master go xp_grantlogin 'DOMAIN\useradmin' go xp_logininfo 'DOMAIN\useradmin' go

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  • How do I make a grouped select box grouped by a column for a given model in Formtastic for Rails?

    - by jklina
    In my Rails project I'm using Formtastic to manage my forms. I have a model, Tags, with a column, "group". The group column is just a simple hardcoded way to organize my tags. I will post my Tag model class so you can see how it's organized class Tag < ActiveRecord::Base class Group BRAND = 1 SEASON = 2 OCCASION = 3 CONDITION = 4 SUBCATEGORY = 5 end has_many :taggings, :dependent => :destroy has_many :plaggs, :through => :taggings has_many :monitorings, :as => :monitorizable validates_presence_of :name, :group validates_uniqueness_of :name, :case_sensitive => false def self.brands(options = {}) self.all({ :conditions => { :group => Group::BRAND } }.merge(options)) end def self.seasons(options = {}) self.all({ :conditions => { :group => Group::SEASON } }.merge(options)) end def self.occasions(options = {}) self.all({ :conditions => { :group => Group::OCCASION } }.merge(options)) end def self.conditions(options = {}) self.all({ :conditions => { :group => Group::CONDITION } }.merge(options)) end def self.subcategories(options = {}) self.all({ :conditions => { :group => Group::SUBCATEGORY } }.merge(options)) end def self.non_brands(options = {}) self.all({ :conditions => [ "`group` != ? AND `group` != ?", Tag::Group::SUBCATEGORY, Tag::Group::BRAND] }.merge(options)) end end My goal is to use Formtastic to provide a grouped multiselect box, grouped by the column, "group" with the tags that are returned from the non_brands method. I have tried the following: = f.input :tags, :required => false, :as => :select, :input_html => { :multiple => true }, :collection => tags, :selected => sel_tags, :group_by => :group, :prompt => false But I receive the following error: (undefined method `klass' for nil:NilClass) Any ideas where I'm going wrong? Thanks for looking :]

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  • how to apply group by on xslt elements

    - by Amit
    Hello All, I need to group the value based on some attribute and populate it. below mentioned is i/p xml and if you see there are 4 rows for Users and for id 2,4 Division is same i.e. HR while generating actual o/p I need to group by Division ... Any help ??? I/P XML <Users> <User id="2" name="ABC" Division="HR"/> <User id="3" name="xyz" Division="Admin"/> <User id="4" name="LMN" Division="Payroll"/> <User id="5" name="PQR" Division="HR"/> </Users> expected Result: I need to group the values based on Division and populate i.e. <AllUsers> <Division value="HR"> <User> <id>2</id> <name>ABC</name> </User> <User> <id>5</id> <name>PQR</name> </User> </Division> <Division value="ADMIN"> <User> <id>3</id> <name>XYZ</name> </User> </Division> <Division value="Payroll"> <User> <id>4</id> <name>LMN</name> </User> </Division> </AllUsers>

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  • Getting the first of a GROUP BY clause in SQL

    - by Michael Bleigh
    I'm trying to implement single-column regionalization for a Rails application and I'm running into some major headaches with a complex SQL need. For this system, a region can be represented by a country code (e.g. us) a continent code that is uppercase (e.g. NA) or it can be NULL indicating the "default" information. I need to group these items by some relevant information such as a foreign key (we'll call it external_id). Given a country and its continent, I need to be able to select only the most specific region available. So if records exist with the country code, I select them. If, not I want a records with the continent code. If not that, I want records with a NULL code so I can receive the default values. So far I've figured that I may be able to use a generated CASE statement to get an arbitrary sort order. Something like this: SELECT *, CASE region WHEN 'us' THEN 1 WHEN 'NA' THEN 2 ELSE 3 END AS region_sort FROM my_table WHERE region IN ('us','NA') OR region IS NULL GROUP BY external_id ORDER BY region_sort The problem is that without an aggregate function the actual data returned by the GROUP BY for a given row seems to be untameable. How can I massage this query to make it return only the first record of the region_sort ordered groups?

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  • Permutations distinct under given symmetry (Mathematica 8 group theory)

    - by Yaroslav Bulatov
    Given a list of integers like {2,1,1,0} I'd like to list all permutations of that list that are not equivalent under given group. For instance, using symmetry of the square, the result would be {{2, 1, 1, 0}, {2, 1, 0, 1}}. Approach below (Mathematica 8) generates all permutations, then weeds out the equivalent ones. I can't use it because I can't afford to generate all permutations, is there a more efficient way? Update: actually, the bottleneck is in DeleteCases. The following list {2, 2, 2, 2, 2, 2, 2, 1, 1, 1, 1, 1, 1, 0, 0, 0} has about a million permutations and takes 0.1 seconds to compute. Apparently there are supposed to be 1292 orderings after removing symmetries, but my approach doesn't finish in 10 minutes removeEquivalent[{}] := {}; removeEquivalent[list_] := ( Sow[First[list]]; equivalents = Permute[First[list], #] & /@ GroupElements[group]; DeleteCases[list, Alternatives @@ equivalents] ); nonequivalentPermutations[list_] := ( reaped = Reap@FixedPoint[removeEquivalent, Permutations@list]; reaped[[2, 1]] ); group = DihedralGroup[4]; nonequivalentPermutations[{2, 1, 1, 0}]

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  • West Palm Beach Developers&rsquo; Group Celebrates its Fifth Anniversary as a Member of INETA

    - by Sam Abraham
    Earlier this week marked our fifth anniversary as an INETA group, a fact that we had forgotten but thankfully INETA remembered. In celebrating our membership, INETA sent us a certificate recognizing our membership which we will be sharing with our members at our upcoming meeting. It‘s been a great two-year tenure for me as group co-coordinator working with Venkat Subramanian who had been involved with the group since its inception. Moving into the future we hope to grow both group membership and leadership. We continue to strive to bring added value to our membership which can only happen with your ideas, feedback and involvement in our community-driven group. Our next almost sold-out meeting will be taking place on 8/28/2012 6:30PM (Register at: http://www.fladotnet.com/Reg.aspx?EventID=607) . Will Strohl, DotNetNuke’s Technical Evangelist will be presenting to us an overview on getting started with DNN’s latest 6.2 version all while taking us on a deep dive into its built-in social networking integration features. There is still time to register, but don’t procrastinate! Our September meeting will feature Jonas Stawski, Microsoft MVP sharing with us on SignalR while October will bring us the much anticipated visit by our Microsoft Developer Evangelist Joe Healy who will be talking to us about the latest with Windows 8. Joe will be also presenting in Miami the next day after our event in case you miss his West Palm appearance. We look forward to meeting you at our upcoming meetings. All the best --Sam Abraham

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  • Post SQL 2008 R2 Launch Thurs 15th London - UK SQL Server User Group is having a Social Event @ the

    - by tonyrogerson
    The UK SQL Server User Group is organising a Social event for SQL and SQL Server professionals, the event will be held after the SQL Server 2008 R2 launch event and is a short walk from that venue. See site for more information: http://sqlserverfaq.com/events/222/Social-for-SQL-and-SQL-Server-professionals-SQL-quiz-meet-your-peers-ask-the-group-Q-A.aspx We are putting some light bites on, if you are coming then do let us know through the site. Neil Hambly who is the London UK SQL Server User Group...(read more)

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  • Queyring container with Linq + group by ?

    - by Prix
    public class ItemList { public int GuID { get; set; } public int ItemID { get; set; } public string Name { get; set; } public entityType Status { get; set; } public class Waypoint { public int Zone { get; set; } public int SubID { get; set; } public int Heading { get; set; } public float PosX { get; set; } public float PosY { get; set; } public float PosZ { get; set; } } public List<Waypoint> Routes = new List<Waypoint>(); } I have a list of items using the above class and now I need to group it by ItemID and join the first entry of Routes of each iqual ItemID. So for example, let's say on my list I have: GUID ItemID ListOfRoutes 1 23 first entry only 2 23 first entry only 3 23 first entry only 4 23 first entry only 5 23 first entry only 6 23 first entry only 7 23 first entry only Means I have to group entries 1 to 7 as 1 Item with all the Routes entries. So I would have one ItemID 23 with 7 Routes on it where those routes are the first element of that given GUID Routes List. My question is if it is possible using LINQ to make a statment to do something like that this: var query = from ItemList entry in myList where status.Contains(entry.Status) group entry by entry.ItemID into result select new { items = new { ID = entry.ItemID, Name = entry.Name }, routes = from ItemList m in entry group m.Routes.FirstOrDefault() by n.NpcID into m2 }; So basicly I would have list of unique IDS information with a inner list of all the first entry of each GUID route that had the same ItemID. <<< UPDATE: This would be an example of public List<ItemList> myList = new List<ItemList>(); data: GUID ItemID ListOfRoutes 1 20 Routes[1] 2 20 Routes[2] 3 20 Routes[3] 4 20 Routes[4] 5 20 Routes[5] 6 55 Routes[6] 7 55 Routes[7] 8 55 Routes[8] 9 1 Routes[9] 10 1 Routes[10] As you can see GUID is unique, ItemID can reapeat it self. Each GUID has a Routes list and all routes list have a minimum of 1 entry and above. Routes example. Routes[1] have: Entry Zone SubID Heading PosX PosY PosZ 1 1200 0 100 1029.32 837.21 29.10 2 1200 0 120 1129.32 537.21 29.10 3 1200 0 180 1229.32 137.21 29.10 4 1200 0 360 1329.32 437.21 29.10 5 1200 0 100 1429.32 637.21 29.10 Routes[2] have: Entry Zone SubID Heading PosX PosY PosZ 1 100 0 10 129.32 437.21 29.10 So what I want to do is a list of all entries I have on myList grouped by ItemID maintainning the fields ItemID and Name ... and a new field or item that will have all the first elements of Routes of those GUIDs. For example ItemID 20 would produce the follow result: ItemID, Name, ListOfRoutes This ItemID ListOfRoutes would contain Routes[1] first entry: Entry Zone SubID Heading PosX PosY PosZ 1 1200 0 100 1029.32 837.21 29.10 Routes[2] first entry: Entry Zone SubID Heading PosX PosY PosZ 1 100 0 10 129.32 437.21 29.10 Routes[3], Routes[4], Routes[5] first entries. Example of how myList is feeded: ItemList newItem = new ItemList(); newItem.GUID = GUID; newItem.ItemID = ItemID; newItem.Name = Name; newItem.Status = Status; // Item location ItemList.Waypoint itemLocation = new ItemList.Waypoint(); itemLocation.SubID = SubID; itemLocation.Zone = Zone; itemLocation.Heading = convertHeading(Heading); itemLocation.PosX = PosX; itemLocation.PosY = PosY; itemLocation.PosZ = PosZ; itemLocation.Rest = Rest; newItem.Routes.Add(itemLocation); myList.Add(newItem);

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  • Efficient representation of Hierarchies in Hibernate.

    - by Alison G
    I'm having some trouble representing an object hierarchy in Hibernate. I've searched around, and haven't managed to find any examples doing this or similar - you have my apologies if this is a common question. I have two types which I'd like to persist using Hibernate: Groups and Items. * Groups are identified uniquely by a combination of their name and their parent. * The groups are arranged in a number of trees, such that every Group has zero or one parent Group. * Each Item can be a member of zero or more Groups. Ideally, I'd like a bi-directional relationship allowing me to get: * all Groups that an Item is a member of * all Items that are a member of a particular Group or its descendants. I also need to be able to traverse the Group tree from the top in order to display it on the UI. The basic object structure would ideally look like this: class Group { ... /** @return all items in this group and its descendants */ Set<Item> getAllItems() { ... } /** @return all direct children of this group */ Set<Group> getChildren() { ... } ... } class Item { ... /** @return all groups that this Item is a direct member of */ Set<Group> getGroups() { ... } ... } Originally, I had just made a simple bi-directional many-to-many relationship between Items and Groups, such that fetching all items in a group hierarchy required recursion down the tree, and fetching groups for an Item was a simple getter, i.e.: class Group { ... private Set<Item> items; private Set<Group> children; ... /** @return all items in this group and its descendants */ Set<Item> getAllItems() { Set<Item> allItems = new HashSet<Item>(); allItems.addAll(this.items); for(Group child : this.getChildren()) { allItems.addAll(child.getAllItems()); } return allItems; } /** @return all direct children of this group */ Set<Group> getChildren() { return this.children; } ... } class Item { ... private Set<Group> groups; /** @return all groups that this Item is a direct member of */ Set<Group> getGroups() { return this.groups; } ... } However, this resulted in multiple database requests to fetch the Items in a Group with many descendants, or for retrieving the entire Group tree to display in the UI. This seems very inefficient, especially with deeper, larger group trees. Is there a better or standard way of representing this relationship in Hibernate? Am I doing anything obviously wrong or stupid? My only other thought so far was this: Replace the group's id, parent and name fields with a unique "path" String which specifies the whole ancestry of a group, e.g.: /rootGroup /rootGroup/aChild /rootGroup/aChild/aGrandChild The join table between Groups and Items would then contain group_path and item_id. This immediately solves the two issues I was suffering previously: 1. The entire group hierarchy can be fetched from the database in a single query and reconstructed in-memory. 2. To retrieve all Items in a group or its descendants, we can select from group_item where group_path='N' or group_path like 'N/%' However, this seems to defeat the point of using Hibernate. All thoughts welcome!

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  • Facebook Invalid OAuth access token signature trying to post an attachment to group wall from PHP

    - by Volodymyr B
    I am an administrator (manager role) of a Facebook Group. I created an app, and stored its id and secret. I want my app to be able to post something on the Facebook group's feed. But when I attempt to post, I get the error 190 Invalid OAuth access token signature, even though I able to successfully obtain the access_token with publish_stream and offline_access scopes. It has the form of NNNNNNNNNNNNNNN|XXXXXXXXXXXXXXXXXXXXXXXXXXX, where N is a number (15) and X is a letter or a number (27). What should I do more to get this accomplished? Here is the code I am using: public static function postToFB($message, $image, $link) { //Get App Token $token = self::getFacebookToken(); // Create FB Object Instance $facebook = new Facebook(array( 'appId' => self::fb_appid, 'secret' => self::fb_secret, 'cookie' => true )); //$token = $facebook->getAccessToken(); //Try to Publish on wall or catch the Facebook exception try { $attachment = array('access_token' => $token, 'message' => $message, 'picture' => $image, 'link' => $link, //'name' => '', //'caption' => '', 'description' => 'More...', //'actions' => array(array('name' => 'Action Text', 'link' => 'http://apps.facebook.com/xxxxxx/')) ); $result = $facebook->api('/'.self::fb_groupid.'/feed/', 'post', $attachment); } catch (FacebookApiException $e) { //If the post is not published, print error details echo '<pre>'; print_r($e); echo '</pre>'; } } Code which returns the token //Function to Get Access Token public static function getFacebookToken($appid = self::fb_appid, $appsecret = self::fb_secret) { $args = array( 'grant_type' => 'client_credentials', 'client_id' => $appid, 'client_secret' => $appsecret, 'redirect_uri' => 'https://www.facebook.com/connect/login_success.html', 'scope' => 'publish_stream,offline_access' ); $ch = curl_init(); $url = 'https://graph.facebook.com/oauth/access_token'; curl_setopt($ch, CURLOPT_URL, $url); curl_setopt($ch, CURLOPT_HEADER, false); curl_setopt($ch, CURLOPT_RETURNTRANSFER, true); curl_setopt($ch, CURLOPT_POST, true); curl_setopt($ch, CURLOPT_POSTFIELDS, $args); try { $data = curl_exec($ch); } catch (Exception $exc) { error_log($exc->getMessage()); } return json_encode($data); } If I uncomment $token = $facebook->getAccessToken(); in the posting code, it gives me yet another error (#200) The user hasn't authorized the application to perform this action. The token I get using developers.facebook.com/tools/explorer/ is of another form, much longer and with it I am able to post to the group page feed. How do I do it without copy/paste from Graph API Explorer and how do I post as a group instead of posting as a user? Thanks.

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  • Listing issue, GROUP mysql

    - by SethCodes
    Here is a mock-up example of Mysql table: | ID | Country | City | ________________________________ | 1 | Sweden | Stockholm | | 2 | Sweden | Stockholm | | 3 | Sweden | Lund | | 4 | Sweden | Lund | | 5 | Germany | Berlin | | 6 | Germany | Berlin | | 7 | Germany | Hamburg | | 8 | Germany | Hamburg | Notice how both rows Country and city have repeated values inside them. Using GROUP BY country, city in my PDO query, the values will not repeat while in loop. Here is PDO for this: $query = "SELECT id, city, country FROM table GROUP BY country, city"; $stmt = $db->query($query); while($row = $stmt->fetch(PDO::FETCH_ASSOC)) : The above code will result in an output like this (some editing in-between). GROUP BY works but the country repeats: Sweden - Stockholm Sweden - Lund Germany - Berlin Germany - Hamburg Using bootstrap collapse and above code, I separate the country from the city with a simple drop down collopase. Here is code: <li> <a data-toggle="collapse" data-target="#<?= $row['id']; ?>" href="search.php?country=<?= $row['country']; ?>"> <?= $row['country']; ?> </a> <div id ="<?= $row['id']; ?>" class="collapse in"> //collapse div here <a href="search.php?city=<?= $row['city']; ?>"> <?= $row['city']; ?><br></a> </div> //end </li> It then looks something like this (once collapse is initiated): Sweden > Stockholm Sweden > Lund Germany >Berlin Germany >Hamburg Here is where I face the problem. The above lists the values Sweden and Germany 2 times. I want Sweden and Germany to only list one time, and the cities listed below, so the desired look is to be this: Sweden // Lists one time > Stockholm > Lund Germany // Lists one time >Berlin >Hamburg I have tried using DISTINCT, GROUP_CONTACT and other methods, yet none get my desired output (above). Suggestions? Below is my current full code in action: <? $query = "SELECT id, city, country FROM table GROUP BY country, city"; $stmt = $db->query($query); while($row = $stmt->fetch(PDO::FETCH_ASSOC)) : ?> <li> <a data-toggle="collapse" data-target="#<?= $row['id']; ?>" href="search.php?country=<?= $row['country']; ?>"> <?= $row['country']; ?> </a> <div id ="<?= $row['id']; ?>" class="collapse in"> //collapse div here <a href="search.php?city=<?= $row['city']; ?>"> <?= $row['city']; ?><br></a> </div> //end </li> <? endwhile ?>

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  • SQL - Count grouped entries and then get the max values grouped by date

    - by Marcus
    hello, I am out of any logic how to write the right sql statment. I've got a sqlite table holding every played track in a row with played date/time Now I will count the plays of all artists, grouped by day and then find the artist with the max playcount per day. I used this Query SELECT COUNT(ARTISTID) AS artistcount, ARTIST AS artistname,strftime('%Y-%m-%d', playtime) AS day_played FROM playcount GROUP BY artistname to get this result "93"|"The Skygreen Leopards"|"2010-06-16" "2" |"Arcade Fire" |"2010-06-15" "2" |"Dead Kennedys" |"2010-06-15" "2" |"Wolf People" |"2010-06-15" "3" |"16 Horsepower" |"2010-06-15" "3" |"Alela Diane" |"2010-06-15" "46"|"Motorama" |"2010-06-15" "1" |"Ariel Pink's Haunted" |"2010-06-14" I tried then to query this virtual table but I always get false results in artistname. SELECT MAX(artistcount), artistname , day_played FROM ( SELECT COUNT(ARTISTID) AS artistcount, ARTIST AS artistname,strftime('%Y-%m-%d', playtime) AS day_played FROM playcount GROUP BY artistname ) GROUP BY strftime('%Y-%m-%d',day_played) result in this "93"|"lilium" |"2010-06-16" "46"|"Wolf People"|"2010-06-15" "30"|"of Montreal"|"2010-06-14" but the artist name is false. I think through the grouping by day, it just use the last artist, or so. I tested stuff like INNER JOIN or GROUP BY ... HAVING in trial and error, I read examples of similar issues but always get lost in columnnames and stuff (I am a bit burned out) I hope someone can give me a hint. thanks m

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  • On Windows how can I prevent login until a software package has been installed?

    - by Phil Hannent
    I have an MSI which is configured for machine level installation because it is a device driver. I can deploy it via Active Directory and Group Policy just fine. However on a newly booted machine a user can login before the installation has a chance to complete and I get an warning in the event log saying it couldn't complete and will be tried at next reboot. How can I make the login screen wait for the installation to be completed?

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  • What are the side-effects of disabling the old Lan Manager hash?

    - by Bigbio2002
    All of the computers in our domain are running Windows XP/Server 2003 and above (with one exception, a Win2Ksp4 server, which is not a domain controller). I intend to disable the LM hashes via group policy as indicated in KB299656, and want to ensure that there won't be any unforseen problems or side-effects. Does anyone have experience with performing this change? Are there any caveats that I should keep in mind?

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  • Complete Active Directory redesign and GPO application

    - by Wolfgang Kuehne
    after much testing and hundreds of tries and hours invested I decided to consult you experts here. Overview: I want to apply some GPO to our users which will add some specific site to the Trusted Sites in Internet Explorer settings for all users. However, the more I try the more confusing the results become. The GPO is either applied to one group of users, or to another one. Finally, I came to the conclusion that this weird behavior is cause rather by the poor organization in Users and Groups in Active Directory. As such I want to kick the problem from the root: Redesign the Active Directory Users and Groups. Scenario: There is one Domain Controller, and we use Terminal Services (so there is a Terminal Server as well). Users usually log on to the Terminal Server using Remote Desktop to perform their daily tasks. I would classify the users in the following way: IT: Admins, Software Development Business: Administration, Management The current structure of the Active Directory Users and Groups is a result of the previous IT management. The company has used Small Business Server which has created multiple default user groups and containers. Unfortunately, the guys working before me have do no documentation at all. Now, as I inherit this structure I am in the no mans land. No idea which direction to head first. As you can see, the Active Directory User and Groups have become a bit confusing. There is no SBS anymore, but when migrating from SBS to the current Windows Server 2008 R2 environment the guys before me have simply copied the same structure. The real question: Where should I start cleaning from, ensuring that I won't break totally the current infrastructure? What is a nice organization for the scenario that I have explained above? Possible useful info for the current structure: Computers folder contains Terminal Services Computers user group Members: TerminalServer computer located at Server -> Terminalserver OU Member of: NONE Foreign Security Principals : EMPTY Managed Service Accounts : EMPTY Microsoft Exchange Security Groups : not sure if needed, our emails are administered by external service provider Distribution Groups : not sure if needed Security Groups : there are couple of groups which are needed SBS users : contains all the users Terminalserver : contains only the TerminalServer machine

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  • getUserPrincipal() in JCIFS / Lan-Manager authentitation level setting in Windows 2k8

    - by Chris
    I have to find out in which exact format JCIFS stores the user principal in the "getUserPrincipal()" property. Therefor i created a test Environment like this: Windows Server 2008 Domain Controller Domain named "MYDOMAIN" Many Testusers in Active Directory Tomcat Application Server with my Web Application (which simply reads the user Principal and displays its values). The user should be logged in to the web-application with SSO therefor i need the format that jcifs is using to store the user. (For example user@MYDOMAIN or MYDOMAIN\user...) I tested the Authentication with other SSO frameworks with Kerberos Method and it works as expected. I'm now trying to use SSO through the NTLMHttpFilter of JCIFS. When i try to login i get the following error message: jcifs.smb.SmbException: The parameter is incorrect. jcifs.smb.SmbTransport.checkStatus(SmbTransport.java:541) jcifs.smb.SmbTransport.send(SmbTransport.java:641) jcifs.smb.SmbSession.sessionSetup(SmbSession.java:322) jcifs.smb.SmbSession.send(SmbSession.java:224) jcifs.smb.SmbTree.treeConnect(SmbTree.java:176) jcifs.smb.SmbSession.logon(SmbSession.java:153) jcifs.smb.SmbSession.logon(SmbSession.java:146) jcifs.http.NtlmHttpFilter.negotiate(NtlmHttpFilter.java:189) jcifs.http.NtlmHttpFilter.doFilter(NtlmHttpFilter.java:121) Regarding to the documentation i'm using to configure this, this is a know issue with the Group policy. It is stated there, that i have to change the Group policy "Networkaccess: lan-manager authentication level" to respond to NTLMv1 request. I have done this, but it's still not working. So what i also have to configure is the same policy on the client computer. I have to change the policy, so that the client computer sends NTLMv1. But it is always sending NTLMv2 tokens. The problem now is that i'm somehow not able to change this setting. (I already was before) because the dropdown box to choose the authentication method is "greyed out". edit: just to make this clear, this dialog is on the client-side in the "local-security policies" As you can see from this screenshot, the chosen method is "Only send NTLMv2 responses" which is the wrong setting and i'm pretty sure that this is causing the error above. My question is now, why can't i change this setting? Why is it greyd out?

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  • Is there a way to apply a GPO to all but selective users? (SBS 2008)

    - by CandyCo
    I've created a GPO in SBS 2008 that deploys and updates software. Unfortunately, one of our VPN users lives out in the sticks and has severe latency, so the start up processes and updates time out and take an awfully long time, if they ever complete at all. I'd like to apply this GPO to all auth'd users except for him, without having to create a new custom user group. Any thoughts?

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