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  • HTML5 Search Input: No Background Image in Chrome?

    - by Jason
    I have been pulling my hair out trying to get Chrome to style my search input with a background image. Firefox has no problem, but I fear it's because it treats the input as a regular text input. Is this simply not possible? Try this as a demo: <input type="search" /> ?input[type="search"] { background: transparent url(http://google.com/intl/en_ALL/images/srpr/logo1w.png) no-repeat 0 0; }?????? If it worked correctly, it should put Google's logo (or part of it) as the background image for the "Search" input. But as you will see when you look at this in Chrome, it DOES NOT WORK. Any ideas, or is this just one of HTML5's quirks? :\

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  • Objectify - Retrieve subclass instances with superclass query

    - by Deviling Master
    for a project i'm making, i'm using Objectify and Google AppEngine I'm quoting and old message from Google Groups, but the problem i have is the same: Here's the problem I'm trying to solve: I'd like to persist instances of several subclasses of one superclass to the datastore, and then retrieve them by querying for that superclass. (For example, a query for Game would return instances of Chess and Backgammon). Is there any way to accomplish this using Objectify? Because the thing i want is the same, but the topic does not provides yet an answer (it's 3 years old), I moved here with the same question. From 2010 to now, this question has been solved? Thanks Bye

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  • UnicodeDecodeError from a GET-parameter in webapp2

    - by Aneon
    I'm getting a UnicodeDecodeError when recieving a GET-parameter from webapp2 that contains unicode characters, and then using it to do a NDB query. I get the same error message when manually running a unicode() on the parameter in the handler, so there either seems to be a problem in webapp2's URL routing or I've missed something. Preferably, all GET-parameters should be converted to unicode before getting passed into the handler so I don't need to do manual conversions in all of my handlers. I actually think it's worked before in an earlier version. The full error message read: UnicodeDecodeError: 'ascii' codec can't decode byte 0xc3 in position 1: ordinal not in range(128) The GET-parameter contains the following string: göteborg. It looks fine when I raise an Exception on it, but gives me an error when I (or NDB) use unicode() on it. EDIT: In NDB, it fails on the following code: File "C:\Program Files (x86)\Google\google_appengine\google\appengine\api\datastore_types.py", line 1562, in PackString pbvalue.set_stringvalue(unicode(value).encode('utf-8')) Thanks.

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  • How can I modify this javascript code?

    - by TIMEX
    I'm using the Google Local Search API and Google Maps API. See here: http://geodit.com:8000/test You can perform a search, and then the javascript fills the Map, as well as the results next to the map. I think this function fills the results next to the map: function OnLocalSearch() My question is: how can I change the results displayed? Right now, by default it shows the Name of the business and the address. How can I disable the business link? And then add more text to each search result?

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  • How would I best make this SEO_able?

    - by alex
    I have a search engine that searches albums. For each music album, I have a page. So, the work flow goes like this: People search for music titles The search engine displays a list of albums. People click on an album to go to a details page. I want google to index my front page and the details page. I want the details page to be highly ranked. How can I build a sitemap for this? By the way, I have about 5 million albums (but I want the top 1000 ones to be highly ranked on google)

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  • Alternate value of "FeedUri" for contacts entry .

    - by Preeti
    Hi, I am trying to create a contact on Google Apps. I am using Admin credential to create contact in other users in same domain. Problem i am facing is when i use: Uri feedUri = new Uri(ContactsQuery.CreateContactsUri("default")); ContactEntry createdEntry = (ContactEntry)service.Insert(feedUri, ContactEntry[0]); It is adding contact in Admin account but i a want to put contact in other user's account. How can i do that? I am using Google Apps API version 2 for .NET. Thanx

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  • Obtaining Android Public Map API Key

    - by TheHighLifeSon
    I have been trying to obtain a public map api key for my Android app. However the public key that I receive from Google does not work. I have been using the following steps: Obtaining Release Public Map API Key 1.Obtain Private Key: Use Export of Eclipse to sign release application and create new keystore 2.Obtain MD5 certificate: using alias and keystore set up use keytool in Java directory: keytool -list -alias poly_alias -keystore copy MD5 certificate 3.Obtain API Map Key: Visit http://code.google.com/android/maps-api-signup.html and enter MD5 certificate copy key 4.Use New Map API Key: insert new map key for string in strings.xml for string mapApiKey Does anyone have any suggestions on what I am doing wrong?

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  • Content API for Shopping Office Hours - June 12, 2012

    Content API for Shopping Office Hours - June 12, 2012 Hangout discussing Product Listing Ads (PLAs) and the Google Affiliate Network (GAN) with guest Mark Coppin (GAN) and Claire Hugo (PLAs) of Google. In the Hangout, we reference the video "How to create a new Product Listing Ads campaign" (www.youtube.com which can be found in the Getting Starting page on the Shopping/Ads integration site (www.google.com Also, check out the GAN site to learn more: www.google.com From: GoogleDevelopers Views: 703 6 ratings Time: 31:23 More in Science & Technology

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  • GWT with spring security not working on app engine live server.

    - by bedanand
    I configured gwt with spring and spring security that works fine on local development server on google app engine. I deployed to the appspot but there it shows critical error when i see on the log. and on the browser side shows 500 server error. log error Uncaught exception from servlet javax.servlet.UnavailableException: Initialization failed. at com.google.apphosting.runtime.jetty.AppVersionHandlerMap.createHandler(AppVersionHandlerMap.java:200) at com.google.apphosting.runtime.jetty.AppVersionHandlerMap.getHandler(AppVersionHandlerMap.java:168) at com.google.apphosting.runtime.jetty.JettyServletEngineAdapter.serviceRequest(JettyServletEngineAdapter.java:123) at com.google.apphosting.runtime.JavaRuntime.handleRequest(JavaRuntime.java:243) at com.google.apphosting.base.RuntimePb$EvaluationRuntime$6.handleBlockingRequest(RuntimePb.java:5838) at com.google.apphosting.base.RuntimePb$EvaluationRuntime$6.handleBlockingRequest(RuntimePb.java:5836) at com.google.net.rpc.impl.BlockingApplicationHandler.handleRequest(BlockingApplicationHandler.java:24) at com.google.net.rpc.impl.RpcUtil.runRpcInApplication(RpcUtil.java:398) at com.google.net.rpc.impl.Server$2.run(Server.java:852) at com.google.tracing.LocalTraceSpanRunnable.run(LocalTraceSpanRunnable.java:56) at com.google.tracing.LocalTraceSpanBuilder.internalContinueSpan(LocalTraceSpanBuilder.java:576) at com.google.net.rpc.impl.Server.startRpc(Server.java:807) at com.google.net.rpc.impl.Server.processRequest(Server.java:369) at com.google.net.rpc.impl.ServerConnection.messageReceived(ServerConnection.java:442) at com.google.net.rpc.impl.RpcConnection.parseMessages(RpcConnection.java:319) at com.google.net.rpc.impl.RpcConnection.dataReceived(RpcConnection.java:290) at com.google.net.async.Connection.handleReadEvent(Connection.java:474) at com.google.net.async.EventDispatcher.processNetworkEvents(EventDispatcher.java:831) at com.google.net.async.EventDispatcher.internalLoop(EventDispatcher.java:207) at com.google.net.async.EventDispatcher.loop(EventDispatcher.java:103) at com.google.net.rpc.RpcService.runUntilServerShutdown(RpcService.java:251) at com.google.apphosting.runtime.JavaRuntime$RpcRunnable.run(JavaRuntime.java:404) at java.lang.Thread.run(Unknown Source) web.xml <web-app> <servlet> <servlet-name>dispatcher</servlet-name> <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class> <load-on-startup>1</load-on-startup> </servlet> <servlet-mapping> <servlet-name>dispatcher</servlet-name> <url-pattern>*.rpc</url-pattern> </servlet-mapping> <filter> <filter-name>springSecurityFilterChain</filter-name> <filter-class>org.springframework.web.filter.DelegatingFilterProxy</filter-class> </filter> <filter-mapping> <filter-name>springSecurityFilterChain</filter-name> <url-pattern>/*</url-pattern> </filter-mapping> <listener> <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class> </listener> <!-- Default page to serve --> <welcome-file-list> <welcome-file>PushUrl.html</welcome-file> </welcome-file-list> </web-app> appengine-web.xml <application>pushurl</application> <version>1</version> <!-- Configure java.util.logging --> <system-properties> <property name="java.util.logging.config.file" value="WEB-INF/logging.properties"/> </system-properties> <sessions-enabled>true</sessions-enabled> applicationContext.xml <security:http auto-config="true"> <security:intercept-url pattern="/**/users.rpc" access="ROLE_USER"/> <security:intercept-url pattern="/**/categories.rpc" access="ROLE_ADMIN"/> <security:intercept-url pattern="/css/**" filters="none"/> <security:intercept-url pattern="/login.jsp*" filters="none"/> <security:form-login login-page='/login.jsp' /> </security:http> <security:authentication-manager> <security:authentication-provider> <security:user-service> <security:user name="jimi" password="jimi" authorities="ROLE_USER, ROLE_ADMIN" /> <security:user name="bob" password="bob" authorities="ROLE_USER" /> </security:user-service> </security:authentication-provider> </security:authentication-manager> dispatcher-servlet.xml <bean class="org.springframework.web.servlet.handler.SimpleUrlHandlerMapping"> <property name="mappings"> <value> /**/users.rpc=userService /**/categories.rpc=categoryService </value> </property> </bean> <bean id="userController" class="com.beda.pushurl.server.GwtRpcController"> <property name="remoteService" ref="userService"> </property> </bean> <bean id="userService" class="com.beda.pushurl.server.UserServiceImpl" > <property name="userDAO" ref="myUserDAO"></property> </bean> <bean id="categoryService" class="com.beda.pushurl.server.CategoryServiceImpl"> <property name="categoryDAO" ref="myCategoryDAO"></property> </bean> <bean id="myUserDAO" class="com.beda.pushurl.server.dao.UserDAOImpl"> </bean> <bean id="myCategoryDAO" class="com.beda.pushurl.server.dao.CategoryDAOImpl"> </bean>

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  • org.hibernate.NonUniqueObjectException Within GWT application using hibernate through gilead

    - by molleman
    Hello Guys, i am working on a project for college that uses GWT,Hibernate and Gilead. Basically for the moment users should be able to add friends and remove them. also a user can see if his or her friends are online or not. my trouble is that when i add a friend that is already related to another friend i get this error org.hibernate.NonUniqueObjectException: a different object with the same identifier value was already associated with the session: [com.example.client.YFUser#4] i have a service class public class TestServiceImpl extends PersistentRemoteService implements TestService { this is my service class for my gwt application. my toruble is here with my implmentation class of my serivce in this method that is called when a user presses add friend button on the client-side public void addYFUserFriend(String userName){ //this retrieves the current user YFUser user = (YFUser)getSession().getAttribute(SESSION_USER); Session session = com.example.server.HibernateUtil.getSessionFactory().getCurrentSession(); session.beginTransaction(); YFUser friend = (YFUser) session.createQuery("select u FROM YFUser u where u.username = :username").setParameter("username", userName).uniqueResult(); System.out.println("user " + friend.getUsername() + " Found"); user.getFriends().add(friend); friend.getBefriended().add(user); session.update(user); session.update(friend); session.getTransaction().commit(); } a scenerio : user1 adds user2 as a friend. this works fine. then user3 adds user2 and the exeception is thrown. any ideas why and where my logic is going wrong Ok so i have changed my code, and i have removed all the getCurrentASession() calls and replaced with openSession() call which are closed at the appropiate point, now the error i am getting is com.google.gwt.user.server.rpc.UnexpectedException: Service method 'public abstract void com.example.client.TestService.addYFUserFriend(java.lang.String)' threw an unexpected exception: org.hibernate.NonUniqueResultException: query did not return a unique result: 3

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  • What Can I Do To One Of My Team Number (Good Friend As Well) Who Lost His Passion.

    - by skyflyer
    It seems this question is not program related, but there are lot of similar questions. So please bear with me! By the way, I am programmer and my team is also charging a software project. And SO is the only place which solved me lot of thorny troubles!THANK YOU GUYS! I joined my company with him years ago. At that time he was quite passionate on his job which is a front-end development. He gave us lot of useful suggestions concerning his work like design. And I believed he was a smart guy. I believe he still is smart too by the way. One years later, however, he seemed lost his passion and fooling around every day, did not care about his work any more and produced poorwork. Even worse he literally stopped learning new skills and honing his work related skills. For me it is horrible, we got to keep abreast with new technology development, otherwise we will be throw out. Since we were just coworkers, I did not care about it too much except mentioned my thoughts several times. But last month, we resembled a new group and assigned very important project. And I am the team leader, sadly! My boss gave me lot of support and expectation as well. I did a pretty good job before and I am very optimism to our future. But as a team, if my team does not work hard, we will be doomed to failure no matter how hard I work and push. In order to revitalize his passion, I tried couple of ways like talking to him about my concern and my boss's angry. I offered his new task which is quite new to him. I even persuaded my boss to give him new incentive package. But all of them knocked wall. His reaction was just he did not care. Even worse he did not want to talk about his situation. I want to be hard on him, but since we are friends and coworkers, I really can not see it will work. Even it works, I can not so quickly change my self from friend and coworker into manager. As a novice in management, I am really overwhelmed! I do not want get him fired, we are friends and I do not see him fired as my team number. What can I do? Thank you guys!

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  • sudo apt-get update does not work for 12.10

    - by Brian Hawi
    hey i recently installed ubuntu 12.10 but the software center does not work i tried the sudo apt-get update because that worked when i was using ubuntu 11.04.... these are the errors hawi@hawi-HP-G62-Notebook-PC:~$ sudo apt-get update [sudo] password for hawi: Err http:ke.archive.ubuntu.com quantal InRelease Err http:ke.archive.ubuntu.com quantal-updates InRelease Err http:ke.archive.ubuntu.com quantal-backports InRelease Err http:ke.archive.ubuntu.com quantal Release.gpg Unable to connect to ke.archive.ubuntu.com:http: Err http:ke.archive.ubuntu.com quantal-updates Release.gpg Unable to connect to ke.archive.ubuntu.com:http: Err http:ke.archive.ubuntu.com quantal-backports Release.gpg Unable to connect to ke.archive.ubuntu.com:http: Err http:security.ubuntu.com quantal-security InRelease Err http:security.ubuntu.com quantal-security Release.gpg Unable to connect to security.ubuntu.com:http: [IP: 91.189.92.190 80] Err http:extras.ubuntu.com quantal InRelease Err http:extras.ubuntu.com quantal Release.gpg Unable to connect to extras.ubuntu.com:http: Reading package lists... Done W: Failed to fetch http:ke.archive.ubuntu.com/ubuntu/dists/quantal/InRelease W: Failed to fetch http:ke.archive.ubuntu.com/ubuntu/dists/quantal-updates/InRelease W: Failed to fetch http:ke.archive.ubuntu.com/ubuntu/dists/quantal-backports/InRelease W: Failed to fetch http:security.ubuntu.com/ubuntu/dists/quantal-security/InRelease W: Failed to fetch http:extras.ubuntu.com/ubuntu/dists/quantal/InRelease W: Failed to fetch http:ke.archive.ubuntu.com/ubuntu/dists/quantal/Release.gpg Unable to connect to ke.archive.ubuntu.com:http: W: Failed to fetch http:ke.archive.ubuntu.com/ubuntu/dists/quantal-updates/Release.gpg Unable to connect to ke.archive.ubuntu.com:http: W: Failed to fetch http:ke.archive.ubuntu.com/ubuntu/dists/quantal-backports/Release.gpg Unable to connect to ke.archive.ubuntu.com:http: W: Failed to fetch http:security.ubuntu.com/ubuntu/dists/quantal-security/Release.gpg Unable to connect to security.ubuntu.com:http: [IP: 91.189.92.190 80] W: Failed to fetch http:extras.ubuntu.com/ubuntu/dists/quantal/Release.gpg Unable to connect to extras.ubuntu.com:http: W: Some index files failed to download. They have been ignored, or old ones used instead. (note i have removed the // after http because the site does not allow me to post more than two links) what could be the issue?

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  • How do I connect to Ubuntu One after changing the password?

    - by rumtscho
    I changed my password for Ubuntu One using the Web interface, and added a new computer. Since then, the old computer does not synchronize with Ubuntu One. It doesn't show any error messages or such, but files uploaded from the web interface or changed on the newly added computer don't appear/change on the old computer. I guess that it can't connect because it is still using the old password. The problem is that I can't find an interface to change the password the client is using to connect to the service. The "manage account" option opens the Web interface. I looked into the keyring, and found the key for Ubuntu One, but there I only see an encrypted version of the password, so I can't change it there. So what is the correct way to tell my client that my account password has changed? Edit this is what I see when I open Preferences -- Ubuntu One. Is there something wrong with it? It also stubbornly insists that it has successfully synchronized. But the files I have added from other computers are not in my Ubuntu One folder.

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  • So now Google has said no to old browsers when can the rest of us follow suit?

    - by Richard
    Google recently announced that they will no longer support older browsers on Aug 1st: http://www.bbc.co.uk/news/technology-13639875 http://gmailblog.blogspot.com/2011/06/our-plans-to-support-modern-browsers.html For this reason, soon Google Apps will only support modern browsers. Beginning August 1st, we’ll support the current and prior major release of Chrome, Firefox, Internet Explorer and Safari on a rolling basis. Each time a new version is released, we’ll begin supporting the update and stop supporting the third-oldest version. There is nothing worse than looking at the patching of code that takes place to support older browsers. If we could all move towards a standards only web (I'm looking at you IE9) then surely we could spend more time programming good web apps and less trying to make them run equally on terrible non standards compliant older browsers. So when can the rest of us expect to be able to tell our clients that we no longer support older browsers? Because it seems that large corporates will continue to run older browsers and even if google chrome frame can be installed without admin privileges (it's coming soon, currently in beta) we can't expect all users to be motivated to do this. I appreciate any thoughts.

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  • How to reference or connect a variable to another class without stack overflow?

    - by SystemNetworks
    I really need to re-arrange all my functions. I created a class. All my var, booleans, int, doubles and other things. I created every new variable so they can reference it and so they don't have an error. If your asking why I never just reference my main class vars to my sub-class becuase it will give me stack overflow! When in my main class i link my sub-class. subClass s = new subClass(); Then I reference my fake variable to my real variable for example: This is my sub-class variable(I call it fake) public int x = 0; In my main class, I put it like this: s.x = x; The problem is, it does not work! Maybe this is not the right place but I cant ask any questions on stack overflow because they banned me. If I connect my main class and connect my sub-class it will give me stack overflow. How do I stop it?

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  • Deadlock Analysis in NetBeans 8

    - by Geertjan
    Lock contention profiling is very important in multi-core environments. Lock contention occurs when a thread tries to acquire a lock while another thread is holding it, forcing it to wait. Lock contentions result in deadlocks. Multi-core environments have even more threads to deal with, causing an increased likelihood of lock contentions. In NetBeans 8, the NetBeans Profiler has new support for displaying detailed information about lock contention, i.e., the relationship between the threads that are locked. After all, whenever there's a deadlock, in any aspect of interaction, e.g., a political deadlock, it helps to be able to point to the responsible party or, at least, the order in which events happened resulting in the deadlock. As an example, let's take the handy Deadlock sample code from the Java Tutorial and look at the tools in NetBeans IDE for identifying and analyzing the code. The description of the deadlock is nice: Alphonse and Gaston are friends, and great believers in courtesy. A strict rule of courtesy is that when you bow to a friend, you must remain bowed until your friend has a chance to return the bow. Unfortunately, this rule does not account for the possibility that two friends might bow to each other at the same time. To help identify who bowed first or, at least, the order in which bowing took place, right-click the file and choose "Profile File". In the Profile Task Manager, make the choices below: When you have clicked Run, the Threads window shows the two threads are blocked, i.e., the red "Monitor" lines tell you that the related threads are blocked while trying to enter a synchronized method or block: But which thread is holding the lock? Which one is blocked by the other? The above visualization does not answer these questions. New in NetBeans 8 is that you can analyze the deadlock in the new Lock Contention window to determine which of the threads is responsible for the lock: Here is the code that simulates the lock, very slightly tweaked at the end, where I use "setName" on the threads, so that it's even easier to analyze the threads in the relevant NetBeans tools. Also, I converted the anonymous inner Runnables to lambda expressions. package org.demo; public class Deadlock { static class Friend { private final String name; public Friend(String name) { this.name = name; } public String getName() { return this.name; } public synchronized void bow(Friend bower) { System.out.format("%s: %s" + " has bowed to me!%n", this.name, bower.getName()); bower.bowBack(this); } public synchronized void bowBack(Friend bower) { System.out.format("%s: %s" + " has bowed back to me!%n", this.name, bower.getName()); } } public static void main(String[] args) { final Friend alphonse = new Friend("Alphonse"); final Friend gaston = new Friend("Gaston"); Thread t1 = new Thread(() -> { alphonse.bow(gaston); }); t1.setName("Alphonse bows to Gaston"); t1.start(); Thread t2 = new Thread(() -> { gaston.bow(alphonse); }); t2.setName("Gaston bows to Alphonse"); t2.start(); } } In the above code, it's extremely likely that both threads will block when they attempt to invoke bowBack. Neither block will ever end, because each thread is waiting for the other to exit bow. Note: As you can see, it really helps to use "Thread.setName", everywhere, wherever you're creating a Thread in your code, since the tools in the IDE become a lot more meaningful when you've defined the name of the thread because otherwise the Profiler will be forced to use thread names like "thread-5" and "thread-6", i.e., based on the order of the threads, which is kind of meaningless. (Normally, except in a simple demo scenario like the above, you're not starting the threads in the same class, so you have no idea at all what "thread-5" and "thread-6" mean because you don't know the order in which the threads were started.) Slightly more compact: Thread t1 = new Thread(() -> { alphonse.bow(gaston); },"Alphonse bows to Gaston"); t1.start(); Thread t2 = new Thread(() -> { gaston.bow(alphonse); },"Gaston bows to Alphonse"); t2.start();

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  • Exceptions from automongobackup, yet script completes

    - by chakram88
    I am using automongobackup to, well, automate the backups of mongodb. output from the script (to STDERR) has the following exceptions (but the backup completes, and the dump files are created) ###### WARNING ###### STDERR written to during mongodump execution. The backup probably succeeded, as mongodump sometimes writes to STDERR, but you may wish to scan the error log below: exception: connect failed exception: connect failed exception: connect failed exception: connect failed exception: HostAndPort: bad port # exception: connect failed exception: connect failed exception: connect failed exception: connect failed exception: connect failed exception: connect failed I know that the Host & Port are correct. If I run mongodump --host=127.0.0.1:27017 --journal (which is the effective command from automongobackup based on the options set and my reading of the src code) everything runs clean without any error reporting and the dump files are created as expected. Why would automongobackup report connection errors, even tho it does create the dump files, yet a straight call to mongodump does not? Debian 6.0 Lenny (from Linode image: Latest 3.2 (3.2.1-x86_64-linode23)) AutoMongoBackup VER 0.9 mongodb v 2.0.2

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  • Should I be concerned that I can't program very fast without Google? [closed]

    - by seth
    Possible Duplicate: Google is good or bad for programmer? I'm currently in college to be a software engineer, and one of the main principles taught to us is how to learn for ourselves, and how to search the web when we have a doubt. This leads to a proactive attitude - when I need something, I go get it. Recently, I started wondering how much development would I be able to do without internet access and the answer bugged me quite a bit. I know the concept of the languages and how to use them, but I was amazed by how "slow" things were without having the Google to help in the development. Most of the problems I have are related to specific syntax. For example, reading and writing to a file in Java. I have done this about a dozen times in my life, yet every time I need to do it, I end up googling "read file java" and refreshing my memory. I completely understand the code and fully understand what it does, but I am sure that without Google it would take me a few tries to get the code correct. Is this normal? Should I be worried and try to change something in my programming behaviour?

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  • Where do I read more about building an architecture like Google has? [on hold]

    - by user107148
    I want to develop a program that watches and traverses a rather big network for data. This data should then be available to search through with my program, maybe through a web interface or something. My intuitive thought at the moment is to build an architecture kind of like the one Google has. One "front-end" (the Google Search page) which is essentially a regular web application and one "back-end" (which in Google's case traverses the web). Now for the hard part: If I decide to make such a system, how should communication be done between these parts? One idea I had is to use some kind of database that both the back-end and front-end can access, but then comes the issues of concurrent writes and reads. Another issue with just using a database to communicate is that it makes it hard to "notify" the other part when something changes. Let's say that I want the "front-end" part to push changes to the UI when a change is noticed in the back-end. Then the back-end would have to have some way of notifying the front-end of this.

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  • PHP] How can I connect to MySQL on wamp server?

    - by user294359
    This might be ridiculously easy for you.. but I've been struggling with this for an hour.. :( <?php $connect = mysql_connect("localhost:8080", "root", "mypassword"); echo($connect);?> This is the code that I'm trying to run - you can see that I'm using 8080 as my port number and, of course, I have html codes as well. However, it gives me the following error msgs whenever I try to open the php file. ==================================================================================== Warning: mysql_connect() [function.mysql-connect]: MySQL server has gone away in C:\wamp\www\php_sandbox\index.php on line 2 Warning: mysql_connect() [function.mysql-connect]: Error while reading greeting packet. PID=4932 in C:\wamp\www\php_sandbox\index.php on line 2 Warning: mysql_connect() [function.mysql-connect]: MySQL server has gone away in C:\wamp\www\php_sandbox\index.php on line 2 ===================================================================================== I don't know... what's wrong with this. Is it because of the port number?

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