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  • Best place to check user authenticity in a back end module where all pages are only available to mem

    - by understack
    I've a backend module which could only be accessed by only authorized members. So I need to check authenticity for all actions and for all controllers. Currently I'm doing it inside preDispatch() functions inside controller classes. So it takes care of all the actions inside that controller. But still I've to do it for all controllers. Is there a place I could check it for all the controllers as well. So basically I want one place authenticity check for whole backend module. Can I do it in bootstrap?

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  • How to maintain unique login in windows form application?

    - by Vivek
    Hello All, I am developing a winform application in which user's login is validated through ms sql server 2000 database.When user entry its user name and password, application checks its exists in user table or not. Now my requirement is if a user already login through one system it should not log in through another system. if solution like make entry in database about status of user like on successful log in mark user status is true and on closing application mark false , then in the case of network or hardware failure or system exception. so, please suggest me a optimal solution .

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  • Is there a way to achieve covariance of generic types in C# 3.5?

    - by nullDev
    This has been introduced in C# 4.0, but is there a way to achieve this in c# 3.5? For e.g., consider the following code: class Base { } class Derived1 : Base { } class Derived2 : Base { } class User<T> where T : Base { } class User1 : User<Derived1> { } Now, I would like to have a list of User<T>, in which I can store User<Derived1> as well as User<Derived2>, but the following code fails to compile in C# 3.5: List<User<Base>> users = new List<User<Base>>(); users.Add(new User1()); Any ideas?

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  • how to get list of databases that a user owns?

    - by chiggsy
    Id like to find out ( and delete ) all the databases owned by an owner in postgres 8.4.3 I'm new to postgres also, and although I can , and will , read the whole manual today i was forced to use for i in $(psql -l |grep novicedba | awk '{print $1}') psql -d postgres -c " drop database \"$i\"" out of desperation. What's the postgresql way to do this?

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  • Can I have a user submit a form and receive a PDF copy?

    - by thatryan
    Not quite sure how to ask this :) But what I need is to have some forms online that people can fill out, like registration form etc. They will then submit it and be emailed it as well as me and have it stored in a database. Is there a way for the files to be PDFs? Can I have an editable PDF form online? Thank you.

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  • How to get my program to log the user into Windows?

    - by blood
    i have been working on a program that will enter usernames and passwords if someone plugs in a Usb, but i don't know how to enter a windows log in password. So the idea is to have my program running so it can find if the usb is plugged in if so it will use keybd_event to enter the password and to hit enter. how would i get my program to run so i can do this?

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  • OpenVPN useradd error

    - by zfz
    I tried to install an OpenVPN access server in Centos 6 on a linode VPS. The installation error occours when adding the user "openvpn". However, the installation is okay for my ubuntu 11.10 distro in another VPS. The error message is "useradd: canot open /etc/passwd" The detail of My "/etc/passwd" file: "-rw-r--r-- 1 root root 1194 Oct 9 00:33 /etc/passwd" So how can I add the user "openvpn" to setup the VPN service? Thanks.

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  • Screen Snip/Capture Utility callable from API or command line?

    - by Raymond
    I am looking for a screen capture tool that is controllable from the command line. Ideally I would pass the filename, and possibly some options (capture mouse pointer or not, etc..), then it would take control, allow the user to select a region of the screen, and then save it to the specified file and disappear. screensnip.exe /output c:\users\public\pictures\screenshot.png /hidecursor user draws rectangle on screen control passes back to batch file, script, etc....

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  • Flex 4: Getter getting before setter sets

    - by Steve
    I've created an AS class to use as a data model, shown here: package { import mx.controls.Alert; import mx.rpc.events.FaultEvent; import mx.rpc.events.ResultEvent; import mx.rpc.http.HTTPService; public class Model { private var xmlService:HTTPService; private var _xml:XML; private var xmlChanged:Boolean = false; public function Model() { } public function loadXML(url:String):void { xmlService = new HTTPService(); if (!url) xmlService.url = "DATAPOINTS.xml"; else xmlService.url = url; xmlService.resultFormat = "e4x"; xmlService.addEventListener(ResultEvent.RESULT, setXML); xmlService.addEventListener(FaultEvent.FAULT, faultXML); xmlService.send(); } private function setXML(event:ResultEvent):void { xmlChanged = true; this._xml = event.result as XML; } private function faultXML(event:FaultEvent):void { Alert.show("RAF data could not be loaded."); } public function get xml():XML { return _xml; } } } And in my main application, I'm initiating the app and calling the loadXML function to get the XML: <fx:Script> <![CDATA[ import mx.containers.Form; import mx.containers.FormItem; import mx.containers.VBox; import mx.controls.Alert; import mx.controls.Button; import mx.controls.Label; import mx.controls.Text; import mx.controls.TextInput; import spark.components.NavigatorContent; private function init():void { var model:Model = new Model(); model.loadXML(null); var xml:XML = model.xml; } ]]> </fx:Script> The trouble I'm having is that the getter function is running before loadXML has finished, so the XML varible in my main app comes up undefined in stack traces. How do I put a condition in here somewhere that tells the getter to wait until the loadXML() function has finished before running?

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  • How do I get my Flash CS4 buttons to direct the user to another URL?

    - by goldenfeelings
    My apologies if this has been fully addressed before, but I've read through several other threads and still can't seem to get my file to work. My actionscript code is at the bottom of this message. I created it using instructions from the Adobe website: http://help.adobe.com/en_US/ActionScript/3.0_ProgrammingAS3/WS5b3ccc516d4fbf351e63e3d118a9b90204-7fd7.html I believe I have all of my objects set to the correct type of symbol (button) and all of my instances are named appropriately (see screenshot here: www.footprintsfamilyphoto.com/wp-content/themes/Footprints/images/flash_buttonissue.jpg) Action Script here. Let me know if you have suggestions! (Note: I am very new to Flash): stop (); function families(event:MouseEvent):void { var targetURL:URLRequest = new URLRequest("http://www.footprintsfamilyphoto.com/portfolio/families"); navigateToURL(targetURL); } bc_btn1.addEventListener(MouseEvent.CLICK, families); bc_btn2.addEventListener(MouseEvent.CLICK, families); function families(event:MouseEvent):void { var targetURL:URLRequest = new URLRequest("http://www.footprintsfamilyphoto.com/portfolio/families"); navigateToURL(targetURL); } f_btn1.addEventListener(MouseEvent.CLICK, families); f_btn2.addEventListener(MouseEvent.CLICK, families); function families(event:MouseEvent):void { var targetURL:URLRequest = new URLRequest("http://www.footprintsfamilyphoto.com/portfolio/families"); navigateToURL(targetURL); } cw_btn1.addEventListener(MouseEvent.CLICK, families); cw_btn2.addEventListener(MouseEvent.CLICK, families);

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  • Rails routes and model woes

    - by Chris Maness
    I'm a little new to rails sorry if this seems basic Alright so here's the deal I'm creating an application that will have many users and all the users have many songs. However when I try to create a song I get the following error:No action responded to 1. Actions: create and new and my browser is at the url: http://0.0.0.0:3000/users/1/songs which is not the correct route it should have redirected to songs/create Here is my controller code: class SongsController < ApplicationController def index @user = current_user @songs = @user.songs end def new @user = current_user @song = @user.songs.build end def create @user = current_user @song = @user.songs.build(params[:song]) if @song.save redirect_to user_song_url(@user, @song) else render :action => "new" end end end If anyone can help I would greatly appreciate it.

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  • how to put array of user control in the columns of Grid.

    - by jolly
    Hi I have array of Employee data which includes photo,description, title name,salary. I have to show each employee data in separate panel control structure that means if I have 10 employees there will be 10 panels. and I have to show these panels in a grid which has two columns. Also width of the panel in each column will vary according to main page size.

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  • Android: Why my user Interface does not get drawn when I Inflate the resource layout file?

    - by Einiosaurus
    First of all, I'm a newbie on Android programming, so please be detailed in your answers. I have a layout main.xml file with format similar to <?xml version="1.0" encoding="utf-8"?> <LinearLayout xmlns:android = "http://schemas.android.com/apk/res/android" android:orientation = "vertical" android:layout_width = "fill_parent" android:layout_height = "fill_parent"> <LinearLayout xmlns:android = "http://schemas.android.com/apk/res/android" android:orientation = "horizontal"   android:layout_width = "fill_parent" android:layout_height = "fill_parent"> <EditText android:id="@+id/a" android:layout_width="fill_parent" android:layout_height="wrap_content" /> <TextView android:id="@+id/xSquared" android:layout_width = "fill_parent" android:layout_height = "wrap_content" android:text = "@string/equationPart1" /> </LinearLayout> <LinearLayout ... </LinearLayout> </LinearLayout> In my Java source file, I inflate the UI using command: setContentView(R.layout.main); public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.main); } However, when I run the emulator, the UI does not show up like what I expect. Instead, it just display a simple EditText text box. I wonder what is going wrong. Is it because I put a layout inside another layout? I don't think there is any problem with that right?

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  • Is Work Stealing always the most appropriate user-level thread scheduling algorithm?

    - by Il-Bhima
    I've been investigating different scheduling algorithms for a thread pool I am implementing. Due to the nature of the problem I am solving I can assume that the tasks being run in parallel are independent and do not spawn any new tasks. The tasks can be of varying sizes. I went immediately for the most popular scheduling algorithm "work stealing" using lock-free deques for the local job queues, and I am relatively happy with this approach. However I'm wondering whether there are any common cases where work-stealing is not the best approach. For this particular problem I have a good estimate of the size of each individual task. Work-stealing does not make use of this information and I'm wondering if there is any scheduler which will give better load-balancing than work-stealing with this information (obviously with the same efficiency). NB. This question ties up with a previous question.

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  • Is a "Confirm Email" input good practice when user changes email address?

    - by dibson
    My organization has a form to allow users to update their email address with us. It's suggested that we have two input boxes for email: the second as an email confirmation. I always copy/paste my email address when faced with the confirmation. I'm assuming most of our users are not so savvy. Regardless, is this considered a good practice? I can't stand it personally, but I also realize it probably isn't meant for me. If someone screws up their email, they can't login, and they must call to sort things out.

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  • Unix console becomes inactive after closing vim

    - by gotts
    user@laptop:~$ locate file.ext | xargs vim -p Vim: Warning: Input is not from a terminal 2 files to edit user@laptop:~$ After finding files and modifying them in vim I want to save them and continue to work in unix console but I can't do that. After vim close console just halts. No activity on any keypress. The only workaround is to close console tab and create a new one. How can I solve this problem?

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  • Backing up files on ubuntu for reinstall. Will there be problems with permissions?

    - by adam
    I have some very important files I want to backup before I reinstall my Ubuntu back to 9.04 from the 9.10 (its causing me all sorts of problems). The files total size is small so im just going to copy them over to Dropbox. Im wondering, when i reinstall Ubuntu and copy them back will there be any issues re the permissions of those files because my old user account which created them and the new user Ill setup on the new install will be different?

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  • Stuggling with webkit-transition in javascript

    - by Mungbeans
    I've tried a few variations of using webkit-transition that I've found from googling but I've not been able to get any to work. I have some audio controls that I make appear on a click event, they appear suddenly and jerky so I want to fade them in. The target browser is iOS so I am trying webkit extensions. This is what I currently have: <div id = "controls"> <audio id = "audio" controls></audio> </div> #controls { position:absolute; top: 35px; left:73px; height: 20px; width: 180px; display:none; } #audio { opacity:0.0; } audio.src = clip; audio.addEventListener('pause', onPauseOrStop, false); audio.addEventListener('ended', onPauseOrStop, false); audio.play(); audioControls.style.display = 'block'; audio.style.setProperty("-webkit-transition", "opacity 0.4s"); audio.style.opacity = 0.7; The documentation for webkit-transition says it takes effect on a change in the property, so I was assuming changing style.opacity in the last line would kick it off. The controls appear with an opacity of 0.7 but I want it to fade in and that animation isn't happening. I also tried this: #audio { opacity:0.0; -webkit-transition-property: opacity; -webkit-transition-duration: 1s; -webkit-timing-function: ease-in; } Also tried audio.style.webkitTransition = "opacity 1.4s"; from this posting How to set CSS3 transition using javascript? I can't get anything to work, I'm testing on iOS, Safari desktop and Chrome. Same non result on all of them.

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