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  • Java if/else behaving strangely

    - by Alex
    I'm a real newbie to java, so please excuse me if this is a hopelessly straightforward problem. I have the following from my java game server: // Get input from the client DataInputStream in = new DataInputStream (server.getInputStream()); PrintStream out = new PrintStream(server.getOutputStream()); disconnect=false; while((line = in.readLine().trim()) != null && !line.equals(".") && !line.equals("") && !disconnect) { System.out.println("Received "+line); if(line.equals("h")){ out.println("h"+EOF); // Client handshake System.out.println("Matched 1"); }else if (line.equals("<policy-file-request/>")) { out.println("..."+EOF); // Policy file System.out.println(server.getInetAddress()+": Policy Request"); disconnect=true; System.out.println("Matched 2"); }else if(line.substring(0,3).equals("GET")||line.substring(0,4).equals("POST")){ out.println("HTTP/1.0 200 OK\nServer: VirtuaRoom v0.9\nContent-Type: text/html\n\n..."); // HTML status page disconnect=true; System.out.println("Matched 3"); } else { System.out.println(server.getInetAddress()+": Unknown command, client disconnected."); disconnect=true; System.out.println("Matched else"); } } server.close(); First of all, the client sends an "h" packet, and expects the same back (handshake). However, I want it to disconnect the client when an unrecognised packet is received. For some reason, it responds fine to the handshake and HTML status request, but the else clause is never executed when there's an unknown packet. Thanks

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  • Raspberry Pi broadcast serial port data to local network

    - by D051P0
    I didn't find anything to help me with this problem. What I want is: Serial device sends repeatedly some data to serial port. Raspberry Pi should get this data from RxD and stream it to local network via port 10001 without filtering it. So I can find this device on my pc. This should also work in other direction: Raspberry listen to port 10001 and forward all data from local network to TxD. I'm newbie in Linux World. How can I listen to some port on Raspberry Pi and send broadcast to the same port? I'm using Raspbian Wheezy with soft float. I have found a library Pi4j for Java, that I already use to get and write data from/to serial port. final Serial serial = SerialFactory.createInstance(); serial.addListener(new SerialDataListener() { public void dataReceived(SerialDataEvent event) { forward(event.getData()); } }); event.getData() is a String, which I want to broadcast in my local network. Is it generally a good Idea to use Java for that? I need also a String from port 10001, which I can forward to serial port.

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  • Generics in a bidirectional association

    - by Verhoevenv
    Let's say I have two classes A and B, with B a subtype of A. This is only part of a richer type hierarchy, obviously, but I don't think that's relevant. Assume A is the root of the hierarchy. There is a collection class C that keeps track of a list of A's. However, I want to make C generic, so that it is possible to make an instance that only keeps B's and won't accept A's. class A(val c: C[A]) { c.addEntry(this) } class B(c: C[A]) extends A(c) class C[T <: A]{ val entries = new ArrayBuffer[T]() def addEntry(e: T) { entries += e } } object Generic { def main(args : Array[String]) { val c = new C[B]() new B(c) } } The code above obviously give the error 'type mismatch: found C[B], required C[A]' on the new B(c) line. I'm not sure how this can be fixed. It's not possible to make C covariant in T (like C[+T <: A]) because the ArrayBuffer is non-variantly typed in T. It's not possible to make the constructor of B require a C[B] because C can't be covariant. Am I barking up the wrong tree here? I'm a complete Scala newbie, so any ideas and tips might be helpful. Thank you! EDIT: Basically, what I'd like to have is that the compiler accepts both val c = new C[B]() new B(c) and val c = new C[A]() new B(c) but would reject val c = new C[B]() new A(c) It's probably possible to relax the typing of the ArrayBuffer in C to be A instead of T, and thus in the addEntry method as well, if that helps.

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  • Obj-C Sending Messages Between Classes

    - by user544359
    I'm a newbie in iPhone Programming. I'm trying to send a message from one view controller to another. The idea is that viewControllerA takes information from the user and sends it to viewControllerB. viewControllerB is then supposed to display the information in a label. viewControllerA.h #import <UIKit/UIKit.h> @interface viewControllerA : UIViewController { int num; } -(IBAction)do; @end viewControllerA.m #import "viewControllerA.h" #import "viewControllerB.h" @implementation viewControllerA - (IBAction)do { //initializing int for example num = 2; viewControllerB *viewB = [[viewControllerB alloc] init]; [viewB display:num]; [viewB release]; //viewA is presented as a ModalViewController, so it dismisses itself to return to the //original view, i know it is not efficient [self dismissModalViewControllerAnimated:YES]; } - (void)dealloc { [super dealloc]; } @end viewControllerB.h #import <UIKit/UIKit.h> @interface viewControllerB : UIViewController { IBOutlet UILabel *label; } - (IBAction)openA; - (void)display:(NSInteger)myNum; @end viewControllerB.m #import "viewControllerB.h" #import "viewControllerA.h" @implementation viewControllerB - (IBAction)openA { //presents viewControllerA when a button is pressed viewControllerA *viewA = [[viewControllerA alloc] init]; [self presentModalViewController:viewA animated:YES]; } - (void)display:(NSInteger)myNum { NSLog(@"YES"); [label setText:[NSString stringWithFormat:@"%d", myNum]]; } @end YES is logged successfully, but the label's text does not change. I have made sure that all of my connections in Interface Builder are correct, in fact there are other (IBAction) methods in my program that change the text of this very label, and all of those other methods work perfectly... Any ideas, guys? You don't need to give me a full solution, any bits of information will help. Thanks.

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  • .NET Development of iPhone App with MonoTouch - which development environment?

    - by Click Ahead
    Hi All, I'm a .NET developer (C#) with several years developing Windows Mobile Apps. I would like to get into developing iPhone Apps and MonoTouch looks good based on reviews I've read. So I'm going to go with MonoTouch. My understanding is that I'll need a new Mac, but as it happens I also need a new PC for my .NET windows development. My question is should I (a) Purchase a Mac Book Pro and dual boot with Windows 7 (b) Purchase a Mac Pro and dual boot with Windows 7 (c) Purchase a good Dev PC and a slighlty less well spec'd Mac Book Pro or Mac Pro Bear in mind I'm only doing MonoTouch development with the Mac, most of my development (approx. 80% initially) will be done on the Windows side. My budget is approx. €3,000 / $4,000 and I'd like a good, fast development environment.It's purely for development so on the windows side installing SQL 2008/VS 2010/Office and on the OS X side installing MonoTouch. BTW - my budget excludes licensing for VS/MonoTouch/etc, I have a MonoTouch and MSDN license. Any opinions are greatly appreciated. I'm a newbie to Mac's !

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  • What are the possible tags inside the "global" tag in Magento "config.xml" file?

    - by Knowledge Craving
    Can someone professional experienced Magento developer tell me how to accomplish the following in Magento? I want to know what are the possible tags that can fit in the "global" tag of the "config.xml" page of every module's etc folder? I have tried searching for this answer at many places in Internet but in vain. Please provide the full details along with it for Magento version = 1.4.0.0, because I want at least the users accessing this website find it useful enough, instead of scratching their heads. I really want a detailed explanation, because every newbie like me gets totally confused at this point. From what I know till now, is that in this page, you can set routers, rewrites, cron jobs, admin html, front-end html and many more. But without any strong concepts, none can go ahead with the belief that his code is 100% correct w.r.t. the Magento MVC architecture. So please I want that strong fundamental concept, getting underlined here, with a detailed explanation about it, so that no one gets into this pitfall ever again. Many many thanks to those who can answer only upon knowing the total concept clearly.

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  • NSMagedObjectContext, threads and NSFechedResultsController

    - by tmpz
    Dear iphone developers, Core Data newbie speaking here. In my application I have two NSManagedObjectContext that refer to that same NSPersistentStorageController. One ManagedObjectContext (c1) is in the main thread --created when I create a NSFetchedResultsController -- and the second ManagedObjectContext (c2) created in a second thread, running in the background, detached from the main thread. In the background thread I pull some data off a website and insert the entities created for the pulled data in the thread's ManagedObjectContext (c2). In the meanwhile, the main thread sits doing nothing and displaying a UITableView whose data do be display should be provided by the NSFetchedResultsController. When the background thread has finished pulling the data and inserting entities in c2, c2 saves, and the background thread notifies the main thread that the processing has finished before it exiting. As a matter of fact, the entities that I have inserted in c2 are know by c1 because it can ask it about one particular entity with [c1 existingObjectWithID:ObjectID error:&error]; I would expect at this point, if I call on my tableview reloadData to see some rows showing up with the data I pulled from the web in the background thread thanks to the NSFetchedResults controller which should react to the modifications of its ManagedObjectContext (c1). But nothing is happening! Only if I restart the application I see what I have previously pulled from the web! Where am I doing things wrong? Thank you in advance!

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  • Saving Email/Password to Keychain in iOS

    - by Jason
    I'm very new to iOS development so forgive me if this is a newbie question. I have a simple authentication mechanism for my app that takes a user's email address and password. I also have a switch that says 'Remember me'. If the user toggles that switch on, I'd like to preserve their email/password so those fields can be auto-populated in the future. I've gotten this to work with saving to a plist file but I know that's not the best idea since the password is unencrypted. I found some sample code for saving to the keychain, but to be honest, I'm a little lost. For the function below, I'm not sure how to call it and how to modify it to save the email address as well. I'm guessing to call it would be: saveString(@"passwordgoeshere"); Thank you for any help!!! + (void)saveString:(NSString *)inputString forKey:(NSString *)account { NSAssert(account != nil, @"Invalid account"); NSAssert(inputString != nil, @"Invalid string"); NSMutableDictionary *query = [NSMutableDictionary dictionary]; [query setObject:(id)kSecClassGenericPassword forKey:(id)kSecClass]; [query setObject:account forKey:(id)kSecAttrAccount]; [query setObject:(id)kSecAttrAccessibleWhenUnlocked forKey:(id)kSecAttrAccessible]; OSStatus error = SecItemCopyMatching((CFDictionaryRef)query, NULL); if (error == errSecSuccess) { // do update NSDictionary *attributesToUpdate = [NSDictionary dictionaryWithObject:[inputString dataUsingEncoding:NSUTF8StringEncoding] forKey:(id)kSecValueData]; error = SecItemUpdate((CFDictionaryRef)query, (CFDictionaryRef)attributesToUpdate); NSAssert1(error == errSecSuccess, @"SecItemUpdate failed: %d", error); } else if (error == errSecItemNotFound) { // do add [query setObject:[inputString dataUsingEncoding:NSUTF8StringEncoding] forKey:(id)kSecValueData]; error = SecItemAdd((CFDictionaryRef)query, NULL); NSAssert1(error == errSecSuccess, @"SecItemAdd failed: %d", error); } else { NSAssert1(NO, @"SecItemCopyMatching failed: %d", error); } }

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  • Android onFling not responding

    - by Kevin Moore
    I am new to android first of all so think of any newbie mistakes first I am trying to add a fling function in my code. public class MainGamePanel extends SurfaceView implements SurfaceHolder.Callback, OnGestureListener { private MainThread thread; private Droid droid; private Droid droid2; private static final String TAG = gameView.class.getSimpleName(); private GestureDetector gestureScanner; public MainGamePanel(Context context){ super(context); getHolder().addCallback(this); droid = new Droid(BitmapFactory.decodeResource(getResources(), R.drawable.playerbox2), 270, 300); droid2 = new Droid(BitmapFactory.decodeResource(getResources(), R.drawable.playerbox2), 50, 300); thread = new MainThread(getHolder(), this); setFocusable(true); gestureScanner = new GestureDetector(this); } public boolean onTouchEvent(MotionEvent event){ return gestureScanner.onTouchEvent(event); } @Override protected void onDraw(Canvas canvas){ canvas.drawColor(Color.BLACK); droid.draw(canvas); droid2.draw(canvas); } @Override public boolean onFling(MotionEvent e1, MotionEvent e2, float velocityX, float velocityY) { droid.setX(50); droid.setY(50); Log.d(TAG, "Coords: x=" + e1.getX() + ",y=" + e2.getY()); return true; } @Override public boolean onDown(MotionEvent e) { droid2.setX((int)e.getX()); droid2.setY((int)e.getY()); Log.d(TAG, "Coords: x=" + e.getX() + ",y=" + e.getY()); return false; } I got the gestureListener to work with: onDown, onLongPress, and onShowPress. But i can't get any response with onFling, onSingleTapUp, and onScroll. What mistake am I making? does it have to do with views? I don't know what code would be useful to see.... so any suggestions would be much appreciated. Thank You!

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  • two view controllers and reusability with delegate

    - by netcharmer
    Newbie question about design patterns in objC. I'm writing a functionality for my iphone app which I plan to use in other apps too. The functionality is written over two classes - Viewcontroller1 and Viewcontroller2. Viewcontroller1 is the root view of a navigation controller and it can push Viewcontroller2. Rest of the app will use only ViewController1 and will never access Viewcontroller2 directly. However, triggered by user events, Viewcontroller2 has to send a message to the rest of the app. My question is what is the best way of achieving it? Currently, I use two level of delegation to send the message out from Viewcontroller2. First send it to Viewcontroller1 and then let Viewcontroller1 send it to rest of the app or the application delegate. So my code looks like - //Viewcontroller1.h @protocol bellDelegate -(int)bellRang:(int)size; @end @interface Viewcontroller1 : UITableViewController <dummydelegate> { id <bellDelegate> delegate; @end //Viewcontroller1.m @implementation Viewcontroller1 -(void)viewDidLoad { //some stuff here Viewcontroller2 *vc2 = [[Viewcontroller2 alloc] init]; vc2.delegate = self; [self.navigationController pushViewController:vc2 animated:YES]; } -(int)dummyBell:(int)size { return([self.delegate bellRang:size]); } //Viewcontroller2.h @protocol dummyDelegate -(int)dummyBell:(int)size; @end @interface Viewcontroller2 : UITableViewController { id <dummyDelegate> delegate; @end //Viewcontroller2.m @implementation Viewcontroller2 -(int)eventFoo:(int)size { rval = [self.delegate dummyBell:size]; } @end

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  • Framework or CMS for php web development?

    - by rocknroll
    Hi all, I am a C++,Unix developer who has never dabbled in web development apart from creating simple HTML pages. I am going to change that and develop a website at a personal level soon. I am going to use php,mysql on a linux machine. In this regard I am browsing through relevant literature. The language isn't a problem but reading about CMS's and frameworks is confusing. And since I am new to web development, the number of CMS's and Frameworks are overwhelming. ? My question is do I need to have knowledge of one or more CMS' and/or Frameworks like Drupal,Joomla,Zend,Wordpress etc. If yes which is the best open source CMS' and/or Framework suggested for a newbie. ?? If the answer to the above question is yes, does the choice changes if one delves into the realms of commercial web development? Note:- I will be developing on a Linux machine, using open source tools. Thanks in advance

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  • On load rather than on click

    - by connor
    I have the following code: jQuery(function ($) { var OSX = { container: null, init: function () { $("input.apply, a.apply").click(function (e) { e.preventDefault(); $("#osx-modal-content").modal({ overlayId: 'osx-overlay', containerId: 'osx-container', closeHTML: null, minHeight: 80, opacity: 65, position: ['0',], overlayClose: true, onOpen: OSX.open, onClose: OSX.close }); }); }, open: function (d) { var self = this; self.container = d.container[0]; d.overlay.fadeIn('fast', function () { $("#osx-modal-content", self.container).show(); var title = $("#osx-modal-title", self.container); title.show(); d.container.slideDown('fast', function () { setTimeout(function () { var h = $("#osx-modal-data", self.container).height() + title.height() + 20; // padding d.container.animate( {height: h}, 200, function () { $("div.close", self.container).show(); $("#osx-modal-data", self.container).show(); } ); }, 300); }); }) }, close: function (d) { var self = this; // this = SimpleModal object d.container.animate( {top:"-" + (d.container.height() + 20)}, 500, function () { self.close(); // or $.modal.close(); } ); } }; OSX.init(); }); To load this script, a button with the class "apply" has to be clicked... Does anyone know a way of loading this script "onload" without a button being clicked? I have tried a lot of things, but I am a newbie when it comes to Javascript. Thanks!

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  • Something missing

    - by DHF
    The error of "} expected" appears at line 5. Why is that? I have included it at line 15. The error of "Declaration missing ;" appears at line 8. Why? There is ";" at the end of the line. #include<iostream> using namespace std; class PEmployee { public: PEmployee(); PEmployee(string employee_name, double initial_salary); void set_salary(double new_salary); double get_salary() const; string get_name() const; private: Person person_data; double salary; }; //line 15 int main() { PEmployee f("Patrick", 1000.00); cout << f.get_name() << " earns a salary of " << f.get_salary() << endl; return 0; } Newbie here, sorry for unclear question

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  • Use combobox value as query value (VC# 2k8 / ADO SQLITE)

    - by nicodevil
    Hi, I'm a newbie in VC# and ADO SQLITE... I'm trying to change the content of a combobox according to the value present in another one... My problem is here : SQLiteCommand cmd3 = new SQLiteCommand("select distinct(ACTION) from ACTION_LIST where CATEGORY='comboBox1.text'", conn2); What to use to do the job ? Here 'comboBox1.text' is see as a sentence not a variable... Here is the code : private void Form1_Load(object sender, EventArgs e) { using (SQLiteConnection conn1 = new SQLiteConnection(@"Data Source = Data\MRIS_DB_MASTER")) { conn1.Open(); SQLiteCommand cmd2 = new SQLiteCommand("select distinct(CATEGORY) from ACTION_LIST", conn1); SQLiteDataAdapter adapter1 = new SQLiteDataAdapter(cmd2); DataTable tbl1 = new DataTable(); adapter1.Fill(tbl1); comboBox1.DataSource = tbl1; comboBox1.DisplayMember = "CATEGORY"; adapter1.Dispose(); cmd2.Dispose(); } using (SQLiteConnection conn2 = new SQLiteConnection(@"Data Source = Data\MRIS_DB_MASTER")) { conn2.Open(); SQLiteCommand cmd3 = new SQLiteCommand("select distinct(ACTION) from ACTION_LIST where CATEGORY='comboBox1.text'", conn2); SQLiteDataAdapter adapter2 = new SQLiteDataAdapter(cmd3); DataTable tbl2 = new DataTable(); adapter2.Fill(tbl2); comboBox2.DataSource = tbl2; comboBox2.DisplayMember = "ACTION"; adapter2.Dispose(); cmd3.Dispose(); } } Thanks regards

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  • Setting default values for object properties in AS3

    - by Paul T
    I'm an actionscript newbie so please bear with me. Below is a function, and I am curious how to set default property values for objects that are being created in a loop. In the example below, these propeties are the same for each object created in the loop: titleTextField.selectable, titleTextField.wordWrap, titleTextField.x If you pull these properties out of the loop, they are null because the TextField objects have not been created, but it seems silly to have to set them each time. What is the correct way to do this. Thanks! var titleTextFormat:TextFormat = new TextFormat(); titleTextFormat.size = 10; titleTextFormat.font = "Arial"; titleTextFormat.color = 0xfff200; for (var i=0; i<arrThumbPicList.length; i++) { var yPos = 55 * i var titleTextField:TextField = new TextField(); titleTextField.selectable = false; titleTextField.wordWrap = true; titleTextField.text = arrThumbTitles[i]; titleTextField.x = 106; titleTextField.y = 331 + yPos; container.addChild(titleTextField); titleTextField.setTextFormat(titleTextFormat); }

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  • how to filter selected objects then hide objects not selected.

    - by ussteele
    following up from yesterday... This portion of the code does work. $(document).ready(function(){ $('#listMenu a').click(function (selected) { var getPage = $(this).attr('id'); var getName = $(this).attr('name'); //console.log(getPage); //console.log(getName); $(function() { $("#" + getName ).show(); var getColor = $('#' + getName ).css('background-color'); $('#header' ).css('background', getColor); $('#slideshow' ).css('background', getColor); $('span').css('background', getColor); $('#menuContainer').css('background', getColor); }); $('li.listMenu ul').hide(); }); }); I am able to get what I wanted selected; based on vars getPage and getName, now I need to hide what is not selected. I have tried this: $(function() { var notSelected = $('div').filter(selected).attr('id', 'name'); $(this).hide(); console.log(notSelected); }); placed just above: $('li.listMenu ul').hide(); but it's not correct, remember I am really a newbie. what I see on screen is the new selected items on top of what should be hidden. again any help is appreciated. -sjs

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  • How to check whether a default browser is opened in the operating system (Java)?

    - by stempel1984
    Hi, I am newbie here. During my work, I faced an interesting problem. I need to: check whether a default html browser is opened; check whether the browser is minimized/maximized (simply, a window's state); get an url address typed in the browser. If any of these conditions is not met, I have to open the browser in a maximized view with a desired url address. I primarily wanted to do all this in Java, but it came to my mind that I should employ many techniques/technologies and combine them appropriately to complete the functionality. But, which ones? That's the problem. I just recalled Windows API, but I'm not sure if it is of any help... Some users on another forum suggested that I should consider JNI (no experience at all)... I only know how to open a default browser (e.g. with use of the 'browse(URI uri)' method of the 'java.awt.Desktop' class) - that's too little to be proud of. Please give me some hints, maybe links to reasonable discussions, I would greatly appreciate any suggestions how to approach the problem.

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  • How to write a cgi script in perl that accepts output (an image file) from a urlconnection in a Java applet and writes it to the server?

    - by Brad Rock
    I created a Java applet for my web page that creates an image file. I want users to be able to run the applet and create unique images, click a button, and have the image they created be saved to the web server. I think I have the code down for writing the image to a URLconnection in the Java applet itself after having successfully written a file while running the applet on my system rather than the web page and saving a file to the local disk, and then altering a few things to write to a URLConnection instead of to the local disk (although we shall see how that works too). I am now trying to write a cgi script in perl that takes the image output from the URLConnection and writes the image to a file on my web server (note: I am a newbie to perl). I have found many examples of how to do something similar with simple text coming from an applet and then writing it to a text file, but I want to know how to apply the same concept to an image. Particularly, how do I read in the image? I've seen text input get read by using read(STDIN, $some_variable)--does the same thing work with an image? Likewise, how do I write the image file? What function do I use? Thanks for your help. I know that I am rather naive about all of this.

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  • Best (in your opinion) GIT workflow for case when releases are done on demand (in most cases 1-2 tickets at once)

    - by Robert
    I'm rather a Git newbie and I'm looking for your advice. In the company I work for we have a "workflow" where we have a single Git repo for our project with 2 branches: master and prod. All devs work on the master branch. If a ticket is done (from the dev perspective), we push to the repo. If all tests are passed, we make a release. The issue is that in most cases, the request from business guys sounds like: "please release ticket A or A && B". In most cases, I end up doing something like git checkout prod git cherry-pick --no-commit commit_hash git commit -m "blah blah to prod" -a As you can see this is not a perfect solution, and I'm under a huge impression this is a perfect way to nowhere especially when change A depends on changes B and C. Do you have any suggestions how to handle releases on demand if more devs works on the same branch and the flow looks like I described above? All suggestions are welcome. I cannot change business processes and it will have to stay as it is - unfortunately.

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  • Installing gnome on Linode with Ubuntu 9.10 x64 - remote VNC/RDP

    - by Kieran Benton
    Hi, I'm a self confessed Linux newbie, having lived and worked mostly within the Windows world for most of my life. I'm making the effort to try moving my virtual host from a Windows box to a Linode instance to try and better learn Linux, and one of the uses I occasionally have with my current Windows VPS is to RDP into it and browse the internet. I'm aware that this is probably not best practice (from either performance or security), and most of the time I will be learning from the shell, but I do occasionally need to boot into a GUI. Because of this, I'd like the ability within my Ubuntu installation on Linode to start/stop Windows X and Gnome at will after SSHing in (startx? gdm?), so I've tried: apt-get install ubuntu-desktop Reboot startx But I've got an error that no amount of googling has helped me with so far, which I'm assuming is something to do with the fact the box is headless and X needs some more configuration that is beyond me at the moment: root@local:~# startx hostname: Unknown host xauth: creating new authority file /root/.Xauthority xauth: creating new authority file /root/.Xauthority xauth: (argv):1: bad display name "local.kieranbenton.com:0" in "list" command xauth: (stdin):1: bad display name "local.kieranbenton.com:0" in "add" command X.Org X Server 1.6.4 Release Date: 2009-9-27 X Protocol Version 11, Revision 0 Build Operating System: Linux 2.6.24-23-server x86_64 Ubuntu Current Operating System: Linux local.kieranbenton.com 2.6.31.5-x86_64-linode9 #1 SMP Mon Oct 26 19:35:25 UTC 2009 x86_64 Kernel command line: root=/dev/xvda xencons=tty console=tty1 console=hvc0 nosep nodevfs ramdisk_size=32768 ro Build Date: 26 October 2009 05:19:56PM xorg-server 2:1.6.4-2ubuntu4 (buildd@) Before reporting problems, check http://wiki.x.org to make sure that you have the latest version. Markers: (--) probed, (**) from config file, (==) default setting, (++) from command line, (!!) notice, (II) informational, (WW) warning, (EE) error, (NI) not implemented, (??) unknown. (==) Log file: "/var/log/Xorg.0.log", Time: Wed Dec 2 15:50:23 2009 Primary device is not PCI (==) Using default built-in configuration (21 lines) (EE) open /dev/fb0: No such file or directory (EE) No devices detected. Fatal server error: no screens found Please consult the The X.Org Foundation support at http://wiki.x.org for help. Please also check the log file at "/var/log/Xorg.0.log" for additional information. ddxSigGiveUp: Closing log Can anyone give me any pointers as to how to go from here and get VNC/RDP setup? (RDP would be preferred?). Thanks.

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  • Installing gnome on Linode with Ubuntu 9.10 x64 - remote VNC/RDP

    - by Kieran Benton
    Hi, I'm a self confessed Linux newbie, having lived and worked mostly within the Windows world for most of my life. I'm making the effort to try moving my virtual host from a Windows box to a Linode instance to try and better learn Linux, and one of the uses I occasionally have with my current Windows VPS is to RDP into it and browse the internet. I'm aware that this is probably not best practice (from either performance or security), and most of the time I will be learning from the shell, but I do occasionally need to boot into a GUI. Because of this, I'd like the ability within my Ubuntu installation on Linode to start/stop Windows X and Gnome at will after SSHing in (startx? gdm?), so I've tried: apt-get install ubuntu-desktop Reboot startx But I've got an error that no amount of googling has helped me with so far, which I'm assuming is something to do with the fact the box is headless and X needs some more configuration that is beyond me at the moment: root@local:~# startx hostname: Unknown host xauth: creating new authority file /root/.Xauthority xauth: creating new authority file /root/.Xauthority xauth: (argv):1: bad display name "local.kieranbenton.com:0" in "list" command xauth: (stdin):1: bad display name "local.kieranbenton.com:0" in "add" command X.Org X Server 1.6.4 Release Date: 2009-9-27 X Protocol Version 11, Revision 0 Build Operating System: Linux 2.6.24-23-server x86_64 Ubuntu Current Operating System: Linux local.kieranbenton.com 2.6.31.5-x86_64-linode9 #1 SMP Mon Oct 26 19:35:25 UTC 2009 x86_64 Kernel command line: root=/dev/xvda xencons=tty console=tty1 console=hvc0 nosep nodevfs ramdisk_size=32768 ro Build Date: 26 October 2009 05:19:56PM xorg-server 2:1.6.4-2ubuntu4 (buildd@) Before reporting problems, check http://wiki.x.org to make sure that you have the latest version. Markers: (--) probed, (**) from config file, (==) default setting, (++) from command line, (!!) notice, (II) informational, (WW) warning, (EE) error, (NI) not implemented, (??) unknown. (==) Log file: "/var/log/Xorg.0.log", Time: Wed Dec 2 15:50:23 2009 Primary device is not PCI (==) Using default built-in configuration (21 lines) (EE) open /dev/fb0: No such file or directory (EE) No devices detected. Fatal server error: no screens found Please consult the The X.Org Foundation support at http://wiki.x.org for help. Please also check the log file at "/var/log/Xorg.0.log" for additional information. ddxSigGiveUp: Closing log Can anyone give me any pointers as to how to go from here and get VNC/RDP setup? (RDP would be preferred?). Thanks.

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  • How can I install things in Linux with *no yum* and *no wget*?

    - by e9t
    I'm a newbie to Linux (that mainly uses Windows and Mac OS X) needing some advice. I was trying to install git on a Linux machine today, and encountered some problems: Not knowing the version of the installed OS, I've opened the /proc/version file which said: Linux version 2.6.9-42.0.2.ELsmp ([email protected]) (gcc version 3.4.6 20060404 (Red Hat 3.4.6-3)) #1 SMP Thu Aug 17 17:57:31 EDT 2006 Then, as written in the git documents (http://git-scm.com/download/linux), I assumed I could use the yum install git command for Fedora, but got the following result. [root@myserver ~]# yum install git -bash: yum: command not found So I tried installing yum using wget, but wasn't so lucky. [root@myserver ~]# wget http://linux.duke.edu/projects/yum/download/2.0/yum-2.0.7.tar.gz -bash: wget: command not found I googled and found this page and this page, so tried installing yum with rpm, but only got a result full of question marks. (Possibly an encoding problem, hmm...) [root@myserver ~]# rpm -Uvh http://www.eomy.net/linux/install-yum-x86_64/wget-1.10.2-0.40E.x86_64.rpm http://www.eomy.net/linux/install-yum-x86_64/wget-1.10.2-0.40E.x86_64.rpm(??)?? ?????? ?: /var/tmp/rpm-xfer.TbuAOu: V3 DSA signature: NOKEY, key ID 443e1821 ???.. ########################################### [100%] wget-1.10.2-0.40E U???????g??????? wget-1.10.2-0.40E???? ??g??/usr/bin/wget ?? wget-1.10.2-0.40E U?????? ???? wget-1.10.2-0.40E???? ??g??/usr/share/man/man1/wget.1.gz ?? wget-1.10.2-0.40E U?????? ???? [root@myserver ~]# Finally, when I typed rpm --version in the terminal, I got the below results. [root@myserver ~]# rpm --version RPM ???? - 4.3.3 I would like to know what I can do or possibly try now. Is it not possible to wget or yum anything in my situation? Or is there any magical tool like homebrew (http://mxcl.github.com/homebrew/) that I can use? Any comments or advice would be appreciated. Thanks in advance!

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  • How to reference a Domain Controller out of the Local Network?

    - by Adrian
    We have multiple servers scattered over different hosting providers. For learning, experimenting and, ultimately, production purposes, I set one of them as a Domain Controller. That went well, most of our services are now authenticating via AD, which helps us a lot. What I want to do now is to simplify the authentication for the multiple servers, by making each of them look at the Domain Controller. This way, our Devs can log into (Remote Desktop) the multiple servers with the same credentials from AD. I know I have to configure each server to look at the Domain Controller. But when I try to add the Domain Controller to the Computer, it cannot find it, although the Domain Controller address is a valid, reachable internet sub-domain (as in "ad.ourcompany.com"). This is the detailed error message: Note: This information is intended for a network administrator. If you are not your network's administrator, notify the administrator that you received this information, which has been recorded in the file C:\Windows\debug\dcdiag.txt. The following error occurred when DNS was queried for the service location (SRV) resource record used to locate an Active Directory Domain Controller for domain ad.ourcompany.com: The error was: "DNS name does not exist." (error code 0x0000232B RCODE_NAME_ERROR) The query was for the SRV record for _ldap._tcp.dc._msdcs.ad.ourcompany.com Common causes of this error include the following: - The DNS SRV records required to locate a AD DC for the domain are not registered in DNS. These records are registered with a DNS server automatically when a AD DC is added to a domain. They are updated by the AD DC at set intervals. This computer is configured to use DNS servers with the following IP addresses: 109.188.207.9 109.188.207.10 - One or more of the following zones do not include delegation to its child zone: ad.ourcompany.com ourcompany.com com . (the root zone) For information about correcting this problem, click Help. What am I missing? I'm an experienced Dev, but a newbie Sysdamin experimenting with new stuff. Disclaimer All IP addresses and domains/subdomains were changed to preserve security. If by any chance you still can see private information, please let me know so that I can change it.

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  • VPN - force a selective range of ip to run on VPN (linux)

    - by Francesco
    Preface: I know there are similar question here and there however I'm a kind of newbie on Net stuff so I need an answer on this specific scenario, hoping that can help others too as it is a common problem Let say I cannot do anything on the local switch to change the local ip range, I don't want to use any complicate trick as use VMachine to hide the local ip range but I want to use net tools to solve the issue. Scenario my local net assign me an IP of this class 192.168.1.xxx (ex. 192.168.1.116) and my VPN (VPNC) assign me IP of same class 192.168.1.xxx (ex. 192.168.1.247) Obviously I need VPN to access local address (ex. 192.168.1.100) but when I open any address of the class 192.168.1.xx the route point to my local net and not to the VPN ones. I'm on linux and i'd like gui solution (network manager) in case it is not possible let play with route command. here what network manager offer me: Here my actual route once connected to the VPN: Here some route information (route -n) Destination Gateway Genmask Flags Metric Ref Use Iface 0.0.0.0 0.0.0.0 0.0.0.0 U 0 0 0 ppp0 169.254.0.0 0.0.0.0 255.255.0.0 U 1000 0 0 wlan0 182.71.21.106 192.168.1.1 255.255.255.255 UGH 0 0 0 wlan0 182.71.21.106 192.168.1.1 255.255.255.255 UGH 0 0 0 wlan0 192.168.1.0 0.0.0.0 255.255.255.0 U 9 0 0 wlan0 192.168.1.246 0.0.0.0 255.255.255.255 UH 0 0 0 ppp0 Here my ifconfig : ppp0 Link encap:Point-to-Point Protocol inet addr:192.168.1.247 P-t-P:192.168.1.246 Mask:255.255.255.255 UP POINTOPOINT RUNNING NOARP MULTICAST MTU:1400 Metric:1 RX packets:3415 errors:0 dropped:0 overruns:0 frame:0 TX packets:2525 errors:0 dropped:0 overruns:0 carrier:0 collisions:0 txqueuelen:3 RX bytes:3682328 (3.6 MB) TX bytes:402315 (402.3 KB) wlan0 Link encap:Ethernet HWaddr 4c:eb:42:06:a3:a6 inet addr:192.168.1.116 Bcast:192.168.1.255 Mask:255.255.255.0 inet6 addr: fe80::4eeb:42ff:fe06:a3a6/64 Scope:Link UP BROADCAST RUNNING MULTICAST MTU:1500 Metric:1 RX packets:72598 errors:0 dropped:0 overruns:0 frame:0 TX packets:42300 errors:0 dropped:0 overruns:0 carrier:0 collisions:0 txqueuelen:1000 RX bytes:76000532 (76.0 MB) TX bytes:13919400 (13.9 MB) The Question So basically I would like to add a rule to force this particular address (192.168.1.100) on the VPN and not on my local net

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  • Restart mysql keeping the data

    - by sitonico
    I'm quite new using mysql, so let me know if I'm missing something. I took some holidays, and when I got back to work and I tried to log in phpmyadmin I got a ERROR 2002 (HY000): Can't connect to local MySQL server through socket '/var/run/mysqld/mysqld.sock' (2). I never had this problem, so I was browsing to look for a solution. I tried some things, and I'm afraid I touched too much. I couldn't solve the problem, and the I realized that I had some actualizations to be done, and I thought that they may be helpful for mysql. Then I also realized that when I was doing this actualizations first day, they stopped because I had a lack of space, so I restarted then. Then,when the system was configuring mysql, it didn't advance. I waited for a long time and then I just stopped it and restarted the computer. After it, I just tried to uninstall mysql with sudo apt-get remove mysql-server-5.1, and install it again, but it didn't work. Now I have 2 questions: What do you think it is happening? Should I remove mysql completely? What should I do? I'm afraid of losing my databases, is there anyway to recover the data? Thank you very much in advance. -----------EDIT------- These are the messages: alfonso@alfonso-laptop:/$ tail -F /var/log/syslog | grep Feb 15 15:08:01 alfonso-laptop init: mysql post-start process (15192) terminated with status Feb 15 15:08:01 alfonso-laptop init: mysql main process (15263) terminated with status Feb 15 15:08:01 alfonso-laptop init: mysql main process ended, Feb 15 15:08:31 alfonso-laptop init: mysql post-start process (15264) terminated with status Feb 15 15:08:31 alfonso-laptop init: mysql main process (15358) terminated with status Feb 15 15:08:31 alfonso-laptop init: mysql main process ended, Feb 15 15:09:01 alfonso-laptop init: mysql post-start process (15359) terminated with status Feb 15 15:09:01 alfonso-laptop init: mysql main process (15447) terminated with status Feb 15 15:09:01 alfonso-laptop init: mysql main process ended, Feb 15 15:09:32 alfonso-laptop init: mysql post-start process (15448) terminated with status 1 This is the content of error.log-old 110128 13:17:20 [Note] /usr/sbin/mysqld: Normal shutdown 110128 13:17:20 [Note] Event Scheduler: Purging the queue. 0 events 110128 13:17:20 InnoDB: Starting shutdown... 110128 13:17:22 InnoDB: Shutdown completed; log sequence number 0 590872 110128 13:17:22 [Note] /usr/sbin/mysqld: Shutdown complete 110214 2:08:18 [Note] Plugin 'FEDERATED' is disabled. 110214 2:08:19 InnoDB: Started; log sequence number 0 590872 110214 2:08:19 [Note] Event Scheduler: Loaded 0 events 110214 2:08:19 [Note] /usr/sbin/mysqld: ready for connections. Version: '5.1.41-3ubuntu12.8' socket: '/var/run/mysqld/mysqld.sock' port: 3306 (Ubuntu) -- Some links of similar problems https://bugs.launchpad.net/ubuntu/+source/mysql-dfsg-5.1/+bug/573318 http://www.linuxquestions.org/questions/linux-newbie-8/lamp-install-on-lucid-mysqld-sock-missing-mysql-terminating-status%3D1-853152/ It seems it's a permissions problem... But I don't know which permissions I should change... SOLVED -- mysql error 2002 "cannot connect to socket"

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