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  • How trasmit a Dictionary in a jsons form

    - by xRobot
    I have a dictionary in jsons form like this: $user = "{ name: Mary , born: 1963, money: 213 }"; I need to pass it throught this field: <input type="hidden" name="custom" value="" > and then insert it in the db: INSERT INTO user ( name, born, money ) VALUE ( $name, $born, $money ) How can I do that ?

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  • Sort database entries via a dropdown list

    - by Lin
    Hello! I'm curious if anyone could possibly help me, because I can't find anything exactly related to it anywhere, and it's driving me nuts. I'd like to have a dropdown list on a page, that will give the visitor the option to sort all entries by year. I have entries from i.e. 2001, 2005, 2009, 2010. The years should be displayed in the dropdown, so the visitor can easily just select all entries dated 2001 if they want. The year for each entry is located in the one database table I have. In other words, I simply want a "sort by" dropdown that you can see on pretty much any shopping site nowadays. But with set years. Thanks in advance for any replies!

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  • Activetopics - Get max 5 topics per category

    - by Arjen
    Hey, I want to get the 5 latest active topics within several category's. Each topic has a subcatid and this subcatid relates to a catid. What I want is to get the 5 active topics within each catid. I'm trying to use the query below, but this isn't working at all: set @num := 0, @catid := 0; SELECT forum_posts.topicid, forum_topics.titel, forum_topics.sticky, forum_topics.gesloten, MAX(forum_cats.id) AS catid, MAX(forum_cats.titel) AS cattitel, MAX(forum_subcats.id) AS subcatid, MAX(forum_posts.id) AS maxid, DATE_FORMAT(MAX(forum_posts.datum), '%d-%m-%Y om %H:%i uur') AS datum, UNIX_TIMESTAMP(MAX(forum_posts.datum)) AS laatstereactieunix, (COUNT(forum_posts.id) - 1) AS reactieaantal, @num := IF(@catid = MAX(forum_cats.id), @num + 1, 1) AS row_number, @catid := MAX(forum_cats.id) AS dummy FROM forum_posts INNER JOIN forum_topics ON forum_topics.id = forum_posts.topicid INNER JOIN forum_subcats ON forum_subcats.id = forum_topics.subcat INNER JOIN forum_cats ON forum_cats.id = forum_subcats.cat WHERE forum_cats.id IN (1) AND forum_topics.gesloten != '1' GROUP BY forum_posts.topicid, forum_topics.titel, forum_topics.sticky, forum_topics.gesloten HAVING row_number <= 5 ORDER BY forum_cats.id ASC, MAX(forum_posts.datum) DESC When executing this code I get always the same number (1) for row_number, so this is not the result I want. Does anyone know how I can get this work? Thanks!

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  • PHP:Wrong Login info does not redirect to the specific page

    - by sdr
    <?php include 'lib/db_conn.php'; $uid=$_REQUEST['uid']; $pass=$_REQUEST['pass']; if(($uid==NULL && $pass==NULL) ||($uid==NULL) ||($pass==NULL)) { header("location:index.php?msg=Fields can't be left blank.."); } $pass=md5($pass); $sql1="SELECT * FROM `tb_user` WHERE `email`='$uid' AND `pass`='$pass'"; $rs1=mysql_query($sql1) or die (mysql_error()); $row1=mysql_fetch_array($rs1) or die (mysql_error()); $email=$row1['email']; if($uid==$email) { session_start(); $_SESSION['id']=$row1['id']; header("location:home.php"); } else { header("location:index.php?msg=Wrong Credentials.."); } ?>

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  • Database contents setting themselves to 0

    - by Luis Armando
    I have a Database that contains 4 tables, however I'm using 1 of them which is separated from the others. In this table I have 4 fields which are varchar and the rest are ints (11 other fields), when the users fill up the DB everything gets saved correctly, however it has happened 3 times so far that the database values for the int's reset to 0 without any apparent reason. At first, I thought, it was because those fields (where the numbers should go) were varchars not ints. However since I changed it, it happened again. I've already double checked my code and I have nothing that even updates or inserts a 0 value. Also I'm using codeigniter and active records which protect against SQL injections AND have XSS filtering enabled, could anyone point out something I might be missing or a reason for this to be happening? Also, I'm pretty sure about the answer of this but, is there ANY way to recover some data?? Other than having to ask everyone to fill in everything again.. =/ ** EDIT ** The Storage Engine is MyISAM and Collation is latin1_swedish_ci, Pack Keys are default, for all intents and purposes it's a normal DB

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  • mysqli_query SELECT FROM WHERE [ partial match ] ?

    - by user296516
    Hi guys, I have a database that a time filed that is stored in this format "2010.06.04. | 18:53 01". What I need is to select rows that have a specific date, for example "2010.06.04." Right now I am doing it my first selecting all rows and then looping through them and adding ones with the specified date to a new array. Maybe there is an easier way to do it and I somehow can select it using mysqli_query? Thanks!

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  • How Can I Join Two DB Tables and Return Lowest Price From Joined Table

    - by Jason
    I have two tables, the first table has the product and the second table the prices. The price table could have more than one price per product but I only want to display the lowest. But I keep getting all the prices returned and I'm having trouble figuring out how to do it. this is what I get returned in my query: SELECT * FROM products AS pr JOIN prices AS p ON pr.id = p.product_id WHERE pr.live = 1 AND p.live = 1 id product1 name description £100 id product1 name description £300 id product1 name description £200 id product2 name description £50 id product2 name description £80 id product2 name description £60 id product3 name description £222 id product3 name description £234 id product3 name description £235 but I'm after: id product1 name description £100 id product2 name description £50 id product3 name description £222 Any help would be appreciated

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  • Possible to sort via two time stamps and display same row twice.

    - by jamiethompson90
    I'm looking at creating a time table solution. I have a task sheet that looks like Area 1 item 1 startTime endTime Area 1 item1 startTime endTime I wish to create a display where I can view what even is happening next, either endTime or startTime i.e. Newcastle reel 16:45 18:45 Newcastle reel2 17:45 19:45 would output Newcastle reel 16:45 Newcastle reel 17:45 Newcastle reel 18:45 Newcastle reel 19:45 More so, I would like to detect if the time is a startTime or an endTime would I have to enter two rows for each activity (time,area,item, start|end). I can make the interface to the creation of two rows. I just wondered if there was a better solution. Any input is appreciated, Thanks, Jamie

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  • Perl daemon script for message queue hanging for 20 seconds after each process. Why?

    - by Mike Diena
    I have daemon script written in Perl that checks a database tables for rows, pulls them in one by one, sends the contents via HTTP post to another service, then logs the result and repeats (only a single child). When there are rows present, the first one is posted and logged immediately, but every subsequent one is delayed for around 20 seconds. There are no sleep()'s running, and I can't find any other obvious delays. Any ideas?

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  • how to join 3 relational tables

    - by orioncabbar
    Hello there, how to join 3 relational tables with the structure: t1 | id t2 | id | rating t3 | source_id | relation t3 stores the data of a field which t1 and t2 uses both. so source_id field can be t1's id or t2's id. input : t1 id output : t2 rating an example: **t1** id | --------- 42 | **t2** id | rating ------------- 37 | 9.2 **t3** id | source_id -------------- 42 | 1 37 | 1 26 | 2 23 | 1 what i want is to get 9.2 output with 42 input. can you do that in one sql query?

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  • Select 2 Rows from Table when COUNT of another table

    - by Marcus
    Here is the code that I currently have: SELECT `A`.* FROM `A` LEFT JOIN `B` ON `A`.`A_id` = `B`.`value_1` WHERE `B`.`value_2` IS NULL AND `B`.`userid` IS NULL ORDER BY RAND() LIMIT 2 What it currently is supposed to do is select 2 rows from A when the 2 rows A_id being selected are not in value_1 or value_2 in B. And the rows in B are specific to individual users with userid. What I need to do is make it also so that also checks if there are already N rows in B matching a A_id (either in value_1, or value_2) and userid, and if there are more than N rows, it doesn't select the A row.

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  • problem in creating a php tree menu

    - by Mac Taylor
    hi mates im writing a tree menu for my categories in php and i wonder how can i code it correctly ! this is my table in database " |----topicid------topicname--------parent | |---- 1 ------ News -------- 0 | |---- 2 ------ sport -------- 1 | |---- 3 ------ games -------- 1 | |---- 4 ------ PES -------- 3 | so now for showing it like a tree i did try but not worked : $result = mysql_query("SELECT * FROM Topics ORDER BY topicid"); while ($row = mysql_fetchrow($result)) { $id = intval($row['topicid']); $title = filter($row['topicname'], "nohtml"); $parent = $row['parent'] ; if ($parent==0) { $menu_item .= "<li><span class='folder'><a title = \"$alt\" href=\"modules.php?name=News&amp;new_topic=$id\">$title</a></span></li>"; }else { $result = mysql_query("SELECT * FROM ".$prefix."_Topics where parent='$id' ORDER BY topicid"); while ($row = mysql_fetchrow($result)) { $id = intval($row['topicid']); $title = filter($row['topicname'], "nohtml"); $parent = $row['parent'] ; $menu_item .= " <ul><li><span class='file'><a title = \"$alt\" href=\"modules.php?name=News&amp;new_topic=$id\">$title</a></span></li></ul>"; } } i dont know how to solve this

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  • How to do left joins with least-n-per-group query?

    - by Nate
    I'm trying to get a somewhat complicated query working and am not having any luck whatsoever. Suppose I have the following tables: cart_items: +--------------------------------------------+ | item_id | cart_id | movie_name | quantity | +--------------------------------------------+ | 0 | 0 | braveheart | 4 | | 1 | 0 | braveheart | 9 | | . | . | . | . | | . | . | . | . | | . | . | . | . | | . | . | . | . | +--------------------------------------------+ movies: +------------------------------+ | movie_id | movie_name | ... | +------------------------------+ | 0 | braveheart | . | | . | . | . | | . | . | . | | . | . | . | | . | . | . | +------------------------------+ pricing: +-----------------------------------------+ | id | movie_name | quantity | price_per | +-----------------------------------------+ | 0 | braveheart | 1 | 1.99 | | 1 | braveheart | 2 | 1.50 | | 2 | braveheart | 4 | 1.25 | | 3 | braveheart | 8 | 1.00 | | . | . | . | . | | . | . | . | . | | . | . | . | . | | . | . | . | . | | . | . | . | . | +-----------------------------------------+ I need to join the data from the tables, but with the added complexity that I need to get appropriate price_per from the pricing table. Only one price should be returned for each cart_item, and that should be the lowest price from the pricing table where the quantity for the cart item is at least the quantity in the pricing table. So, the query should return for each item in cart_items the following: +---------------------------------------------+ | item_id | movie_name | quantity | price_per | +---------------------------------------------+ Example 1: Variable passed to the query: cart_id = 0. Return: +---------------------------------------------+ | item_id | movie_name | quantity | price_per | +---------------------------------------------+ | 0 | braveheart | 4 | 1.25 | | 1 | braveheart | 9 | 1.00 | +---------------------------------------------+ Note that this is a minimalist example and that additional data will be pulled from the tables mentioned (particularly the movies table). How could this query be composed? I have tried using left joins and subqueries, but the difficult part is getting the price and nothing I have tried has worked. Thanks for your help. EDIT: I think this is similar to what I have working with my "real" tables: SELECT t1.item_id, t2.movie_name, t1.quantity FROM cart_items t1 LEFT JOIN movies t2 ON t2.movie_name = t1.movie_name WHERE t1.cart_id = 0 Assuming I wrote that correctly (I quickly tried to "port over" my real query), then the output would currently be: +---------------------------------+ | item_id | movie_name | quantity | +---------------------------------+ | 0 | braveheart | 4 | | 1 | braveheart | 9 | +---------------------------------+ The trouble I'm having is joining the price at a certain quantity for a movie. I simply cannot figure out how to do it.

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  • mysql_query where statment help

    - by Anders Kitson
    I am retrieving values from the url with the GET method and then using a if statement to determine of they are there then query them against the database to only show those items that match them, i get an unknown error with your request. here is my code $province = $_GET['province']; $city = $_GET['city']; if(isset($province) && isset($city) ) { $results3 = mysql_query("SELECT * FROM generalinfo WHERE province = $province AND city = $city ") or die( "An unknown error occurred with your request"); } else { $results3 = mysql_query("SELECT * FROM generalinfo"); } /*if statement ends*/

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  • How can I figure out a users postal code if I have their latitude / longitude location? Need help w

    - by mike
    I'm using HTML5 geolocation to collect the users lat / long and I need to figure out what their postal code is as well. I have a database of all the lat / long for each postal code in the US & Canada. How can I write a query to find out what their postal code is? Below, is an example of how the data is structured in the 'zips' table. Country PostalCode Latitude Longitude USA 0051 40.813078 -73.046388 USA 00616 18.426456 -66.673779 I can't do a 'SELECT PostalCode FROM zips WHERE Latitude = user.lat AND Longitude = user.long'. I believe I need to find the nearest lat / long. Any suggestions on how I can write this?

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  • While loop in foreach loop not looping correctly

    - by tominated
    I'm trying to make a very basic php ORM as for a school project. I have got almost everything working, but I'm trying to map results to an array. Here's a snippet of code to hopefully assist my explanation. $results = array(); foreach($this->columns as $column){ $current = array(); while($row = mysql_fetch_array($this->results)){ $current[] = $row[$column]; print_r($current); echo '<br><br>'; } $results[$column] = $current; } print_r($results); return mysql_fetch_array($this->results); This works, but the while loop only works on the first column. The print_r($results); shows the following: Array ( [testID] => Array ( [0] => 1 [1] => 2 ) [testName] => Array ( ) [testData] => Array ( ) ) Can anybody shed some light? Thanks in advance!

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  • Zend Framework multiple databases

    - by Uffo
    I'm currently using only one database with Zend Framework, but now I have to add ONE MORE. I'm using this code right now: public static function setupDatabase() { $config = self::$registry->configuration; $db = Zend_Db::factory($config->db->adapter, $config->db->toArray()); $db->query("SET NAMES 'utf8'"); self::$registry->database = $db; Zend_Db_Table::setDefaultAdapter($db); } What code do I need to write in order to use ONE MORE database; and how I will reference it, when I need to make some queries or so.. Best Regards!

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  • COUNT issue across multiple tables

    - by Kim
    I am trying to count across 2 tables and I dont see whats wrong with my query yet I get a wrong result. User 2 does not exist in table_two, so the zero is correct. SELECT t1.creator_user_id, COUNT(t1.creator_user_id), COUNT(t2.user_id) FROM table_one AS t1 LEFT JOIN table_two AS t2 ON t2.user_id = t1.creator_user_id GROUP BY t1.creator_user_id, t2.user_id Actual result 1 192 192 2 9 0 Expected result 1 16 12 2 9 0 The result indicate a missing group by condition, but I already got both fields used. Where am I wrong ? Also, can I sum up all users that doesnt exist in table_two for t1 ? Like user 3 exists 21 times in t1, then the results would be: 1 16 12 (users with > 0 in t2 will need their own row) 2 30 0 (user 2=9 + user 3=21 => 30) Its okay for the user Id to be wrong for sum of t1 for all users with 0 in t2. If not possible, then I'll just do two queries.

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  • SQL - How to display the students with the same age?

    - by Cristian
    the code I wrote only tells me how many students have the same age. I want their names too... SELECT YEAR(CURRENT DATE-DATEOFBIRTH) AS AGE, COUNT(*) AS HOWMANY FROM STUDENTS GROUP BY YEAR(CURRENT DATE-DATEOFBIRTH); this returns something like this: AGE HOWMANY --- ------- 21 3 30 5 Thank you. TABLE STUDENTS COLUMNS: StudentID (primary key), Name(varchar), Firstname(varchar), Dateofbirth(varchar) I was thinking of maybe using the code above and somewhere add the function concat that will put the stundents' names on the same row as in

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