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  • Allowing users to delete their own comments in Django

    - by RaDeuX
    I am using the delete() function from django.contrib.comments.views.moderation module. The staff-member is allowed to delete ANY comment posts, which is completely fine. However, I would also like to give registered non-staff members the privilege to delete their OWN comment posts, and their OWN only. How can I accomplish this?

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  • Graphics glitch when drawing to a Cairo context obtained from a gtk.DrawingArea inside a gtk.Viewport.

    - by user410023
    I am trying to redraw the part of the DrawingArea that is visible in the Viewport in the expose-event handler. However, it seems that I am doing something wrong with the coordinates that are passed to the event handler because there is garbage at the edge of the Viewport when scrolling. Can anyone tell what I am doing wrong? Here is a small example: import pygtk pygtk.require("2.0") import gtk from numpy import array from math import pi class Circle(object): def init(self, position = [0., 0.], radius = 0., edge = (0., 0., 0.), fill = None): self.position = position self.radius = radius self.edge = edge self.fill = fill def draw(self, ctx): rect = array(ctx.clip_extents()) rect[2] -= rect[0] rect[3] -= rect[1] center = rect[2:4] / 2 ctx.arc(center[0], center[1], self.radius, 0., 2. * pi) if self.fill != None: ctx.set_source_rgb(*self.fill) ctx.fill_preserve() ctx.set_source_rgb(*self.edge) ctx.stroke() class Scene(object): class Proxy(object): directory = {} def init(self, target, layers = set()): self.target = target self.layers = layers Scene.Proxy.directory[target] = self def __init__(self, viewport): self.objects = {} self.layers = [set()] self.viewport = viewport self.signals = {} def draw(self, ctx): x = self.viewport.get_hadjustment().value y = self.viewport.get_vadjustment().value ctx.set_source_rgb(1., 1., 1.) ctx.paint() ctx.translate(x, y) for obj in self: obj.draw(ctx) def add(self, item, layer = 0): item = Scene.Proxy(item, layers = set((layer,))) assert(hasattr(item.target, "draw")) assert(isinstance(layer, int)) item.layers.add(layer) while not layer < len(self.layers): self.layers.append(set()) self.layers[layer].add(item) if not item in self.objects: self.objects[item] = set() self.objects[item].add(layer) def remove(self, item, layers = None): item = Scene.Proxy.directory[item] if layers == None: layers = self.objects[item] for layer in layers: layer.remove(item) item.layers.remove(layer) if len(item.layers) == 0: self.objects.remove(item) def __iter__(self): for layer in self.layers: for item in layer: yield item.target class App(object): def init(self): signals = { "canvas_exposed": self.update_canvas, "gtk_main_quit": gtk.main_quit } self.builder = gtk.Builder() self.builder.add_from_file("graphics_glitch.glade") self.window = self.builder.get_object("window") self.viewport = self.builder.get_object("viewport") self.canvas = self.builder.get_object("canvas") self.scene = Scene(self.viewport) signals.update(self.scene.signals) self.builder.connect_signals(signals) self.window.show() def update_canvas(self, widget, event): ctx = self.canvas.window.cairo_create() self.scene.draw(ctx) ctx.clip() if name == "main": app = App() scene = app.scene scene.add(Circle((0., 0.), 10.)) gtk.main() And the Glade file "graphics_glitch.glade": <?xml version="1.0"?> <interface> <requires lib="gtk+" version="2.16"/> <!-- interface-naming-policy project-wide --> <object class="GtkWindow" id="window"> <property name="width_request">200</property> <property name="height_request">200</property> <property name="visible">True</property> <signal name="destroy" handler="gtk_main_quit"/> <child> <object class="GtkScrolledWindow" id="scrolledwindow1"> <property name="visible">True</property> <property name="can_focus">True</property> <property name="hadjustment">h_adjust</property> <property name="vadjustment">v_adjust</property> <property name="hscrollbar_policy">automatic</property> <property name="vscrollbar_policy">automatic</property> <child> <object class="GtkViewport" id="viewport"> <property name="visible">True</property> <property name="resize_mode">queue</property> <child> <object class="GtkDrawingArea" id="canvas"> <property name="width_request">640</property> <property name="height_request">480</property> <property name="visible">True</property> <signal name="expose_event" handler="canvas_exposed"/> </object> </child> </object> </child> </object> </child> </object> <object class="GtkAdjustment" id="h_adjust"> <property name="lower">-1000</property> <property name="upper">1000</property> <property name="step_increment">1</property> <property name="page_increment">25</property> <property name="page_size">25</property> </object> <object class="GtkAdjustment" id="v_adjust"> <property name="lower">-1000</property> <property name="upper">1000</property> <property name="step_increment">1</property> <property name="page_increment">25</property> <property name="page_size">25</property> </object> </interface> Thanks! --Dan

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  • How to replace a Widget with another using Qt ?

    - by Natim
    Hi, I have an QHBoxLayout with a QTreeWidget on the left, a separator on the middle and a widget on the right. When I click on the QTreeWidget, I want to change the widget on the right to modify the QTreeWidgetItem I tried to do this with this code : def new_rendez_vous(self): self.ui.horizontalLayout_4.removeWidget(self.ui.editionFormWidget) del self.ui.editionFormWidget self.ui.editionFormWidget = RendezVousManagerDialog(self.parent) self.ui.editionFormWidget.show() self.ui.horizontalLayout_4.addWidget(self.ui.editionFormWidget) self.connect(self.ui.editionFormWidget, QtCore.SIGNAL('saved'), self.scheduleTreeWidget.updateData) def edit(self, category, rendez_vous): self.ui.horizontalLayout_4.removeWidget(self.ui.editionFormWidget) del self.ui.editionFormWidget self.ui.editionFormWidget = RendezVousManagerDialog(self.parent, category, rendez_vous) self.ui.editionFormWidget.show() self.ui.horizontalLayout_4.addWidget(self.ui.editionFormWidget) self.connect(self.ui.editionFormWidget, QtCore.SIGNAL('saved'), self.scheduleTreeWidget.updateData) def edit_category(self, category): self.ui.horizontalLayout_4.removeWidget(self.ui.editionFormWidget) del self.ui.editionFormWidget self.ui.editionFormWidget = CategoryManagerDialog(self.parent, category) self.ui.editionFormWidget.show() self.ui.horizontalLayout_4.addWidget(self.ui.editionFormWidget) self.connect(self.ui.editionFormWidget, QtCore.SIGNAL('saved'), self.scheduleTreeWidget.updateData) But it doesn't work and all the widgets are stacked up on each other : . Do you know how I can remove the old widget and next display the new one ?

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  • Intersection of two querysets in django

    - by unagimiyagi
    Hello, I can't do an AND on two querysets. As in, q1 & q2. I get the empty set and I do not know why. I have tested this with the simplest cases. I am using django 1.1.1 I have basically objects like this: item1 name="Joe" color = "blue" item2 name="Jim" color = "blue" color = "white" item3 name="John" color = "red" color = "white" Is there something weird about having a many-to-many relationship or what am I missing? queryset1 = Item.objects.filter(color="blue") this gives (item1, item2) queryset2 = Item.objects.filter(color="white") this gives (item2, item3) queryset1 & queryset2 gives me the empty set [] The OR operator works fine (I'm using "|" ) Why is this so?

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  • Django database caching

    - by hekevintran
    I have a Django form that uses an integer field to lookup a model object by its primary key. The form has a save() method that uses the model object referred to by the integer field. The model's manager's get() method is called twice, once in the clean method and once in the save() method: class MyForm(forms.Form): id_a = fields.IntegerField() def clean_id_a(user_id): id_a = self.cleaned_data['id_a'] try: # here is the first call to get MyModel.objects.get(id=id_a) except User.DoesNotExist: raise ValidationError('Object does not exist') def save(self): id_a = self.cleaned_data['id_a'] # here is the second call to get my_model_object = MyModel.objects.get(id=id_a) # do other stuff I wasn't sure whether this hits the database two times or one time so I returned the object itself in the clean method so that I could avoid a second get() call. Does calling get() hit the database two times? Or is the object cached in the thread? class MyForm(forms.Form): id_a = fields.IntegerField() def clean_id_a(user_id): id_a = self.cleaned_data['id_a'] try: # here is my workaround return MyModel.objects.get(id=id_a) except User.DoesNotExist: raise ValidationError('Object does not exist') def save(self): # looking up the cleaned value returns the model object my_model_object = self.cleaned_data['id_a'] # do other stuff

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  • Scraping paginated items from a website using scrapy

    - by Mridang Agarwalla
    I'm using scrapy to scrape items from a site. I'm not being able to implement this scraping pattern. The site I'm trying to scrape is a forum and I scrape the site once a day. Each page has a table containing posts. New posts are added to the top of the table and as more and more posts are posted to the site, the older posts go further into the pages due to pagination. This is a very simple scenario and we will assume that the order of the posts never change. I would like to scrape this site and scrape all the "new" records until the last scraped post from yesterday is encountered. I have configured my spider to paginate endlessly and when it encounters yesterday's last scraped post, it should stop. How can implement this? (My Scrapy installation works with my Django installation using django-dynamic-scraper )

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  • the error "invalid literal for int() with base 10:" keeps coming up

    - by ratce003
    I'm trying to write a very simple program, I want to print out the sum of all the multiples of 3 and 5 below 100, but, an error keeps accuring, saying "invalid literal for int() with base 10:" my program is as follows: sum = "" sum_int = int(sum) for i in range(1, 101): if i % 5 == 0: sum += i elif i % 3 == 0: sum += i else: sum += "" print sum Any help would be much appreciated.

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  • Non-global middleware in Django

    - by hekevintran
    In Django there is a settings file that defines the middleware to be run on each request. This middleware setting is global. Is there a way to specify a set of middleware on a per-view basis? I want to have specific urls use a set of middleware different from the global set.

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  • downloading archives response corrupts files

    - by panchicore
    wrapper = FileWrapper(file("C:/pics.zip")) content_type = mimetypes.guess_type(result.files)[0] response = HttpResponse(wrapper, content_type=content_type) response['Content-Length'] = os.path.getsize("C:/pics.zip") response['Content-Disposition'] = "attachment; filename=pics.zip" return response pics.zip is a valid file with 3 pictures inside. server response the download, but when I am going to open the zip, winrar says This archive is either in unknown format or damaged! If I change the file path and the file name to a valid image C:/pic.jpg is downloaded damaged too. What Im missing in this download view?

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  • A graph-based tuple merge?

    - by user1644030
    I have paired values in tuples that are related matches (and technically still in CSV files). Neither of the paired values are necessarily unique. tupleAB = (A####, B###), (A###, B###), (A###, B###)... tupleBC = (B####, C###), (B###, C###), (B###, C###)... tupleAC = (A####, C###), (A###, C###), (A###, C###)... My ideal output would be a dictionary with a unique ID and a list of "reinforced" matches. The way I try to think about it is in a graph-based context. For example, if: tupleAB[x] = (A0001, B0012) tupleBC[y] = (B0012, C0230) tupleAC[z] = (A0001, C0230) This would produce: output = {uniquekey0001, [A0001, B0012, C0230]} Ideally, this would also be able to scale up to more than three tuples (for example, adding a "D" match that would result in an additional three tuples - AD, BD, and CD - and lists of four items long; and so forth). In regards to scaling up to more tuples, I am open to having "graphs" that aren't necessarily fully connected, i.e., every node connected to every other node. My hunch is that I could easily filter based on the list lengths. I am open to any suggestions. I think, with a few cups of coffee, I could work out a brute force solution, but I thought I'd ask the community if anyone was aware of a more elegant solution. Thanks for any feedback.

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  • Sending data from one Protocol to another Protocol in Twisted?

    - by veb
    Hi! One of my protocols is connected to a server, and with the output of that I'd like to send it to the other protocol. I need to access the 'msg' method in ClassA from ClassB but I keep getting: exceptions.AttributeError: 'NoneType' object has no attribute 'write' Actual code: http://pastebin.com/MQPhduSY Any ideas please? :-)

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  • Selective emboldeing of text in a webpage

    - by Eknath Iyer
    while printing out utf-8 characters onto a webpage, if encapsulate them with they get emboldened, but anything else, the page turns blank. Why? def main(): print "Content-type: text/html\r\n\r\n"; print '<html>' print '<head>' print '<style type="text/css">' print '.highlight { background-color: yellow }' print '.color1 { color: green; }' print '.color2 { color: blue; }' print '.color3 { color: purple; }' print '.color4 { color: red; }' print '.color5 { color: teal; }' print '.color6 { color: yellow; }' print '.color7 { color: orange; }' print '.color8 { color: violet; }' print '</style></head>' print '<body>' form = cgi.FieldStorage() ch = form.getvalue('choice') if ch == 'English': in_sent = form.getvalue('f1') in_sent = in_sent.lower() cho=0 elif ch == 'Hindi': in_sent = trans_he(form.getvalue('transl1').decode("utf-8")).strip() cho=1 #cho = 0 for english #cho = 1 for hindi adict=[] print '<center><u> User Input Sentence ==> <b>', in_sent,'</b></u></center><br>' in_sent=in_sent.strip().split(' ') colordict={} counter=1 for word in in_sent: colordict[word]=counter counter = counter + 1 f = open('bidirectional.alignment.txt','rb').read() records=f.strip().split('\n\n\n') for record in records: el=[] el2 = [] #basic file processing is done here. record = record.strip().split('\n') source = record[cho] target = record[(cho+1)%2] source_sent = source.split(' # ')[1] target_sent = target.split(' # ')[1] source_words = source_sent.strip().split(' ') target_words = target_sent.strip().split(' ') trans_index = source.split(' # ')[2].strip().split(' ') for word in in_sent: if word in source_words: if int(trans_index[source_words.index(word)]) > 0: tword=target_words[(int(trans_index[source_words.index(word)])-1)] target_sent = target_sent.replace(tword+' ','<b>'+tword+' </b>') # When the <b> tag is used here(for the 'target_sent = ...' statement). it is fine. But when <b> is replaced by something like in the next line or even <i> or <u>, it doesn't show an output at all source_sent = source_sent.replace(word+' ','<span class="color1">'+word+' </span>') el2.append(source_sent) el2.append(target_sent) el.append(target_sent.count('<b>')) el.append(el2) if target_sent.count('<b>') > 0: adict.append(el) print '<table><tr><td><center><h1>SOURCE LANGUAGE</h1></center></td><td><center> <h1>TARGET LANGUAGE</h1></center></td></tr>' for entry in adict: print '<tr><td>',entry[1][0],'</td><td>',trans_eh(entry[1][1]).encode("utf-8"),'</td> </tr>' print '</table></body>' print '</html>' main()

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  • Programatically Determining Bin Path

    - by Andy
    I'm working on a web app called pj and there is a bin file and a src folder. The relative paths before I deploy the app will look something like: pj/bin and pj/src/pj/script.py. However, after deployment, the relative paths will look like: pj_dep/deployed/bin and pj_dep/deployed/lib/python2.6/site-packages/pj/script.py Question: Within script.py, I am trying to find the path of a file in the bin directory. This leads to 2 different behaviors in the dev and deployment environment. If I do os.path.join(os.path.dirname(__file__), 'bin') to try to get the path for the dev environment, I will have a different path for the deployment environment. Is there a more generalized way I can find the bin directory so that I do not need to rely on an if statement to determine how many directories to go up based on the current env? This doesn't seem flexible and might cause other issues later on when the code is moved.

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  • How to clone a mercurial repository over an ssh connection initiated by fabric when http authorizati

    - by Monika Sulik
    I'm attempting to use fabric for the first time and I really like it so far, but at a certain point in my deployment script I want to clone a mercurial repository. When I get to that point I get an error: err: abort: http authorization required My repository requires http authorization and fabric doesn't prompt me for the user and password. I can get around this by changing my repository address from: https://hostname/repository to: https://user:password@hostname/repository But for various reasons I would prefer not to go this route. Are there any other ways in which I could bypass this problem?

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  • In Elixir or SQLAlchemy, is there a way to also store a comment for a/each field in my entities?

    - by kchau
    Our project is basically a web interface to several systems of record. We have many tables mapped, and the names of each column aren't as well named and intuitive as we'd like... The users would like to know what data fields are available (i.e. what's been mapped from the database). But, it's pointless to just give them column names like: USER_REF1, USER_REF2, etc. So, I was wondering, is there a way to provide a comment in the declaration of my field? E.g. class SegregationCode(Entity): using_options(tablename="SEGREGATION_CODES") segCode = Field(String(20), colname="CODE", ... primary_key=True) #Have a comment attr too? If not, any suggestions?

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  • Sort a list of tuples without case sensitivity

    - by dound
    How can I efficiently and easily sort a list of tuples without being sensitive to case? For example this: [('a', 'c'), ('A', 'b'), ('a', 'a'), ('a', 5)] Should look like this once sorted: [('a', 5), ('a', 'a'), ('A', 'b'), ('a', 'c')] The regular lexicographic sort will put 'A' before 'a' and yield this: [('A', 'b'), ('a', 5), ('a', 'a'), ('a', 'c')]

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  • Technique to remove common words(and their plural versions) from a string

    - by Jake M
    I am attempting to find tags(keywords) for a recipe by parsing a long string of text. The text contains the recipe ingredients, directions and a short blurb. What do you think would be the most efficient way to remove common words from the tag list? By common words, I mean words like: 'the', 'at', 'there', 'their' etc. I have 2 methodologies I can use, which do you think is more efficient in terms of speed and do you know of a more efficient way I could do this? Methodology 1: - Determine the number of times each word occurs(using the library Collections) - Have a list of common words and remove all 'Common Words' from the Collection object by attempting to delete that key from the Collection object if it exists. - Therefore the speed will be determined by the length of the variable delims import collections from Counter delim = ['there','there\'s','theres','they','they\'re'] # the above will end up being a really long list! word_freq = Counter(recipe_str.lower().split()) for delim in set(delims): del word_freq[delim] return freq.most_common() Methodology 2: - For common words that can be plural, look at each word in the recipe string, and check if it partially contains the non-plural version of a common word. Eg; For the string "There's a test" check each word to see if it contains "there" and delete it if it does. delim = ['this','at','them'] # words that cant be plural partial_delim = ['there','they',] # words that could occur in many forms word_freq = Counter(recipe_str.lower().split()) for delim in set(delims): del word_freq[delim] # really slow for delim in set(partial_delims): for word in word_freq: if word.find(delim) != -1: del word_freq[delim] return freq.most_common()

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  • The dictionary need to add every word in SpellingMistakes and the line number but it only adds the l

    - by Will Boomsight
    modules import sys import string Importing and reading the files form the Command Prompt Document = open(sys.argv[1],"r") Document = open('Wc.txt', 'r') Document = Document.read().lower() Dictionary = open(sys.argv[2],"r") Dictionary = open('Dict.txt', 'r') Dictionary = Dictionary.read() def Format(Infile): for ch in string.punctuation: Infile = Infile.replace(ch, "") for no in string.digits: Infile = Infile.replace(no, " ") Infile = Infile.lower() return(Infile) def Corrections(Infile, DictWords): Misspelled = set([]) Infile = Infile.split() DictWords = DictWords.splitlines() for word in Infile: if word not in DictWords: Misspelled.add(word) Misspelled = sorted(Misspelled) return (Misspelled) def Linecheck(Infile,ErrorWords): Infile = Infile.split() lineno = 0 Noset = list() for line in Infile: lineno += 1 line = line.split() for word in line: if word == ErrorWords: Noset.append(lineno) sorted(Noset) return(Noset) def addkey(error,linenum): Nodict = {} for line in linenum: Nodict.setdefault(error,[]).append(linenum) return Nodict FormatDoc = Format(Document) SpellingMistakes = Corrections(FormatDoc,Dictionary) alp = str(SpellingMistakes) for word in SpellingMistakes: nSet = str(Linecheck(FormatDoc,word)) nSet = nSet.split() linelist = addkey(word, nSet) print(linelist) # # for word in Nodict.keys(): # Nodict[word].append(line) Prints each incorrect word on a new line

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  • Django: Summing values

    - by Anry
    I have a two Model - Project and Cost. class Project(models.Model): title = models.CharField(max_length=150) url = models.URLField() manager = models.ForeignKey(User) class Cost(models.Model): project = models.ForeignKey(Project) cost = models.FloatField() date = models.DateField() I must return the sum of costs for each project. view.py: from mypm.costs.models import Project, Cost from django.shortcuts import render_to_response from django.db.models import Avg, Sum def index(request): #... return render_to_response('index.html',... How?

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