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  • How to change icon/emblem of a directory from bash

    - by Question Mark
    I'm playing around with get_iplayer (fantastic) it's running every few hours to grab any new episodes of whatever.... After it has finished grabbing anything new i'd like to change the emblem of ~/Videos to add a plus or star (nautilus emblem preferably) Do i go about this via nautilus? Do i need to change something in gnome-config? I'm sure this can't be FS level? Cheers for any links and advice.

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  • Format stdin in bash

    - by User1
    I have a multi-line string coming from another program that I want to convert to a SQL command. I was hoping that printf could help me, but it doesn't seem to work: echo -e '1\n2\n3'|printf 'SELECT %s INTO MyTable' I was hoping to see: SELECT '1 2 3' INTO MyTable But I got: SELECT INTO MyTable How can I get the %s to read stdin?

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  • Writing " to a file in bash.

    - by S1syphus
    Simply I need to write "echo" t${count} = "$"t${count}" To a text file, including all the So the output would be something like: echo " t1 = $t1" With " as they are. So I have tried: count=1 saveIFS="$IFS" IFS=$'\n' array=($(<TEST.txt)) IFS="$saveIFS" for i in "${array[@]}" do echo "echo" t${count} = "$"t${count}"" (( count++ )) done >> long1.txt And variations on this such as: echo "echo" """"" t${count} = "$"t${count}"" But I guess the wrapping in double " is only for variables. Ideas?

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  • How to prevent filename expansion in for loop in bash

    - by cagri
    In a for loop like this, for i in `cat *.input`; do echo "$i" done if one of the input file contains entries like *a, it will, and give the filenames ending in 'a'. Is there a simple way of preventing this filename expansion? Because of use of multiple files, globbing (set -o noglob) is not a good option. I should also be able to filter the output of cat to escape special characters, but for i in `cat *.input | sed 's/*/\\*'` ... still causes *a to expand, while for i in `cat *.input | sed 's/*/\\\\*'` ... gives me \*a (including backslash). [ I guess this is a different question though ]

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  • Replacing a column in CSV file with another in bash

    - by user2525881
    I have a csv file with a number of columns. I am trying to replace the second column with the second to last column from the same file. For example, if I have a file, sample.csv 1,2,3,4,5,6 a,b,c,d,e,f g,h,i,j,k,l I want to output: 1,5,3,4,5,6 a,e,c,d,e,f g,k,i,j,k,l Can anyone help me with this task? Also note that I will be discarding the last two columns afterwards with the cut function so I am open to separating the csv file to begin with so that I can replace the column in one csv file with another column from another csv file. Whichever is easier to implement. Thanks in advance for any help.

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  • Resolve bash variable containted in another variable

    - by kogut
    I have code like that: TEXT_TO_FILTER='I would like to replace this $var to proper value' var=variable All I want to get is: TEXT_AFTER_FILTERED="I'd like to replace this variable to proper value" So I did: TEXT_AFTER_FILTERED=`eval echo $TEXT_TO_FILTER` TEXT_AFTER_FILTERED=`eval echo $(eval echo $TEXT_TO_FILTER)` Or even more weirder things, but without any effects. I remember that someday I had similar problem and I did something like that: cat << EOF > tmp.sh echo $TEXT_TO_FILTER EOF chmod +x tmp.sh TEXT_AFTER_FILTERED=`. tmp.sh` But this solution seems to be to much complex. Have any of You heard about easier solution?

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  • help with using alias in bash shell

    - by ajsie
    i want to have an alias "t" to enter a folder and list the content there. i tried with: alias t="cd $1; ls -la" but it just listed the folder i typed but did not enter it. i wonder why? cause when i use this one: alias b="cd ..; ls" it went back to the parent and listed the content. so i want the "t" do enter the folder i type in too. someone knows how to do this right?

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  • Unexpected variable update when using bash's $(( )) operator for arithmetic

    - by philo
    I'm trying to trim a few lines from a file. I know exactly how many lines to remove (say, 2 from the top), but not how many total lines are in the file. So I tried this straightforward solution: $ wc -l $FILENAME 119559 my_filename.txt $ LINES=$(wc -l $FILENAME | awk '{print $1}') $ tail -n $(($LINES - 2)) $FILENAME > $OUTPUT_FILE The output is fine, but what happened to LINES?? $ wc -l $OUTPUT_FILE 119557 my_output_file.txt $ echo $LINES 107 Hoping someone can help me understand what's going on.

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  • Add a file in a folder with bash

    - by CuriousGeorge
    I have figured out how to remove bad files in my folders but I am wanting to know how to add certain named files to that folder. I want to add something like address.xml I have this and can remove the bad files. for addxml in $(find $DIRECTORY/$directoryname -name address.xml); do rm -v $addxml done I am trying to learn how later down the code I can add a file from another folder no where near the folders that are being edited.

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  • Bash scripting - Iterating through "variable" variable names for a list of associative arrays

    - by user1550254
    I've got a variable list of associative arrays that I want to iterate through and retrieve their key/value pairs. I iterate through a single associative array by listing all its keys and getting the values, ie. for key in "${!queue1[@]}" do echo "key : $key" echo "value : ${queue1[$key]}" done The tricky part is that the names of the associative arrays are variable variables, e.g. given count = 5, the associative arrays would be named queue1, queue2, queue3, queue4, queue5. I'm trying to replace the sequence above based on a count, but so far every combination of parentheses and eval has not yielded much more then bad substitution errors. e.g below: for count in {1,2,3,4,5} do for key in "${!queue${count}[@]}" do echo "key : $key" echo "value : ${queue${count}[$key]}" done done Help would be very much appreciated!

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  • Source From Standard In (Bash on OSX)

    - by yar
    I am trying to do something like this ruby test.rb | source /dev/stdin where test.rb just prints out cd /. There are no errors, but it doesn't do anything either. If I use this: ruby test.rb > /eraseme; source /eraseme it works fine, but I want to avoid the intermediate file.

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  • bash "map" equivalent: run command on each file

    - by Claudiu
    I often have a command that processes one file, and I want to run it on every file in a directory. Is there any built-in way to do this? For example, say I have a program data which outputs an important number about a file: ./data foo 137 ./data bar 42 I want to run it on every file in the directory in some manner like this: map data `ls *` ls * | map data to yield output like this: foo: 137 bar: 42

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  • How to make this if statement in bash

    - by Selmak
    Hi, I'm having a hard time figuring out how to do this if statement. I want to do this: IF (the function has only 1 argument AND $1 is a directory (in the current folder)) OR IF (the function has 2 arguments AND $1 is NOT a directory ) THEN .... END Sorry if it's not very clear, Thanks in advance

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  • ImageMagick bash script issue

    - by gAMBOOKa
    // This works convert ${path}${dst} -crop ${crop} ${path}${dst} // but when changed to this, it fails convert ${path}${src} -trim ${path}${dst} convert ${path}${dst} -crop ${crop} ${path}"pdf_"${dst} What am I doing wrong?

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  • Need a very simple bash-based webserver for logging XML in HTTP POST

    - by Syffys
    As in title, it's for testing purpose and I need it to be extremely light (1 line to 1 single light file). Here is a XML query sample: XML_QUERY=$(cat <<EOF <?xml version='1.0' encoding='UTF-8'?> <Test></Test> EOF ) curl -H "Content-type: text/xml; charset=utf-8" -H "Soapaction: \"\"" -k -d "${XML_QUERY}" http://localhost:8088 Here are some of the tracks I have found so far even if I wasnt able to adapt them to work as I expect: Netcat minimal webserver: Problem is that my nc does not have the -q option, so the connection is closing before delivering the XML content Netcat Only webserver: Same as above Python based: But does not handle POST Thanks in advance!

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  • Getting a partial path to a file in a bash script

    - by Massif
    I have a path that is stored in a variable $FULLPATH="/this/is/the/path/to/my/file.txt" I also have another variable containing a partial path $PARTIAL="/this/is/the/" I want to remove the partial path from the full path so that I am left with: path/to/my/file.txt What's the best way to do this?

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