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  • How can I sort a DataGridTemplateColumn on a WPF Toolkit DataGrid?

    - by Kilhoffer
    I have a WPF Toolkit DataGrid with one DataGridTemplateColumn. I've specified in a grid attribute that I wish all columns to be sortable, but the DataGridTemplateColumn won't allow it. All other columns do allow sorting. I've even tried explicitly setting CanUserSort to true for that column, but no luck. Is it even possible to sort a template column? I've provided a custom sorter that works for all columns, but the header won't allow a sort click. <Controls:DataGrid ItemsSource="{Binding Events}" AutoGenerateColumns="False" CanUserSortColumns="True" CanUserReorderColumns="False" Sorting="DataGrid_Sorting" x:Name="EventsGrid"> <Controls:DataGrid.Columns> <Controls:DataGridTemplateColumn Header="Type" Width="42" CanUserResize="False"> <Controls:DataGridTemplateColumn.CellTemplate> <DataTemplate> <Image Source="{Binding EventTypeImage, Mode=OneWay}" HorizontalAlignment="Center" Width="16"/> </DataTemplate> </Controls:DataGridTemplateColumn.CellTemplate> </Controls:DataGridTemplateColumn> <Controls:DataGridTextColumn Header="Source" Binding="{Binding Source, Mode=OneWay}" /> <Controls:DataGridTextColumn Header="Details" MinWidth="175" Binding="{Binding Details, Mode=OneWay}" /> <Controls:DataGridTextColumn Header="Timestamp" MinWidth="175" Binding="{Binding Timestamp, Mode=OneWay}" IsReadOnly="True"/> </Controls:DataGrid.Columns> </Controls:DataGrid>

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  • How to Sort ip addresses and merge two files in efficent manner using perl or *nix commands?

    - by berkay
    (*) This problem should be done in perl or any *nix commands. i'm working on a program and efficiency matters.The file1 consists ip addresses and some other data: index ipsrc portsrc ip dest port src 8 128.3.45.10 2122 169.182.111.161 80 (same ip src and dst) 9 128.3.45.10 2123 169.182.111.161 22 (same ip src and dst) 10 128.3.45.10 2124 169.182.111.161 80 (same ip src and dst) 19 128.3.45.128 62256 207.245.43.126 80 and other file2 looks like (file1 and file2 are in different order) 128.3.45.10 ioc-sea-lm 169.182.111.161 microsoft-ds 0 0 3 186 3 186 128.3.45.10 hypercube-lm 169.182.111.161 https 0 0 3 186 3 186 128.3.44.112 pay-per-view 148.184.171.6 netbios-ssn 0 0 3 186 3 186 128.3.45.12 cadabra-lm 148.184.171.6 microsoft-ds 0 0 3 186 3 186 1- SORT file1 using IP address in second column and SORT file2 using IP address in first column 2- Merge the 1st, 3rd and 5th columns of File1 with File 2 i need to create a new file which will look: 128.3.45.10 ioc-sea-lm 169.182.111.161 microsoft-ds 0 0 3 186 3 186 --> 2122 80 8 128.3.45.10 hypercube-lm 169.182.111.161 https 0 0 3 186 3 186 --> 2123 22 9 128.3.44.112 pay-per-view 148.184.171.6 netbios-ssn 0 0 3 186 3 186 --> * * * 128.3.45.12 cadabra-lm 148.184.171.6 microsoft-ds 0 0 3 186 3 186 --> * * * basically port numbers and index number will be added.

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  • How to sort the file names in bash in this circumstance?

    - by Nicolas
    I have run a program to generate some results with the different parameters(i.e. the R, C and RP). These results are saved in files named results.txt. Then, I should parse these experimental results to make an analysis. In the params_R_7_C_16_RP_0, the 7 is the value of the parameter R, the 16 is the value of the parameter C and the 0 is the value of the parameter RP. Now, I want to get these results.txt files in the current directory to parse, and sort the path with the parameter values of R,C and RP. I first use the following command to get the results.txt files that I want to parse: find ./ -name "results.txt" and the output is: ./params_R_11_C_9_RP_0/results.txt ./params_R_7_C_9_RP_0/results.txt ./params_R_7_C_4_RP_0/results.txt ./params_R_11_C_16_RP_0/results.txt ./params_R_9_C_4_RP_0/results.txt ./params_R_5_C_9_RP_0/results.txt ./params_R_9_C_25_RP_0/results.txt ./params_R_7_C_16_RP_0/results.txt ./params_R_5_C_25_RP_0/results.txt ./params_R_5_C_16_RP_0/results.txt ./params_R_11_C_4_RP_0/results.txt ./params_R_9_C_16_RP_0/results.txt ./params_R_7_C_25_RP_0/results.txt ./params_R_15_C_4_RP_0/results.txt ./params_R_5_C_4_RP_0/results.txt ./params_R_9_C_9_RP_0/results.txt and I change the command as follows: find ./ -name "results.txt" | sort and the output is: ./params_R_11_C_16_RP_0/results.txt ./params_R_11_C_25_RP_0/results.txt ./params_R_11_C_4_RP_0/results.txt ./params_R_11_C_9_RP_0/results.txt ./params_R_5_C_16_RP_0/results.txt ./params_R_5_C_25_RP_0/results.txt ./params_R_5_C_4_RP_0/results.txt ./params_R_5_C_9_RP_0/results.txt ./params_R_7_C_16_RP_0/results.txt ./params_R_7_C_25_RP_0/results.txt ./params_R_7_C_4_RP_0/results.txt ./params_R_7_C_9_RP_0/results.txt ./params_R_9_C_16_RP_0/results.txt ./params_R_9_C_25_RP_0/results.txt ./params_R_9_C_4_RP_0/results.txt ./params_R_9_C_9_RP_0/results.txt But I want it output as following: ./params_R_5_C_4_RP_0/results.txt ./params_R_5_C_9_RP_0/results.txt ./params_R_5_C_16_RP_0/results.txt ./params_R_5_C_25_RP_0/results.txt ./params_R_7_C_4_RP_0/results.txt ./params_R_7_C_9_RP_0/results.txt ./params_R_7_C_16_RP_0/results.txt ./params_R_7_C_25_RP_0/results.txt ./params_R_9_C_4_RP_0/results.txt ./params_R_9_C_9_RP_0/results.txt ./params_R_9_C_16_RP_0/results.txt ./params_R_9_C_25_RP_0/results.txt ... I should let it params_R_005_C_004_RP_0 when generating the results. But it would take much time to rerun the program to get the results. So I wonder if there is any way to use the bash command to achieve this objective.

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  • How to sort objects in a many-to-many relationship in ruby on rails?

    - by Kenji Kina
    I've been trying to deal with this problem for a couple of hours now and haven't been able to come up with a clean solution. It seems I'm not too good with rails... Anyway, I have the following: In code: class Article < ActiveRecord::Base has_many :line_aspects, :dependent => :destroy has_many :aspects, :through => :line_aspects #plus a name field end class LineAspect < ActiveRecord::Base belongs_to :article belongs_to :aspect end class Aspect < ActiveRecord::Base belongs_to :data_type has_many :line_aspects has_many :articles, :through => :line_aspects end Now, what I would like to do, is to sort these in two steps. First list of Articles by their Articles.name, and then inside sort them by Aspect.name (note, not the middleman). For instance, alphabetically (sorry if the notation is not correct): [{ article => 'Apple', line_aspects => [ {:value => 'red'}, #corresponding to the Attribute with :name => 'color' {:value => 'small'} #corresponding to the Attribute with :name => 'shape' ] },{ article => 'Watermelon', line_aspects => [ {:value => 'green'}, #corresponding to the Attribute with :name => 'color' {:value => 'big'} #corresponding to the Attribute with :name => 'shape' ] }] Again, note that these are ordered by the aspect name (color before shape) instead of the specific values of each line (red before green). (NOTE: My intention is to displaye these in a table in the view) I have not found a good way to do this in rails yet (without resorting to N queries). Can anyone tell me a good way to do it?

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  • algorithm - How to sort a 0/1 array with 2n/3 comparisons?

    - by Jackson Tale
    In Algorithm Design Manual, there is such an excise 4-26 Consider the problem of sorting a sequence of n 0’s and 1’s using comparisons. For each comparison of two values x and y, the algorithm learns which of x < y, x = y, or x y holds. (a) Give an algorithm to sort in n - 1 comparisons in the worst case. Show that your algorithm is optimal. (b) Give an algorithm to sort in 2n/3 comparisons in the average case (assuming each of the n inputs is 0 or 1 with equal probability). Show that your algorithm is optimal. For (a), I think it is fairly easy. I can choose a[n-1] as pivot, then do something like in quicksort partition, scan 0 to n - 2, find the middle point where left side is all 0 and right side is all 1, this take n - 1 comparisons. But for (b), I can't get a clue. It says "each of the n inputs is 0 or 1 with equal probability", so I guess I can assume the numbers of 0 and 1 equal? But how can I get a result which is related to 1/3? divide the whole array into 3 groups? Thanks

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  • How to sort data in a table data structure in Java?

    - by rgksugan
    I need to sort data based on the third column of the table data structure. I tried based on the answers for the following question. But my sorting does not work. Please help me in this. Here goes my code. Object[] data = new Object[y]; rst.beforeFirst(); while (rst.next()) { int p_id = Integer.parseInt(rst.getString(1)); String sw2 = "select sum(quantity) from tbl_order_detail where product_id=" + p_id; rst1 = stmt1.executeQuery(sw2); rst1.next(); String sw3 = "select max(order_date) from tbl_order where tbl_order.`Order_ID` in (select tbl_order_detail.`Order_ID` from tbl_order_detail where product_id=" + p_id + ")"; rst2 = stmt2.executeQuery(sw3); rst2.next(); data[i] = new Object[]{new String(rst.getString(2)), new String(rst.getString(3)), new Integer(rst1.getString(1)), new String(rst2.getString(1))}; i++; } ColumnComparator cc = new ColumnComparator(2); Arrays.sort(data, cc); if (i == 0) { table.addCell(""); table.addCell(""); table.addCell(""); table.addCell(""); } else { for (int j = 0; j < y; j++) { Object[] theRow = (Object[]) data[j]; table.addCell((String) theRow[0]); table.addCell((String) theRow[1]); table.addCell((String) theRow[2]); table.addCell((String) theRow[3]); }

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  • How to sort an NSMutableArray List of objects in alphabetical order.

    - by Madan Mohan
    Hi guys, I have an object with different values that is name,nameid, lifebeging,lifeEndiging .... etc, for loop { Search *Obj=[artistslist objectAtIndex:i];// here i will get name, ids, other value for each objcet } 0 obj.name= //string values1 get from parser 1 obj.name= //string values1 2 obj.name= //string values1 3 obj.name= //string values1 4 obj.name= //string values1 I am getting values in the artistList then i need to sort only by name not other feilds when i use this below statement [artistsList sortUsingSelector:@selector(NSOrderedAscending:)]; i am getting exception here ,it is not working.

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  • Gridview - Is it necessary to grab data from database every time a filter, sort, or paging event occ

    - by hamlin11
    Regarding gridviews that are not bound to a Data Source Control: In most GridView tutorials that I have seen, when just about any GridView event occurs, the end of the event handler will include BindDataGrid(). In some form, these BindDataGrid() functions 1) Grab data from the database 2) Assign any Filter or Sort expressions to the data, and 3) Bind the gridview to that data source (usually a DataView or DataTable. Is there a better way to provide filterable & sortable data to a GridView without having to hit the database so often? Thanks

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  • How do you sort a C# dictionary by value?

    - by kurious
    I often have a Dictionary of keys & values and need to sort it by value. For example, I have a hash of words and their frequencies, and want to order them by frequency. There's SortedList which is good for a single value (frequency), but I want to map it back to the word. SortedDictionary orders by key, not value. Some resort to a custom class, but what's the cleanest way?

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  • Is there a way to turn on some sort of JVM logging so I can see whats happening during classloading

    - by Spines
    I'm trying to optimize the startup time/class loading time of my Java web app because its on the Google App Engine and startup time is important. Is there a way I can turn on some sort of class loading debug messages or someway to see where time is being spent while class loading? I want to see if any specific libraries take a while to load and then get rid of them if they aren't essential.

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  • Is Minus Zero some sort of JavaScript performance trick?

    - by James Wiseman
    Looking in the jQuery core I found the folloiwng code convention: nth: function(elem, i, match){ return match[3] - 0 === i; }, And I was really curious about the snippet match[3] - 0 Hunting around for '-0' on google isn't too productive, and a search for 'minus zero' brings back a reference to a Bob Dylan song. So, can anyone tell me. Is this some sort of performance trick, or is there a reason for doing this rather than a parseInt or parseFloat? Thanks

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  • Search sort by parameter match count in the query? PostgreSQL

    - by Ben Dauphinee
    I am working on a search query in PostgreSQL, and one of the things I do is sort my query results by the number of parameters matched. I have no clue how this can be done. Does anyone have a suggestion or solution? Table brand color type engine Ford Blue 4-door V8 Maserati Blue 2-door V12 Saturn Green 4-door V8 GM Yellow 1-door V4 Current Query SELECT brand FROM table WHERE color = 'Blue' or type = '4-door' or engine = 'V8' Result Should Be Ford (3 match) Saturn (2 match) Maserati (1 match)

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  • Is there a way to sort by more than one field in Crystal Reports?

    - by John at CashCommons
    I'm using Crystal Report with VB.NET in Visual Studio 2005. I have report that works if I pass in a list of List(Of Stuff). I had been sorting the report by one of the members of Stuff but a need now to sort first by one member, like Stuff.StatusCode and then by another member, like Stuff.ItemNumber. Can I do this just be having more than one SortField member, or do I need to do it some other way? Thanks as always!

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  • Does Zend application server provide any sort of pushed-based messaging architecture support?

    - by Alex
    Does Zend application server provide any sort of pushed-based messaging architecture support?I mean some different message-oriented middlewares that can be used for the push-based architecture or email support?There is a need in provision of the non web-based interface for certain users of the website who would get regular messages notifying them of different special offers in their field of interest(it should be push-based)

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