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  • Django templatetag "order of processing"

    - by Jason Persampieri
    I am trying to write a set of template tags that allow you to easily specify js and css files from within the template files themselves. Something along the lines of {% requires global.css %}, and later in the request, {% get_required_css %}. I have this mostly working, but there are a couple of issues. We'll start with the 'timing' issues. Each template tag is made up of two steps, call/init and render. Every call/init happens before any render procedure is called. In order to guarantee that all of the files are queued before the {% get_required_css %} is rendered, I need to build my list of required files in the call/init procedures themselves. So, I need to collect all of the files into one bundle per request. The context dict is obviously the place for this, but unfortunately, the call/init doesn't have access to the context variable. Is this making sense? Anyone see a way around this (without resorting to a hack-y global request object)? Another possibility to store these in a local dict but they would still need to be tied to the request somehow... possibly some sort of {% start_requires %} tag? But I have no clue how to make that work either.

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  • Generating all possible subsets of a given QuerySet in Django

    - by Glen
    This is just an example, but given the following model: class Foo(models.model): bar = models.IntegerField() def __str__(self): return str(self.bar) def __unicode__(self): return str(self.bar) And the following QuerySet object: foobar = Foo.objects.filter(bar__lt=20).distinct() (meaning, a set of unique Foo models with bar <= 20), how can I generate all possible subsets of foobar? Ideally, I'd like to further limit the subsets so that, for each subset x of foobar, the sum of all f.bar in x (where f is a model of type Foo) is between some maximum and minimum value. So, for example, given the following instance of foobar: >> print foobar [<Foo: 5>, <Foo: 10>, <Foo: 15>] And min=5, max=25, I'd like to build an object (preferably a QuerySet, but possibly a list) that looks like this: [[<Foo: 5>], [<Foo: 10>], [<Foo: 15>], [<Foo: 5>, <Foo: 10>], [<Foo: 5>, <Foo: 15>], [<Foo: 10>, <Foo: 15>]] I've experimented with itertools but it doesn't seem particularly well-suited to my needs. I think this could be accomplished with a complex QuerySet but I'm not sure how to start.

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  • Crossed import in django

    - by Kuhtraphalji
    On example, i have 2 apps: alpha and beta in alpha/models.py import of model from beta.models and in beta/models.py import of model from alpha.models manage.py validate says that ImportError: cannot import name ModelName how to solve this problem?

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  • Django admin default filter

    - by h3
    I know I already managed to do this but can't remember how nor I can't find any documentation about this.. How can apply a filter by default on a object list view in the admin ? I have an app which list quotes and those quotes have a status (ex: accepted, rejected, on hold ..). I want the filter set on status='accepted' by default that is..

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  • django filefield return filename only in template

    - by John
    I've got a field in my model of type FileField. This gives me an object of type type File, which has the following method: File.name: The name of the file including the relative path from MEDIA_ROOT. What I want is something like .filename that will only give me the filename and not the path as well something like: {% for download in downloads %} <div class="download"> <div class="title">{{download.file.filename}}</div> </div> {% endfor %} which would give something like myfile.jpg thanks

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  • Django ForeignKey _set on an inherited model

    - by neolaser
    I have two models Category and Entry. There is another model ExtEntry that inherits from Entry class Category(models.Model): title = models.CharField('title', max_length=255) description = models.TextField('description', blank=True) ... class Entry(models.Model): title = models.CharField('title', max_length=255) categories = models.ManyToManyField(Category) ... class ExtEntry(Entry): groups= models.CharField('title', max_length=255) value= models.CharField('title', max_length=255) ... I am able to use the Category.entry_set but I want to be able to do Category.blogentry_set but it is not available. If this is not available,then I need another method to get all ExtEntryrelated to one particular Category Thanks

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  • Django Custom Admin

    - by Harry
    Hello there Currently I have an app with a save method in its models.py . So I would like to change this so the models does not do the save() method, but rather have a separate view that will do this in die admin site. Can you please direct me in the correct direction? Thank you

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  • Django limit access by group only

    - by Mike
    I only you can limit what a user can do via the user permissions in admin.. But is there a way to limit them in admin via what group you add them to? I want to allow a certain group to do everything in that model if they belong to a certain group thanks!

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  • Django - Add rows to MySQL database

    - by yeenow123
    So I already have a database setup with a few columns and a few rows already inserted in. I'm trying to create a view that you would just input information into a form and press Submit, then a row would be added to the MySQL database with the information you just typed in. I believe you can do this with admin, but I would like to try without admin and I'm not sure if this is possible? I've been using the MySQL commandline to add rows as of now..

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  • Aggregation over a few models - Django

    - by RadiantHex
    Hi folks, I'm trying to compute the average of a field over various subsets of a queryset. Player.objects.order_by('-score').filter(sex='male').aggregate(Avg('level')) This works perfectly! But... if I try to compute it for the top 50 players it does not work. Player.objects.order_by('-score').filter(sex='male')[:50].aggregate(Avg('level')) This last one returns the exact same result as the query above it, which is wrong. What am I doing wrong? Help would be very much appreciated!

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  • Django modelform ForeignKey List

    - by Harry
    How do you get each item in the ForeignKey field in a list, for example: class Delegate(models.Model): excursion = models.ForeignKey(Excursion, limit_choices_to = {'is_activity': False}, related_name='excursion', null=True, blank=True) Template: {% for object in formset.excursion_set.all %} {{ object.lable }} etc {% endfor %} My reason is that I don't want the options to display as a dropdown, but in a custom way that I will style etc.

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  • Get Url Parameters In Django

    - by picomon
    I want to get current transaction id in url. it should be like this www.example.com/final_result/53432e1dd34b3 . I wrote the below codes, but after successful payment, I'm redirected to Page 404. (www.example.com/final_result//) Views.py @csrf_exempt def pay_notif(request, v_transaction_id): if request.method=='POST': v_transaction_id=request.POST.get('transaction_id') endpoint='https://testpay.com/?v_transaction_id={0}&type=json' req=endpoint.format(v_transaction_id) last_result=urlopen(req).read() if 'Approved' in last_result: session=Pay.objects.filter(session=request.session.session_key).latest('id') else: return HttpResponse(status=204) return render_to_response('final.html',{'session':session},context_instance=RequestContext(request)) Urls.py url(r'^final_result/(?P<v_transaction_id>[-A-Za-z0-9_]+)/$', 'digiapp.views.pay_notif', name="pay_notif"), Template: <input type='hidden' name='v_merchant_id' value='{{newpayy.v_merchant_id}}' /> <input type='hidden' name='item_1' value='{{ newpayy.esell.up_name }}' /> <input type='hidden' name='description_1' value='{{ newpayy.esell.up_description }}' /> <input type='hidden' name='price_1' value='{{ newpayy.esell.up_price }}' /> #page to be redirected to after successful payment <input type='hidden' name='success_url' value='http://127.0.0.1:8000/final_result/{{newpayy.v_transaction_id}}/' /> How can I go about this?

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  • How to save links in Django

    - by xRobot
    I have a simple Blog model with a TextFields. What is the best way to save link ? 1) Saving link in the database in this form: http://www.example.com and then using some filter in the template to trasform it in form: <a rel="nofollow" href="http://www.example.com>http://www.example.com</a> 2) Saving link in the database directly in this form: <a rel="nofollow" href="http://www.example.com>http://www.example.com</a>

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  • Default FileField names for Django files

    - by Adam Nelson
    I have a model: class Example(models.Model): unique_hash = models.CharField(max_length=32,unique=True) content = models.FileField(upload_to='source',blank=True,verbose_name="HTML Content File") I would like to be able to set the content filename to default to a callable, but I don't see any way to have the callable reference unique_hash (or vice versa). Is this possible?

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  • How to retrieve items from a django queryset?

    - by sharataka
    I'm trying to get the video element in a queryset but am having trouble retrieving it. user_channel = Everything.objects.filter(profile = request.user, playlist = 'Channel') print user_channel[0] #returns the first result without error print user_channel[0]['video'] #returns error Models.py: class Everything(models.Model): profile = models.ForeignKey(User) playlist = models.CharField('Playlist', max_length = 2000, null=True, blank=True) platform = models.CharField('Platform', max_length = 2000, null=True, blank=True) video = models.CharField('VideoID', max_length = 2000, null=True, blank=True) video_title = models.CharField('Title of Video', max_length = 2000, null=True, blank=True) def __unicode__(self): return u'%s %s %s %s %s' % (self.profile, self.playlist, self.platform, self.video, self.video_title)

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  • Django menu item sorting

    - by doktorno
    Hi i've got MenuItem model : MenuItem(models.Model) name=models.CharField(max_length=50) url = models.URLField() position = models.IntegerField() Class Meta: ordering =['position'] then i'm retriving it by MenuItem.objects.all() My question is how can i make any user friendly interface in admin panel to allow sorting MenuItems - for example list with + and - buttons to move MenuItem up and down ....

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  • django overwrite form clean method

    - by John
    Hi, When overwriting a form clean method how do you know if its failed validation on any of the fields? e.g. in the form below if I overwrite the clean method how do I know if the form has failed validation on any of the fields? class PersonForm(forms.Form): title = Forms.CharField(max_length=100) first_name = Forms.CharField(max_length=100) surname = Forms.CharField(max_length=100) password = Forms.CharField(max_length=100) def clean(self, value): cleaned_data = self.cleaned_data IF THE FORM HAS FAILED VALIDATION: self.data['password'] = 'abc' raise forms.ValidationError("You have failed validation!") ELSE: return cleaned_data Thanks

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  • Django Find Out if User is Authenticated in Custom Tag

    - by greggory.hz
    I'm trying to create a custom tag. Inside this custom tag, I want to be able to have some logic that checks if the user is logged in, and then have the tag rendered accordingly. This is what I have: def user_actions(context): request = template.Variable('request').resolve(context) return { 'auth': request['user'].is_athenticated() } register.inclusion_tag('layout_elements/user_actions.html', takes_context=True)(user_actions) When I run this, I get this error: Caught VariableDoesNotExist while rendering: Failed lookup for key [request] in u'[{}]' The view that renders this ends like this: return render_to_response('start/home.html', {}, context_instance=RequestContext(request)) Why doesn't the tag get a RequestContext object instead of the Context object? How can I get the tag to receive the RequestContext instead of the Context? EDIT: Whether or not it's possible to get a RequestContext inside a custom tag, I'd still be interested to know the "correct" or best way to determine a user's authentication state from within the custom tag. If that's not possible, then perhaps that kind of logic belongs elsewhere? Where?

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  • I want to select the distict value from models field and then update them (django)

    - by qulzam
    I have models... class Item(models.Model): name = models.CharField('Item Name', max_length = 30) item_code = models.CharField(max_length = 10) color = models.CharField(max_length = 150, null = True, blank = True) size = models.CharField(max_length = 30, null = True, blank = True) fabric_code = models.CharField(max_length = 30, null = True, blank = True) I have values in Item. in Item model name field has the similar values..(but the other values of record are change). I want to select the name field values distinctly(ie similar values select only ones). in one box(like combo box). What kind of form or views i use??

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  • How do I set prifix to django contrib tables names?

    - by Software Enthusiastic
    HI One of my requirement is to have prefix on all the tables of the django based project (Because db is hosted on shared server). I have used db_table Meta option to set the prefix for the tables which I have created. Now my query is how do I set the prefix for tables provided by django.contrib. Instead of auth_group django should create prefix_auth_group.... How do I do that? Thank you very much...

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  • reverse many to many fields in Django + count them

    - by cleliodpaula
    I'm trying to figure out how to solve this class Item(models.Model): type = models.ForeignKey(Type) name = models.CharField(max_lenght = 10) ... class List(models.Model): items = models.ManyToManyField(Item) ... I want to count how many an Item appears in another Lists, and show on template. view def items_by_list(request, id_): list = List.objects.get(id = id_) qr = list.items.all() #NOT TESTED num = [] i = 0 for item in qr: num[i] = List.objects.filter(items__id = item__id ).count() #FINISH NOT TESTED c = {} c.update(csrf(request)) c = {'request':request, 'list' : qr, 'num' : num} return render_to_response('items_by_list.html', c, context_instance=RequestContext(request)) template {% for dia in list %} <div class="span4" > <div> <h6 style="color: #9937d8">{{item.type.description}}</h6> <small style="color: #b2e300">{{ item.name }}</small> <small style="color: #b2e300">{{COUNT HOW MANY TIMES THE ITEM APPEAR ON OTHER LISTS}}</small> </div> {% endfor %} This seems to be easy, but I could not implement yet. If anyone has some glue to me, please help me. Thanks in advance.

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  • Django template CSS/IMG is "off" in the URL

    - by erimar77
    I have /path/to/my/theme/static/css/frontend.css which is called by base.html <link rel="stylesheet" type="text/css" href="{{ STATIC_URL }}css/frontend.css" media="all" /> In which I've got a background for the header: #header-wrapper min-width: 960px; height: 150px; background: transparent url(img/header-bg.png) repeat-x center bottom; } The file is /path/to/my/theme/static/img I've run manage.py collectstatic to gather the files and almost everything looks correct except the link generated looks like: http://example.com/static/css/img/header-bg.png In which the image does not show, because the correct URL is: http://example.com/static/img/header-bg.png Where am I going wrong??

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