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  • When does n++ execute faster than n=n+1 ?

    - by gcc
    Related: http://stackoverflow.com/questions/24853/c-what-is-the-difference-between-i-and-i In C language, Why does n++ execute faster than n=n+1? (int n=...; n++;) (int n=...; n=n+1;) Our instructor asked that question in today's class. (this is not homework)

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  • pointer&dynamic memory

    - by gcc
    how many methods are there taking input by using with pointer and dynamic memory input 3 1 2 n k l 2 1 2 p 4 55 62 * # x x is stop character and first input 3 is for another variable int hakko; only hakko use first input the others will be hold in one pointer and input size not determined

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  • freeing malloc and checkin it is empty or not

    - by gcc
    char *p; p="kjkjk"; . .//there are codes which are checking another command . if(.....)//i used pointer p in only that area free(p); . . //there are codes which are checking another command . if(p==NULL) //i check whether is empty .... if(p==-1) //can we use "EOF==p " in if statement ... //are there any usage like that EOF==p else .... I think there is big error , but where?

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  • will 'printf' always do its job? [closed]

    - by gcc
    printf("/something else/"); //without using \n in printf I know printf() uses a buffer which prints whatever it contains when, in the buffer, "\n" is seen by the buffer. So when we forget to use "\n" in printf ,rarely,buffer will not be emptied.Therefore,printf wont do its job. Am I wrong?

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  • creating new array according to input

    - by gcc
    int *arrays[20],j,a=0; /*int num_arrays;*/ char *tutar[200]; int /*fe*/i=0,n,temp; do{ tutar[i]=malloc(sizeof(int)); scanf("%s",tutar[i]); temp=*tutar[i]; ++i; } while(temp!='x'); int *arrays[20],j,a=0; n=i; j=1; for(i=1;i if(atoi(tutar[i])=='n') { ++j; arrays[j]=malloc(sizeof(int)); a=0; } arrays[j][a]=*(int *)tutar[i]; if(atoi(tutar[i])=='x') break; } input: 1 2 3 4 n 14 23 39 n 98 100 x output: arrays[1]:2 3 4 arrays[2]:14 23 39 arrays[3]:98 100 //i wanna output like that but my code didnt give me output like that //can anyone fix my code or (explain where is my error)

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  • between syntax, are there any equal function

    - by gcc
    /* char **mainp=malloc(sizeof(char *)*2); mainp[0]=malloc(sizeof(char)*300); mainp[1]=malloc(sizeof(char )*300); */ *I have some input about propositional calculus *After calculating some math funtion-removing paranthesis-changing"&" with ","-replacing "|" with"," I have >> (1) P,-Q,Q,-R is stored in mainp[0] R,A,P,B,F is stored in mainp[1] *My question is: Between comma , I have want to compare two pointer array. If there is any equal two or more functions(Q,-R is function representation) ,function which you will show me how to write must return int. According to example (1),function will return 1 (I expect like that) /*I have som thought://which function should I have use:*/ in for loop if( strspn(mainp[0][i])==1 ) increment d; continue; or in for loop srtcmp(mainp[0][i],mainp[1]);

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  • dimension || pointer pointer

    - by gcc
    What are pointers to pointers (like char **p;) used for? Can there be char ***p; or char ****p;? What would they be used for? my real question is >>what is the main purpose of char **p; why we need to use that type one answer is char *p - one dimension char *p - 2 dimensions char **p - 3 dimensions i have asked you can give example but he havenot answer i am thinking can we use ? is p[i][j] to **p that is can we use it like for(;;) for(;;) scanf("....",p[i][j]);

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  • function takes only half of the inputs

    - by gcc
    /*-> struct sam set_of_data[4] -<*/ int main (void) {int k=0; for(i=0;i<4;++i) { {char nm; double thelow,theupp; double numbers[200]; scanf("%c %lf %lf",&nm ,&thelow ,&theupp); for(k=0;scanf("%lf",&numbers[k])!=0;++k) ; set_of_data[i]=construct_struct(nm,thelow,theupp,numbers,k); } ; } .. /* helper function to construct data structure*/ sam_t construct_struct(char name,double thelow,double theupp,double *numbers,int k) { stored_name_t stn; stn.name=name; stn.the_lower_limit=thelow; stn.the_upper_limit=theupp; for(i=0 ; i<k && numbers[k]!='\n' && numbers[k]!='\0' ; ++i) stn.numbers[k]=numbers[k]; return stn; } these two funtion takes only half of the inputs(lines starting with D and B didnot be taken,why? inputs: C 3.25 18. 0.01 .01 .02 .04 .08 .02 .02 .05 .065 .08 .1 .13 .2 .05 .04 .04 .03 .01 .005 .0 A 0 7.5 .054 .031 .016 .008 .116 .124 .147 .155 .039 .023 .016 .008 .124 .062 .031 .016 .008 .008 .008 .006 D -1.5 0.5 .012 .025 .05 .1 .1 .1 .025 .012 0 0 0 .012 .025 .1 .2 .1 .05 .039 .025 .025 B 1 3 .117 .058 .029 .015 .007 .007 .007 .015 .022 .029 .036 .044 .051 .058 .066 .073 .080 .088 .095 .103

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  • pointer and malloc [closed]

    - by gcc
    How many methods/ways are there taking input by using with pointer and dynamic memory? Input: 3 1 2 n k l 2 1 2 p 4 55 62 * # x (x is stop value, first input always integer) Example code: p=malloc(sizeof(int)); scanf("%d",&num_arrays); while(1) { scanf("%c",&(*(p+i))); if(*(p+i)=='x') break; ++i; } "3" is stored in num_arrays. The other input values are stored in pointer[array].

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  • command&pointer&malloc [closed]

    - by gcc
    input 23 3 4 4 42 n 23 0 9 9 n n n 3 9 9 x //according to input,i should create int pointer arrays. pointer arrays starting from 1 (that is initial arrays is arrays[1].when program sees n ,it must be jumb to arrays 2 expected output arrays[1] 3 4 5 42 arrays[2] 23 0 9 9 arrays[5] 3 9 9 x is stopper n is comman to create new pointer array i am new in this site anyone help me how can i write

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  • How can I put back a character that I've read when I detect it's the start of a new row?

    - by gcc
    char nm; int i=0; double thelow, theupp; double numbers[200]; for(i=0;i<4;++i) { { char nm; double thelow,theupp; /*after erased ,created again*/ scanf("%c %lf %lf", &nm, &thelow, &theupp); for (k = 0; ; ++k) ; { scanf("%lf",numbers[k]); if(numbers[k]=='\n') break; } /*calling function and sending data(nm,..) to it*/ } /*after } is seen (nm ..) is erased*/ ; } I want say compiler : hey my dear code read only i-th row,dont touch characters at placed in next line. because characters at placed in next line is token after i increased by 1 and nm ,thelow,theupp is being zero or erased after then again created. how can I do ? input; D -1.5 0.5 .012 .025 .05 .1 .1 .1 .025 .012 0 0 0 .012 .025 .1 .2 .1 .05 .039 .025 .025 B 1 3 .117 .058 .029 .015 .007 .007 .007 .015 .022 .029 .036 .044 .051 .058 .066 .073 .080 .088 .095 .103

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  • copy string one place to another

    - by gcc
    how can i copy part of the specific string to the another place example (aaa),(ddd),(fff),(fff),#p copy (ddd) to the side of the p (aaa),(fff),(fff),#p,(ddd) //before copyin add comma copy (fff) to side of the (ddd) (aaa),(fff),#p,(ddd),(fff) //string lenght always same

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  • taking and holding input

    - by gcc
    i tried to take input from user input like that input:: first line:>>name(white space)last name second line:>>identification number(white space)birtdate(,,:,,:) third line:>>lesson which he take (ce140 ce213 ce383...) last line:>>note he take(80 60 ......) this input type for each student i tried to hold this input in struct like struct name is first line { second line third line last line } my testing scanf("%[^\n]\n); take input hold in string scanf("%s",...secondline_name); storing in secondline_name . . . but this doesnot work are there any other way to hold input

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  • dynamic memory allocation [closed]

    - by gcc
    i wanna write a program that creates (allocating memory) and manipulates (adding elements and increasing memory etc.) integer arrays dynamically according to given input sequences. input sequence which starts with the maximum number of arrays, includes integers to be put into arrays and some one letter characters which are commands to carry out some tasks (activating next array, deleting an array etc). also, i wanna create *c_arrays which is the address of the array whose elements are the actual capacities (How many integer slots are already allocated for an array?) of arrays how should i organize(set up) the algorithm?

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  • make it simpler and efficient

    - by gcc
    temp1=*tutar[1]; //i hold input in char *tutar[] if(temp1!='x'||temp1!='n') arrays[1]=malloc(sizeof(int)*num_arrays); //if second input is int a=0; n=i; for(i=1;i<n;++i) { temp1=*tutar[i]; if(temp1=='d') { ++i; j=atoi(tutar[i]); free(arrays[j]); continue; } if(temp1=='x') break; if(temp1=='n')//if it is n { a=0; ++j; arrays[j]=malloc(sizeof(int)*num_arrays);//create and allocate continue; } ++a; if(a>num_arrays) //resize the array arrays[j]=realloc(arrays[j],sizeof(int)*(num_arrays+a)); *(arrays[j]+a-1)=atoi(tutar[i]); printf("%d",arrays[1][1]); } arrays is pointer when you see x exit you see n create (old one is new array[a] new one is array[i+1]) you see d delete arrays[i] according to int after d first number is size of max arrays and where is the error in code input is composed from int and n d x i make a program -taking input(first input must be int) -according to input(there is comman in input like n or d or j , i fill array with number and use memory efficiently -j is jumb to array[x] ( x is int coming after j in input)

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  • realizing number ...how?? [closed]

    - by gcc
    i hold input like that A is char pointer A[0]=n A[1]=j A[2]=n A[3]=d . there is one number in A[] and every A[i] is important for me because what will i do in next step is determined by input in A[i] or A[n] A[j]=$ . A[i]=14(any number) . . int func(int temp) { if(temp=='n') ..do something then return 10; if(temp=='j') .. return 11; if(temp=='d') .. return 12; if(........) when temp find/realize number ,i wanna return 13; in if statement, what code should i write } how i can do }

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  • p=malloc()!=null.......

    - by gcc
    char *p,*p1,*p2,*p3,*p4; for(;;) { if((p=malloc(10))!=NULL && (p1=malloc(20))!=NULL ......) break; } Writing if(........) is too boring and long, are there any ways to make it simpler?

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  • expected identifier before ‘(’

    - by gcc
    stored_name_t scan_construct_struct(void) { stored_name_t stn; int i=0; scanf("%c %lf %lf",&(stn.name) ,&(stn.(the_lower_limit)) ,&(stn.(the_upper_limit))); for(i=0; (scanf("%s", stn.(numbers[i])))!=0; ++i) ; return stn; } dene.c:37: error: expected identifier before ‘(’ token and there is an one more error but I cannot see

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  • make it simpliest

    - by gcc
    input 000 000 000 000 255 000 000 000 000 000 000 000 purpose instead of 000 write 0 and 255 write 2 take input { char A[800][600]; scanf("%d",&height); for(i=0;i<height;++i) scanf("%s",A[i]); then what output 0 0 0 0 2 0 0 0 0 0 0 0

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  • (again) i improve my question [closed]

    - by gcc
    Possible Duplicate: realizing number …how?? i hold input like that A is char pointer A[0]=n A[1]=j A[2]=n // i take (one number)+special char(s)+command(s) (like $ or #) from user A[3]=d // the input order can be changed like char(s)+number+command . // there is one number in A[] . // and every A[i] is important for me because what will i do in next step . // is determined by that input in A[h] or A[n] . // example . // when you see $ go before array do something . // when you see number go farad equation and use it in there A[j]=$ // (number can be pozitif or negatif . A[i]=14(any number) . . int func(int temp) { if(temp=='n') //..do something then return 10; if(temp=='j') return 11; if(temp=='d') return 12; if(/*........*/) // when temp find/realize number ,i wanna return 13; // in if statement, (instead of .....) what code should i write } how i can do } NOTE::please ,dont close my question ,when you close icannot edit it

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