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  • CSS Div Width Problem - Lining divs... widths seem to be off in IE7

    - by jlrolin
    So far, I'm doing this programmatically using VB.net/ASP.net: 'Create Container Div Dim ContainerDiv As New HtmlGenericControl("div") ContainerDiv.Style("width") = "100%" ContainerDiv.Style("clear") = "both" ContainerDiv.Style("text-align") = "left" ContainerDiv.Style("margin") = "0" 'Create Expand/Collapse Image Dim img As New Image img.ImageUrl = Page.ResolveUrl("~/images/minus99.jpg") img.Attributes.Add("onclick", "change(this.parent);") 'Create Company Display Dim lbl As New Label lbl.Text = Parsetext(pc.NAME) lbl.Font.Bold = True lbl.Style("font-size") = "16px" Dim NameDiv As New HtmlGenericControl("div") 'NameDiv.Style("background-color") = "#F0D3D3" NameDiv.Style("width") = "375px" NameDiv.Style("float") = "left" NameDiv.Style("margin") = "0" NameDiv.Style("display") = "block" NameDiv.Controls.Add(img) NameDiv.Controls.Add(lbl) ContainerDiv.Controls.Add(NameDiv) Dim SetupDiv As New HtmlGenericControl("div") SetupDiv.Style("background-color") = "#F0D3D3" SetupDiv.Style("width") = "210px" SetupDiv.Style("float") = "left" SetupDiv.Style("margin") = "0" SetupDiv.Style("display") = "block" 'SetupDiv.Style("position") = "fixed" ContainerDiv.Controls.Add(SetupDiv) Dim UsedDiv As New HtmlGenericControl("div") UsedDiv.Style("background-color") = "#CFF5CE" UsedDiv.Style("width") = "140px" UsedDiv.Style("float") = "left" UsedDiv.Style("margin") = "0" UsedDiv.Style("display") = "block" 'UsedDiv.Style("position") = "fixed" ContainerDiv.Controls.Add(UsedDiv) Dim RemDiv As New HtmlGenericControl("div") RemDiv.Style("background-color") = "#BEE0F7" 'RemDiv.Style("position") = "absolute" RemDiv.Style("width") = "210px" RemDiv.Style("float") = "right" RemDiv.Style("padding") = "0" RemDiv.Style("margin") = "0" RemDiv.Style("display") = "block" 'RemDiv.Style("position") = "fixed" ContainerDiv.Controls.Add(RemDiv) This should give me four DIVS inside a container DIV. Here's what it's coming out as: The correct blocks above the non-inline blocks are from a table with the same exact widths as the ones I'm using on the Divs. There isn't any CSS adding pixels to them, I don't think. I need to line these up, and I can't figure out where my problem is here. Any help would be appreciated.

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  • Canvas rotate from bottom center image angle?

    - by Tom
    How do you rotate an image with the canvas html5 element from the bottom center angle? See http://uptowar.com/test.php for my current code and image: <html> <head> <title>test</title> <script type="text/javascript"> function startup() { var canvas = document.getElementById('canvas'); var ctx = canvas.getContext('2d'); var img = new Image(); img.src = 'player.gif'; img.onload = function() { ctx.translate(185, 185); ctx.rotate(90 * Math.PI / 180); ctx.drawImage(img, 0, 0, 64, 120); } } </script> </head> <body onload='startup();'> <canvas id="canvas" style="position: absolute; left: 300px; top: 300px;" width="800" height="800"></canvas> </body> </html> Unfortunately this seems to rotate it from the top left angle of the image. Any idea? Edit: in the end the object (space ship) has to rotate like a clock pointer, as if it is turning right/left.

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  • How can I make an AJAX link work once it is moved out of the iFrame?

    - by KcYxA
    Hi, I am using an iFrame with a form that return some content with an AJAX link. I am then moving the returned content out of the iFrame into the main page. However, then the ajax link does not work and the error "Element is null" is created once the link is clicked. How can I move content from the iFrame and still have the AJAX link working? Here's the code returned by the iFrame: <span id="top"> <a id="link8" onclick=" event.returnValue = false; return false;" href="/item_pictures/delete/7"> <img src="/img/delete.bmp"/> </a> <script type="text/javascript"> parent.Event.observe('link8', 'click', function(event) { new Ajax.Updater('top','/item_pictures/delete/3', { asynchronous:true, evalScripts:true, onCreate:function(request, xhr) { document.getElementById("top").innerHTML = "<img src=\"/img/spinner_small.gif\">"; }, requestHeaders:['X-Update', 'top'] }) }, false); </script> </span>

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  • Resizing image algorithm in python

    - by hippocampus
    So, I'm learning my self python by this tutorial and I'm stuck with exercise number 13 which says: Write a function to uniformly shrink or enlarge an image. Your function should take an image along with a scaling factor. To shrink the image the scale factor should be between 0 and 1 to enlarge the image the scaling factor should be greater than 1. This is not meant as a question about PIL, but to ask which algorithm to use so I can code it myself. I've found some similar questions like this, but I dunno how to translate this into python. Any help would be appreciated. I've come to this: import image win = image.ImageWin() img = image.Image("cy.png") factor = 2 W = img.getWidth() H = img.getHeight() newW = int(W*factor) newH = int(H*factor) newImage = image.EmptyImage(newW, newH) for col in range(newW): for row in range(newH): p = img.getPixel(col,row) newImage.setPixel(col*factor,row*factor,p) newImage.draw(win) win.exitonclick() I should do this in a function, but this doesn't matter right now. Arguments for function would be (image, factor). You can try it on OP tutorial in ActiveCode. It makes a stretched image with empty columns :.

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  • Can I use Data URLs in Android 2.1's Webkit-based browser?

    - by Sven Haiges
    Hi all, I am writing a tutorial about the HTML5 Canvas for mobile and did some basic tests. While I can call the getDataURL() Method on an iPhone's HTML5 Canvas Element, it does not seem to return the data URL on Android 2.1 (Google Nexus One) and it's webkit-based default browser. Here is the sample: var dataURL = canvas.toDataURL(); var img = document.createElement('img'); img.setAttribute('src', dataURL); document.getElementById('box').appendChild(img); This will work on iPhone, it will add a new image element with the same content as the canvas. It does nothing or fails on Android 2.1. Has anyone ever gotten this to work? I am also wondering if anyone could help me with understanding the WebKit Build numbers and what it means with regards to what features I can expect. For the iphone, I see a build number of 528.18, on Android 2.1's Browser I see (from the user agent strign) a WebKit build 530.17. So it looks Android 2.1's webkit browser is more up to date, still some features work on iPhone's webkit but not on Android. Does this comparison just make no sense? Thanx all!

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  • GLOBAL loading inside each single button with Jquery in ajax calls of asp.net mvc

    - by Ricky
    I have the following scenario: I have a button\link with a image inside like this: <button type="submit" id="myButton" class="button"><img src="../../Content/images/check.png" id="defaultImage" /> SaveData!!!</button> We are OK here! Now what I need to do is: I want on the click that the image change for a loading element that is previously loaded in the page like this: <img id="loadingImage" src="../../Content/images/loader.gif" style="display: none;" alt="loading"/> And then when the load complete turn back the old button image, I ended with this code: function loader() { var $button = $('#myButton'); if (btnState == '1') { $button.find('img').hide(); $button.prepend($('#loadingImage')); $('#loadingImage').css({ 'display': 'inherit' }); btnState = '0'; } else { $button.find('img').hide(); $button.prepend($('#defaultImage')); $('#defaultImage').show(); btnState = '1'; } } This does the trick for ONE SINGLE button(since I pass its ID in the function) but, when I have for example a grid with a button on each line, I found inviable when managing a screen with many buttons do this for each of then. The main question is: How can I make this method general for all buttons/links on one specific class in the page? The goal is: Click a button, get the image and change it and stop(can be manual). I just don't wanna have to Hook ALL buttons.

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  • Why I can't update my UIImageView?

    - by Tattat
    I make my own UIImageView, like this: @interface MyImageView : UIImageView{ } And I have the initWithFrame like this: - (void)initWithFrame{ UIImage *img = [UIImage imageWithContentsOfFile: [[NSBundle mainBundle] pathForResource:@"myImage" ofType:@"png"]]; CGRect cropRect = CGRectMake(175, 0, 175, 175); CGImageRef imageRef = CGImageCreateWithImageInRect([img CGImage], cropRect); self = [[UIImageView alloc] initWithFrame:CGRectMake(0, 0, 175, 175)]; self.image = [UIImage imageWithCGImage:imageRef]; [self addSubview:imageView]; CGImageRelease(imageRef); } I want to change the image when the user touchesBegin, so I have something like this: - (void)touchesBegan:(NSSet *)touches withEvent:(UIEvent *)event { UIImage *img = [UIImage imageWithContentsOfFile: [[NSBundle mainBundle] pathForResource:@"myImage2" ofType:@"png"]]; CGRect cropRect = CGRectMake(0, 0, 175, 175); CGImageRef imageRef = CGImageCreateWithImageInRect([img CGImage], cropRect); self = [[UIImageView alloc] initWithFrame:CGRectMake(0, 0, 175, 175)]; [self setImage:[UIImage imageWithCGImage:imageRef]]; CGImageRelease(imageRef); } I find that I can't change the image. So, I add a line [self addSubview:imageView]; in the touchesBegan method, that's work. But I have no idea on why I can't change the image from the touchesBegan, thz.

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  • CSS 3 - Scaling CSS Transitions

    - by Viv Shc
    I am trying to scale an image when you mouseenter, which is working. I would like the image to gradually scale up with an ease transition. I used ease-in-out, which it's not working. Any suggestions? Also, I used addClass & removeClass twice in the jquery code. Is there a way to only use it once? Thanks! <style> .image { opacity: 0.5; } .image.opaque { opacity: 1; } .size{ transform:scale(1.2); -ms-transform:scale(1.2); /* IE 9 */ -webkit-transform:scale(1.2); /* Safari and Chrome */ -webkit-transition: scale 2s ease-in-out; -moz-transition: scale 2s ease-in-out; -o-transition: scale 2s ease-in-out; -ms-transition: scale 2s ease-in-out; transition: scale 2s ease-in-out; transition: opacity 2s; } </style> <script> $(document).ready(function() { $(".image").mouseenter(function() { $(this).addClass("opaque"); $(this).addClass("size"); }); $(".image").mouseleave(function() { $(this).removeClass("opaque"); $(this).removeClass("size"); }); }); <div id="gallery"> <h3>Gallery of images</h3> <img class="image" src="images/gnu.jpg" height="200px" width="250px"> <img class="image" src="images/tiger.jpg" height="200px" width="250px"> <img class="image" src="images/black_rhino.jpg" height="200px" width="250px"> <img class="image" src="images/cape_buffalo.jpg" height="200px" width="250px"> </div>

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  • CSS: "float:left" doesn't work as expected

    - by Patrick
    hi, I want to display 2 columns of images using "float:left", and I dunno why the 3rd image is on the right. See screenshot:http://dl.dropbox.com/u/72686/imagesFloat.png See HTML: <div class="field-item odd"> <img alt="" class="filefield-imagecache-galleryImage" src="http://localhost/bernardi/sites/default/files/Picture%202.png" title=""><br> <span>description1</span> </div> <div class="field-item even"> <img alt="" class="filefield-imagecache-galleryImage" src="http://localhost/bernardi/sites/default/files/Picture%203.png" title=""><br> <span>description2</span> </div> <div class="field-item odd"> <img alt="" class="filefield-imagecache-galleryImage" src="http://localhost/bernardi/sites/default/files/Picture%204.png" title=""><br> <span>description3</span> </div> <div class="field-item even"> <img alt="" class="filefield-imagecache-galleryImage" src="http://localhost/bernardi/sites/default/files/Picture%205.png" title=""><br> <span></span> </div> see CSS: .field-field-image .odd { padding-right:20px; } .field-field-image .even { padding-left:20px; } .field-field-image .field-item { float:left; } thanks

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  • '$.fn' is null or not an object

    - by metal-gear-solid
    Problem 1 Error: Microsoft JScript runtime error: '$.fn' is null or not an object Error area: $.fn.apply=function(item,content,header){ $(".featureBox"+item).css('z-index', "1000"); $("img.featureBox" + item +"top").attr("src",basepath + "box-big-top.jpg"); $("img.featureBox" + item +"imgcut").attr("src",basepath + "box-big-img"+item+".jpg"); featureboxcont[item].attr("src",basepath + "box-big-cont.jpg"); $("img.featureBox" + item +"foot").attr("src",basepath + "box-big-bot2.jpg"); //$("#NoteModalDialog > #x-dlg-bd > #x-dlg-tab > #acc-ct") $("#box"+item+"headtext > .h2div > h2").text(header); $("#box"+item+"bottext").css({"top":"181px","width":"205px","font-size":"12px","color":"#ffffff","left":"10"}); $("#box"+item+"foottext").css({"top":footheight+"px","width":"215px","left":"20"}); $("#box"+item+"hidden").css({"display":"block"}); $("#box"+item+"bottext").text(content); $("#box"+item+"headtext > .h2div > h2").removeClass("sIFR-replaced"); callsIFR(); } Problem 2 Error : Microsoft JScript runtime error: 'null' is null or not an object Error area : $("#innerWrapper").addClass("js-version"); I'm also using protoype.js on page.

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  • Can't find solution for CSS vertical align for Firefox

    - by Sergio
    I have a problem with DIV vertical align in Firefox The HTML code is: <div class="mess"><div class="rpl"><img src="img/16.png" width="16" height="16" border="0"></div><div class="pic"><img src="img/1.png" width="100" height="100" border="0"></div></div> The CSS looks like: .mess{ float:left; width:658px; border-top:1px solid #CCC;padding-top:5px; } .rpl{ position: relative;width:19px; float:left;top: 20%;display: table-cell; vertical- align: middle; padding-top:20px; } .pic{width:100px; float:left; padding-bottom:5px;margin-right:10px; } I'm trying to put "rpl" DIV at the vertical middle of the "mess" DIV. In IE it looks fine but I can't get it right in Firefox (always at the top of the "mess" div) I tried with display: inline,display: table-cell for "rpl" DIV but with no effect in FF. Is there any solution for vertical align for DIV in FF?

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  • Parsing the first image src of a list

    - by zurna
    I need to parse a value from an xml and place it to image's src field. I tried parsing it as $(".photoBox img").append(ImageSmURL); and I got <img src="" alt="">/FLPM/media/images/0E7Q9Z0C_sm.jpg/FLPM/media/images/2A9L1V2X_sm.jpg</img> how do I do it so the result will be as... <img src="/FLPM/media/images/0E7Q9Z0C_sm.jpg" alt="" /> My xml <Images> <ImageID id="63"> <ImageSmURL>/FLPM/media/images/5V2G4Q5S_sm.jpg</ImageSmURL> <ImageLgURL>/FLPM/media/images/5V2G4Q5S.jpg</ImageLgURL> </ImageID> <ImageID id="64"> <ImageSmURL>/FLPM/media/images/5Y2K4T5V_sm.jpg</ImageSmURL> <ImageLgURL>/FLPM/media/images/5Y2K4T5V.jpg</ImageLgURL> </ImageID> </Images>

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  • jQuery: list appended not displaying bullets

    - by Shizhidi
    I have the following html: <!DOCTYPE html> <html> <head> <script src="http://code.jquery.com/jquery-latest.js"></script> </head> <body> <span>not so important</span> <span title="some specific text"><img src="/img/some.gif" /></span> <span title="more specific text">important 1</span> <span title="more specific text">important 2</span> <span title="more specific text">important 3</span> <span title="more specific text"><img src="/img/some.gif" /></span> <ul> <li>example 1</li> <li>example 2</li> <li>example 3</li> <ul> <script> var ul = $('body').append($('<ul>')); $("span[title*='specific text']") .contents() .filter(function(){ return $(this).nodeType != 1; }) .each(function(){ ul.append($('<li>' + $(this).text() + '</li>')); }) </script> </body> </html> I want to retrieve the text within a 'span' whose title attribute contains "specific text", in this case "important 1", "important 2" and "important 3". Then I want to list them below just like the example. However the bullets do not appear, why is that? Any hints would be appreciated!

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  • jQuery plugin Breaks after ajax call

    - by Jason
    Hello, I am quite a newbie to jQuery/ajax but am having a problem with my site that im making. Basically at first the page loads fine. On the boxes is a fade caption, when the title of the caption is clicked you are brought to an ajax page. Once you use the 'Back' button on browser, or the 'Back to list' button i've made the caption fade plugin no longer works and the box i had previously clicked is no longer clickable. can anyone help? heres my website: http://www.jcianfrone.com/testing jquery: h**p://www.jcianfrone.com/testing/script.js HTML: <div id="pageContent"> <div class="item"><a href="#page6"><img src="images/wrk-kd.jpg" width="286" height="200" alt="Koodikkki"></a><span id="caption"><a href="#">Title</a><p>Description</p></span></div> <div class="item"><a href="#page7"><img src="images/wrk-kd.jpg" width="286" height="200" alt="Koodikkki"></a><span id="caption"><a href="#">Title</a><p>Description</p></span></div> <div class="item"><a href="#page8"><img src="images/wrk-kd.jpg" width="286" height="200" alt="Koodikkki"></a><span id="caption"><a href="#">Title</a><p>Description</p></span></div> <div class="item"><a href="#page9"><img src="images/wrk-kd.jpg" width="286" height="200" alt="Koodikkki"></a><span id="caption"><a href="#">Title</a><p>Description</p></span></div> </div> Many thanks in advance

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  • Can I programmatically add a linkbutton to gridview?

    - by pschorf
    I've been looking through some similar questions without any luck. What I'd like to do is have a gridview which for certain items shows a linkbutton and for other items shows a hyperlink. This is the code I currently have: public void gv_RowDataBound(object sender, GridViewRowEventArgs e) { if (e.Row.RowType == DataControlRowType.DataRow) { var data = (FileDirectoryInfo)e.Row.DataItem; var img = new System.Web.UI.HtmlControls.HtmlImage(); if (data.Length == null) { img.Src = "/images/folder.jpg"; var lnk = new LinkButton(); lnk.ID = "lnkFolder"; lnk.Text = data.Name; lnk.Command += new CommandEventHandler(changeFolder_OnCommand); lnk.CommandArgument = data.Name; e.Row.Cells[0].Controls.Add(lnk); } else { var lnk = new HyperLink(); lnk.Text = data.Name; lnk.Target = "_blank"; lnk.NavigateUrl = getLink(data.Name); e.Row.Cells[0].Controls.Add(lnk); img.Src = "/images/file.jpg"; } e.Row.Cells[0].Controls.AddAt(0, img); } } where the first cell is a TemplateField. Currently, everything displays correctly, but the linkbuttons don't raise the Command event handler, and all of the controls disappear on postback. Any ideas?

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  • Use jQuery to find and add an image tooltip

    - by lund.mikkel
    Hey people Okay, what I'm trying to accomplish is a simple tool tip that, when you hover over the name of a color, shows a little image of that color. The html markup looks like this: <label class="colorPicker"> <input type="radio" checked="" id="20" value="20" name="id[2]"> <img width="16" height="16" title=" DinoBlack Mat " alt="DinoBlack Mat" src="images/attributes/color/dinoblack_mat.jpg">DinoBlack Mat </label> <label class="colorPicker"> <input type="radio" id="874" value="874" name="id[2]"> <img width="16" height="16" title="XrayBlue shiny" alt="XrayBlue shiny" src="images/attributes/color/xrayblue_shiny.jpg">XrayBlue shiny </label> I'm using the jQuery plugin "Tooltip" and I've added following to my main js-file: $('.colorPicker').tooltip({ track: true, delay: 0, showURL: false, fade: 250, bodyHandler: function() { return $("<img/>").attr("src", [THE SOURCE FOR THE IMAGE]); } }); The idea is simply that the image should be hidden by default. But when you hover over the text the little thumbnail shows up and makes it easy to recognize the color. The problem is I haven't got a clue how to get the src for the thumbnail. I don't know how to extract the src from the img inside the selected element. I've tried various combinations using the this keyword, but nothing seemed to work. I've also tried to add the src path as a rel attribute to the label, but also without any success. Should be needless to say I also control the PHP-output... I really hope you can help me. I've search the web for days without any luck. I'm getting desperate :D /Mikkel Lund

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  • jQuery validate and tabs

    - by ntan
    Hi i am using jQuery validate for my form validation. The form is inside tabs.When i get an error i add an icon to the tab that error exist to be visual by the user So far so good. My problem is that after correct the error i can not remove the error in tab icon. I was assuming that validator is accessible via success but its not Assuming that the first tab (tab0) has 3 field for validation (field1,field2,field3) Here is the full code $("form#Form1") .validate({ invalidHandler: function(form, validator) { //TAB 0 if (validator.errorMap.field1 != "" && validator.errorMap.field2 != "" && validator.errorMap.field3 != "") { if ($("#tabs>ul>li").eq(0).find("img").length == 0) { $("#tabs>ul>li").eq(0).prepend("<img src=\"error.gif\">"); } } }, errorClass: "errorField", errorElement: "p", errorPlacement: function(error, element) { var parent = element.parent(); parent.addClass("error"); error.prependTo( parent ); }, //validator in not accessible via success //so my code its not working success: function(element,validator) { var parent = element.parent(); parent.removeClass("error"); $(parent).children("p.errorField").remove(); //TAB 0 if (validator.errorMap.field1 == "" && validator.errorMap.field2 == "" && validator.errorMap.field2 == "") { if ($("#tabs>ul>li").eq(0).find("img").length == 0) { $("#tabs>ul>li").eq(0).find("img").remove(); } } }, rules: { field1: { required: true }, field2: { required: true }, field3: { required: true } } }); Any suggestion is welcome.

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  • Saving and retrieving image in SQL database from C# problem

    - by Mobin
    I used this code for inserting records in a person table in my DB System.IO.MemoryStream ms = new System.IO.MemoryStream(); Image img = Image_Box.Image; img.Save(ms, System.Drawing.Imaging.ImageFormat.Bmp); this.personTableAdapter1.Insert(NIC_Box.Text.Trim(), Application_Box.Text.Trim(), Name_Box.Text.Trim(), Father_Name_Box.Text.Trim(), DOB_TimePicker.Value.Date, Address_Box.Text.Trim(), City_Box.Text.Trim(), Country_Box.Text.Trim(), ms.GetBuffer()); but when i retrieve this with this code byte[] image = (byte[])Person_On_Application.Rows[0][8]; MemoryStream Stream = new MemoryStream(); Stream.Write(image, 0, image.Length); Bitmap Display_Picture = new Bitmap(Stream); Image_Box.Image = Display_Picture; it works perfectly fine but if i update this with my own generated Query like System.IO.MemoryStream ms = new System.IO.MemoryStream(); Image img = Image_Box.Image; img.Save(ms, System.Drawing.Imaging.ImageFormat.Bmp); Query = "UPDATE Person SET Person_Image ='"+ms.GetBuffer()+"' WHERE (Person_NIC = '"+NIC_Box.Text.Trim()+"')"; the next time i use the same code for retrieving the image and displaying it as used above . Program throws an exception

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  • Trying to write a video file using OpenCV

    - by Ted pottel
    Hi , I’m trying to use OpenCV to write a video file. I have a simple program that loads frames from a video file then accepts to save them At first the cvCreateVideoWrite always return NULL. I got a answer from your group saying it returns separate images and to try to change the file name to test0001.png, this worked. But now the cvWriteFrame function always fails, the code is CString path; path="d:\\mice\\Test_Day26_2.avi"; CvCapture* capture = cvCaptureFromAVI(path); IplImage* img = 0; CvVideoWriter *writer = 0; int isColor = 1; int fps = 25; // or 30 int frameW = 640; // 744 for firewire cameras int frameH = 480; // 480 for firewire cameras writer=cvCreateVideoWriter("d:\\mice\\test0001.png",CV_FOURCC('P','I','M','1'), fps,cvSize(frameW,frameH),isColor); if (writer==0) MessageBox("could not open writter"); int nFrames = 50; for(int i=0;i<nFrames;i++){ if (!cvGrabFrame(capture)) MessageBox("could not grab frame"); img=cvRetrieveFrame(capture); // retrieve the captured frame if (img==0) MessageBox("could not retrive data"); if (!cvWriteFrame(writer,img) ) MessageBox("could not write frame"); } cvReleaseVideoWriter(&writer); Any help would be GREAT - Ted

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  • Images in Applet not showing in web page

    - by Leanne C
    I am trying to display a JPEG image and a moving dot on a Java applet which I am using on a web based application. However, when I run the applet it works fine, but when I display the applet from the JSP page, I get the moving dot but not the JPEG image. Is there a specific folder where the JPEG needs to be? These are the 2 methods i use for drawing the picture and the moving dot on the screen. public class mapplet extends Applet implements Runnable { int x_pos = 10; int y_pos = 100; int radius = 20; Image img, img2; Graphics gr; URL base; MediaTracker m; @Override public void init() { mt = new MediaTracker(this); try { //getDocumentbase gets the applet path. base = getCodeBase(); img = getImage(base, "picture.jpg"); m.addImage(img, 1); m.waitForAll(); } catch (InterruptedException ex) { Logger.getLogger(movement.class.getName()).log(Level.SEVERE, null, ex); } public void paint (Graphics g) { g.drawImage(img, 0, 0, this); // set color g.setColor (Color.red); // paint a filled colored circle g.fillOval (x_pos - radius, y_pos - radius, 2 * radius, 2 * radius); } The code one below is the call from the jsp page <applet archive="mapplet.jar" code="myapplets/mapplet.class" width=350 height=200> </applet> The jar file and the picture are in the same folder as the jsp page, and there is also a folder containing the contents of the class and image of the applet in the web section of the application. The applet loads fine however the picture doesn't display. I think it's not the code but the location of the picture that is causing a problem. Thanks

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  • Bullets WILL NOT dissapear in firefox

    - by DunlopBurns
    Hoping you can help me with a problem. I cannot get rid of Bullets in Firefox, i don't want any anywhere, hence my list-style-type: none!important being everywhere. It only appears in Firefox as far as i can tell. the HTML.... <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" lang="en" xml:lang="en"> <head> <title>littleprints.nl</title> <meta name="description" content="----" /> <meta name="keywords" content="----" /> <meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" /> <script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.4/jquery.min.js"></script> <script type="text/javascript" src="js/slimbox2.js"></script> <link rel="stylesheet" href="css/slimbox2.css" type="text/css" media="screen" /> <link rel="stylesheet" href="layout.css"/> <link rel="stylesheet" href="style.css"/> </head> <body> <div id="container"> <div id="inline1"> <div id="mainpic"> <img src="myimages/circle.jpg" width="100%" alt="Circle bracelet"/> </div> <div id="intro"> <p>Hi and welcome to little prints NL. we make this and that all by hand with 100% silver. my name is Donna Burns and i work by commision, ive been studying for 4 years and am currently learning to become a goldsmith.</p> </div> </div> <div id="inline2"> <p>Click for more...</p> <div id="images"> <a href="myimages/photos/dogtag.jpg" rel="lightbox-gal" title="Beautiful, isn't it?" ><img src="myimages/work/chunky.gif" alt="chunky"/></a> <a href="myimages/photos/hearts.jpg" rel="lightbox-gal" title="Beautiful, isn't it?" ><img src="myimages/work/hearts.gif" alt="hearts"/></a> <a href="myimages/photos/close.jpg" rel="lightbox-gal" title="Beautiful, isn't it?" ><img src="myimages/work/close.gif" alt="close"/></a> <a href="myimages/photos/pearl.jpg" rel="lightbox-gal" title="Beautiful, isn't it?" >&nbsp;</a> <a href="myimages/photos/flower.jpg" rel="lightbox-gal" title="Beautiful, isn't it?" >&nbsp;</a> <a href="myimages/photos/frontcircle.jpg" rel="lightbox-gal" title="Beautiful, isn't it?" >&nbsp;</a> <a href="myimages/photos/dogtag.jpg" rel="lightbox-gal" title="Beautiful, isn't it?" >&nbsp;</a> </div> </div> </div><!--end container--> <div id="footer"> <div id="footalign"> <div id="social"> <ul> <li> <a href="http://www.facebook.com/littleprints" title="Little Prints"> <img src="myimages/facebook.png" width="50px" height="50px" alt="FB"/> </a> </li> <li> <a href="contact.html" title="contact"> <img src="myimages/at.gif" alt="@"/> </a> </li> </ul> </div> <div id="contact"> <p><br/>To enquire about a charm either phone:<br/> 0787463289<br/> or use one of the methods to the side.</p> </div> </div> </div> </body> </html> the CSS... * {margin: 0; padding: 0; border: 0;} html, body { background-color: #000000;image; text-align: center; font: 16px/1.8 Verdana, Arial, Helvetica, sans-serif; list-style-type: none!important; text-decoration: none;} #container { position: relative; width: 900px; top: 0; min-height: 100%; margin-left: auto; margin-right: auto; padding-top: 20px; background-image: URL(myimages/back2.gif); margin-bottom: 180px; } #footer { background-color: #555555; position: relative; clear: both; bottom: 0; width: 900px; height: auto; margin-left: auto; margin-right: auto; margin-bottom: 20px; padding-bottom: 22px; margin-top: -180px; } #inline1{ display: inline-block; margin-top: 250px; margin-bottom: 20px; } #inline2 { display: inline-block; margin-top: 30px; margin-bottom: 50px; } #mainpic { float: left; width: 68%; margin-left: 20px; } #intro { float: right; width: 20%; margin-left: auto; margin-right: 50px; margin-top: 20px; } #images { margin-bottom: 20px; margin-left: auto; margin-right: auto; } #footalign { display: inline; width:900px; list-style-type: none; } #contact { text-align: center; background-color:#555555; float: middle; list-style-type: none; } #social{ background-color:#555555; float: right; list-style: none; padding:0; padding-right: 5px; text-align:center; list-style-type: none!important; } #social img{ border: none; list-style-type: none!important; margin: 3px; } #social ul{ border: none; list-style-type: none!important; } #social a{ display:inline-block; -webkit-transition:all .5s ease-out; -moz-transition:all .5s ease-out; -ms-transition:all .5s ease-out; -o-transition:all .5s ease-out; transition:all .5s ease-out; list-style-type: none!important; } #social a:hover{ display:inline-block; -webkit-transform:translate(-10px,0px); -moz-transform:translate(0px,-10px); -ms-transform:translate(-10px,0px); -o-transform:translate(-10px,0px); transform:translate(-10px,0px); list-style-type: none!important; } #form { margin-top: 250px; margin-bottom: 50px; } .nav1 {font-family: sans-serif;font-size: 22px;text-shadow: 2px 2px 5px #000000;} a:link {text-decoration:none; color:#000000; padding:3px;} a:visited {text-decoration:none; color:#000000;} a:active {text-decoration:none; color:#555555;} a:hover {text-decoration:none; color:#555555;} .nav2 {font-family: sans-serif;font-size: 22px;text-shadow: 2px 2px 5px #ffffff;} a:link {text-decoration:none; color:#ffffff; padding:3px;} a:visited {text-decoration:none; color:#ffffff;} a:active {text-decoration:none; color:#555555;} a:hover {text-decoration:none; color:#555555;} .p1 { color: #ffffff; } div#images img { max-width: 500px; height: auto; }

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  • make array from a list of images with jquery

    - by robertdd
    i have a list of photos like this: <div class="upimage"> <ul id="upimagesQueue" class="thumbs ui-sortable"> <li id="upimagesKHGYUD"> <a href="uploads/0002.jpg"> <img src="uploads/0002.jpg" id="KHGYUD"> </a> </li> <li id="upimagesNCEEKI"> <a href="uploads/0003.jpg"> <img src="uploads/0003.jpg" id="NCEEKI"> </a> </li> <li id="upimagesPWSHUN"> <a href="uploads/0003.jpg"> <img src="uploads/0003.jpg" id="PWSHUN"> </a> </li> <li id="upimagesOYJAQV"> <a href="uploads/0004.jpg"> <img src="uploads/0004.jpg" id="OYJAQV"> </a> </li> </ul> </div> i want to make a function in jquery too get all the images in 1 array to be able to sent the array to php! the array i want to be in this form: array( 'image_id_1' => array( 'image_src_1' => 'xyz.jpg', ) 'image_id_2' => array( 'image_src_2' => 'xyz.jpg', ) 'image_id_3' => array( 'image_src_3' => 'xyz.jpg', ) 'image_id_4' => array( 'image_src_4' => 'xyz.jpg', ) ) how i can code this? thanks

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  • Automatically hyper-link URL's and Email's using C#, whilst leaving bespoke tags in place

    - by marcusstarnes
    I have a site that enables users to post messages to a forum. At present, if a user types a web address or email address and posts it, it's treated the same as any other piece of text. There are tools that enable the user to supply hyper-linked web and email addresses (via some bespoke tags/markup) - these are sometimes used, but not always. In addition, a bespoke 'Image' tag can also be used to reference images that are hosted on the web. My objective is to both cater for those that use these existing tools to generate hyper-linked addresses, but to also cater for those that simply type a web or email address in, and to then automatically convert this to a hyper-linked address for them (as soon as they submit their post). I've found one or two regular expressions that convert a plain string web or email address, however, I obviously don't want to perform any manipulation on addresses that are already being handled via the sites bespoke tagging, and that's where I'm stuck - how to EXCLUDE any web or email addresses that are already catered for via the bespoke tagging - I wan't to leave them as is. Here are some examples of bespoke tagging for the variations that I need to be left alone: [URL=www.msn.com]www.msn.com[/URL] [URL=http://www.msn.com]http://www.msn.com[/URL] [[email protected]][email protected][/EMAIL] [IMG]www.msn.com/images/test.jpg[/IMG] [IMG]http://www.msn.com/images/test.jpg[/IMG] The following examples would however ideally need to be automatically converted into web & email links respectively: www.msn.com http://www.msn.com [email protected] Ideally, the 'converted' links would just have the appropriate bespoke tags applied to them as per the initial examples earlier in this post, so rather than: <a href="..." etc. they'd become: [URL=http://www.. etc.) Unfortunately, we have a LOT of historic data stored with this bespoke tagging throughout, so for now, we'd like to retain that rather than implementing an entirely new way of storing our users posts. Any help would be much appreciated. Thanks.

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  • @attribute elements in XML

    - by danit
    Here is my XML: ["link"]=> array(2) { [0]=> object(SimpleXMLElement)#244 (1) { ["@attributes"]=> array(3) { ["type"]=> string(9) "text/html" ["href"]=> string(48) "http://twitter.com/MoodleDan/statuses/1226112723" ["rel"]=> string(9) "alternate" } } [1]=> object(SimpleXMLElement)#245 (1) { ["@attributes"]=> array(3) { ["type"]=> string(9) "image/png" ["href"]=> string(59) "http://a3.twimg.com/profile_images/226895523/Dan_normal.png" ["rel"]=> string(5) "image" } } } ["author"]=> object(SimpleXMLElement)#246 (2) { ["name"]=> string(14) "Dan Humpherson" ["uri"]=> string(16) "http://vl3.co.uk" } The above XML is part of a larger array, but how do i get the href -> ["href"]=> string(59) "http://a3.twimg.com/profile_images/226895523/Dan_normal.png" Element to echo in PHP? This is what I tried (Wrong I know) foreach ($entry->link as $img) { echo $img->href; echo "<img src='". $img ."' />"; }

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  • Garbled text when constructing emails with vmime

    - by Klaus Fiedler
    Hey, my Qt C++ program has a part where it needs to send the first 128 characters or so of the output of a bash command to an email address. The output from the tty is captured in a text box in my gui called textEdit_displayOutput and put into my message I built using the Message Builder ( the object m_vmMessage ) Here is the relevant code snippet: m_vmMessage.getTextPart()->setCharset( vmime::charsets::US_ASCII ); m_vmMessage.getTextPart()->setText( vmime::create < vmime::stringContentHandler > ( ui->textEdit_displayOutput->toPlainText().toStdString() ) ); vmime::ref < vmime::message > msg = m_vmMessage.construct(); vmime::utility::outputStreamAdapter out( std::cout ); msg->generate( out ); Giving bash 'ls /' and a newline makes vmime give terminal output like this: ls /=0Abin etc=09 initrd.img.old mnt=09 sbin=09 tmp=09 vmlinuz.o= ld=0Aboot farts=09 lib=09=09 opt=09 selinux usr=0Acdrom home=09 = lost+found=09 proc srv=09 var=0Adev initrd.img media=09 root = Whereas it should look more like this: ls / bin etc initrd.img.old mnt sbin tmp vmlinuz.old boot farts lib opt selinux usr cdrom home lost+found proc srv var dev initrd.img media root sys vmlinuz 18:22> How do I encode the email properly? Does vmime just display it like that on purpose and the actual content of the email is ok?

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