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  • MySQL PHP incompatibility.

    - by Evernoob
    Ok maybe I've overlooked something really simple here, but I can't seem to figure this out. I'm running WAMP locally, but connecting to a remote MySQL database. The local version of PHP is the latest 5.3.0. One of the remote databases, being version 5.0.45 works fine. However, the other remote database I'm trying to connect to, which is version 5.0.22 throws the following error before dying: Warning: mysql_connect() [function.mysql-connect]: OK packet 6 bytes shorter than expected. PID=5880 in ... Warning: mysql_connect() [function.mysql-connect]: mysqlnd cannot connect to MySQL 4.1+ using old authentication in ... WTF? UPDATE: Reverting to PHP 5.2.* i.e. anything lower than 5.3.0 resolves the problem completely. As long as I am not running 5.3.0 I can connect to both databases. I'm not sure what the explanation is for this weirdness.

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  • PHP - Select from database the same query

    - by How to PHP
    I created a table that contains the name of the user and his job, and created PHP page that shows me all the users that works doctor, I entered doctor into a variable then I selected from the table where Jobs equal to $doctor, that is great, but I need it to get the same Jobs into a table in the page and the other same jobs into a table in the same page. this is my code that shows only the users works doctor in one table, <html> <h1>Doctors</h1> </html> <?php mysql_connect('localhost','root',''); mysql_select_db('data'); $doctor='doctor'; $query= mysql_query("SELECT * FROM `users` WHERE `job` = '$doctor'")or die(mysql_error()); while ($arr = mysql_fetch_array($query)) $name= $arr['name']; echo $name; } ?> That shows me doctors when I put doctor in a variable I want to show all same Jobs in a table. Is there is a way to do this? Thanks :)

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  • Displaying data from a linked table and displaying it as a list with HTML/PHP/MySQL

    - by user1672694
    I have three tables. students studentID | FirstName | LastName | Email | Form course CCode | Title courseenrolement courseenrolementid | studentID | ccode | complete | scode With the website, I have a page where I can view all the current enrolements and I wish to be able to view the list displaying the first name, surname and course title. I know I could do it with the following SQL (for the names): SELECT FirstName, LastName FROM student, courseenrolement WHERE courseenrolement.studentID = student.studentID But I am unsure how to get this to work using HTML/PHP. At present I only know how to display the studentID and CCode from the courseenrolement table using the following code: <ul> <?php foreach ($courseenrolements as $ce): ?> <li> <form action="" method="post"> <div> <?php htmlout($ce['studentID']); ?> <?php htmlout($ce['CCode']); ?> <input type="hidden" name="courseenrolementid" value="<?php echo $ce['courseenrolementid']; ?>"> <input type="submit" name="action" value="Edit"> <input type="submit" name="action" value="Delete"> </div> </form> </li> <?php endforeach; ?> </ul> which displays this: But I would like the names and course title. I managed to get it to show the names etc in the dropdown on the 'Add new' form, so I would assume it will be similar, but just unsure on how exactly. Thanks in advance

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  • Is sqlite3 faster than MySQL on shared hosting?

    - by Osvaldo
    Can sqlite3 be faster than MySQL on shared hosting and small to average websites (less than 500 visitors a day). I have an account in a popular shared hosting provider and I've noticed that it has become quite slow redering pages. My doubt is that this may happen because the MySQL server is overloaded. Some CMS'es work fine with SQLlite too, so I was wandering if I should use SQLite for the new sites instead of MySQL.

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  • mysql_connect randomly hangs up

    - by sergdev
    I install php 5 (more precisely 5.3.1) as apache module. After this one of my application becomes randomly hang up on mysql_connect - sometimes works, sometimes no, sometimes reload of page helps. How can this be fixed? I use Windows Vista, Apache/2.2.14 (Win32) PHP/5.3.1 with php module, MySql 5.0.67-community-nt.

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  • MySQL enters another value that the one given by PHP

    - by Tristan
    Hello, The big problem : mysql does not stores the information i told him to via PHP Example (this req is an echo just before the query) : INSERT INTO serveur (GSP_nom , IPserv, port, tickrate, membre, nomPays, finContrat, type, jeux, slot, ipClient, email) VALUES ( 'ckras', '88.191.88.57', '37060', '100' , '', 'Allemagne','20110519', '2', '4','99' ,'82.220.201.183','[email protected]'); But on the MySQL i have : 403 ckras 88.191.88.57 32767 100 Allemagne 20110519 1 2010-04-25 00:51:47 2 4 99 82.220.201.183 [email protected] port : 37060 (right value) //// 32767 (MySQL's drug?) Any help would be appreciated, i'm worse than stuck and i'm ** off PS: *There is no trigger on the mysql as far as i know / there is no controll on the port which means that nowhere i modify the "port" value and this script works for 80% of the time ( it seems that as soon as the users enters a port = 30000 it causes that bug), an user first reported to me this error today and the script was running since 3 months* Thanks

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  • MySQL Path Detection, Command Line

    - by swt83
    I have a script that I want to run via command line. In setting up the command to run, I am trying to do a detection for the MySQL path. When I type "which mysql" in my terminal, I get an answer. When I run PHP -- $path = exec('which mysql'); -- I get nothing. If I do the same command for "which php" I get an answer, but not MySQL. Why would I get a response from terminal and not from PHP CLI on this?

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  • trouble connecting to MySql DB (PHP)

    - by user332817
    Hi I have the following PHP code to connect to my db. <?php ob_start(); $host="localhost"; // Host name $username="root"; // Mysql username $password=""; // Mysql password $db_name="test"; // Database name $tbl_name="members"; // Table name // Connect to server and select databse. mysql_connect("$host", "$username", "$password")or die("cannot connect"); ?> however I get the following error: Warning: mysql_connect() [function.mysql-connect]: [2002] A connection attempt failed because the connected party did not (trying to connect via tcp://localhost:3306) in C:\Program Files (x86)\EasyPHP-5.3.2i\www\checklogin.php on line 11 Warning: mysql_connect() [function.mysql-connect]: A connection attempt failed because the connected party did not properly respond after a period of time, or established connection failed because connected host has failed to respond. in C:\Program Files (x86)\EasyPHP-5.3.2i\www\checklogin.php on line 11 Fatal error: Maximum execution time of 30 seconds exceeded in C:\Program Files (x86)\EasyPHP-5.3.2i\www\checklogin.php on line 11 I am able to add a db/tables via phpmyadmin but I cant connect using php. here is a screenshot of my phpmyadmin page: http://img294.imageshack.us/img294/1589/sqls.jpg any help would be appreciated, thanks in advance.

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  • MySQL Split Time Ranges into Smaller Chunks

    - by Neren
    Hello all, I've recently been tasked with finishing a PHP/MySQL web app when the developer quit last week. I'm no MySQL expert, so I apologize if this is an intensely simple question. I've searched SO for the better part of two days trying to find a relatively easy solution to my problem, which is as follows. Problem in a Nutshell: I have a MySQL table full of start and end datetime (GMT -5) & UNIX Timestamp values covering durations of irregular length and need to break/split/divide them into more-regular time chunks (5 minutes). I'm not after a count of row entries per time chunk/bucket/period, if that makes any sense. Data Example: started, ended, started_UNIX, ended_UNIX 2010-10-25 15:12:33, 2010-10-25 15:47:09, 1288033953, 1288036029 What I'm hoping to get: 2010-10-25 15:12:33, 2010-10-25 15:15:00, 1288033953, 1288037700 2010-10-25 15:15:00, 2010-10-25 15:20:00, 1288037700, 1288038000 2010-10-25 15:20:00, 2010-10-25 15:25:00, 1288038000, 1288038300 2010-10-25 15:25:00, 2010-10-25 15:30:00, 1288038300, 1288038600 2010-10-25 15:30:00, 2010-10-25 15:35:00, 1288038600, 1288038900 2010-10-25 15:35:00, 2010-10-25 15:40:00, 1288038900, 1288039200 2010-10-25 15:40:00, 2010-10-25 15:45:00, 1288039200, 1288039500 2010-10-25 15:45:00, 2010-10-25 15:47:09, 1288039500, 1288039629 If you're interested, here's the quick & dirty on the app and why I need the data: App overview: The application receives very simple POST requests generated by a basic sensor device when its input pins go to ground, which submits an INSERT query to the database where MySQL records a timestamp (as started). When the input pins return from a grounded state, the device submits a different POST request, which causes the PHP app to submit an UPDATE query, where a modification time timestamp is inserted (as ended). My employer recently changed the periodic reporting unit of measure from Seconds "On" Per Day to Seconds "On" Per 5 Minute Interval. I had formulated what I thought would be a workable solution, but when I looked at it on paper, it looked like Rube Goldberg's nightmare constructed in MySQL, so that was out. Any suggestions as to how to break these spans into 5 minute blocks? Keeping it all in MySQL would be my preference, though I'll take any suggestions. Thank you for any suggestions you may have. Again, I apologize if this is a no-brainer. If I ask any additional questions of the SO collective consciousness in the future, I'll try to word them a bit better. Any help will be happily welcomed. Thanks, Neren

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  • Connect to MySQL via PHP script tunnel

    - by Neo
    Here's the question, I need to connect to a remote MySQL database from my C# Application, problem is the MySQL instance will block all access to all IP's apart from localhost, this can not be changed as its too much of a security issue. The question is, is it possible to connect via a tunnel instead to a php script hosted on the server, this would then act as the mysql connection. Any ideas and suggestions?

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  • MySQL problem reconnecting (mysqld.exe) keeps giving error...

    - by Ronedog
    Need some guidance figuring out what went wrong. I've been using mysql, phpmyadmin for just under a year on my home computer while I develop a webapp. 3 days ago I updated my windows vista with all the "wonderful" microsoft updates, security patches, etc...and now it's broke. I tried uninstalling all the upgrades, but there are 4 of them I can't unistall because microsoft says their "operating system" updates and can't be unistalled. My system is: windows vista, php 5+, mysql 5.1, Apache 2+. I can run my web app and it queries the database without any problems. However, when I run phpmyadmin to get into the database I get an error: "mysqld.exe has stopped working" and phpmyadmin crashes. I tried going to the command line for mysql to do a mysqldump to backup my database and it gives me an error "2013, could not connect to the server". If I restart the computer the webapp will work again. Basically, php can query the database, but if I try to get at the database through phpmyadmin, or the command prompt the mysqld.exe error occurs and blows mysql out. Any ideas what's going on here? Any ideas how to get around this to backup the db, so I can reinstall mysql?. I'm really lost where to start. I don't really know if the updates caused the problem, or if the 4 updates that can't be unistalled are really the problem. Any tips will be appreciated. thanks.

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  • Remote connect to mysql?

    - by chobo2
    Hi I don't use php or mysql but I am trying to upgrade a phpbb board I got but the one click installer forgot to install some stuff in the database so I can't upgrade to the newest version till I add the missing stuff. So I need to do a remote connect to mysql database but I am not sure how to do this or what software I need(free, and very easy to setup I don't want to spend much time on this). I don't really want to use phpmyadmin since I don't want to start setting up a virtual directory and whatever else it needs to be installed. Like I said I don't do php or mysql I just choose it since in my hosting package it was one click to install phpbb and I had a mysql database free. Thanks

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  • How to loop through an array return from the Query of Mysql

    - by Jerry
    This might be easy for you guys but i could't get it. I have a php class that query the database and return the query result. I assign the result to an array and wants to use it on my main.php script. I have tried to use echo $var[0] or echo $var[1] but the output are 'array' instead of my value. Anyone can help me about this issue? Thanks a lot! My php class <?php class teamQuery { function teamQuery(){ } function getAllTeam(){ $connection = mysql_connect(DB_SERVER,DB_USER,DB_PASS); if (!$connection) { die("Database connection failed: " . mysql_error()); } $db_select = mysql_select_db(DB_NAME,$connection); if (!$db_select) { die("Database selection failed: " . mysql_error()); } $teamQuery=mysql_query("SELECT * FROM team", $connection); if (!$teamQuery){ die("database has errors: ".mysql_error()); } $ret = array(); while($row=mysql_fetch_array($teamQuery)){ $ret[]=$row; } mysql_free_result($teamQuery); return $ret; } } ?> My php on the main.php $getTeam=new teamQuery(); $team=$getTeam->getAllTeam(); //echo $team[0] or team[1] output 'array' string! // while($team){ // do something } can't work either // How to loop through the values?? Thanks!

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  • Inserting a Date and Time value to a MySql from PHP

    - by DomingoSL
    Hello i want to send to a MySQL data base a date and time in a format compatible with the mysql DateTime format, wich is: 0000-00-00 00:00:00 ... Im using this code who brings the date and time from a PHP command: $insert = "INSERT INTO sms (ref, texto, fecha) VALUES ('".$_POST['usuario']."', '".$_POST['sms']."', '".date(DATE_ATOM, mktime(0, 0, 0, 7, 1, 2000))."')"; $add_member = mysql_query($insert); I really want to do this but with a MySQL command, i mean, using the Date and Time from the mysql server. Thanks

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  • mysql_num_rows(): supplied argument is not a valid MySQL result resource

    - by php-b-grader
    I am getting this error when I pass an invalid SQL string... I spent the last hour trying to find the problem assuming - It's not my SQL it must be the db handle... ANyway, I've now figured out that it was bad SQL... What I want to do is test the result of the mysql_query() for a valid resultset. I am simply using empty($result)... Is this the most effective test? Is there a more widely accepted method of testing a resultset for a valid result?

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  • syntax for MySQL INSERT with an array of columns

    - by Mike_Laird
    I'm new to PHP and MySQL query construction. I have a processor for a large form. A few fields are required, most fields are user optional. In my case, the HTML ids and the MySQL column names are identical. I've found tutorials about using arrays to convert $_POST into the fields and values for INSERT INTO, but I can't get them working - after many hours. I've stepped back to make a very simple INSERT using arrays and variables, but I'm still stumped. The following line works and INSERTs 5 items into a database with over 100 columns. The first 4 items are strings, the 5th item, monthlyRental is an integer. $query = "INSERT INTO `$table` (country, stateProvince, city3, city3Geocode, monthlyRental) VALUES ( '$country', '$stateProvince', '$city3', '$city3Geocode', '$monthlyRental')"; When I make an array for the fields and use it, as follows: $colsx = array('country,', 'stateProvince,', 'city3,', 'city3Geocode,', 'monthlyRental'); $query = "INSERT INTO `$table` ('$colsx') VALUES ( '$country', '$stateProvince', '$city3', '$city3Geocode', '$monthlyRental')"; I get a MySQL error - check the manual that corresponds to your MySQL server version for the right syntax to use near ''Array') VALUES ( 'US', 'New York', 'Fairport, Monroe County, New York', '(43.09)' at line 1. I get this error whether the array items have commas inside the single quotes or not. I've done a lot of reading and tried many combinations and I can't get it. I want to see the proper syntax on a small scale before I go back to foreach expressions to process $_POST and both the fields and values are arrays. And yes, I know I should use mysql_real_escape_string, but that is an easy later step in the foreach. Lastly, some clues about the syntax for an array of values would be helpful, particularly if it is different from the fields array. I know I need to add a null as the first array item to trigger the MySQL autoincrement id. What else? I'm pretty new, so please be specific.

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  • Need to determine how php files are being rendered in a LAMP configuration (CGI, FastCGI, or mod-php)

    - by Chris Williams
    How do I determine how our php files are being rendered in a simple LAMP configuration? phpinfo shows: -- Configure Command -- --enable-force-cgi-redirect --enable-fastcgi -- Server API -- CGI/FastCGI -- cgi-fcgi -- Directive Local Value Master Value cgi.check_shebang_line 1 1 cgi.fix_pathinfo 1 1 cgi.force_redirect 1 1 cgi.nph 0 0 cgi.redirect_status_env no value no value cgi.rfc2616_headers 0 0 fastcgi.logging 1 1

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  • PHP Websites: Very high IOPS

    - by Khuram
    We are hosting a set of websites on VM Cloud. These sites were previously on a couple of dedicated servers but to enhance performance, we transferred them onto a Cloud environment. The Cloud has SSD storage but they are now saying that we have very high IOPS and are goign to degrade us if we do not do anything soon. We have good PHP Websites but they are run without any Caching. how do I start to debug this? Sincerely, Khuram

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  • Newbie's problems with MySQL and php

    - by Mirage81
    I'm a real newbie with php and MySQL. Now I'm working on the following code which should search the database for eg. all the Lennons living in Liverpool. 1) How should I modify "get.php" to get the text "no results" to appear if there are no search results. 2) How should I modify "index.php" to get the option values (city and lastname) straight from the database instead of having to type them one by one? 3) Am I using mysql_real_escape_string the right way? 4) Any other mistakes in the code? index.php: <form action="get.php" method="post"> <p> <select name="city"> <option value="Birmingham">Birmingham</option> <option value="Liverpool">Liverpool</option> <option value="London">London</option> </select> </p> <p> <select name="lastname"> <option value="Lennon">Lennon</option> <option value="McCartney">McCartney</option> <option value="Osbourne">Osbourne</option> </select> </p> <p> <input value="Search" type="submit"> </p> </form> get.php: <?php $city = $_POST['city']; $lastname = $_POST['lastname']; $conn = mysql_connect('localhost', 'user', 'password'); mysql_select_db("database", $conn) or die("connection failed"); $query = "SELECT * FROM users WHERE city = '$city' AND lastname = '$lastname'"; $result = mysql_query($query, $conn); $city = mysql_real_escape_string($_POST['city']); $lastname = mysql_real_escape_string($_POST['lastname']); echo $rowcount; while ($row = mysql_fetch_row($result)) { if ($rowcount == '0') echo 'no results'; else { echo '<b>City: </b>'.htmlspecialchars($row[0]).'<br />'; echo '<b>Last name: </b>'.htmlspecialchars($row[1]).'<br />'; echo '<b>Information: </b>'.htmlspecialchars($row[2]); } } mysql_close($conn);

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  • Problems with MYSQL database

    - by shinjuo
    I have a database that worked fine until I decided to add a log onto the page. here is what I have now: <body> <?php if($_SERVER['REQUEST_METHOD'] == 'POST') { require("serverInfo.php"); mysql_query("UPDATE `cardLists` SET `AmountLeft` = `AmountLeft` + ".mysql_real_escape_string($_POST['Add'])." WHERE `cardID` = '".mysql_real_escape_string($_POST['Cards'])."'"); echo "\"" .$_POST['Add'] ."\" has been added to the inventory amount for the card \"". $_POST['Cards']. "\""; mysql_query("INSERT INTO `log` (`changes`, `amount`, `cardID`, `person`, Date)VALUES('ADDED','$_POST['Add']','$_POST['Cards']', '$_POST['Person']', NOW())"); mysql_close($link); } ?> <form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post"> <?php require("serverInfo.php"); ?> <?php $res = mysql_query("SELECT * FROM cardLists order by cardID") or die(mysql_error()); echo "<select name = 'Cards'>"; while($row=mysql_fetch_assoc($res)) { echo "<option value=\"$row[cardID]\">$row[cardID]</option>"; } echo "</select>"; ?> Amount to Add: <input type="text" name="Add" maxlength="8" /> Changes Made By: <select name="Person"> <option value="justin">Justin</option> <option value="chris">Chris</option> <option value="matt">Matt</option> <option value="dan">Dan</option> <option value="tim">Tim</option> <option value="amanda">Amanda</option> </select> <input type="submit" name ="submit" onClick= "return confirm( 'Are you sure you want to add this amount?');"> </form> <br /> <input type="button" name="main" value="Return To Main" onclick="window.location.href='index.php';" /> </body> </html> it works fine until I added the: mysql_query("INSERT INTO `log` (`changes`, `amount`, `cardID`, `person`, Date)VALUES('ADDED','$_POST['Add']','$_POST['Cards']', '$_POST['Person']', NOW())"); mysql_close($link); Can anyone see what is going on?

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  • Set up lnux box for hosting a-z

    - by microchasm
    I am in the process of reinstalling the OS on a machine that will be used to host a couple of apps for our business. The apps will be local only; access from external clients will be via vpn only. The prior setup used a hosting control panel (Plesk) for most of the admin, and I was looking at using another similar piece of software for the reinstall - but I figured I should finally learn how it all works. I can do most of the things the software would do for me, but am unclear on the symbiosis of it all. This is all an attempt to further distance myself from the land of Configuration Programmer/Programmer, if at all possible. I can't find a full walkthrough anywhere for what I'm looking for, so I thought I'd put up this question, and if people can help me on the way I will edit this with the answers, and document my progress/pitfalls. Hopefully someday this will help someone down the line. The details: CentOS 5.5 x86_64 httpd: Apache/2.2.3 mysql: 5.0.77 (to be upgraded) php: 5.1 (to be upgraded) The requirements: SECURITY!! Secure file transfer Secure client access (SSL Certs and CA) Secure data storage Virtualhosts/multiple subdomains Local email would be nice, but not critical The Steps: Download latest CentOS DVD-iso (torrent worked great for me). Install CentOS: While going through the install, I checked the Server Components option thinking I was going to be using another Plesk-like admin. In hindsight, considering I've decided to try to go my own way, this probably wasn't the best idea. Basic config: Setup users, networking/ip address etc. Yum update/upgrade. Upgrade PHP: To upgrade PHP to the latest version, I had to look to another repo outside CentOS. IUS looks great and I'm happy I found it! cd /tmp #wget http://dl.iuscommunity.org/pub/ius/stable/Redhat/5/x86_64/epel-release-1-1.ius.el5.noarch.rpm #rpm -Uvh epel-release-1-1.ius.el5.noarch.rpm #wget http://dl.iuscommunity.org/pub/ius/stable/Redhat/5/x86_64/ius-release-1-4.ius.el5.noarch.rpm #rpm -Uvh ius-release-1-4.ius.el5.noarch.rpm yum list | grep -w \.ius\. [will list all packages available in the IUS repo] rpm -qa | grep php [will list installed packages needed to be removed. the installed packages need to be removed before you can install the IUS packages otherwise there will be conflicts] #yum shell >remove php-gd php-cli php-odbc php-mbstring php-pdo php php-xml php-common php-ldap php-mysql php-imap Setting up Remove Process >install php53 php53-mcrypt php53-mysql php53-cli php53-common php53-ldap php53-imap php53-devel >transaction solve >transaction run Leaving Shell #php -v PHP 5.3.2 (cli) (built: Apr 6 2010 18:13:45) This process removes the old version of PHP and installs the latest. To upgrade mysql: Pretty much the same process as above with PHP #/etc/init.d/mysqld stop [OK] rpm -qa | grep mysql [installed mysql packages] #yum shell >remove mysql mysql-server Setting up Remove Process >install mysql51 mysql51-server mysql51-devel >transaction solve >transaction run Leaving Shell #service mysqld start [OK] #mysql -v Server version: 5.1.42-ius Distributed by The IUS Community Project The above upgrade instructions courtesy of IUS wiki: http://wiki.iuscommunity.org/Doc/ClientUsageGuide Create a chroot jail to hold sftp user via rssh. This will force SCP/SFTP and will circumvent traditional FTP server setup. #cd /tmp #wget http://dag.wieers.com/rpm/packages/rssh/rssh-2.3.2-1.2.el5.rf.x86_64.rpm #rpm -ivh rssh-2.3.2-1.2.el5.rf.x86_64.rpm #useradd -m -d /home/dev -s /usr/bin/rssh dev #passwd dev Edit /etc/rssh.conf to grant access to SFTP to rssh users. #vi /etc/rssh.conf Uncomment line allowscp This allows me to connect to the machine via SFTP protocol in Transmit (my FTP program of choice; I'm sure it's similar with other FTP apps). Above instructions for SFTP appropriated (with appreciation!) from http://www.cyberciti.biz/tips/linux-unix-restrict-shell-access-with-rssh.html And this is where I'm at. I will keep editing this as I make progress. Any tips on how to Configure virtual interfaces/ip based virtual hosts for SSL, setting up a CA, or anything else would be appreciated.

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  • Problems installing MySQL-python via yum / missing dependency / incompatibility problem?

    - by bs0
    I have come up against problems installing MySQL-python via yum. Our server is running Centos 5.5 and MySQL Version 5.1.45, Python-dev is installed. Yum complains about the missing dependency libmysqlclient_r.so.15: Missing Dependency: libmysqlclient_r.so.15()(64bit) is needed by package MySQL-python-1.2.1-1.x86_64 (base) The server is up to date and the packages mysql mysql-devel python-devel are installed. The missing dependency is nowhere on the system: locate libmysqlclient /usr/lib64/libmysqlclient.so /usr/lib64/libmysqlclient.so.15 /usr/lib64/libmysqlclient.so.16 /usr/lib64/libmysqlclient.so.16.0.0 /usr/lib64/libmysqlclient_r.so /usr/lib64/libmysqlclient_r.so.16 /usr/lib64/libmysqlclient_r.so.16.0.0 /usr/lib64/mysql/libmysqlclient.a /usr/lib64/mysql/libmysqlclient.la /usr/lib64/mysql/libmysqlclient.so /usr/lib64/mysql/libmysqlclient_r.a /usr/lib64/mysql/libmysqlclient_r.la /usr/lib64/mysql/libmysqlclient_r.so /usr/local/cpanel/lib64/libmysqlclient.so.14 rpm -qa | grep -i mysql MySQL-devel-5.1.45-0.glibc23 MySQL-bench-5.0.89-0.glibc23 MySQL-shared-5.1.45-0.glibc23 MySQL-server-5.1.45-0.glibc23 MySQL-test-5.1.45-0.glibc23 MySQL-client-5.1.45-0.glibc23 The Python version is python-2.4.3-27.el5.x86_64: Python 2.4.3 (#1, Sep 3 2009, 15:37:37) [GCC 4.1.2 20080704 (Red Hat 4.1.2-46)] on linux2 Any suggestions would be greatly appreciated.

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  • How do I setup ASP.NET MVC 2 with MySQL?

    - by NovaJoe
    Okay, so I'm cheating and not actually a question, but instead making a flat-out post. I know that goes against the grain of Stack Overflow, but this is too valuable not to share. I'm assuming that you have Visual Studio Professional 2008 and access to an instance of MySQL server. This MAY work with VS2008 Web edition, but not at all sure. If you haven't, install MySQL Connector for .NET (6.2.2.0 at the time of this write-up) Optional: install MySQL GUI Tools If you haven't, install MVC 2 RTM, or better yet, use Microsoft's Web Platform Installer. Create an empty MySQL database. If you don't want to access your application with the MySQL root user account (insecure), create a user account and assign the appropriate privileges (outside the scope of this write-up). Create a new MVC 2 application in Visual Studio In the MVC 2 app, reference MySql.Web.dll. It will either be in your GAC, or in the folder that the MySQL Connector installer put it. Modify the connection strings portion of your web.config: <connectionStrings> <remove name="LocalMySqlServer"/> <add name="MySqlMembershipConnection" connectionString="Data Source=[MySql server host name];user id=[user];password=[password];database=[database name];" providerName="MySql.Data.MySqlClient"/> </connectionStrings> Modify the membership portion of your web.config: <membership defaultProvider="MySqlMembershipProvider"> <providers> <clear/> <add name="MySqlMembershipProvider" type="MySql.Web.Security.MySQLMembershipProvider, MySql.Web, Version=6.2.2.0, Culture=neutral, PublicKeyToken=c5687fc88969c44d" connectionStringName="MySqlMembershipConnection" enablePasswordRetrieval="false" enablePasswordReset="true" requiresQuestionAndAnswer="false" requiresUniqueEmail="true" passwordFormat="Hashed" maxInvalidPasswordAttempts="5" minRequiredPasswordLength="6" minRequiredNonalphanumericCharacters="0" passwordAttemptWindow="10" applicationName="/" autogenerateschema="true"/> </providers> </membership> Modify the role manager portion of your web.config: <roleManager enabled="true" defaultProvider="MySqlRoleProvider"> <providers> <clear /> <add connectionStringName="MySqlMembershipConnection" applicationName="/" name="MySqlRoleProvider" type="MySql.Web.Security.MySQLRoleProvider, MySql.Web, Version=6.2.2.0, Culture=neutral, PublicKeyToken=c5687fc88969c44d" autogenerateschema="true"/> </providers> </roleManager> Modify the profile portion of your web.config: <profile> <providers> <clear/> <add type="MySql.Web.Security.MySQLProfileProvider, MySql.Web, Version=6.2.2.0, Culture=neutral, PublicKeyToken=c5687fc88969c44d" name="MySqlProfileProvider" applicationName="/" connectionStringName="MySqlMembershipConnection" autogenerateschema="true"/> </providers> </profile> At this point, you ought to be able to run the app and have the default ASP.NET MVC 2 home page come up in your browser. However, it may be a better idea to first run the ASP.NET Web configuration Tool (in Visual Studio top menus: Project - ASP.NET Configuration). Once the tool launches, check out each of the tabs; no errors = all good. The configuration tool Nathan Bridgewater's blog was essential to getting this working. Kudos, Nathan. Look for the "Configuration Tool" heading half way down the page. The public key token on the MySql.web.dll that I've posted here ought not change any time soon. But in case you suspect a bad token string from copying and pasting or whatever, just use the Visual Studio command line to run: "sn -T [Path\to\your.dll]" in order to get the correct public key token. There you have it, ASP.NET MVC 2 running over MySQL. Cheers!

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  • Checking form input data on submit with pure PHP [migrated]

    - by Leron
    I have some experience with PHP but I have never even try to do this wit pure PHP, but now a friend of mine asked me to help him with this task so I sat down and write some code. What I'm asking is for opinion if this is the right way to do this when you want to use only PHP and is there anything I can change to make the code better. Besides that I think the code is working at least with the few test I made with it. Here it is: <?php session_start(); // define variables and initialize with empty values $name = $address = $email = ""; $nameErr = $addrErr = $emailErr = ""; $_SESSION["name"] = $_SESSION["address"] = $_SESSION["email"] = ""; $_SESSION["first_page"] = false; if ($_SERVER["REQUEST_METHOD"] == "POST") { if (empty($_POST["name"])) { $nameErr = "Missing"; } else { $_SESSION["name"] = $_POST["name"]; $name = $_POST["name"]; } if (empty($_POST["address"])) { $addrErr = "Missing"; } else { $_SESSION["address"] = $_POST["address"]; $address = $_POST["address"]; } if (empty($_POST["email"])) { $emailErr = "Missing"; } else { $_SESSION["email"] = $_POST["email"]; $email = $_POST["email"]; } } if ($_SESSION["name"] != "" && $_SESSION["address"] != "" && $_SESSION["email"] != "") { $_SESSION["first_page"] = true; header('Location: http://localhost/formProcessing2.php'); //echo $_SESSION["name"]. " " .$_SESSION["address"]. " " .$_SESSION["email"]; } ?> <DCTYPE! html> <head> <style> .error { color: #FF0000; } </style> </head> <body> <form method="POST" action="<?php echo htmlspecialchars($_SERVER["PHP_SELF"]);?>"> Name <input type="text" name="name" value="<?php echo htmlspecialchars($name);?>"> <span class="error"><?php echo $nameErr;?></span> <br /> Address <input type="text" name="address" value="<?php echo htmlspecialchars($address);?>"> <span class="error"><?php echo $addrErr;?></span> <br /> Email <input type="text" name="email" value="<?php echo htmlspecialchars($email);?>"> <span class="error"><?php echo $emailErr;?></span> <br /> <input type="submit" name="submit" value="Submit"> </form> </body> </html>

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